Hello, this is not a question just a pick up for yall having a bad day. you are beautiful in your own way! shine how you want. don't let anyone try to shape your figure or your future. if you are g-y or straight. black or white. a kid or a adult. love you for who you choose to be! don't be embarrassed by who you are. shine brighter than your haters! :)
i hope this will help your day if your down i love you all so much. remember you a strong in your own way :)

Answer:

If 99.995 A  pass thru a shunt and 5 mA pass thru the meter, the meter will have full scale deflection for a current of 100 A.

By Ohm's Law  

99.995 Rs = .005 Rm

Rs = .005 / 99.995 * 120

Rs = .006 ohms

Using a shunt resistance of .006 Ω will produce the required result.

The value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of 0.0012 ohms.

The value of the shunt resistor (Rs) is:

Rs = (Rm × Im) ÷ (If - Im)

where:

Rs = Shunt resistor value

Rm = Resistance of the milliammeter

Im = Full-scale current of the milliammeter

If = Maximum current we want to measure

The shunt resistor value:

Rs = (120 × 5 ) ÷ (100  - 5)

Rs = (0.12 ) ÷ (100 - 0.005)

Rs = 0.12 ÷ 99.995

Rs = 0.00120018 ohms

Since the value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of  0.0012 ohms.

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A matter can be separated into three states.

Answer:

Your answer is Jumping

Explanation:

Answer:

jumping

Explanation:

Answer:

In January 2012, Compton suffered a heart attack. On 25 February 2012, he died at one of his daughters' home in Washington. His wife Donna preceded him in death in 1994. Buck Compton was survived by two daughters and four grandchildren.

Explanation:

In January 2012, Compton suffered a heart attack. On 25 February 2012, he died at one of his daughters' home in Washington. His wife Donna preceded him in death in 1994. Buck Compton was survived by two daughters and four grandchildren.

Answer:

22/25 m/s^

Explanation:

The magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².

In this system, the force of gravity acts on both boxes, but the tension in the rope is the same on both sides of the pulley, so it cancels out. The frictional force acts only on the 20 kg box, opposing its motion to the right.

To find the acceleration of the 20 kg box, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:

Net force = mass x acceleration

The net force on the 20 kg box is the force of gravity pulling it down minus the force of friction opposing its motion to the right:

net force = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) = 156.8 N

The net force on the 5 kg box is the force of gravity pulling it down plus the tension in the rope pulling it up:

Net force = (5 kg)(9.8 m/s²) + T

Since the tension is the same on both sides of the pulley, we can set these two equations equal to each other and solve for the tension:

T = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) - (5 kg)(9.8 m/s²) = 93.68 N

Now we can use the net force on the 20 kg box to find its acceleration:

Net force = (20 kg) x acceleration

156.8 N = (20 kg) x acceleration

Acceleration = 7.84 m/s²

Therefore, the magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².

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Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer: Debbie exerts applied force on the first cart.

Explanation:

The first cart exert applied force on the second cart.

Answer:

Answer:

15.67 seconds

Explanation:

Using first equation of Motion

Final Velocity= Initial Velocity + (Acceleration * Time)  

v= u + at

v=3

u=50

a= - 4 (negative acceleration or deceleration)  

3= 50 +( -4 * t)

-47/-4 = t

Time = 15.67 seconds

We have that the speed  must be at the speed below if they want to just hit their target

From the Question we are told that

Distance \(d=50m\)

Height \(h=70m\)

Constant Velocity \(v= 7.0 m/s\)

Generally the equation for the time  is mathematically given as

\(T=\frac{h}{v}\\\\T=\frac{70}{7}\\\\T=10s\)

Therefore

The velocity required to make horizontal movement is

\(V=\frac{d}{T}\\\\V=\frac{50}{10}\\\\V=5m/s\)

Given that

Velocity on the Vertical axis is

\(v_y=7m/s\)

Velocity on the  horizontal axis is

\(v_x=5m/s\)

Therefore resultant speed

\(v_r=\sqrt{v_x^2+V_y^2}\\\\v_r=\sqrt{(5)^2+(7)^2}\)

\(v_r=8.6023m/s\)

In conclusion

\(v_r=8.6023m/s\) must be their total speed if they want to just hit their target

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The velocity of the car 1 can be seen from the calculation as 20 m/s West

A coordinate system or point of view used to observe motion is known as a frame of reference. It can be used as a guide when describing an object's position, speed, and acceleration. Different frames of reference may result in various motion observations.

The relative velocity is the velocity of an object or observer as observed from a particular frame of reference.

We can see that the velocity of the car 1 is;

45 m/s - 25 m/s

= 20 m/s West

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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A white-hot iron piece has internal motion energy due to constant particle movement at the atomic and molecular levels, as per scientists. Thermal energy or heat energy is motion. Higher temperature means more kinetic energy and faster motion of atoms and molecules.

White-hot iron vibrates atoms and molecules at high temperatures. Kinetic theory states that all matter is made up of moving particles. Motion occurs at the microscopic level, beyond eye view. Higher temperature = greater particle energy.

When a scientist refers to white-hot iron, they recognize its high temperature corresponds to increased kinetic energy and motion. Motion and energy at the atomic level are not visible like a bowling ball, but are fundamental traits of matter.

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The initial temperature of the metal bolt is 80.8 °C

We'll begin by calculating the heat absorbed by the water.

Q = MCΔT

Q = 0.15 × 4184 × 4

Q = 2510.4 J

Finally, we shall determine the initial temperature of the metal bolt.

Q = MC(T₂ – T₁)

–2510.4 = 0.050 × 899 (25 – T₁)

–2510.4 = 44.95 (25 – T₁)

Clear bracket

–2510.4 = 1123.75 – 44.95T₁

Collect like terms

–2510.4 – 1123.75 = –44.95T₁

–3634.15 = –44.95T₁

Divide both side by –44.95

T₁ = –3634.15 / –44.95

T₁ = 80.8 °C

Thus, the initial temperature of the metal is 80.8 °C.

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Answer:

There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

 Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

 Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

Explanation:

PF

Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

 Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

 Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

Answer:

a = 0.9139 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

The forces are on two different axes, x & y axes (North and East). In this way, the Pythagorean theorem should be used to determine the total force.

Fx = 1800 [N]

Fy = 1050 [N]

\(F = \sqrt{(F_{x} )^{2} +(F_{y} )^{2} } \\F=\sqrt{(1800)^{2} +(1050)^{2} } \\F=2083[N]\)

Now using Newton's second law.

ΣF = m*a

where:

F = force = 2083.8 [N] (units of Newtons)

m = mass = 2280 [Kg]

a = acceleration [m/s²]

2083.8 = 2280*a

a = 0.9139 [m/s²]

The angle below the horizontal of the velocity of the puck just before it hits the ground is 12.6°.

Given:

v₀x=28m/s

v₀y=0m/s

y₀=2.00m

x₀=0m

we know that velocity of an object is defined as the speed of that thing in a direction. rate of change in  the velocity is acceleration . so here  first we are calculating the time and then we are finding the speed of the object

yf=y₀+v₀yt+1/2at²

yf=0

0=2.00m+0m/s+1/2(−9.8m/s²)t²

4.9 m/s² t²=2.00m

t=1.025s

Then using time to calculate the final x-position...

x=x₀+v₀xt+1/2at²

x=0m+(28ms)(0.64s)+0

x=28.7m/s

After we got the speed then finally we are putting that in a triangle and we are finding the angle.

tan(θ)=2.00/28.7

θ=12.6°

So from the above we got that the angle is 12.6°

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The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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The constant acceleration of the green car which passes red color car is  2.81 m/s^2.

In this problem, the initial positions of the red and green cars are xr = 0 and xg = 220 m, respectively, and their initial velocities are vr = 20 km/h and vg = 0. When the red car has a velocity of 20 km/h, the cars pass each other at x = 44.5 m, and when the red car has a velocity of 40 km/h, they pass each other at x = 76.6 m.

We can use these two equations to solve for the acceleration of the green car. First, we convert the velocities from kilometers per hour to meters per second by dividing by 3.6. This gives us vr = 5.56 m/s and vg = 0 m/s.

Then, we can substitute these values into the equation for position and solve for the acceleration. When the red car has a velocity of 20 km/h, the equation becomes:

x = 0 + 5.56t + 1/2at^2

x = 44.5

Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.

When the red car has a velocity of 40 km/h, the equation becomes:

x = 220 + 11.11t + 1/2at^2

x = 76.6

Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.

When the red car has a velocity of 40 km/h, the equation becomes:

x = 220 + 11.11t + 1/2at^2

x = 76.6

Solving for a, we find that the acceleration of the green car is a = 3.02 m/s^2.

Since the acceleration is the same in both cases, we can take the average of these two values to find the constant acceleration of the green car. The average of 2.61 m/s^2 and 3.02 m/s^2 is 2.81 m/s^2.

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Answer:

Carbohydrates are divided into four types: monosaccharides, disaccharides, oligosaccharides, and polysaccharides. Monosaccharides consist of a simple sugar; that is, they have the chemical formula C 6 H 12 O 6. Disaccharides are two simple sugars. Oligosaccharides are three to six monosaccharide units, and polysaccharides are more than six.

a) Resultant velocity is 15.63 m/s.

b) Resultant  velocity is 12.97m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

a)  A surfer traveling at 1.5 m/s relative to the water across a wave that is traveling at 5.5 m/s.

Resultant velocity = √(1.5²+5.5²) m/s = 15.63 m/s.

b)  A  fish swimming at 2.5 m/s relative to the water across a river that moves at 4.5 m/s.

Resultant  velocity = √(2.5²+4.5²) m/s = 12.97m/s.

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The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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The radius of the Rigel bright blue star and the procyan B is found to be   5.4x10¹⁰m and 5.4x10⁶m

Using the surface radiation formula P (energy per second in Watt) = emissivity constant * surface area * Stefan-boltzmann constant * temperature in kelvin4*.

2.7x10³¹ = 1x5.67x10⁻⁸xAx11000⁴

Making A Formula Subject = 2.7x10³¹/ (5.67*10⁻⁸x1.46x10¹⁶) = 0.3261x10²³m²

The surface area = 4R² since the form is a spherical (radius of the Rigel)

R = √ (0.3261x10²³/ 4π) = 5.1 x 10¹⁰m

The radius of the Rigel star is 5.1 x 10¹⁰m.

B) repeating the previous step

2.1x10²³ = 1xAx5.67x10⁻⁸x1000⁴, where A is the Procyon's surface area.

Creating a formula topic,

A = 2.1x10²³/(5.67x10⁻⁸x10¹⁶)

A = 0.37x10¹⁵

The star is thought to be a spherical;

A = 4R², where R is Procyon's radius.

R = √(0.37x10¹⁵/4π) = 5.4x10⁶m

The radius of the Procyan B is  5.4x10⁶m.

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Answer: a. The moment the ball leaves the athlete's hand traveling upwards, reaches maximum height, then traveling downward till the moment just before the athlete catches it.

I think this is the answer. In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. The body is moving only under the influence of the earth's gravity.

Brainliest please if the answer is clear and correct! <3 ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

The work done on 85 N boxes of books while carried horizontally 4m across a room is equal to zero. Therefore, option (C) is correct.

Work can be demonstrated as the energy used when a force is exerted to move an object through a definite displacement. The work done defines both the exerted force on the object and the distance moved by the object.

The applied force moves an object in a straight line in the direction of the exerted force over a displacement 'd'.

W= F × d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Given, the weight of the box = 80 N

The displacement , d = 4 m

In order for to work to be done the box should move in the direction of exerted force as the books are moving forward direction and the applied force in an upward direction to carry the box.

Therefore, the distance moved in the direction of force is zero so the work done is also equal to zero.

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Answer:

A) -40° C and -40° F

B) 574.25° K and 574.25° F

Explanation:

see attachment for calculation and explanation

Answer:

Holes are formed when electrons in atoms move out of the valence band (the outermost shell of the atom that is completely filled with electrons) into the conduction band. (the area in an atom where electrons can escape easily) which happens everywhere in a semiconductor. When an electron and a hole interact and recombine the energy is not transferred into heat energy or thermal vibrations. instead the energy is transferred into an electron within the conduction band which is then promoted to an energy higher in condition band.

Explanation:

So considering that information, electrons and holes make a semiconductor when moving.

The total energy in a rotation is the sum of the rotational kinetic energy

and the potential energy of torsion.

Reasons:

When external forces are applied to the system, the total mechanical

energy changes and the rotational kinetic energy depends on the work the

torque applied does. Therefore, when the force applied reduces friction,

the rotational kinetic energy can be conserved.

The rotational kinetic energy is given by the equation, \(\displaystyle E_{rotational} = \frac{1}{2} \cdot I \cdot \omega ^2\)

Where;

I = The moment of inertia of the object

ω = The angular speed of the object

Therefore, correct response is the rotational kinetic energy is proportional to the moment of inertia I.

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The speed of the hoop when it has rolled halfway up the side of the pipe is √(v₀² - gR).

The speed of the hoop when it has rolled halfway up the side of the pipe is calculated as follows;

K.E = P.E

- ¹/₂mv₀²  + ¹/₂Iω² = (mgh₀ - mghf)

- ¹/₂mv₀²  + ¹/₂Iω² = (0 - 0.5mgh)        (hf = 0.5h) (half way up)

¹/₂Iω² = ¹/₂mv₀² - 0.5mgh  

where;

¹/₂(mr²)(vf/r)² = ¹/₂mv₀²  - 0.5mgh

¹/₂vf²  = ¹/₂v₀² - ¹/₂gh  

vf²  = v₀² - gh

vf = √(v₀² - gh)

where;

vf = √(v₀² - gR)

\(v_f = \sqrt{v_0^2 - gR}\)

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Answer:

no..

Explanation:

in balanced force it will or in this case u would stay still or u would move at the same speed.. but when u jumps the speed changes..so this is an unbalanced force

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