Every tenth customer to Macy's end of the season sale gets a $10
coupon. Every twenty-fifth customer gets a free gift bag. Which customer
will be the first one to get both the $10 off coupon and the gift bag?

Answer:

1. P(2 or 4) - 2/3

2. P(multiple of 2) - 1

3. P(multiple of 3) - 1/3

4. P(odd prime numbers) - 0

Step-by-step explanation:

Good luck lol

P(2 or 4) =  2/3

P( multiple of 2) = 1

P( multiple of 3) = 1/3

P(odd prime numbers) = 0

Probability is the likelihood of an event happening or not.

Analysis:

possible outcome = (2,2,4,4,6,6) = 6

P(2 or 4)

n( 2) = required outcome = (2,2) = 2

P(2) = 2/6 = 1/3

n(4) = (4,4) = 2

P(4) = 2/6 = 1/3

P(2 or 4) = 1/3 + 1/3 = 2/3

n( multiple of 2) = (2,2,4,4,6,6) = 6

P( multiple of 2) = 6/6 = 1

n(multiple of 3) = (6,6) = 2

P(multiple of 3) = 2/6 = 1/3

P(odd prime numbers) = 0

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Answer:

Step-by-step explanation:

4x² + 6 = 40

4x² = 34

x² = 8.5

x = ±√8.5 ≈ 2.92

Answer:

2:1

Step-by-step explanation:

14:7

14÷7 : 7÷7

2 : 1

Option C is the correct option for the given problem; let’s consider all options and identify the different reasons in the number list.

From the second element (index 1) through the last element, this procedure iterates through the list of numbers using a for loop. It determines whether the current number is lower than the previous number after each repetition. If it is, the process gives a prompt False response, meaning that the list is not growing.

The procedure returns True, indicating that the list is growing, if the for loop concludes without running into a number that is less than the number it encountered before.

According to the issue definition, this technique implies the list has at least two elements. This guarantees that the for loop will always have a previous number to compare to.

Comments are written in italic to explain the code

Line 1: PROCEDURE Is Increasing(numberList)//start Is Increasing procedure with a list number List

Line 2: {//start procedure

Line 3: count<-2//set count to be 2

Line 4: REPEAT UNTIL (count -> LENGTH(numberList)//repeat from element 2 to last

Line 5: {//start repeat

Line 6: IF(numberList[count] < numberList[count-1]//if previous number is greater

Line 7: {//start if

Line 8: RETURN(true)//return true as next is greater than

Line 9: }//end if

Line 10: count<- count +1//increment to next element

Line 11: }//end repeat

Line 12: RETURN (false)//return false

Line 13: }//end procedure

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Complete question is:

A list of numbers is considered increasing if each value after the first is greater than or equal to the preceding value. The following procedure is intended to return true if numberList is increasing and return false otherwise. Assume that numberList contains at least two elements. PROCEDURE isIncreasing(numberList) Tue 61 Line 1: Line 2: { Line 3: count 2 Line 4: REPEAT UNTIL(count > LENGTH(numberList)) Line 5: } IF(numberList[count] < numberList[count - 1]) Line 6: Line 7: To entd Line 8: RETURN(true) :80 onij { count count + 1 Line 9: Line 10: er onil Line 11: } Line 12: RETURN(false) BELAS(ConuE) Line 13: } Which of the following changes is needed for the program to work as intended? Lines 8 and 12 should be interchanged. c. In line 6, < should be changed to >=. a. b. Lines 10 and 11 should be interchanged. d. In line 3, 2 should be changed to 1. 3.

The correct option is (B) generated randomly from probability distributions.

The values for random variables in a Monte Carlo simulation are generated randomly from probability distributions.

A frequency distribution that has been idealized is a probability distribution. An individual sample or dataset is described by its frequency distribution. It's the number of times in the dataset that each possible value of a variable appears. The probability of occurrence of a value determines how frequently it appears in a sample.

A random variable can have any number of alternative values and likelihoods within a particular range, and a probability distribution is a statistical function that captures all of these possibilities. This range will be constrained by the minimum and maximum possible values, but the location of the possible value on the probability distribution will rely on a number of other variables.

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The solution of the given initial value problem is y(t) = sin(t) + H(t-2π)cos(t-2π), where H(t) is the Heaviside step function.

To solve the initial value problem, we start by finding the complementary solution, which satisfies the homogeneous differential equation y'' + y = 0. The complementary solution is given by y_c(t) = A sin(t) + B cos(t), where A and B are constants to be determined.

Next, we find the particular solution for the given non-homogeneous term δ(t-2π)cos(t). Since the forcing term is a Dirac delta function at t = 2π, we can write the particular solution as y_p(t) = K(t-2π)cos(t-2π), where K is a constant to be determined.

Applying the initial conditions y(0) = 0 and y'(0) = 1, we can solve for the constants A, B, and K. Plugging in these initial conditions into the general solution, we find A = 0, B = 1, and K = 1.

Therefore, the solution of the initial value problem is y(t) = sin(t) + H(t-2π)cos(t-2π), where H(t) is the Heaviside step function.

The initial value problem with the given conditions is solved by finding the complementary solution and the particular solution. The solution is y(t) = sin(t) + H(t-2π)cos(t-2π), where H(t) is the Heaviside step function. This solution satisfies the given initial conditions y(0) = 0 and y'(0) = 1.

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5) The value of probability P(X<2.262) is, 0.0485

6) The value of probability P(X> -2.262) is, 0.0485

7) The value of probability P(Y<-1.325) is, 0.1019

8) TDIST(2.179, df, 2) can be used to find the probability P(X > 2.179) for a t-distribution with df degrees of freedom.

The required probability is P(X < 2.262).

Using the TINV function in Excel, the quantile corresponding to a probability value of 0.95 and 9 degrees of freedom can be calculated.

t = 2.262

In Excel, the probability is calculated using the following formula:

P(X < 2.262) = TDIST(2.262, 9, 1) = 0.0485

The required probability is P(X > -2.262).

Using the TINV function in Excel, the quantile corresponding to a probability value of 0.975 and 9 degrees of freedom can be calculated.

t = -2.262

In Excel, the probability is calculated using the following formula:

P(X > -2.262) = TDIST(-2.262, 9, 2) = 0.0485

The required probability is P(Y < -1.325). Using the TINV function in Excel, the quantile corresponding to a probability value of 0.1 and 20 degrees of freedom can be calculated.

t = -1.325

In Excel, the probability is calculated using the following formula:

P(Y < -1.325) = TDIST(-1.325, 20, 1) = 0.1019

TDIST(2.179, df, 2) can be used to find the probability P(X > 2.179) for a t-distribution with df degrees of freedom.

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Answer:

88

Step-by-step explanation:

At least 75% of the flights (or 15 out of the 20 flights) will last between 3 days and 11 days, according to Chebyshev's Theorem.

Chebyshev's Theorem states that for any given number k greater than 1, at least (\(1-\frac{1}{k^2}\)) of the data values in any data set will fall within k standard deviations of the mean.

In this case, we can use Chebyshev's Theorem to determine the minimum number of flights that lasted between 3 and 11 days.

Given:

Mean (μ) = 7 days

Standard Deviation (σ) = 2 days

To find the number of flights within the range of 3 to 11 days, we need to calculate how many standard deviations away from the mean these values are.

Lower Bound:

Value = 3 days

Number of standard deviations away from the

\(mean = \frac{(Value - Mean)}{ Standard Deviation}\)

\(mean =\frac{(3 - 7) }{2}\)

\(mean =\frac{-4}{2}\)

\(mean = -2\)

Upper Bound:

Value = 11 days

Number of standard deviations away from the

\(mean = \frac{(Value - Mean)}{Standard Deviation}\)

\(mean = \frac{(11 - 7)}{2}\)

\(mean = \frac{4}{2}\)

\(mean = 2\)

According to Chebyshev's Theorem, the minimum proportion of data values within k standard deviations of the mean is given by \((1- \frac{1}{k^2} )\).

So, we need to determine the proportion of data within 2 standard deviations, which is k = 2.

Proportion within 2 standard deviations = \(1-\frac{1}{2^2}\)

\(=1-\frac{1}{4}\)

\(= 1 - 0.25\)

\(= 0.75\)

Now, we can find the percentage of \(0.75\):

\(= 0.75\times 100\)

\(= 75\%\)

Therefore, at least 75% of the flights (or 15 out of the 20 flights) will last between 3 days and 11 days, according to Chebyshev's Theorem.

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Step-by-step explanation:

In blue colour square

Perimeter= 4 × side

= 4 (3x +7)

=12x +28 unit

In green colour square

Perimeter= 4 × side

= 4 ( 5x+1)

= 20x +4 unit

Answer:

12x + 28 = p

20x + 4 = p

Step-by-step explanation:

Assuming that both shapes are square, the perimeter of a square is the equation:

4 * x = p

Where x is the length of one side. Plug the variables in for the first square:

4 * (3x + 7) = p

Expand the brackets:

4 * 3x = 12x

4 * 7 = 28

12x + 28 = p

For the second square, plug the variables in again:

4 * (5x + 1) = p

Expand the brackets:

4 * 5x = 20x

4 * 1 = 4

20x + 4 = p

Hope this helps!

The minimum sum of products (MSP) expression of the given function F(A, B, C, D) can be obtained by using the Quine-McCluskey method.  In this case, the MSP expression for the given function is F(A, B, C, D) = A'C'D' + A'BCD + AB'C'D + ABCD.

The MSP expression is a simplified Boolean expression that represents the function in terms of its essential prime implicants.

The Quine-McCluskey method is an algorithm that uses the concepts of prime implicants, essential prime implicants, and petrick's method to simplify Boolean functions. The method starts with finding all the prime implicants of the function and then grouping them to form essential prime implicants. The essential prime implicants are then used to form the MSP expression of the function. The MSP expression obtained using this method is minimal, which means that it has the least number of terms and literals compared to other simplified expressions.

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Answer: 10.92

Step-by-step explanation: Transforming the mixed fractions makes 4.2 and 2.6, which which when multiplied would give you 10.92.

The solutions to the equation are x = -10√5 and x = 10√5 = 22.3607. Option d. 0,10 correctly represents the two solutions, where x = 0 and x = 10.

To find the solutions of the equation\(2x^2\) – 1000 = 0, we can start by setting the equation equal to zero and then solving for x. The equation becomes:

\(2x^2\) – 1000 = 0

Adding 1000 to both sides, we get:

\(2x^2\) = 1000

Dividing both sides by 2, we have:

X^2 = 500

Taking the square root of both sides, we get:

X = ±√500

Simplifying the square root, we have:

X = ±√(100 * 5)

X = ±10√5

Therefore, the solutions to the equation are x = -10√5 and x = 10√5 == 22.3607.

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The value of the equation is A = ( 3y + 3x ) / 4

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = ( x + y ) ( 3/ 4 )   be equation (1)

On simplifying the equation , we get

A = [ 3 ( x ) + 3 ( y ) ] / 4

Now , on further simplification , we get

A = ( 3y + 3x ) / 4

Hence , the equation is A = ( 3y + 3x ) / 4

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Hi there!  

»»————-　★　————-««

I believe your answer is:  

\(y^\frac{2}{3}\)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

The rule for a fraction exponent is:

\(a^{\frac{x}{y}}=\sqrt[y]{a^x}\\\\\\\huge\boxed{\frac{\text{Power}}{\text{Root}}}\)

⸻⸻⸻⸻

We are given the expression of \(\sqrt[3]{y^2}\).

⸻⸻⸻⸻

\(\boxed{\text{Rewriting the expression:}}\\\\\sqrt[3]{y^2}\\\\\text{The '3' is the root and the '2' is the power.}\\\\\rightarrow \sqrt[3]{y^2} \\\\\rightarrow {y^{\frac{2}{3}}\)

⸻⸻⸻⸻

\(\text{The answer should be: } \boxed{y^\frac{2}{3} }\)

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

E. a=10.

it's the answer

hope it helps

A country with little land and few natural resources could make up for such deficits without depending on other countries and having a healthy economy by developing its Human Capital.

Examples of small countries with low natural resources and high GDP are:

It is to be noted that of all the factors of production, (Land, labor, Capital, and Entrepreneurship) Human Capital (Labor and Entrepreneurship) are the most valuable and yield the greatest return on investment.

The Democratic Republic of the Congo is commonly regarded as the world's richest country in terms of natural resources; its undiscovered stockpiles of raw minerals are estimated to be worth more than US $24 trillion.

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Answer:

The square root of 516 is 22.627416997969522 or approximately 22.63.

-5 < -3 and the second inequality is -3 > -5

Answer:

There are 5 vowels in the English alphabet: A, E, I, O, and U. Since repetition is allowed, each letter can be any one of the 5 vowels.

The probability of the first letter being a vowel is 5/26, since there are 5 vowels out of 26 letters in total. The probability of the second letter being a vowel is also 5/26, and so on for the third and fourth letters.

Since the events of each letter being a vowel are independent, we can use the multiplication rule to find the probability of all four letters being vowels:

P(all 4 vowels) = (5/26) x (5/26) x (5/26) x (5/26) = (5/26)^4

Using a calculator, we get:

P(all 4 vowels) ≈ 0.0023

To express the answer as a percent, we multiply by 100:

P(all 4 vowels) ≈ 0.23%

Therefore, the probability that all 4 letters typed will be vowels, with repetition allowed, is approximately 0.23%.

Step-by-step explanation:

3/4x+10=4

Then solve for x

3/4x = 4 - 10

x = (4-10)/(3/4)

. = -6/3/4

. = -24/3

. = -8

In consecuence , answer IS

x= -8

Answer:

The answer is B) 432

Step-by-step explanation:

The 4 in 432 becomes a 3, because we can't subtract 6 from 3. The 3 becomes 13 and if we subtract 13 with 6... We get 7.

I got 0 with option B... With A I got 2 which is a remainder. With C I got 6.5 (repeating). And with D I got 7.77777777778.

Hence, B) 432 is the correct option.

Check screenshot of my work below.

(I forgot to include 48 on top of the division I just did. Don't mind that too much..)

A) 326

\( \frac{326}{9} \)

\( = 36.2222222222 \)

B) 432

\( \frac{432}{9} \)

\( = 48\)

C) 531

\( \frac{531}{9} \)

\( = 59\)

D) 630

\( \frac{630}{9} \)

\( = 70\)

so, the correct answer is option A.

Answer:

x = -23

Step-by-step explanation:

3.5(x+20) = 6 + .75(x + 1)  Multiply the terms inside the parentheses on the left by 3.5 and the parentheses on the left by .75

(3.5)x +(3.5)(20) = 6 + (.75)x +(.75)(1)

3.5x + 70 = 6 + .75x + .75  Combine the 6 and .75 on the right side

3.5x + 70 = 6.75 + .75x  Subtract .75x from both sides of the equation

2.75x + 70 = 6.75  Subtract 70 from both sides of the equation

2.75x  = -63.25  Divide both sides by 2.75

x = -23

Check

3.5(-23+20) = 6 + .75(-23 + 1)

3.5(-3) = 6 +.75(-22)

-10.5 = 6 +(-16.5)

-10.5 = -10.5

Answer:

x = -23

Step-by-step explanation:

3.5(x+20)=6+.75(x+1)

3.5x + 70 = 6 + .75x + .75

3.5x+70=.75x+6.75

2.75x+70=6.75

2.75=−63.25

divide^

x = -23

Answer:

The answer is D on edg 2020

Step-by-step explanation:

brainliest plz

Answer:

Its D

Step-by-step explanation:

∠2 ≅ ∠4

a. i Find the graph in the attachment

ii. The vertical asymptotes are at x = 2 and x = 3

iii. we find the vertical asysmtotes by finding the L.C.M of the expression and equating to zero.

b. i. At x = - 1 there is a critical point.

ii. there isn't a vertical asymptote at x = - 1 because it also has a critical point at x = -1.

c. The value of x when y = 0 is x = ±4.796

The graph of the equation is in the attachment

From the graph, the vertical asymptotes are at x = 2 and x = 3

So, the vertical asymptotes are at x = 2 and x = 3

Since y = (x + 5)/(x + 1) ÷ (x + 3)(x - 2)/(x - 4)(x + 1) - 1/(x - 2), we find the vertical asysmtotes by finding the L.C.M of the expression and equating to zero.

So, we find the vertical asysmtotes by finding the L.C.M of the expression and equating to zero.

The graphical feature that occurs at x = - 1 there is a critical point.

So, at x = - 1 there is a critical point.

There isn't a vertical asymptote at x = - 1 because

So, there isn't a vertical asymptote at x = - 1 because it also has a critical point at x = -1.

Since y = (x + 5)/(x + 1) ÷ (x + 3)(x - 2)/(x - 4)(x + 1) - 1/(x - 2), when y = 0, we have

0 = (x + 5)/(x + 1) ÷ (x + 3)(x - 2)/(x - 4)(x + 1) - 1/(x - 2)

(x + 5)(x - 4)(x + 1)/(x + 1)(x + 3)(x - 2) = 1/(x - 2)

(x + 5)(x - 4)/(x + 3)(x - 2) = 1/(x - 2)

(x + 5)(x - 4)/(x + 3) = (x - 2)/(x - 2)

(x + 5)(x - 4)/(x + 3) = 1

(x + 5)(x - 4) = (x + 3)

x² - 4x + 5x - 20 = x + 3

x² + x - 20 = x + 3

x² + x - x - 20 - 3 = 0

x² + 0 - 23 = 0

x² - 23 = 0

x² = 23

x = ±√23

x = ±4.796

So, the value of x when y = 0 is x = ±4.796

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Answer:

2 (x+1) (x+4)

and you can use Microsoft math solver to help you and it helps solve and example step by step

Answer:

(6,-3)

Step-by-step explanation:

;-;

Answer:

\( \frac{1}{24} miles \\ \)

Step-by-step explanation:

\( \frac{7}{8} - \frac{5}{6} = \frac{1}{24} \)