Assume that a 19 cm length of wire is carrying a current perpendicular to a 4. 1 T magnetic field and experiences a force of 7. 6 mN. What is the current in the wire?

A) 3. 4x10^-7 A

B) 9. 8x10^3 A

C) 1. 0x10^-2 A

D) 9. 8 A

when you’re trying to ollie higher, your front foot will be slightly farther back than it normally is. this lets you drag more on the board, helping you get the height you need. hope this helped :)

Answer: I had the same problem if I was you I would use my phone and record a slowdown of your ollie. Also pop hard and focus on how much  you jump, your ollie is only going to go as high as you jump so try to get some Hight also do moving first it helps in the long run trust if you dont its just as hard as learning how to ollie in the first place.

Explanation: keep riding I hope the best

The magnitude of the average acceleration of the ball during its contact with the wall is  68000 m/s².

When the ball collides with the wall, it experiences a change in momentum. The time interval during which the ball is in contact with the wall is 3.95 ms, or 0.00395 s. Using the principle of conservation of momentum,

We  use the average acceleration formula to find the acceleration of the ball during the collision.Initial momentum of the ball before collision = m₁v₁ = (0.0515 kg)(27.0 m/s) = 1.3905 kg⋅m/s. Final momentum of the ball after collision = m₂v₂ = (0.0515 kg)(-19.0 m/s) = -0.9785 kg⋅m/s

According to the conservation of momentum, the initial momentum is equal to the final momentum, so:m₁v₁ = m₂v₂

1.3905 kg⋅m/s = -0.9785 kg⋅m/s  Solving for the mass, we get: = 0.0515 kg

Using the average acceleration formula: a = Δv/Δt = (v₂ - v₁)/Δt = (-19.0 m/s - 27.0 m/s)/0.00395 s = -16455.7 m/s² Since the acceleration is in the opposite direction to the initial velocity, we take the magnitude to be: |a| = 16455.7 m/s² ≈ 68000 m/s².

To know more about acceleration , refer here:

https://brainly.com/question/31479424#

#SPJ11

Answer:

A) 3.39 seconds

Explanation:

We can find the time it takes the arrow to hit the ground by using a constant acceleration equation.

Let's make the positive direction upwards and the negative direction downwards. Let's list out the relevant variables:

Find a constant acceleration equation that contains these four variables.

Substitute known values into the formula and solve for t.

Use the quadratic formula to continue solving for t.

From this, when we add the discriminant we get -12.04664168. When we subtract the discriminant we get 3.38819129.  

Since time cannot be negative, the time it takes for the arrow to hit the ground must be 3.39 seconds.

Answer:V^2=U^2+2gSIN45S

60^2=2asin45x200

3600=400sin45(a)

3600=282•84a

a=3600/282•84

a=12m/s^2

S=ut+0•5gt^2

200=0•5(12)t^2

200=6t^2

t^2=200/6

t^2=33.33

t=5.77s

Explanation:

The mechanical equilibrium condition allows to find the value of the normal for the body is:

Newton's second law establishes a relationship between the force, the mass and the acceleration of bodies, in the special case that the acceleration is zero, it is called a mechanical equilibrium condition.

       ∑ F = 0

A free body diagram is a diagram of the forces without the details of the bodies, in the attachment we can see this diagram, let's write the equilibrium condition for each axis.

x- axis

          Fₓ -fr = 0

y-axis

          F_y + N – W =0

Let's use trigonometry to find the components of the applied force.

            Cos 30= \(\frac{F_x}{F} \)

            sin 30 = \(\frac{F_y}{F } \)

            Fₓ = F cos 30

            \(F_y\) = F sin 30

The weight of a body is the mass times the acceleration due to gravity.

           W = m g

Let's substitute.

           F sin 30 + N – m g = 0

           N= m g – F sin 30

Let's calculate.

           N = m 9.8 – 150 sin  30

           N = m 9.8 - 75

To finish the calculation, the mass of the body must be known, suppose a value of 10 kg.

          N=10 9.8 -75

          N = 23N

In conclusion using the mechanical equilibrium condition we can find the value of the normal for the body is:

Learn more about the mechanical equilibrium condition here: brainly.com/question/12804448

The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.

For such more question on perpendicular

https://brainly.com/question/1202004

#SPJ8

Answer:

Average speed = 60km/hr

Explanation:

Given the following data;

Time = 2.5 hrs

Distance = 150km

To find the average speed;

Average speed = distance/time

Substituting into the equation, we have

Average speed = 150/2.5

Average speed = 60km/hr

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s .The amplitude of the subsequent oscillations 48.13 cm/s

a 1.25 kilogram block is fastened to a spring with a 17.0 newtons per meter spring constant. Given that K is equal to 14 Newtons per meter and mass equals 10.5 kg. The block is then struck with a hammer by a student while it is at rest, giving it a speedo of 46.0 cm for a brief period of time. The required energy provided by the hammer, which is half mv squared, is transformed into potential energy as a result of the succeeding oscillations. This is because we know that energy is still available for consultation. So access the amplitude here from here. He will therefore be equal to and by. Consequently, the Newton's spring constant is 14 and the value is 10.5. The velocity multiplied by 0.49

Speed at X equals 0.35 into amplitude, or vice versa. At this point, the spirit will equal half of K X 1 squared plus half. Due to the fact that this is the overall energy, square is equivalent to half of a K square or an angry square. amplitude is 13 and half case 14 x one is 0.35. calculate that is equal to initial velocities of 49 squares and masses of 10.5. This will be divided in half and start at about 10.5 into the 49-square-minus-14. 13.42 into the entire square in 20.35. dividing by 10.5 and taking the square as a result. 231 6.9 Six centimeters per square second. 10.5 into 49 sq. 14. 2 into a 13.42 square entire. then subtract 10.5 from the result to get the square. So that is 48.13cm/s.

To learn more about oscillations Please click on the given link:

https://brainly.com/question/26146375

#SPJ4

This is incomplete question Complete Question is:

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?

Good conductors and bad conductors, also known as insulators, have different properties that make them suitable for various practical applications.

A conductor is a material that allows the flow of electric current, while an insulator (or bad conductor) is a material that resists the flow of electric current.

Good conductors are materials that allow the flow of electric current with low resistance. They are characterized by having a high density of free electrons that can move through the material easily when a voltage is applied. Metals, especially copper, silver, and gold, are good conductors of electricity because they have a large number of free electrons in their outermost atomic shells. Other materials such as aluminum, iron, and graphite are also good conductors, although they may not be as efficient as metals.

Good conductors have a wide range of practical applications in various industries, including electrical wiring, electronics, and energy generation. They are used in everything from electrical cables to electronic devices like smartphones and computers, where their low resistance allows for efficient energy transfer and signal transmission.

To learn more about Good Conductor visit here:

brainly.com/question/12370218

#SPJ4

Answer:

Conflict resolution is the process by which two or more parties reach a peaceful resolution to a dispute. In the workplace, there can be a variety of types of conflict: Conflict may occur between co-workers, or between supervisors and subordinates, or between service providers and their clients or customers.

The term conflict resolution implies the process of seeking effective and plausible settlement in conflict situations between aggrieved parties.

The term conflict in itself refers to a disagreement between two or more parties. Conflicts are common in human parlance. An example is the current conflict between Russia and Ukraine in recent times.

The term conflict resolution implies the process of seeking effective and plausible settlement in conflict situations between aggrieved parties.

Learn more about conflict resolution: https://brainly.com/question/21923826

Answer:

Option C

Explanation:

The answer is option C or "they convert chemical energy from gasoline into kinetic energy." Electric motors usually require a power source for example a car, you put gasoline in that car which is converted into kinetic energy which allows the motor to operate and run, (enabling you to drive the car) the kinetic energy is then used into you run out of gasoline.

Hope this helps.

When your muscles contract to move your body, such as during walking, work is done, and work requires energy. Based on the Law of Conservation of Energy, this energy comes from c) "Mechanical energy stored in ATP."

Energy is a fundamental concept in physics that describes the ability to do work. When your muscles contract to move your body, work is done, and this work requires energy.

The statement, "When your muscles contract to move your body, such as during walking, work is done, and work requires energy," is absolutely true. However, the question is where this energy comes from. The Law of Conservation of Energy states that energy cannot be created or destroyed; it can only be converted from one form to another.

So, from where does this energy come? Option A, "New energy is created by our cells whenever we need it," is incorrect because it violates the Law of Conservation of Energy. Energy cannot be created out of nothing. Option B, "Heat," is also incorrect because the energy generated by muscle contractions is not heat energy.

The correct answer is C, "Mechanical energy stored in ATP." ATP (adenosine triphosphate) is a molecule that stores energy in the cells of our bodies. When our muscles contract, ATP is broken down to release the stored energy, which is used to power the muscle contractions. This stored mechanical energy is converted into kinetic energy, which is the energy of motion that is used to move our bodies.

Option D, "Chemical energy," is not a complete answer because it does not specify where the chemical energy is stored. In this case, the chemical energy is stored in ATP molecules.

In conclusion, the energy that is required for muscle contractions during movement comes from the mechanical energy stored in ATP molecules in our cells. The Law of Conservation of Energy is fundamental to understanding where energy comes from and how it is used in our bodies and in the world around us.

To know more about energy click here:

https://brainly.com/question/16182853

#SPJ11

Signals generated by transducers are normally of the order of microvolts to millivolts.

What are transducers?

Transducers are electrical components that transform energy from one form into another. They are electrical sensors that generate an electrical signal based on the quantity being assessed.

A transducer is a device that transforms a physical quantity such as force, pressure, or temperature into an electrical signal. This electrical signal can then be amplified, filtered, or measured in other ways.

Some common examples of transducers include microphones, strain gauges, accelerometers, and thermocouples.

What are the signals generated by transducers?

The signals generated by transducers are normally of the order of microvolts to millivolts. The magnitude of the signal generated depends on the quantity being assessed, as well as the type and sensitivity of the transducer.

In order to use the signal generated by a transducer, it is usually necessary to amplify and filter the signal to remove noise and unwanted frequencies. This can be done using an amplifier or other signal processing equipment.

Overall, the signals generated by transducers are a crucial part of many electronic systems and are used in a wide variety of applications.

To learn more about transducers from the given link.

https://brainly.com/question/21510006

#SPJ11

Answer:

An image is formed on the retina with light rays converging most at the cornea and upon entering and exiting the lens. Rays from the top and bottom of the object are traced and produce an inverted real image on the retina. The distance to the object is drawn smaller than scale

Answer: D

Explanation: I saw it in a bill nye video.

By shooting past it's equilibrium position and then oscillate before settling to the equilibrium position is characterize the response of the mass once you let go. So, option A is corect choice.

The given mass-spring-damper system can be represented by the differential equation:

\(my'' + \mu_fy' + k\timesy = F_{ext}\)

where y is the displacement of the mass from its equilibrium position, and \(F_{ext}\) is any external force acting on the system.

To determine the response of the mass once you let go, we need to solve the above differential equation for the initial condition y(0) = 0.2 and y'(0) = 0 (assuming that the mass is released from rest).

To solve the differential equation, we first need to determine the damping ratio, which is given by:

damping ratio (ζ) = \(\mu_f / (2 \times \sqrt{(k \times m)})\)

Substituting the given values, we get:

damping ratio (ζ) = \(7 / (2 \times \sqrt{160 \times 80})\) = 0.1106

Since the damping ratio is less than 1, the system is underdamped.

Therefore, the response of the mass once you let go will oscillate with a decreasing amplitude until it reaches its equilibrium position.

The frequency of oscillation (ω) can be determined using the following formula:

ω = \(\sqrt{(k / m - \zeta ^2 times (\mu_f^2 / 4 \times m^2))}\)

Substituting the given values, we get:

ω = \(\sqrt{160 / 80 - 0.1106^2 \times (7^2 / (4 \times 80^2)}\)= 4.352 rad/s

The time period of oscillation (T) can be determined using the formula:

T = 2π / ω

Substituting the value of ω, we get:

T = 2π / 4.352 = 1.444 s

Therefore, once you let go, the mass will oscillate around its equilibrium position with a decreasing amplitude and a time period of 1.444 s until it eventually comes to rest.

Hence, the correct answer is option A: "It would shoot past its equilibrium position and then oscillate before settling to the equilibrium position."

For similar question on equilibrium position

https://brainly.com/question/14297698

#SPJ11

Question:-

you have a mass spring damper system as descried by

\(m\frac{d^2y}{dt^2}+\mu_f\frac{dy}{dt}  +ky =F_{ext}\)

where

m= 80 kg

\(\mu_f\)  = 7 N*s/m

k = 160 N/m

The unit of Newtons (N) is equivalent to kg m/s²

If you were to displace the mass by 0.2 m from its equilibrium position, how would you characterize the response of the mass once you let go? (Hint: you need to determine the value of the damping ratio).

a. It would shoot past it's equilibrium position and then oscillate before settling to the equilibrium position

b. It will approach the equilibrium position very slowly but not oscillate.

c. The answer depends on the value of the time constant

d. The system will be critically damped.

The specimen that will be on display is set up on stage. When working at greater magnifications when careful motions of the specimen slide are needed, a mechanical stage is employed.

A microscope having several lenses and a separate light source is called a compound light microscope.

Ocular lenses are located in the binocular eyepieces of this type of microscope, while objective lenses are located in a rotating nosepiece that is located closer to the specimen.

Hence, the part of the compound light microscope is specimens placed for viewing is stage.

To learn more about the compound light microscope refer;

https://brainly.com/question/1600608

#SPJ1

The maximum height of the ball is approximately 6.096 m and the work done by gravity is -4.95 J.

Given information,

m = 0.071 kg

V₀ = 11 m/s

(a) Finding the maximum height:

The initial kinetic energy of the ball is converted into potential energy at its maximum height.

Initial kinetic energy = Potential energy at maximum height

(1/2)mv₀² = mgh

(1/2)(0.071 kg)(11 m/s)² = (0.071 kg)(9.8 m/s)h

h = (0.5)(11²)/(9.8) ≈ 6.096 m

Part (b) Calculating the work done by gravity:

The work done by gravity during the ball's flight to its maximum height is equal to the change in potential energy. Since the gravitational potential energy is defined as zero at the initial height, the work done by gravity is equal to the negative of the potential energy at the maximum height.

Wg = -mgh

Wg = -0.071 × 9.8 × 6.096

Wg ≈ -4.95 J

Learn more about gravity, here:

https://brainly.com/question/1479537

#SPJ1

According to the given question, a force of 8 N is applied at an angle of 150 degrees with respect to the displacement of a 12 kg box. This means that the force is not being applied in the same direction as the displacement of the box.

In order to calculate the work done, we need to first determine the component of the force in the direction of the displacement. To do this, we can use trigonometry to find the cosine of the angle between the force vector and the displacement vector.

Once we have this value, we can multiply it by the magnitude of the force and the distance traveled to get the work done. It is important to note that work is a scalar quantity and is measured in joules.

Therefore, the final answer will be in joules. In this case, the work done will be less than if the force was applied in the same direction as the displacement.

To know more about displacement refer here:

https://brainly.com/question/11934397#

#SPJ11

Match the volcano type with its correct

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

Magma Composition: Mafic

Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

Magma Composition: Intermediate, varies from felsic to mafic

Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath  continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

Magma Composition: Mafic

Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Magma Composition: Mafic

Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.

5. Seafloor Volcanism, Pillow Lava:

Plate Tectonic Setting: Mostly Spreading Ridges

Magma Composition: Mafic

Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.

These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.

Learn more about magma composition here:

https://brainly.com/question/862669

#SPJ11

Explanation: Research highlights the individuals with ASDS are nutritionally vulnerable because they exhibit a selective or pick eating pattern and sensory sensitivity that predisposes them to restricted intakes.

I hope this helps!

The thermal conductivity of the metal is approximately B, 241 W/(m · K).

To find the thermal conductivity (k) of the metal, use the formula:

Q = k × A × (ΔT/Δx) × t

Where:

Q = Heat conducted by the rod (in Joules)

A = Cross-sectional area of the rod (in square meters)

ΔT = Temperature difference across the rod (in Kelvin)

Δx = Length of the rod (in meters)

t = Time (in seconds)

Given:

Q = 8.5 g of ice melted = 8.5 × Lf (latent heat of fusion of ice)

Lf = 3.34 × 10⁵ J/kg

Δx = 60 cm = 0.6 m

A = 1.25 cm² = 1.25 × 10⁻⁴ m²

t = 10 min = 600 seconds

ΔT = (100°C - 0°C) = 100 K

Substituting the given values into the formula:

8.5 × Lf = k × (1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s

Simplifying the equation:

k = (8.5 × Lf) / [(1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s]

Calculating the value:

k = (8.5 × 3.34 × 10⁵) / [(1.25 × 10⁻⁴) × (100 / 0.6) × 600]

k ≈ 241 W/(m · K)

Therefore, the thermal conductivity of the metal is approximately 241 W/(m · K).

Find out more on thermal conductivity here: https://brainly.com/question/11213835

#SPJ1

The weight of an object is the force of gravity on the object and may be defined as the mass times the acceleration of gravity, w = mg. Where W = weight in N. m = mass in kg and g = gravitational field strength in N/kg. g = 10 N/kg.

Answer:

(a) k = 80 N/m   (b) x = 75 cm

Explanation:

The question says that, "A spring is elongated 30 centimeters when we exert a force of 24 N on it a) calculate the value of the spring constant b) calculate the elongation of the spring when applying a force of 60 N"

Given that,

Force exerted on the spring, F = 24 N

Elongation in the spring, k = 30 cm =0.3 m

(a) We know that, the force on the spring is given by :

F = kx

Where

k is spring constant

So,

\(k=\dfrac{F}{x}\\\\k=\dfrac{24}{0.3}\\\\k=80\ N/m\)

(b) When F = 60 N,

\(x=\dfrac{F}{k}\\\\x=\dfrac{60}{80}\\\\x=0.75\ m\\\\x=75\ cm\)

Hence, this is the required solution.

When a rock is transported from the moon to the earth, both mass and weight are changed.

Explanation:

The reason why both mass and weight are changed when a rock is transported from the moon to the earth is that the gravitational field on the surface of the earth is stronger than that on the surface of the moon.

This means that the rock's mass, which is the measure of the amount of matter that an object contains, will remain the same.

However, the rock's weight, which is the force with which an object is attracted to the earth due to gravity, will be different since the gravitational pull on the moon is much weaker than that on the earth. This implies that when the rock is transported from the moon to the earth, it will experience a higher gravitational force which will cause it to weigh more compared to when it was on the moon.

Therefore, both mass and weight will change when a rock is transported from the moon to the earth.

To know more amount gravitational force here:

https://brainly.com/question/24783651

#SPJ11

Answer:

The nature of volcanic eruptions is highly dependent on magma viscosity and also on dissolved gas content. ... long it takes the treacle to flow from one end of a boiling tube to the other.