Are x and y proportional?

The midpoint of AB is M(4,1), If the coordinates of A are (2,8), then the coordinates of B are (6,-6).

The midpoint formula states that the midpoint of a line segment in a coordinate plane is given by the average of the x-coordinates and the average of the y-coordinates.

The midpoint of AB is M(4,1) and the coordinates of A are (2,8).

Therefore, we can write the following equation: x-coordinate of the midpoint = (x-coordinate of A + x-coordinate of B) / 2y-coordinate of the midpoint = (y-coordinate of A + y-coordinate of B) / 2

Substituting the given values into the above equation, we get:4 = (2 + x-coordinate of B) / 2 1 = (8 + y-coordinate of B) / 2

Simplifying the equations above, we get: x-coordinate of B = 6 y-coordinate of B = -6

Therefore, the coordinates of B are (6,-6).

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44 is the answer

Step-by-step explanation:

8, 18, 27, 38, 44, 46, 62, 91, 752

Answer:

44

Step-by-step explanation:

[I suppose there must be a comma between 18 and 46].]

First, arrange the numbers in ascending order.

8, 18, 27, 38, 44, 46, 62, 91, 752

The median is the middle number in a set of numbers. There are 9 numbers  here, so we can easily find the middle number. [This only applies to an odd set of numbers. But if there were an even set of numbers, you would have to find the average of the two middle numbers]

∴ Median = 44

the null hypothesis (H0) represents the statement that there is no significant difference or effect, while the alternative hypothesis (Ha) states the opposite.

to determine if there is enough evidence to support the claim that the mean annual return is indeed greater than 3.6 percent or not.In hypothesis testing, the null hypothesis (H0) represents the statement that there is no significant difference or effect, while the alternative hypothesis (Ha) states the opposite.

In this case, the null hypothesis is that the mean annual return for the employee's IRA is at most 3.6 percent. It suggests that the true mean return is equal to or less than 3.6 percent. Mathematically, it can be represented as H0: μ ≤ 3.6, where μ represents the population mean.

The alternative hypothesis, Ha, contradicts the null hypothesis and asserts that the mean annual return is greater than 3.6 percent. It suggests that the true mean return is higher than 3.6 percent. It can be represented as Ha: μ > 3.6.

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Answer:

m∠D = 94°

Step-by-step explanation:

Quadrilateral ABCD is also called a cyclic quadrilateral or a quadrilateral that is inscribed in a circle.

Opposite angles in a cyclic Quadrilateral are supplementary, i.e the sum of two opposite angles in a Quadrilateral = 180°

m∠A + m∠C = 180°

m∠A = 74°

74° + m∠C = 180°

m∠C = 180° - 74°

m∠C = 106°

In a cyclic quadrilateral, the total sum of the angles outside the circle = 360°

i.e =

m∠AB + m∠BC + mDC + mAD = 360°

m∠DAB= ( m∠C) × 2

= 106° × 2 = 212°

m∠DAB = m∠AD + m∠AB

m∠AD = 79°

212° = 79° + m∠AB

m∠AB = 212° - 79°

= 133°

m∠ABC = m∠AB + m∠BC

m∠AB = 133°

m∠BC= 55°

m∠ABC = 133° + 55°

= 188°

We are asked to find m∠D

m∠D = 1/2m∠ABC

m∠ABC = 188°

m∠D = 1/2 × 188°

m∠D = 94°

Therefore, m∠D = 94°

Answer:

its -1/5

Step-by-step explanation:

Answer:

Step-by-step explanation:

1/2 (1/9) + 2=

1/18 + 2=

2 1/18

Answer:

150-75=75, so a change of -75

Step-by-step explanation:

He spent 150 tokens and only got 75 tokens back

The original price for the television is $883.51

A store will discount an item by a percent of the original price.

Given that, a store is having a sale on televisions, all televisions are on sale for 15% off, a customer buys a television for $750.99.

Let the original price be x

x*(100-15)% = 750.99

x = 750.99*100/85

x = 883.51

Hence, the original price for the television is $883.51

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The equation of the circle in standard form is (x-6)² + (y-11)² = 121.

The equation of a circle can be defined in the standard form :

(x-a)² + (y-b)² = r²,

Here (a,b) is the center of the circle, and r is the radius of the circle.

We know that circle is said to be tangent to the x-axis if its center lies on the x-axis.

Thus , Let the center is given to be (6,11) and is tangent to the x-axis. Hence, the equation of the circle can be written as follows;

(x-6)² + (y-11)² = r².

The radius of the circle can be determined by nothing that it is tangent to the x-axis, which means the distance from the center (6,11) to the x-axis is equal to the radius of the circle.

Thus the x-axis is perpendicular to the y-axis, the distance between the center (6,11) and the x-axis is the distance between (6,11) and (6,0). Therefore, r = 11 - 0 = 11

Thus, the equation of the circle is; (x-6)² + (y-11)² = 121.

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The complete question is;

Consider the circle with a center  (6,11) and which is a tangent to the x-axis. The objective is to find the equation of the circle is in standard form and to graph the circle.

a) Point O

b) \(\overline{OB}\)

c) \(\overline{AB}\)

4) arc DE (m)

5) \(\overline{DE}\)

6) Semicircle AEB

Yes line TV is also parallel to line QS according to transverse property

According to the transitive property, all the quantities are equal to each other if two quantities are equal to the third quantity.

When the term equal is replace by parallel it suits the case at hand hence transitive property of parallel lines is introduced

When attempting to demonstrate that several parallel lines have congruent properties, the transitive property of parallel lines can be used to create a link between numerous equal quantities.

Therefore, it can be interpreted as: if line TV || line ZX and line ZX || line QS then line TV || line ZX

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On solving the provided question, we can say that - the percentage decrease in the number of students​ is -10%.

A percentage in mathematics is a figure or ratio that is stated as a fraction of 100. The abbreviations "pct.," "pct," and "pc" are also occasionally used. It is frequently denoted using the percent symbol "%," though. The amount of percentages has no dimensions. It has no measuring systems. With a denominator of 100, percentages are basically fractions. To show that a number is a percentage, place a percent symbol (%) next to it. Your score is 75%, for instance, if you correctly answer 75 out of 100 questions on a test (75/100).

Given that,

The school has 1,200 students last year.

And, this year it is 1,080.

Based on the above information, the calculation is as follows:

1080-1200/1200

= -10%

Therefore we can conclude that the percentage decrease in the number of students​ is -10%.

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Answer:

Let f(x)=x

4

+4x

3

−5x

2

−6x+7.

Let R be the remainder obtained when f(x) is divided by x+3.

Equate x+3 to 0 and put the value of x in f(x).

x+3=0

⟹x=−3

R=(−3)

4

+4(−3)

3

−5(−3)

2

−6(−3)+7

   =81−108−45+18+7

   =−47

Thus required remainder is −47

1)  An expression for the amount of fabric needed to make 13 pairs of wings is; 3/4 * $8 = $6 each

2) An expression of the total cost is; 3/4 * $8 * 13 = $78

3) The way we will use  associative and commutative properties is to start by treating 1 yard of fabric like the fraction 4/4.

4) Simplifying equals $78

We are told that each pair of wings is made with 3/4 yard of fabric. Since the fabric costs $8 per yard. Thus;

1) 3/4 * $8 will give us the cost of the amount required for 3/4 yard of fabric.  3/4 * $8 = $6 each

2) Now, we are told that Mr. Townsend needs to make 13 pairs of butterfly wings and as such;

Amount needed to make 13 pairs is expressed as; 3/4 * $8 * 13 = $78

3) Treat 1 yard of fabric like the fraction 4/4.

Now, if this 1 fabric is equal to $8, then it means that 3/4 of the fabric will be $6. That is for one pair of butterfly wings, there's 13 of those so multiply $6 by 13.

This pattern is easier  because we know how much 1 fabric costs, but we don't know what 3/4 of it does, so we treat 1 yard of fabric as the fraction 4/4.

4) Simplifying the expression gives; $78

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The total distance Raven is driving is 300 mi. The distance she has left to drive is 210 mil.

Percentage is the fraction out of an amount that is usually expressed as a number out of hundred. It is a measure of frequency.

Total distance = 90 mi / 30%

=90 / 0.3 = 300 mi

Distance he has left = 300 - 90 = 210 mi

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the sign will be a negative sign -

Answer:

IN a series of multiplications (or divisions)

add up the negative signs ... if they are even the answer is positive "+"

the there is an odd number the answer will be negative "-"

Step-by-step explanation:

By adding and subtracting 9, we will be able to complete squares and rewrite the expression as:

x^2 + 6x = (x + 3)^2 - 9

Remembert that the perfect square trinomial is:

(a + b)^2 = a^2 + 2ab + b^2

Here we have the quadratic expression:

x^2 + 6x

We can rewrite the second term as:

x^2 + 2*3*x

Then, comparing with the variables on the first equation, we can use:

x = a

3 = b

Then what we need to add to complete squares is 3^2 = 9

To not change the expression, we will add and subtract that number (which is equivalent to adding 0).

x^2 + 2*3*x + 9 - 9

(x^2 + 3*3x + 9) - 9

(x + 3)^2 - 9

That is the expression after we complete squares.

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Answer:

4 and 7

Step-by-step explanation:

7-4=3

4x7=28

Answer:

obtuse angles

Answer: the answer is  0.015% you have to didved 339% by 226 you ge t0.015%

Step-by-step explanation:

The value of b is 2.

Since the hanger diagram models the equation 2b = 4, we can see that the bar representing 2b has a length of 4 units.

To find the value of b, we need to divide both sides of the equation by 2. This gives us:

2b/2 = 4/2

b = 2

Therefore, the value of b is 2.

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Answer:

This is a little late but it's D. ​1.15h+3=1.75h

Step-by-step explanation:

I took this test

Given statement solution is :- a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

Set A: {apple, banana}, Set B: {cat, dog}

Power set of A: {{}, {apple}, {banana}, {apple, banana}}

Power set of B: {{}, {cat}, {dog}, {cat, dog}}

Set A: {red, blue}, Set B: {circle, square}

Power set of A: {{}, {red}, {blue}, {red, blue}}

Power set of B: {{}, {circle}, {square}, {circle, square}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

Set A: {apple, banana, orange}, Set B: {cat, dog, elephant}

Power set of A: {{}, {apple}, {banana}, {orange}, {apple, banana}, {apple, orange}, {banana, orange}, {apple, banana, orange}}

Power set of B: {{}, {cat}, {dog}, {elephant}, {cat, dog}, {cat, elephant}, {dog, elephant}, {cat, dog, elephant}}

Set A: {red, blue, green}, Set B: {circle, square, triangle}

Power set of A: {{}, {red}, {blue}, {green}, {red, blue}, {red, green}, {blue, green}, {red, blue, green}}

Power set of B: {{}, {circle}, {square}, {triangle}, {circle, square}, {circle, triangle}, {square, triangle}, {circle, square, triangle}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

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The required answer is  If t: R2 → R2 rotates vectors about the origin through an angle φ.

If t rotates vectors about the origin through an angle φ, then it satisfies the properties of linearity: t(u+v) = t(u) + t(v) and t(cu) = ct(u) for any vectors u,v in r2 and scalar c. Therefore, t is a linear transformation.
True: If t: R2 → R2 rotates vectors about the origin through an angle φ, then t is a linear transformation.

Transformation of three phase electrical quantities to two phase quantities is a usual practice to simplify analysis of three phase electrical circuits. Polyphase  machines can be represented by an equivalent two phase model provided the rotating polyphases winding in rotor and the stationary polyphase windings in stator can be expressed in a fictitious two axes coils. The process f replacing one set of variables to another related set of variable is called winding transformation or simply transformation or linear transformation. The term linear transformation means that the transformation from old to new set of variable and vice versa is governed by linear equations. The equations relating old variables and new variables are called transformation equation and the following general form:

This is because the rotation of vectors satisfies the properties of a linear transformation, which are:
1. Additivity: t(u + v) = t(u) + t(v) for all vectors u and v in R2.
2. Homogeneity: t(αu) = αt(u) for all vectors u in R2 and all scalars α.

There are at least a countable infinity of rotation vectors corresponding to any rotation. Furthermore, all rotations by 2πM are the same as no rotation at all, so, for a given integer M, all rotation vectors of length 2πM, in all directions, constitute a two-parameter uncountable infinity of rotation vectors encoding the same rotation as the zero vector.

The axis–angle representation is equivalent to the more concise rotation vector, also called the Euler vector. In this case, both the rotation axis and the angle are represented by a vector codirectional with the rotation axis whose length is the rotation angle θ,
Rotating vectors about the origin through an angle φ preserves these properties, making t a linear transformation.

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Answer:

False.

Step-by-step explanation:

4・4・4・4・4・4・4 = 16,384.

Hope this helps! :)

Answer:

False

Step-by-step explanation:

Answer:

Step-by-step explanation:

The slope of a perpendicular line is the negative inverse of the reference line.  If the reference line is y=mx + b, with slope of m, the perpendicular line will have slope of -(1/m).  The perpendicular line would take the form:

y = -(1/m)+b

Example:  Reference Line:  y = 2x + 2

Perpendicular Line:  y = -(1/2)x + 2

See attachment.

Answer:

The answer, if it is addition, would be 4 + 4/5w

Step-by-step explanation:

Answer:

X = 20

Step-by-step explanation:

The two quadrilaterals are similar to each other. So the ratio of  each side of the larger quadrilateral to the corresponding side of the smaller quadrilateral must be the same.

Examining the two figures we see the side which has  68° and 128° pf the smaller quadrilateral has length 2

The corresponding side of the larger quadrilateral on the right is 6

So each side of the larger quadrilateral =6/2 = 3 times each side of the smaller one

Side which has length 10 pf the smaller quadrilateral corresponds to the side with length x+10 of the larger one. This ratio must also be 1:3

So

\(\dfrac{10 + x}{10}= 3\\\\\)

Cross-multiplying we get
10 + x = 10 x 3

10 + x = 30

x = 30-10

x =20

ANSWER

Answer:

  25 kg

Step-by-step explanation:

The sum of the weights of the small and large sacks is 65 kg. The larger sack weighs 15 kg more. You want the weight of the smaller sack.

Let w represent the weight of the sand in the small sack. Then (w+15) is the weight of the sand in the larger sack. The total weight is 65 kg, so we have ...

  w +(w+15) = 65

Subtracting 15 from both sides gives ...

  2w = 50

  w = 25

The weight of the sand in the small sack is 25 kg.