Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average density from the attached density profile for a spherical shell (which does not have to be very thin, for example, a shell from the inner core-outer core boundary to the middle depth of the outer core). Do not make the shell contains a large density contrast. Calculate enough points to make the g profile. Note that only the mass at radius less than r contributes to the gravitational acceleration. (15 points)
Answers
Solution :
Acceleration due to gravity of the earth, g \($=\frac{GM}{R^2}$\)
\($g=\frac{G(4/3 \pi R^2 \rho)}{R^2}=G(4/3 \pi R \rho)$\)
Acceleration due to gravity at 1000 km depths is :
\($g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$\)
\($g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-1000) \times 5.5 \times 10^3\right)$\)
\($= 822486 \times 10^{-8}$\)
\($=0.822 \times 10^{-2} \ km/s$\)
= 8.23 m/s
Acceleration due to gravity at 2000 km depths is :
\($g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$\)
\($g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$\)
\($= 673552 \times 10^{-8}$\)
\($=0.673 \times 10^{-2} \ km/s$\)
= 6.73 m/s
Acceleration due to gravity at 3000 km depths is :
\($g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$\)
\($g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$\)
\($= 3371 \times 153.86 \times 10^{-8}$\)
= 5.18 m/s
Acceleration due to gravity at 4000 km depths is :
\($g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$\)
\($g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$\)
\($= 153.84 \times 2371 \times 10^{-8}$\)
\($=0.364 \times 10^{-2} \ km/s$\)
= 3.64 m/s
Related Questions
Which circuit is a series circuit ?
Answers
Answer:
the right answer is d
Explanation:
4800 g to kg? With the work pls
Answers
Answer:
[See Below]
Explanation:
✦ Formula = \(Mass / 1000\)
✧ \(4800 / 1000 = 4.8\)
So \(4800\) grams is equal to \(4.8\) kilograms.
~Hope this helps Mate. If you need anything feel free to message me.
You are walking in Paris alongside the Eiffel Tower and suddenly a croissant smacks you on the
head and knocks you to the ground. From your handy dandy tourist guidebook, you find that the
height of the Eiffel Tower is 300.5 m. If you neglect air resistance, calculate how many seconds
the croissant dropped before it tagged you on the head.
What is the answer
Answers
300.5 = 1/2 x 9.8 x t^2
t = square root ( 61.3 )
t = 7.8 seconds
In golf par is the
A. number of golfers who can play a hole at a time
B. typical number of strokes needed to complete a hole .
C. typical number of golfers who pass the course
D. number of holes in a golf course
Answers
Par is a term used in golf to describe the number of strokes a skilled golfer should be able to complete a particular hole or course in. It is determined based on the length and difficulty of the hole or course. A golfer's score for a particular hole is then compared to the par for that hole to determine whether they scored above par (meaning they took more strokes than the expected number), below par (took fewer strokes), or at par (took the expected number of strokes). The overall score for a round of golf is also compared to the total par for the course to determine a golfer's performance.
Answer:
B. typical number of strokes needed to complete a hole.
A man with weight of 150 lb is holding to a balloon with both hands equally. Determine the tension in each of his hands when: a) the balloon rises with v=0.8t ft/s, and b) the balloon descents with v=0.4t ft/s.
1) a) T=153.8 lb, b) T=148.1 lb
2) a) T=135.0 lb, b) T=45.0 lb
3) a) T=74.1 lb, b) T=76.9 lb
4) a) T=76.9 lb, b) T=74.1 lb
Answers
a) The tension is 76.9 lb when the balloon rises with v=0.8t ft/s and b) The tension is 74.1 lb when the balloon descents with v = 0.4t ft/s.
What is Newton's second law?Newton's second law, states that the net force on an object is equal to its mass times its acceleration.
We can apply Newton's second law to the man and the balloon separately to determine the tension in each of his hands.
a) The net force on the balloon is equal to its mass times its acceleration, which is given by:
F(b) = mg + ma = mg + m(dv/dt)
= mg + m(d/dt(0.8 ft/s)
= (mg + 0.8m)/2
= [150 lb + (150b/32 ft/s²)(0.8 ft/s)]/2
T = 76.86 lb or 76.9 lb
b) When the balloon descends with a velocity of 0.4t ft/s, its acceleration is -0.4 ft/s² (negative because it is descending).
The net force on the man is still equal to the tension in his hands, which we can call T. Therefore:
T = m(m) × g - F(b)
where m(b) is the mass of the balloon, r is its radius, and ρₐ is the density of air,.
T = 150 lb × 32.2 ft/s² - (4/3)πr³ × ρₐ × 0.4 ft/s²
Dividing the tension equally between the man's hands, we get:
T(h) = T/2 = 75 lb × 32.2 ft/s² - (2/3)πr³× ρₐ × 0.4 ft/s²
Substituting the value of r and ρₐ, we get:
T(h) = 74.1 lb
Therefore, the answer is option 4) a) T=76.9 lb, b) T=74.1 lb.
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Please help been struggling with this problem thank you!
Answers
The change in the electrical potential energy is -3.78 × 10⁻¹⁸ J.
What is the change in the electric potential?The electrical potential energy of a point charge in an electric field is given by:
ΔU = qΔV
where;
ΔU is the change in potential energy, q is the charge, and ΔV is the change in electric potential.The electric potential is defined as the electric potential energy per unit charge, so we can also express this as:
ΔU = q(Vf - Vi)
where;
Vf is the final potential and Vi is the initial potential.In this case, we are given the distance moved by an electron in an electric field and the strength of the electric field. We can use the formula for electric potential to find the change in potential energy:
ΔV = Ed
where;
E is the electric field strength and d is the distance moved.Plugging in the given values, we get:
ΔV = (525 N/C)(0.045 m) = 23.625 Nm/C
To find the change in potential energy, we need to know the charge of the electron. The charge of an electron is -1.6 × 10⁻¹⁹ C.
Therefore, we can calculate the change in potential energy as:
ΔU = qΔV = (-1.6 × 10⁻¹⁹ C)(2362.5 Nm/C)
= -3.78 × 10⁻¹⁸ J
Note that the negative sign indicates a decrease in potential energy, which makes sense since the electron is moving in the direction of the electric field.
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The engine of a high speed train, travelling at 50 ms-1, delivers a power of 2 MW. What is the force exerted by the engine?
Answers
Answer:To calculate the force exerted by the engine, we can use the formula:
Power = Force × Velocity
We are given the power (P) as 2 MW and the velocity (v) as 50 m/s. Rearranging the formula, we can solve for the force (F):
Force = Power / Velocity
Plugging in the values, we get:
Force = 2,000,000 W / 50 m/s = 40,000 N
Therefore, the force exerted by the engine is 40,000 Newtons.
E
The force exerted by the engine is 40,000 N.
We can use the formula for power to find the force exerted by the engine:
Power = Force × Velocity
Rearranging this formula gives:
Force = Power / Velocity
Substituting the given values:
Force = 2 MW / 50 ms⁻¹
We need to convert MW to watts (W) and ms^-1 to meters per second (m/s) to solve for force in Newtons (N):
1 MW = 10⁶ W
1 ms⁻¹ = 1 m/s
So, we get:
Force = (2 × 10⁶ W) / (50 m/s)
Force = 40,000 N
Therefore, the force exerted by the engine is 40,000 N.
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Which would be a good analogy of wave motion
Answers
----------------
Answer:
i believe it would be C
Explanation:
A chemist must dilute 55.6 ml of 1.48 M aqueous silver nitrate (AgNO3)solution until the concentration falls to 1.00 M. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to 3 significant digits.
Answers
Answer:
82.2 mL
Explanation:
The process of adding water to a solution to make it more dilute is known as dilution. The formula for dilution is;
C1V1=C2V2
Where;
C1= concentration of stock solution
V1= volume of stock solution
C2= concentration of dilute solution
V2= volume of dilute solution
V2= C1V1/C2
V2= 1.48 × 55.6/ 1.0
V2= 82.2 mL
A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better
Answers
Answer and Explanation:
A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.
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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.
Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body
In order to get going fast, eagles will use a technique called stooping, in which they dive nearly straight down and tuck in their wings to reduce their surface area. While stooping, a 6- kg golden eagle can reach speeds of up to 53 m/s . While golden eagles are not very vocal, they sometimes make a weak, high-pitched sound. Suppose that while traveling at maximum speed, a golden eagle heads directly towards a pigeon while emitting a sound at 1.1 kHz. The emitted sound has a sound intensity level of 30 dB when heard at a distance of 5 m .A) Model this stooping golden eagle as an object moving at terminal velocity. The eagle’s drag coefficient is 0.5 and the density of air is 1.2 kg/m 3 . What is the effective cross-sectional area of the eagle’s body while stooping?B) What is the doppler-shifted frequency that the pigeon will hear coming from the eagle?C) Consider the moment when the pigeon is 5 m away from the eagle. At the pigeon’s position, what is the intensity (in W/m^2 ) of the sound the eagle makes?D) The golden eagle slams into the 250- g pigeon, which is initially moving at 10 m/s in the opposite direction (toward the eagle). The eagle grabs the pigeon in its talons, and they move off together in a perfectly inelastic collision. How fast do they move after the collision?
Answers
Answer:
Check the explanation
Explanation:
Part A
F = CA
this drag force balances the weight = 6X 9.8
so
6X9.8 = 0.5 X A X0.5 X 1.2 X 532
A= 0.069 m2
Part B
here the sorce is moving and the observer is at rest
so f= f(- 1 - 1
f = 1.1X10 343 343 – 53
f' = 1.3 KHz
Part C:
given the intensity = 30 dB
we know that I dB = 10 log (I(W/m2))
so we get I (W/m2) = 1000
Part D : The catch
Given that U1 = 53 M1 = 6 kg
U2 =-10 M2=0.25
V1=V2
now conserving momentum
6 X 53 -0.25 X10 =(6+0.25)V
V= 50.48 m/sec
A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy
Answers
Answer:
\(9\:\mathrm{J}\)
Explanation:
Kinetic energy is given by the following equation:
\(KE=\frac{1}{2}mv^2\), where \(m\) is mass in \(\mathrm{kg}\) and \(v\) is velocity in \(\mathrm{m/s}\).
Since the cell phone's mass is given in grams, we need to convert this into kilograms:
\(80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}\).
Therefore, the kinetic energy of the cell phone is:
\(KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}\).
Two small, identical conducting spheres A and B are a distance R apart; each carries the same charge Q. What is the magnitude of the force sphere B exerts on sphere A? What is the direction of the force sphere B exerts on sphere A? An identical sphere with zero charge, sphere C, makes contact with sphere B and is then moved very far away. What is the magnitude of the net force now acting on sphere A? Express your answer in terms of the variables Q, R, and appropriate constants. Sphere C is brought back and now makes contact with sphere A and is then moved far away. What is the magnitude of the force on sphere A in this third case? Express your answer in terms of the variables Q, R, and appropriate constants
Answers
The force exerted in case 1 is F = k Q² / R², in case 2 is F = k Q² / 2 R² and in case 3 is F = 3 k Q² / 8 R². The direction of force exerted by sphere B on sphere A is towards left, if A is on left side of B.
According to Coulomb's law,
F = k \(q_{1}\) \(q_{2}\) / R²
F = Force
k = Coulomb's constant
R = Distance between two forces
\(q_{1}\), \(q_{2}\) = Charge on two forces
Distance between the identical conducting spheres A and B = R
Charge of the identical conducting spheres A and B = Q
1 ) The force exerted by sphere B on sphere A is
F = k \(q_{1}\) \(q_{2}\) / R²
F = k Q² / R²
2 ) Since the spheres have same charge, the force will be repulsive. So, the direction of force exerted by sphere B on sphere A will be towards left, if A is placed on the left side of B.
3 ) Since sphere C is identical to the other two spheres, the charges will be shared until they acquire same potential.
After sphere C makes contact with sphere B,
Charge on sphere B = Q / 2
Charge on Sphere C = Q / 2
Since sphere C is moved far away from the other two sphere, there will be no force acting on A and B due to C. So net force will be,
F = k \(q_{1}\) \(q_{2}\) / R²
F = k Q Q / 2 R²
F = k Q² / 2 R²
4 ) After sphere C makes contact with sphere A,
Charge on sphere A = 3 Q / 4
Charge on Sphere C = 3 Q / 4
Charge on sphere B = Q / 2
Since sphere C is moved far away from the other two sphere, there will be no force acting on A and B due to C. So the force on sphere A is,
F = k \(q_{1}\) \(q_{2}\) / R²
F = 3 k Q Q / 4 * 2 * R²
F = 3 k Q² / 8 R²
Therefore,
F = k Q² / R²The direction of force exerted by sphere B on sphere A is towards left, if A is on left side of B.F = k Q² / 2 R²F = 3 k Q² / 8 R²To know more about Coulomb's law
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1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance，what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
Answers
A 5.00 kg wagon is being pulled along at 2.50 m/s. A 2.50 kg box is dropped in the wagon, which continues at the same speed. What was the change in momentum?
Answers
Answer:
Why are you talking help in french wow u bad
Explanation:
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
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Why are you talking help in french wow u bad
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Why are you talking help in french wow u bad
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Why are you talking help in french wow u bad
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Why are you talking help in french wow u bad
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Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
Why are you talking help in french wow u bad
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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what is the velocity of a 1.3 kg puppy with a forward momentum of 6 kg m/s
Answers
Answer:
by using p = mv equation we can find v,
6 = 1.3 v
4.615 = v
A boat sails for 24 km pointed in the direction [40° S of WI. A constant current moves the boat 8 km [30° W of N]. If the trip takes 3 hours, find the boats resultant velocity
Please brainliest, really need it!!!
Answers
The resultant velocity of the boat is 7.5 km/h.
What is the resultant displacement of the boat?The resultant displacement of the boat is calculated as follows;
Sum of the vertical displacement of the boat is calculated as;
∑Fy = -24 km sin(50) + 8 km sin(60)
∑Fy = -11.5 km
Sum of the horizontal displacement of the boat is calculated as;
∑Fx = -24 km cos(50) - 8 km cos(60)
∑Fx = -19.4 km
The resultant displacement is calculated as follows;
d = √ (-11.5² + 19.4²)
d = 22.55 km
The resultant velocity of the boat is calculated as follows;
v = ( 22.55 km ) / ( 3 hrs )
v = 7.5 km/h
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5.) A bulb is plugged into a 120 Volt outlet. The resistance of the bulbs is 330 ohms.
a. Calculate the current through the bulb.
b. Calculate the watts and kw.
c. Calculate the cost to run the bulb for 10 hours at 8 cents/ kWhr.
Answers
Answer:
a. The current through the bulb can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance:
I = V/R = 120 V / 330 ohms = 0.36 A
Therefore, the current through the bulb is 0.36 A.
b. The power of the bulb can be calculated using the formula P = VI, where P is power, V is voltage, and I is current:
P = VI = (120 V) x (0.36 A) = 43.2 W
Therefore, the power of the bulb is 43.2 watts or 0.0432 kW.
c. To calculate the cost to run the bulb for 10 hours at 8 cents/ kWhr, we need to first calculate the energy consumption in kilowatt-hours (kWh):
Energy consumption = power x time
Energy consumption = 43.2 W x 10 hours = 432 Wh = 0.432 kWh
The cost can now be calculated by multiplying the energy consumption by the cost per kWh:
Cost = energy consumption x cost per kWh
Cost = 0.432 kWh x $0.08/kWh
Cost = $0.03456
Therefore, the cost to run the bulb for 10 hours at 8 cents/ kWhr is $0.03456.
Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
Answers
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?
Answers
Answer:
The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:
16:42
λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.
Explanation:
A boat accelerates uniformly from rest to a speed of 10 m/s over a distance of 50 m. (a) Determine the acceleration of the bike. (b) how long will take to do that? ТУЛ in this 34 A boat accelerates uniformly from rest to a speed of 10 m / s over a distance of 50 m . ( a ) Determine the acceleration of the bike . ( b ) how long will take to do that ?
Answers
Answer:
See below
Explanation:
Average speed = (0+ 10)/2 = 5 m/s
then to cover 50 m will take 50 m / 5 m/s = 10 seconds
change in velocity/ change in time = acceleration = 10/10 = 1 m/s^2
Electric charge that is stationary is
Answers
Answer:
is only producing an electric field in the surrounding space
Explanation:
Compare the table of information with the bar graph shown. What makes verifying that the bar graph has the same information as the table especially challenging? own answer
Answer:The table uses metric tons as its numerical scale unit, whereas the bar graph uses pounds. This use of differing units means the reader must convert units of measurement before verifying that the information in the table matches the information in the bar graph.
Answers
When displaying sections of data, bar charts is used. As long as the number of categories to compare, vertical bar charts can be useful for comparing several category discrete data, like ages, classes, schools.
Why are graphs more illuminating than tables?Charts and graphs are useful visual aids because they make information accessible and quick to understand. So, it is not unexpected that both print and digital media frequently use graphs. When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.
What do the tables, graphs, and data represent?Visual representations of data, such as tables and graphs, are used to arrange information and reveal patterns and correlations. To present the results of their research, scientists and researchers frequently employ tables and graphs.
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A heating coil operates on 220 V if it draws 15.0 A. Find it's resistance
Answers
Answer:
R ≈ 15 ohms
Explanation:
Using ohm's law equation,
I = V/R, to solve for the resistance of the heating coil.
R = V/I
Known:
V = 220 v = 220 kgm^2s^-3A^-1
I = 15 A
Unknown:
R =?
Solution:
R = (220 kgm^2s^-3A^-1)/ 15.0 A
R = 14.6 kgm^2s^-3A^-2
R ≈ 15 kgm^2s^-3A^-2
R ≈ 15 ohms
I’m in a test and I’m sort of being timed here’s a photo of question
Answers
Answer: D.
Explanation:
Answer:
i think the answer is b
Explanation:
playing sports often require both
what is nuclear force
Answers
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answers
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
Captain John Stapp pioneered research into the physiological effects of large accelerations on humans. During one such test his sled slowed from 282 m/s
with an acceleration of -201 m/s2. How long did it take him to stop?
Answers
This question involves the concepts of the equations of motion.
It took him "1.4 s" to stop.
EQUATIONS OF MOTIONIn this scenario, we will use the first equation of motion to find out the time taken by the sled to stop.
\(v_f=v_i+at\)
where,
\(v_f\) = final velocity of the sled = 0 m/s
\(v_i\) = initial velocity of the sled = 282 m/s
a = decceleration = - 201 m/s²
t = time taken = ?
Therefore,
\(0\ m/s=282\ m/s + (-201 m/s^2)t\\\\t=\frac{282\ m/s}{201\ m/s^2}\)
t = 1.4 s
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A plane has a speed of 275 km/hr. The wind is at a 70 degree angle to the direction of the plane with a speed of 75 km/hr. What is the combined speed?
Answers
The combined speed of the plane and the wind is 249.35 km/h.
Relative speed
The relative speed of the plane due to speed of the wind is calculated as follows;
Let the direction of the plane be horizontal direction.
Speed of the windThe speed of the wind is calculated as follows;
\(V_b = V \times cos\theta\\\\V_b = 75 \times cos(70)\\\\V_b = 25.65 \ km/hr\)
Combined speedThe combined speed of the plane and the wind is calculated as follows;
V = 275 km/h - 25.65 km/h
V = 249.35 km/h
Thus, the combined speed of the plane and the wind is 249.35 km/h.
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