a spaceship launches into the air at 14550 meters in 30 minutes. Which is the average speed of the spaceship in meters per hour.

Answer:

C. No -12 is to the left of -2 on the number line

Answer:

Slope - intercept form    \(y = \frac{14}{3} x + 34\)

Step-by-step explanation:

Explanation:-

Given points are ( -9 ,-8 ) and (-6,6)

slope of given two points

    \(m = \frac{y_{2} -y_{1} }{x_{2}-x_{1} } = \frac{6-(-8)}{-6-(-9)} = \frac{14}{3}\)

The equation of the straight line passing through the points and having slope

          \(y - y_{1} = m ( x - x_{1} )\)

        \(y - (-8) = \frac{14}{3} ( x - (-9) )\)

          3 y + 2 4 = 14 x + 126

           3 y = 14 x + 126 - 24

          3 y = 14 x + 102

            \(y = \frac{14}{3} + \frac{102}{3}\)

           \(y = \frac{14}{3} x + 34\)

Slope - intercept form  y= mx +C

Slope - intercept form    \(y = \frac{14}{3} x + 34\)

Answer:

No mode ???? I'm not sure

The solution to the nonlinear system of equations is (x, y) = (-3, -2) and (x, y) = (1, 6). These points represent the coordinates where the two equations intersect and satisfy both equations simultaneously.

To solve the nonlinear system of equations:

Equation 1: \(y = -x^2 + 7\)

Equation 2: y = 2x + 4

We can equate the right sides of both equations since they both represent y.

\(-x^2 + 7 = 2x + 4\)

To simplify the equation, we can rearrange it to be in the standard quadratic form:

\(x^2 + 2x - 3 = 0\)

Now, we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. In this case, let's use factoring:

(x + 3)(x - 1) = 0

From this equation, we get two possible solutions:

x + 3 = 0 => x = -3

x - 1 = 0 => x = 1

Now, we substitute these x-values back into either equation to find the corresponding y-values.

For x = -3:

y = 2(-3) + 4

y = -6 + 4

y = -2

For x = 1:

y = 2(1) + 4

y = 2 + 4

y = 6

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In-state corresponds to students who are residents of the same state as the university, out-of-state corresponds to students from different states, and foreign corresponds to students from countries other than the university's country.

To match the vocabulary word with its corresponding example in the context of the state university survey, we need to understand the terms and their meanings.

Here are the vocabulary words and their corresponding examples:

Vocabulary Word: In-state

Example: A student who is a resident of the same state where the university is located.

They pay lower tuition fees compared to out-of-state or foreign students.

Vocabulary Word: Out-of-state

Example: A student who is not a resident of the state where the university is located.

They typically pay higher tuition fees compared to in-state students.

Vocabulary Word: Foreign

Example: A student who is from a country other than the country where the university is located.

They are international students who may have different visa requirements and tuition fees.

To match these vocabulary words with their corresponding examples:

In-state: A student from the same state as the university, paying lower tuition fees.

Out-of-state: A student from a different state than the university, paying higher tuition fees.

Foreign: A student from a country other than the country where the university is located, with potential differences in visa requirements and tuition fees.

By associating each vocabulary word with its respective example, we can accurately describe the three categories of students based on their residency and origin in the context of the state university's survey.

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Answer:

51

Step-by-step explanation:

arrange in ascending order

48,49,50,52 54,62

number of terms=6

median=(3rd term+4th term)/2=(50+52)/2=102/2=51

Answer:

51

Step-by-step explanation:

Hope it helps

Answer:

46.8 cm²

Step-by-step explanation:

The diagonal of the square has length \(\sqrt{6^2+10^2}=2\sqrt{34}\). Therefore, the radius of the circle is \(\sqrt{34}\), meaning the area is \(\pi(\sqrt{34})^2 \approx 34(3.14)=106.76\).

The area of the rectangle is \((6)(10)=60\) cm².

Subtracting the areas, the answer is 46.76 cm², which is 46.8 cm² to the nearest tenth.

The value for the height of the rectangular prism is found as; h = 7.

The formula for the surface area of rectangular prism is;

S = 2(ab+bh+ah)

Where,

a=6, b=5 and s=214

Substitute the values in the formula.

214 = 2(6×5 + 5h + 6h)

Simplifying;

30 + 11h = 107

11h = 107 - 30

11h = 77

h = 7

Thus, the value for the height of the prism is found as; h = 7.

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Answer:

y = 50x

Step-by-step explanation:

Answer:

\(-7,-2,\:3,\:8,\:13,\:18\)

Step-by-step explanation:

First Term

\(a_1=-7\)

Second Term

\(a_n=a_{n-1}+5\\\\a_2=a_{2-1}+5\\\\a_2=a_1+5\\\\a_2=-7+5\\\\a_2=-2\)

Third Term

\(a_3=a_{3-1}+5\\\\a_3=a_2+5\\\\a_3=-2+5\\\\a_3=3\)

Fourth Term

\(a_4=a_{4-1}+5\\\\a_4=a_3+5\\\\a_4=3+5\\\\a_4=8\)

Fifth Term

\(a_5=a_{5-1}+5\\\\a_5=a_4+5\\\\a_5=8+5\\\\a_5=13\)

Sixth Term

\(a_6=a_{6-1}+5\\\\a_6=a_5+5\\\\a_6=13+5\\\\a_6=18\)

All you are doing is just adding 5 to -7 to get the next term each time for 6 times!

Answer is in the file below

cutt.us/brainly

A=352in2

A=2(wl+hl+hw)=2·(8·12+4·12+4·8)=352in²

The additional 60 men, the provisions will last for approximately 20 weeks.

To determine how long the provisions will last with the additional 60 men, we need to consider the total number of people and the original duration the provisions were meant to last.

Originally, the provisions were intended to sustain 400 men for 23 weeks. This means that the provisions were estimated to be sufficient for a total of 400 * 23 = 9200 person-weeks.

Now, with the additional 60 men, the total number of men becomes 400 + 60 = 460.

To calculate how long the provisions will last with the increased number of men, we divide the total person-weeks by the new number of men:

Provisions last = Total person-weeks / Number of men

= 9200 / 460

≈ 20 weeks (rounded to the nearest whole number)

The additional 60 men will extend the supply's shelf life to around 20 weeks.

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Answer:

3x²–6x–5

Step-by-step explanation:

3x²–2x+1–4x–6

collect like terms

3x²–2x–4x–6+1

3x²–6x–5

To find the exact value of (7π/6) using the unit circle, locate the angle (π/6) on the unit circle in the second quadrant, determine the coordinates, and adjust the y-coordinate to be negative. The final answer is (√3/2, -1/2). This answer is obtained by understanding the reference angle and using the coordinates of the point where the angle intersects the unit circle.

To find the exact value of (7π/6) using the unit circle, follow these steps:

1. Start by understanding the reference angle. The reference angle for (7π/6) is (π/6).

2. Locate the angle (π/6) on the unit circle. This angle lies in the second quadrant.

3. Determine the coordinates of the point where the angle intersects the unit circle. For (π/6), the x-coordinate is √3/2 and the y-coordinate is 1/2.

4. Since (7π/6) lies in the second quadrant, the x-coordinate will remain the same, but the y-coordinate will be negative. Therefore, the coordinates for (7π/6) are (√3/2, -1/2).

5. The exact value of (7π/6) is (√3/2, -1/2).

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Answer: 24

Step-by-step explanation: LCM(8, 12) = 24

12 x 2 = 24

8 x 3 = 24

Answer:6_7

Step-by-step explanation:

Answer:

2l+2w, 60+60+30+30

Step-by-step explanation:

2(length)+2(width)

The perimeter of the ballroom will be represented by 2l+2w, and 2( 60 + 30 ).

The perimeter of a closed shape is the overall length of the boundary. As a result, the perimeter of that shape is determined by adding up all of its sides. Therefore, Perimeter(P) = Sum of All Sides is the perimeter formula.

A quadrilateral with four right angles is a rectangle. As all of its angles are equal, it can alternatively be described as an equiangular quadrilateral or a parallelogram with a right angle.

Given that a ballroom is 60 ft long and 30 ft wide. The equation for the perimeter of the ballroom will be calculated as:-

Perimeter = 2 ( l +  w)

Perimeter = 2 ( 60 + 30 )

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The solutions to the equation 1x² - 16x = 20 are x = 8 + 2√21 and x = 8 - 2√21.

To solve the quadratic equation 1x² - 16x = 20, we need to rearrange it into the standard form ax² + bx + c = 0. Let's simplify the equation step by step:

1x² - 16x = 20

First, move all terms to one side of the equation:

1x² - 16x - 20 = 0

Now we have a quadratic equation in the standard form. To solve it, we can use factoring, completing the square, or the quadratic formula. In this case, factoring may not be straightforward, so let's use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

For our equation, a = 1, b = -16, and c = -20. Substituting these values into the quadratic formula:

x = (-(-16) ± √((-16)² - 4(1)(-20))) / (2(1))

Simplifying further:

x = (16 ± √(256 + 80)) / 2

x = (16 ± √336) / 2

x = (16 ± √(16 * 21)) / 2

x = (16 ± 4√21) / 2

Simplifying:

x = 8 ± 2√21

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Answer:

answer is c makes sense because you just add 1.25 x 20

Answer:

Given that the vertices of quadrilateral PQRS are P(6,3), Q(4,2), R(2,4) and S(4,5) and the quadrilateral is dilated with a scale factor of 2, about the origin.

Now, let's find the new vertices of the dilated image:

Vertex P is dilated by a scale factor of 2, its new coordinates will be (2 × 6, 2 × 3) = (12, 6). Therefore, the new vertex P' is at (12, 6).

Vertex Q is dilated by a scale factor of 2, its new coordinates will be (2 × 4, 2 × 2) = (8, 4). Therefore, the new vertex Q' is at (8, 4).

Vertex R is dilated by a scale factor of 2, its new coordinates will be (2 × 2, 2 × 4) = (4, 8). Therefore, the new vertex R' is at (4, 8).

Vertex S is dilated by a scale factor of 2, its new coordinates will be (2 × 4, 2 × 5) = (8, 10). Therefore, the new vertex S' is at (8, 10).

Therefore, the coordinates of the vertices of the final image are P’(12, 6), Q’(8, 4), R’(4, 8), and S’(8, 10).So, the correct option is D. P’(12, 6), Q’(8, 4), R’(4, 8), and S’(8, 10).

Step-by-step explanation:

Hope this helps you!! Have a good day/night!!

Answer:

1 inch = 8 feet is the answer

Answer:

Its actually 150

Step-by-step explanation:

Just did it on a test and got 100%

The correct pairings are:

a) Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

b) Five times the difference of a number squared and six: 5(n² - 6)

c) Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

d) O twice the difference of nine and a number squared: 2(9 - n²)

The correct pairings of descriptions and expressions are as follows:

Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

This expression represents taking a number, cubing it, dividing the result by seven, subtracting four, and then adding three.

Five times the difference of a number squared and six: 5(n² - 6)

This expression represents taking a number, squaring it, subtracting six, and then multiplying the result by five.

Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

This expression represents taking the cube of a number, dividing six by the cube, adding nine, and then subtracting four.

O twice the difference of nine and a number squared: 2(9 - n²)

This expression represents taking a number, squaring it, subtracting it from nine, and then multiplying the result by two.

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Answer:

f(4) = 9

Step-by-step explanation:

You just need to substitute 4 in for x.

f(4) = 5(4) - 11

f(4) = 20 - 11

f(4) = 9

Answer:

22

Step-by-step explanation:

= 7 − (−15)

= 7 + 15

= 22

Prime numbers only have 2 factors 1 and itself. Arrays for prime number 19 and 13 are as follows

He would need to add 20 cups of flour.

According to the problem Marcus puts in twelve cups of sugar, and the original amount of sugar was 3 cups. If you divide 12 by 3 you get 4. This means that you multiply 5 by 4 to get the total amount of flour required (originally there were 5 cups of flour).

Hope this helps and have a nice day.

-R3TR0 Z3R0