Area of triangle with height is on clear

The phase that is not a part of the planning process for both statistical and non-statistical sampling is determining the sample size.

Determining the sample size is an essential step in statistical sampling, as it involves calculating the number of observations needed to ensure statistical validity. However, in non-statistical sampling, the focus is on selecting specific cases or items for examination based on subjective criteria, rather than relying on statistical principles or sample size calculations. Instead, non-statistical sampling emphasizes judgment and expert knowledge to choose representative samples. By excluding the determination of sample size, non-statistical sampling allows for greater flexibility and adaptability in the sampling process, enabling a more tailored approach to the specific objectives of the study or investigation.

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Answer:  (3,5)

Step-by-step explanation:

A minimum sample size of 121 individuals needs to be surveyed, ensuring a rounded-up value to estimate the proportion of non-graduates within the 25 to 30 age group with a 10% margin of error and 90% confidence.

To determine the sample size required to estimate the proportion of non-graduates within the 25 to 30 age group with a certain level of confidence and margin of error, we can use the formula:

n = (Z^2 * p * (1 - p)) / E^2

Where:

n is the required sample size

Z is the Z-score corresponding to the desired confidence level (90% confidence corresponds to a Z-score of approximately 1.645)

p is the estimated proportion of non-graduates (0.21 based on the information provided)

E is the desired margin of error (10% or 0.10)

Substituting the values into the formula:

n = (1.645^2 * 0.21 * (1 - 0.21)) / 0.10^2

n ≈ 120.41

Rounding up to the nearest integer, the required sample size is 121.

Therefore, you would need to survey at least 121 individuals in the 25 to 30 age group to estimate the proportion of non-graduates within 10% margin of error with 90% confidence.

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4/5

Step-by-step explanation:

9x+1=5

or, 9x=5-1

or, 9x=4

therefore x=4/5

Answer

First - Use subtraction property

Second - add or subtract like terms

Third - Divison property

Fourth - X=4/9

Step-by-step explanation:

The derivative of the function g(x) = (x² - x + 1\()^1^0\) * (tan(x))³ is g'(x) = 10(x² - x + 1)⁹ * (2x - 1) * (tan(x))³ + 3(x² - x + 1\()^1^0\) * (tan(x))² * sec²(x).

To find the derivative of the given function g(x), we can apply the product rule and the chain rule. Let's break down the function into its constituent parts: f(x) = (x² - x + 1\()^1^0\) and h(x) = (tan(x))³.

Using the product rule, the derivative of g(x) can be calculated as g'(x) = f'(x) * h(x) + f(x) * h'(x).

First, let's find f'(x). We have f(x) = (x² - x + 1\()^1^0\), which is a composite function. Applying the chain rule, f'(x) = 10(x² - x + 1\()^9\) * (2x - 1).

Next, let's determine h'(x). We have h(x) = (tan(x))³. Applying the chain rule, h'(x) = 3(tan(x))² * sec²(x).

Now, we substitute these derivatives back into the product rule formula:

g'(x) = f'(x) * h(x) + f(x) * h'(x)

       = 10(x² - x + 1)² * (2x - 1) * (tan(x))³ + 3(x² - x + 1\()^1^0\)* (tan(x))² * sec²(x).

In summary, the derivative of the function g(x) = (x² - x + 1\()^1^0\) * (tan(x))³ is g'(x) = 10(x² - x + 1)⁹  * (2x - 1) * (tan(x))³ + 3(x² - x + 1\()^1^0\) * (tan(x))² * sec²(x).

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Answer: -18

Step-by-step explanation:

We know that Kayla’s grade was lowered every time she was late to class. Taking this into consideration, we multiply -3 and 6 (beacuse she was late to class 6 times; 3 is negative because her grade is decreasing) which results in -18.

The change is Katja’s grade is -18% or points.

The geometric mean radius of the unconventional conductors in terms of the radius r of an individual strand is 1.583r.

To find the geometric mean radius of the unconventional conductors, we need to understand the concept of geometric mean. The geometric mean of two numbers is the square root of their product. In this case, we are looking for the geometric mean radius of multiple strands.

First, we need to determine the number of strands in the unconventional conductors. The question does not provide this information explicitly, so we assume there are at least two strands.

We know that the geometric mean radius is the square root of the product of the individual strand radii. Let's assume there are n strands, and the radius of each strand is r. Therefore, the product of the individual strand radii would be r^n.

Now, we can calculate the geometric mean radius by taking the square root of r^n. Mathematically, it can be expressed as (r^n)^(1/n) = r^((n/n)^(1/n)) = r^1 = r.

Therefore, the geometric mean radius in terms of the radius r of an individual strand is 1.583r.

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Answer:

h = 6 units

Step-by-step explanation:

area of a parallelogram = bh

where:

area = 54 sq. units

b = 9 units

h = ? units

plugin values into the formula:

54 = 9 (h)

h = 54 / 9

h = 6 units

The statement that proves that angle XWY is equal to angle ZYW is

A. If two parallels are cut by a transverse, then alternate interior angles are congruent

Alternate interior angles are a pair of angles that are formed on opposite sides of a transversal line when two parallel lines are intersected by the transversal.

When a transversal intersects two parallel lines, it creates eight angles. Among these angles, the alternate interior angles are located on the inside of the parallel lines and on opposite sides of the transversal.

In a parallelogram, the two opposite sides are parallel to each other hence the line crossing them will lead to formation of alternate interior angles

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Answer:

(21, 28)

Step-by-step explanation:

Multiply the coordinates by 7.

The estimate made by Warner is 95% reasonable.

Given is that Warner received 7 letters and each letter weighed between 3.92 ounces and 4.1 ounces.

If the we take the maximum possible weight of each letter, which is 4 ounces, then the total weight of 7 letters will be equal to (4 x 7) = 28. But since the weights are weighted between 3.92 ounces and 4.1 ounces, let us assume that the weight of each letter is equivalent to -

w(a) = (3.92 + 4.10)/2 = 8.02/2 = 4.01

So, the weight of 7 letters would be -

W{7} = w(a) x 7 = 7 x 4.01 = 28.7

28.7 = 29 (round off) ≈ 30

So, yes the estimate of the Warner is reasonable.

Therefore, the estimate made by Warner is 95% reasonable.

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f(x) is a linear function with no restrictions

Domain: x = All real numbers

Range: y = All real numbers

The Domain : {(−∞,∞), {x/x∈R} and Range : {(−∞,∞), {y/y∈R} of the function  f(x)=2x-5

A relation is a function if it has only One y-value for each x-value.

We have to find the domain and range of f(x)=2x-5

The domain of the expression is all real numbers except where the expression is undefined.

In this case, there is no real number that makes the expression undefined.

Interval Notation:(−∞,∞)

The range is the set of all valid y values.

Domain : {(−∞,∞), {x/x∈R}

Range : {(−∞,∞), {y/y∈R}

Hence, the Domain : {(−∞,∞), {x/x∈R} and Range : {(−∞,∞), {y/y∈R} of the function  f(x)=2x-5

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The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as "rise over run" (change in y divided by change in x).

Since the slope of the line segment AB is 3/4, we know that its rise is 3, and its run is 4.

So, the coordinates of points A and B could be A(0,0) and B(4,3).

On the other hand, the rule for a rotation by 180° about the origin is:

Then we can apply the above rule and calculate the coordinates of line segment A'B'.

Finally, let us find the slope of the line segment A'B'.

As we can see, the slope of the line segment A'B' is also 3/4.

Supports Jessie's claim

The probability of reaching into a box and randomly drawing a specific chip, such as chip 107, is calculated as the number of favorable outcomes (in this case, one chip) divided by the total number of possible outcomes (the total number of chips in the box).

If only one chip numbered 107 in the box, then the probability of randomly drawing that chip would be 1/N, where N is the total number of chips in the box. If there are multiple chips numbered 107, the probability would be the number of chips numbered 107 divided by the total number of chips in the box.

So, if there is only one chip numbered 107 in the box, and the total number of chips in the box is N, the probability of randomly drawing that chip would be 1/N. If we don't know the value of N, we can't calculate the probability exactly.

It's worth noting that probabilities are always between 0 and 1, inclusive, where 0 means an impossible event, and 1 means a certain event.

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Option (e) 16t^2 = 81 is the equation that can be solved for t to find the time (in seconds) when the diver hits the water.

The equation that can be solved for t to find the time (in seconds) when the diver hits the water is:

d(t) = 16t^2 = 81

We want to find the value of t that satisfies this equation, which represents the time it takes for the distance fallen to reach the height of the water surface.

To solve for t, we can start by dividing both sides of the equation by 16:

t^2 = 81/16

Next, we can take the square root of both sides to isolate t:

t = ±√(81/16)

t = ±(9/4)

Since time cannot be negative, we discard the negative solution, and we get:

t = 9/4

Therefore, the time it takes for the cliff diver to hit the water surface is 9/4 seconds, or approximately 2.25 seconds.

Option (e) 16t^2 = 81 is the equation that can be solved for t to find the time (in seconds) when the diver hits the water.

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We have to find the present value and the compound discount of $4352.73 due 8.5 years from now if money is worth 3.7% compounded annually. Here, the formula for the present value of a single sum is PV=FV/(1+r)^n Where, PV = present value, FV = future value, r = interest rate, and n = number of years.

Step by step answer:

Given, Future value (FV) = $4352.73

Time (n) = 8.5 years

Interest rate (r) = 3.7%

Compounding period = annually Present value

(PV) = FV / (1 + r)ⁿ

As per the formula, PV = $4352.73 / (1 + 0.037)^8.5

PV = $2576.18 (approx)

Hence, the present value of the money is $2576.18 (rounded to the nearest cent). Compound discount is calculated by taking the difference between the face value and the present value of a future sum of money. Therefore, Compound discount = FV – PVD = $4352.73 – $2576.18

Compound discount = $1776.55 (approx)

Hence, the compound discount of $4352.73 due 8.5 years from now is $1776.55 (rounded to the nearest cent).

Therefore, the present value of the money is $2576.18 and the compound discount of $4352.73 due 8.5 years from now is $1776.55 (rounded to the nearest cent).

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Answer:

C. 208,900

Step-by-step explanation:

Scientific notation with a positive exponent:

Start with the decimal number and move the decimal point to the right the same number of places as the exponent. The exponent of 10 is 5.

Start with 2.089

Now add some zeros to the right of the 9.

2.0890000

Now move the decimal point 5 places to the right.

208900.00

The number is 208,900

The volume of the solid obtained by rotating the region R about the z-axis is 64π/3.

The volume of the solid is -100/9 cubic units.

We have,

(a)

We need to compute the volume of the solid obtained by rotating the region R about the z-axis.

This solid is the union of a hemisphere of radius 2 and a pyramid of base area A = πr^2 = 16π and height h = 2.

The volume is given by:

V = Vsphere + Vpyramid

= (4π/3)(2³) + (1/3)(16π)(2)

= (32π/3) + (32π/3)

= (64π/3)

(b)

We need to compute the volume of the solid that lies above the triangle R in the xy - plane and below the plane z = 20 - 4x - 5y.

Since the solid is bounded by a plane and a surface, we can use the formula:

V = ∬R [20 - 4x - 5y] dA

where R is the triangle bounded by the lines 5y + 4x = 20, x = 0, and y = 0 in the xy-plane.

To evaluate this integral, we need to express dA in terms of x and y.

Since the triangle is in the positive octant, we have:

dA = dxdy

Therefore, the integral becomes:

V = ∫0^4 ∫0^(5/4)(20 - 4x - 5y) dy dx

= ∫0^4 [(20/5)x - (2/5)x² - (25/24)x²] dx

= ∫0^4 [(20/5) - (2/5)x - (25/24)x²] dx

= [20x/5 - (1/5)x² - (25/72)x³]_0^4

= (16/5) - (16/5) - (500/72)

= -100/9

The volume of the solid is -100/9 cubic units.

Note that the negative sign indicates that the solid lies below the

xy - plane.

Thus,

The volume of the solid obtained by rotating the region R about the z-axis is 64π/3.

The volume of the solid is -100/9 cubic units.

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Answer:

a)13

b)64

c)26

Step-by-step explanation:

4x+12=6x-14

Divide by 2

2x+6=3x-7

2x-3x=-7-6

-x=-13

x=13

m<1

4x+12

4(13)+12

52+12

64

64+64+y+y=180

divide by 2

64+y=90

y=90-64

y=26

Answer:

40words

Step-by-step explanation:

Answer: 40

Step-by-step explanation: I Took The Test

a. Estimating the regression equation The estimated regression equation is used to predict the overall score given the score for shore excursions. The equation is:

y^ = 12.84 + 0.63x1Where: y^ is the predicted overall scorex1 is the Shore Excursion scoreb. Adding Food/Dining Score The estimated regression equation that can be used to predict the overall score given the scores for Shore Excursions and Food/Dining is:

y^ = 9.93 + 0.55x1 + 0.32x2Where: y^ is the predicted overall scorex1 is the Shore Excursion scorex2 is the Food/Dining score c. Predicting the overall score Predict the overall score for a cruise ship with a Shore Excursions score of 78 and a Food/Dining Score of 91.

Substituting the values into the regression equation:

y^ = 9.93 + 0.55x1 + 0.32x2

y^ = 9.93 + 0.55(78) + 0.32(91)

y^ = 9.93 + 42.90 + 29.12

y^ = 81.95

Thus, the predicted overall score is 81.9.

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The standard error of the average sample weight when 15 participants are randomly selected for the sample is 9.05 (rounded to two decimal places).

The standard error of the average sample weight when 15 participants are randomly selected for the sample can be calculated using the formula given below:SE = σ/√nWhere,σ = standard deviation of the populationn = sample sizeSE = standard error of the meansubstituting the given values,SE = 35/√15 = 9.05

Note:When using the given formula, it is important to note that it assumes a normal distribution of sample means. The standard error is used to estimate the true value of the mean from the sample data. The larger the sample size, the smaller the standard error. The smaller the standard error, the more precise the estimate of the true value of the mean.

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the probability that a Bar-headed goose chosen at random flaps its wings between 4 and 4.5 times per second is approximately 0.6831 or 68.31%.          

To find the probability that a Bar-headed goose chosen at random flaps its wings between 4 and 4.5 times per second, we can use the properties of the Normal distribution.

Given that the wingbeat frequency follows a Normal distribution with a mean (μ) of 4.25 flaps per second and a standard deviation (σ) of 0.2 flaps per second, we need to calculate the probability that the wingbeat frequency falls within the range of 4 to 4.5.

We can standardize the range by using the Z-score formula

Z = (X - μ) / σ

where X is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.

For the lower bound, 4 flaps per second:

Z_lower = (4 - 4.25) / 0.2

For the upper bound, 4.5 flaps per second:

Z_upper = (4.5 - 4.25) / 0.2

Now, we need to find the probabilities associated with these Z-scores using a standard Normal distribution table or a calculator.

Using a standard Normal distribution table, we can find the probabilities as follows:

P(4 ≤ X ≤ 4.5) = P(Z_lower ≤ Z ≤ Z_upper)

Let's calculate the Z-scores:

Z_lower = (4 - 4.25) / 0.2 = -1.25

Z_upper = (4.5 - 4.25) / 0.2 = 1.25

Now, we can look up the corresponding probabilities in the standard Normal distribution table for Z-scores of -1.25 and 1.25. Alternatively, we can use a calculator or statistical software to find these probabilities.

using a standard Normal distribution table, we find:

P(-1.25 ≤ Z ≤ 1.25) ≈ 0.7887 - 0.1056 = 0.6831

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Answer:the answer is 9

Step-by-step explanation:

Answer:

The interval on which the solution is defined depends on the domain of the exponential function. Since e^((1/2)x^2 + ln(2)) is defined for all real numbers, the solution is defined on the interval (-∞, +∞), meaning the solution is valid for all x values.

Step-by-step explanation:

o solve the differential equation dy/dx = xy with the initial condition y(0) = 2, we can separate the variables and integrate both sides.

Starting with the given differential equation:

dy/dx = xy

We can rearrange the equation to isolate the variables:

dy/y = x dx

Now, let's integrate both sides with respect to their respective variables:

∫(dy/y) = ∫x dx

Integrating the left side gives us:

ln|y| = (1/2)x^2 + C1

Where C1 is the constant of integration.

Now, we can exponentiate both sides to eliminate the natural logarithm:

|y| = e^((1/2)x^2 + C1)

Since y can take positive or negative values, we can remove the absolute value sign:

y = ± e^((1/2)x^2 + C1)

Next, we consider the initial condition y(0) = 2. Substituting x = 0 and y = 2 into the solution equation, we get:

2 = ± e^(C1)

Here, we see that e^(C1) is positive since it represents the exponential of a real number. So, the ± sign can be removed, and we have:

2 = e^(C1)

Taking the natural logarithm of both sides:

ln(2) = C1

Now, we can rewrite the general solution with the determined constant:

y = ± e^((1/2)x^2 + ln(2))

Answer:{ x,y } = { - 2, - 3 }

Step-by-step explanation: 4x = 2y - 2                                                                      

x = y/2 - 1/2                  

3. (y   /2 -  1/2 ) + 2y  =  - 12  

7y/2 =  - 21/2  

7y =   -  21    

x =   y/2 - 1/2  

   y =  - 3    

x = (/2) ( - 3 ) - 1/2 = - 2

The probability that the sample mean would be less than 31,358 miles in a sample of 242 tires if the manager is correct is 0.9925 (or 99.25%).

What is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.

We can use the central limit theorem to approximate the distribution of the sample mean. According to the central limit theorem, if the sample size is sufficiently large, the distribution of the sample mean will be approximately normal with a mean of 30,641 and a standard deviation of sqrt(variance/sample size).

So, we have:

mean = 30,641

variance = 14,561,860

sample size = 242

standard deviation = sqrt(variance/sample size) = sqrt(14,561,860/242) = 635.14

Now, we need to calculate the z-score corresponding to a sample mean of 31,358 miles:

z = (sample mean - population mean) / (standard deviation / sqrt(sample size))

= (31,358 - 30,641) / (635.14 / sqrt(242))

= 2.43

Using a standard normal distribution table or calculator, we can find the probability that a z-score is less than 2.43. The probability is approximately 0.9925.

Therefore, the probability that the sample mean would be less than 31,358 miles in a sample of 242 tires if the manager is correct is 0.9925 (or 99.25%).

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Answer:

A) if and only if a = 0

Step-by-step explanation:

Since Z1 = 12 + 6݅  and Z2 = a + bi , then the product, Z1Z2 = (12 + 6)(a + bi)

Z1Z2 = (12 + 6)(a + bi)

Expanding the brackets, we have

Z1Z2 = 12a + 12bi + 6a + 6bi

Collecting like terms, we have

Z1Z2 = 12a + 6a + 12bi +6bi

Z1Z2 = 12a + 6a + (12b +6b)i

Simplifying, we have

Z1Z2 = 18a + 18bi

For Z1Z2 to be imaginary, then the real part must be zero.

That is 18a = 0 ⇒ a = 0

So, Z1Z2 is imaginary if and only if a = 0

Consider a simulation that uses random numbers to represent inputs. the reason why confidence intervals are used to analyze simulation output is A. Because process output will vary randomly.

The output data that is obtained from a simulation model is analyzed for obtaining a valid statistical inference. The inference is obtained from the initial as well as the long-term behaviour of the system. The average is obtained from n number of replicate simulation runs. The analysis of the data that is generated by the simulation run is called “output analysis”. The analysis can be used for predicting the performance of the system or for comparing the performance of multiple system designs. Multiple simulation runs are required and necessary for stochastic simulation.

The output data that is obtained from the simulation runs exhibits random variability. It is produced when the random number generators are deployed. For instance, when two different and random number streams are used there will be two different sets of outputs. The confidence interval can be used for finding out the average (or mean) in such a scenario. The confidence interval will provide information between the expected value of a certain parameter (when the simulation is run infinite times) and the actual or real value/statistic obtained for a certain simulation.

The question is incomplete. The complete question is:

"Consider a simulation that uses random numbers to represent inputs. the reason why confidence intervals are used to analyze simulation output is:

A. Because process output will vary randomly.

B. Because the simulation code may not be 100% accurate for representing the process flow.

C. All of these reasons reasons

D. To account for inaccuracies in the simulation code."

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