A(n) ____ turns a figure a certain number of degrees around a point.

\(\qquad\qquad\qquad\boxed{\bf\:\:{(c) \: 31.4 \: cm \: ans \: }}\)

Explanation -:

The diameter is = 10 cm

( Take π = 3.14 )

\( \\ \: \tt :\implies \: 10 \: \times 3.14 \\ \\ 31.4 \: ans\)

More Information -:

Answer:

he would have to ride for 3 miles each of the six days left to meet his goal

Step-by-step explanation:

Answer: no the solution is (-1,-3)

Step-by-step explanation:

Step-by-step explanation:

step 1. a solution to a 2 variable system must work for both equations

step 2. y = 4x + 1, 3 = 4(-1) + 1, 3 = -4 + 1. no.

step 3. answer: no.

Answer:

im sorry i need the poonts have a good day

Answer:

A 2808

Step-by-step explanation:

From top to bottom

The top one is 9

Second layer is 16

Third is 23

Bottom is 30

I did 9 x 6, 16 x 6, 23 x 6, 30 x 6 = 54, 96, 138, 180

Added all of them up and got 468 then I times it by 6 and got 2808

Heyo! ;D

The volume of the sandcastle above is 10,596 cubic inches.

Hope this helped! If so, please lmk! Tysm and good luck!

Answer:

You don't like them

Step-by-step explanation:

definition: contemptuously  

ADVERB

contemptuously (adverb)

in a scornful way that shows disdain.

"he contemptuously dismisses his son's work"

The equation of the path of the parabola is y = a(x - 13)² + 27

Given data ,

To represent the path of Al's toss, we can assume that the path is a parabolic trajectory.

The equation of a parabola in vertex form is given by:

y = a(x - h)² + k

where (h, k) represents the vertex of the parabola

Now , the balloon was released from the 10-yard line and landed at the 16-yard line, we can determine the x-values for the vertex of the parabola.

The x-coordinate of the vertex is the average of the two x-values (10 and 16) where the balloon was released and landed:

h = (10 + 16) / 2 = 13

Since the height of the balloon reached 27 yards, we have the vertex point (13, 27)

Now, let's substitute the vertex coordinates (h, k) into the general equation:

y = a(x - 13)² + k

Substituting the vertex coordinates (13, 27)

y = a(x - 13)² + 27

To determine the value of 'a', we need another point on the parabolic path. Let's assume that the highest point reached by the balloon is the vertex (13, 27).

This means that the highest point (13, 27) lies on the parabola

Substituting the vertex coordinates (13, 27) into the equation

27 = a(13 - 13)² + 27

27 = a(0) + 27

27 = 27

Hence , the equation representing the path of Al's toss is y = a(x - 13)² + 27, where 'a' can be any real number

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Answer:

if you know why did you ask?

Step-by-step explanation:

Answer:

Blue

Hello there I hope you are having an great day :) If you select a marble without looking which colour are you less likely to pick, All together there is 10 marbles.

Orange : 2/10

Black : 2/10

Green : 5/10

Blue: 1/10

The less Colour is Blue as there is only 1 Marble so it probably the less likely to be picked.

Hopefully that helps you :)

Answer:

P(40) = 64, P(50) = 70, P(60) = 72,

P(70) = 70

60 minutes is correct.

Answer:

Distributive property

Step-by-step explanation:

Answer:

Distributive property

Step-by-step explanation:

Answer:

I believe it is 14.

Step-by-step explanation:

Answer: The value of x is 14°

Step-by-step explanation:

Since line m is parallel to n, then then the two given angles will have the same measures. Meaning that 136 degrees has to equation (9x+10).

Set them to equal each other and solve for x.

9x + 10 = 136

    - 10      -10

  9x  = 126

x=  14

Answer:

Simplifying

7 + -1(4p + 3) = -3(p + 2) + -1(2P + 3)

Reorder the terms:

7 + -1(3 + 4p) = -3(p + 2) + -1(2P + 3)

7 + (3 * -1 + 4p * -1) = -3(p + 2) + -1(2P + 3)

7 + (-3 + -4p) = -3(p + 2) + -1(2P + 3)

Combine like terms: 7 + -3 = 4

4 + -4p = -3(p + 2) + -1(2P + 3)

Reorder the terms:

4 + -4p = -3(2 + p) + -1(2P + 3)

4 + -4p = (2 * -3 + p * -3) + -1(2P + 3)

4 + -4p = (-6 + -3p) + -1(2P + 3)

Reorder the terms:

4 + -4p = -6 + -3p + -1(3 + 2P)

4 + -4p = -6 + -3p + (3 * -1 + 2P * -1)

4 + -4p = -6 + -3p + (-3 + -2P)

Reorder the terms:

4 + -4p = -6 + -3 + -2P + -3p

Combine like terms: -6 + -3 = -9

4 + -4p = -9 + -2P + -3p

Solving

4 + -4p = -9 + -2P + -3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '3p' to each side of the equation.

4 + -4p + 3p = -9 + -2P + -3p + 3p

Combine like terms: -4p + 3p = -1p

4 + -1p = -9 + -2P + -3p + 3p

Combine like terms: -3p + 3p = 0

4 + -1p = -9 + -2P + 0

4 + -1p = -9 + -2P

Add '-4' to each side of the equation.

4 + -4 + -1p = -9 + -4 + -2P

Combine like terms: 4 + -4 = 0

0 + -1p = -9 + -4 + -2P

-1p = -9 + -4 + -2P

Combine like terms: -9 + -4 = -13

-1p = -13 + -2P

Divide each side by '-1'.

p = 13 + 2P

Simplifying

p = 13 + 2P

Step-by-step explanation:

5x - y - 13 = 0  is the equation of the plane

To find the equation of the plane, we need two pieces of information: a point on the plane, and the normal vector of the plane.

We are given a point on the plane: P0(2, -3, -5).

To find the normal vector of the plane, we need to use the fact that the plane is perpendicular to the given line. The direction vector of the line is <1, 5, 0>, since the line has parametric equations x=2+t, y=-3+5t, z=-3, and the vector <1, 5, 0> is the coefficient vector of the parameter t in these equations.

Any vector that is perpendicular to <1, 5, 0> will be a normal vector of the plane. One such vector is <5, -1, 0>, which we can verify by taking the dot product of this vector with <1, 5, 0>:

<5, -1, 0> · <1, 5, 0> = 5(1) + (-1)(5) + 0(0) = 0

Thus, the normal vector of the plane is <5, -1, 0>.

Now we can use the point-normal form of the equation of a plane:

ax + by + cz = d

where <a, b, c> is the normal vector of the plane, and (x, y, z) is any point on the plane. Substituting in the values we have:

5(x - 2) - 1(y + 3) + 0(z + 5) = 0

Simplifying:

So the equation of the plane is:

5x - y - 13 = 0

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The area of the figure is given as follows:

100.56 mm².

The figure in this problem is composed as follows:

The areas for each region are given as follows:

Hence the total area is of:

48 + 14 + 20 + 6 + 12.56 = 100.56 mm².

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A homogeneous system in parametric vector form:

(x1,x2,x3) = (s,s,-0.25s)

Parametric vector Form:

Any equation expressed as a parameter is a parametric equation. The general equation y = mx + b (where m and b are parameters) of a straight line in the form of a slope intersection is an example of a parametric equation. Example: one of the variables to t(x = t). Then we can rewrite this equation as y = t²+5.

So the set of parametric equations is x = t and y=t²+5.

According to the Question:

We are to solve them in parametric form.

X₁ + 2X₂ + 12X₃ = 0     ----------------------- (1)

2X₁ + X₂ + 12X₃ = 0     ----------------------- (2)

-X₁ + X₂ = 0                  ----------------------- (3)

From equation 3 we get

x₁ = x₂

Substitute in 1 and 2 to get

3x₁ + 12x₃ = 0 and

3x₁ + 12x₃ = 0

Thus, we find these two equations are dependent.  So we can have infinite solutions in parametric form only.

No unique solution is possible

Let x₁ = x₂ = s

Since 3x₁ +12x₃ = 0

x₁ = -4x₃

Or x₃ = -0.25s

So solution in parametric form is

(x1,x2,x3) = (s,s,-0.25s) for all real values.

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Step-by-step explanation:

given ponts,

(3,0)=(x1,y1)

(-6,-3)=(x2,y2)

we know,

Eqn of any line joining two points be,

(y-y1)={(y2-y1)/(x2-x1)}*(x-x1)

y-0={(-3-0)/(-6-3)}*(x-3)

y=(1/3)*(x-3)

y=(x-3)/3

3y=x-3

0=x-3y-3

x-3y-3=0

Therefore it is required eqn

Answer:

To find how much money they shared first find the total parts

Which is

5 + 7 + 8 = 20

Deila's share is

5 /20 × £1600

= 1/4 × £1600 = £ 400

Edwin's share is

7/ 20 ×£1600 = £560

Freya's share is

8/20 × £1600

= 2/5 × £1600 = £640

Hope this helps you

Answer:

£ 40,000

Step-by-step explanation:

Given that:

Freya receives 8 parts of the total amount

8 parts = £1600

this means, we can calculate 1 part:

8 parts  = £1600

1 part =£1600/8 = £ 2000

Now, we are able to calculate the total share :

Total number of parts = 8 + 5 + 7 = 20

1 share = £2000

So, 20 shares = £40000

hope this helps,

Good Luck

Please mark brainiest

The correct answer is (4) All of the above (1, 2, and 3).

When using ANOVA to evaluate models, among the important considerations are:

The ANOVA table is not the fitted model itself but rather an attempt to partition credit for the model's predictive power across the different variables,

Interpreting the ANOVA table requires more subtlety when there is correlation among model predictors, and there can only be one correct ANOVA table for any given model in the context of an observational study.

Hence, the correct answer is (4) All of the above (1, 2, and 3).

ANOVA, short for Analysis of Variance, is a statistical method for comparing the means of two or more groups. It is utilized to compare whether there are any statistically significant differences between the group means.

The ANOVA table is not the fitted model itself but rather an attempt to partition credit for the model's predictive power across the different variables. Interpreting the ANOVA table requires more subtlety when there is correlation among model predictors.

There can only be one correct ANOVA table for any given model in the context of an observational study.

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The y-coordinate of point C is -12, and the value of sinθ is -12/13.

We can begin by using the Pythagorean theorem to find the y-coordinate of point C.

Since the circle has a radius of 13 units, we know that the distance from the origin to point C is also 13 units. We can use the x-coordinate of point C to find the length of the horizontal leg of the right triangle formed by the origin, point C, and the x-axis.

The length of this leg is equal to the absolute value of the x-coordinate, so in this case it is 5 units. To find the length of the vertical leg, we can use the Pythagorean theorem:

y² + 5² = 13²

y² = 13² - 5²

y² = 144

y = ±12

Since point C is in quadrant II, the y-coordinate is positive. Therefore, the y-coordinate of point C is 12.

To find the value of sin(θ), we can use the fact that sin(θ) = opposite/hypotenuse. In this case, the opposite side is the y-coordinate of point C (which is 12), and the hypotenuse is the radius of the circle (which is 13).

So, sin(θ) = 12/13.

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The statement "Double integrals  can only be calculated on rectangular domains" is false. Double integrals can be calculated on various types of domains, not limited to rectangular ones. The concept of double integration extends to more general regions, including non-rectangular domains, such as circles, triangles, and irregular shapes.

Double integrals are used to calculate the signed volume or area under a surface or over a region in two-dimensional space. While rectangular domains are often used for simplicity and ease of computation, they are not the only type of domain on which double integrals can be applied. In fact, double integrals can be evaluated on a wide range of regions as long as they satisfy certain conditions. These conditions include being bounded, connected, and having a well-defined boundary. The region can be defined by any shape, including circles, triangles, ellipses, polygons, or irregular curves. To calculate a double integral over a non-rectangular domain, appropriate coordinate transformations or changes of variables may be required. These transformations help to map the non-rectangular domain onto a rectangular one, allowing for the application of standard integration techniques. In conclusion, while rectangular domains are commonly used in double integrals, they are not the only option. Double integrals can be computed on a variety of domains, enabling the evaluation of integrals over non-rectangular regions.

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The answer of 21 tracks is accurate since, once the membership cost has been paid, the store charges $1.50 by each song. Since the monthly charge is a one-time expense, it is deducted from the $50 price cap.

The characteristic that every input is associated to approximately one output defines a function as a relationship between a series of inputs but a set of allowable outputs. A mapping from Here to there B will only be a function if every piece in set A has one end and only the image in set B. Let A & B have been any two non-empty sets.

The number of songs that may be downloaded with the specified budget is then calculated by dividing the remaining balance by the price of each song. The outcome is an analytic sequence because each song's price is set. The outcome is then rounded down to the closest whole number, which in this example is 21.

1. Take the $50 budget and deduct the $18 membership fee:

$50 - $18 = $32

2. Take the leftover amount and divide it by the price of each song:

$32 ÷ $1.50 = 21.33

3. To the nearest full number, round down:

21 songs

As a result, you may purchase 21 tracks for $50.

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Answer:

SAS

Step-by-step explanation:

the lines in the middle of a segment mean that they are equal in length.

So OE = EB and AE = EC.

Now, since angle AEB and angle DEC are vertical angles, they are equal.

Therefore the triangles are equal by SAS

Answer:

X= - 3

Step-by-step explanation:

Multiply both sides by 2 to remove the division on the LHS

3X - 15=8X

Move 3X to the RHS

-15 =8X - 3X

-15= 5X

Divide both sides by 5

-3 =X

\(\boxed{c.\:x\:=\:-3}\) ✅

\(\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}\)

\( \frac{3x - 15}{2} = 4x \\ ⇢ 3x - 15 = 4x \times 2 \\ ⇢ 3x - 15 = 8x \\ ⇢ 3x - 8x = 15 \\ ⇢  - 5x = 15 \\ ⇢ x = \frac{15}{ - 5} \\ ⇢ x = - 3\)

\({ \bf{ \underbrace{To\:verify :}}}\)

\( \frac{3x - 15}{2} = 4x \\ ⇢  \frac{3 \times (- 3) - 15 }{2} = 4 \times - 3 \\ ⇢  \frac{ - 9 - 15}{2} = - 12 \\ ⇢  \frac{ - 24}{2} = - 12 \\ ⇢  - 12 = - 12 \\ ⇢ L.H.S.=R. H. S\)

Hence verified.

\(\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}\)

Given that Angles A and B are complementary to each other, the numerical value of x is 15.

Complementary angles are angles that sum up to 90 degrees.

Given the data in the question;

Since Angles A and B are complementary to each other, the sum of angle A and B is 90 degrees.

Measure of angle A + Measure of angle B = 90°

Plug in the given values and solve for x.

41 + (2x + 19) = 90

41 + 2x + 19 = 90

2x + 60 = 90

2x = 90 - 60

2x = 30

x = 30/2

x = 15

Given that Angles A and B are complementary to each other, the numerical value of x is 15.

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Answer: A is the answer

Step-by-step explanation: i took the test and got it right

Answer:

70°

Step-by-step explanation:

Since m∠JKH and m∠LKM are verticle angles, they are equal to each other.

The derivate of a function f(x) is determinated as:

For the function

First we have to determine de f ( x + h ) as follow:

Then we calculate and simplify the coeficient in the first formula

------------------------------------------------------------------------------------The equation of the tangent:

First you need to know that the derivate of a function is equal to the slope (m) of the tangent of this function

And the equation to thist tangent in a specific point will be find using the next formula:

We have to calculate the slope in the point x =4 using the derivate:

In the point x=4

Calculate the value of f(x0) substituting in the function the given point x:

Knowing that we put the value of m and f(x0) in the equation of the tangent:

---------------------------------------------------------------------------

The normal line

The slope of the normal line is the opposite of the slope of theu tangent in an espesific point:

So in this situation is:

The equation of the normal line is given by the next formula:

Replacing the data we obtain:

If G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure (indistinguishable encryptions in the presence of an eavesdropper).

Let's assume that G is not a PRG. This means that there exists some efficient algorithm D that can distinguish the output of G from random strings with non-negligible advantage. We will use this assumption to construct an adversary A that can break the EAV-security of Construction 3.17.

The adversary A works as follows:

1. A receives a security parameter n.

2. A runs the key generation algorithm Gen and obtains the key k.

3. A chooses two distinct messages m0 and m1 of length ℓ(n).

4. A computes the ciphertexts c0 = G(k) ⊕ m0 and c1 = G(k) ⊕ m1.

5. A chooses a random bit b and sends cb to the challenger.

6. The challenger encrypts cb using the encryption algorithm Enc with key k and obtains the ciphertext c*.

7. A receives c* and outputs b' = D(G(k) ⊕ c*).

8. If b = b', A outputs 1; otherwise, it outputs 0.

We analyze the probability that A can distinguish between encryptions of messages m0 and m1. Since G is not a PRG, D has a non-negligible advantage in distinguishing G's output from random strings. Therefore, there exists a non-negligible function negl such that:

|Pr[D(G(k)) = 1] - Pr[D(U) = 1]| ≥ negl(n),

where U denotes a truly random string of length ℓ(n).

Now, consider the probability of A winning the PrivK game:

Pr[PrivK_A,Π

eav

(n) = 1] = Pr[b = b']

           = Pr[D(G(k) ⊕ c*) = D(G(k))]

           = Pr[D(G(k)) = 1]

           ≥ Pr[D(U) = 1] - negl(n).

Since negl(n) is non-negligible, we have:

Pr[PrivK_A,Π

eav

(n) = 1] ≥ 2^(-1) + negl(n).

Thus, if G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

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To find the limit of ln(5x)/√5x as x approaches infinity, we can use l'Hospital's Rule since it is an indeterminate form of ∞/∞.

Taking the derivative of the numerator and denominator separately, we get: lim [(1/5x) / (1/2√5x)] x→[infinity]

Simplifying this expression, we get: lim 2/5√5x x→[infinity]

Since the denominator approaches infinity as x approaches infinity, the limit is equal to 0.

Therefore: lim ln(5x)/√5x = 0 x→[infinity]

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The Area of Trapezium is 50, 267 mm².

We have,

base 1 = 224 mm

base 2 = 77 mm

Height = 334 mm

Now, Area of Trapezium

= 1/2 (Sum of parallel side) x height

= 1/2 (224 + 77) x 334

= 1/2 x 301 x 334

= 50, 267 mm²

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