Answers
Answer:
The mass of air stored in the vessel is 235.34 kilograms.
Explanation:
Let supossed that air inside pressure vessel is an ideal gas, The density of the air (\(\rho\)), measured in kilograms per cubic meter, is defined by following equation:
\(\rho = \frac{P\cdot M}{R_{u}\cdot T}\) (1)
Where:
\(P\) - Pressure, measured in kilopascals.
\(M\) - Molar mass, measured in kilomoles per kilogram.
\(R_{u}\) - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.
\(T\) - Temperature, measured in Kelvin.
If we know that \(P = 2026.5\,kPa\), \(M = 28.965\,\frac{kg}{kmol}\), \(R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K}\) and \(T = 300\,K\), then the density of air is:
\(\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}\)
\(\rho = 23.534\,\frac{kg}{m^{3}}\)
The mass of air stored in the vessel is derived from definition of density. That is:
\(m = \rho \cdot V\) (2)
Where \(m\) is the mass, measured in kilograms.
If we know that \(\rho = 23.534\,\frac{kg}{m^{3}}\) and \(V = 10\,m^{3}\), then the mass of air stored in the vessel is:
\(m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})\)
\(m = 235.34\,kg\)
The mass of air stored in the vessel is 235.34 kilograms.
Related Questions
Which statement is true of a catalyst in a reaction?
A. It acts as a reactant, in place of the original reactant.
B. It gets used up in the reaction.
C. It changes the activation energy required for the reaction.
D. It makes a reaction faster by adding energy.
Answers
Answer:
Hello There!!
Explanation:
The answer is=>C. It changes the activation energy required for the reaction.
hope this helps,have a great day!!
~Pinky~
The true statement for a catalyst used in a reaction is that it makes a reaction faster by adding energy. The correct option is D.
What is a catalyst?A catalyst is a substance that increases the chemical reaction rate without undergoing any permanent chemical change in itself. It makes the reaction faster.
The correct option is D.
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A driver is texting without seeing the traffic ahead and crashes into a stationary vehicle. Explain what happens to the kinetic energy. Answer in 4-6 sentences.
Answers
Answer:
By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.
Explanation:
By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.
A vehicle approaches a set of traffic lights with a speed of 15m/s. When 50m from the lights the driver brakes and comes to a rest at the lights. Calculate the deceleration of the vehicle
Answers
Answer:
–2.25 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 15 m/s
Distance travelled (s) = 50 m
Final velocity (v) = 0 m/s
Deceleration (a) =?
v² = u² + 2as
0² = 15² + (2 × a × 50)
0 = 225 + 100a
Collect like terms
0 – 225 = 100a
– 225 = 100a
Divide both side by 100
a = –225/100
a = –2.25 m/s²
Thus, the deceleration of the vehicle is –2.25 m/s²
What amount of force is required to accelerate a 20 gram toy car at 5 m/s²?
O 150 N
O 100 N
O 50 N
Ο ΟΝ
Answers
Answer:
100
Explanation:
F = m * a
Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):
F = 0.02 kg * 5 m/s^2 = 0.1 N
So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.
Approximately 20.0gm of milk at 6.0oC is added into a cup containing 270.0 gm of weak tea. The specific heat of weak tea is 3.91 x 103J kg-1 oC-1 and the final temperature of the milk - tea mixture is 85.0oC. Given the initial temperature of the weak tea is 90.0oC, what is the specific heat of milk?
Answers
Answer:
4161 J/kg·°C
Explanation:
We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.
Let's first calculate the heat lost by the tea:
Q(tea) = mcΔT
Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)
Q(tea) = 6555 J
where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.
Next, let's calculate the heat gained by the milk:
Q(milk) = mcΔT
Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)
Now we can equate the two expressions:
Q(tea) = Q(milk)
6555 J = (0.02 kg)(c)(79.0°C)
Solving for c, we get:
c = 4161 J/kg·°C
Therefore, the specific heat of milk is approximately 4161 J/kg·°C.
What is the rotational speed of the hour hand on a clock?
Answers
Answer:
π/21600 rad /s.
brianna swings a ball on the end of a rope in a circle. The rope is 1.5 m long. The ball completes a full circle every 2.2s. What is the tangential speed of the ball
Answers
Answer:
4.3 m/s
Explanation:
This model shows DNA, chromosomes, and genes. If B is a cell and C is the nucleus, what is A?
Answers
Based on the information, we can infer that A. represents a Mitochondria.
What is a mitochondria?Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.
Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.
Note: This question is incomplete. Here is the complete information:
Attached image
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Could a car drive on a frictionless surface? Explain using the terms action
force and reaction force. *
Answers
Answer:
No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place
some more disconnectiob
Answers
let the student report the tutor and check
answer is updated
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T/F when a car goes around a curve of smaller and smaller radius, the centripetal force on it decreases.
Answers
False. When a car goes around a curve of smaller and smaller radius, the centripetal force on it increases.
What is centripetal force?Centripetal force is an inward directed force that is necessary for an object to travel in a circular path. It is the force that keeps a body moving in a curved path and is directed towards the center of the circle. Centripetal force is the cause of a body's change in direction and is what allows it to maintain its circular motion. It is also known as the tangential force due to its perpendicular relationship to the radius of the circular path. Centripetal force is caused by a variety of factors such as gravity, friction, tension, and other forces that act on the object. It is important to note that the direction of the centripetal force is always perpendicular to the velocity of the body. This means that the velocity of the body will always point away from the center of the circle.
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An electric water heater consumes 2.5 kW for 1.9 h per day.
What is the cost (in $) of running it for one year if electricity costs 11.5 cents/kWh?
Answers
Answer:
The cost of running the electric water heater for one year is 55.2391 $
Explanation:
The simple rule of 3 helps to quickly solve proportionality problems when you have three known values and one unknown. If two quantities are directly proportional (that is, when multiplying or dividing one of them by a number, the other is multiplied or divided respectively by the same number) the rule of three can be applied as follows:
a ⇒ b
c ⇒ x
So: \(x=\frac{c*b}{a}\)
where a, b and c are the known values and x is the value you want to find out.
In this case, you can first apply the following rule of three: if 2.5 kW are consumed in 1.9 hours, in 1 hour how many kW are consumed?
\(kWh=\frac{1 h*2.5 kW}{1.9 h}\)
kWh=1.316
So an electric water heater consumes 1.316 kWh in one day. You apply another simple rule of three: if the heater in 1 day consumes 1.316 kWh, in 365 days (1 year) how many kWh are consumed?
\(kWh=\frac{365 days*1.316 kWh}{1 day}\)
kWh= 480.34
So an electric water heater consumes 480.34 kWh in a year.
If 1 kWh costs 11.5 cents, 480.34 kWh how many cents does it cost?
\(cost=\frac{480.34 kWh*11.5 cents}{1 kWh}\)
cost= 5,523.91 cents
Finally, if 100 cents is equal to 1 dollar, 5,523.91 cents, how many dollars are equal?
\(cost=\frac{5,5523.91 cents*1 dollar}{100 cents}\)
cost= 55.2391 $
The cost of running the electric water heater for one year is 55.2391 $
A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answers
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
A hamster eats a carrot before using its hamster wheel. The hamster wheel is connected to a generator which powers a light bulb.
Mechanical → Chemical → Radiant → Electrical
Chemical → Mechanical → Electrical → Radiant
Chemical → Mechanical → Thermal → Electrical
Mechanical → Electrical → Thermal → Radiant
Answers
Answer: Chemical → Mechanical → Electrical → Radiant
Explanation:
First, the Hamster eats the carrot, then the hamster is getting chemical energy.
Now the hamster starts using his wheel, then he "transforms" the chemical energy into mechanical energy.
Now the mechanical energy is connected to a generator, this means that the mechanical energy (the rotation of the wheel) is being converted into electrical energy.
And we know that there is a light bulb powered by this electrical energy, then we have electrical energy being transformed into radiant energy.
Then the correct option is:
Chemical → Mechanical → Electrical → Radiant
Please help me I’ll mark brainless
Answers
Answer:
ITS B NOT A
Explanation:
suppose you drop an object and it strikes the ground. you can calculate the velocity of the object as it strikes the ground using the law of conservation of energy. in order to do this, you need to know the original height of the object. do you also need to know the mass of the object? why or why not?
a. you do not need to know the mass because you can compute it based on the provided information.
b. you do not need to know the mass because it cancels out.
c. you need to know the mass of the object in order to compute the kinetic and gravitational potential energies.
d. you need to know the mass of the object in order to compute the elastic potential energy.
Answers
Answer:
b)
Explanation:
Assuming no friction forces present, the total mechanical energy must be conserved, so at any moment, the sum of the gravitational potential energy and the kinetic energy must be the same.When the object is dropped, all the energy is gravitational, as follows:E = m*g*h (1)When the object strikes the ground, if we choose the ground as the zero reference level for the gravitational potential energy, all the energy is kinetic:E = 1/2*m*v² (2)Since E is constant, left sides in (1) and (2) are equal each other, so the right sides must be equal each other too.Since the mass is present in the right side of (1) and (2) it cancels out, so b) is the right answer.
Answer: B you do not need to know the mass because it cancels out
Explanation:
A tsunami, an ocean wave generated by an earthquake, propagates along the open ocean at 700 km/hr and has a wavelength of 750 km. What is the frequency of the waves in such a tsunami?.
Answers
Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.
What is wavelength, frecuency and propagation speedFirst of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f×λ
Frequency of the waves in the tsunamiIn this case, you know:
v=700 km/h= 0.194 km/sf= ?λ= 750 kmReplacing:
0.194 m/s=f× 750 km
Solving:
f= 0.194 m/s ÷ 750 km
λ= 2.59×10⁻⁴ Hz
In summary, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.
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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin
Answers
The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.
1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).
2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.
3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.
4. However, the given equation does not explicitly mention resistance.
5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).
6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.
7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).
8. Therefore, V = VR + VL.
9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.
10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.
The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.
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Find the size of the image formed in the situation shown in figure.
A) 0.5 cm
B) 0.6 cm
C) 1.2 cm
D) 1 cm
Answers
Given
distance of the object u = -40 cm.
radius of curvature of the refracting surface R = -20 cm.
The height of the object h = 1 cm.
To Find
The size of the image
Solution
We will now write the following data using the sign convention:
The object's distance is u = -40 cm.
The refracting surface has a radius of curvature of R = -20 cm.
The object's height is h = 1 cm.
We know that the lens maker formula is: n2vn1u=n2n1R.
v denotes the image formation distance.
The refractive index of the second medium is n2=1.33, and the refractive index of the first medium is n1=1.
In the preceding equation, we will now substitute the known values.
1.33v−1−40cm=1.33−1−20cmv=32.05cm
We know that the magnification ratio can be expressed as vu=Hh.
H denotes the height of the created image.
We'll now swap the given and obtained values.
⇒32.05cm divide by 40cm=H divide by 1cm
⇒H=0.6cm
As a result, the best choice is (B).
Further information: The rules of reflection apply to reflection from a concave mirror. The normal to the point of incidence is drawn along the radius of the mirror, that is, by connecting the point of incidence to the centre of curvature.
The development of an image in a concave mirror is mostly determined by the distance between the object and the mirror. The concave mirror produces both real and virtual images. A virtual and magnified picture is generated when the object is placed very close to the mirror.
The complete question is -
Find the size of the image formed in the situation shown in figure.
photo
A) 0.5 cm
B) 0.6 cm
C) 1.2 cm
D) 1 cm
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what should be done in order to increase the gravitational force between two objects? Decrease the mass of both of the objects. Decrease the mass of one of the objects. Decrease the distance between the two objects. Increase the distance between the two objects.
Answers
Answer:
Decrease the distance between the two objects.
Explanation:
The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:
F = GM₁M₂ / r²
NOTE: G is the gravitational force constant.
From the equation:
F = GM₁M₂ / r²
We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.
Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.
Considering the question given above,
To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.
Answer:
Decrease the distance between the two objects.
Explanation:
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10. Convert the following:
a. 37.4 mL into ML
b. 689 km/hr into m/s
c. 34.5 m² into mm²
Answers
A. When we convert 37.4 mL to ML, the result obtained is 3.74×10¯⁸ ML
B. When we convert 689 km/hr to m/s, the result obtained is 191.39 m/s
C. When we convert 34.5 m² to mm², the result obtained is 3.45×10⁷ mm²
A. How to convert millimeters (mL) to megaliter (ML)Volume (mL) = 37.4 mLVolume (ML) =?1 mL = 1×10¯⁹ ML
Therefore,
37.4 mL = 37.4 × 1×10¯⁹
37.4 mL = 3.74×10¯⁸ ML
Thus, 37.4 mLis equivalent to 3.74×10¯⁸ ML
B. How to convert 689 km/hr to m/sConversion scale
3.6 Km/hr = 1 m/s
Therefore,
689 km/hr = 689 / 3.6
689 km/hr = 191.39 m/s
Thus, 689 km/hr is equivalent to 191.39 m/s
C. How to convert 34.5 m² to mm²Conversion scale
1 m² = 1×10⁶ mm²
Therefore,
34.5 m² = 34.5 × 1×10⁶
34.5 m² = 3.45×10⁷ mm²
Thus, 34.5 m² is equivalent to 3.45×10⁷ mm²
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Suppose that A’, B’ and C’ are at rest in frame S’, which moves with respect to S at speed v in the +x direction. Let B’ be located exactly midway between A’ and C’. At t’=0 a light flash occurs at B’ and expands outward as spherical wave.
1. According to an observer in S’, do the wave fronts arrive at A’ and C’ simultaneously?
2. According to an observer in S, do the wavefronts arrive at A’ and C’ simultaneously?
3. If you answered no to either 1. or 2., what is the difference in their arrival times and at which point did the front arrive first?
Answers
Answer:
1) an observer in B 'sees the two simultaneous events
2)observer B sees that the events are not simultaneous
3) Δt = Δt₀ /√ (1 + v²/c²)
Explanation:
This is an exercise in simultaneity in special relativity. Let us remember that the speed of light is the same in all inertial systems
1) The events are at rest in the reference system S ', so as they advance at the speed of light which is constant, so it takes them the same time to arrive at the observation point B' which is at the point middle of the two events
Consequently an observer in B 'sees the two simultaneous events
2) For an observer B in system S that is fixed on the Earth, see that the event in A and B occur at the same instant, but the event in A must travel a smaller distance and the event in B must travel a greater distance since the system S 'moves with velocity + v. Therefore, since the velocity is constant, the event that travels the shortest distance is seen first.
Consequently observer B sees that the events are not simultaneous
3) let's calculate the times for each event
Δt = Δt₀ /√ (1 + v²/c²)
where t₀ is the time in the system S' which is at rest for the events
The speed of an object doubles.How does the change in the magnitude of the objects
momentum compare to the change in its kinetic energy
Answers
Answer:
The change in kinetic energy is twice the change in momentum
Explanation:
The momentum of an object is given by:
where
m is the mass of the object
v is its velocity
While the kinetic energy is given by
We want to check how these two quantities change when the speed of the object doubles, therefore when the new velocity is
For the momentum, we have
So, the momentum doubles.
For the kinetic energy, we have
So, the kinetic energy quadruples.
Therefore, the change in kinetic energy is twice the change in momentum.
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Answers
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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A coaxial cable of length 2m consists of a wire of diameter 1mm and an outer shell of diameter 3mm. Find the capacitance of the cable.
Answers
According to the information, the capacitance of the coaxial cable is approximately 120.9 pF.
How to calculate the capacitance of the cable?To calculate the capacitante of the cable we have to consider that the capacitance of a coaxial cable is given by the formula:
C = (2πεrε0 / ln(b/a))
where:
εr = the relative permittivity of the medium between the two conductors (in this case, air)
ε0 = permittivity of free space
a = radius of the inner conductor
b = radius of the outer conductor
We can find the values of εr, a, and b as follows:
The radius of the inner conductor is 0.5 mm, or 0.0005 m.
The radius of the outer conductor is 1.5 mm, or 0.0015 m.
The relative permittivity of air is very close to 1, so we can use εr = 1.
So, now we have to substituting these values into the formula, we get:
C = (2π * 8.85 x 10^-12 * 1 / ln(0.0015/0.0005))
= 120.9 pF (picoFarads)
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. When a parallel plate capacitor is connected to a 12 V battery, each plate requires a charge of magnitude 0.0024 C. Find its capacitance. If the capacitor is connected to 24 V battery, will its capacitance increase? Why?
Answers
The capacitance of the capacitor is 1.7 * 10^-4 F. The capacitance will increase when the voltage is increased.
How does the capacitance relate to the magnitude of the voltage?If we hold the capacitance constant, a higher voltage applied to the capacitor will result in a greater amount of electrical charge stored on the capacitor. Conversely, if we hold the voltage constant, a capacitor with a higher capacitance will be able to store more electrical charge. In other words, the capacitance and the voltage are directly proportional to the amount of electrical charge that can be stored on a capacitor.
We know that;
q = CV
C = q/V
C = 0.0024 C/12 V
C = 1.7 * 10^-4 F
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Sharon and Kaylyn are playing air hockey. Sharon hits the hockey puck sending it at a velocity of 6 m/s and it hits Kaylyn's puck Both hockey pucks have a mass of 0.3 kg Sharon's puck stops after it hits Kaylyn's puck According to the law of conservation of momentum, what should the resulting velocity of Kaylyn's puck be if it. was at rest before colliding with Sharon's puck?
A. Equal to the velocity of Sharon's puck before they collided
B. Twice the velocity of Sharon's puck before they collided
C. Half the velocity of Sharon's puck before they collided
D. Equal to the velocity of Sharon's puck ball after they collided
Answers
Answer:
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since Sharon's puck stops after the collision, all of its momentum is transferred to Kaylyn's puck. Therefore, the resulting momentum of Kaylyn's puck is equal to the initial momentum of Sharon's puck:
m1v1 = m2v2
where m1 and v1 are the mass and velocity of Sharon's puck before the collision, and m2 and v2 are the mass and velocity of Kaylyn's puck after the collision.
Substituting the given values:
0.3 kg × 6 m/s = 0.3 kg × v2
Simplifying:
1.8 kg m/s = 0.3 kg × v2
Dividing both sides by 0.3 kg:
v2 = 6 m/s
Therefore, the resulting velocity of Kaylyn's puck should be equal to the velocity of Sharon's puck before they collided, which is 6 m/s.
Answer: A. Equal to the velocity of Sharon's puck before they collided.
A 5 cm spring is suspended with a mass of 1.057 g attached to it which extends the spring by 1.932 cm. The same spring is placed on a frictionless flat surface and charged beads are attached to each end of the spring. With the charged beads attached to the spring, the spring's extension is 0.286 cm. What are the charges of the beads? Express your answer in microCoulombs.
Answers
ANSWER:
0.02182 μC
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 1.057 g = 0.001057 kg
Length spring (l) = 5 cm = 0.05 m
spring stretch (x) = 1.932 cm = 0.01932 m
spring stretch + beads (x1) = 0.286 cm = 0.00286 m
The first thing to calculate is the value of the spring constant k, just like this:
\(\begin{gathered} F=k_sx \\ \\ F=mg \\ \\ mg=k_sx \\ \\ k_s=\frac{mg}{x} \\ \\ \text{ We replacing} \\ \\ k_s=\frac{(0.001057)(9.8)}{(0.01932)} \\ \\ k_s=0.5361\text{ N/m} \end{gathered}\)When the charged beads are attached in equilibrium, therefore:
\(\begin{gathered} \frac{k\cdot q^2}{(l+x_1)^2}=k_s\cdot x_1 \\ \\ q^2=\frac{(k_s\cdot x_1)(l+x_1)^2}{k} \\ \\ q=\sqrt{\frac{(k_sx_1)(l+x_1)^2}{k}} \\ \\ \text{ We replacing:} \\ \\ q=\sqrt{\frac{\left(0.5361\cdot0.00286\:\right)\left(0.05+0.00286\:\right)^2}{9\cdot10^9}} \\ \\ q=2.182\cdot10^{-8}C\cdot\frac{1\text{ }\mu C}{1\cdot10^{-6}\text{ }C}=0.02182\text{ }\mu C \end{gathered}\)The charge of the beads is 0.02182 μC
A plastic block of cork floats in water with two-fifth of it's volume above the water and six-eight of it in oil. calculate the density of the cork and oil
Answers
The density of the plastic block of cork is 600 kg/m³.
The density of the oil is 800 kg/m³.
Specific gravity of the cork in waterThe specific gravity of the cork in water is the fraction of the cork submerged in the water.
S.G = 1 - ²/₅
S.G = ³/₅ = 0.6
Density of the corkThe density of the cork is calculated as follows;
\(S.G = \frac{\rho_c}{\rho _w} \\\\\rho_c = S.G \times \rho_w \\\\\rho_c = 0.6 \times 1000\ kg/m^3\\\\\rho_c = 600 \ kg/m^3\)
Density of the oilThe density of the oil is calculated as follows;
S.G = ⁶/₈ = 0.75
\(S.G = \frac{\rho_c }{\rho_o} \\\\\rho_o = \frac{\rho_c }{S.G} \\\\\rho_o =\frac{600 \ kg/m^3}{0.75} \\\\\rho_o = 800 \ kg/m^3\)
Learn more about specific gravity and density here: https://brainly.com/question/12910511