‼️Answer question and tell me how you got your answer‼️ ​

Answer:

0

Step-by-step explanation:

use the slope formula

\(m = \frac{y2 - y1}{x2 - x1} \)

(-5, 8); -5 is x1 and 8 is y1

(-11, 8); -11 is x2 and 8 is y2

Plugin the numbers and solve.

\(m = \frac{8 - 8}{ - 11 - - 5 } \\ \\ m = \frac{8 - 8}{ - 11 \ + 5} \\ \\ m = \frac{0}{ - 6} \\ \\ m = 0\)

Answer:

The answer is: B.

Step-by-step explanation:

They are prependicular

:)

Answer:

\(2\sqrt{3}+3\)

Step-by-step explanation:

\($\frac{3}{2 \sqrt 3 - 3}$\)

Rationalize the fraction.

\($\frac{3}{2 \sqrt 3 - 3}\cdot \frac{2 \sqrt 3 + 3}{2 \sqrt 3 + 3} =\frac{6\sqrt{3}+9 }{12-9} =\frac{6\sqrt{3}+9 }{3} =2\sqrt{3}+3 $\)

Note that I used the positive signal because we would have a difference of squares.

Answer:

\(320 \: {in}^{3} \)

Step-by-step explanation:

Given:

A rectangular prism

h (height) = 12 in

l (base length) = 10 in

w (base width) = 8 in

Find: V (volume) - ?

First, we have to find the area of the base:

\(a(base) = w \times l = 10 \times 8 = 80 \: {in}^{2} \)

Now, we can find the volume:

\(v = \frac{1}{3} \times a(base) \times h\)

\(v = \frac{1}{3} \times 80 \times 12 = 320 \: {in}^{3} \)

Answer:

V = 320

Step-by-step explanation:

The formula for the volume of a rectangular pyramid is length x width x height divided by 3 \((v =\frac{lwh}{3})\)

So

10 × 8 × 12 = 960

960 ÷ 3 = 320

Or

\(\frac{10*8*12}{3} = 320\)

The expression that gives the distance is \(\sqrt{(-3 - 6)^2 + (4 + 2)^2}\)

The points are given as:

(-3, 4) and (6, -2)

The distance between two points is calculated using:

\(d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\)

This gives

\(d = \sqrt{(-3 - 6)^2 + (4 + 2)^2}\)

Hence, the expression that gives the distance is \(\sqrt{(-3 - 6)^2 + (4 + 2)^2}\)

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Answer: y=3/2x+7

Step-by-step explanation:

To find the equation of the line that passes through the given point, let's first convert the given equation to slope-intercept form.

3x-2y=2           [subtract both sides by 3x]

-2y=-3x+2        [divide both sides by -2]

y=3/2x-1

Now that we have the equation in slope-intercept form, we know that the slope must stay the same because parallel lines NEVER touch. All we have to do is plug in the given point to find the y-intercept.

-2=3/2(-6)+b    [multiply]

-2=-9+b            [add both sides by 9]

b=7

Now, we know that the parallel equation is y=3/2x+7.

Answer:

\( \frac{23}{5} \)

Step-by-step explanation:

4 3/5

\( \frac{4 \times 5 + 3}{5} \)

\( \frac{20 + 3}{5} \)

= 23/5

The type of study design used in the scenario you provided is a retrospective cohort study. (option b).

In this study, the researcher selected a group of 14-year-old girls and looked back in time to compare their previous dietary habits and exposures between those who had already started having monthly periods and those who had not.

It is important to note that this study design has some limitations. For instance, the researcher is relying on self-reported data from the girls, which may not always be accurate.

This study design involves selecting a group of individuals and looking back in time to compare their exposures or characteristics between those who developed the outcome of interest and those who did not. By identifying potential risk factors, the researcher can gain insights into the onset of early menses in 14-year-old girls.

Hence the correct option is (b).

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Complete Question:

Which type of study design is used in the following scenario: A researcher interested in the onset of early menses compared 1,000 14-year-old girls, half of whom had already begun to have monthly periods and half of whom had not. The girls were interviewed regarding previous exposures. including their prior dietary habits.

a) Prospective cohort study

b) Retrospective cohort study

c) Case-control study

d) Clinical trial

e) None of the answers listed

When finding the slope of real-world situations, it is often referred to as rate of change. change in y Rate of change = change in x change in height change in time The average rate of change or a rider between 0 and 5 seconds is —24 ft/s. magnitude relation. Another synonym is "velocity".

Hope this helps

The classification of the compounds according to their functional class: A | Aldehyde

B | Alcohol

C | Ketone

D | Amine

Compound A contains a carbonyl group (C=O) bonded to two alkyl groups (R-). This is the general structure of an aldehyde. Aldehydes are characterized by their strong, sweet odor.

They are also very reactive, and can be used to make a variety of other compounds, such as esters and carboxylic acids.

Compound B contains an oxygen atom (O) bonded to two alkyl groups (R-). This is the general structure of an alcohol. Alcohols are characterized by their ability to dissolve other polar compounds, such as water. They are also used in a variety of products, such as solvents, cleaners, and fuels.

Compound C contains a carbonyl group (C=O) bonded to a propyl group (CH3CH2CH2-) and an amino group (NH2). This is the general structure of a ketone.

Ketones are characterized by their strong, sweet odor. They are also very reactive, and can be used to make a variety of other compounds, such as esters and carboxylic acids.

Compound D contains a nitrogen atom (N) bonded to three alkyl groups (R-). This is the general structure of an amine. Amines are characterized by their basic properties. They are also used in a variety of products, such as pharmaceuticals, plastics, and fertilizers.

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The largest area you can enclose with 20 meters of fencing against a long, straight wall is 50 square meters. Itcan be found using optimization methods.

Step 1: Define the variables
Let x be the length of the fencing parallel to the wall and y be the length of the fencing perpendicular to the wall.
Step 2: Set up the constraint equation
Since you have 20 meters of fencing, the sum of x and 2y (both sides perpendicular to the wall) should equal 20. The constraint equation is:x + 2y = 20
Step 3: Express one variable in terms of the other
Solve the constraint equation for one variable. In this case, solve for x: x = 20 - 2y

Step 4: Write the area function
The area of the rectangle can be expressed as A = xy. Substitute x from the previous step into this equation: A(y) = (20 - 2y)y.

Step 5: Find the critical points
Differentiate the area function with respect to y and set it to zero to find the critical points: dA/dy = 20 - 4y = 0, Solve for y:4y = 20, y = 5
Step 6: Find the corresponding value for x
Plug the value of y back into the equation for x: x = 20 - 2(5), x = 10

Step 7: Check for maximum area
The critical point we found (x=10, y=5) is indeed a maximum since the second derivative of the area function is negative.Step 8: State the largest area
The largest area you can enclose with 20 meters of fencing against a long, straight wall is A = xy = 10 * 5 = 50 square meters.

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The probability that the employee sold two hurricane policies or sold one hurricane policy is 15/17.

According to the statement

Number of employees who sold three hurricane policies is 2

Number of employees who sold two hurricane policies is 6

Number of employees who sold 1 hurricane policies is 9

SO,

The total number of employees is 2+6+9=17.

The number that sold two hurricane policies or sold one hurricane policy is 6+9=15,

so the Probability = Total number of policies sold / total number of employees

Probability = 15/17

So, The probability that the employee sold two hurricane policies or sold one hurricane policy is 15/17.

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The equivalent equation of the equation, \(\frac{5x+6}{2}=3-(4x+12)\) is 5x + 6 = -18 - 8x

Two equations are said to be equivalent when they have the same solution set.

Equivalent equations are algebraic equations that have identical solutions or roots.

Therefore, let's find the equivalent equation of the equation.

\(\frac{5x+6}{2}=3-(4x+12)\)

Let's open the bracket on the right side

\(\frac{5x+6}{2}=3-(4x+12)\)

\(\frac{5x+6}{2}=3 - 4x - 12\)

\(\frac{5x+6}{2}=(-9-4x)\)

cross multiply

5x + 6 = 2(-9 - 4x)

5x + 6 = -18 - 8x

5x + 8x = -18 - 6

13x = - 24

divide both sides by 13

x = - 24 / 13

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No, there is significant difference in the use of e readers by different age groups.

Given sample 1 ( 29 years old) \(n_{1}\)=628, \(p_{1}\)=7%, sample 2( 30 years old)\(n_{2}\)=2309, \(p_{2}\)=0.11.

We have to first form hypothesis one null hypothesis and other alternate hypothesis.

\(H_{0}:\)π1-π2=0

\(H_{1}:\)π1-π2≠0

α=0.05

Difference between proportions \(p_{1}-p_{2} =-0.04\)

\(p_{d}=0.07-0.11=-0.04\)

The pooled proportion needed to calculate standard error is:

\(p=(X_{1} -X_{2} )/(n_{1} +n_{2} )\)

=(44+254)/(628+2309)

=0.10146

The estimated standard error of difference between means is computed using the formula:

\(S_{p_{1} -p_{2} }=\sqrt{p(1-p)/m_{1}+p(1-p)/n_{2} }\)

=\(\sqrt{0.101*0.899/628+0.101*0.899/2309}\)

=\(\sqrt{0.000143+0.00003}\)

=\(\sqrt{0.000173}\)

=0.01315

Z= Pd-(π1-π2)/\(S_{p_{1} -p_{2} }\)

=-0.04-0/0.013

=-3.0769

This test is a two tailed test so the p value for this test is calculated as (using z table)

p value:2 P(Z<-3.0769)

=2*0.002092

=0.004189

P value< significance level of 5%.

Hence there is enough evidence to show the claim that there is a significant difference in the use of e readers by different age groups.

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Question is incomplete as it also includes:

Significance level of 5%.

The orthonormal basis U obtained through the Gram-Schmidt process for the given basis B = {V₁, V₂} is U = {(2/3, -1/3, 2/3), (9/√187, 5/√187, 19/√187)}. The vectors in U are mutually orthogonal and have unit length. This orthonormal basis U spans the same subspace as B but provides a more convenient and geometrically meaningful representation.

To perform the Gram-Schmidt process on the given basis B = {V₁, V₂}, where V₁ = (2, -1, 2) and V₂ = (1, 0, 3), we can:

1: Compute the first vector u₁:

u₁ = V₁ / ||V₁|| = (2, -1, 2) / √(2² + (-1)² + 2²) = (2, -1, 2) / 3

2: Compute the projection of V₂ onto u₁ and subtract it from V₂:

projₙ(V₂, u₁) = (V₂ · u₁) * u₁ = ((1, 0, 3) · (2, -1, 2)) * (2, -1, 2) / ||(2, -1, 2)||² = (5/3) * (2, -1, 2) / 9 = (10/9, -5/9, 10/9)

u₂ = V₂ - projₙ(V₂, u₁) = (1, 0, 3) - (10/9, -5/9, 10/9) = (9/9, 5/9, 19/9) = (1, 5/9, 19/9)

3: Normalize the vectors u₁ and u₂ to obtain an orthonormal basis:

uí = u₁ / ||u₁|| = (2/3, -1/3, 2/3)

u₂ = u₂ / ||u₂|| = (9/√187, 5/√187, 19/√187)

Therefore, the orthonormal basis U = {uí, u₂} is:

U = {(2/3, -1/3, 2/3), (9/√187, 5/√187, 19/√187)}.

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A random variable assigns one and only one numeric value to each experimental outcome.

A random variable used in experimental trials assign numerical values to the members or elements of the trial. This random variable is used to study the outcome of a trial conveniently.

A random variable assigns one and only one numeric value to each experimental outcome. This assigned numeric value may not be exact. In an experimental trial the possible outcomes are denoted by a random variable. So these values are just practically assigned and not theoretically exact.

There are discrete and continuous random variables. They are usually denoted by capital letters such as X, Y,.. etc. These random variables are used to calculate the probability of each outcome in a trial.

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Answer:

\(\frac{2}{9}\)

Step-by-step explanation:

We require to create 2 fractions with the repeating 2 after the decimal point.

let x = 0.22.... → (1) ← multiply both sides by 10

10x = 2.22....... → (2)

Subtract (1) from (2) thus eliminating the repeating decimal

9x = 2 ( divide both sides by 9 )

x = \(\frac{2}{9}\)

Thus

0.22..... = \(\frac{2}{9}\)

Answer:

2/9

Step-by-step explanation:

We require to create 2 fractions with the repeating 2 after the decimal point.

let x = 0.22.... → (1) ← multiply both sides by 10

10x = 2.22....... → (2)

Subtract (1) from (2) thus eliminating the repeating decimal

9x = 2 ( divide both sides by 9 )

x =

Thus

0.22..... =

With regard to a​ regression-based forecast, the standard error of the estimate gives a measure of option (C) the variability around the regression line

The standard error of the estimate in a regression-based forecast is a measure of the variability of the actual data points around the predicted values of the regression line.

It tells us how much the actual data points are likely to deviate from the predicted values, and provides a measure of the accuracy of the forecast. It is not related to the time required to derive the forecast equation, the maximum error of the forecast, or the time period for which the forecast is valid.

Therefore, the correct option is (C) The variability around the regression line.

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The give question is incomplete, the complete question is:

With regard to a​ regression-based forecast, the standard error of the estimate gives a measure of:

A. the time required to derive the forecast equation.

B. the maximum error of the forecast.

C. the variability around the regression line.

D. the time period for which the forecast is valid.

The quadratic equation that models the data is \(\(y = 0.04x^2 - 0.1x + 79.4\)\). According to this equation, the life expectancy of females born between 1995 and 2000 is approximately 80.3 years, and for those born between 2000 and 2005, it is approximately 80.5 years.

To find the quadratic equation, we can use the given data points and substitute the values into the equation \(\(y = ax^2 + bx + c\)\). Plugging in the point (0, 79.4), we get \(\(79.4 = a(0)^2 + b(0) + c\)\), which simplifies to \(\(c = 79.4\)\).

Next, plugging in the point (5, 80), we have \(\(80 = a(5)^2 + b(5) + 79.4\)\), which simplifies to \(\(25a + 5b = 0.6\)\) (equation 1).

Finally, substituting the point (10, 80.4), we get \(\(80.4 = a(10)^2 + b(10) + 79.4\)\), which simplifies to \(\(100a + 10b = 1\)\) (equation 2).

We now have a system of linear equations with two unknowns (a and b). Solving equations 1 and 2 simultaneously, we find \(\(a = 0.04\)\) and \(\(b = -0.1\)\).

Substituting these values back into the equation \(\(y = ax^2 + bx + c\)\), we obtain the quadratic equation \(\(y = 0.04x^2 - 0.1x + 79.4\)\).

To estimate the life expectancy of females born between 1995 and 2000, we substitute x = 15 into the equation: \(\(y = 0.04(15)^2 - 0.1(15) + 79.4\)\), which gives us approximately 80.3 years.

Similarly, for females born between 2000 and 2005, we substitute \(\(x = 20\)\) into the equation: \(\(y = 0.04(20)^2 - 0.1(20) + 79.4\)\), which gives us approximately 80.5 years.

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Answer:

Set two equations:

\(\left \{ {{x+y=50} \atop {\frac{x}{y}=\frac{7}{11} }} \right.\)

Rearrange one of the equations to find the value of a variable:

\(x+y=50\\x=50-y\)

Substitute in that value into the other equation:

\(\frac{50-y}{y}=\frac{7}{11}\)

Cross-multiply & solve for y:

\(7y=11(50-y) \\7y=550-11y\\7y+11y=550\\18y=550\\y=\frac{550}{18}=\frac{275}{9}\)

Substitute in the value to the original equation to find x:

\(\frac{x}{\frac{275}{9}}=\frac{7}{11} \\\frac{9x}{275}=\frac{7}{11} \\9(11)x=275(7)\\99x=1925\\x=\frac{1925}{99} =\frac{175}{9}\)

Therefore, the answer will be:

You can check your answers by:

\(\frac{175}{9} +\frac{275}{9} =\frac{450}{9} =50\)

\(\frac{\frac{175}{9} }{\frac{275}{9} } =\frac{175}{9} *\frac{9}{275} =\frac{175}{275}=\frac{7}{11}\)

Answer:

x = 175/9

y = 275/9

Step-by-step explanation:

Let the larger number be 'x' and smaller number be 'y'

sum of two numbers is 50.

x +y = 50 --------(I)

      x = 50 - y   -------------(II)

The larger number is divided by the smaller number we get 7/11.

\(\frac{x}{y}=\frac{7}{11}\\\\\)

Cross multiply,

11x = 7y

11x - 7y = 0 ------------(III)

Substitute x = 50 -y in equation (III)

11*(50-y) - 7y = 0  

11*50 - 11*y - 7y  = 0             {Distributive property}

550 - 11y - 7y = 0  

550 - 18 y = 0        {Combine like terms}

Subtract 550 from both sides

- 18y = -550

Divide both sides by (-18)

y = -550/-18

y = 275/9

substitute y = 275/9 in equation (III)

\(11x - 7*(\frac{275}{9})=0\\\\11x-\frac{1925}{9}=0\\\\11x =\frac{1925}{9}\\\\x=\frac{1925}{9*11}\\\\x=\frac{175}{9}\)

a. The mean, median and mode for this plot are 70.8, 70 and 60 respectively.

b. Mean best represents the data for this plot.

c. When there are outliers, the mean might be a deceptive center tendency measure.

Mean, Median, and Mode

Mean = Sum of prices / Total number of sunglasses

Mean = (20 + 20 + 50 + 50 + 50 + 60 + 60 + 60 + 60 + 60 + 60 + 70 + 70 + 70 + 80 + 80 + 80 + 80 + 90 + 90 + 90 + 90 + 100 + 100 + 130) / 25

Mean = 70.8

Median is equal to (n/2 + 1) when n is an odd number.

Here, the number of sunglasses is represented by n.

⇒ (25/2 + 1)th term is the median

Median = 13th term

Median = 70

Mode is the most frequent data from the plot.

⇒ Mode = 70

Mean Being the Best Central Measure

The mean is often the ideal measure of central tendency to use when your data distribution is continuous and symmetrical, such as when your data are normally distributed. So, mean here denotes the typical cost of the sunglasses.

Misleading Measure

When there are outliers, the data mean is significantly impacted. As a result, it may be inaccurate when examining the data's average price.

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let's solve :

2/5 of the class is male

40% of the class is male

3/5 of the class is female

60% of the class is female

Not sure if this is right, but this is what I got.

To find the consumer's and producer's surplus, we need more information about the demand and supply functions or the market equilibrium.

You provided the demand function D(x) = 25, but we require additional details to proceed with the calculations. The consumer's surplus is the difference between the maximum price consumers are willing to pay and the price they actually pay. It represents the benefit or surplus gained by consumers in a market transaction.

The producer's surplus is the difference between the minimum price producers are willing to accept and the price they actually receive. It represents the benefit or surplus gained by producers in a market transaction.

To calculate these surpluses, we typically need information about the supply function, equilibrium price, and equilibrium quantity. These values help determine the areas of the consumer's and producer's surpluses on the supply-demand graph.

Please provide the necessary information about the supply function, equilibrium price, or any other relevant details so that I can assist you in calculating the consumer's and producer's surplus accurately.

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The type of sampling that Huw is using is called Convenience Sampling.

Explanation:

Convenience sampling is a non-probability sampling technique where the sample is selected based on ease of access and availability. In Huw's case, he is administering the questionnaire to people who happen to be in the town centre, which is convenient for him. The sample is not selected randomly, and therefore does not accurately represent the population as a whole. Convenience sampling is often used in quick, informal surveys where the researcher does not have the resources or time to conduct a more rigorous, randomized sampling method.

The Laplace transforms of the given time domain functions are:

(a) E(s) = ω/(s + a)² + ω²   

(b) E(s) = s/(s + a)² + ω²   

(c) E(s) = 6/s⁴

The Laplace transform is a mathematical tool used to convert a function from the time domain to the complex frequency domain. The Laplace transform of a function f(t) is denoted by F(s), where s is the complex frequency variable.

(a) For the function e(-at)sin(ωt), we can use the Laplace transform property for the time-shifted sine function:

L{sin(ωt)} = ω/(s² + ω²)

Applying this property and taking into account the exponential decay factor, we get:

L{e(-at)sin(ωt)} = ω/(s + a)² + ω²

(b) For the function e(-at)cos(ωt), we can use a similar approach:

L{cos(ωt)} = s/(s² + ω²)

Applying this property and taking into account the exponential decay factor, we get:

L{e(-at)cos(ωt)} = s/(s + a)² + ω²

(c) For the function t³, we can use the Laplace transform property for the power of t:

L{tⁿ} = n!/(s(n+1))

Applying this property with n = 3, we get:

L{t³} = 6/s⁴

These are the Laplace transforms of the given time domain functions.

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Answer:

I may be wrong but I think it's c