|2b - 9|= |b - 6|
solve this please
Step-by-step explanation:
|2b - 9| = |b - 6|
|2b - b| = |-6 + 9|
|b| = |3|
b = 3
Hope I helped :)
List the side lengths in order from shorted to longest.
Answer:
z y x
Step-by-step explanation:
i dk
Answer:
X, Z, Y
Step-by-step explanation:
We can use the theorem that "opposite to the smallest angle lies the shortest side."
\(180 - 47 - 35 = 98\)
Against the angle with 98 degrees, the biggest angle, lies the longest side, y.
Against the angle with 35 degrees, the smallest angle, lies the shortest side, x.
So, we have the order:
x, z, y
If →u and →v are the vectors below, find the vector →w whose tail is at the point halfway from the tip of →v to the tip of →u+→v and whose head is at the point halfway from the tip of →u to the tip of →v. what is →w .
→u = [2 -1 -5]
→v = [1 -2 2]
Vector →w = [1.5, -1.5, -1.5] - [2, -2.5, -0.5] = [-0.5, 1, -1]
What method is used to calculate vector →w?Let →u and →v be the given vectors:
→u = [2, -1, -5]
→v = [1, -2, 2]
We need to find the vector →w such that its tail is at the point halfway from the tip of →v to the tip of →u+→v and its head is at the point halfway from the tip of →u to the tip of →v.
The tip of →v is at [1, -2, 2]. The tip of →u+→v is at the point obtained by adding →u and →v:
→u+→v = [2, -1, -5] + [1, -2, 2] = [3, -3, -3]
The halfway point between the tip of →v and the tip of →u+→v is the average of these two points:
[(1+3)/2, (-2-3)/2, (2-3)/2] = [2, -2.5, -0.5]
This point is the tail of →w.
The halfway point between the tip of →u and the tip of →v is:
[(2+1)/2, (-1-2)/2, (-5+2)/2] = [1.5, -1.5, -1.5]
This point is the head of →w.
Therefore, the vector →w is obtained by subtracting the tail from the head:
→w = [1.5, -1.5, -1.5] - [2, -2.5, -0.5] = [-0.5, 1, -1]
To find →w .→u, we take the dot product of →w and →u:
→w .→u = [-0.5, 1, -1] . [2, -1, -5]
= (-0.5 x 2) + (1 x -1) + (-1 x -5)
= -1
Therefore, →w .→u = -1
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A city doubles its size every 41 years. If the population is currently 700,000, what will the population be in 123 years?
The population in 123 years will be 5600000.
How to calculate the population?An expression is simply used to show the relationship between the variables that are provided or the data given regarding an information. in this case, it is vital to note that they have at least two terms which have to be related by through an operator.
In this case, the city doubles its size every 41 years. If the population is currently 700,000. After 123 years, it'll have doubled 3 times.
The population will be:
= 700000 × 2³
= 5600000
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Answer: 5600000
Step-by-step explanation: I got it right on my ixl
The slope of the line below is -0.5. Enter the equation for the line in point-
slope form.
(1, 1)
The equation for the line in point-(1, 1) is y = -0.5x + 0.5.
Given that the slope of the line below is -0.5. We are to enter the equation for the line in point-(1, 1).The equation for the slope-intercept form of the line is y = mx + c where m is the slope and c is the y-intercept.
Now, the slope of the line is given as -0.5.Therefore, the equation for the slope-intercept form of the line is y = -0.5x + c. Now we need to find the value of c for the equation of the line.
To find the value of c, substitute the values of x and y in the equation of the slope-intercept form of the line.
Given that the point is (-1,1), x=-1 and y=1y = -0.5x + c⇒ 1 = (-0.5) (-1) + c⇒ 1 = 0.5 + c⇒ c = 1 - 0.5⇒ c = 0.5
Therefore, the equation for the line in point-(1, 1) is y = -0.5x + 0.5.The slope of a line refers to how steep the line is and is used to describe its direction. Slope is defined as the vertical change between two points divided by the horizontal change between them.A positive slope moves up and to the right, while a negative slope moves down and to the right. If a line has a slope of zero, it is said to be a horizontal line.
The slope-intercept form of a linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept, or the point at which the line crosses the y-axis. To find the equation of a line with a given slope and a point, we can use the point-slope form of a linear equation.
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work out the value of (4^0 x 6^0)
Answer: 1
Step-by-step explanation:
2. Let f(x) = 2x^2 + x -3 and g(x) = x-1 preform the indicated operation, then find the domain.
(f * g)(x)
a. 2x^3 - x^2 - 4x+3; domain: all real numbers
b. 2x^3 + x^2 - 3x ; domain: all real numbers
c. 2x^3 + x^2 + 4x-3 ; domain: negative real numbers
d. 2x^2+x-3x+3
Answer:
a.
Step-by-step explanation:
for an arithmetic operation on functions you simply apply this operation to the functional expressions :
(2x² + x - 3)(x - 1) = 2x³ - 2x² + x² - x - 3x + 3 =
= 2x³ - x² - 4x + 3
the domain is the range of set of all valid input (x) variable values.
there is no reason to forbid any real number.
so, it is all real numbers.
Sunland Mining Company purchased land on February 1, 2020, at a cost of $975,900. It estimated that a total of 57,600 tons of mineral was available for mining. After it has removed all the natural resources, the company will be required to restore the property to its previous state because of strict environmental protection laws. It estimates the fair value of this restoration obligation at $110,700. It believes it will be able to sell the property afterwards for $123,000. It incurred developmental costs of $246,000 before it was able to do any mining. In 2020, resources removed totaled 28,800 tons. The company sold 21,120 tons.
Sunland Mining Company purchased land on February 1, 2020, at a cost of $975,900. It estimated that a total of 57,600 tons of mineral was available for mining. After it has removed all the natural resources, the company will be required to restore the property to its previous state because of strict environmental protection laws. It estimates the fair value of this restoration obligation at $110,700. It believes it will be able to sell the property afterwards for $123,000. It incurred developmental costs of $246,000 before it was able to do any mining. In 2020, resources removed totaled 28,800 tons. The company sold 21,120 tons.
Calculate :
a. Per unit mineral cost.
b. Total material cost of December 31, 2020, inventory
c. Total materials cost in cost of goods sold at December 31, 2014.
Answer:
a. Per unit mineral cost is $21
b. Total material Cost of ending inventory is $161280
c. Total materials cost in cost of goods sold is $443520
Step-by-step explanation:
The Per unit mineral cost can be computed as follows:
Details Amount ($)
Cost of land 975900
Add: Restoration obligation 110700
Add: Development cost 246000
1332600
Less: Resale value of property 123000
Total cost of land 1209600
Divide:Total estimated cost 57600
of minerals
Per unit mineral cost 21
b. The ending inventory cost on December 31, 2020 can be calculated as follows:
Ending inventory = Total mined tons - sold tons
Ending inventory = 28800 - 21120
Ending inventory = 7680
Cost per ton= $21
Cost of ending inventory = 7680 × $21
Cost of ending inventory = $161280
c.To calculate the cost of goods sold in December 2020; we have:
Cost per ton = $21
Total units sold = 21120
Cost of goods sold = 21120 × $21
Cost of goods sold = $443520
What is the perimeter of a rectangle with a length of 6 and a width of 5?
Answer:
\(\huge\boxed{Answer\hookleftarrow}\)
Given,
Length of the rectangle (l) = 6
Width of the rectangle (w) = 5
Perimeter of the rectangle (p) = ?
\(p = 2(l + w) \\ p = 2(6 + 5) \\p = 2(11) \\ p = 2 \times 11 \\ p = 22 \: \: units\)
⎆ The perimeter of the rectangle (p) is 22 units.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
# ꧁❣ RainbowSalt2²2² ࿐
the composition of two rotations with the same center is a rotation. to do so, you might want to use lemma 10.3.3. it makes things muuuuuch nicer.
The composition R2(R1(x)) is a rotation about the center C with angle of rotation given by the angle between the vectors P-Q and R2(R1(P))-C.
Lemma 10.3.3 states that any rigid motion of the plane is either a translation a rotation about a fixed point or a reflection across a line.
To prove that the composition of two rotations with the same center is a rotation can use the following argument:
Let R1 and R2 be two rotations with the same center C and let theta1 and theta2 be their respective angles of rotation.
Without loss of generality can assume that R1 is applied before R2.
By Lemma 10.3.3 know that any rotation about a fixed point is a rigid motion of the plane.
R1 and R2 are both rigid motions of the plane and their composition R2(R1(x)) is also a rigid motion of the plane.
The effect of R1 followed by R2 on a point P in the plane. Let P' be the image of P under R1 and let P'' be the image of P' under R2.
Then, we have:
P'' = R2(R1(P))
= R2(P')
Let theta be the angle of rotation of the composition R2(R1(x)).
We want to show that theta is also a rotation about the center C.
To find a point Q in the plane that is fixed by the composition R2(R1(x)).
The angle of rotation theta must be the angle between the line segment CQ and its image under the composition R2(R1(x)).
Let Q be the image of C under R1, i.e., Q = R1(C).
Then, we have:
R2(Q) = R2(R1(C)) = C
This means that the center C is fixed by the composition R2(R1(x)). Moreover, for any point P in the plane, we have:
R2(R1(P)) - C = R2(R1(P) - Q)
The right-hand side of this equation is the image of the vector P-Q under the composition R2(R1(x)).
The composition R2(R1(x)) is a rotation about the center C angle of rotation given by the angle between the vectors P-Q and R2(R1(P))-C.
The composition of two rotations with the same center is a rotation about that center.
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4\3(-12)+8=
answer quickly please
actually it took to long and it -8 for anyone who would like to know :)
Answer:
-24
Step-by-step explanation:
4/3(-12)-8
1.3(-12)‐8
-24
A rhombus, which is a quadrilateral with 4 equal sides, is plotted on the coordinate plane. The coordinates of the vertices are (2, 0), (7, 0), (5, 4), and (10, 4). How long is each side of the rhombus?.
Answer:
5 units
Step-by-step explanation:
You want to know the side length of the rhombus with vertices (2, 0), (7, 0), (5, 4), and (10, 4).
Side lengthYou can find the length of the horizontal edges by counting the grid squares, or by subtracting the x-coordinates:
7 -2 = 5
10 -5 = 5
The slanted sides are each the hypotenuse of a 3-4-5 right triangle, so are also 5 units long. (You expect all of the sides of the rhombus to be the same length.)
Each side is 5 units long.
The answer is 5, 4.47, 5, and 8.94.
Step 1: Determine the length of the sides using the distance formula.The distance formula is d = √(x2-x1)^2 + (y2-y1)^2
Step 2: Calculate the length of the first side. To do this, plug in the coordinates for the two points that make up the first side into the distance formula. This side is formed by the points (2, 0) and (7, 0).d = √(7-2)^2 + (0-0)^2
d = √(5)^2 + (0)^2
d = √(25) + (0)
d = 5
Step 3: Calculate the length of the second side. To do this, plug in the coordinates for the two points that make up the second side into the distance formula. This side is formed by the points (7, 0) and (5, 4).d = √(5 - 7)^2 + (4 - 0)^2
d = √(-2)^2 + (4)^2
d = √4 + 16
d = √20
d = 4.47
Step 4: Calculate the length of the third side. To do this, plug in the coordinates for the two points that make up the third side into the distance formula. This side is formed by points (5, 4) and (10, 4).d = √(10 - 5)^2 + (4 - 4)^2
d = √25 + 0
d = 5
Step 5: Calculate the length of the fourth side. To do this, plug in the coordinates for the two points that make up the fourth side into the distance formula. This side is formed by the points (10, 4) and (2, 0).d = √(2 - 10)^2 + (0- 4)^2
d = √(-8)^2 + (-4)^2
d = √64 + 16
d = √80
d = 8.94
Therefore, each side of the rhombus has a length of 5, 4.47, 5, and 8.94.
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a spring, whose equilibrium length is 1 m,1 m, extends to a length of 4 m4 m when a force of 5 n5 n is applied. find the work needed to extend the spring to a length of 2 m.
The work needed to extend the spring to a length of 2 m is 1.875 Joules.
To find the work needed to extend the spring to a length of 2 m, we can use the concept of work done by a force in stretching a spring.
The work done is given by the formula:
Work =\((1/2)k(x^2 - x0^2)\),
where k is the spring constant, x is the final displacement, and x0 is the initial displacement (equilibrium length).
Given:
Equilibrium length (x0) = 1 m
Force applied (F) = 5 N
Final displacement (x) = 2 m
We need to find the spring constant (k) to calculate the work. The spring constant can be determined using Hooke's Law:
F = k * x
Substituting the values:
5 N = k * 4 m
Solving for k:
k = 5 N / 4 m = 1.25 N/m
Now we can calculate the work done to extend the spring to a length of 2 m:
Work = (1/2) * k * (x^2 - x0^2)
= (1/2) * 1.25 N/m * ((2 m)^2 - (1 m)^2)
= (1/2) * 1.25 N/m * (4 m^2 - 1 m^2)
= (1/2) * 1.25 N/m * 3 m^2
= (1/2) * 3.75 N*m
= 1.875 J
Therefore, the work needed to extend the spring to a length of 2 m is 1.875 Joules.
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IK this is simple math but I need help.
Answer:
C
Step-by-step explanation:
\(60*2 = 120\)
\(60*3=180\)
\(60*4=240\)
Please help me out tired want to sleep
Answer:
The approximate area by Riemann Sum of the curve is represented by \(A = 0.4\cdot \Sigma\limits_{t = 1}^{n} [2\cdot (2+0.4\cdot t)^{3} - 4]\).
Step-by-step explanation:
The area below the curve is estimated by the concept of Riemann Sum with right endpoint rectangles, which is defined by the following formula:
\(A = \left(\frac{\Delta x}{n} \right) \cdot \Sigma \limits_{t = 1}^{n} g\left (x_{o} + \frac{\Delta x}{n}\cdot t \right)\) (1)
Where:
\(A\) - Area below the curve, in square units.
\(n\) - Number of rectangles, no units.
\(x_{o}\) - Lower bound of the interval, in units.
\(\Delta x\) - Length of the interval, in units.
\(t\) - Summation index.
If we know that \(g(x) = 2\cdot x^{3} - 4\), \(n = 10\), \(x_{o} = 2\) and \(\Delta x = 4\), then the area below the curve is represented by the following equation:
\(A = 0.4\cdot \Sigma\limits_{t = 1}^{n} [2\cdot (2+0.4\cdot t)^{3} - 4]\)
Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply.
For any value of x, g(x) will always be greater than h(x).
For any value of x, h(x) will always be greater than g(x).
g(x) > h(x) for x = -1.
g(x) < h(x) for x = 3.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Correct option are C,D, E. g(x) > h(x) for x = -1, For positive values of x, g(x) > h(x), For negative values of x, g(x) > h(x).
What are functions?A function is a type of rule that produces one output for a single input. This is illustrated by the equation y=x2. Any input for x results in a single output for y. Considering that x is the input value, we would state that y is a function of x.
They have the same value if x=0.
The first and second choices are not viable
for x=-1
g(-1)=1
h(-1)=-1
3. is accurate
4th , false G(x)>H for all values other than zero (x)
the proper ones are
For x=-1, g(x) exceeds h(x).
G(x) > h for positive values of x. (x).
G(x) > h for negative values of x (x).
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write code to assign x and y coordinates to currcoord, and store currcoord in locations. input first receives an x value, then a y value. input example: 12 32 88 2 -1 -1
It will be feasible to create a coordinate code that looks like this using the knowledge of the Python computational language:
Writing coordinate code in python:
def __init__(self, x, y):
self.x = x
self.y = y
def getX(self):
directly
return self.x
def getY(self):
return self.y
def __str__(self):
return '<' + str(self.getX()) + ',' + str(self.getY()) + '>'
class Coordinate(object):
def __init__(self,x,y):
self.x = x
self.y = y
def getX(self):
return self.x
def getY(self):
return self.y
def __str__(self):
return '<' + str(self.getX()) + ',' + str(self.getY()) + '>'
def __eq__(self, other):
if other.x == self.x and other.y == self.y:
return True
else:
return False
def __repr__(self):
return "Coordinate"+ str((self.x, self.y))
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Find the missing dimension of the figure shown to the right round to the nearest 10th
Given the right triangle:
The Pythagorean theorem states that:
\(a^2+b^2=c^2\)From the problem, we identify:
\(\begin{gathered} b=14^{\prime}^{\prime} \\ c=19^{\prime}^{\prime} \end{gathered}\)And a is our missing value. Using the Pythagorean theorem:
\(\begin{gathered} a+14^2=19^2 \\ a^2=361-196 \\ a=\sqrt[]{165} \\ a=12.8^{\prime}^{\prime} \end{gathered}\)It takes Sally 15 min to pick the apples from the tree in her backyard. Lisa
can do it in 25 min. How long will it take them working together?
The answer for this problem is that the number is 31p
The temperature fell from 0 degrees farenheight to 6 3/5 in 2 1/5 hours. What was the temperature change per hour?
A. -3
B. -4 2/5
C. 3
D. 4 2/5
Answer with step-by-step explanation:
C: 3
This is because 6 3/5 is a positive number, and 6 3/5 ÷ 2 1/5 = 3
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Can SAS be proven congruent?
Yes SAS can be proven to be congruent
What is SAS congruent postulate?The SAS postulate says that if two sides of one triangle and the angle included between them are congruent to two sides and the included angle of a second triangle, then the triangles are congruent. SAS as the meaning of Side- Angle - side
For example, in triangle ABC , where AB is 10cm and AC is 7cm and angle A is 50°
and another triangle XYZ , where XZ is 10 and YZ is 7 and angle Z is 50°
to prove ∆ ABC and ∆ XYZ are congruent, we have to check if the two sides of a triangle are congruent to the other two sides of the corresponding triangle and the included angles are congruent in both triangle.
XZ = AB
YZ = AC
angle Z = 50° = angle A
therefore ∆ABC and ∆XYZ are congruent.
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Kate places greeting cards from two different companies on a display rack that can hold up to 90 cards. She
has agreed to display at least 40 of company a's cards on the rack and at least 25 of company b's cards.
kate makes a profit of $0. 30 on each card she sells from company a and $0. 32 on each card she sells from
company b.
To get the maximum profit, Kate should display as many cards from company B as possible, since she makes a higher profit from those cards.
Let x be the number of cards from company A and y be the number of cards from company B.
The constraints are:
x + y ≤ 90 (the display rack can hold up to 90 cards) x ≥ 40 (at least 40 of company A's cards must be displayed) y ≥ 25 (at least 25 of company B's cards must be displayed)The objective function is:
P = 0.30x + 0.32y (the profit from selling the cards)
To maximize the profit, we need to maximize the value of y. Since the display rack can hold up to 90 cards, we can set y = 90 - x.
Substituting this into the objective function:
P = 0.30x + 0.32(90 - x)
P = 0.30x + 28.8 - 0.32x
P = -0.02x + 28.8
To maximize P, we need to minimize x. Since x must be at least 40, we can set x = 40.
Substituting this back into the objective function:
P = -0.02(40) + 28.8
P = 28
So the maximum profit Kate can make is $28, by displaying 40 cards from company A and 50 cards from company B.
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What are the inputs of the function below? x –8 2 4 6 f(x) –6 –3 1 5 –6, –3, 1, 5 –6, –3, 4, 6 –8, 2, 4, 6 –8, 2, 1, 5
The inputs of the function are -8, 2, 4, and 6.
What is the input function?The input is the number that we put into the given function to get the output function.
x and y of the function are given below
X –8 2 4 6
f(x) –6 –3 1 5
From the given table, the inputs are given as the set of x values.
outputs are given as the set of y values. here, x is the input value that gives the output f(x).
Since x represents the input values and y represents the output values.
So, inputs of the function are -8, 2, 4 and 6
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Half a number increased by 15 is equal to the sum of five and the product of three and the number what is the number 
The number is (x/2)+15=5+3x if Half of Number augmented by 15 equals the sum of 5 and the product of 3 and the number.
Explain what a number system is?A system of writing numbers is known as a number system. It is the mathematical notation for consistently employing digits or other symbols to represent the numbers in a particular set. It represents the arithmetic and algebraic structure of the numbers and gives each number a distinct representation.
Which four different number systems are there?Decimal Number System is one of the four popular forms of number systems and other 3 are -
System of binary numbers.
System of Octal Numbers.
System of Hexadecimal Numbers.
From the given question,
X is the number. first we have to halve it , then we add 15.
Next ,set it equal to the other side . the second side is 5+ ( because it is the sum)
3x( the product of 3 and x means multiply them)
Hence the number is (x/2)+15=5+3x
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4. a drama club is planning a bus trip to new york city to see a broadway play. the cost per person for the bus rental varies inversely as the number of people going on the trip. it will cost $22 per person if 44 people go on the trip. how much will it cost per person if 66 people go on the trip? round your answer to the nearest cent, if necessary
If 44 people go on the trip, the cost per person is $22. If the number of people increases to 66, the cost per person will be approximately $14.67.
The problem states that the cost per person for the bus rental varies inversely as the number of people going on the trip. In other words, as the number of people increases, the cost per person decreases, and vice versa.
To find the cost per person when 66 people go on the trip, we can set up a proportion based on the inverse variation relationship. Let's denote the cost per person when 66 people go as x. The proportion can be written as:
44/22 = 66/x
To solve for x, we can cross-multiply and then divide:
44x = 22 * 66
x = (22 * 66) / 44
x ≈ 14.67
Therefore, if 66 people go on the trip, the cost per person will be approximately $14.67 when rounded to the nearest cent.
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help pls xxxxxxxxxxx
Answer:
inside the c circle put 12 inside the d circle put 7 and inside the middle put 19 or 15 and inside rectangle put 30
100 points
Choose the different ways that a graph can be misleading.
The y-axis starts at zero and uses consistent intervals.
Different bar heights are used on the same graph.
The y-axis doesn't start at zero.
The intervals on the y-axis are too large.
Different bar widths are used on the same graph.
The y-axis starts at zero but has different intervals.
Just a little note you put 50 points and not 100
The y-axis doesn't start at zero.
The intervals on the y-axis are too large.
Different bar widths are used on the same graph.
The y-axis starts at zero but has different intervals.
Answer:
The y-axis starts at zero and uses consistent intervals.
Step-by-step explanation:
List the angles in order from least to Greatest.
Answer:
I think it would be B) A,B,C
Step-by-step explanation:
well A is smaller than B or C and B is smaller than C.
Anyone read yaoi?
i finished all of them
plz help i need to fill this void in my soul
any recomendations?
Answer:
um ever watched banana fish? or go on wattpad?
Step-by-step explanation:
Answer:
You can read (if u have not read it yet) Seashell Boy, When the yakuza fall in love, Don´t pick up the soap, Love is an illusion, Bj Alex, Your wish is my command, Better than strangers. etc.
Step-by-step explanation:
prove that if g is a finite group the index of z(g) cannot be prime
A finite group is a group that has a finite number of elements. Now, let us define the center of a group. The center of a group, denoted by Z(G), is the set of all elements in G that commute with every element in G.
Now, we need to prove that if g is a finite group, the index of Z(g) cannot be prime. We can prove this using contradiction. Suppose the index of Z(g) is prime. Let this prime be denoted by p. This means that the number of distinct left cosets of Z(g) in g is p. Therefore, we can write:
|g/Z(g)| = p
where |g/Z(g)| represents the number of distinct left cosets of Z(g) in g.
Now, we can use the fact that the number of left cosets of a subgroup in a group is equal to the index of that subgroup in the group. Therefore, we can rewrite the above equation as:
|g|/|Z(g)| = p
Multiplying both sides by |Z(g)|, we get:
|g| = p|Z(g)|
Since p is a prime number, it can only be divided by 1 and itself. Therefore, the only possible divisors of p|Z(g)| are 1, p, and |Z(g)|.
Now, since |g| is finite, we know that |Z(g)| cannot be infinite. Therefore, the only possible values for |Z(g)| are positive integers that divide |g|. However, since p is a prime number, |Z(g)| cannot be equal to p. This means that the only possible values for |Z(g)| are 1 and |g|.
If |Z(g)| = 1, this means that Z(g) only contains the identity element. Therefore, g does not have any non-identity elements that commute with every other element in g. This is not possible since every group has at least one element that commutes with every other element in the group - the identity element.
If |Z(g)| = |g|, this means that every element in g commutes with every other element in g. This implies that g is an abelian group. However, this contradicts the fact that g is a finite group that is not abelian.
Therefore, we have reached a contradiction in both cases. This means that our assumption that the index of Z(g) is prime is false. Therefore, if g is a finite group, the index of Z(g) cannot be prime.
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