Find the perimeter of the figure below, composed of an isoceles trapezoid and one semicircle. Rounded to the nearest tenths place

According to the unitary method,

A) The time taken for Peter to finish the job alone is 4 hours, 48 minutes.

B) The time taken for Emily and Peter to finish the job together is 2 hours, 36 minutes.

Unitary method:

In math, unitary method refers the process of finding the value of a single unit, and based on this value.

Given,

Emily, Ashley and Peter can clean a warehouse in 2 hours. If Emily does the job alone, she can finish it in 6 hours. If Ashley does the job alone she can finish it in 8 hours.

Here we need to find the following:

A) The time take for Peter to finish the job alone

B) The time taken for Emily and Peter to finish the job together

Let us consider x be the time taken for Peter to finish the job alone.

So, based on the given question we can write it as,

=> 1/6 + 1/8 + 1/x = 1/2

=> (8 + 6)/48 + 1/x = 1/2

=> 14/48 + 1/x = 1/2

=> 7/24 + 1/x = 1/2

=> 1/x = 1/2 - 7/24

=> 1/x = 12 -7/24

=> 1/x = 5/24

=> x = 24/5

=> x = 4.8

So, the time taken for Peter to finish the job alone is 4 hours, 48 minutes.

Then the time taken for Emily and Peter to finish the job together is calculated as,

=> 5/24 + 1/6

=> 5 + 4/ 24

=> 9/24

=> 3/8

Therefore, the time taken for Emily and Peter to finish the job together 2 hours, 36 minutes.

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The LCM of A = 3² × 5⁴ × 7 and B = 3⁴ × 5³ × 7 × 11 is 3898125 using Prime factorization.

Given are two numbers which are showed in the prime factorized form.

A = 3² × 5⁴ × 7

B = 3⁴ × 5³ × 7 × 11

Prime factorization is the factorization of a number in terms of prime numbers.

In order to find the LCM of these two numbers, we have to first match the common primes and write down vertically when possible and then bring down the primes in each column.

A = 3² ×         5³ × 5 × 7

B = 3² × 3² × 5³ ×       7 × 11

Bring down the primes in each column.

LCM = 3² × 3² × 5³ × 5 × 7 × 11

        = 3898125

Hence the LCM is 3898125.

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Answer:

Here's an interesting project idea for mathematics that can relate three different topics:

Topic 1: Fractals

Topic 2: Chaos Theory

Topic 3: Differential Equations

Research Question: Can fractals be used to model chaotic systems described by differential equations?

In this project, you can explore the concept of fractals and their applications in modeling complex systems. You can also delve into chaos theory and differential equations to understand how they are used to describe chaotic systems. By combining these three topics, you can investigate whether fractals can provide a better understanding of chaotic systems by modeling them more accurately.

Your research paper can cover the following areas:

Introduction: Provide an overview of fractals, chaos theory, and differential equations, and explain their relevance to the research question.

Fractals: Discuss the properties of fractals and how they can be used to model complex systems. Provide examples of fractals in nature and technology.

Chaos Theory: Explain the concept of chaos and how it is described by differential equations. Discuss the importance of chaos theory in understanding complex systems.

Differential Equations: Provide an overview of differential equations and their applications in physics, engineering, and other fields. Explain how differential equations are used to model chaotic systems.

Combining the three topics: Explain how fractals can be used to model chaotic systems described by differential equations. Provide examples of fractals used in modeling chaotic systems and compare the results to traditional methods.

Conclusion: Summarize the findings of your research and discuss the implications of using fractals to model chaotic systems.

Overall, this project can be a challenging and rewarding exploration of the interplay between three different mathematical topics.

Step-by-step explanation:

Answer

925 students brought their lunch.

Explanation

First let's rewrite the equation.

You know that "of" means multiply and "is" means equal.

Okay, so let's break it down.

The question says, "At your school, 74% of students brought their lunch at the cafeteria. There are 1250 students in the school."

This means that 74% of 1250 students brought their lunch at the cafeteria.

You are trying to find how many students brought their lunch. This will be x.

So the equation would be this.

74% × 1250 = x

74% is 0.74.

0.74 × 1250 = x

0.74 × 1250 = 925

So 925 students brought their lunch.

we get that

so the missing value is

so the answer is c

A moviegoer sees 7632 frames in 159s.

Answer:

-729

Step-by-step explanation:

sequence is to multiply by -3 to get next term

Given -

To find -

Explanation -

Here as we are required to find the value of two different individuals hence first we will from 2 linear equations into two variables (taking each to be value as x and y or whatever you like, I will take them as a and b) will solve the equation by any method of your choice (explanation for them is in the link, below, it is given by the same me)

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Solution -

Let the sum of money that was given to each boy be a and the number of boys be b. Hence, the total no. of money distributed to b no. of boys is ab.

According to the question,

Scenario 1 -

➡ (a + 2)(b - 10) = ab

Solving it further,

➡ a(b - 10) + 2(b - 10)= ab

➡ ab - 10a + 2b - 20= ab

Cancelling ab,

➡ 10a - 2b + 20 = 0

➡ 10a = 2b - 20

➡ a = 2(b - 10)/10

➡ a = (b - 10)/5

Scenario 2 -

➡ (a - 2)(b + 15) = ab

Solving it further,

➡ a(b + 15) - 2(b + 15)= ab

➡ ab + 15a - 2b - 30= ab

Cancelling ab,

➡ 15a - 2b - 30 = 0

Substituting the value of a in the equation,

➡ 15{(b - 10)/5} - 2b - 30 = 0

➡ 3(b - 10) - 2b - 30 = 0

➡ 3b - 30 - 2b - 30 = 0

➡ 3b - 2b -60 = 0

➡ b = 60

Substituting the value of b in a = (b - 10)/5,

➡ a = (60 - 10)/5

➡ a = 50/5

➡ a = 10

[Here we have used the substitution method]

Henceforth, the total number of boys is 60 and the sum received by each is Rs. 10 .

Answer:

D but see below.

Step-by-step explanation:

It can be factored if you are allowed to use square roots.

(p + 5√5)(p - 5√5)

Usually, you are not allowed to do that. Usually you must be working with whole numbers or rational well behaved fractions.

I think, given the above comment, the answer is D

The solution to the system of equations is (x, y) = (-261/47, 44/47) as an ordered pair.

To solve the given system of equations:

Equation 1: 8x + 9y = -36

Equation 2: x + 7y = 1

We can use the method of substitution or elimination to find the values of x and y. Let's use the method of substitution:

From Equation 2, we can solve for x:

x = 1 - 7y

Substituting this value of x into Equation 1:

8(1 - 7y) + 9y = -36

8 - 56y + 9y = -36

-47y = -44

y = 44/47

Substituting the value of y back into Equation 2 to find x:

x + 7(44/47) = 1

x + 308/47 = 1

x = 1 - 308/47

x = (47 - 308)/47

x = -261/47

Therefore, as an ordered pair, the solution to the system of equations is (x, y) = (-261/47, 44/47).

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Answer:

P = 20 ft

h = 2 ft

B = 10.56 ft²

Step-by-step explanation:

P = 8.8 + 8.8 + 1.2 + 1.2 = 20 ft

h = 2 ft

B = 1.2 x 8.8 = 10.56 ft²

Answer:

The question isn't clear. Can you provide more information or context? What is A? Is it a set or a number? Without this information, I can't provide a meaningful answer.

The probability of selecting a girl and a boy for the class committee can be calculated by considering the total number of outcomes and the number of favorable outcomes.

Identify the number of girls and boys in the class. In this case, there are 5 girls and 7 boys.

Determine the total number of students in the class. That is 5 + 7 = 12.

Determine the number of ways to select two students from the class.

Here we can use the combination formula, which is written as C(n, r), where n is the total number of items and r is the number of items to be chosen.

In our case, n = 12 (total number of students) and r = 2 (number of students to be selected).

C(12, 2) = 12! / (2!(12-2)!) = 66.

Determine the number of favorable outcomes.

In this case, we want to select one girl and one boy. We multiply the number of girls by the number of boys: 5 x 7 = 35.

To find the probability, we divide the number of favorable outcomes (35) by the total number of outcomes (66):

Probability = Number of favorable outcomes / Total number of outcomes = 35 / 66 = 5/6.

So, the probability of selecting a girl and a boy for the class committee is 5/6.

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We know that cos(45) = sin(45) = √2/2.

Substituting these values, we can simplify the expression as follows:

4cos(45) - 2sin(45)

= 4(√2/2) - 2(√2/2) (substituting cos(45) and sin(45) values)

= 2√2 - √2

= √2

Therefore, the answer is √2.

Answer:

78.93 yan ats yung sagot hula ko

Answer:

it is 78.93 yun

hope this will help you

Answer:

$ 3750  = truck rental;   $125 per ton of sugar transported

C is cost;  S is number of tons transported

Equation relating C to S would be a linear equation like y = mx + b

C = 125S + $3750

This equation would be graphed in the first quadrant only

you would start with your y-intercept at (0, 3750)

As x increases by 1, your y increases by 125 yielding these points:

(1, 3875)  (2, 4000)  (3, 4125)  etc.  

This shows that for each increase by one ton of sugar, the cost goes up $125

Step-by-step explanation:

It should be A. The distance between Jupiter and Earth is Greater than the distance between Mercury and Earth.

Answer:

neither

Step-by-step explanation:

parallel lines will have the same number next to the x

perpendicular lines will have the negative reciprocal number next to the x

(for example 2 and -1/2 are negative reciprocals)

y−4=3(x+5)

parenthesis first

y−4=3x+15

y=3x+19

y+3= −13(x+1)

y+3= −13x−13

y= −13x−16

3x and −13x are neither the same nor negative reciprocals of each other so

the answer is neither

Answer:

w² - 2w + 4

Step-by-step explanation:

(w² - 4w + 14) - (2w + 10) = w² - 2w + 4

After 300 trials, the experimental probabilities may not align perfectly with the theoretical probabilities. However, with more trials, the experimental probabilities tend to converge towards the theoretical probabilities for closer alignment.

To examine whether experimental probabilities after 300 trials align closely with theoretical probabilities, let's consider an example of flipping a fair coin.

Theoretical probability: When flipping a fair coin, the theoretical probability of obtaining heads or tails is 0.5 each. This assumes that the coin is unbiased and has an equal chance of landing on either side.

Experimental probability: After conducting 300 trials of flipping the coin, we record the outcomes and calculate the experimental probabilities. Let's assume that heads occurred 160 times and tails occurred 140 times.

Experimental probability of heads: 160/300 = 0.5333

Experimental probability of tails: 140/300 = 0.4667

Comparing the experimental probabilities to the theoretical probabilities, we can observe that the experimental probability of heads is slightly higher than the theoretical probability, while the experimental probability of tails is slightly lower.

In this particular example, the experimental probabilities after 300 trials do not align perfectly with the theoretical probabilities. However, it is important to note that these differences can be attributed to sampling variability, as the experimental outcomes are subject to random fluctuations.

To draw a more definitive conclusion about the alignment between experimental and theoretical probabilities, a larger number of trials would need to be conducted. As the number of trials increases, the experimental probabilities tend to converge towards the theoretical probabilities, providing a closer alignment between the two.

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The question probable may be:

Do experimental probabilities after 300 trials tend to align closely with theoretical probabilities? Consider an example scenario and calculate both the theoretical and experimental probabilities to determine if they are close.

Answer:

The numbers are 65, 67, and 69

Step-by-step explanation:

Hi there!

We need to find 3 consecutive odd integers.

Consecutive numbers are numbers that follow each other (ex. 1, 2, 3, 4)

We're given that 5 times the first number + 4 times the second + 3 times the third = 800

Let's make the first number x

Since the second number is consecutive to the first and odd, it will be x+2 (Why? Well, let's say x is 5. In that case, x+1=6, which is even. However, x+2=7)

Therefore, the third number is x+4 (once again, if x is 5, x+3=8, but x+4=9)

5 times the first number is 5x

4 times the second is 4(x+2)

3 times the third is 3(x+4)

And of course, that equals 800

As an equation, it'll be:

5x+4(x+2)+3(x+4)=800

open the parenthesis

5x+4x+8+3x+12=800

combine like terms

12x+20=800

Subtract 20 from both sides

12x=780

Divide by 12 on both sides

x=65

The first number is x, so the first number is 65

The second number is x+2, or 65+2=67

The third number is x+4, or 65+4=69

Hope this helps!

Answer:

I think its (-4,2)

Step-by-step explanation:

\(Hiya!\)

Sokka is here to help!!

Here's a explanation!

\(\frac{38}{100} (12)\)

\(=(\frac{38}{100} )(\frac{12}{1} )\)

\(=(\frac{19}{50} )(\frac{12}{1} )\)

\(=\frac{(19)(12)}{(50)(1)}\)

\(=\frac{228}{50}\)

\(4.56\)

ANSWER:

\(\frac{114}{25}, OR: 4.56\)

Hopefully, this helps you!!

\(Sokka\)

Answer:

C!

Step-by-step explanation:

I Got it correct! I hope you have a wondeful weekend and Day!!!

Answer:

The ratio of cosine X = 12 : 13

Step-by-step explanation:

Given;

∠Y=90°

length WY = 5

length XW = 13

length YX = 12

Check the image uploaded for the solution.

hypotenuse is

Since the y-intercept of the line is (0,1) and the line passes through the point (2,4) which is also satisfied by the equation of the line, the given equation represents the graph of the line.

The slope-intercept form of a line is y = mx +c where m is the slope of the line and c is the y-intercept.

The given equation of the line is y = (3/2)x + 1.

To find the y-intercept of the line, substitute x = 0 into the given equation,

y = (3/2)(0) + 1

y = 1

Note that the y-intercept of the graph of the line is also 1.

The graph of the line passes through points (2,4).

To verify whether the equation satisfies the coordinates of (2,4) or not, substitute the coordinates of the point into the given equation:

4 = (3/2)(2) + 1

4 =4

The equation is true.

Hence, it can be said that the given equation represents the graph of the line.

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