calculate the atomic mass of carbon if the two common isotopes of carbon have masses of 12.000 amu (98.89% abundance) and 13.003 amu (1.11% abundance)

Answers

Answer 1

12.01 amu

Work:

(12.000 × .9889) + (13.003 × .0111) = 12.01

turn the precents into decimals


Related Questions

Experiments conducted flow of liquid through eylinder Shows following correlation for a dissolving solute ( mass tramien Sh=0.023(Re)0.83(3e)1/3;Sh=5herwood number, 3e = benimidt number colburn Asbuming chilton-analogy, write the corresponding heat transfer correlation.

Answers

The Chilton-Colburn analogy, also known as Reynolds Analogy, provides a connection between heat transfer and mass transfer of a fluid.

Hence, the corresponding heat transfer correlation, assuming the Chilton-Colburn analogy for mass transfer is:

Sh = 0.023(Re)0.83(3e)1/3

The corresponding heat transfer correlation by Chilton-Colburn analogy is:

Nu = 0.023 (Re)0.83 (Pr)n, where n = 0.4 to 0.6.

Assuming that the Chilton-Colburn analogy holds good for the present situation, the above correlation can be used as a heat transfer correlation.

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For periods 2 and above, what is the maximum number of valence
electrons that an atom can have?

Answers

7 electrons, These elements can include fluorine, chlorine, bromine, iodine, and astatine.

magnesium crystallizes in a face-centered cubic unit cell. calculate the radius of the magnesium atom (in pm) if the density of a cubic unit cell of magnesium is 1.74 g/cm3.

Answers

In this magnesium crystallizes in a face-centered cubic unit cell, don't need density.

What is pure crystals ?

Having no grain boundaries and being continuous and unbroken to the sample's borders defines a material as a single crystal.

What is atom ?

An atom is a unit of matter that specifically identifies a chemical element. An atom is made up of a core nucleus that is encircled by one or more negatively charged electrons. The positively charged nucleus has one or more protons and neutrons, which are relatively heavy particles.

Density = z X molar mass/ no. X a³ (a= edge length)

but no need of this principle here

for FCC, 4r =\(\sqrt{2}\)a

r= radius of atom a= edge length

r= \(\sqrt{2}\)a/4

=\(\sqrt{2}\) * 4.880 *10²/4

r= 169.7pm

or

r=1.697*10²pm

here no need of density

Therefore, in this magnesium crystallizes in a face-centered cubic unit cell, don't need density.

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match the ion channel action with its resulting change in membrane potential.

Answers

When a negative ion enters the cell through an ion channel, it causes hyperpolarization, resulting in a more negative membrane potential. This makes it more difficult for the membrane potential to reach the threshold for an action potential.

Determine what are the change in membrane potential?

When a negative ion enters the cell through an ion channel, it causes hyperpolarization of the membrane potential. Hyperpolarization is a change in the membrane potential where the inside of the cell becomes more negative than the resting membrane potential.

This occurs because the entry of negative ions, such as chloride (Cl⁻), increases the negative charge inside the cell, making it more difficult for the membrane potential to reach the threshold for an action potential.

On the other hand, the exit of a positive ion, such as sodium (Na⁺), results in depolarization. Depolarization is a change in the membrane potential where the inside of the cell becomes less negative or even positive compared to the resting membrane potential.

This occurs because the exit of positive ions reduces the positive charge inside the cell, making it easier for the membrane potential to reach the threshold for an action potential.

Therefore, the correct matching is the entry of a negative ion, which leads to hyperpolarization of the membrane potential.

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Which ion channel action is correctly matched with its resulting change in membrane potential? exit of a positive ion: depolarization exit of a negative ion; hyperpolarization entry of a positive ion, hyperpolarization entry of a negative ion; hyperpolarization activation of sodium-potassium transporters; depolarization

HELPPPPP MEEEEEE WILL OFFER BRAINLIEST

1. Which graph represents the endothermic reaction?

2. Which graph represents the exothermic reaction?

HELPPPPP MEEEEEE WILL OFFER BRAINLIEST 1. Which graph represents the endothermic reaction?2. Which graph

Answers

Answer:

A is endothermic, B is exothermic.

Explanation:

I actually just looked at the bottom of the graph. Endothermic reactions absorb energy, but exothermic reactions release it. Hope this helped!

Compact globular portions of a folded polypeptide chain are called________
a. secondary structures b. epitopes c. domains d. subunits
e. chains

Answers

Compact globular portions of a folded polypeptide chain are called "domains". Domains are regions of a protein that are compact, stable, and can often fold independently of the rest of the protein.

They typically consist of 50-350 amino acids and have a specific structure and function. Domains are important because they allow proteins to perform multiple functions and interact with other molecules, and can also be used as a structural unit for protein engineering and design. Some proteins contain multiple domains, which can perform different functions or be regulated independently. The study of protein domains and their interactions is an important area of research in biochemistry and molecular biology, as it provides insight into the structure and function of proteins and can lead to the development of new therapeutics and biotechnologies.

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PLEASE HELP: Explain why most substances are carbon compounds?

Answers

Answer:

The reason is carbon's ability to form stable bonds with many elements, including itself. 

Explanation:

This property allows carbon to form a huge variety of very large and complex molecules. In fact, there are nearly 10 million carbon-based compounds in living things!

Answer:

Explanation:

The reason is that carbon is able to form stable bonds with many elements, including itself, which allows carbon to form a huge variety of very large and complex molecules.

Hi!, please help :)

Hi!, please help :)

Answers

Answer:

5.8

Explanation:

What is the volume occupied by 0.17 grams of gaseous H2S at 27◦C and 380 torr?

Answers

Answer:

0.25 liter

Explanation:

Trust

B- Explain the difference between conventional and
auto-transformers

Answers

Conventional transformers have two separate windings that provide electrical isolation between the primary and secondary circuits. They are primarily used for voltage transformation. Auto-transformers, on the other hand, have a single winding and provide voltage transformation as well, but with reduced electrical isolation. They are typically smaller, less expensive, and more efficient than conventional transformers but may not be suitable in applications where complete electrical isolation is required.

Conventional transformers and auto-transformers are both types of electrical transformers, but they differ in their construction and functioning. Here's a step-by-step explanation of the differences between these two types:

Conventional Transformers:

Construction: A conventional transformer consists of two separate windings, the primary winding, and the secondary winding, which are electrically isolated from each other.

Induced Voltage: When an alternating current (AC) is applied to the primary winding, it creates a changing magnetic field that induces a voltage in the secondary winding. The voltage ratio between the primary and secondary windings is determined by the ratio of the number of turns in each winding.

Voltage Isolation: Conventional transformers provide electrical isolation between the primary and secondary windings since they have separate coils. This isolation ensures that there is no direct electrical connection between the primary and secondary circuits.

Voltage and Current Transformation: Conventional transformers are primarily used for voltage transformation. By varying the number of turns in the primary and secondary windings, the transformer can step up or step down the voltage level while keeping the power (product of voltage and current) constant.

Auto-Transformers:

Construction: An auto-transformer has a single winding that acts as both the primary and secondary winding. It consists of a common winding with a tap point along its length.

Induced Voltage: When an AC voltage is applied to the winding, a portion of the voltage is directly transferred from the input side to the output side via the shared winding.

Voltage Transformation: Auto-transformers are primarily used for voltage transformation as well. By changing the tap point along the winding, the voltage ratio between the input and output can be adjusted. However, the voltage difference between the input and output is not fully isolated.

Size and Cost: Auto-transformers tend to be smaller and less expensive than conventional transformers because they have a single winding, resulting in lower copper and insulation requirements. However, this comes at the cost of reduced electrical isolation.

Efficiency: Auto-transformers are generally more efficient than conventional transformers because they have fewer winding turns, resulting in lower copper losses. However, they may have higher core losses due to the shared magnetic path.

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it is the minimum amount of solute that can be dissolved in the solvent
A. Salt Solution C. Saturated Solution
B. Sugar Solution D. ​

Answers

Answer:A

Explanation:

Answer can be option C

Can someone Help please List the methods you think is used to treat water for contaminants before it gets to your
faucet.

Answers

The distillation system is a method also dioxide and ozone.

A sphere of radius 0.457 m, temperature 32.2 ∘
C, and emissivity 0.924 is located in an environment of temperature 82.9 ∘
C. At what rate does the sphere (a) emit and (b) absorb thermal radiation? (c) What is the sphere's net rate of energy exchange? (a) Number (b) Number Units Units

Answers

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

What are the rates of thermal radiation emission, absorption, and net energy exchange for the sphere?

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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when 100 ml of 0.16 m naf is added to 100 ml of 0.16 m hf, relative to the ph of the 0.10 m hf solution the ph of the resulting solution will

Answers

As 100 ml of 0.16 m naf and 100 ml of 0.16 m hf are combined, the resulting solution's pH rises when compared to the 0.10 m hf solution.

What does pH stand for?

a metric for determining how basic or acidic a thing or solution is. The pH scale ranges from 0 to 14. A pH value of 7 is considered neutral on this scale, meaning it is neither acid nor basic. It's more acidic if the pH value is below 7, and more basic if the pH value is above 7.

What is a typical pH value?

The pH scale goes from 0 (very acidic) to 14 (neutral) (strongly basic or alkaline). The neutral range on this scale has a pH of 7.0. Blood typically has a pH range of 7.35 to 7.45, making it mildly basic.

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the causes of air pollution (human activities and natural reasons)

Answers

Answer:

These are largely the result of human reliance on fossil fuels and heavy industry, but can also be due to the accumulation of waste, modern agriculture, and other man-made processes. The combustion of fossil fuels like coal, petroleum and other factory combustibles is a major cause of air pollution

Molarity of Kool Aid solutions can be calculated by comparing the concentrations of Kool Aid powder and sugar added to a given volume of water. The molar mass of Kool Aid will be the same as that of sugar for our purpose. The molecular formula for sugar is C12H22O11- Your objective for this lab will be to calculate the molarity of Kool Aid desired based on package directions. You will then be provided two concentrated Kool Aid solutions. You will use dilution calculations to determine the amount of water and concentrated solution you will need in order to prepare 65 mL of the desired molarity.

Calculate the molarity of Kool Aid desired based on the following information from the package directions.

1 package Kool Aid powder = 4. 25 grams 1 cup sugar = 192. 00 grams
2. 00 quarts of water (1. 06 quarts = 1 liter) ​

Answers

The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Which describes an atom that has fewer neutrons than protons and more electrons than protons?

0negative compound
0positive compound
0positive ion
0negative ion

Answers

Answer:

Option d is correct = Negative ion

Explanation:

We know that an atom consist of electrons, protons and neutrons. Neutrons and protons are present inside the nucleus while electrons are present out side the nucleus. Electron has a negative charge and is written as e⁻. The mass of electron is 9.10938356×10⁻³¹ Kg . While mass of proton and neutron is 1.672623×10⁻²⁷Kg  and 1.674929×10⁻²⁷ Kg  respectively.

Symbol of proton= P⁺  

Symbol of neutron= n⁰  

The number of electron or number of protons are called atomic number while mass number of an atom is sum of protons and neutrons. The  umber of protons and electrons are always equal to make the atom electrically neutral and when an atom loses its valance electron the number of protons increases and thus positive charge increased and atom form cation.

When an atom gain electron negative charge increase because of more number of electron thus atom form negative ion or anion. For example,

Anion formation:

X + e⁻ → X⁻

Cation formation:

X → X⁺ + e⁻

Thus option d is correct option.

which of the following is a weak acid?
A) H2SO4 (Sulfuric acid)
B) HCl (Hydrochloric acid)
C) CH3COOH (Acetic acid)
D) HNO3 (Nitric acid)
correct answer is C).

Answers

CH3COOH is the correct awnser

A sample of CO2 occupies a volume of 14.01 liters at 147.4 kPa. What pressure in kPa would the gas exert if the volume was decreased to 1.67 L.

Answers

As a result, the pressure exerted by the CO₂ gas if the volume was reduced to 1.67 L is 1233.15 kPa.

What is pressure?

The force per unit area exerted on a surface is known as pressure. It is a physical number that defines how much force is distributed across a specific region. Pressure is usually measured in units of pascals (Pa) in the International System of Units (SI), or pounds per square inch (psi) in the English system. Pressure can be caused by a variety of factors, such as the weight of a fluid or gas, or the impact of particles or objects on a surface. Pressure is important in many areas of science and engineering, including fluid mechanics, thermodynamics, and materials science.

Here,

This problem involves the application of Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume, when temperature is held constant. Mathematically, this can be expressed as:

P₁V₁ = P₂V₂

P₁ and V₁ represent the beginning pressure and volume, and P₂ and V₂ represent the end pressure and volume.

We can use this equation to solve for the final pressure of the CO₂ gas. We are given:

P₁ = 147.4 kPa

V₁ = 14.01 L

V₂ = 1.67 L

Substituting these values into the equation, we get:

P₁V₁ = P₂V₂

(147.4 kPa) (14.01 L) = P2 (1.67 L)

P₂= (147.4 kPa) (14.01 L) / (1.67 L)

P₂= 1233.15 kPa

Therefore, the pressure that the CO₂ gas would exert if the volume was decreased to 1.67 L is 1233.15 kPa.

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As a result, the pressure exerted by the CO₂ gas if the volume was reduced to 1.67 L is 1233.15 kPa.

What is pressure?

The force per unit area exerted on a surface is known as pressure. It is a physical number that defines how much force is distributed across a specific region. Pressure is usually measured in units of pascals (Pa) in the International System of Units (SI), or pounds per square inch (psi) in the English system. Pressure can be caused by a variety of factors, such as the weight of a fluid or gas, or the impact of particles or objects on a surface. Pressure is important in many areas of science and engineering, including fluid mechanics, thermodynamics, and materials science.

Here,

This problem involves the application of Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume, when temperature is held constant. Mathematically, this can be expressed as:

P₁V₁ = P₂V₂

P₁ and V₁ represent the beginning pressure and volume, and P₂ and V₂ represent the end pressure and volume.

We can use this equation to solve for the final pressure of the CO₂ gas. We are given:

P₁ = 147.4 kPa

V₁ = 14.01 L

V₂ = 1.67 L

Substituting these values into the equation, we get:

P₁V₁ = P₂V₂

(147.4 kPa) (14.01 L) = P2 (1.67 L)

P₂= (147.4 kPa) (14.01 L) / (1.67 L)

P₂= 1233.15 kPa

Therefore, the pressure that the CO₂ gas would exert if the volume was decreased to 1.67 L is 1233.15 kPa.

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What volume is occupied by 0.580 mol of gas at 98.4 kPa and 11°C?

please help with steps

Answers

The ideal gas law equation can be used to solve this sum. Thus, a 0.580 mol of gas at 98.4 kPa and 11°C occupies a volume of 12.6 L.

What is the ideal gas law?

The ideal gas law is a rudimentary equation in physics and chemistry that reports the behaviour of ideal gases under different states. The law is expressed mathematically as:

PV = nRT

R is the universal gas constant.

First, we need to convert the given temperature of 11°C to Kelvin:

T = 11°C + 273.15 = 284.15 K

Next, we can plug in the given values and solve for V:

V = nRT/P

V = (0.580 mol)(8.31 J/(mol K))(284.15 K)/(98.4 kPa)

V = 12.6 L

Therefore, 0.580 mol of gas at 98.4 kPa and 11°C occupies a volume of 12.6 L.

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pls help me on this I have 5 minutes left to submit

pls help me on this I have 5 minutes left to submit
pls help me on this I have 5 minutes left to submit
pls help me on this I have 5 minutes left to submit

Answers

#1

Heterogenous mixture mean unsimilar substances .

Chicken noodle soyp.salt waterpropane.

#2

An element is a substance made of only one type of atoms

Example-Al,S

Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?.

Answers

Molecules undergo London dispersion forces:

\(C_{4}H_{10}\) is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.

What are London dispersion forces?

A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;

Reason for incorrect options:

b: the compound is ionic because Na is a metal and the other part is covalent,

c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and

d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).

NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?

A. \(C_{4}H_{10}\)

B. \(NaC_{2}H_{3}O_{2}\)

C. \(CH_{2}C_{12}\)

D. \(C_{2}H_{5}OH HF\)

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How many moles of silver are equivalent to 2.408 x 10^24 atoms

Answers

i found this i hope this helps you
How many moles of silver are equivalent to 2.408 x 10^24 atoms

The mole is used to measure small particles like atoms and molecules.  The 4 moles of silver is equivalent to \(\bold{2.408 x 10^2^4 }\) atoms.

Given here,

The number of atoms

\(\bold{2.408 x 10^2^4 }\)

Number of moles = ?

1 mol of substance = \(\bold{ 6.02 x10^2^3}\)

Hence,

moles of silver,

\(\bold {= \dfrac {2.408 x 10^2^4 } { 6.02 x10^2^3} }}\\\\\bold {= 4 mol}\)

Therefore, the 4 moles of silver is equivalent to \(\bold{2.408 x 10^2^4 }\) atoms.

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Step 1. Show that for the Logistic Activation function for the neurons as below: φ(v)=
1+exp(−v)
1

Then the derivative is as following: φ

(t)=φ(t)(1−φ(t)) Step 2. Using the model of a single neuron, calculate the input of the neuron j, net j, as: ∑
i=1
p

(W
ji

X
i

+ Threshold ) where X
i

is the activation of previous layer neuron i W
ji

is the weight of going from node i to node j p is the number of neurons in the previous layer Step 3. Using the error function below, E(
x
)=
2
1


k=1
K

(y
k

(
x
)−t
k

(
x
))
2
Take the partial derivative with respect to the weight as:
∂w
jk


∂E(
x
)

Use chain rule of calculus and simplify it using results of steps 1 and 2 , show that:
∂w
jk


∂E(
x
)

=−y
j

φ(net
j

)(1−φ(net
j

))(t
j

−y
j

)

Answers

Step 1: Deriving the derivative of the logistic activation function.

Step 2: Calculating the input of neuron j (net j).

Step 3: Deriving the expression ∂w_jk / ∂E(x).

Let's go through the steps and derive the expression you mentioned.

Step 1: Deriving the derivative of the logistic activation function

We start with the logistic activation function:

φ(v) = 1 / (1 + exp(-v))

To find its derivative, we differentiate φ(v) with respect to v:

φ'(v) = d/dv [1 / (1 + exp(-v))]

Using the quotient rule, we can differentiate the numerator and denominator separately:

φ'(v) = [0 - (1) * (exp(-v))] / (1 + exp(-v))²

Simplifying, we get:

φ'(v) = exp(-v) / (1 + exp(-v))²

Expanding the denominator:

φ'(v) = exp(-v) / (1 + 2exp(-v) + exp(-2v))

Simplifying further:

φ'(v) = 1 / (1 + exp(-v)) * (exp(-v) / (1 + exp(-v)))

Canceling out the common terms:

φ'(v) = 1 / (1 + exp(-v)) * (1 - 1 / (1 + exp(-v)))

Combining the fractions:

φ'(v) = φ(v) * (1 - φ(v))

Therefore, the derivative of the logistic activation function φ(v) is given by:

φ'(v) = φ(v) * (1 - φ(v))

Step 2: Calculating the input of neuron j (net j)

The input of neuron j (net j) can be calculated as:

net_j = ∑(i=1 to p) (W_ji * X_i + Threshold)

Where:

X_i is the activation of the previous layer neuron i.

W_ji is the weight going from node i to node j.

Threshold is the bias or threshold value.

Step 3: Deriving the expression ∂w_jk / ∂E(x)

To derive the expression, we'll use the chain rule and simplify it using the results from Steps 1 and 2.

Assuming E(x) is the error function, and we are taking the partial derivative with respect to the weight w_jk, the expression is:

∂w_jk / ∂E(x)

Using the chain rule, we have:

∂E(x) / ∂w_jk = ∂E(x) / ∂net_j * ∂net_j / ∂w_jk

Now, let's simplify each term:

∂E(x) / ∂net_j = -2 * (t_j - y_j) (where t_j is the target output and y_j is the actual output of neuron j)

∂net_j / ∂w_jk = X_k (where X_k is the activation of the previous layer neuron k)

Multiplying the two terms together:

∂E(x) / ∂w_jk = -2 * (t_j - y_j) * X_k

Now, we'll substitute φ(net_j) with y_j, using the result from Step 1:

φ(net_j) = y_j

Finally, using the derivative result from Step 1, we have:

∂E(x) / ∂w_jk = -2 * (t_j - y_j) * X_k * φ(net_j) * (1 - φ(net_j))

Substituting y_j with φ(net_j), we get the desired expression:

∂E(x) / ∂w_jk = -y_j * φ(net_j) * (1 - φ(net_j)) * (t_j - y_j)

Therefore, we have shown that:

∂w_jk / ∂E(x) = -y_j * φ(net_j) * (1 - φ(net_j)) * (t_j - y_j)

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Uranium contains two isotopes, U-235 with an atomic mas of 235 g/mol, and u-238 with an atomic mass of 238g/mol. U-235 is needed
as a fuel in nuclear reactors. Until recently, the method used to separate U-235 from U-238 was by gas diffusion. Use U-235 as R1, and
U-238 as R2 and determine the rate of diffusion and which gas will diffuse faster.

⚪︎U-235 diffused 10.01 times faster than U-238
⚪︎U-235 diffused 1.01 times slower than U-238
⚪︎U-235 effused 2.01 times slower than U-238
⚪︎U-235 effused 1.01 times faster than U-238
⚪︎U-235 diffused 1.01 times faster than U-238

Uranium contains two isotopes, U-235 with an atomic mas of 235 g/mol, and u-238 with an atomic mass of

Answers

Answer:

the answer is in the image

Explanation:

Uranium contains two isotopes, U-235 with an atomic mas of 235 g/mol, and u-238 with an atomic mass of

A chemist conducts an experiment in which 2. 00 l of hydrogen gas is collected over water at 1. 00 ATM and 298. 15 K. The phrase over water means that the gas was collected by bubbling it into an inversed bottle filled with water which is sitting in a water bath. However the gas collected is now saturated with water vapor. The partial pressure of water vapor at 298. 15 K is 0. 0 300 ATM. Using Dalton's law calculate the pressure of the hydrogen gas in ATM

Answers

Answer:According to Dalton's law of partial pressures, the total pressure is equal to the sum of the partial pressures of each gas.  In equation form, this looks like this ...

Pt = P1 + P2 + ...

Pt = total pressure

P1 = partial pressure of gas 1

P2 = partial pressure of gas 2

Explanation:

solve for v in the formula d = v + at

Answers

Answer: v=d−at

Explanation: I don't know if this will help

Answer:

\(d = v + at \\ d - at = v \: \: or \: \: v = d - at\)

In metallic bonds, electrons are referred to as electrons.​

Answers

Answer:

Metallic bonding may be described as the sharing of free electrons among a lattice of positively charged metal ions. The structure of metallic bonds is very different from that of covalent and ionic bonds. ... In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.

When 127.68 g of brass at 163 °C are added to 150.00 g H₂O at 22.4 °C, the final
temperature
for brass.
of the brass and water is 32.6 °C. Calculate the value of the specific heat, c,

Answers

For water: q = cmΔT = 4.18 ∙ 150 (32.6 – 22.4) = 6395.4J

For brass: c = q / mΔT = 6395 / 127.68 (163 – 32.6) = 0.384 J / gC

What is water?

The global economy depends heavily on water. Agriculture uses over 70% of the freshwater that people use. 6.5% of the world's protein comes from fishing in salt and fresh water bodies, which has been and still is an important source of food for many regions of the world. Commodities (including oil, natural gas, and manufactured goods) are frequently transported across vast distances by boats over the oceans, rivers, lakes, and canals. In both industry and residences, huge amounts of water, ice, and steam are utilised for cooling and heating. Water is utilised extensively in industrial processes, as well as in cooking and washing, as it is a great solvent for a wide range of compounds, both mineral and organic.

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What did you learn about factors that affect the speed of melting ice? Explain your answer with evidence, such as your data and observations.

Answers

The rate at which ice melts depends on several factors, including temperature, surface area, and the presence of impurities.

Temperature: The most significant factor influencing the rate of ice melting is temperature. When the temperature is above the freezing point of ice (0°C or 32°F), ice starts to melt. The higher the temperature, the faster the ice will melt. For example, in warm weather, ice melts faster than it does in cold weather.

Surface area: The surface area of the ice exposed to the environment also affects the speed of melting. The more surface area exposed, the faster the ice will melt. For example, crushed ice will melt faster than a solid block of ice with the same volume.

Impurities: The presence of impurities, such as dirt or salt, can also affect the speed of melting. When impurities are added to ice, they lower the melting point of the ice, which causes it to melt faster. For example, salt is often used to melt ice on roads and sidewalks during winter.

In summary, the speed of melting ice can be influenced by a variety of factors, including temperature, surface area, and the presence of impurities.
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