Did I answer these correctly? Also the app keeps kicking me off so if I don’t respond that’s why. Thanks for your help

Convex lenses refract light inward toward a focal point. Light rays progress through the edges of a convex lens and are bent most.

convex lenses are across in the middle. Rays of light that pass through the lens are conducted closer together (they converge). A convex lens is a meet lens. When parallel rays of light pass through a convex lens the refracted rays cross at one point called the principal focus.

. A convex lens is a connecting lens. When parallel rays of light pass through a convex lens the refracted rays merge at one point called the principal focus.

So we can conclude that Convex Lens. Concave Lens; It is known as a converging lens as light rays, when passed through this lens, tends to bend towards each other. It is known as a Convex Lens

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Answer:

Coevalent

Explanation:

Because I am smart

in the periodic tables

elements in the same column have the same charge

in a compound oxidation numbers have to equal 0

1.

sulfur in Li2SO3

charges :

Li = +1 S = +4 O = -2

multiply the charge with the subscripted number next to the element

Li = +1

Li2 = +2

O = -2

O3 = -8

in a compound oxidation numbers have to equal 0

+2 S -6 = 0

S -4 = 0

S = +4

Sulfur = +4

2.

MgCl2

Mg = +2

+2 Cl2 = 0

Cl2 = -2

Cl by itself = -2 divided by 2 = -1

Chlorine  = -1

3.

SiO2

Silicon = +4

4.

Sulfur in H2SO4

H: +1 S: +6 O: -2

H2SO4

H2 : +2 O4: -8

+2 +S -8 = 0

S - 6 = 0

S = +6

Sulfur = +6

5.

Sulfur in SO4^2-

Sulfur in SO4

Sulfur = +4

6.

Manganese in MnO4^-

Manganese in MnO4

Manganese = +4

7.

Cr2O7^2-

Dichromate

Cr in Cr2O7^2- or Cr2O7-2-

Cr: +6 O: -2

Answer:

false, true.

Explanation:

"That's because enzymes don't affect the free energy of the reactants or products" good luck!

Answer:

0.06654345229738384 moles of chromium.

7.6 moles of O2 will occupy 170.24 L at STP, and 0.58 moles of O2 will occupy 12.992 L at STP.

We can use the ideal gas law and the molar volume of a gas at STP.

The molar volume of a gas at STP is approximately 22.4 liters/mol.

(a) For 7.6 mol of O2:

Volume = Number of moles * Molar volume

Volume = 7.6 mol * 22.4 L/mol

Volume = 170.24 liters

Therefore, 7.6 moles of O2 occupy approximately 170.24 liters at STP.

(b) For 0.58 mol of O2:

Volume = Number of moles * Molar volume

Volume = 0.58 mol * 22.4 L/mol

Volume = 12.992 liters

Therefore, 0.58 moles of O2 occupy approximately 12.992 liters at STP.

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a) For 7.6 mol of O2 volume occupied at STP is approximately equal to 164.09 L

b) For 0.58 mol of O2 volume occupied at STP is approximately equal to 12.02 L

A temperature of 273.15 K (0 degrees Celsius) and a pressure of 1 atmosphere (atm) are defined as STP (Standard Temperature and Pressure).

We can use the ideal gas law equation to calculate the volume of a gas at STP:

PV = nRT

Where: P is the pressure (1 atm), V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is the temperature in Kelvin.

(a) In the case of 7.6 moles of O2, we can rearrange the equation to solve for the volume (V):

V = nRT / P

V = (7.6 mol) × (0.0821 L·atm/(mol·K)) × (273.15 K) / (1 atm)

On calculating,

V ≈ 164.09 L

(b) In the case of 0.58 moles of O2, we can rearrange the equation to solve for the volume (V):

V = nRT / P

V = (0.58 mol) × (0.0821 L·atm/(mol·K)) × (273.15 K) / (1 atm)

On Calculating,

V ≈ 12.02 L

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Mass of the pure silver deposited on a metal object made into the cathode of the cell is calculated to be 0.0217 gm.

The process of using electrodeposition to coat an object in a layer of metal is called electroplating .

As we know that, Q = I * t

=0.270 * 72

= 19.44 C

Here Q is quantity of electricity , I is current in amperes = 0.270 A (given)

t is time in seconds (72.0 sec)

As 96500 Coulomb of electricity electrolyzes 1 mole of Ag

then,19.44 C of electricity deposits,

=1/96500 * 19.44

= 0.000201 moles of Ag

Mass of Ag is = number of moles * molar mass

= 0.000201 * 108

= 0.0217 gm

Thus, mass of pure silver deposited on a metal object made into the cathode of the cell is  0.0217 gm.

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Answer:

did this help ?

Explanation:

He muddled his way through the opening verse and belted out the chorus, creating a schizophrenic performance.: The results included muddled avant-garde theatrical staging techniques and insensitive and maladroit portraits of African Americans .  

Answer:

19.12 L

Explanation:

At STP(i.e. Standard temperature and pressure).

The volume occupied by one mole of gas = 22.4 L

The pressure = 1 atm

The temperature = 273 K

Thus, since 1 mole of gas = 22.4 L;

Then 0.853 moles of N2 gas will occupy:

= (0.853 moles of N2 gas × 22.4 L)/ 1 mole of N2 gas

= 19.12 L

It is the 4th scenario is the dependent event. There are 7 gold tokens and 4 silver tokens in a cup. The first student randomly draws a gold token and keeps it. A second student randomly draws a gold token from the cup.

The fouth scenario is a dependent event because the probability of the second student drawing a gold token is affected by the outcome of the first student's draw.

If the first student draws a gold token, then there are only 6 gold tokens left in the cup, the probability changes. but  if the first student does not draw a gold token, then there are 7 gold tokens left in the cup, the probability will remain the same

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Answer:

Q = 100.42 J

Explanation:

Given data:

Mass of water = 1.500 g

Specific heat capacity of water = 4.184 J/g.°C

Heat required = ?

Initial temperature = 23°C

Final temperature = 39°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39°C - 23°C

ΔT = 16°C

Q = 1.500 g× 4.184 J/g.°C  ×16°C

Q = 100.42 J

Answer:

a change from a solid to a liquid

Explanation:

Answer:

Dissolving salt in water is a chemical change.

Explanation:

A log burning is a chemical reaction, but not change. All the others are obviously not the answer.

(a) The hazard quotient is:

HQ = Intake / RfD = 0.0002 mg/day / 0.02 mg/kg/day = 0.01

(b) The cancer risk is 1 in 10,000.

(c) The cancer risk is 1 in 1,000.

Hazard quotient (HQ) is a measure used in risk assessment to evaluate the potential health risk posed by exposure to a chemical or other hazard. It is calculated as the ratio of the dose or exposure level of the chemical to a reference dose (RfD) or reference concentration (RfC) established by regulatory agencies or scientific bodies as a safe level of exposure. If the hazard quotient is greater than 1, it suggests that the level of exposure is of potential concern and additional risk assessment may be needed.

(a) The hazard quotient (HQ) is calculated as the daily intake of a chemical divided by its reference dose (RfD). The RfD for 1,1-dichloroethylene is 0.02 mg/kg/day.

The daily intake of 1,1-dichloroethylene can be calculated as:

Intake = concentration × ingestion rate × body weight

Intake = 0.1 μg/L × 2 L/day × 70 kg = 14 μg/day = 0.0002 mg/day

The hazard quotient is:

HQ = Intake / RfD = 0.0002 mg/day / 0.02 mg/kg/day = 0.01

(b) The cancer risk from exposure to 1,1-dichloroethylene can be estimated using the unit risk factor (URF) for this chemical, which is 0.5 per mg/kg/day. The cancer risk is calculated as:

Risk = Intake × URF = 0.0002 mg/day × 0.5 per mg/kg/day = 0.0001

Therefore, the cancer risk is 1 in 10,000.

(c) If the individual drinks this water for 30 years, the total exposure would be:

Exposure = Intake × 365 days/year × 30 years = 2.19 mg

The new hazard quotient is:

HQ = Exposure / (RfD × body weight) = 2.19 mg / (0.02 mg/kg/day × 70 kg) = 1.57

The new cancer risk is:

Risk = Exposure × URF = 2.19 mg × 0.5 per mg/kg/day = 1.10

Therefore, the cancer risk is 1 in 1,000.

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Answer:

Hi

Explanation:

We assume you are converting between moles H2O and gram. You can view more details on each measurement unit: molecular weight of H2O or grams This compound is also known as Water or Dihydrogen Monoxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2O, or 18.01528 grams.

1 mole is equal to 6.023 × 10 ²³ molecules. 63 grams  are in 3.5 moles of H2O.

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.

The mole concept can be used to convert between mass and number of particles.

We expect you are converting between moles H2O and gram. The molecular weight of H2O or gram's This compound is also known as Water or Dihydrogen Monoxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2O, or 18.01528 grams.

Thus, 63 grams  are in 3.5 moles of H2O.

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Answer: -40

Explanation: Percent error is calculated by subtracting the value you actually recieved from the literature value (175 in your case)  SO your answer should be 135-175=-40.

The final pressure of the gas is obtained as 4.80 atm.

We know that the root mean square speed of the gas would depend on the temperature of the molecules of the gas. Here we are told that the root mean square speed of the gas molecules is doubled and it means that the temperature was also doubled.

We have;

P1/T1 =P2/T2

2T1 = 2P1

The final pressure would  be 2(2.40)atm = 4.80 atm

Thus we ought to have the temperature at the end as 4.80 atm from the calculation that has been done.

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Answer:

\(\boxed {\boxed {\sf 1.6 \times 10^{24} \ atoms \ Si}}\)

Explanation:

We are asked to find how many atoms are in a sample of 75 grams of silicon.

First, we must convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. The molar mass is found on the Periodic Table because it is equal to the atomic mass, but the units are grams per mole instead of atomic mass units.

Look up the molar mass of silicon.

We convert using dimensional analysis, so we must set up a conversion factor.

\(\frac {28.085 \ g \ Si}{1 \ mol \ Si}\)

We are converting 75 grams of silicon to moles, so we multiply by this value.

\(75 \ g \ Si*\frac {28.085 \ g \ Si}{1 \ mol \ Si}\)

Flip the conversion factor so the units of grams of silicon cancel.

\(75 \ g \ Si*\frac {1 \ mol \ Si}{28.085 \ g \ Si}\)

\(75 *\frac {1 \ mol \ Si}{28.085 }\)

\(\frac {75}{28.085} \ mol \ Si\)

\(2.670464661 \ mol \ Si\)

Next, we convert moles to atoms using Avogadro's Number, or 6.022 ×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this problem, the particles are atoms of silicon.

Set up another conversion factor, this time with Avogadro's Number.

\(\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}\)

Multiply by the number of moles we found.

\(2.670464661 \ mol \ Si*\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}\)

The units of moles of silicon cancel.

\(2.670464661 *\frac {6.022 \times 10^{23} \ atoms \ Si}{1 }\)

\(2.670464661 * {6.022 \times 10^{23} \ atoms \ Si}\)

\(1.60815382 \times 10^{24} \ atoms \ Si\)

The original value of grams (75) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredths place tells us to leave the 6 in the tenths place.

\(1.6 \times 10^{24} \ atoms \ Si\)

Answer:

C6H12O6

Explanation:

C6H12O6

Answer:

1) As the temperature increased what happened to the N2O4 concentration, it decreased

2) Formation of products, products are the right hand side of the equation.

3) Right to left is exothermic

4) Change in enthalpy N2O4 ⇔2NO2, HR = -14 kcal

As it's an exothermic reaction, the enthalpy of the reactants is higher than the products and the sign of the HR will be negative.

Explanation:

N2O4 ⇔2NO2

(colorless) (reddish-brown)

1) As the temperature increased what happened to the N2O4 concentration, it decreased

2) Formation of products, products are the right hand side of the equation.

3) Right to left is exothermic

4) Change in enthalpy N2O4 ⇔2NO2, HR = -14 kcal

As it's an exothermic reaction, the enthalpy of the reactants is higher than the products and the sign of the HR will be negative.

Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.

Explanation:

The statements that are true about 13C NMR are:

A. In 13C proton-decoupled NMR spectra, all peaks are singlets.

C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.

D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry

Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.

The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.

Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.

Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:

Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)

Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.

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Hydrogen bond is not formed between carbon and hydrogen. That is option B.

Hydrogen bond can be defined as the type of bond that is characterized to be a weak force that forms a special type of dipole-dipole attraction which occurs when a hydrogen atom bonded to a very electronegative atom such as a Nitrogen, Oxygen or Fluorine.

The combination of carbon and hydrogen is through a chemical bond called covalent bond which can occur between carbon and hydrogen atoms that can be found in many organic compounds (these are compounds that are made up of mainly carbon and hydrogen atoms).

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The percent ionic character of a molecule can be calculated using the following equation:

Percent Ionic Character = 100 × (μ/r)^2

Where μ is the dipole moment in Debye and r is the bond length in picometers.

Plugging in the given values, we get:

Percent Ionic Character = 100 × (1.39/121)^2

Percent Ionic Character = 100 × (0.0115)^2

Percent Ionic Character = 1.32%

What is dipole moment?

The dipole moment is a measure of the separation of positive and negative charges in a molecule. It is represented by the vector sum of the individual bond dipole moments and is measured in debyes (D).

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Answer:1=B

2=A

Explanation:

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Answer:

I wouldn't risk it if i were you haha

Explanation:

These are radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays are in order of increasing frequency and decreasing in wavelength.

In general, the electromagnetic spectrum is divided into seven sections, rising in energy and frequency and decreasing in wavelength. Radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV) light, X-rays, and gamma rays ar names for these types of energy.

The parts of the electromagnetic spectrum are known to as gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves, from highest to lowest energy.

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