find the slope of the graphed line though each pair of points​

Answer:

-235+84i

Step-by-step explanation:

I hope this is what you were looking for.

Answer:

So this angle is an acute angle so it would be around 60 so i think its D

Step-by-step explanation:

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The length of the diagonal of a square with a perimeter of 56 is 14√2.

A diagonal is the longest line that divides a plane shape into two equal parts.

To calculate the length of the diagonal of the square, first we need to find the length of the square using the perimeter formula.

Formula:

Where:

From the question,

Given:

Substitute the value into equation 1 and solve for a

Finally to find the length of the diagonal of the square, we use the formula below

Where:

Substitute into equation 2

Hence, the length of the diagonal is 14√2.

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Answer:

qfewwqeffwqfefewqwqreg

Step-by-step explanation:

The equation that could be used to determine x, the number of purses Paula must sell to pay for the new equipment is;

A. 5.00x - 2.25x = 5000

We are told the materials costs $2.25 per purse.

She sells the materials for $5 each.

If the number of materials she purchased was x, it means that;

Selling price - Cost price = 5.00x - 2.25x

Now, we are told that she wants to invest $5000 for some new equipment. This means that she must realize at least $5000 in profit from the sales she is making of the materials.

Since the formula for profit is;

Profit = Selling Price - Cost Price

Then, we will have;

5.00x - 2.25x = 5000

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Answer:  5.00x - 2.25x = 5000

Step-by-step explanation:

Answer:

-15

Step-by-step explanation:

The solution of expression for x = - 4 is,

⇒ - 15

We have to given that,

An expression is,

⇒ 2x - 7

Now, We can simplify the expression for x = - 4 as,

An expression is,

⇒ 2x - 7

Plug x = - 4;

⇒ 2 × - 4 - 7

⇒ - 8 - 7

⇒ - 15

Thus, The solution of expression for x = - 4 is,

⇒ - 15

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We have the next function to find the solutions:

Then, the amount after 7 hours is 3323 grams, and after 60 hours is 241 grams.

\(\sqrt{25*7x^{4}*x^{1} } \\=\sqrt{25*x^{4}*7 *x^{1} } \\=\sqrt{25x^{4} } *\sqrt{7x}\\=5x^{2} \sqrt{7x}\)

Option B is the answer.

Answer: C

i hope you can see my handwriting

The surface area of the base ball to the nearest whole number is 26 in²

A sphere is defined as the set of all points in three-dimensional Euclidean space that are located at a distance.

The area occupied by a three-dimensional object by its outer surface is called the surface area.

The surface area of a sphere is expressed as;

SA = 4πr²

where r is the radius and it's calculated as;

C = 2πr

9 = 2πr

r = 4.5/π =

SA = 4 π × (4.5/π)²

SA = 81/π

SA = 26 in²( nearest whole number)

Therefore the surface area of the sphere is 26 in²

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Step-by-step explanation:

the answer would be to deduct/minus that number from 180, the reason for this is because a triangles 3 angles add up to 180°, so if a triangle is labeled ABC and angle A is 70°, you would do 180 - 70(Angle A) which would give you 110°, meaning those other two angles would have to add up to 110, now if you have an equilateral triangle, the answer is really simple, 60° for each side.

It took Ringani 2.8 years  to accumulate the total amount of R30,000.00 by depositing R8,500.00 yearly into the account with a 7.04% interest rate Compounded annually.The correct answer choice is C. 2.8 years.

To determine how long it took Ringani to accumulate the total amount of R30,000.00 by depositing R8,500.00 yearly into an account with a 7.04% interest rate compounded annually, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount

P is the principal amount (initial deposit)

r is the interest rate (in decimal form)

n is the number of times the interest is compounded per year

t is the time in years

In this case, we have:

P = R8,500.00

A = R30,000.00

r = 7.04% = 0.0704 (in decimal form)

n = 1 (compounded annually)

We want to find the value of t.

Using the formula, we can rearrange it to solve for t:

t = (log(A/P)) / (n * log(1 + r/n))

Substituting the given values, we have:

t = (log(30,000/8,500)) / (1 * log(1 + 0.0704/1))

Calculating this using a calculator, we find that t is approximately 2.8 years.

Therefore, it took Ringani approximately 2.8 years (rounded to one decimal place) to accumulate the total amount of R30,000.00 by depositing R8,500.00 yearly into the account with a 7.04% interest rate compounded annually.

The correct answer choice is C. 2.8 years.

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Answer:

too hard reeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

Answer:

(a) A(0)= 0 (kg)

(b) \(R_{in}=0.28\dfrac{kg}{min}\)

(c) \(C(t)=\dfrac{A(t)}{2840}\)

(d) \(R_{out}=\dfrac{A(t)}{710}\)

(e) \(\dfrac{dA}{dt}=0.28-\dfrac{A(t)}{710}\)

Step-by-step explanation:

A tank contains 2840L of pure water.

A solution that contains 0.07 kg of sugar per liter enters a tank at the rate 4 L/min. The solution is mixed and drains from the tank at the same rate.

(a) Amount of sugar initially in the tank.

Since the tank initially contains pure water, the amount of sugar in the tank

A(0)= 0 (kg)

(b) Rate at which the sugar is entering the tank. (kg/min)

\(R_{in}\)=(concentration of sugar in inflow)(input rate of the solution)

\(=(0.07\dfrac{kg}{liter}) (4\dfrac{liter}{min})\\R_{in}=0.28\dfrac{kg}{min}\)

(c) Concentration of sugar in the tank at time t

Volume of the tank =2840 Liter

Concentration c(t) of the sugar in the tank at time t

Concentration, C(t)= \(\dfrac{Amount}{Volume}\)

\(C(t)=\dfrac{A(t)}{2840}\)

(d) Rate at which the sugar is leaving the tank

\(R_{out}\)=(concentration of sugar in outflow)(output rate of solution)

\(=\dfrac{A(t)}{2840})( 4\dfrac{Liter}{min})=\dfrac{A}{710}\\R_{out}=\dfrac{A(t)}{710}\)

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

\(\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.28-\dfrac{A(t)}{710}\)

Answer:

to the nearest tenth)?

First, we need to find the volume of the cylinder. Since we have the height and are trying to find the radius, we can use the formula for the volume of a cylinder:

V = πr^2h

where V is the volume, r is the radius, and h is the height.

We don't know the volume of the cylinder, but we can use the volume of the cone and the fact that the cone and cylinder share a base to find the radius. The volume of a cone is given by:

V = (1/3)πr^2h

where V is the volume, r is the radius, and h is the height.

We know that the height of the cone is 9 meters and its volume is 57 cubic meters, so we can set up an equation:

57 = (1/3)πr^2(9)

Simplifying, we get:

19 = πr^2

Dividing both sides by π and taking the square root, we get:

r ≈ 2.2

Therefore, the radius of the cylinder is about 2.2 meters (rounded to the nearest tenth).

The equivalent expressions of 45 + 2i are (13 + 4i) + (32 - 6i) and  (9 + 4i) + 2(4 + 7i)(1 - 2i)

From the question, we have the following parameters that can be used in our computation:

Complex number: 45 + 2i

Next, we test the options:

(13 + 4i) + (32 - 6i) = 13 + 4i + 32 - 6i

(13 + 4i) + (32 - 6i) = 45 - 2i --- true

(13 + 4i) + 2(7 + 2i)(2 -i) = (13 + 4i) + 2(14 - 7i + 4i - 2)

(13 + 4i) + 2(7 + 2i)(2 -i) = 13 + 4i + 28 - 14i + 8i - 4

(13 + 4i) + 2(7 + 2i)(2 -i) = 37 - 2i --- false

(2 + 8i) + (30 - 6i) = 2 + 8i + 30 - 6i

(2 + 8i) + (30 - 6i) = 32 + 2i--- false

(9 + 4i) + 2(4 + 7i)(1 - 2i) =  (9 + 4i) + 2(4  - 8i + 7i + 14)

(9 + 4i) + 2(4 + 7i)(1 - 2i) =  9 + 4i + 8  - 16i + 14i + 28

(9 + 4i) + 2(4 + 7i)(1 - 2i) =  45+ 2i --- true

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Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

Answer:

25 Starburst

15 Twizzlers

========================================================

Explanation:

The ratio of Jolly Ranchers to Starburst to Twizzlers is 7:5:3

It means that you could have 7 Jolly Ranchers, 5 Starburst, and 3 Twizzlers.

In reality you actually have 35 Jolly Ranchers. So we'll multiply that "7" by 5. Do the same thing to all parts of the ratio to keep things balanced.

The ratio 7:5:3 scales up to its equivalent form 35:25:15

Answer:

Location AB BC AC m∠ABC m∠BAC m∠ACB

A(3, 4), B(1, 1), C(5, 1) 3.61 units 4 units 3.61 units 56.31° 67.38° 56.31°

A(4, 5), B(2, 1), C(7, 3) 4.47 units 5.39 units 3.61 units 41.63° 82.87° 55.49°

A(3, 6), B(3, -2), C(-3, -2) 8 units 6 units 10 units 90° 36.87° 53.13°Step-by-step explanation:

According to the locations given in the table, diagrams have been attached using GeoGebra.

GeoGebra is a dynamic mathematics software for all levels of education that brings together geometry, algebra, spreadsheets, graphing, statistics and calculus in one engine.

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a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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he two numbers that multiply to -35 and add to get -18 are -5 and 3.

To see why, you can use the factoring method. First, find two numbers that multiply to give you -35. The factors of -35 are -1, 1, -5, and 5. So, the two numbers that multiply to -35 are either -5 and 7 or 5 and -7.

Next, find which pair of numbers adds up to -18. It's clear that 5 and -7 add up to -2, so they don't work. However, if we choose -5 and 3, we get:

-5 + 3 = -2

So, -5 and 3 are the two numbers that multiply to -35 and add to -18.

Answer:

x=1 y=4

Step-by-step explanation:

8x+y=12

-3x+y=1

3x-y=-1

8x+y+3x-y=12-1

11x=11

x=1

y=12-8x=12-8=4

Step-by-step explanation:

For the left end of the function, it moves up towards positive infinity.

For the right end of the function, it movea down towarda negative infinity.

Therefore as x approaches -infinity, y approaches +infinity and as x approaches +infinity, y approaches negative infinity. (2nd option)

The amount (present value at age 60) that Sandro would neet in his retirement savings account in order to have a monthly income of $1,500 until he is 90 years old, compounded at 4.5% monthly is $296,041.74.

The present value is computed using an online fiance calculator that discounts the future withdrawals (monthly income) for a 360-months period.

End of withdrawal period = 90 years old

Beginning of withdrawal period = 60 years old

The number of years between 60 and 90 = 30 years

N (# of periods) = 360 months (30 years x 12)

I/Y (Interest per year) = 4.5%

PMT (Periodic Payment) = $-1,500

FV (Future Value) = $0

Results:

Present Value (PV) = $296,041.74

Sum of all periodic payments = $540,000 ($1,500 x 360 months)

Total Interest = $243,958.26

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Answer:

60 minutes is 20% of 300%

Step-by-step explanation:

The shape of the data that we have here is skewed to the right

A dataset is considered to be right-skewed (sometimes known as excessively positive) when the greater portion of its data points are concentrated on the lower end, forming an asymmetrical distribution that has a long tail to the right.

As such, the mean (average) within these distributions generally surpasses the median in value, with the latter also exceeding the mode.

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Answer:

12

Step-by-step explanation:

Given that,

f(x) = 2x² - 3x + 7

To find the value of f ( 2.5 ), replace x with 2.5 and solve the equation.

Let us solve it now.

f(2.5) = 2(2.5)² - 3×2.5 + 7

f(2.5) = 12.5 - 7.5 + 7

f(2.5) = 12

Answer:

\(f(x) = 2 {x}^{2} - 3x + 7 \\ f(2.5) = 2 {(2.5)}^{2} - 3(2.5) + 7 \\ f(2.5) = 12.5 - 7.5 + 7 \\ \boxed{f(2.5) = 12}\)

Now we can see that our fraction is 30/100, which means that 12/40 as a percentage is 30%.

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Julio will be 30 years old when his father is twice his age.

To determine the age at which Julio will be twice his father's age, we need to find the age difference between them and then add that difference to Julio's current age.

Currently, Julio is 12 years old, and his father is 42 years old. The age difference between them is 42 - 12 = 30 years.

For Julio to be twice his father's age, the age difference needs to remain the same as it is currently. Therefore, when Julio is x years old, his father will be x + 30 years old.

Setting up an equation to solve for x:

x + 30 = 2x

Simplifying the equation, we subtract x from both sides:

30 = x

Thus, when Julio is 30 years old, his father will be 30 + 30 = 60 years old. At this point, Julio will indeed be twice his father's age.

Therefore, Julio will be 30 years old when his father is twice his age.

Note : the translated question is Julio is 12 years old and his father is 42 years old. How old will Julio be when his father is twice his age?

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