Answers
Answer:
The mass of the sun is \(m_s = 5.568 *10^{30} \ kg\)
Explanation:
From the question we are told that
The mass of the planet is \(M = 7 *10^{24} \ kg\)
The period of the planet is \(T = 1 \ Earth \ year = 365 * 24 * 3600 = 3.15 *10^{7} \ s\)
The speed of the planet is \(v = 42000 \ m/s\)
Generally the radius at which the planet orbits the sun is mathematically represented as
\(r = \frac{Gm_s }{v^2 }\)
Where \(G\) is the gravitational constant with value \(G = 6.67 *10^{-11} \ m^3 \cdot kg^{-1} \cdot s^{-2}\)
and \(m_s\) is the mass of the sun
Generally the period of planet is mathematically represented as
\(T = \frac{2 \pi r}{v}\)
=> \(T = \frac{2 \pi}{v} * \frac{G * m_s}{v^2}\)
=> \(m_s = \frac{T * v^3}{2* \pi * G}\)
substituting values
\(m_s = \frac{ 3.15 *10^{7} * (42000)^3}{2* 3.142 * 6.67 *10^{-11}}\)
\(m_s = 5.568 *10^{30} \ kg\)
The mass of the sun will be "5.568 × 10³⁰ kg".
Gravitational forceAccording to the question,
Planet's mass, M = 7 × 10²⁴ kg
Planet's period, T = 1 Earth year
= 365 × 24 × 3600
= 3.15 × 10⁷ s
Planet's speed, v = 4200 m/s
Gravitational constant, G = 6.67 × 10⁻¹¹ m³.kg⁻¹.s⁻²
We know the relation,
T = \(\frac{2 \pi r}{v}\)
or,
= \(\frac{2 \pi}{v}\times \frac{G\times m_s}{v^2}\)
hence,
The sun's mass be:
\(m_s\) = \(\frac{T\times v^3}{2\times \pi\times G }\)
By substituting the values,
= \(\frac{3.15\times 10^7\times (42000)^3}{2\times 3.142\times 6.67\times 10^{-11}}\)
= 5.568 × 10³⁰ kg
Thus the response above is correct.
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Related Questions
A moving walkway has a speed of 0.5 m/s to the east. A stationary observer
sees a man walking on the walkway with a velocity of 0.8 m/s to the east.
What is the man's velocity relative to the moving walkway?
Answers
Answer: 0.3 m/sec
Explanation:
Vrel = (Vs-Vm) = (0.8-0.5) = 0.3 m/sec
Answer:
0.3 m/s east
Explanation:
Mr. Bissell creates a diagram of electric and magnetic fields to teach his students about the concepts. He includes the similarities and differences between the fields on the diagram. Which of the following statements should he add about the similarities between the two fields?
Answers
The similarity between electric field and magnetic field is that both fields attract or repel charges in the field.
What is an electric field?
The force per unit charge that a vanishingly small positive test charge would experience if held fixed at a given point in space is the definition of the electric field at that location.Since force is a vector (i.e., having both magnitude and direction), and the electric field is defined in terms of force, it follows that an electric field is a vector field.The term "force field" is occasionally used to describe fields that can be defined in this way.The gravitational field between two masses and two charges behaves similarly, with both obeying an inverse-square law as the distance between them increases.To know more about electric field, click the link given below:
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Barry Bonds hits a 125m (450’) home run. Assuming that the ball left the bat at an
angle of 45° from the horizontal, calculate how long the ball was in the air.
Answers
The ball left the bat at an angle of 45° from the horizontal, and then the ball was in the air for 4.51 seconds.
To calculate how long the ball was in the air, we can break down the motion of the ball into its horizontal and vertical components. Given that the ball was hit at an angle of 45° from the horizontal, we can determine the initial velocities in the horizontal and vertical directions.
The horizontal component of the initial velocity (Vx) remains constant throughout the motion because there is no horizontal acceleration. The vertical component of the initial velocity (Vy) can be calculated using trigonometry, knowing that the angle is 45° and the magnitude of the velocity is 125 m (450 ft).
Vy = V * sin(45°)
Vy = 125 m/s * sin(45°)
Vy = 125 m/s * √(2)/2
Vy ≈ 88.4 m/s
Next, we can analyze the vertical motion of the ball. The ball is subject to a constant acceleration due to gravity, which is approximately 9.8 m/s². Using this acceleration, we can calculate the time it takes for the ball to reach its maximum height and then fall back down to the ground.
Using the kinematic equation:
Vy = V0y + a * t
where Vy is the final vertical velocity (which is 0 m/s at the highest point), V0y is the initial vertical velocity, a is the acceleration due to gravity (-9.8 m/s²), and t is the time.
0 = 88.4 m/s - 9.8 m/s² * t
Solving for t:
t = 88.4 m/s / 9.8 m/s²
t ≈ 9.02 s
Since the time calculated is for the total time of the ball's flight (going up and coming back down), we can divide it by 2 to get the time the ball was in the air:
t_air = t / 2
t_air ≈ 4.51 s
Therefore, the ball was in the air for approximately 4.51 seconds.
It's important to note that this calculation assumes ideal conditions and neglects factors such as air resistance, variations in gravitational acceleration, and any other external factors that could affect the ball's flight.
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A battery does 1.922 J of work to transfer 0.089 C of charge from the negative to the positive terminal. What is the emf of this battery?
Answers
We can find the EMF as follows:
\(\begin{gathered} EMF=\frac{W}{q} \\ where: \\ W=1.922J \\ q=0.089C \\ so: \\ EMF=\frac{1.922}{0.089} \\ EMF=21.5955V \end{gathered}\)Answer:
21.5955V
A small bullet is fired into a large piece of wood. After the bullet penetrates the wood, the assembly moves as one unit along a low-friction track in the direction of travel of the bullet.
1) After the bullet is stuck in the piece of wood, is the momentum of the wood (not including the bullet; assuming the piece of wood was initially at rest) greater than, equal to, or less than the initial momentum of the bullet?
Choose from:
a)The momentum of the wood is greater than the initial momentum of the bullet
b) The momentum of the wood is greater than the initial momentum of the bullet.
c)The momentum of the wood is less than the initial momentum of the bullet
2) Is the combined kinetic energy of the bullet and the wood after the bullet is stuck in the wood greater than, equal to, or less than the initial kinetic energy of the bullet?
Choose from...
a)The combined energy is less than the initial kinetic energy of the bullet.
b) The combined energy is equal to the initial kinetic energy of the bullet.
C)The combined energy is greater than the initial kinetic energy of the bullet.
Answers
These two statements are true: the wood's momentum is lower than the bullet's starting momentum, and the total energy is lower than the bullet's original kinetic energy.
Pi = Pf, Pbi+Pwi = Pbf+Pwf, MbVbi+MwVwi = Mb Vbf + Mw Vwf, MbVbi + Mw (0) = (Mb + Mw)Vf, and MbVbi = (Mb + Mw)Vf according to the rule of conservation of linear momentum.
As a result, the bullet's initial momentum is smaller than that of the wood.
Consequently, the appropriate choice is (c).
(2) The formula for kinetic energy is Ki = Pi2/2Mb Kf = Pf2 / 2(Mb + Mw).
By dividing the two energies by their ratio, Kf = (Mb / Mb + Mw)Ki and Kf = Pf2 / 2(Mb + Mw) / Pi2/2Mb.
as a result, the appropriate choice is (a).
According to the rule of conservation of momentum, if two objects collide, the force obtained by one object equals the force lost by one.
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A gyroscope consists of a rotating disk with a 25 cm radius suitably mounted at the midpoint of a 20 cm long axle so that it can spin and precess freely. One end is supported by a stand. The disk spins at 2000 rpm. The mass of the disk is 2 kg, and the axle can be taken as massless.
Required:
a. Draw the gyroscope, indicating the direction of the initial angular speed and the initial angular momentum. Choose a direction for the spin of the disk.
b. Draw the torque due to gravity about the support point.
c. What direction will your gyroscope precess once you release it?
d. Find the time required for one precession of the gyroscope if it is supported at one end of the axle and it precesses in the horizontal plane.
Answers
Answer:
A) attached below
B) attached below
C) Anti-clockwise
D) 3.27 secs
Explanation:
A) Diagram of the gyroscope indicating direction of
attached below
B) Diagram of torque due to gravity about support point
Attached below
C) The direction the gyroscope will precess is ANTICLOCKWISE
D) Time required for one precession of the gyroscope
use the relation below
MgL = ΔIw / Δt
∴ Δt = ΔIw / MgL
=( 1/2 * 2 * 0.25^2 * 2π * 2000 ) / ( 2 * 10 * 0.2 * 60 )
= 3.27 secs
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it around her head in a horizontal circle at 100 rpm. What are the highest and lowest frequencies heard by a student in the classroom
Answers
Answer:
619.2 Hz and 582.5Hz
Explanation:
Given that
Frequency of the generator, F(s) = 600 Hz
Length if the rope, r = 1 m
Speed of whirling, w = 100 rpm
For starters, we find the speed of the generator, v(g)
v(g) = r.w
It should be noted, however, that we are to convert the speed of whirling from rpm to rad/s, thus
100 rpm = 100 * 2π/60 rad/s
100 rpm = 200π/60
100 rpm = 620.4 / 60
100 rpm = 10.47 rad/s
Now, we use this to find the speed of the generator
v(g) = r.w
v(g) = 1 * 10.47
v(g) = 10.47 m/s
When approaching the generator, the frequency is calculated as
F(a) = F(s) / [1 - (v(g)/v)]
F(a) = 600 / [1 - (10.47/343)]
F(a) = 600 / 0.969
F(a) = 619.2 Hz
On the other hand, the receding generator frequency is
F(r) = F(s) / [1 + (v(g)/v)]
F(r) = 600 / [1 + (10.47/343)]
F(r) = 600 / 1.030
F(r) = 582.5 Hz
Therefore, we can conclude that the highest and lowest frequency is 619.2 Hz and 582.5 Hz respectively
It takes 24 hours for _______?
a.Earth to circle the sun one time
b.earth to rotate on its axis one time
c. The sun to circle earth one time
d.the sun to rotate on its axis one time
Answers
Answer:
C
Explanation:
Earth rotates once in about 24 hours with respect to the Sun, but once every 23 hours, 56 minutes, and 4 seconds with respect to other, distant, stars. Earth's rotation is slowing slightly with time; thus, a day was shorter in the past. This is due to the tidal effects the Moon has on Earth's rotation.
Answer: the answer is b.
ps: the other answer is wrong, the earth rotates around the sun, and the sun doesn't rotate around the earth.
Explanation:
You walk 57 m to the north, then turn 60° to your right and walk another 45 m. How far are you from where you originally started?
Answers
Your displacement from where you originally started is determined as 52.05 m.
What is resultant displacement?The resultant displacement of an object is the change in position of the object. It can be described as the shortest distance connecting the final position of the object to the initial position of the object.
Mathematically, resultant displacement is given as;
R² = a² + b² - 2ab cos(θ)
where;
R is the resultant displacementa is the initial positionb is the final positionθ is the resultant angleSubstitute the given parameters and solve for the resultant displacement of the journey.
R² = (57)² + (45)² - 2(57 x 45) cos(60)
R² = 5274 - 2565
R² = 2,709
R = √2709
R = 52.05 m
Thus, your displacement from where you originally started is determined as 52.05 m.
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Calculate the height (in m) of a cliff if it takes 2.17 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.16 m/s.
How long (in s) would it take to reach the ground if it is thrown straight down with the same speed?
Answers
The height of the cliff will be equal to 5.37 meters, and the time taken to reach the ground if it is thrown straight down with the same speed will be equal to 0.50 s.
What is Speed?The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.
The maximum speed that can be maintained when a time period grows closer to zero is the starting speed.
As per the given information in the question,
Use the equation given below to find the vertical height of the cliff.
y = y₀ + ut + 1/2 at²
Here,
y represents final position of the object
y₀ is the initial position of the object and t is the time interval.
So,
y₀ = y -ut -1/2at²
y₀ = 0 - (8.16)(2.17) - 1/2(-9.8)(2.17)²
= -17.70 + 23.07
= 5.37 meters.
(b)
Now again rearrange the equation,
y = y₀ + ut + 1/2at² for y - y₀
Now, find the quadratic equation in time,
t = -u ± √[u² - 4(1/2a)(y₀ - y)]/2(1/2a)
Put the values in the above equation,
= -(-8.16 m/s) ± √[(-8.16)² - (-9.8)(2)(5.37)]
= [8.16 ± √(66.58 + 105.25)]/-9.8
= [8.16 ± 13.1]/-9.8
= -4.94/-9.8 = 0.50 s.
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a violin is less than 0.5 m long. a bass fiddle is more than 1.5 m long. which instrument do you expect to be able to play notes with a lower pitch and why?
Answers
Explanation:
When there is a high frequency sound the speed of the vibrations is faster and makes a high pitch sound. When there is a low frequency sound the speed of the vibrations is slower and makes a lower pitch sound.
A toy helicopter with a mass of 20 kg experiences a gravitational force of 200 N. (a) What is the resultant force on the toy helicopter if it is ascending with a constant speed of 5 ms ¹? (b) What is the force acting on the helicopter if the rotor suddenly stops working? (c) What will happen to the helicopter in (b)?
Answers
(a) The resultant force on the toy helicopter if it is ascending with a constant speed of 5 m/s is zero.
(b) The force acting on the helicopter if the rotor suddenly stops working is 200N.
(c) In (b), if the rotor suddenly stops working, the helicopter will fall downward due to the force of gravity. If there is no other force to oppose the force of gravity, the helicopter will accelerate downward at a rate of approximately 9.81 m/s².
(a) The resultant force on the toy helicopter if it is ascending with a constant speed of 5 m/s is zero. The force of gravity, which is 200 N, is equal in magnitude and opposite in direction to the force of the toy helicopter exerting on the air to ascend with a constant speed of 5 m/s. Therefore, the resultant force is zero.
(b) The force acting on the helicopter if the rotor suddenly stops working is 200 N, which is equal in magnitude and opposite in direction to the force of the toy helicopter exerting on the air. When the rotor suddenly stops working, there is no longer a force to keep the toy helicopter in the air. The force of gravity then takes over, causing the helicopter to fall downward at an increasing speed due to the acceleration due to gravity, which is approximately 9.81 m/s².
(c) In (b), if the rotor suddenly stops working, the helicopter will fall downward due to the force of gravity. If there is no other force to oppose the force of gravity, the helicopter will accelerate downward at a rate of approximately 9.81 m/s². This acceleration due to gravity will cause the speed of the helicopter to increase as it falls. Without any means of propulsion or control, the helicopter will continue to fall downward until it reaches the ground or collides with an object.
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If the current in each wire is the same, which wire produces the strongest magnetic field?
-a wire that is 1 mm thick and not coiled
-a wire that is 2 mm thick and not coiled
-a 1-mm-thick coiled wire with ten loops
-a 2-mm-thick coiled wire with two loops
Answers
Answer:
C
Explanation:
I did this before
Answer:
it is c
Explanation:
cuz i know
An appeal of a state appellate court ruling can next be made to:
• A. a state trial court.
• B. the state supreme court.
• C. the U.S. Supreme Court.
• D. a U.S. Court of Appeals.
Answers
The decision of the country's highest court may then be appealing to that Supreme Court of both the U. S., but only in cases where the issue involves federal law.
Why is Supreme renowned?In particular, followers of hip-hop, surfing, and post - punk culture will find their clothing appealing. Every person who appreciates streetwear will discover the ideal item thanks to Supreme's wide range of clothing.
Why is Supreme so expensive?Rebellious and distinctive brand image! Despite giving a venture - capital group a 50% ownership in the company, Supreme has been able to keep its skater roots and fan base. To top it all off, the Supremes' emblem is distinctive, outstanding, and simple to recognize.
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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
Answers
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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the space Hubble Telescope is orbiting earth at a constant speed of 20m/s.The distance between it and planet earth is 100m.The radius of planet earth is 300km. How long will it take for the Space Hubble Telescope to make a complete rotation?
Answers
It will take the Hubble Telescope 94,247 seconds or 26.18 hours to complete one full rotation around the Earth.
Rotation time of the Space Hub TelescopeThe Hubble Telescope is in a circular orbit around the Earth at a constant speed of 20 m/s. The distance between the telescope and the center of the Earth is:
300 km + 100 m = 300,100 m.
Orbital period T of the Hubble Telescope = T = 2πr / v
where
r is the radius of the orbit v is the orbital speed.In this case, r = 300,100 m and v = 20 m/s, so:
T = 2π(300,100 m) / (20 m/s) = 94247 seconds
Thus, it will take the Hubble Telescope approximately 94,247 seconds, or about 26.18 hours, to complete one full rotation around the Earth.
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Particles q1 = -75.8 uC, q2 = +90.6 uQ, and q3 = -84.2 uC are in a line. Particles q1 and q2 are separated by 0.876m and particles q2 and q3 are separated by 0.432m. What is the net force on particle q3?
Answers
The net force on q3 due to q1 and q2 is \(-13.76 * 10^{-3} N\).
Electrostatic force is the fundamental force between charged particles. The electrostatic force is responsible for many phenomena in our daily life, from the attractive force between a magnet and a metal object to the lightning that occurs during a thunderstorm. We can calculate the net force between charged particles using Coulomb's law. In this question, we have three particles q1 = -75.8 uC, q2 = +90.6 uQ, and q3 = -84.2 uC, which are separated by distances r1 = 0.876m and r2 = 0.432m. The electrostatic force on q3 due to q1 and q2 can be calculated by using the formula: \(F13 = k q_1 q_3 / r_1^2 + k q_2 q_3 / r_2^2\), where k is the Coulomb's constant \(k = 9 * 10^9 N m^2 / C^2\). Plugging in the given values of q1, q2, q3, r1, r2, and k in the above formula, we can calculate the electrostatic force on q3 due to q1 and q2.F13 = (9 x 10^9) (-75.8 x 10^-6) (-84.2 x 10^-6) / (0.876)^2 + (9 x 10^9) (90.6 x 10^-6) (-84.2 x 10^-6) / (0.432)^2F13 = \(-13.76 * 10^{-3} N\). The negative sign indicates that the force is attractive and is directed towards q1 and q2. Therefore, the net force on q3 is given by the vector sum of the forces on q3 due to q1 and q2. Since the forces are collinear, we can add them algebraically. Fnet = F13 Fnet = \(-13.76 * 10^{-3} N\)The net force on q3 due to q1 and q2 is -13.76 x 10^-3 N. The negative sign indicates that the force is attractive and is directed towards q1 and q2.For more questions on net force
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A trolley with a 5.0 cm long card passed through
a single light gate. The time recorded by a digital
timer was 0.40 s. What was the average speed of
the trolley in ms-1?
Answers
Answer:0.125m/s
Explanation:
A trolley with a 5.0 cm long card passed through a single light gate. The time recorded by a digital timer was 0.40 s.then the average speed of the trolley would be 0.125 ms⁻¹.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for average speed is given by
average speed = distance /total time
As given in the problem a trolley with a 5.0 cm long card passed through a single light gate. The time recorded by a digital timer was 0.40 s
100 cm = 1 m
1 cm = 1/100 m
5 cm = 5×1/100 m
=0.05 m
By substituting the values in the formula of the average speed
average speed = distance /total time
=0.05/0.4 m/s
=0.125 m/s
Thus, the average speed of the trolley would be 0.125 ms⁻¹.
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A bullet is fired at an angle of 80° with the
horizontal with an initial velocity of 420 m/s.
How high can it travel after 2 seconds? How
far horizontally did it travel after that same 2
seconds?
Answers
The bullet fired at an angle of 80° with the horizontal and an initial velocity of 420 m/s can travel up to a height of 825.4 meters and a horizontal distance of 80.1 meters after 2 seconds.
To determine the height and horizontal distance traveled by a bullet fired at an angle of 80° with the horizontal and an initial velocity of 420 m/s after 2 seconds, we can use the equations of motion.
Firstly, we can break down the initial velocity of the bullet into its horizontal and vertical components. The horizontal component remains constant throughout the motion and is given by:
Vx = Vcosθ
where V is the initial velocity and θ is the angle of projection. Substituting the given values, we get:
Vx = 420cos80° = 40.05 m/s (approx.)
The vertical component of the initial velocity can be calculated as:
Vy = Vsinθ
Substituting the given values, we get:
Vy = 420sin80° = 416.95 m/s (approx.)
Now, we can use the following equations of motion to determine the height and horizontal distance traveled by the bullet after 2 seconds:
Vertical motion:
y = yo + Voyt + (1/2)gt^2
where y is the vertical displacement, yo is the initial height (assumed to be zero), Voy is the initial vertical velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Substituting the given values, we get:
y = 0 + 416.95(2) - (1/2)(9.8)(2)^2
y = 825.4 m (approx.) Therefore, the bullet can travel up to a height of 825.4 meters after 2 seconds. Horizontal motion:
x = xo + Voxt
where x is the horizontal displacement, xo is the initial horizontal position (assumed to be zero), Vox is the initial horizontal velocity, and t is the time.
Substituting the given values, we get:
x = 0 + 40.05(2)
x = 80.1 m (approx.)
Therefore, the bullet can travel a horizontal distance of 80.1 meters after 2 seconds.
In summary, the bullet fired at an angle of 80° with the horizontal and an initial velocity of 420 m/s can travel up to a height of 825.4 meters and a horizontal distance of 80.1 meters after 2 seconds.
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
Answers
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Where is nuclear fusion found to occur?
O nuclear power reactors
black holes
stars
O nuclear bombs
Answers
Nuclear fusion is the process of fusing two lighter nuclei to form heavier ones is occurs in the core of stars. Thus, option C is correct.
Nuclear reaction is of two types and they are nuclear fusion and nuclear fission. Nuclear fission is the process of splitting up molecules. It is defined as the heavier atoms or nuclei undergoing splitting and forming two lighter small nuclei. During the fission process, more energy is required to split molecules.
Nuclear fusion is the process of merging two molecules. It is defined as the two lighter nuclei fusing together to form a large nucleus and during the fusion process, more energy is released. The core of the sun and stars have lighter nuclei Hydrogen undergoes fusion to form heavier atom Carbon.
Thus, the ideal solution is option C.
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determine the strength and direction of the electric field 1 micrometer away from an electron
Answers
The magnitude of the electric filed strength is -1.44 * 10^-3 N/C away from the electron.
What is the electric field strength?The electric field strength refers to the level of impact that a charge has on another charge in its vicinity. Now you have to know that the electric filed intensity depends on the magnitude of the charge and the force that is exerts on another charge.
Thus;
E = Kq/r^2
K = electric constant
q = magnitude of the charge
r = distance
E = 9.0 * 10^9 * -1.6 * 10^-19/1 * 10^-6
E = -1.44 * 10^-3 N/C
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Which has the most mass?
O The Moon
O A Pencil
O Your teacher.
O Earth
Answers
Answer:
Earth
lol... ....
On an aircraft carrier, a jet can be catapulted from 0 to 240
km/h in 2.00 s . If the average force exerted by the capult is 9.25x10^5 n what is the mass of the jet
Answers
Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.
\(v_{f}=v_{o}+a*t\)
where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
\(240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]\)
Now replacing:
\(66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]\)
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a
\(925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]\)
please help, im having trouble can you please explain how to do it
Answers
Answer:
independent and the second one with the (-8, 1, -3)
Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only once.- corona- convection zone- core- photosphere- radiation zone- chromosphere1. nuclear fusion of hydrogen into helium occurs in the ______2. energy moves through the sun's ______ by means of the rising of hot gas and falling of cooler gas. 3. nearly all the visible light we see from the sun is emitted from the ______4. most of the sun's ultraviolet light is emitted from the narrow layer called the ______ where temperature increases with altitude. 5. we can see the sun's ______ most easily during total solar eclipses.6. the ______ is the layer of the sun between its core and convection zone.
Answers
Nuclear fusion is the process that occurs when two or more atomic nuclei unite. In below given way words can be matched.
What is nuclear fusion?Nuclear fusion is the process that occurs when two or more atomic nuclei unite to generate one or more distinct atomic nuclei containing subatomic particles (neutrons or protons). The mass difference between both the products and the reactants manifests itself as either energy release or absorption.
1. Nuclear fusion of hydrogen into helium occurs in the CORE.
2. Energy moves through the sun's CONVECTION ZONE by means of the rising of hot gas and falling of cooler gas.
3. Nearly all the visible light we see from the sun is emitted from the PHOTOSPHERE.
4. Most of the sun's ultraviolet light is emitted from the narrow layer called the CHROMOSPHERE where temperature increases with altitude.
5. We can see the sun's CORONA most easily during total solar eclipses.
6. The RADIATION ZONE is the layer of the sun between its core and convection zone.
Therefore, in above given way words can be matched.
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Which of the following is not true about Triton, the large moon of Neptune? It is more reflective than Earth's Moon. It is larger than Earth's Moon. It is in a retrograde orbit. It has a thin atmosphere. It has nitrogen geysers.
Answers
Answer:
Triton is the largest of Neptune's 13 moons. It is unusual because it is the only large moon in our solar system that orbits in the opposite direction of its planet's rotation―a retrograde orbit. ... Like our own moon, Triton is locked in synchronous rotation with Neptune―one side faces the planet at all times.
Now an electron of mass m and charge −qe (where qe is a positive quantity) is placed within the electric field (see the figure) at height h0 . Part B Calculate the electon's potential energy U(h0) , neglecting gravitational potential energy. Express your answer in terms of qe , E , and h0 .
Answers
The electron's potential energy at height h0 is U(h0) = qe * E * h0. This expression shows that the potential energy of the electron is directly proportional to the electric field strength and the height at which it is placed.
The potential energy of an electron placed within an electric field can be calculated using the formula:U = qe * V, where qe is the charge of the electron, and V is the potential difference between the two points. In this case, the electron is placed at a height h0 within the electric field.
The potential difference between the top and bottom of the electric field is E*h0 (where E is the electric field strength), and the potential at the bottom of the electric field is zero. Therefore, the potential at height h0 is: V = E * h0. Substituting this into the formula for potential energy, we get: U(h0) = qe * V. U(h0) = qe * E * h0
Therefore, the electron's potential energy at height h0 is U(h0) = qe * E * h0. This expression shows that the potential energy of the electron is directly proportional to the electric field strength and the height at which it is placed.
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Do this question by electric flux
A conducting sphere of radius 10cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is \(1.5*10^{3}\) N/C and points radially inwards what is the net charge on the sphere.
Answers
Answer:
To find the net charge on the sphere using electric flux, we can use the formula:
Φ = Q/ε0
Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.
Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:
E = kQ/r^2
Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.
Substituting the given values, we get:
20 = (1/4πε0)(Q)/(0.2)^2
Solving for Q, we get:
Q = (20)(0.2)^2(4πε0)
Q = 0.64πε0 C
Now, substituting this value of Q in the formula for electric flux, we get: Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C
Therefore, the net charge on the sphere is 0.64π C.
7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.
Answers
If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.
What is the speed about?A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.
If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.
In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.
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