Hi! I really need help with the answer to this question!

Answer:

i would say 42

Step-by-step explanation:

5^3 + 6[2 - 4(7-8)^2] = 125 + 6(-2)

= 125 - 12

= 113

The statistic is 101 out of 152 (66.45%) which  the questionnaires returned from the 800 mailed support the enactment of a statewide smoking ban in all enclosed public places.

To calculate this statistic, I first found the total number of questionnaires returned, which was 152. I then found the number of questionnaires that supported the ban, which was 101. To calculate the percentage, I then divided the number of questionnaires that supported the ban (101) by the total number of questionnaires returned (152), which gave me the answer of 66.45%. This percentage shows that a majority of the voters in the state representative's district support the enactment of a statewide smoking ban in all enclosed public places.

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Answer: 3) x = 87°; y = 93°; z = 63°

Step-by-step explanation:

x + 33 + 60 = 180 since they form a triangle.

x + 93 = 180

Subtract 93 from both sides

x = 87°

x and y are linear pairs so they're supplementary.

y + x = 180

y + 87 = 180

Subtract 87 from both sides

y = 93°

z + y + 24 = 180 since they also form a triangle

z + 93 + 24 = 180

z + 117 = 180

Subtract 117 from both sides

z = 63°

Hope this helped!

Oh and nannara nanke demo ii yo, ikasete yaru kara. :p

9514 1404 393

Answer:

  log4(2) = 0.5000

Step-by-step explanation:

You are being asked to figure out how to make the value 2 from the values 6 and 3. Your familiarity with arithmetic facts tells you ...

  2 = 6/3

Taking logs base 4, you have ...

  log4(2) = log4(6/3) = log4(6) -log4(3)

  log4(2) = 1.2925 -0.7925

  log4(2) = 0.5000

__

Additional comment

This is consistent with your knowledge of factors of 4:

  √4 = 4^(1/2) = 2

  log4(2) = 1/2

__

Here, we're using "log4" to mean the base-4 logarithm.

The fourth term a₄ of the sequence aₙ is 15

The definition of the function is given as

a(1)=-11

a(n)=a(n-1)x10

When this definition is rewritten properly, we have the following representation

a₁= 11

aₙ = aₙ₋₁ * 10

The above definitions imply that we simply multiply 10 and the previous term to get the current term

Using the above as a guide,

So, we have the following representation

a₂ = 11 * 10

Evaluate the products

So, we have

a₂ = 110

Also, we have

a₃ = 110 * 10

Evaluate the products

So, we have

a₃ = 1100

Lastly, we have

a₄ = 1100 * 10

Evaluate the products

So, we have

a₄ = 11000

This represents the 4th term of the sequence

Hence, the value of a₄ is 11000

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Answer:

A=12

Step-by-step explanation:

C=3

Answer:

Side a: 12

Side c: 4

Step-by-step explanation:

Answer:

tortilla chips, sails on boats, and slices of pizza

Step-by-step explanation:

Answer:

Nacho chips

Sails (As in sails on a sailing boat)

Sanwiches

Rooves

Answer: The length AC equals 10.25 cm (approximately)

Step-by-step explanation: Please refer to the diagram attached for further details.

The triangle has been constructed according to the dimensions provided with the top B going down to the "little square inside the triangle" which is C. This clearly identifies it as a right angled triangle. The point B meets with point C at the right angle and A is the sharp tip of the triangle, which makes point A the third angle. Hence we now have a right angled triangle with side AB measuring 11 cm, side BC measuring 4 cm and side AC is unknown.

We can now apply the Pythagoras' theorem which is stated as follows;

AC² = BC² + AB²

Where AC is the hypotenuse (longest side) and BC and AB are the other two sides. We can now substitute for the appropriate sides in this question as all the sides have been labelled differently. Hence,

BA² = BC² + CA²

11² = 4² + CA²

121 = 16 + CA²

Subtract 16 from both sides of the equation

105 = CA²

Add the square root sign to both sides of the equation

√105 = √CA²

10.2469 = CA

CA ≈ 10.25 cm

The third side AC (or CA) measures approximately 10.25 cm

The relative frequency of heads is reasonably close to 40%.Mr. Clark's claim about the theoretical probability is likely to be false. This means that the theoretical probability of tails is most likely 0.60.

The relative frequency is the ratio of the number of times an event occurred to the total number of trials. In this case, the relative frequency of heads is 0.38 and tails is 0.62.The theoretical probability of an event is the number of favorable outcomes divided by the total number of possible outcomes.

Here, Mr. Clark claims that the coin is weighted so that the probability of heads is 40%. Therefore, the theoretical probability of heads is 0.40.However, the relative frequency of heads after 200 trials is only 0.38, which is reasonably close to 0.40. Hence, the relative frequency of heads is reasonably close to 40%.

Mr. Clark's claim about the theoretical probability of heads is likely to be false because the relative frequency of heads is less than the theoretical probability of heads (0.38 < 0.40).Therefore, the theoretical probability of tails is 1 - 0.40 = 0.60 because the coin is fair, so the probabilities of heads and tails should add up to 1. Thus, the theoretical probability of tails is most likely 0.60.

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In all cases, we can find a pumped string \(xy^kz\) that does not belong to L₂, which contradicts the assumption that L₂ is regular. Therefore, L₂ is not regular.

To prove that the given languages L₁ and L₂ are not regular using the pumping lemma, we need to show that for any hypothetical regular language L.

There exists a pumping length p such that for any string s in L of length at least p, we can pump s in a way that the pumped string is not in L.

1. L₁ = {\(0^n1^n2^n\) | n ≥ 0, Σ = {0, 1, 2}}

Assume L₁ is regular and let p be the pumping length. Consider the string s = \(0^p1^p2^p\). This string is in L₁ because it has the form \(0^n1^n2^n\), where n = p.

By the pumping lemma, we can decompose s into three parts: s = xyz, such that:

1. |y| > 0

2. |xy| ≤ p

3. For all k ≥ 0, \(xy^kz\) is in L₁.

Let's consider different cases for the possible placement of y in s.

y contains only 0s (\(y = 0^m\), where 1 ≤ m ≤ p).

In this case, when we pump y (k > 1), the number of 0s will exceed the number of 1s and 2s, and hence the pumped string \(xy^kz\) will not be in L₁.

y contains both 0s and 1s (\(y = 0^m1^k\), where 1 ≤ m + k ≤ p).

In this case, when we pump y (k > 1), the number of 0s and 1s will not be balanced with the number of 2s, and hence the pumped string \(xy^kz\) will not be in L₁.

y contains only 1s (\(y = 1^k\), where 1 ≤ k ≤ p).

In this case, when we pump y (k > 1), the number of 1s will exceed the number of 0s and 2s, and hence the pumped string \(xy^kz\) will not be in L₁.

y contains both 1s and 2s (\(y = 1^m2^k\), where 1 ≤ m + k ≤ p).

In this case, when we pump y (k > 1), the number of 1s and 2s will not be balanced with the number of 0s, and hence the pumped string \(xy^kz\) will not be in L₁.

Thus, in all cases, we can find a pumped string \(xy^kz\) that does not belong to L₁, which contradicts the assumption that L₁ is regular. Therefore, L₁ is not regular.

2. L₂ = {ωωω | ω ∈ {a, b}*}

Assume L₂ is regular and let p be the pumping length. Consider the string \(s = a^pb^pa^pb^pa^pb\). This string is in L₂ because it has the form ωωω, where ω = \(a^pb^p\).

By the pumping lemma, we can decompose s into three parts: s = xyz, such that:

1. |y| > 0

2. |xy| ≤ p

3. For all k ≥ 0, \(xy^kz\) is in L₂.

Let's consider different cases for the possible placement of y in s.

y contains only a's (\(y = a^m\), where 1 ≤ m ≤ p).

In this case, when we pump

y (k > 1), the number of a's will exceed the number of b's in the first or second occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.

y contains only b's (\(y = b^m\), where 1 ≤ m ≤ p).

In this case, when we pump y (k > 1), the number of b's will exceed the number of a's in the second or third occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.

y contains both a's and b's (\(y = a^mb^n\), where 1 ≤ m + n ≤ p).

In this case, when we pump y (k > 1), the number of a's or b's will exceed the number of the corresponding symbol in the corresponding occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.

Thus, in all cases, we can find a pumped string \(xy^kz\) that does not belong to L₂, which contradicts the assumption that L₂ is regular. Therefore, L₂ is not regular.

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Complete Question

Use the pumping lemma to prove that the following languages are not regular:

L1 = {0^n 1^n 2^n | n ≥ 0, Σ = {0, 1, 2}}

L2 = {ωωω | ω ∈ {a, b}*}

For each language, apply the pumping lemma to show that there exists a pumping length (p) such that no matter how the string is divided into segments, it is not possible to pump the segments to generate all the strings in the language. This demonstrates that the languages are not regular.

The % below 20 = 98%, % between 11 and 17 = 68%, % above 14 = 50%, % between 5 and 17 = 83.9%. The solution has been obtained by using normal distribution.

What is normal distribution?

The normal distribution, often called the Gaussian distribution, is a symmetric probability distribution about the mean.

We know that normal distribution is expressed as

z = (x - µ) / σ

wherein,

x is the variable

µ is the mean output

σ is the standard deviation

We are given

µ = 14

σ = 3

a) P (x < 20)

So, here, x = 20

z = (20 - 14) / 3

z = 2

The corresponding probability value for this is 0.98.

So, this is equal to 98%.

b) P (11 ≤ x ≤ 17)

So, when x = 11

z = (11 - 14) / 3

z = -1

The corresponding probability value for this is 0.16.

Similarly, when x = 17

z = (17 - 14) / 3

z = 1

The corresponding probability value for this is 0.84.

From this, we get

P (11 ≤ x ≤ 17) = 0.84 - 0.16 = 0.68

So, this is equal to 68%.

c) P (x > 14)

This is same as 1 - P(x ≤ 14)

So, here x = 14

z = (14 - 14) / 3

= 0

The corresponding probability value for this is 0.5.

So,

P(x > 14) = 1 - 0.5 = 0.5

So, this is equal to 50%.

d) P (5 ≤ x ≤ 17)

So, when x = 5,

z = (5 - 14) / 3

z = -3

The corresponding probability value for this is 0.00135.

Similarly, when x = 17

z = (17 - 14) / 3

z = 1

The corresponding probability value for this is 0.84.

From this, we get

P(5 ≤ x ≤ 17) = 0.84 - 0.00135 = 0.839

So, this is equal to 83.9%

Hence, the required values have been obtained.

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The area of the acute triangle can be found by the formula: area of acute triangle = (1/2) × b × h.

According to Pythagoras theorem the triangle is termed as acutely angled if the square of its longest side is less than the sum of the squares of two other smaller sides. Let a, b, and c are the length of sides of a triangle, where side "a" is the longest, then the given triangle is acutely angled if and only if a^2 < b^2 + c^2.

The area of the acute triangle can be calculated by the formula:

         area of acute triangle = (1/2) × b × h

         b = base, and

         h = height

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Answer:

40 minutes

Step-by-step explanation:

rate = distance/time = miles/hr

rate = 240 mi/2 hr = 120 mi/hr

time = distance / rate = (80 mi)/(120 mi/hr) = 0.67 hr = 40 minutes

(0.67 hr)(60 min/hr) = 40 minutes

The percentile value to construct a 90% bootstrap confidence interval for the true mean amount of ammonium in the rainwater is equals to 5%.

If the bootstrap distribution is approximately symmetric, we can construct a confidence interval by finding the percentiles in the bootstrap distribution so that the proportion of bootstrap statistics between the percentiles matches the desired confidence level. We have a forest ranger which select a random rainwater sample from a watershed area in tennessee with

Sample size, n = 10

Ranger measures the amount of ammonium in each sample. Measurements to construct a 90% bootstrap confidence interval for true mean amount of ammonium in the rainwater. We have to determine the p-value for her ordered. Now,

The percentile bootstrap interval is just the interval between the 100×(α/2)100 and 100×(1−α/2) percentiles of the distribution of θ estimates obtained from resampling, where θ represents a parameter of interest and α is the level of significance. but we have to determine percentile value for 90% confidence interval. Here, level of significance for 90% is α = 1 - 0.90 = 0.10, α/2 = 0.05

So, percentile value = α/2 = 0.05

= 5%

The number of the bootstrap sample that must be chopped off to produce a 90% confidence interval is N = 10 ×α/2

=> N = 10× 0.05 = 0.5

Hence, required percentile value is 5%.

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The probability of scoring a goal exactly 8 times by Jon is given by 0.0234. It is obtained using the prerequisite knowledge of binomial distribution and probability.

What is Binomial Distribution in Probability?

When each trial has a probability of occurring equally likely, then the number of trials or observations is outlined using the binomial distribution. The chance of observing a specific number of successful outcomes in a specific number of trials is determined by using the binomial distribution.

Calculation of the probability of the given event

Total no. of possible outcomes, n = 11

The probability that Jon will kick the ball in the net, p(x) = 0.4

The probability that Alex will kick the ball in the net, q(x) = 0.6

Using Binomial Distribution, we get,

P(x = r) = C(n,r) × (p)r × q(n - r)

where x is the score made by Joe

P(x = 8) = C(11,8) × (0.4)8 × (0.6)3

             = 0.0234

Hence, the probability that Jon will score exactly 8 times is 0.0234.

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The sequence given by an = n^2 - 3n + 1, with n starting from 1, produces the values 0, 0, 2, 6, 12, 20, .... This sequence has a closed formula of a_n = (n-1)n, where n is a positive integer.

To find the first few terms of the sequence, we substitute the values of n starting from 1 into the formula an = n^2 - 3n + 1. This gives us the sequence: 0, 0, 2, 6, 12, 20, ....

To find the closed formula for the sequence, we can observe that each term is the sum of the previous term and n(n-1). In other words, a_n = a_(n-1) + n(n-1), where a_1 = 0. We can then use this recursive definition to find a closed formula. We start by finding the first few terms: a_1 = 0, a_2 = 2, a_3 = 6, a_4 = 12, a_5 = 20, ...

We notice that the difference between consecutive terms is n(n-1), so we can express the nth term in terms of the first term and the sum of n(n-1) from k=1 to n-1:

a_n = a_1 + ∑(k=1 to n-1) k(k-1)

Simplifying the sum using the formula for the sum of the first n integers and the sum of the first n squares, we get:

a_n = (n-1)n

Therefore, the closed formula for the sequence starting with a1 is a_n = (n-1)n, where n is a positive integer.

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The height of the building is 16 meters.

What is right triangle?

A right triangle is a type of triangle that has one of its angles measuring 90 degrees (π/2 radians). The side which is opposite to the right angle is the hypotenuse, while the other two sides are called the legs.

We can solve this problem using the Pythagorean theorem, which relates the sides of a right triangle. Let h be the height of the building. Then we can draw a right triangle with one leg of length h and the other leg of length 12m, representing the height and length of the shadow, respectively. The hypotenuse of this triangle is the distance from the top of the building to the tip of the shadow, which is 20m. So we have:

h² + 12² = 20²

Simplifying and solving for h, we get:

h² = 20² - 12²

h² = 256

h = sqrt(256)

h = 16

Therefore, the height of the building is 16 meters.

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The sum of these numbers is 45 + x.

Let x be the smallest of the three numbers.

Then the median of the three numbers, given as 15, must be either the second largest number or the smallest number.

Now, we have two possible cases:

Case 1: The median is the second largest number.

Since the median is the second largest number, the second largest number is 15.

Therefore, the three numbers can be written as follows: x, 15, y, where y is the largest number.

Then, we know that the mean of the three numbers is 20 more than the least of the numbers and 10 less than the greatest.

Mathematically, this can be written as:x + 15 + y / 3 = x + 20y - x - 15 = 30y - x = 45

Now, we can solve for y by substituting y - x = 45 into the expression for the mean:

x + 15 + y / 3 = x + 20y - x - 15

= 30y - x

= 45y

= 30

Therefore, the three numbers are x, 15, and 30.

Their sum is:

x + 15 + 30 = 45 + x

So the sum of these numbers is 45 + x.

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Answer:

y = 10x-37

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 10x+b

Substitute the point into the equation

3 = 10*4+b

3 = 40+b

Subtract 40

3-40 = 40+b-40

-37 = b

y = 10x-37

Answer: y = 10x - 37

Step-by-step explanation:

Hope it helps <3

if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.

To determine the total amount if the installment option is used, we need to calculate the total repayment over the 240-month term.

The installment amount per month is $4,500, and the repayment term is 240 months.

Total repayment = Installment amount per month * Repayment term

Total repayment = $4,500 * 240

Total repayment = $1,080,000

Therefore, if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.

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2) definition of right angles

3) substitution property of equality

4) definition of congruent angles

Answer:

The correct answer is \(-\frac{3}{4} x-3\)

Step-by-step explanation:

3/6=k/7

cross multiply then

6k=21

divide by the coefficient of k

k=3.5

Answer:

n=30

Step-by-step explanation:

n+30+2n-10+70=180

We move all terms to the left:

n+30+2n-10+70-(180)=0

We add all the numbers together, and all the variables

3n-90=0

We move all terms containing n to the left, all other terms to the right

3n=90

n=90/3

n=30

Answer:

26

Step-by-step explanation:

6.5 is 10% of 65, so to find 40% of 65 we multiply 6.5*4=26

Answer:

What we need to find here is, 40% of Landon's shirts.

Thus, 65*40/100 will give us the required answer!

= 26

Therefore 26 shirts of Landon are second hand and the rest are new(first hand)

Using the probability, if you choose two cards out of a deck of cards, then the chances one is a red face card and the other is a black non-face card is 1/2.

In the given question,

If you choose two cards out of a deck of cards, then we have to find the chances one is a red face card and the other is a black non-face card.

As we know that in a deck having 52 cards. In which 26 are red and 26 are black.

We have to choose a red face card.

As we know that in a deck have 12 face cards. In which 6 red face cards and 6 black face cards.

So the chance of getting red face card is

P(R)=Total number of red face cards/Total number of cards

P(R)=6/52

We have to choose a black non-face card.

We know that in a deck have 6 black face cards and total black cards are 26. So the non face cards are 20.

So the chance of getting black non-face card is

P(B)=Total number of black non-face cards/Total number of cards

P(B)=20/52

Now the chances of getting one is a red face card and the other is a black non-face card is

P(R or B)=P(R)+P(B)

P(R or B)=6/52+20/52

P(R or B)=(6+20)/52

P(R or B)=26/52

P(R or B)=1/2

Hence, if you choose two cards out of a deck of cards, then the chances one is a red face card and the other is a black non-face card is 1/2.

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Answer:

6=x

Step-by-step explanation:

Answer:

x=3

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    2*x-4-(4*x-10)=0

Answer:

I don't know ::{

Step-by-step explanation: