Diagram (Fig. 8) below are the Miller-Larson diagram of two nickel based super alloys, M9516 (top) and IN738LC (bottom). Note: Along the vertical axis (stress), consider the 8 minor sticks (shorter maker) between the two marked major sticks (longer marker) are linearly distributed When both materials are under a load of 272.2 MPa, what is the rupture time of the M951G alloy if they are working under 727 °C? M951G Stress (MPa) 25.4 25.6 25.8 26.0 26.2 26.4 26.6 26.8 103 T(20+logtr)K-h 1.14.4 day l. 180.9 day C . 180.9 year IV. 14.4 year

The vectors are magnitude of vector v is 5. The sum of vectors v1 and v2 is (+) = (2, 1, 8).  The difference between vectors v1 and v2 is (-) = (6, -1, -2). The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).

To find the magnitude (||) of a vector, we can use the formula:

||v|| = sqrt(v1^2 + v2^2 + v3^2)

Given vector v = (4, 0, 3), we can calculate its magnitude as follows:

||v|| = sqrt(4^2 + 0^2 + 3^2)

     = sqrt(16 + 0 + 9)

     = sqrt(25)

     = 5

Therefore, the magnitude of vector v is 5.

Now, let's find the sum (+) and difference (-) of the given vectors.

Given vectors v1 = (4, 0, 3) and v2 = (-2, 1, 5), the sum of these vectors is calculated by adding the corresponding components:

v1 + v2 = (4 + (-2), 0 + 1, 3 + 5)

       = (2, 1, 8)

The difference between the vectors is found by subtracting the corresponding components:

v1 - v2 = (4 - (-2), 0 - 1, 3 - 5)

       = (6, -1, -2)

Lastly, let's calculate the scalar multiple of vector v1:

3v1 = 3(4, 0, 3)

   = (12, 0, 9)

Therefore, the vectors are as follows:

- The magnitude of vector v is 5.

- The sum of vectors v1 and v2 is (+) = (2, 1, 8).

- The difference between vectors v1 and v2 is (-) = (6, -1, -2).

- The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).

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The initial pressure in the cylinder of 10 bar of argon with \(C_p\) = (5/2)·R

and the added gas at pressure of 50 bar gives the following values.

(a) 400.6 K

(b) 51.184 J

(c) The pressure of the cylinder when it is shipped is 37.194 bar

(a) Adiabatic compression, we have;

\(\dfrac{p_{1}}{p_{2}} = \mathbf{\left (\dfrac{T_{_{1}}}{T_{2}} \right )^{\dfrac{k}{k-1}}}\)

Where;

\(k = \dfrac{C_p}{C_v} = \mathbf{\dfrac{C_p}{C_p - R}}\)

Therefore;

\(K= \mathbf{\dfrac{\frac{5}{2} \cdot R}{\frac{5}{2} \cdot R - R} }= \dfrac{5}{3}\)

Which gives;

\(\dfrac{10}{50} = \left (\dfrac{298}{T_{2}} \right )^{\dfrac{\frac{5}{3} }{\frac{5}{3} -1}} = \left (\dfrac{298}{T_{2}} \right )^{2.5}\)

\(\dfrac{50}{10} = \mathbf{ \left (\dfrac{T_2}{298.15} \right )^{2.5}}\)

\(ln(5)= 2.5\cdot ln\left (\dfrac{T_2}{298.15} \right )\)

\(T_2 = 298 \times e^{\dfrac{ln(5)}{2.5} } \approx \mathbf{567.29\, K}\)

The temperature

Using an ideal gas model, we have;

\(\dfrac{V_{1}}{V_{2}} = \mathbf{\dfrac{P_{2}\times T_{1}}{T_{2} \times P_1}}\)

Which gives;

\(\dfrac{V_{1}}{V_{2}} = \dfrac{50\times 298}{567.29 \times 10} \approx 2.625\)

V₁ = 2.625·V₂

Volume occupied by the gas in the cylinder after the pressure increases is therefore;

\(V_2 = \dfrac{V_1}{2.625} \approx 0.381 \cdot V_1\)

Volume of gas added is therefore;

\(V =V_1 - \dfrac{V_1}{2.625} = 0.619\cdot V_1\)

Considering a molar volume of gas, we have;

0.040 × 0.619 × 2.5×8.3145×(T₃ - 298) = 0.040 × 0.381 × 2.5×8.3145×(567.29 - T₃)

Solving gives;

T₃ ≈ 400.6 K

For a molar volume of gas cylinder, the temperature just after the valve is closed is T₃ ≈ 400.6 K

(b) If the cylinder sits in the storage for a long time, and heat is conducted out, we have;

The temperature of the cylinder will revert to room temperature of 298 K

The heat transferred is therefore;

0.040 × (2.5 × 8.3145 - 8.3145) ×(400.6 - 298) ≈ 51.184

The heat transferred from the cylinder is 51.184 J

(c) The pressure of the gas in the cylinder is therefore;

\(\dfrac{P_1}{T_1} = \mathbf{\dfrac{P_2}{T_2}}\)

Which gives;

\(P_2= \mathbf{\dfrac{P_1}{T_1} \times T_2}\)

Therefore;

\(P_2= \dfrac{50}{400.6} \times 298 \approx 37.194\)

The pressure of the cylinder when it is shipped is 37.194 bar

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Answer:

steep grading

Explanation:

the farthest

Answer:

The City can grant higher budgets to emergency services like the Fire Department, so a higher budget will allow engineers & scientists to innovate new technology and add more fire stations across the city.

Explanation:

Coal-burning power plants emit pollutants such as sulfur dioxide, nitrogen oxides, and particulate matter. These pollutants can cause local air pollution, which can affect human health and the environment.

What is power plant?
A power plant is a type of industrial building used to produce electricity using raw materials. To meet society's electrical needs, the majority of power plants employ one or more generators that transform mechanical energy into electrical energy. Solar power plants are an exception, as they produce this electricity without the use of a turbine by using photovoltaic cells.

Air pollution from coal-burning power plants can travel through the atmosphere and deposit on other surfaces, including vegetation and water bodies. This deposition of pollutants can lead to acid rain, which can damage forests and aquatic ecosystems.

In addition, coal-burning power plants emit greenhouse gases such as carbon dioxide and methane, which contribute to climate change. Climate change can cause shifts in weather patterns, rising sea levels, and an increase in extreme weather events. These changes can affect human health, agriculture, and ecosystems across the globe.

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Answer:

whatsthe question choices

If control requirements are very complex or extensive, a: A. Master sequencer can be installed.

A master sequencer is a device that controls multiple circuits in a predetermined sequence. It is commonly used in industrial settings where multiple machines or systems need to be turned on or off in a specific order.  A master sequencer can be programmed to turn on and off circuits at specific times, or based on certain conditions. This allows for precise control of complex systems, and can help prevent equipment damage or failures.

Additionally, a master sequencer can provide a level of safety by ensuring that certain circuits are turned off before others are turned on, reducing the risk of accidents or injuries. Overall, a master sequencer is a valuable tool for controlling complex systems in industrial or commercial settings. So the answer is A. Master sequencer.

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Simply put, the phrase means that your package has been transported to the final delivery point that is closest to you. This message is often sent to you by the delivery service's last mile partner.

A notification that the prior shipping service's shuttle partner has been discharged is being offered to the delivery service provider.

Your delivery has been delivered to the nearby post office, which is what it signifies. Usually, USPS serves as the subcontractor, but occasionally, another postal agency may carry out the delivery.

Therefore, It indicates that the box was delivered in the most recent unit delivery, which may have been your neighbourhood post office. It implies that a couple different trucks from DHL will deliver your package.

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Answer: A leak in the system

Explanation:

Answer:

lol Jebus?

Explanation:

Answer:

addsa

sdadsa

Explanation:

dsads

Note that the maximum angle  (θ) that the package can travel before leaving the surface of the ramp is 29.2°.

The critical angle is calculated using the following formula

tan(θ\(_{c}\)) =v²}/rg

where:

Pluging in the values we have

\(tan(\theta_c) = \frac{4.5^2}{1.2 \times 9.8} = 0.518\)

Take the arctangent of both sides

\(\theta_c = \arctan(0.518) = 29.2^\circ\)

Therefore, the maximum angle that the package can travel before leaving the surface of the ramp is 29.2°

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✅C) Avoid having to use a net ✅

IamSugarBee

An architectural element that projects from a wall to support a horizontal part of a building such as beams or eaves of a roof is called: Bracket.

A soffit is a horizontal, elevated aspect of any construction element that can be seen on the interior or exterior of a building. The underside of eaves (used to join a retaining wall to projecting edge(s) of the roof) is its classic form, occasionally integrating or implying the projection of beams. The bracket that gives support underneath a structure like a roof, ceiling, window, beam, or shelf is known in architecture as a corbel. In addition, a block or other system that protrudes from a building's wall is referred to as a corbel.

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Answer: C) Collective action problem

Explanation:

Answer:

a

Explanation:

digital identity is the answer

The core domain for Accenture’s multi-party System is that of a digital identity. Ths that option A is correct.

A multiparty system is a shared data infrastructure within the individual and the organizations that drive the efficiency nf new business and lead to the formation of the revenue models. They include the blockchain and distribution database and include a variety of technology and other capabilities.

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The organizational strategy should ideally IS (Information Systems ) the is strategy.

Alignment between these two strategies is crucial for the overall success and effectiveness of an organization.

The IS strategy refers to the plan and direction of how information systems and technology are utilized within an organization to achieve its objectives. It encompasses the deployment, management, and utilization of technology to support business processes, enhance decision-making, improve efficiency, and gain a competitive advantage.

On the other hand, the organizational strategy defines the long-term goals and objectives of the organization, including its vision, mission, and overall direction. It outlines how the organization plans to achieve its goals, compete in the market, and create value for its stakeholders.

For optimal performance, it is important that the organizational strategy and the IS strategy are closely aligned. When they are not in sync, it can lead to inefficiencies, misallocation of resources, and a lack of integration between business processes and technology.

Alignment between these two strategies ensures that information systems and technology are strategically deployed to support the organization's goals and objectives. It enables the effective use of technology to enhance operations, streamline processes, improve decision-making, and ultimately drive organizational success.

When the organizational strategy and the IS strategy are aligned, organizations can leverage technology to gain a competitive advantage, respond quickly to market changes, innovate, and adapt to evolving customer needs. It fosters a cohesive and integrated approach, where technology becomes an enabler and catalyst for achieving strategic objectives.

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Answer:

oh god... i have no idea lm.ao

Explanation:

Answer:

The answer is below

Explanation:

The complete question is attached.

a) Bernoulli equation is given as:

\(P+\frac{1}{2}\rho V^2+ \rho gz=constant\\\\\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\)

Where P = pressure, V = velocity, z = height, g = acceleration due to gravity and ρ = density.

\(\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\\\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_1}{\gamma} +\frac{V_1^2}{2g} +z_1=\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2\\\\but \ z_1=z_2,P_1=0,V_1=0,V_2=60\ mph=88\ ft/s. Hence:\\\\\frac{P_2}{\gamma} =-\frac{V_2^2}{2g} \\\\P_2=\gamma*-\frac{V_2^2}{2g} =\rho g*-\frac{V_2^2}{2g} \\\\P_2=-\frac{V_2^2}{2}*\rho=-\frac{(88.8\ ft/s)^2}{2} * 0.00238\ slug/ft^3=-9.22\ lb/ft^2\\\\P_2+\gamma_{H_2O}h-\gamma_{oil}(1/12 \ ft)=0\\\\\)

\(\gamma_{oil}=0.9\gamma_{H_2O}=0.9*62.4\ lb/ft^3=56.2\ lb/ft^3\\\\Therefore:\\\\-9.22\ lb/ft^2+62.4\ lb/ft^3(h)-56.2\ lb/ft^3(1/12\ ft)=0\\\\h=0.223\ ft\)

b)

\(\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2=\frac{P_3}{\gamma} +\frac{V_3^2}{2g} +z_3\\\\but \ z_3=z_2,V_3=0,V_2=60\ mph=88\ ft/s. \\\\\frac{P_2}{\gamma}+\frac{V_2^2}{2g} = \frac{P_3}{\gamma}\\\\\frac{P_3-P_2}{\gamma}=\frac{V_2^2}{2g} \\\\P_3-P_2=\frac{V_2}{2g}*\gamma=\frac{V_2^2}{2g}*\rho g\\\\P_3-P_2=\frac{V_2}{2}*\rho=\frac{(88\ ft/s^2)^2}{2}*0.00238\ slg\ft^3\\\\P_3-P_2=9.22\ lb/ft^2\)

Answer:

  1.39 µmol

Explanation:

(1 gal) × (44.7 µg/L)/(121.76 g/mol)(3.785411784 L/gal) = 1.39 µmol

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

The energy density of pumped hydro electrical storage (PHES) with Δh = 300m is 11.3 kWh/m³.

The energy density of pumped hydro electrical storage (PHES) with Δh = 300m can be calculated using the following formula:

Energy Density = (Head x Density x Gravitational Acceleration)/(Efficiency x Specific Weight of Water)

where,Δh = Head = 300mρ = Density of Water = 1000 kg/m³g = Gravitational Acceleration = 9.81 m/s²η = Efficiency = 0.75γ = Specific Weight of Water = 9810 N/m³

Substituting the values in the formula,

Energy Density = (300 x 1000 x 9.81)/(0.75 x 9810)

Energy Density = 11.3 kWh/m³

Therefore, the energy density of pumped hydro electrical storage (PHES) with Δh = 300m is 11.3 kWh/m³.

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In materials that are in direct contact with one another, heat transmission happens through the conduction process. Usually, solids are where it happens.

1.8. Conduct Heat transfer is the movement of heat through materials without the mass of the material moving. Conduction, on the other hand, is the movement of energy from more energetic to less energetic particles of a substance as a result of particle contact.

Heating a skillet on a stove is a typical example of conduction. The pan's surface receives heat directly from the burner.

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Answer:

  leakage

Explanation:

That current is "leakage current."

As the angle of the ramp is increased, the force parallel increases. Hence, option (a) can be considered as the correct answer.

When the angle of a ramp is increased, the force parallel to the ramp, also known as the parallel component of the gravitational force, does increase. This is because the component of gravity acting parallel to the ramp increases with the angle. However, it's important to note that the total gravitational force acting on an object remains constant regardless of the angle of the ramp.As the angle of the ramp increases, the force required to push or pull an object up the ramp against gravity increases. This is due to the increase in the vertical component of the gravitational force, which opposes the motion up the ramp. The parallel force required to overcome this increased vertical force also increases.

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The statement "Forging is a deformation process in which the work is compressed between two dies, using either impact or gradual pressure to form the part" is true because the dies exert pressure on the workpiece, causing it to deform.

Forging is indeed a deformation process in which a workpiece is compressed between two dies to shape it into the desired form. Let's take a closer look at how forging works.

In the forging process, the workpiece, often a heated metal billet or ingot, is positioned between two dies. These dies have specific contours and shapes that correspond to the desired final shape of the forged part. The dies are typically made of hardened steel and are usually mounted in a forging press or hammer.

When the forging process begins, compressive forces are applied to the workpiece by closing or striking the dies together. This pressure causes the material to flow and deform, taking the shape defined by the dies. The applied force can be achieved through impact, where a hammer or similar tool strikes the workpiece, or through gradual pressure exerted by a hydraulic or mechanical press.

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The purpose of the control rods in a nuclear power plant are to regulate the rate of the nuclear reaction that is taking place in the reactor core of the nuclear power plant, and to stop the nuclear reaction in the event of an emergency.

In nuclear power plants, control rods are an essential component that help to control the rate of the nuclear reaction and prevent a nuclear meltdown.

Control rods are made of materials like boron or cadmium that are capable of absorbing neutrons.

When the control rods are inserted into the reactor core, they absorb neutrons and slow down the nuclear reaction.

When they are removed, the nuclear reaction speeds up again.

This makes them a crucial tool for regulating the output of a nuclear power plant.

Control rods also play an important role in safety, as they can be used to quickly stop the nuclear reaction in the event of an emergency.

If something goes wrong with the reactor, the control rods can be fully inserted into the core to stop the nuclear reaction from continuing.

This can help to prevent a meltdown and protect the safety of people living near the nuclear power plant.

In conclusion, control rods are a vital component in a nuclear power plant, as they help to regulate the rate of the nuclear reaction and can quickly stop the reaction in the event of an emergency.

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