A concrete column has a diameter of 350m and length of 2m. If the density (mass/volume) of the concrete is 2. 45mg/m^3 determine the weight of column in pounds

Answer:

The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor, that's why rainwater is also distilled, it doesent have any particles or minerals in it.

The potential energy of the reactants is greater than the potential energy of the products.

Potential energy of a reaction is the stored energy that helps in breaking the bond of a compound during a chemical reaction.

The bonds present in the reactants in the reaction mixture split in the presence of the activation energy to release energy and form the product.

Thus,, option A. The potential energy of the reactants is greater than the potential energy of the products.

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When there is an increasing unbalanced force applied in the opposite direction as the motion, speed will decrease and acceleration will increase.

This is defined as the rate of change of velocity with time and the unit is metres per seconds.

An unbalanced force will lead to the speed of the object decreasing as a result of the distance reached being on a decline. However, the acceleration will increase due to the applied force in which they have a direct relationship.

This is therefore the reasons why they were chosen as the most appropriate choice.

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Answer:

F = Gm1m2/r^2 where G = 6.67x10^-11, m1 =1300, m2 = 7800, r = 0.23m

F = 6.67x10^-11 *1300*7800/(0.23)^2 = 0.0127852N

Explanation:

A magnetic field of magnitude 0.300 T is oriented perpendicular to the plane of a circular loop. According to the Faraday's law of electromagnetic induction, the emf induced in a coil is directly proportional to the rate of change of magnetic flux .

which is given as;emf = -NdΦ/dtwhere, N = number of turns in the coil,dΦ/dt = rate of change of magnetic fluxThus, the main ans to this question is the emf induced in the circular loop. The explanation for the emf induced in a circular loop can be given as follows; The magnetic flux through a circular loop of area A is given by;Φ = B*AWhere,B = magnetic field strength A = area of the circular loop Hence, the rate of change of magnetic flux can be given as;dΦ/dt = dB/dt *

A Therefore, the emf induced in the circular loop can be given as;emf = -NdΦ/dtemf = -N*dΦ/dtTherefore,emf = -N * d(B*A)/dtemf = -N * A * dB/dt Given, B = 0.300 T Therefore, dB/dt = 0The magnitude of magnetic field and the area of the circular loop are given .Hence, the emf induced in the circular loop can be found by using the following formula; emf = -N * A * dB/dtemf = -N * A * 0Therefore,emf = 0

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The hippo's center of gravity is located 3.2 meters from its tail.

To determine the distance of the hippo's center of gravity from its tail, we need to consider the weight distribution between its front and rear feet. Given that the hippo carries 80% of its weight on its front foot, we can assume that 80% of the hippo's total weight acts at the front. Let's denote the distance from the tail to the center of gravity as "x."

Since the rear foot is located at the tail, the remaining 20% of the weight acts at the rear foot. Using the principle of moments, we can set up the equation: (80% of the weight) * (distance from front foot to center of gravity) = (20% of the weight) * (distance from rear foot to center of gravity). Plugging in the given values, we have (0.8) * (4.0 - x) = (0.2) * x. Solving this equation, we find x = 3.2 meters. Therefore, the hippo's center of gravity is located 3.2 meters from its tail.

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Answer:

confusion

Explanation:

mark as brainlist plz

Answer:

Answer B is the correct answer: "Motion of one projectile as seen from the other is a straight line."

Explanation:

Let's write the equations of motion for each projectile, using that projectile \(a\) is launched with velocity \(a\) which has components associated with the angle of launching, given in x and y coordinates as: \(a_x\,\,and\,\,a_y\).

Similarly, assume that projectile b is launched with velocity \(b\) with components due to the launching angle = \(b_x\,\,and \,\,b_y\)

then the equations of motion for the two projectiles launched at the same time (t) from the same spot (position that we assume to be at the origin of coordinates to simplify formulas) are:

\(x_a=a_x\,t\\y_a= a_y\,t-\frac{1}{2} g\,t^2\\and\\x_b=b_x\,t\\y_b= b_y\,t-\frac{1}{2} g\,t^2\)

therefore, from the frame of reference of projectile "b", the x and y position of projectile "\(a\)" would be:

\(x_{a\,b}= x_a-x_b= a_x\,t-b_x\,t=(a_x-b_x)\,t\)  which is linear in "t"

\(y_{a\,\,b}=y_a-y_b= a_y\,t-\frac{1}{2} g\,t^2-\left[ b_y\,t-\frac{1}{2} g\,t^2\right]=(a_y-b_y)\,t\) which is also linear in t.

Therefore the motion of one projectile with reference to the other is a straight line (answer B)

Notice as well that this two projectiles cannot collide because they have been launched together, and supposedly at different speeds and angles. The only way that they can share the same x-coordinate and the same y-coordinate at the same time "t" is if their velocity components are equal, which is not what we are told.

\(x_a=x_b\\a_x\,t= b_x\,t\\and\\y_a= y_b\\a_y\,t-\frac{1}{2} g\,t^2= b_y\,t-\frac{1}{2} g\,t^2\\a_y\,t=b_y\,t\\a_y=b_y\)

The statements about the independent variable that are correct are:

The correct option are A, C, and E.

A variable that is independent is precisely what it sounds like. It is a stand-alone variable that is unaffected by the other variables you are attempting to assess. Age, for instance, could be an independent variable.

The dependent variable is the variable that is being measured in an experiment

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Answer:

D

Explanation:

i did that yesterday and your welcome homie b

Answer:

1323

Explanation:

we know ,

weight = m*g

= 135 * 9.8 ( acceleration due to gravity in earth is 9.8 m/S2)

= 1323 N

So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.

Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.

Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.

Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).

If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.

Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.

Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.

Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]

Electrical tape

Rubber bands

Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)

The X₅ impulsive flare has a total X-ray flux that is four times greater than the X1 long-duration flare.

The total X-ray flux for the X5 impulsive flare is:

5x10-4e⁻² W/m² * 3600 s/hour * 1 hour

= 5.4 J/m²

The total X-ray flux for the X1 long-duration flare is:

1x10⁻⁴ e-t/3 W/m² * 3600 s/hour * 1 hour

= 1.2 J/m²

As you can see, the X₅ impulsive flare has a total X-ray flux that is four times greater than the X1 long-duration flare. Therefore, the X impulsive flare is more likely to signal the beginning of a significant space weather event.

The reason for this is that the X₅ impulsive flare is a much more powerful event. It releases a much larger amount of energy in a much shorter period of time.

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Answer:

\( \rm Velocity \: is \: 0.66 \: m/s\)

Explanation:

Given :

To Find :

Solution :

Formula used :

Momentum of a body is calculated by the product of the mass and the velocity.

Here,

putting the values,

40 = 60 × v

40/60 = v

v \(\approx \)0.66 m/s

\({\underline{\rm{ Hence \: the \: required \: velocity \: is \: 0.66\: m/s}}} \)

The magnetic field generated by a current loop is given by the equation:

B = (μ0 * n * I * A) / (2 * R)

where μ0 is the permeability of free space (4π x 10^-7 T·m/A), n is the number of turns, I is the current, A is the area of the loop, and R is the distance from the center of the loop to the point where the magnetic field is measured.

In this case, we want to make a loop with a length of 1.30 m, so the circumference of the loop will be C = 2πr = 1.30 m, where r is the radius of the loop. Solving for r, we get:

r = C / (2π) = 1.30 m / (2π) = 0.2077 m

The area of the loop is given by A = πr^2, so:

A = π(0.2077 m)^2 = 0.1358 m^2

Now we can plug in the values given and solve for the number of turns:

0.700 T = (4π x 10^-7 T·m/A) * n * 1.20 A * 0.1358 m^2 / (2 * 0.2077 m)

Solving for n, we get:

n = (0.700 T * 2 * 0.2077 m) / [(4π x 10^-7 T·m/A) * 1.20 A * 0.1358 m^2]

n = 147.4 turns

Therefore, you need to make a current loop with 147 turns to generate a 0.700 mT magnetic field at the center of the loop using the entire 1.30 m long copper wire.

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Standard conditions refer to a specific set of temperature, concentration, and pressure values, which are commonly used in scientific experiments and calculations to provide a consistent basis for comparison.

In most thermodynamic calculations, standard conditions are defined as a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions are important because they serve as a reference point, allowing scientists to easily compare the properties and behavior of various substances under the same set of conditions.

The use of standard conditions simplifies calculations and ensures that the results are consistent across different studies. By providing a uniform reference point, researchers can focus on the effects of specific variables, such as the type of substance, its structure, or its interactions with other substances, without having to account for variations in temperature, concentration, or pressure.

To summarize, standard conditions for most thermodynamic calculations involve a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions provide a consistent basis for comparison, enabling scientists to examine the properties and behavior of various substances under the same set of conditions.

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Answer: Planets would be pulled into the sun

Explanation:

This is the correct answer.

The possible values of mJ are -7/2, -5/2, -3/2, -1/2, 1/2, 3/2, 5/2, and 7/2. The minimum angle between the total angular momentum vector and the z-axis for the 6²F7/2 state is approximately 81.79°.

(a) In the 6²F7/2 state, the total angular momentum quantum number J = 7/2. To determine the possible values of Jz, we use the formula:

Jz = mJ * ħ

where mJ is the magnetic quantum number, ranging from -J to +J in integer steps, and ħ is the reduced Planck constant. For J = 7/2, the possible values of mJ are -7/2, -5/2, -3/2, -1/2, 1/2, 3/2, 5/2, and 7/2.

(b) To determine the minimum angle (θ) between the total angular momentum vector and the z-axis, we use the relation:

cos(θ) = |Jz|/J

In this case, we want the minimum angle, so we choose the smallest possible value for |Jz|, which is 1/2 * ħ. Therefore:

cos(θ) = (1/2 * ħ)/(7/2 * ħ)

The ħ cancels out:

cos(θ) = 1/7

Taking the inverse cosine, we find:

θ ≈ 81.79°

So, the minimum angle between the total angular momentum vector and the z-axis for the 6²F7/2 state is approximately 81.79°.

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Main Answer: The force exerted by the ceiling on the hook is 40N.

Supporting Question and Answer:

How does the radius of the pulley affect the force exerted by the ceiling on the hook?

The radius of the pulley does not directly affect the force exerted by the ceiling on the hook. The force exerted by the ceiling is determined by the weight of the weights and the tension in the cord, which is dependent on the weight alone. The radius of the pulley only influences the mechanical advantage of the system, affecting the distribution of forces between the weights and the tension in the cord. However, regardless of the pulley's radius, the force exerted by the ceiling will always be half the weight of the weights.

Body of the Solution: To determine the force exerted by the ceiling on the hook, we need to consider the forces acting on the system.

Let's assume that the two weights are labeled as W1 and W2. W1 is connected to the pulley on one side, and W2 is connected to the other side. The force exerted by the ceiling on the hook is equal to the tension in the cord.

Considering the equilibrium of forces:

1.For W1:

2.For W2:

Since the pulley is frictionless, there are no torque or rotational forces to consider.

Now, let's analyze the system using the given information:

The tension in the cord is the same on both sides. Let's call it T. Since the cord is light and flexible, it doesn't contribute any significant weight or force.

For W1:

Downward force: W1

Upward force: T

For W2:

Downward force: W2

Upward force: T

Since the pulley is in equilibrium, the sum of the clockwise and counterclockwise torques must be zero.

The torque due to W1 is given by:

τ1 = (W1)(r)

The torque due to W2 is given by:

τ2 = (W2)(r)

Since the torques are equal and in opposite directions:

τ1 = τ2

W1r = W2r

Therefore, W1 = W2

Given that the two weights are equal, we can label their weight as W.

For both W1 and W2:

Downward force: W

Upward force: T

Now, we can set up an equation using Newton's second law for the vertical motion of the weights:

For W1:

W - T = m1a, where m1 is the mass of W1

For W2:

W - T = m2a, where m2 is the mass of W2

Since W1 = W2 = W, we can rewrite the equations as:

W - T = W1a

W - T = W2a

Combining these equations, we get:

W - T = W1a = W2a

Simplifying further, we have: 2T = W

Therefore, the tension in the cord (T) is equal to half the weight of the weights (W).

Now, we can determine the force exerted by the ceiling on the hook, which is equal to the tension in the cord. Thus, the force exerted by the ceiling is half the weight of the weights.

the force exerted by the ceiling on the hook is equal to half the weight of the weights, which in this case is 40.0 N.

Final Answer:Therefore,in this case the force exerted by the ceiling on the hook is 40N.

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Yes, as of September 2021, fossil fuels still dominated the energy consumption in the United States, with solar power accounting for only about 2.3% of the total energy consumption. This statement was true.

Despite the rapid growth of solar power in recent years, traditional fossil fuels like oil, natural gas, and coal continue to be the primary sources of energy in the country, powering industries, transportation, and homes. However, there is a growing push towards renewable energy sources, driven by concerns over climate change and a desire to reduce dependence on foreign energy sources. Many states and the federal government have implemented policies and incentives to promote the adoption of renewable energy sources like solar power, which is expected to continue to grow in the coming years.

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Answer:

Sketch the situation.

b. Calculate the potential energy, the kinetic energy, and the total energy of the car as it leaves the cliff.

c. Make a graph displaying the kinetic, gravitational potential, and total energy of the car at each 10 m

increment of height as it drops

Explanation:

The potential energy of the car at that position is 10.6 x 10⁵ J.

Potential energy of an object is defined as the energy acquired by the object by virtue its position.

Here,

Mass of the car, m = 1200 kg

Speed of the car, v = 29 m/s

Height of the cliff, h = 90 m

Therefore,

Potential energy of the car, PE = mgh

PE = 1200 x 9.8 x 90

PE = 10.6 x 10⁵ J

Hence,

The potential energy of the car at that position is 10.6 x 10⁵ J.

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no clue what the question is but pop off i guess

Answer: (from top to bottom)

350 N, 80 kg, 10 m/s^2, 80 kg, -15 m/s^2, -3000 N

Explanation:

Force = Mass*Acceleration (aka F = ma)

Using algebra, you can find the variables/unknown values.

Answer:

Because the Earth is EXTREMELY massive

Explanation:

Average speed = total distance/total time.

To calculate the width of a single slit that produces its first minimum at 60.0° for 620 nm light, we can use the formula:

sinθ = (mλ)/w

Where θ is the angle of the first minimum, m is the order of the minimum (which is 1 for the first minimum), λ is the wavelength of the light, and w is the width of the slit.

Rearranging the formula, we get:

w = (mλ)/sinθ

Substituting the given values, we get:

w = (1 x 620 nm)/sin60.0°

Using a calculator, we can find that sin60.0° is approximately 0.866. Substituting this value, we get:

w = (1 x 620 nm)/0.866

Simplifying, we get:

w = 713.8 nm

Therefore, the width of the single slit that produces its first minimum at 60.0° for 620 nm light is approximately 713.8 nm.

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Explanation:

Number of nucleons

= no of protons + no of neutrons

= 8 + 8

= 16

Atomic number = no of protons = 8

Atomic mass = 15.999