A block has 73 kg is being pushed and accelerated at rate of 10 m/s. what force is being applied to the block?

A-730 N
B-7.3 N
C-7300 N
D-730 Kg

The rate of the given reaction is 0.00197 M/s.

The balanced chemical equation of the reaction is:

CO (g) + NO₂ (g) → CO₂ (g) + NO (g)

From the equation, 1 mole of CO produces 1 mole of CO₂, and hence the number of moles of CO2 produced is equal to the number of moles of CO consumed.

The concentration of CO₂ produced = 0.123 M.

Therefore, the concentration of CO consumed is also 0.123 M.

The rate of reaction is given by the formula:

where Δ[C] is the change in concentration and Δt is the change in time.

Over 62.3 seconds, the concentration of CO decreases from 0 M to 0.123 M.

Δ[C] = 0.123 M - 0 M

Δ[C]  = 0.123 M

Δt = 62.3 s

Substituting the values in the formula, we get:

rate of the reaction = Δ[C]/Δt

rate of the reaction = 0.123 M/62.3 s

rate of the reaction = 0.00197 M/s

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answer and explanation

7.5x10⁹ - 2.5x10⁸ = 7.25x10⁹

the coefficent is 7.25

the exponent is 9

Explanation:

The first step of the Hydrogen fusion process: a nucleus of Deuterium (2H) is formed from two protons with the emission of an antielectron and a neutrino. The basic Hydrogen fusion cycle involves four Hydrogen nuclei (protons) and two electrons and yields a Helium nucleus, two neutrinos and six photons.

Answer:

C just took it

Explanation:

Answer: A. HNO3

Explanation:

4) The volume of the HCl used is 9.500 mL while the volume of the NaOH used is 3.800 mL.

5) Molarity of sodium hydroxide is obtained from; Molarity of HCl * 1/2

By reacting an unknown component with a known quantity of a different chemical known as a titrant, titration is a laboratory procedure used to measure the concentration of an unknown substance, often a solute dissolved in a liquid.

The endpoint of a titration can be detected in a number of ways, depending on the specific titration being performed.

4)

Volume of the Acid used = Initial reading - Final reading = 25.00 - 15.50 = 9.500 mL

Volume of the base used = 8.80 - 5.00 = 3.800 mL

5)

We know that the mole ratio is 1:2 and the implication of this is that the set up to obtain the molarity of the sodium hydroxide solution is Molarity of HCl * 1/2

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Answer:

Explanation:

where are the anwser choices

Answer:

First part: volume of HNO3 solution = 51.4 mL

Second part: mass of CO2 = 0.170 g

Explanation:

First part:

Based on the volume and concentration of the  Na2CO3  solution, there is 3.86  mmol  of  Na2CO3  available to react with  HNO3 . Considering the stoichiometric relationship, you then calculate the volume of a 0.150  M  solution that contains 7.71  mmol  of  HNO3 .

51.4 mL

Second part:

Since the reactant and product have a stoichiometric relationship that is 1:1, 0.00386  mol  of  Na2CO3  can react to form 0.00386  mol  of  CO2 . The molar mass of  CO2  (44.01  g/mol ) is then used to convert the moles to the corresponding mass in grams.

0.170 g

Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

The change that will cause a chemical reaction to speed up is increasing the surface area of a solid reactant.

A chemical reaction involves the formation of product (s) by the collision of reactant molecules.

However, a chemical reaction can be caused to speed up i.e. occur more rapidly.

The factors that can cause a chemical reaction to speed up are as follows:

Therefore, the change that will cause a chemical reaction to speed up is increasing the surface area of a solid reactant.

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Answer:

D

Explanation:

The sound gets louder

Answer:

D. The sound gets louder.

Answer:

P2 = 1125 mmHg

Explanation:

Gas Pressure Calculation

To solve this problem, we need to use the combined gas law, which relates the pressure, volume, and temperature of a gas under different conditions. The combined gas law is given by:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature.

Let's start by calculating the initial conditions:

P1 = 750 mmHg

V1 = 120 cm^3

T1 = 25°C + 273.15 = 298.15 K (temperature in Kelvin)

Now we can plug in these values and solve for P2:

(P1V1)/T1 = (P2V2)/T2

(750 mmHg x 120 cm^3) / 298.15 K = (P2 x 150 cm^3) / (40°C + 273.15)

Simplifying this equation, we get:

P2 = (750 mmHg x 120 cm^3 x (40°C + 273.15)) / (298.15 K x 150 cm^3)

P2 = 1125 mmHg

Therefore, the pressure of the gas would increase to 1125 mmHg if its volume increased to 150 cm^3 at 40°C.

ChatGPT

1. The pressure increases when the volume decreases

2. A solid has a fixed volume and is not compressible

3. The volume of 1 mol of an ideal gas is 22.4 L

4. Solid molecules do not move. (Option A)

5. Temperature and volume have a direct relationship

6. Pressure and volume have an indirect relationship

7. The equation to be used is option C

8. The equation to be used is option B

Gas laws serve as a foundation for comprehending gas behavior and have a variety of uses, including industrial operations, gas storage, and the investigation of atmospheric phenomena.

It's vital to keep in mind that these gas laws are based on the assumption that gases behave in an ideal way and consist of infinitely small particles that do not interact with one another. Under specific circumstances, the behavior of actual gases may differ from these idealized connections.

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Potash alum, represented by the chemical formula KAl(SO4)2·12H2O, is a double salt because it consists of two different salts, potassium sulfate (K2SO4) and aluminum sulfate (Al2(SO4)3), combined together. It forms a unique crystalline structure with 12 water molecules incorporated in its composition.

Potash alum is a type of alum that is commonly used in dyeing and water purification applications. The chemical formula for alum is KAl(SO4)2·12H2O.

The term "double salt" refers to the fact that the compound is made up of two different types of ions that are combined together.
In the case of potash alum, the two different types of ions are potassium ions (K+) and aluminum ions (Al3+). These two ions are combined together in a 1:1 ratio to form a complex ion, KAl(SO4)2, which is then combined with 12 water molecules to form the final compound, KAl(SO4)2·12H2O.
The term "double salt" is used to describe this type of compound because it contains two different types of cations (positive ions) that are combined together to form a single crystal lattice structure.

The two different cations are held together by ionic bonds, which are relatively strong and help to give the compound its characteristic properties.
Potash alum is a particularly useful compound because it has a number of important properties that make it useful in a variety of applications.

For example, it is highly soluble in water, which makes it a good choice for use in water purification applications.

It is also relatively stable and non-toxic, which makes it safe to use in a variety of different settings.

Finally, it has a number of useful physical properties, such as its ability to form crystals that are highly reflective and have a characteristic octahedral shape.

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The percent ionization of an acidic solution can be calculated from the H+ concentration. the percent ionization of the monoprotic acid of 0.141 M is 18.23 %.

Percent ionization of an acidic solution is the percent of H+ ions in the solution. Thus, mathematically, it is the ratio of H+ ion concentration to the concentration of solution multiplied by 100.

Let HA be the monoprotic acid when it ionizes, forming equal concentration of H+ and A- let it be x. Thus ionization  constant can be written as follows:

Ka = [x]² /[HA]

0.00469 =[x]²/[0.141 M]

   [X] = 0.025. = [H+]

Percentage ionization  = (0.025 M / 0.141 M)× 100

                                      = 18.23 %

Therefore percentage ionization of the acid is 18.23%.

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A polystyrene cup is used to minimise  the thermal energy loss because polystyrene cup is acts as a very good insulator.

It is important to use polystyrene cup to minimise thermal energy loss because it prevent the heat energy loss as it has air bubbled trapped inside them. if we hold a hot coffee in a polystyrene cup , the hot coffee does not burn your finger because it is a bad conductor of heat. it is a natural insulator. we can also use this styroform or polystyrene idea to make home warm in cold region , it reduce the transfer of heat ,so  that building stays warmer.

We can use plastic foam to reduce heat energy loss .  Both polystyrene and plastic foams are the good insulators and bad conductor of heat.

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we need to add 0.20 moles of HCl to 1 liter of the buffer solution to achieve a pH of 8.56.

The Henderson-Hasselbalch equation for the buffer system is:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant for ammonium ion (NH4+), [A-] is the concentration of ammonia (NH3), and [HA] is the concentration of ammonium ion (NH4+).

The pKa for NH4+ is 9.25, so:

pH = 9.25 + log([NH3]/[NH4+])

Substituting the given concentrations, we get:

8.56 = 9.25 + log([NH3]/0.96)

log([NH3]/0.96) = -0.69

[NH3]/0.96 = 0.21

[NH3] = 0.20 M

The balanced chemical equation for the reaction between HCl and NH3 can be used to determine how much HCl is necessary to reach this new concentration:

HCl + NH3 → NH4+ + Cl-

Calculating the amount of HCl required to convert some of the NH3 to NH4+ is all that is necessary because the buffer solution already includes NH4+ and Cl-. The required amount of NH4+ is:

[NH4+] = [NH3] = 0.20 M

The amount of  HCl is needed is

0.20 mol NH3 × 1 mol HCl/1 mol NH3 = 0.20 mol HCl

Therefore, we need to add 0.20 moles of HCl to 1 liter of the buffer solution to achieve a pH of 8.56.

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Answer:

identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas

identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas

Explanation:

identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas

The balanced equation for the given reaction is:

4 Si4C3 + 15 O2 → 8 Si2O3 + 3 C

What is Balanced Chemical Equation?

The coefficients in a balanced chemical equation represent the stoichiometric relationship between the reactants and products. They show the relative amounts of each substance that are involved in the reaction. In the given chemical equation, Si4C3 + O2 -> Si2O3 + C, the coefficients can be determined by balancing the number of atoms of each element on both sides of the equation.

Starting with Si, there are 4 Si atoms on the left and 2 Si atoms on the right, so a coefficient of 2 is needed in front of Si2O3 to balance the number of Si atoms.

Moving on to C, there are 3 C atoms on the left and 1 C atom on the right, so a coefficient of 3 is needed in front of C to balance the number of C atoms.

Finally, for O, there are 2x3=6 O atoms on the left and 2x2=4 O atoms on the right, so a coefficient of 3 is needed in front of O2 to balance the number of O atoms.

The balanced equation is thus: Si4C3 + 3O2 -> 2Si2O3 + 3C, with coefficients of 1, 3, 2, and 3 for Si4C3, O2, Si2O3, and C, respectively.

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Explanation

Given:

Mass of N2 = 42 g

Balanced chemical reaction: N2 + 3H2 → 2NH3

We know the molar mass of N2 = 28.0134 g/mol

the molar mass of NH3 = 17,031 g/mol

Required: Mass of NH3 that will be produced

Solution:

Step 1: Calculate the moles of N2

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 42g/28.0134 g/mol

n = 1.499 mol

Step 2: Use the stoichiometry to calculate the moles of NH3

The molar ratio between N2 and NH3 is 1:2

Therefore the moles of NH3 = 1.499 mol x 2 = 2.998 mol

Step 3: Use the moles to calculate the mass of NH3

m = n x M

m = 2.998 mol x 17,031 g/mol

m = 51 g

Answer

B. 51 g

In the given equation 5.96 L of O2 will be produced.

What is chemical equation?

A chemical equation is a symbolic representation of a chemical reaction that shows the reactants on the left side and the products on the right side, with the coefficients indicating the relative amounts of each substance involved. It follows the law of conservation of mass, which states that mass cannot be created or destroyed in a chemical reaction.

The balanced equation for the reaction is:

2Li₂O(s) → O₂(g) + 4Li(s)

From the equation, we can see that 2 moles of Li₂O produces 1 mole of O₂. We can use this ratio to convert the mass of Li₂O to moles of O₂

First, we need to calculate the number of moles of Li₂O:

n(Li₂O) = m/M

where m is the mass of Li₂O and M is the molar mass of Li₂O. The molar mass of Li₂O is:

M(Li₂O) = 2(M(Li) + M(O)) = 2(6.941 g/mol + 15.999 g/mol) = 45.88 g/mol

Plugging in the values, we get:

n(Li₂O) = 25 g / 45.88 g/mol = 0.544 mol

According to the balanced equation, 2 moles of Li₂O produce 1 mole of O2. So, the number of moles of O2 produced is:

n(O2) = 0.544 mol / 2 = 0.272 mol

Finally, we can convert the number of moles of O2 to liters using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Assuming the reaction occurs at standard temperature and pressure (STP), which is 0°C (273.15 K) and 1 atm, we can simplify the equation to:

V = nRT/P

Plugging in the values, we get:

V = (0.272 mol) (0.08206 L·atm/mol·K) (273.15 K) / 1 atm = 5.96 L

Therefore, we can expect 5.96 L of O2 to be produced.

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Answer:

Prueba con tus argumentos quienes sufren mas con la violencia?

Answer:

Sure! The complete balanced chemical equation for the reaction you provided is: `2A + BC3 -> AC2 + 3B`.

The balanced redox reaction in the chemical reaction is given below:

40H2S + 48H+ + 16MnO4¯ ---> 5S8 + 16Mn2+ + 64H2O

Balancing the redox reaction:

Solution:

1) Half-reactions:

H2S ---> S8

MnO4¯ ---> Mn2+

2) Balance:

8H2S ---> S8 + 16H+ + 16e¯

5e¯ + 8H+ + MnO4¯ ---> Mn2+ + 4H2O

3) Make the number of electrons equal (note that there are no common factors between 5 and 16 except 1):

40H2S ---> 5S8 + 80H+ + 80e¯ <--- factor of 5

80e¯ + 128H+ + 16MnO4¯ ---> 16Mn2+ + 64H2O <---

factor of 16

4) Thus, the final answer is given below;

40H2S + 48H+ + 16MnO4¯ ---> 5S8 + 16Mn2+ + 64H2O

Oxidation-reduction can simply be defined as a special type of chemical reaction in which the oxidation states of the substrate change.

So therefore, the balanced redox reaction in the chemical reaction is given below:

40H2S + 48H+ + 16MnO4¯ ---> 5S8 + 16Mn2+ + 64H2O

Complete question:

Balance the following redox reaction:

MnO4¯ + H2S ---> Mn2+ + S8

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The ratio of ions in the given ionic compound, 2 Na₃PO₄ is 6 : 2.

Ions are substances formed when atoms of elements gain or lose or lose electrons.

In some instances, the group of atoms may come together and react as one unit and these are called radicals.

Ionic compounds are formed when two oppositely charged ions are held together by electrostatic forces of attraction.

The ions in the given ionic compound, 2 moles of Na₃PO₄, are as follows;

2 * 3 moles of Na⁺ = 6 moles

2 * 1 mole of PO₄ = 2 moles

The ratio of ions = 6 : 2

The ratio of ions = 3 : 1

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Answer:

lungs

Explanation:

From the given data, the name of the hydrated salt would be  \(CoCl_2.83H_2O\).

The formula of the hydrated salt can be determined using the empirical formula approach. That is, we will find the mole equivalent of the anhydrous salt and the water of hydration and then combine them into a single formula after dividing by the smallest mole.

First, we need to determine the mass of the anhydrous salt and the water of hydration.

Mass of crucible (x) = 12.090 g

Mass of hydrated salt + crucible (y) = 16.250 g

Thus, the mass of the hydrated salt can be determined by subtracting x from y.

Mass of hydrated salt = 16.250 - 12.090 = 4.16 g

Mass of hydrate + crucible after evaporating off the water (z) = 12.424 g

Mass of anhydrous salt = z - x

                                      = 12.424 - 12.090

                                      = 0.334 g

Mass of water = 4.16 - 0.334

                        = 3.826 g

Now, let's find the moles:

Molar mass of \(CoCl_2\) = 129.839 g/mol

Molar mass of water = 18.01 g/mol

Mole of \(CoCl_2\) = 0.334/129.839 = 0.00257 mol

Mole of water = 3.826/18.01 = 0.2124 mol

Dividing through by the smallest mole

\(CoCl_2\) =  0.00257 / 0.00257  = 1

water = 0.2124/ 0.00257 = 83

Thus, the formula of the hydrate would be \(CoCl_2.83H_2O\)

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Answer:

Two molecules of hydrogen combine with two molecules of oxygen to form hydrogen peroxide. Hence, its chemical formula is H2O2. It is the simplest peroxide (since it is a compound with an oxygen-oxygen single bond). Hydrogen peroxide has basic uses as an oxidizer, bleaching agent and antiseptic

Answer:

7.71 × 10⁻⁴ M/s

Explanation:

The initial rate of the reaction can be expressed by using the formula:

\(\dfrac{\Delta [O_2]}{\Delta t}\)

where the number of moles of O₂ = \(\dfrac{PV}{RT}\)

where;

Pressue P = 1.00 atm

Volume V =5.74mL =  (5.74 /1000) L

Rate R = 0.082 L atm/mol.K

Temperature = 298 K

\(= \dfrac{1.00 \ atm \times \dfrac{5.74 }{1000}L}{0.082 \ L \ atm/mol.K \times 298 K}\)

= 2.35 × 10⁻⁴ mol

Δ[O₂] = \(\dfrac{moles \ produced - initial \ mole}{\dfrac{5.08 }{1000}L }\)

Δ[O₂] = \(\dfrac{2.35 \times 10^{-4} M - 0 M}{\dfrac{5.08 }{1000}}\)

Δ[O₂]  = 0.04626 M

The initial rate = \(\dfrac{\Delta [O_2]}{\Delta t}\)

= \(\dfrac{0.04626}{60}\)

= 7.71 × 10⁻⁴ M/s

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