A sprinkler can water between 1 and 130 square yards of a lawn. The length L in inches of rotating pipe needed to water A square yards is given by the function L=119.75 square root of A. How much area can be watered if the length of the pipe is 600, 900, or 1,000 inches long?

The income you need to afford a $425,000 house is largely dependent on your debt-to-income ratio, credit score, and down payment. However, a general rule of thumb is to have an annual income that is at least three times the purchase price of the home, which in this case would be $1,275,000.

To more accurately determine the income needed to afford a $425,000 house, consider factors such as the interest rate on the mortgage, property taxes, homeowners insurance, and any homeowner association fees.

These additional expenses can significantly impact your monthly mortgage payment and thus your income requirements.
It's important to keep in mind that lenders have varying criteria when determining mortgage eligibility and income requirements, so it's best to speak with a mortgage professional to get a more accurate estimate based on your individual circumstances.

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We can simplify the expression to get:

2*(b + b²)

Here we want to simplify the following expression:

b + 3b² + b - b²

We can reorder that expression in the following way.

b + b + 3b² - b²

And now group like terms, we will get:

b + b + 3b² - b²

2b + (3 - 1)* b²

2b + 2b²

Now we can take 2 as a common factor to get:

2*(b + b²)

That is the expresion simplfied.

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Answer:

the answer is (a) 28.

Step-by-step explanation:

The given situation can be represented by a linear equation of the form:

Cost = mx + b

where "m" is the slope (the rate of change of cost with respect to time), "x" is the number of hours of the tour, and "b" is the y-intercept (the cost when x = 0).

In this case, the y-intercept is $60, which represents the one-time fee. The cost increases by $28 per hour, so the slope is:

m = $28/hour

Therefore, the answer is (a) 28.

The purchase price of a 5-year zero coupon bond will be $768.87.

The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol ‘%’ is used to symbolize it.

Let x be the price before 5 years.

If it is purchased today and has a face value of $1,000. Then we have

(1 + 0.046)(1 + 0.049)(1 + 0.052)(1 + 0.055)(1 + 0.068) x = 1000

(1.046 × 1.049 × 1.052 × 1.055 × 1.068) x = 1000

1.3 x = 1000

x = $768.87

The purchase price of a 5-year zero coupon bond will be $768.87.

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Answer:

5 gallons

Step-by-step explanation:

If she can do 1/10 gallon per seconds, that means she can do 5/50.

You can write it as this ratio:

1/10 = x/50.

You know that 10 * 5 = 50.

Since it is a constant ratio, it has to be 1 * 5 = x

Since 1 * 5 = 5, Tiffany can fill the pool 5 gallons per 50 seconds.

Answer:

\(\dfrac{27}8\)

Step-by-step explanation:

\(= \left(\dfrac{32}{243} \right)^{-\tfrac 35}\\\\\\= \left(\dfrac{2^5}{3^5} \right)^{-\tfrac 35}\\\\\\=\left(\dfrac 23 \right)^{-\tfrac{3\times 5}5 \right)\\\\\\=\left(\dfrac 23 \right)^{-3}\\\\\\=\dfrac{3^3}{2^3}\\\\\\=\dfrac{27}8\)

The difference in value between the two accounts after 8 years is approximately £18.01, with the Central Alliance Bank (CAB) account having a higher value.

For Central Alliance Bank (CAB) with simple interest, the formula to calculate the final amount (A) is:

A = P * (1 + r*t)

Let's calculate the final amounts for each account after 8 years:

Northern Savings Bank (NSB):

P = £6400

r = 2.5% = 0.025 (as a decimal)

n = 1 (compounded annually)

t = 8

A_NSB = £6400 * (1 + 0.025/1)^(1*8)

= £6400 * (1 + 0.025)⁸

= £6400 * (1.025)⁸

= £6400 * 1.20973297

≈ £7758.39

Central Alliance Bank (CAB):

P = £6400

r = 2.7% = 0.027 (as a decimal)

t = 8

A_CAB = £6400 * (1 + 0.027 * 8)

= £6400 * (1 + 0.216)

= £6400 * 1.216

≈ £7776.40

The difference in value between the two accounts after 8 years is:

Difference = A_CAB - A_NSB

= £7776.40 - £7758.39

≈ £18.01

Therefore, the difference in value between the two accounts after 8 years is approximately £18.01, with the Central Alliance Bank (CAB) account having a higher value.

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Answer:

144?

Step-by-step explanation:

1+3+5+7+9+11 blah blah blah...

1+3+5+7+9+11+13+15+17+19+21+23 which gives 144.

Answer:

664 ft²

Step-by-step explanation:

The rectangular yard has dimensions 36 ft by 55 ft.

The area of the yard is 36 ft × 55 ft = 1980 ft²

The walkway inside the fence is 4 ft wide. The area inside the walkway has dimensions

36 ft - 2 × 4 ft = 28 ft

55 ft - 2 × 4 ft = 47 ft

The area of the rectangle inside the walkway is 28 ft × 47 ft = 1316 ft²

The area of the walkway is the difference between the total area enclosed by the fence and the rectangle inside the walkway.

area of walkway = 1980 ft² - 1316 ft² = 664 ft²

Answer:

Step-by-step explanation:

720

Answer:

i dont know

Step-by-step explanation:

hi

The Area of the composite figure = area of the rectangle + area of the triangle = 148.5 cm².

The figure formed by the arrow can be decomposed into a rectangle and a triangle.

The area of the composite figure = area of the rectangle + area of the triangle.

Find the area of the rectangle:

Length = 12 cm

Width = 11 cm

Area of the rectangle = (length)(width) = (12)(11)

Area of the rectangle = 132 cm²

Find the area of the triangle

Base = 11 cm

Height = 15 - 12 = 3 cm

Area of the triangle = 1/2(b)(h) = 1/2(11)(3)

Area of the triangle = 16.5 cm²

Area of the composite figure = area of the rectangle + area of the triangle = 132 + 16.5 = 148.5 cm².

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Performing a Chi-Square test is a statistical tool used to determine if there is a significant difference between observed and expected data. The test helps to analyze categorical data by comparing observed frequencies to the expected frequencies. The p-value in a Chi-Square test refers to the probability of obtaining the observed results by chance alone.

If a p-value lower than 0.01 is obtained in a Chi-Square test, it means that the results are statistically significant. In other words, there is strong evidence to reject the null hypothesis, which states that there is no significant difference between the observed and expected data. This means that the observed data is not due to chance alone, but rather to some other factor or factors.

The mean, or average, is not directly related to the Chi-Square test or the p-value. The Chi-Square test is specifically used to determine the significance of the observed data. However, the mean can be used as a measure of central tendency for continuous data, but it is not applicable to categorical data.

In conclusion, obtaining a p-value lower than 0.01 in a Chi-Square test means that there is strong evidence to reject the null hypothesis, and that the observed data is statistically significant.

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The type of sampling which Mr.Stratford using is Cluster Sampling.

Cluster sampling is the method of sampling that involves dividing a population into groups, or clusters, and selecting a random sample of the groups. This method is used when it is not possible or practical to obtain a complete list of the population. For example, cluster sampling may be used to select a sample of schools from a list of all schools in a country.

There are three types of cluster sampling:

Single-stage

Double-stage

Multi-stage

This type of sampling is used when it is difficult or impossible to obtain a complete list of the population of interest. In these cases, cluster sampling may be the only practical option.

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Answer:

x = 10, x = 0

I dont know if you wanted an answer but yeah-

A Turing machine can be drawn to compute the function f(x, y) = x + 2y, where x and y are positive integers. we need to design the machine to perform the necessary operations.

To draw a Turing machine that computes the function f(x, y) = x + 2y, we need to design the machine to perform the necessary operations. Here's a high-level explanation of the Turing machine:

Input: The input to the Turing machine consists of two positive integers x and y.

Initialization: The machine initializes its state and the tape with the values of x and y.

Addition: The machine performs the addition operation by repeatedly decrementing y by 1 and incrementing x by 1 until y reaches 0. This step effectively adds 1 to x for every 2 decrements of y.

Output: Once y becomes 0, the machine halts and outputs the final value of x, which represents the result of f(x, y).

The drawn Turing machine would include states, transitions, and symbols on the tape to represent the operations and computations described above. The exact representation would depend on the specific conventions and notation used for drawing Turing machines.

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A Turing machine can be drawn to compute the function f(x, y) = x + 2y, where x and y are positive integers. we need to design the machine to perform the necessary operations.

To draw a Turing machine that computes the function f(x, y) = x + 2y, we need to design the machine to perform the necessary operations. Here's a high-level explanation of the Turing machine:

Input: The input to the Turing machine consists of two positive integers x and y.

Initialization: The machine initializes its state and the tape with the values of x and y.

Addition: The machine performs the addition operation by repeatedly decrementing y by 1 and incrementing x by 1 until y reaches 0. This step effectively adds 1 to x for every 2 decrements of y.

Output: Once y becomes 0, the machine halts and outputs the final value of x, which represents the result of f(x, y).

The drawn Turing machine would include states, transitions, and symbols on the tape to represent the operations and computations described above. The exact representation would depend on the specific conventions and notation used for drawing Turing machines.

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Answer:

4 ^ 9

Step-by-step explanation:

4 ^ 3 * 4 ^ 6

when multiplying with same base and different exponents, add the exponents.

(4)^ 3 + 6

= 4 ^ 9

The Normal model is a good approximation for the sampling distribution.

a) According to the Central Limit Theorem, the theoretical mean and standard deviation for a sample size of 20 should be 0.05 and 0.02, respectively. For a sample size of 100, the theoretical mean and standard deviation should be 0.05 and 0.01, respectively.

b) The observed mean and standard deviation for a sample size of 20 was 0.052 and 0.021, respectively. For a sample size of 100, the observed mean and standard deviation was 0.051 and 0.012, respectively. These values are fairly close to the theoretical values.

c) Looking at the histograms in Exercise 1, I would be comfortable using the Normal model as an approximation for the sampling distribution at a sample size of 100.

d) The Success/Failure Condition states that the sample size should be large enough for the sampling distribution of the sample proportions to be approximately normal. Since I chose a sample size of 100, which satisfied the condition, I can be confident that the Normal model is a good approximation for the sampling distribution.

The sample size of 100 is large enough for the sampling distribution of the sample proportions to be approximately normal, and the observed mean and standard deviation is close to the theoretical values. Therefore, the Normal model is a good approximation for the sampling distribution.

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Answer: B. Niche

Explanation:

Definition of niche: a niche is the match of a species to a specific environmental condition. It describes how an organism or population responds to the distribution of resources and competitors and how it in turn alters those same factors.

Answer: Niche

Niche is basically like a type of place of something or someone

Answer:

216.

Step-by-step explanation:

Answer:

216 Bottles

Step-by-step explanation:

A cross-sectional effect diagram, also known as an axial force-shear force-bending moment diagram or simply an internal force diagram, is a graphical representation that shows the distribution of internal forces (axial force, shear force, and bending moment) along the length of a structural member, such as a beam or column.

To draw the cross-sectional effect diagrams for the beam whose loading condition is given in the figure, we need to follow these steps:

Step 1: Identify the type of loadingFor this question, the loading conditions are {N}, {T}, {M}. So, the loading types are axial force, shear force, and bending moment.

Step 2: Draw the cross-sectional diagram of the beam. We need to draw the diagram of the cross-section of the beam in the direction of the forces acting on the beam. In this case, it will be a rectangular beam.

Step 3: Draw the effect diagrams After drawing the cross-sectional diagram, we need to draw the effect diagrams for each loading condition.

The effect diagrams are as follows: 1. Axial force diagram (N):In this case, the axial force is positive (+) which means it is a tensile force. 2. Shear force diagram (T):The shear force is negative (-) from x = 0 to x = 1, which means the shear force is acting downward. It is zero at x = 1 and then becomes positive (+) from x = 1 to x = 2, which means the shear force is acting upward. 3. Bending moment diagram (M):The bending moment is zero at x = 0, becomes negative (-) from x = 0 to x = 1, reaches a minimum at x = 1, and then becomes positive (+) from x = 1 to x = 2.

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Answer:

4x^{3} ÷ 8 = x^{3}/2

(15y+x)^2

That’s your answer. I hope i helped!

Even numbers between 10 to 18 are 5

Total stockholders’ equity 7,800,000

Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000

Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000

Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000

Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000

To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.

The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.

Calculations:Opening balance of common stock = $100,000

Opening balance of additional paid-in capital = $4,100,000

Opening balance of retained earnings = $3,000,000

Net Income for the year ended December 31, 2012 = $800,000

Retained earnings (Opening Balance) = $3,000,000

Add: Net Income for the year ended December 31, 2012 = $800,000

Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000

Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000

Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000

Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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A 11.544 acre-feet of this ice field will melt from the beginning of day 1 (t = 0) to the beginning of day 4 (t = 3). So, correct option is C.

To solve the problem, we need to integrate the given rate of melting with respect to time over the interval [0,3] to find the total amount of ice that melts during this time.

First, we can simplify the given rate of melting by using the identity: sin³(t) = (3sin(t) - sin(3t))/4

So, M(t) = 4 - (3sin(t) - sin(3t))/4 = 16/4 - 3sin(t)/4 + sin(3t)/4 = 4 - 0.75sin(t) + 0.25sin(3t)

Integrating this expression with respect to t over the interval [0,3], we get:

\(\int\limits^3_0\) M(t) dt = \(\int\limits^3_0\) (4 - 0.75sin(t) + 0.25sin(3t)) dt

= [4t + 0.75cos(t) - (1/3)cos(3t)]|[0,3]

= (12 + 0.75cos(3) - (1/3)cos(9)) - (0 + 0.75cos(0) - (1/3)cos(0))

= 11.544

Therefore, the answer is (C) 11.544.

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The absolute maximum value is ln(18), and the absolute minimum value is ln(1/4).

The absolute maximum and absolute minimum values of f on the interval [-2, 1] for the function f(x) = ln(x^2 - 3x + 8) can be determined by analyzing the critical points and endpoints.

To find the critical points, we need to take the derivative of f(x) and set it equal to zero. Let's calculate the derivative of f(x) first:

f'(x) = (2x - 3) / (x^2 - 3x + 8)

To find the critical points, we set f'(x) = 0 and solve for x:

(2x - 3) / (x^2 - 3x + 8) = 0

Since the numerator can only be zero when 2x - 3 = 0, we have:

2x - 3 = 0

2x = 3

x = 3/2

Now we need to check the endpoints of the interval, which are x = -2 and x = 1.

To determine whether the critical point and the endpoints are relative maximum or minimum values, we evaluate f(x) at these points. However, before doing that, we need to check if f(x) is defined and continuous on the interval [-2, 1]. Since ln(x) is defined only for positive values of x, we need to ensure that x^2 - 3x + 8 > 0.

The discriminant of the quadratic equation x^2 - 3x + 8 is:

D = (-3)^2 - 4(1)(8) = 9 - 32 = -23

Since the discriminant is negative, x^2 - 3x + 8 is always positive. Therefore, f(x) is defined and continuous on the interval [-2, 1].

Now, let's evaluate f(x) at the critical point and the endpoints:

f(-2) = ln((-2)^2 - 3(-2) + 8) = ln(4 + 6 + 8) = ln(18)

f(1) = ln(1^2 - 3(1) + 8) = ln(1 - 3 + 8) = ln(6)

f(3/2) = ln((3/2)^2 - 3(3/2) + 8) = ln(9/4 - 9/2 + 8) = ln(1/4)

After evaluating these values, we can conclude the following:

- The maximum value of f(x) on the interval [-2, 1] is ln(18), which occurs at x = -2.

- The minimum value of f(x) on the interval [-2, 1] is ln(1/4), which occurs at x = 3/2.

Therefore, the absolute maximum value is ln(18), and the absolute minimum value is ln(1/4).

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Answer:

About 3.41 inches per year

Step-by-step explanation:

2 cm per 12 week

52 weeks in a year

52/12 = about 4.33

2 cm * 4.33 =  about 8.67 cm

2.54 cm = 1 inch

8.67/2.54 = about 3.41 inches per year

Hope this helps!

(pls mark brainliest)

The surface area of the complex shape in the image shown is calculated as: 508 ft².

To Find the Surface Area of the Complex Shape, decompose the shape into two rectangular prism.

Rectangular prism 1 dimensions would be:

Length = 12 ft

Width = 5 ft

Height = 7 ft

Surface area (SA) = 2(wl + hl + hw)

= 2·(5·12 + 7·12 + 7·5) = 358 ft²

Rectangular prism 2 dimensions would be:

Length = 12 - 7 = 5 ft

Width = 5 ft

Height = 12 - 7 = 5 ft

Surface area (SA) = 2(wl + hl + hw)

= 2·(5·5 + 5·5 + 5·5) = 150 ft²

Therefore, surface area of the complex shape = 358 + 150 = 508 ft².

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Answer:

25.37

Step-by-step explanation:

Write a function:

f(t)=840e^{rt}

f(t)=840e

rt

Continuously uses Pe^(rt)

-0.05

r: decays 5%→−0.05

per day

f(t)=840e^{-0.05t}

f(t)=840e

−0.05t

(where t is in days)

10 weeks→10⋅7→70 days

There are 7 days in a week

Plug in t=70

f(70)=840e^{-0.05(70)}

f(70)=840e

−0.05(70)

25.3658020747

≈25.37