A crate rests on a flatbed truck which is initially traveling at 13.6m/s on a level road. The driver applies the brakes and the truck is brought to a halt in a distance of 41.0m. If the deceleration of the truck is constant, what is the minimum coefficient of friction between the crate and the truck that is required to keep the crate from sliding?

Answer:

-384.22N

Explanation:

From Coulomb's law;

F= Kq1q2/r^2

Where;

K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2

q1 and q2 = magnitudes of the both charges

r= distance of separation

F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2

F= -495.65 × 10^-3/ 1.29 × 10^-3

F= -384.22N

Based on the information, we can infer that A. represents a Mitochondria.

Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.

Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.

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Answer:

Nuclear Fusion reactions power the Sun and other stars. In a fusion reaction, two light nuclei merge to form a single heavier nucleus. The process releases energy because the total mass of the resulting single nucleus is less than the mass of the two original nuclei.

Explanation:

The sun's energy comes in the form of a nuclear reaction due to the Two nuclei joining to form a larger nucleus. Thus option A is correct.

A nuclear fusion is a reaction in which 2 or more atomic nuclei combine to form one or more atomic nuclei and is manifested by the release or the absorber of energy.

This is due to the differeces in the nuclear binding energy due to the force of nuclei before and after the reaction. The process releases energy as single declines less than the mass of the original nuclei.

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Answer:

]

Explanation:

To calculate the volume of a parallelepiped given the sides, we can use the scalar triple product. The formula for the volume of a parallelepiped with sides a, b, and c is:

Volume = |a · (b × c)|

where · represents the dot product and × represents the cross product.

Using the given sides:

a = (7, 2, 4)

b = (4, 7, 6)

c = (3, 4, 7)

First, calculate the cross product of b and c:

b × c = (7*7 - 4*4, 6*3 - 7*7, 4*4 - 2*3)

      = (49 - 16, 18 - 49, 16 - 6)

      = (33, -31, 10)

Next, calculate the dot product of a and the cross product (b × c):

a · (b × c) = 7*33 + 2*(-31) + 4*10

           = 231 - 62 + 40

           = 209

Finally, take the absolute value of the result to obtain the volume:

Volume = |209| = 209 cubic units

Therefore, the correct answer is:

209 cubic units

The elasticity of supply of labor varies among occupations. The supply of labor is elastic for occupations (a) and (b) and inelastic for occupations (c).

The elasticity of the supply of labor is an important concept that measures the responsiveness of the quantity of labor supplied to changes in the wage rate. An occupation's supply of labor is said to be elastic if its elasticity is greater than 1, inelastic if the elasticity is less than 1, and unitary elastic if the elasticity of supply equals 1. Let's calculate the elasticity of supply for the following occupations and determine whether the supply of labor is elastic, inelastic, or unitary elastic.

a. %ΔES = 7, %ΔW = 3

The formula for the elasticity of supply is (% change in quantity supplied / % change in wage). Therefore, the elasticity of supply for this occupation would be:

Elasticity of supply = (7% / 3%) = 2.33

Since the elasticity of supply is greater than 1, the supply of labor is elastic.

b. ES = 120, W = $8

E’S = 90, W’ = $6

The formula for the elasticity of supply is ((% change in quantity supplied) / (% change in wage)). Therefore, the elasticity of supply for this occupation would be:

Elasticity of supply = ((90 - 120) / ((90 + 120) / 2)) / ((6 - 8) / ((6 + 8) / 2))

The elasticity of supply = (-30 / 105) / (-2 / 7)

Elasticity of supply = 2.00

Since the elasticity of supply is greater than 1, the supply of labor is elastic.

c. ES = 100, W = $5

E’S = 120, W’= $7

The formula for the elasticity of supply is ((% change in quantity supplied) / (% change in wage)). Therefore, the elasticity of supply for this occupation would be:

Elasticity of supply = ((120 - 100) / ((120 + 100) / 2)) / ((7 - 5) / ((7 + 5) / 2))

The elasticity of supply = (20 / 110) / (2 / 6)

Elasticity of supply = 0.81

Since the elasticity of supply is less than 1, the supply of labor is inelastic. The elasticity of supply is a critical concept in labor economics and helps us understand how changes in wage rates affect the quantity of labor supplied in different occupations.

Complete question:

As with the own-wage elasticity of demand for labor, the elasticity of supply of labor can be similarly classified. The elasticity of the supply of labor is elastic if the elasticity is greater than 1. It is inelastic if the elasticity is less than 1, and it is unitary elastic if the elasticity of supply equals 1. For each of the following occupations, calculate the elasticity of supply, and state whether the supply of labor is elastic, inelastic, or unitary elastic. E’s and W’ are the original supply of workers and wages. and are the new supply of workers and wages.

a %ΔES = 7, %ΔW = 3

b. ES = 120, W = $8

E’S = 90, W’ = $6

c. ES = 100, W = $5

E’S = 120, W’= $7

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Wind energy is converted to electrical energy using a device called a wind turbine.

Wind turbines are typically composed of three main parts: the rotor blades, the rotor hub, and the nacelle.

Here's a brief outline of the process:

1. Wind hits the rotor blades, causing them to spin. The rotor blades are shaped like airfoils, similar to airplane wings, and are designed to maximize the amount of energy that can be extracted from the wind.

2. The rotor blades are connected to the rotor hub, which is in turn connected to a shaft. As the rotor blades spin, they turn the shaft, which rotates a generator in the nacelle.

3. The generator uses the rotational energy from the shaft to produce electrical energy. The electrical energy is typically in the form of alternating current (AC) electricity.

4. The AC electricity from the generator is sent through a transformer, which increases the voltage of the electricity to make it suitable for transmission over long distances.

5. The electricity is then sent through power lines to homes and businesses, where it can be used to power electrical devices and appliances.

6. After the electricity has been used, it returns to the power grid and may be reused or stored for later use.

Overall, this process allows for the mechanical energy of the wind to be transformed into electrical energy, which can then be used to power homes and businesses.

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Answer: positive

Explanation:

Gravity can be defined as the force with which the body is attracted towards the center of the earth, or towards any other body. If the force acting on the body is in the direction of displacement then the word done by the applicable force is positive. This causes the free fall of the ball under the influence of gravity is also positive.

Given:

The initial speed of car is: u = 140 km/h = 140 × 5/18 m/s= 38.889 m/s

The final speed of the car is: v = 110 km/h = 110 × 5/18 m/s = 30.5556 m/s

The mass of the car is: m = 1565 kg

To find:

A) Initial kinetic energy of the car.

B) The final kinetic energy of the car.

C) Work done during the deceleration.

Explanation:

A) The initial kinetic energy of the car can be calculated as:

Substituting the values in the above equation, we get:

The value of initial kinetic energy is very close to the value 1183420 J given in the options. Thus, the initial kinetic energy of the car is 1183420 J.

B) The final kinetic energy of the car can be calculated as:

Substituting the values in the above equations, we get:

The value of final kinetic energy is very close to the value 730575 J given in the options. Thus, the final kinetic energy of the car is 730576 J.

C) The work done in the deceleration of the car is calculated by applying the work energy theorem. Thus, we get:

The work done in the deceleration of the car is -452845 J. The work done is negative because the car is decelerating.

Final answer:

A) The initial kinetic energy of the car is 1183420 J.

B) The final kinetic energy of the car is 730575 J.

C) The work done in decelerating the car is -452845 J.

Answer:

See the attachment above !!! Mark as brainliest ..!!

First we'll have to convert centimeter into meter.

\(\large\boxed{\bold{1 \: cm= 100 \: m}}\)

So we'll have to divide 2.3 cm by 100.

\(\frac{2.3}{100}\)

\(\bold{= 0.023 \: m}\)

Now, we can find the speed of the wave.\(\large \boxed{\bold{v= {f}{λ}}}\)

In this question all the values are given so we'll simply have to substitute and solve.

Let's solve!

To find the speed, we'll have to multiply the wavelength and frequency.

Substitute the values according to the formula.

\(v= 0.023\times 3.7\)

\(\large\boxed{\bold{v= 0.0851 \: m/s}}\)

Therefore, the speed of the given wave is 0.0851 m/s

The weight of the pail and sand necessary to start the pumpkin moving in this case is less than 11 N.

The force of friction acting on the pumpkin depends on the weight of the pumpkin and the coefficient of static friction.

F = μW

where;

The weight of the pumpkin is calculated as follows;

W = mg

where;

W = 1.8 kg  x  9.8 m/s²

W = 17.64 N

The static friction force preventing the pumpkin from moving is calculated as follows;

F = μW

F = 0.55 x 17.64 N

F = 9.7 N

Thus, the minimum force required to move the pumpkin is 9.7 N which is less than 11 N.

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The complete question is blow:

Suppose the coefficient of static friction is 0.55 rather than 0.61. is the weight of the pail and sand necessary to start the pumpkin moving in this case greater than, less than or equal to 11 N? calculate the required weight. mass of the pumpkin is 1.8 kg.

The models provide important tools for understanding the strong force interactions within a proton.

The strong force interactions between quarks and gluons within a proton are described by Quantum Chromodynamics (QCD), which is a fundamental theory of the strong nuclear force in particle physics. QCD is a non-Abelian gauge theory, meaning that the interactions between the quarks and gluons are highly nonlinear and non-perturbative.

One of the most promising theoretical models for describing the strong force interactions within a proton is lattice QCD, which is a numerical approach that uses a discrete grid to represent the space-time continuum. Lattice QCD allows for the calculation of QCD observables from first principles, without resorting to perturbative expansions. This method can handle non-perturbative effects such as confinement and chiral symmetry breaking by allowing for the simulation of the strong interactions on a discrete space-time grid

Another promising model is effective field theory, which provides a way to describe the low-energy behavior of QCD by constructing an effective Lagrangian that contains only the degrees of freedom relevant to a particular energy scale. This allows for the calculation of QCD observables in a systematic expansion in powers of a small parameter, such as the ratio of the quark mass to the QCD energy scale.

Chiral perturbation theory is another effective field theory that focuses on the dynamics of light quarks, which are the building blocks of pions, the lightest hadrons. Chiral perturbation theory provides a systematic expansion for the interactions between pions and nucleons, and can be used to calculate the properties of these particles at low energies.

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Explanation:

We know that momentum is the product of mass and velocity so

An object's mass times its velocity gives the object's momentum

Hope it will help :)

Explanation:

A rainbow is a meteorological phenomenon that is caused by reflection, refraction and dispersion of light in water droplets resulting in a spectrum of light appearing in the sky. It takes the form of a multicoloured circular arc. Rainbows caused by sunlight always appear in the section of sky directly opposite the sun.

Hope it helps You °_°

Answer:

the acceleration of the train is - 8 m/s² since it is decelerating as the influence of the brake comes to stop

Explanation:

Answer:

shreya Sister's answer is correct hope it's help you have a good day

Answer:

F_{total}= 8.25 \(\frac{G m^2}{L^2}\),      θ’= 194º

Explanation:

To solve this problem we must use the law of universal gravitation and vectorly add the forces

         F = \(G \frac{m_{1} m_{2} }{r^{2} }\)

Let us call the mass m with the subscript 1, the mass 3m with the subscript 3 and the mass 5m with the subscript 5, the total force on particle 1 is

          F_total = F₁₅ + F₁₃

The bold are vectors, in the attachment we can see a diagram of the angles and the forces, the distance between the masses is

           r = L

let's find the force between m1 and m5

           F₁₅ = G m₁ m₅ / r²

           F₁₅ = G m 5m / L²

           F₁₅ = G 5m² / L²

this force is on the line that joins the two masses, let's use trigonometry to decompose this force

           cos 30 = F₁₅ₓ / F₁₅

           sin 30 = \(\frac{Fx_{15y} }{F_{15} }\)

           F₁₅ₓ = F₁₅ cos 30

           \(F_{15y}\) = F₁₅ sin 30

equally with the force between mass 1 and mass 3

            F₁₃ = -G 3 m² / L²

            F₁₃ₓ = F₁₃ cos 30

            F_{13y} = F₁₃ sin 30

to find the total force we can add each component independently, see attached

X axis

           F_total x = -F₁₅ₓ + F₁₃ₓ

           F_total x = -G 5m2 / L² + G 3m² / L²

           F_total x = - G 2m² / L²

Y axis  

           F_total y = - F_{15y} - F_{13y}

           F_total y = - G 5m² / L² - G 3 m² / L²

           F_toal y = - G 8 m² / L²

We can give the result in two ways

1) F_total = - G m ^ 2 / L² (2 i ^ + 8 j ^)

2) in the form of module and angle.

Let's use the Pythagorean theorem

       \(F_{total}^{2} = F_{total x}^{2} + F_{total y}^2\)

       \(F_{total}\) = \(\frac{G m^{2} }{L^2} \sqrt{(2^2 + 8^2)}\)

       F_{total}= 8.25 \(\frac{G m^2}{L^2}\)

with trigonometry

        tan θ = \(\frac{F_{total y} }{F_{total x} }\)

        tan θ = 8/2

        θ = tan⁻¹ 4

        θ = 76º

if we measure this angle from the positive side of the x axis in a counterclockwise direction

       θ’= 270 -76

       θ’= 194º

If mass is oscillating on a frictionless surface at the end of a horizontal spring, then option B states that the acceleration of the mass is zero at x=0 everywhere.

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration. The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not always. An object that follows a circular path while maintaining a constant speed is still moving forward because the direction of its velocity is shifting. A point or object moving straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is constantly shifting.

Here,

When mass is oscillating on a frictionless surface at the end of a horizontal spring, the acceleration of the mass is zero at x=0, which is option B.

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Complete question is;

A force stretches a wire by 0.60 mm. A second wire of the same material has the same cross section and twice the length.

a) How far will it be stretched by the same force?

b) A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the same force?

Answer:

0.15 mm

Explanation:

According to Hooke's Law,

E = Stress(σ)/Strain(ε)

Where E is youngs modulus

Formula for stress is;

Stress(σ) = Force(F)/Area(A)

Formula for strain is;

Strain(ε) = Change in length/original length = (Lf - Li)/Li

We are also told that a second wire of the same material has the same cross section and twice the length.

Thus;

Rearranging Hooke's Law to get the constants on one side, we have;

F/(AE) = ε

Thus from the conditions given;

ε1 = 0.6/Li

ε2 = (Change in length)/(2*Li)

And ε1 = ε2

Thus;

0.6/Li = Change in length/(2*Li)

Li will cancel out and we now have;

Change in length = 2 × 0.6 = 1.2 mm

Finally, we are told A third wire of the same material has the same length and twice the diameter as the first.

Area of a circle;A1 = πd²/4

Now, we are told d is doubled.

Thus, new area of the new circle is;

A2 = π(2d)²/4 = πd²

Rearranging Hooke's Law,we have;

F/A = εE

Since F and E are now constants, we have;

F/E = constant = Aε

Thus;

A1(ε1) = A2(ε2)

A1 = πd²/4

e1 = 0.60/Li

A2 = πd²

e2 = Change in length/Li

Thus;

((πd²/4) × 0.6)/Li = (πd² × Change in length)/ Li

Rearranging, Li and πd² will cancel out to give;

0.6/4 = Change in length

Change in length = 0.15 mm

The following is not a source of outdoor air pollution : D) Household cleaning products.

Presence of one or more substances in air at concentration or for a duration above the natural level is called air pollution.

Outdoor air pollution refers to pollutants that are released into the atmosphere by sources outside of buildings or structures. The sources of outdoor air pollution can be natural or human-made. Some examples of sources of outdoor air pollution are:

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Solid fuel burning

E) Forest fires

Therefore, the correct option is D) Household cleaning products.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Household cleaning products.

The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.

The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.

When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.

To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.

20×1 = 15×d

d = 20/15

  =4/3 m

Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.

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Answer:

  T = 5.66 s

Explanation:

The system formed by the bar plus ball forms a physical pendulum

        w = \(\sqrt{mgd/I}\)

the moment of inertia of a rod held at one end is

       I = \(\frac{1}{3}\) m L²

we substitute

       w = \(\sqrt{\frac{d \ d}{ 3 L^2 } }\)

in this case the turning distance and the length of the rod are equal

        d = L

        w = \(\sqrt{\frac{g}{3L} }\)

angular velocity and period are related

       w = 2π / T

        2π / T = \(\sqrt{\frac{g}{3L} }\)

        T = 2π \(\sqrt{3L/g}\)

let's calculate

       T = 2π \(\sqrt{3 \ 2.65 / 9.8}\)

       T = 5.66 s

Answer:

C_d = 0.942

Explanation:

Let's first calculate the angle of inclination.

Formula is;

tan θ = (%slope)

% Slope is given as 12%

Thus;

θ = tan^(-1) (12/100)

θ = 6.843°

Let's now calculate the force due to the weight of the rider and bike combined from;

F = mg sin θ

We are given; m = 100 kg.

Thus;

F = 100 × 9.81 × sin 6.843

F = 116.885 N

The drag force will also be the same as the force due to the weight of the body. Thus;

Drag force; F = C_d(½ρu²A)

Where;

C_d is drag coefficient

ρ is density

U is terminal speed

A is area

We are given;

A = 0.9 m²

U = 15 m/s

From online tables, density of air is approximately 1.225 kg/m³

Thus;

116.885 = C_d(½ × 1.225 × 15² × 0.9)

116.885 = 124.03125C_d

C_d = 116.885/124.03125

C_d = 0.942

Answer:

sunspots looking dark

Answer:

a) mv(final):<0,0,0> minus mv(initial):<25,0,0> = <-25,0,0>

b) mv(final):<25,0,0> minus mv(initial):<0,0,0> = <25,0,0>

c) conservation of momentum makes it <0,0,0>

for a-b-c, momentum_system + momentum_surroundings = 0

Explanation:

Hope this helps

The velocity of each ball after the collision is 1.75 m/s

Law of conservation of momentum states that:

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = (m₁ + m₂)v

Where m₁, m₂ is the mass of object, u₁, u₂ is the initial velocity before collision and v is the final velocity after collision

Given that: m₁ = m₂ = 0.25 kg, u₁ = 3.5 m/s, u₂ = 0, hence:

0.25(3.5) + 0.25(0) = (0.25 + 0.25)v

v = 1.75 m/s

The velocity of each ball after the collision is 1.75 m/s

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The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.

The time taken for the hiker to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

t = √(2h/g)

t = √[(2 x 0.6) / (9.8)]

t = 0.35 seconds

The horizontal velocity of the hiker during the period of acceleration is calculated as follows;

Vₓ = at

Vₓ = (5.92 m/s²) x (1.2 s)

Vₓ = 7.104 m/s

The horizontal distance travelled during the time period of 0.35 seconds;

X = Vₓt

X = 7.104 x 0.35

X = 2.49 m

Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.

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Answer:

Most likely (B)

Explanation:

B in the passage is the most representative out of all your choices and it has evidence from the passage  

Hope dis helps Jit!

Sorry i forgot to type C

B and C both measure mass while the others are calculations and are bias

The following experimental set-ups would allow a student to calculate the magnitude of the gravitational field strength using only the quantities measured:

A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies.

When  a known mass from a spring scale is hung; by e; measuring the spring scale reading when the mass is at rest, the magnitude of the gravitational field strength ( reading/mass) can be calculated.

When  a heavy metal ball is dropped, by measuring e the drop height and the time it takes the ball to hit the ground, the magnitude of the gravitational field strength ( h = gt²/2) can be calculated. Hence, option (B) and option (D) is correct.

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Explanation:

Both because water can fall in holes and then freeze. However, water can also be chemically react with other elements and substances to wear something away.

We have that the overhang possible for the two bricks are is mathematically given as

x=13.5m

Length of Overhang

Question Parameters:

A uniform brick of length 18 m

a maximum overhang of 9 m attained

Length 18 m are stacked over the edge of a horizontal

surface.

Generally the equation that balances the moment    is mathematically given as

\(mg*(x-l/2)=mg(L-x)\\\\2x=3l/l\\\\x=3l/4\\\\x=3/4*18\\\\\)

x=13.5m

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