A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0400 kg bullet to accelerate it to a speed of 575 m/s in a time of 4.80 ms (milliseconds)

Answer:

7 1/2m/s/s

Explanation:

37-22=15

15/2=7 1/2

The principles which allow aircraft to fly are also applicable in car racing. The only difference being the wing or airfoil shape is mounted upside down producing downforce instead of lift. The Bernoulli Effect means that: if a fluid (gas or liquid) flows around an object at different speeds, the slower moving fluid will exert more pressure than the faster moving fluid on the object. The object will then be forced toward the faster moving fluid. The wing of an airplane is shaped so that the air moving over the top of the wing moves faster than the air beneath it. Since the air pressure under the wing is greater than that above the wing, lift is produced. The shape of the Indy car exhibits the same principle. The shape of the chasis is similar to an upside down airfoil. The air moving under the car moves faster than that above it, creating downforce or negative lift on the car. Airfoils or wings are also used in the front and rear of the car in an effort to generate more downforce. Downforce is necessary in maintaining high speeds through the corners and forces the car to the track. Light planes can take off at slower speeds than a ground effects race car can generate on the track. An Indy ground effect race car can reach speeds in excess of 230 mph using downforce. In addition the shape of the underbody (an inverted wing) creates an area of low pressure between the bottom of the car and the racing surface. This sucks the car to road which results in higher cornering speeds.

The total aerodynamic package of the race car is emphasized now more than ever before. Teams that plan on staying competitive use track testing and wind tunnels to develop the most efficient aerodynamic design. The focus of their efforts is on the aerodynamic forces of negative lift or downforce and drag. The relationship between drag and downforce is especially important. Aerodynamic improvements in wings are directed at generating downforce on the race car with a minimum of drag. Downforce is necessary for maintaining speed through the corners. Unwanted drag which accompanies downforce will slow the car. The efficient design of a chassis is based on a downforce/drag compromise. In addition the specific race circuit will place a different demand on the aerodynamic setup of the car.

A road course with low speed corners, requires a car setup with a high downforce package. A high downforce package is necessary to maintain speeds in the corners and to reduce wear on the brakes. This setup includes large front and rear wings. The front wings have additional flaps which are adjustable. The rear wing is made up of three sections that maximize downforce.

The speedway setup looks much different. The front and rear wings are almost flat and are used as stabilizers. The major downforce is found in the shape of the body and underbody. Drag reduction is more critical on the speedway than on other circuits. Since the drag force is proportional to the square of the speed, minimizing drag is a primary concern in the speedway setup. Lap speeds can average over 228 mph and top speeds can exceed 240 mph on a speedway circuit. Effective use of downforce is especially pronounced in highspeed corners. A race car traveling at 200 mph. can generate downforce that is approximately twice its own weight.

Generating the necessary downforce is concentrated in three specific areas of the car. The ongoing challenge for team engineers is to fine tune the airflow around these areas.

Answer:

formula

Explanation:

Answer:

A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves.

Explanation: hope that helps :)

The moment when the coffee filter fall from the upward, it is in the equilibrium.

A coffee filter is falling through the air after being released from a specific height. The filter accelerates for a time and rotates a bit so that the bottom of the filter is facing down, but then reaches a terminal velocity. Now, it is continuing to fall at a constant speed without tipping or rotating. When it is falling from the height, the gravitational force acting on it and the air resistance acting on it balances out each other. Then there is no net force on the coffee filter that is acting on it either ways. When the filter is going downwards many are the forces they are working on it, but when it is going down all the forces acting on it got cancel out and only the net forces acting on majorly cancel each other effect and it nullifies them and their effect and we got a net zero force on it. Hence, we can conclude that at the moment, when the coffee filter is falling from the height the forces are balance out and there is no net force and the coffee cup is in equilibrium.

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Answer:

ball b has the greater mass.

Explanation:

b only moved because a bumped into it. if a bounced back, it had less mass and b moved slowly.

Answer:

Explanation:

Since we are looking at speed over a time unit, we have an acceleration graph. The definition of acceleration mathematically is:

\(a=\frac{v_f-v_0}{t}\) (that's the change in velocity over the change in time). The slope of any line in this graph wil represent the acceleration. Slope is rise over run, or y over x. Therefore, if acceleration is velocity over time, then the y axis is the velocity axis and the x axis is the time axis. It makes perfect, beautiful sense!!

The velocity of the car before it began to accelerate is 36.6 m/s.

The initial velocity of the car is calculated by applying the third kinematic equation.

v² = u² - 2as

where;

When the car stops, the final velocity, u will be equal to zero.

v² = u² - 2as

0 = u² - 2as

u² = 2as

u = √ (2as)

u = √ ( 2 x 3.2 x 210 )

u = 36.6 m/s

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Answer:

Explanation:

Fascia is loose connective tissue that surrounds and interpenetrates all components of the human body including muscles, nerves, blood vessels, and organs. It provides structural integrity, serves as a matrix for intercellular communication, and is involved in biochemical and bioelectric signaling.

Explanation:

You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east.

Answer:

1.1259*10^9 Newton per Columb

Explanation:

the magnitude of the electric field intensity can be calculated using the expresion below;

E=Kq/r^2

Where k= constant

q= electric charge

r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency

:,K=59*10^9 Columb

If we substitute the value into above formula we have

E=(9*10^9)*(5*10^-3)/(20*10^-2)^2

=1.1259*10^9 Newton per Columb

Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb

Answer:

Spring tides occur when the moon is full or new. Earth, the moon, and the Sun are in a line. The moon’s gravity and the Sun’s gravity pull Earth’s crust and ocean water. This causes tides to be higher than normal.

At neap tide, the moon and the Sun are at right angles to each other. This happens during the first and third quarters of the lunar cycle. At neap tide, the Sun’s gravity and the moon’s gravity are balanced. High tides are lower; low tides are higher.

1. Wave number can be calculated by using the formula:

k = 2π/λ, where λ is the wavelength of the wave.

The equation of the wave is y(x,t) = 2 cos(300t + 0.6x).

Comparing with the standard equation of wave:

y(x,t) = A cos(kx - ωt + φ)

Hence, the wave number, k, which is equal to 0.6.

2. The angular frequency, ω, is given by the formula:

ω = 2πf, where f is the frequency of the wave.

Hence, the angular frequency is 300 radians per second.

3. The speed of the wave, v, is given by the formula:

v = λf = ω/k

The speed of the wave is:

v = (2π/0.6) * (1/300)

v ≈ 35.4 m/s

4. The direction of the wave can be determined by looking at the coefficient of x in the equation:

y(x,t) = 2 cos (300t + 0.6x)

Since the coefficient of x is positive, the wave is traveling in the positive x direction.

5. The frequency of the wave, f, is given by the formula:

f = ω/2π

Therefore, the frequency is 300/2π ≈ 47.7 Hz.

6. The amplitude of the wave is

7. The frequency is already determined above in part 5

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Answer:

Reverberation is created when a sound produced in a sapce is reflected off surfaces, like walls, teh floor or the ceiling. ... The time it takes for this sound in the space to decrease in volume down to 60 decibels (practically silence) after the sound source is extinguished is its reverberation time.

Answer:

Magnetic field is the strength of magnetism created by a magnet, whereas the magnetic force is the force due to two magnetic objects. The concepts of magnetic field and magnetic force are widely used in fields such as classical mechanics, electromagnetic theory, field theory and various other applications.

Explanation:

A gas dissolves in a liquid most rapidly when under High pressure.

An example of a high pressure boiler is one that produces energy in thermal power plants that runs at 80 bars or more. They produce electricity by turning water into steam through thermal energy using water-filled tubes in a metal tank or enclosure, which is then utilized to power machinery. There is a higher likelihood of leaks occurring in the system if the boiler pressure is too high. The system won't function as well if the boiler pressure is too low, though. For your system to effectively heat your home, it is crucial to maintain the proper boiler pressure.

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Answer:

0.441

Explanation:

life is great :))

In the given problem, a centrifugal water pump is given that is designed to operate at 1300 rpm and has inlet and outlet dimensions with some given values. Parameters Radius, r (mm)Blade width, b (mm)Blade angle, β (deg)Inlet10010β=40Outlet1757.

The volume flow rate is 35 L/s. Now, we need to draw the inlet velocity diagram at this volume flow rate.The inlet velocity diagram is shown in the figure below;In the figure, we can see that the blade angle, β = 40º and the entering velocity has no tangential component when the inlet blade angle is 65º. Now, we need to draw the outlet velocity diagram and determine the outlet absolute flow angle.The outlet velocity diagram is shown in the figure below;From the figure, we can see that the outlet absolute flow angle, β2 = 10.22º.

Now, we need to evaluate the hydraulic power delivered by the pump, if its efficiency is 75 percent.The hydraulic power delivered by the pump can be calculated as Where;ρ = Density of water = 1000 kg/m³Q = Volume flow rate = 35 L/s = 0.035 m³/sH = Head developed by the pumpThe efficiency of the pump is given as 75%. Therefore,η = 75/100 = 0.75Now, the head developed by the pump can be calculated .

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The first step is to convert the parallax angle of the star to distance. We can use the formula: parallax angle in arc seconds = (distance to star in parsecs)^-1 We can rearrange this equation to isolate distance: d = (parallax angle)^-1 Therefore, the distance to the star in parsecs is:

d = (0.0190 arcseconds)^-1 = 52.6 parsecs Next, we need to find the actual distance in meters. One parsec is equivalent to 3.09 × 10^16 meters. Therefore, the distance to the star in meters is: distance = (52.6 parsecs)(3.09 × 10^16 meters/parsec) = 1.63 × 10^18 meters Now, we can use the formula for time: d = vt Solving for time: t = d/v We are told to travel at half the speed of light, which is v = 0.5c, where c is the speed of light.

Therefore, the time to travel to the star is: t = (1.63 × 10^18 meters)/(0.5c) Using the speed of light, c = 3.00 × 10^8 m/s, we get: t = (1.63 × 10^18 meters)/(0.5 × 3.00 × 10^8 m/s)t ≈ 10.9 years Therefore, it would take about 10.9 years to travel to the star if traveling at half the speed of light.

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Answer:

See explanation

Explanation:

Observe, question, research, hypothesize, experiment, review hypothesis, report results.

By the time the universe was a few minutes old, the majority of the normal matter in the universe was hydrogen, and the remainder was mostly helium.

During the first few minutes after the Big Bang, the universe was hot and dense enough for nuclear fusion to occur. The high temperature and pressure allowed protons and neutrons to combine to form helium nuclei. This process, known as Big Bang nucleosynthesis, produced roughly three-quarters of the universe's helium, with the remaining quarter being produced by fusion in the cores of stars. The majority of the remaining matter in the universe after this process was hydrogen, with only trace amounts of other elements such as lithium and beryllium.

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Answer:

Students should realize that each atom in a group has the same number of electrons in its outermost energy level. For instance, hydrogen, lithium, sodium, and potassium all have 1 electron on their outer energy level. Let students know that these electrons in the outermost energy level are called valence electrons.

Answer:

22 mins and 30 seconds

Explanation:

2m in 1 min so:

45m in x mins Cross multiply

2x = 45

x = 45/2

x=22.5

v(speed) = wavelenght x frequency

v = 0.579 m x 4 hz = 2.32 m/s

Answer:

The speed of the ball can be found using the formula:

v = sqrt(Fc / m) = sqrt(23 N / 0.48 kg) = sqrt(23 / 0.48) m/s

v = approximately 4.53 m/s

The speed of the ball is approximately 9.01 m/s.

The centripetal force acting on a moving object in a circular path is given by the formula:

F = (mv²) / r

where F is the force, m is the mass of the object, v is its speed, and r is the radius of the circular path.

In this case, we know the mass of the ball is 0.48 kg, the centripetal force acting on the ball is 23 N, and the radius of the circular path is 1.7 m. Solving the formula for v, we get:

v = sqrt((Fr) / m)

Plugging in the given values, we get:

v = sqrt((23 N * 1.7 m) / 0.48 kg)

v = sqrt(81.167) m/s

v ≈ 9.01 m/s

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The net force acting on a 1.0-kg ball moving at a constant velocity will be zero

Since , ball is moving at a constant velocity , that means there is no acceleration as acceleration is equal to change in velocity divided by time . Here velocity is constant hence no change in velocity is taking place .

since, there exist no acceleration which means there exist no external force . Hence , net force on the ball is zero in this system .

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1) When the block is released from a height of h/2, the conservation of energy principle can be used to find its speed at the bottom of the inclined plane. The potential energy at the top of the inclined plane is mgh/2, where m is the mass of the block and g is the acceleration due to gravity. At the bottom of the inclined plane, all of the potential energy is converted into kinetic energy, so:

(1/2)mv´² = mgh/2

where v´ is the speed of the block at the bottom of the inclined plane. Solving for v´, we get:

v´ = sqrt(gh)

The speed of the block at the bottom of the inclined plane is therefore proportional to the square root of the height from which it is released. Since sqrt(h/2) < sqrt(h), we can conclude that v´ < v/2. Therefore, the new speed of the block at the bottom of the plane is less than half of the original speed.

2) The potential energy at the top of the inclined plane is mgh, and the kinetic energy at the bottom of the inclined plane is (1/2)mv². The total mechanical energy of the system is the sum of the potential and kinetic energies, so:

Total mechanical energy at the top = mgh

Total mechanical energy at the bottom = (1/2)mv²

3)If the system is defined as the block-Earth, the potential energy at the top of the inclined plane is still mgh, but the potential energy at the bottom of the inclined plane is now 0 (since the block is at ground level). The kinetic energy at the bottom of the inclined plane is (1/2)mv², so:

Total mechanical energy at the top = mgh

Total mechanical energy at the bottom = (1/2)mv²

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We can see that v´ is less than v/2. When the block is released from a lower height, it has less potential energy, and thus less kinetic energy at the bottom of the plane.

What is Kinetic Energy?

It is a scalar quantity that depends on both the mass and speed of the object. The formula for kinetic energy is KE = 1/2 mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity (speed) of the object.

The potential energy of the block when it is released from a height h is given by mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the inclined plane. When the block reaches the bottom of the plane, all of its potential energy is converted to kinetic energy, given by (1/2)mv^2, where v is the speed of the block at the bottom.

If the block is released from a height of h/2, then its potential energy when it reaches the bottom of the plane is (1/2)mgh. Since the potential energy at the bottom of the plane must equal the kinetic energy, we have:

(1/2)mgh = (1/2)mv´^2

Simplifying and solving for v´, we get:

v´ = sqrt(gh)

We can express this in terms of v by noting that the potential energy of the block is proportional to the height h, so when the block is released from a height of h/2, it has half as much potential energy as when it is released from a height of h. Therefore:

v´ = sqrt((1/2)gh) = sqrt((1/2)(2gh/2)) = sqrt(gh/2)

Comparing v´ to v/2, we have:

v´ = sqrt(gh/2) = (sqrt(g/2)) * sqrt(h)

Since v = sqrt(2gh) from the initial setup, we can rewrite the above equation as follows:

v´ = (sqrt(g/2)) * (v / sqrt(2gh))

Simplifying and cancelling terms, we get:

v´ = v/sqrt(2)

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