Answer:
what is the value of X by the way
min ti x₁ = x₂-u x₂ = u -144²1 (x₁, x₂) arbitrary starting point. Let (0,0) be the Check whether situation (x₁, x₂)→ (0,0) shortest time is met. the beginning of the the coordinate. generality condition of the
It appears that the system dynamics can be manipulated through the control input u to minimize the time required for convergence to the origin (0,0).
Here, we have,
given that,
min t_i
x₁ = x₂-u
x₂ = u
-1 ≤ u ≤ 1, (x₁, x₂) are arbitrary starting point.
and origin (0,0) be the begging of the coordinate.
also given that, (x₁, x₂)→ (0,0)
so, min t_i at origin (0,0) = t
Therefore, the generality condition of the situation does not met.
so, we get,
The given system can be represented by the following equations:
x₁' = x₂ - u
x₂' = u
To analyze the behavior of the system, we can examine the dynamics of each variable separately.
For x₁:
x₁' = x₂ - u
The equation implies that the rate of change of x₁ is dependent on x₂ and the input u. The term (-u) acts as a control input that can affect the dynamics of x₁. If we choose an appropriate control input u, we can manipulate the rate of change of x₁ and potentially minimize the time required to reach the origin.
For x₂:
x₂' = u
The equation for x₂ indicates that the rate of change of x₂ is solely determined by the input u. The variable x₂ can be directly controlled by the input u, allowing us to influence its behavior and potentially expedite convergence.
Based on the given equations, it appears that the system dynamics can be manipulated through the control input u to minimize the time required for convergence to the origin (0,0).
By carefully selecting the control input, it is possible to achieve the shortest time to reach the origin from any arbitrary starting point (x₁, x₂).
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Aisha had a of ribbon. She used 15% of the ribbon to decorate cards and had 17 feet of ribbon left. She then used 20% of the remaining ribbon to wrap gifts
Answer:
The total amount of ribbon she had was 35 feet of ribbon.
Step-by-step explanation:
I hope this is one of the answers and I hope this helps you. Stay safe:)
Step-by-step explanation:
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What is the fifth term of the sequence defined by f(n) = 3n - 9?
Answer: 6
Step-by-step explanation:
To calculate the fifth term of the sequence defined by f(n) = 3n - 9, we have to put 5 as the value of n in the equation. This will be:
f(n) = 3n - 9
f(5) = 3(5) - 9
= 15 - 9
= 6
Therefore, the fifth term is 6.
Consider the random walk with drift model
xt = δ + xt-1 + wt for t = 1,2,3,… with x0 = 0 and wt is white noise with mean zero and variance σw2.
a. Show the model can be written as xt = δt + ∑1twk (Hint: Use induction.)
v. Find the mean function and autocovariance function of xt.
c. Determine if xt is stationary.
a. To show that the model can be written as xt = δt + ∑1twk, we can use induction.
For t = 1:
x1 = δ + x0 + w1
= δ + 0 + w1
= δ + w1
So the base case holds.
Assume that the model holds for t = k, i.e., xk = δk + ∑1k wk.
For t = k+1:
xk+1 = δ + xk + wk+1
= δ + (δk + ∑1k wk) + wk+1
= δk+1 + ∑1k+1 wk
Therefore, by induction, the model can be written as xt = δt + ∑1twk.
v. To find the mean function of xt, we can take the expected value of both sides of the model equation:
E[xt] = E[δt + ∑1twk]
= E[δt] + E[∑1twk]
= δt + ∑1tE[wk]
= δt
So, the mean function of xt is given by μt = δt.
To find the autocovariance function of xt, we need to calculate Cov(xt, xs) for s ≠ t.
For s < t:
Cov(xt, xs) = Cov(δt + ∑1twk, δs + ∑1swk)
= Cov(δt, δs) + Cov(δt, ∑1swk) + Cov(∑1twk, δs) + Cov(∑1twk, ∑1swk)
= 0 + 0 + 0 + Cov(∑1twk, ∑1swk)
= Cov(∑1twk, ∑1swk)
= Cov(wt + ∑1t-1wk, ws + ∑1s-1wk)
= Cov(wt, ws) + Cov(wt, ∑1s-1wk) + Cov(∑1t-1wk, ws) + Cov(∑1t-1wk, ∑1s-1wk)
= 0 + 0 + 0 + Cov(∑1t-1wk, ∑1s-1wk)
Since wt and wk are white noise with mean zero and variance σw^2, their covariance is zero unless t = s. Therefore, we have:
Cov(xt, xs) = 0 for s < t
For s > t, the covariance remains zero as well, since we can use the same logic as above.
For s = t, we have:
Cov(xt, xs) = Cov(δt + ∑1twk, δt + ∑1twk)
= Cov(δt, δt) + Cov(δt, ∑1twk) + Cov(∑1twk, δt) + Cov(∑1twk, ∑1twk)
= Var(δt) + Cov(∑1twk, ∑1twk)
= Var(δt) + Var(∑1twk) + 2Cov(∑1twk, ∑1twk)
= Var(δt) + Var(∑1twk) + 2∑1t-1Cov(wk, wk)
= Var(δt) + Var(∑1twk) + 2∑1t-1σw^2
Since δ is a constant and wk is a white noise process, Var(∑1twk) = ∑1tVar(wk) = tσw^2.
Therefore, we have:
Cov(xt, xs) = Var(δt) + tσw^2 + 2∑1t-1σw^2
= Var(δt) + tσw^2 + 2σw^2(t-1)
= Var(δt) + 3tσw^2 - 2σw^2
Finally, we can conclude that the mean function of xt is μt = δt, and the autocovariance function of xt is Cov(xt, xs) = Var(δt) + 3tσw^2 - 2σw^2.
c. To determine if xt is stationary, we need to check if the mean function and autocovariance function are independent of time (t).
In this case, the mean function is μt = δt, which is dependent on time. Therefore, xt is not stationary.
Similarly, the autocovariance function Cov(xt, xs) = Var(δt) + 3tσw^2 - 2σw^2 depends on both t and s, so xt is not stationary.
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Does positive selection increases the frequency of an allele until it goes to fixation?
positive selection can increase the frequency of an allele within a population, but whether it reaches fixation depends on a range of factors, including the initial frequency of the allele, the strength and duration of the selection, and the effects of genetic drift.
Positive selection refers to the process where a particular allele or trait is favored by natural selection and consequently increases in frequency within a population. The selective advantage can arise due to factors such as enhanced survival, reproduction, or immunity to diseases. As a result, the frequency of the advantageous allele in the population increases over time.
However, whether the allele eventually reaches fixation, meaning it becomes the only allele present in the population, depends on several factors. One of the key factors is the initial frequency of the allele in the population. If the allele is rare, positive selection can increase its frequency, but it may not necessarily reach fixation due to genetic drift or other factors.
In contrast, if the allele is initially common, it is more likely to reach fixation through positive selection as it has a higher chance of being passed on to future generations. Additionally, the strength and duration of positive selection also play a role in determining whether an allele reaches fixation or not. Strong and long-lasting positive selection increases the likelihood of an allele reaching fixation, whereas weak or short-lived selection may not lead to fixation.
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A random sample of 64 sat scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240. the 95onfidence interval for the population mean sat score is: ________
a. 1.96. b. 1.998.
c. 1.645. d. 1.28.
The 95% confidence interval for the population mean SAT score is given as follows:
(1340, 1460).
How to calculate the confidence interval?The confidence interval is calculated using the t-distribution, as the standard deviation for the population is not known, only for the sample.
The bounds are obtained according to the equation defined as follows:
\(\overline{x} \pm t\frac{s}{\sqrt{n}}\)
In which the variables of the equation are presented as follows:
\(\overline{x}\) is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.In the context of this problem, the values of these parameters are given as follows:
\(\overline{x} = 1400, n = 64, s = 240\)
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 64 - 1 = 63 df, is t = 1.998.
Then the lower bound of the interval is of:
1400 - 1.998 x 240/sqrt(64) = 1340.
The upper bound of the interval is of:
1400 + 1.998 x 240/sqrt(64) = 1460.
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i forgot how to do this help?
Select all the statements that would be true in a probability model for rolling a cube with faces numbered 1 through 6.
a: sample space: 1,2,3,4,5,6
b: p(1)=1/6
c: p(2)=2/6
d: p(6)=1/6
e: the outcomes of the trial: 2,2,2,5,3,2,6,5,6,1
The probability of 1, 2, and 6 if rolling a cube with faces numbered 1 through 6 are 1/ 6, 1 / 6, and 1 / 6 respectively, and the sample space would be 6.
What is probability?The ratio of good outcomes to all possible outcomes of an event is known as probability. A lot of successful results for an experimental with 'n' results can be represented by the symbol x.
Given:
Rolling a cube with faces numbered 1 through 6.
Calculate the sample space as shown below,
Sample space = 1, 2, 3, 4, 5, 6 = 6,
Calculate the probability of 1 as shown below,
p(1) = 1 / 6
Calculate the probability of 2 as shown below,
p(2) = 1 / 6
Calculate the probability of 6 as shown below,
p(6) = 1 / 6
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Solve the equation.
-9x + 1 = -x + 17
O x=-8
O x= -2
O x= 2
O x = 8
HELP!! CAN I PLEASE GET HELP I JUST NEED WHAT X IS ♀️?
Answer:
x = 2
Step-by-step explanation:
63x - 1 and 62x + 1 are corresponding angles and congruent, thus
63x - 1 = 62x + 1 ( subtract 62x from both sides )
x - 1 = 1 ( add 1 to both sides )
x = 2
Answer:
A.
Step-by-step explanation: 63 x - 1 62 x + 1
Explain how to estimate the quotient using compatible numbers. 27 and two-thirds divided by 3 and StartFraction 9 over 10 EndFraction
Answer:
The quotient will be around 7
Step-by-step explanation:
Compatible numbers in division, refers to numbers that can be divided mentally.
27 + 2/3 ÷ 3 + 9/10
27 + 0.67 ÷ 3 + 0.9
27.67 ÷ 3.9
Approximately
28 ÷ 4
=7
Answer:
the sample response is-
The first fraction is between 27 and 28, closer to 28. The second fraction is between 3 and 4, closer to 4. Compatible numbers in division are numbers that can be divided mentally. 28 divided by 4 is 7. The quotient will be around 7.
Step-by-step explanation:
15. A famer has 100 pigs and 180 sheep.
What is the ratio of pigs to sheep in the form 1:n
Answer:
5:9
Step-by-step explanation:
100:180 can be simplified by dividing by 20, which results in the ratio 5:9
Answer:
1 : 1.8
Step-by-step explanation:
ratio of pigs : sheep = 100 : 180 ( divide both parts of the ratio by 100 )
= 1 : 1.8
need done asap please
Answer:
6. 12/13 7. 4/3
Step-by-step explanation:
6) cos = adj/hyp
opp ∠C = 5
adj ∠C = 36
hyp = 39
cosC = 36/39 = 12/13
7) tan = opp/adj
opp ∠C = 36
adj ∠C = 27
hyp = 45
tanX = 36/27 = 4/3
Can someone help me find the domain of this??
RIGHT ANSWERS ONLY PLS
NO LINKS!
Answer:
D, assuming that the function continues past the line shown
Step-by-step explanation:
There is no reason that the X is ending on either side. There should be arrows on both ends of the graphed function though.
an item on sale costs 60 of the original price. if the original price was $80 what is the sale price 82 whats the sales price
The sales price of the item is $48.
The sale price of an item that costs 60% of its original price which is $80 is $48. The original price of the item is $80, and it costs 60% of the original price. The amount of money we'll be spending is calculated as follows: 60 per cent of $80 (60/100) × $80= $48 Therefore, the sales price is $48. The percentage discount for the item is calculated as follows:$80 - $48 = $32
$32 is the amount of money saved due to the discount, which is then divided by the original price, $32/$80 = 0.4 or 40%. Thus, there was a 40% discount on the original price.
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Which questions can the manager ask that will result in discrete quantitative data? check all that apply. what movie did you just see? what genre of movie is your favorite? how much did you spend at the movies today? did you order anything from the concession stand?
The question that will result in discrete quantitative data is:
how much did you spend at the movies today?
Which questions can the manager ask that will result in discrete quantitative data?Discrete quantitative data refers to data that can take only a given set of numeric values (not like continuous quantitative data, where the data can take "any real value").
So, a question like "what genre of movie is your favorite?" is not the correct option, because the answer to that question will not be a number.
"did you order anything from the concession stand?" The answer to this question is also not a number, so this is also wrong.
Now, the correct option is "how much did you spend at the movies today?".
Here the answer will be a quantity (a number) and that number only can be a multiple of the objects that are sold on the cine theater (food, tickets, etc) so that number belongs to a discrete set.
Thus, we conclude that this question is the correct option.
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Answer:
C) How much did you spend at the movies today?
Step-by-step explanation:
edge 2023
use the method of variation of parameters to solve the initial value problem x' = ax f(t), x(a) = xa using the following values. 4 -2 16t2 0 1 2t - 40 a= f(t) = x(0) = 2 - 1 4t t 1-2t x(t) =
The process involves finding the complementary solution x_c(t) by solving the homogeneous equation, determining the particular solution x_p(t) using the method of variation of parameters, and combining them to obtain the general solution x(t).
1. The method of variation of parameters can be used to solve the initial value problem x' = axf(t), x(a) = xa, where a and f(t) are given functions. In this case, we have the values a = 4 - 2t and f(t) = 16t^2. We need to find the solution x(t) using the initial condition x(0) = 2.
2. To solve the initial value problem using the method of variation of parameters, we first find the complementary solution x_c(t) by solving the homogeneous equation x' = ax.
3. For the given a = 4 - 2t, the homogeneous equation becomes x' = (4 - 2t)x. By separation of variables and integration, we find the complementary solution x_c(t) = Ce^(2t - t^2).
4. Next, we find the particular solution x_p(t) by assuming a particular solution of the form x_p(t) = u(t)e^(2t - t^2), where u(t) is a function to be determined.
5. Differentiating x_p(t) and substituting it into the original differential equation, we can solve for u'(t) and determine the form of u(t). After finding u(t), we substitute it back into x_p(t).
6. Finally, the general solution is given by x(t) = x_c(t) + x_p(t). By substituting the values and integrating, we can obtain the specific solution x(t) for the given initial condition.
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Consider the following AR(1) model:- X₂ = a + 0₁ X-₁ + & Calculate the E(X₂), V(X₂), 1st order autocorrelation and 2nd order autocorrelation.
The first-order autocorrelation (ρ₁) is ρ₁ = Cov(X₂, X-₁) / √(V(X₂) * V(X-₁)).
The given AR(1) model is represented by the equation X₂ = a + 0₁ X-₁ + ε₂, where X₂ represents the value of the variable at time period 2, a is a constant term, 0₁ is the autoregressive coefficient, X-₁ represents the value of the variable at time period 1, and ε₂ is the error term.
To calculate the expected value (E(X₂)), we take the expectation of the AR(1) model:
E(X₂) = E(a + 0₁ X-₁ + ε₂)
Since E(a) = a and E(ε₂) = 0 (assuming the error term is mean-zero), we have:
E(X₂) = a + 0₁ E(X-₁) + E(ε₂) = a + 0₁ E(X-₁) = a + 0₁ X-₁
Therefore, the expected value of X₂ is a + 0₁ X-₁.
To calculate the variance (V(X₂)), we need to consider the variance of the error term:
V(X₂) = V(a + 0₁ X-₁ + ε₂) = V(ε₂) = σ²
Where σ² represents the variance of the error term.
The first-order autocorrelation (ρ₁) can be calculated as the covariance between X₂ and X-₁ divided by the square root of the product of their variances:
ρ₁ = Cov(X₂, X-₁) / √(V(X₂) * V(X-₁))
The second-order autocorrelation (ρ₂) can be calculated in a similar manner, considering the covariance between X₂ and X-₂.
In summary, for the given AR(1) model, the expected value of X₂ is a + 0₁ X-₁, the variance of X₂ is σ², and the first and second-order autocorrelations depend on the covariance between X₂ and X-₁, and X₂ and X-₂, respectively, divided by the appropriate variances.
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An automobile tire at 30.0°c has a pressure of 3.00 atm. the temperature decreases to -5.00°c. assume that there is no volume change in the tire. formula to use: p1 t1 = p2 t2 how does the tire pressure change in response to the temperature change?
The process is an isochoric process. Then the tire pressure change in response to the change in temperature is 2.65 atm.
What is thermodynamics?It is a branch of science that deals with heat and work transfer.
An automobile tire at 30.0°C has a pressure of 3.00 atm.
The temperature decreases to -5.00°C.
Assume that there is no volume change in the tire.
Then for the constant volume process, we have
\(\dfrac{P_1}{P_2} = \dfrac{T_1}{T_2}\\\\\dfrac{3}{P_2} = \dfrac{303}{268}\\\\P_2 \ = 3\times \dfrac{268}{303}\\\\P_2 \ = 2.65\)
The tire pressure change in response to the change in temperature is 2.65 atm.
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Answer:
How does the tire pressure change in response to the temperature change?
✔ decreases
What is the new pressure of the tire after the temperature change?
2.65 ✔ atm
Step-by-step explanation:
Got it right on edge
6th grade math help me pleaseeee
Answer:
T I hope this helps:D
What is the probability that a randomly selected day from 2013 will have fewer than 2,740,000 group trades?
The probability that a randomly selected day will have a group trades total within 85,000 of the mean is 0.1328.
What is the probability about?
In the question given, the Mean (u) is said to be = 3421439
Therefore since Standard deviation = 508638.08
Note that:
z = x-u/sd
So:
P(u - 85000 <= x <= u + 85000)
u = 3421439
We insert the formula into the equation and it will be
= P(3421439 - 85000, 3421439 + 85000)
= P(3336439, 3506439)
= (3336439 - 3421439) / 508638.08, 3506439-3421439) / 508638.08)
= prob(-0.1671 and 0.1671 (So check the column under the z table)
So:
= 0.5664 - 0.4336
= 0.1328
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After allowing 20% discount on a marked price 13% VAT was levied on an article. If it was sold for 7232 dollars, what was the marked price of the article?
The marked price of the article was $7865
Answer:
solution given:
let marked price be x=?
discount =20%
vat=13%
selling price =$7232
we have
discount amount=discount % of marked price=20/100*x=0.2 x
and
vat amount = vat% of selling price=13/100*$7232=$940.16
we have
Selling price with tax =marked price - discount amount + vat amount
$7232=x-0.2x+$940.16
$7232-$940.16=x-0.2x
0.8x=$6291.84
x=$6291.84/0.8
x=$7864.8
Rewrite the expression in the form y^n
Step-by-step explanation:
y^3/4×y^1/3y(3/4+1/3)y^2/3stay safe healthy and happy.Answer:
y^13/12 or y^1 1/12
Step-by-step explanation:
Convert the fractions to compatible bases. In this case, you can multiply the 3/4 by 3 making it 9/12, and multiply the 1/3 by 4 making it 4/12. If you add these now compatible fractions, you get 13/12. The base remains the same, I hope this helps!
pls help its the last question
Answer:
Step-by-step explanation:
9.2 to 9.3 the top right one
A man walks directly from paint A towards the foot of a tall building 240m away. After covering 180m, he observes that the angle of the top of the building is 45. (3 marks) Determine the angie of elevation of the top of the building from A.
Using trigonometry, the angle of elevation of the top of the building from A is 36.87 degrees
What is the angle of elevation of the top of the building from A?The angle of elevation of the building from A, we can apply the concept of trigonometry;
tan(θ) = opposite/adjacent
tan(θ) = height/180m
Since we're given that the angle of the top of the building is 45 degrees when the man is 180m away from point A, we can set up the equation:
tan(45°) = height/180m
The tangent of 45 degrees is 1, so the equation becomes:
1 = height/180m
Solving for the height:
height = 180m
Using the tangent of the angle;
tan(θ) = height/distance
tan(θ) = 180m/240m
Simplifying:
tan(θ) = 0.75
θ = tan⁻¹(0.75)
θ = 36.87 degrees
Therefore, the angle of elevation of the top of the building from point A is approximately 36.87 degrees.
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Choose the word that makes this sentence true.
A square is ____ a rectangle.
Answer: the same as or equal to
Step-by-step explanation: The shapes are the same one's just stretched
Answer:
A square is a special kind of a rectangle
Step-by-step explanation:
Every Square is a rectangle but not every rectangle is a square.
Let f(x) be the probability density function for a normal distribution N(68,5). Answer the following: (a) At what x value does f(x) reach a maximum? Maximum height: x (b)Does f(x) touch the x-axis at μ±30 ? No Yes
The probability density function for a normal distribution N(68, 5) reaches its maximum height at x = 68, which is the mean of the distribution. The function does not touch the x-axis at μ±30.
The probability density function (PDF) for a normal distribution is bell-shaped and symmetrical around its mean. In this case, the mean (μ) is 68, and the standard deviation (σ) is 5.
(a) To find the x value at which the PDF reaches a maximum, we look at the mean of the distribution, which is 68. The PDF is highest at the mean, and as we move away from the mean in either direction, the height of the PDF decreases. Therefore, the x value at which f(x) reaches a maximum is x = 68.
(b) The PDF of a normal distribution does not touch the x-axis at μ±30. The x-axis represents the values of x, and the PDF represents the likelihood of those values occurring. In a normal distribution, the PDF is continuous and never touches the x-axis. However, the PDF becomes close to zero as the values move further away from the mean. Therefore, the probability of obtaining values μ±30, which are 38 and 98 in this case, is very low but not zero. So, the PDF does not touch the x-axis at μ±30, but the probability of obtaining values in that range is extremely small.
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How do teachers expect us to teach ourselves?
Answer:
Homeschooling!
Step-by-step explanation:
Answer:
absolutely no clue :/
If the length of a room is 4.02m, the width of a room is 3.37m, and the height of a room is 2.35m, what is the volume of the room m^3? after figuring out the volume, then find out the mass of the air kg in the room.
The value for the volume of the room is 31. 84 cubic centimeters(cm³)
The mass of the air in the room is 41. 39 kg
How to determine the volume of the roomThe formula for calculating the volume of the room is expressed as;
Volume = l × w × h
Where;
l is the length of the roomw is the width of the roomh is the height of the roomFrom the information given, we have to substitute the values of the measurements of the room into the formula.
We have;
Volume, v = 4. 02 × 3. 37 × 2. 35
Volume, v = 31. 84 cubic centimeters(cm³)
To determine the mass of the air in the room, we use the formula for mass which is expressed as;
Mass = Density × volume
Given that;
Density of air = 1. 3kg/m³Volume of the room = 31. 84 cubic centimeters(cm³)Substitute the values
Mass = 1. 3 × 31. 84
Mass = 41. 39 kg
Hence, the volume is 31. 84 cubic centimeters(cm³)
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how many dimes equal the value of 6 quarters.show you step
Answer:
15 dimes
Step-by-step explanation:
6 quarter = 1.50$
150 / 10 = x amount of dimes
X amount of dimes = 150$
15 dimes = 1.50$
HOPE THIS HELPS
PLZ MARK BRAINLIEST
Answer:
6 quarters is in total 1.50, so youll need a total of 15 dimes in order to have the same amount of 6 quarters
Step-by-step explanation: