Convert 0.128 to a percent.

The required distance between the take-off point and the water tower is 1980.1 feet.

Given that,
A plane took off and rose at an angle of 8º with the horizontal ground. As the plane flies over a water tower, it has covered a distance from the take-off point of 2000 feet.
To determine how far apart are the take-off point and the water tower.​

These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operation.

Here,
Now,
The distance flying over inclination is 2000 feet at an angle of 8° with horizontal.
Now,
Required horizontal distance = 2000 * cos 8°
                                            = 1980.1 feet.

Thus, the required distance between the take-off point and the water tower is 1980.1 feet.

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Since it's a two-tailed test, P-value = 2 * 0.1271 ≈ 0.2542.

With α = 0.01, the P-value (0.2542) is greater than α, so Steve should fail to reject the null hypothesis.

Steve's hypotheses should be:

H₀: p = 0.346

H₁: p ≠ 0.346

Using the sample, we find the sample proportion (p_hat) is 93/250 = 0.372.

To calculate the z-test statistic:

z = (p_hat - p) / sqrt((p * (1 - p)) / n)

z = (0.372 - 0.346) / sqrt((0.346 * 0.654) / 250)

z ≈ 1.14

To find the P-value, use a two-tailed test and a z-table to determine the area right of z. ≈ 0.1271. Since it's a two-tailed test, P-value = 2 * 0.1271 ≈ 0.2542.

With α = 0.01, the P-value (0.2542) is greater than α, so Steve should fail to reject the null hypothesis.

The evidence is not strong enough to suggest that the proportion of students planning to attend college differs from 34.6%.

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Students will apply their understanding of differentiation and analytical techniques to solve real-world problems.

Unit 5 in analytical applications of differentiation typically covers topics such as finding maximum and minimum values, optimization problems, related rates, and curve sketching using differentiation techniques. These topics require an understanding of differentiation, which is the process of finding the rate at which a function changes at a specific point or interval. Analytical techniques involve using algebraic methods to solve problems, which is necessary for solving complex optimization and related rates problems.

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Answer:

10

Step-by-step explanation:

Perform the said operations

Answer:

10

Step-by-step explanation:

16*2 = 32

32/8 = 4

4*15 = 60

60/6 = 10

10

The dimensions of the closed rectangular box with a square base and volume of 8000 cubic centimeters that can be constructed with the least amount of material are 20 cm.

Let the length and width of the rectangular box with a square base be x.

and the height is y.

The volume, V = 8000 = \(x^{2} y\)       --------(1)

The surface area, S = 2\(x^{2}\) + 4xy .   -------(2)

S =  2\(x^{2}\) + 4xy and  8000/ \(x^{2}\) =y     -------( from 1 and 2)

so, S= 2\(x^{2}\) + 4x(8000/ \(x^{2}\))

S= 2\(x^{2}\) + 32000/x

to find the least amount of material to be used, we will differentiate the surface area w.r.t x.

ds/dx= 0 = 4x - 32000/\(x^{2}\)

therefore, we have, 4x = 32000/\(x^{2}\)

                                 4\(x^{3}\) =32000

                                   \(x^{3}\) =8000

                                     x=20

Hence, The dimensions of the closed rectangular box with a square base and volume of 8000 cubic centimeters that can be constructed with the least amount of material are 20 cm.

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Answer:

x + 5y -10 = 2x

or, 5y = 2x - x + 10

or, 5y = x + 10

or, y = (x + 10)/5

The Venn diagram is given below. Then the number of students who offer only Twi will be 9.

Sets are groups of clearly specified components. The number of items in a finite set is denoted by a curly bracket.

In a class of 39 students, 25 offer Fante and 19 offer Twi.

Five students do not offer any of the two languages.

The Venn diagram is given below.

The number of students who offer both Fante and Twi will be

⇒ 25 + 19 - (39 - 5)

⇒ 44 - 34

⇒ 10

Then the number of students who offer only Twi will be

⇒ 19 - 10

⇒ 9

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Answer:

1.72

Step-by-step explanation:

AB tangent at D, AD = OD = 4

so triangle OAD is right angle with side of 4 and 4.

area of OAD = 1/2 * 4 * 4 = 8

Angle AOD = DAO = 45 deg.

so circular sector OCD area = area of circle O * 45/360

= pi * 4 * 4 * 45/360

= 2pi

Shade area ACD = trigangle OAD - circular sector OCD

= 8 - 2pi

= 1.72

Answer:

.....Your answer is D

...

.

Answer:

  0.253 m/s

Step-by-step explanation:

You want to know the horizontal component of motion of a passenger riding a Ferris wheel when they are 1/27 of the way around the circle and their rate of rise is 0.06 m/s.

The wheel makes one revolution in 27 minutes, so the angular displacement is changing at the rate of (360°)/(27 min) = 13 1/3°/min.

After 1 minute, the passenger is following a path that has an angle of elevation of 13 1/3°.

The ratio of vertical speed to horizontal speed will be the tangent of the angle of elevation:

  Vv/Vh = tan(13 1/3°)

Then the horizontal speed will be ...

  Vh = Vv/tan(13 1/3°) = (0.06 m/s)/0.237004

  Vh ≈ 0.253 m/s

The passenger's horizontal motion is about 0.253 m/s.

The efficiency E (expressed as a percent) of the assembly line worker at time t hours since the worker's shift began is given by E(t) = 50t - 2t^2 + 48.

To find E(t), we need to integrate the rate function E'(t) with respect to time t:

∫E'(t) dt = ∫(50 - 4t) dt

E(t) = 50t - 2t^2 + C

where C is a constant of integration. We can determine the value of C by using the initial condition E(1) = 96:

E(1) = 50(1) - 2(1)^2 + C = 96

Simplifying this equation, we get:

C = 48

Now we can substitute C into our equation for E(t):

E(t) = 50t - 2t^2 + 48

Therefore, the efficiency E (expressed as a percent) of the assembly line worker at time t hours since the worker's shift began is given by E(t) = 50t - 2t^2 + 48.

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Answer:

yes the answer is x = -2

Step-by-step explanation:

0.25x^2 - 0.16y^4

Both terms are perfect squares so use the difference of squares formula

A^2 - b^2 = (a+b)(a-b) where a = 5x and b = 4y^2

Answer is 0.01(5x + 4y^2)(5x-4y^2)

Answer:

Solution given:

0.25x^2 - 0.16y^4

[0.5x]²-[0.4y²]²

[Note: Using formula: x²-y²=(x+y)(x-y)]

(0.5x+0.4y²)(0.5x-0.4y²) is a required answer.

\(\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-1}x^2\stackrel{\stackrel{b}{\downarrow }}{-6}x\stackrel{\stackrel{c}{\downarrow }}{-16} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ -6}{2(-1)}~~~~ ,~~~~ -16-\cfrac{ (-6)^2}{4(-1)}\right) \implies \left( - \cfrac{ -6 }{ -2 }~~,~~-16 - \cfrac{ 36 }{ -4 } \right) \\\\\\ (-3~~,~~-16+9)\implies (-3~~,~~-7)\)

Answer:

Step-by-step explanation:

The answer is B I think

Answer:

Step-by-step explanation:

The nth term of an arithmetic sequence:  aₙ = a₁ + d(n - 1)

{d = common difference}

a₁ = 5

a₄ = 5 + d(4 - 1)

-4 = 5 + 3d

-4 - 5 = 3d

3d = -9

 d = -3

Therefore;

                  aₙ = 5 + (-3)(n - 1)

                   aₙ = -3n + 8

Check:  a₁₀ = 5 + (-3)(10 - 1) = 5 - 27 = - 22

The nth term of the sequence is Tn = 8 - 3n

The given parameters are:

a = 5, first term

T4 = -4 --- the 4th term

T10 = -22 --- the 10th term

The nth term of an arithmetic sequence is:

Tn = a + (n - 1) * d

So, we  have:

T4 = a + (4 - 1) * d

Substitute known values

-4 = 5 +(4 -1) * d

This gives

-4 = 5 + 3d

Subtract 5 from both sides

3d = -9

Divide by 3

d = -3

Recall that:

Tn = a + (n - 1) * d

So, we have:

Tn = 5 + (n - 1) * -3

Expand

Tn = 5 + 3 - 3n

Solve

Tn = 8 - 3n

Hence, the nth term of the sequence is Tn = 8 - 3n

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Given:

Leo had $91, which is 7 times as much money as Alison had.

Let x represents Alison's money.

So, the expression for Leo's money is,

Divide both sides of the above equation by 7.

So, Alison had $13.

Therefore, the correct solution method is

A) 7x = 91. Divide both sides by 7. Alison had $13.

To find the third side of an inequality of a triangle, you must first use the Triangle Inequality Theorem.

This theorem states that for any triangle, the sum of any two sides of the triangle must be greater than the third side. This means that in order to find the length of the third side, you must subtract the sum of the two known sides from the smaller of the two sides, then the length of the third side will be equal to the difference between these two numbers. For example, if two sides of a triangle have lengths of 4 and 3, the third side must be greater than 1 (4 + 3 = 7 and 4 - 3 = 1). Therefore, the length of the third side must be greater than 1.

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Therefore, the correct expression of the density, rounded to three significant figures, would be 2.46 g/cm³.

To express a density value to three significant figures, you need to consider the number of significant figures in the given data or measurement.

For example, if the given data or measurement has four significant figures, you would round the density value to three significant figures.

Let's consider an example:

Suppose the density of a substance is measured as 2.456 grams per cubic centimeter (g/cm³). To express this density value to three significant figures, you would round it to the nearest thousandth:

2.456 g/cm³ rounded to three significant figures is 2.46 g/cm³.

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Answer:

4/52

Step-by-step explanation:

We multiply these three individual probabilities together to get P(QQQ) = P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52)

HOPE THIS HELPS

Answer:

7(x + 5)

Step-by-step explanation:

7x has the following factors: 1,7,x

35 has the following factors: 1, 5, 7, 35

the greatest common factor is 7

7(x + 5) = 7x + 35

Answer:

The first number is 3

The second number is 7

Step-by-step explanation:

Let x = the first number

Let y = the second (other) number

One number added to three times another number is 24:

x + 3y = 24

Make 3y the subject by subtracting x from both sides:  3y = 24 - x

Five times the first number added to three times the other number is 36:

5x + 3y = 36

Substitute  3y = 24 - x  into  5x + 3y = 36  and solve for x:

5x + (24 - x) = 36

5x + 24 - x = 36

Combine like terms:  4x + 24 = 36

Subtract 24 from both sides:  4x = 12

Divide both sides by 4:  x = 3

Substitute found value of x into x + 3y = 24 to find y:

3 + 3y = 24

Subtract 3 from both sides:  3y = 21

Divide both sides by 3:  y = 7

Answer:

-3/2 which is a

Step-by-step explanation: finding the exact value

The value (-15/8 + 1.5) ÷ (15 - \(14\frac{3}{4}\))  = -3/2,

Hence, Option A is correct.

The given expression is,

(-15/8 + 1.5) ÷ (15 - \(14\frac{3}{4}\))

Since we know,

Dividing two fractions is equivalent to multiplying the first fraction by its reciprocal. The first step in splitting fractions is to get the reciprocal of the second fraction (reverse the numerator and denominator). Then, multiply the numerators.

Here we have to find the value of the given expression is,

We can write it as,

⇒  (-15/8 + 1.5) ÷ (15 - 59/4)

⇒  (-15 + 12)/8  ÷ (60-59)/4

⇒  -3/8 ÷ 1/4

⇒  -3/8 x 4/1

⇒  -3/2

Hence,

(-15/8 + 1.5) ÷ (15 - \(14\frac{3}{4}\))  = -3/2

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Answer: 96 played one sport only.

Step-by-step explanation:

To find out how many played one sport only, we can use the principle of inclusion-exclusion.

Let S be the total number of sports men surveyed. Then, we have:

S = number who played soccer + number who played volleyball + number who played basketball - number who played soccer and volleyball - number who played soccer and basketball - number who played volleyball and basketball + number who played all three sports

Substituting the given values, we get:

S = 64 + 94 + 58 - 28 - 26 - 22 + 14

S = 154

Therefore, there were 154 sports men surveyed in total.

Now, let x be the number of sports men who played one sport only. Then, we have:

x = number who played soccer only + number who played volleyball only + number who played basketball only

Substituting the given values and using the principle of inclusion-exclusion, we get:

x = (64 - 28 - 26 + 14) + (94 - 28 - 22 + 14) + (58 - 26 - 22 + 14)

x = 22 + 58 + 24

x = 104

Therefore, there were 104 sports men who played one sport only.

Note that this includes those who did not play any of the three sports. To find out how many played at least one sport, we can subtract the number who did not play any sport from the total number surveyed:

number who played at least one sport = total number surveyed - number who did not play any sport

number who played at least one sport = 154 - (S - x)

number who played at least one sport = 154 - (154 - 14)

number who played at least one sport = 14

Therefore, there were 14 sports men who did not play any of the three sports.

Finally, to find out how many played one sport only, excluding those who did not play any sport, we can subtract 14 from 104:

number who played one sport only, excluding those who did not play any sport = 104 - 14

number who played one sport only, excluding those who did not play any sport = 90

Therefore, there were 90 sports men who played one sport only, excluding those who did not play any sport.

Answer:

No

Step-by-step explanation:

The only consecutive integers that satisfy the Pythagorean theorem are 3, 4, and 5.

___

4^2 ≠ 2^2 + 3^2

16 ≠ 4 + 9 . . . . . . . an attempt at applying the Pythagorean theorem to the given numbers fails.

Answer:

mAngleFDE = 92°

Step-by-step explanation:

Angle BDC and Angle FDB are supplementary angles, that is they add up to 180° So we can write an equation. Solve for x. Then find AngleBDC. AngleBDC and AngleFDE are equal because they are vertical angles.

8x+12+12x-32 = 180°

Combine like terms.

20x - 20 = 180

Add 20.

20x = 200

Divide by 20.

x = 10

AngleBDC

= 8x + 12

= 8(10) + 12

= 80 + 12

= 92°

AngleFDE

= AngleBDC

= 92°

Looks like the picture is not drawn to scale, but no worries. The math is all good.

Answer:

157.08 ft

Step-by-step explanation:

R = 20+5 = 25

Circumfrence = 2*pi*r = 2*pi*25 = 157.079 ft

Answer:

K=24

B=21

Step-by-step explanation:

x+x-5=43

2x=48

x=24

K=24

B=21

Answer:

24

Step-by-step explanation:

So the only way I think would be possible to get the answer is if you divide 43 by 2 (since Bobbie and Kylie are 2 people) then subtract 5 to get the answer?