6 - 4 2/7 =
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Answer:

I think it's y=x+2 if not then I'm sorry

Answer: y=x-7

Step-by-step explanation:

Here’s the photo of my explanation, if it helps

The given problem is asking for a test to see if the sample mean is significantly different from 85 at the 0.05 level. To solve the problem, we can use the following formula:$$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$$where$\bar{x}$ = sample mean$\mu$ = population mean$s$ = sample standard deviation$n

$ = sample sizeTo calculate the t-value, we need to calculate the sample mean and the sample standard deviation. The sample mean is calculated as follows:$$\bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}$$where $x_i$ is the score of the $i$th student and $n$ is the sample size.

Using the given data, we get:$$\bar

{x} = \frac{78+89+67+85+90+83+81+79}{8}

= 81.125$$The sample standard deviation is calculated as follows:$$

s = \sqrt{\frac{\sum_{i=1}^{n} (x_i - \bar{x})^2}{n-1}}$$Using the given data, we get:$$

s = \sqrt{\frac{(78-81.125)^2+(89-81.125)^2+(67-81.125)^2+(85-81.125)^2+(90-81.125)^2+(83-81.125)^2+(81-81.125)^2+(79-81.125)^2}{8-1}}

= 7.791$$Now we can calculate the t-value as follows:$$

t = \frac{\bar{x} - \mu}{\frac{s}

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Answer:

The average rate will be: -4

Hence, option A is correct.

Step-by-step explanation:

Given the interval

0 ≤ x  ≤ 2

From the graph, it is clear that:

at x₁ = 0, f(x₁) = 3

at x₂ = 2,  f(x₂) = -5

Using the formula to determine the average rate of change:

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                      = [-5 - 3] / [2-0]

                      = -8 / 2

                     = - 4

Therefore, the average rate will be: -4

Hence, option A is correct.

Answer:

Height - 12.692 in

Step-by-step explanation:

Answer:

A = 1/2 bh

Step-by-step explanation:

Replace are and base to get:

82.5 = 1/2 x 15 x height

Multiply both sides by 2:

165 = 15 x height

Divide both sides by 15:

Height = 165 / 15

Height = 11 inches.

Answer:

3/10 of the total distance to her grandmother's house was traveled on Sunday

Step-by-step explanation:

Carly's family traveled distance of Saturday = \(\frac{3}{10}\)

Remaining distance =\(1-\frac{3}{10}=\frac{7}{10}\)

They traveled 3/7 of the remaining distance on Sunday.

So, Distance traveled on Sunday =\(\frac{3}{7}(\frac{7}{10})\)

Distance traveled on Sunday =\(\frac{3}{10}\)

Fraction of the total distance to her grandmother's house was traveled on Sunday =\(\frac{3}{10}\)

Hence 3/10 of the total distance to her grandmother's house was traveled on Sunday

Based on the total amount that Danielle sold last week, the amount that she earned from her commission and base salary was $1,087.75

Danielle gets a total earning of both her commission which is 8.25% on goods sold, and a base salary of $700 per week.

In the given week, she sold $4,700 which means that the commission was:

= 4,700 x 8.25%

= $387.75

This means that Danielle's total earnings for the week was:

= 700 + 387.75

= $1,087.75

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Answer:

B)Yes, all four conditions in BINS have been met.

Step-by-step explanation:

Yes, all four conditions in BINS have been met.

Conditional probability is defined as the likelihood of an event or outcome occurring, based on the occurrence of a previous event or outcome. Conditional probability is calculated by multiplying the probability of the preceding event by the updated probability of the succeeding, or conditional, event.

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Answer:

\(\overline{GB}\) = 9

Step-by-step explanation:

The given parameters are;

The point of intersection of the perpendicular bisectors of the sides \(\overline{BC}\), \(\overline{BA}\), and \(\overline{CA}\) intersect (meet) at point G

Let D represent the point of intersection of the perpendicular bisector from G to \(\overline{BC}\), we have for ΔBGD and ΔCGD;

\(\overline{GD}\) ≅ \(\overline{GD}\) by reflexive property

∠GDB = ∠GDC = 90° given that \(\overline{GD}\) is the perpendicular bisector of \(\overline{BC}\)

Similarly, \(\overline{DB}\) ≅ \(\overline{DC}\), also given that  \(\overline{GD}\) is the perpendicular bisector of \(\overline{BC}\)

Therefore;

ΔBGD ≅ ΔCGD by Side-Angle-Side (SAS) rule of congruency

\(\overline{GB}\) ≅ \(\overline{GC}\)   by Congruent Parts of Congruent Triangles are Congruent, (CPCTC)

\(\overline{GB}\) = \(\overline{GC}\) = 9 by definition of congruency

∴ \(\overline{GB}\) = 9.

The 7 inches pen would not fit in the box with dimensions 3 in × 4 in × 5 in

The 7 inches long pen would not fit in a box with dimensions of 3 inches x 4 inches x 5 inches because the dimensions of the box are not long enough to accommodate the length of the pen.

Specifically, the length dimension of the box (3 inches) is less than the length of the pen (7 inches), so the pen would not be able to fit inside the box.

Additionally, even if the length of the box was greater than 7 inches, the width and height dimensions of the box (4 inches and 5 inches, respectively) would likely be too small to accommodate the diameter of the pen.

In conclusion, the pen is too long for the box, and the box is not wide or tall enough to fit the pen.

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Answer:

7

Step-by-step explanation:

x+5=12

x=12-5

x=7

The measure of the angle m∠HEF = 64°, for the diagonals of rectangular room.

The given data:

As, GE is the straight line.

Thus,

m∠EHF = 180 - 128 (sum of all angles of line is 180, linear pair)

            = 52°

Now,

m∠HEF = 180 - 52 / 2 (isosceles triangle)

m∠HEF = 64°

Thus, the measure of the angle m∠HEF = 64°, for the diagonals of rectangular room.

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The diagram for the question is attached.

The appropriate answer is option E: X,Y Joint Constant Density of 2 Random Variables over a Region.

The given scenario states that X and Y have a constant joint density on the triangle where OSX SY51. This means that the joint density of X and Y is constant over the given region. The correct option that applies to this situation is E. X,Y Joint Constant Density of 2 Random Variables over a Region. Because, options A, B, and D do not fit the scenario as they involve uniform, Bernoulli, and uniform functions of a random variable, respectively. Option C involves a discrete uniform random variable, which does not match the continuous nature of the given problem. Option F involves two discrete random variables with joint mass, which again does not fit the continuous nature of the problem.

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Step-by-step explanation:

plz give brainlyest

4* 53+1/(8-5)^3

4(54)/(8−5)3

4(54/3^3)

4(54/27)

(4)(2)=8  the answer is 8

Answer:

Add 53 + 1

Step-by-step explanation:

24-x-24=-16-24

1. Subtract the numbers

-x=-16-24

2. -x=-16-24

-x=-40

3.Divide both sides of the equation by the same term

-x=-40

-x/-1=-40/-1

4. simplify

x=40

The term for the probability that a value falling outside the control limits is still due to normal variation is called the Type I error or the alpha error.

The term for the probability that a value falling outside the control limits is still due to normal variation is called the Type I error or alpha error.

It refers to the probability of rejecting a true null hypothesis (in this case, the process is in control) when it should not be rejected. In other words, it is the probability of concluding that there is a problem with the process when there is actually no problem, and the observed value is simply a result of random variation.

This means that the value appears to be abnormal, but it is actually just a result of the natural variation in the process. It is important to minimize the risk of Type I errors to ensure that only truly abnormal values are addressed and corrected.

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Answer:

r = 6

Step-by-step explanation:

Distribute -2 to (6 - 6r):

7r + 18 = -12 + 12r

Subtract 7r from both sides of the equation:

7r + 18 - 7r = -12 + 12r - 7r

18 = -12 + 5r

Add 12 to both sides of the equation to isolate 5r:

18 + 12 = -12 + 5r + 12

30 = 5r

Divide both sides of the equation by 5 to isolate r:

\(\frac{30}{5} = \frac{5r}{5}\)

6 = r

To double check whether the value of r = 6 is correct, plug it into the original equation:

7r + 18 = -2(6 - 6r)

7(6) + 18 = -2[6 - 6(6)]

42 + 18 = -12 + 72

60  = 60

The price at which the total quantity supplied is 250 is $11.58.

In order to find the price at which the total quantity supplied is 250, we need to equate the total quantity supplied by both producers (Supply 1 and Supply 2) and solve for the price.

Supply 1: P = 6 + 0.7Q

Supply 2: P = 16 + 0.6Q

To find the equilibrium price, we set the total quantity supplied equal to 250:

0.7Q + 0.6Q = 250

1.3Q = 250

Q = 250 / 1.3 ≈ 192.31

Now that we have the quantity, we can substitute it back into either supply function to find the price. Let's use Supply 1:

P = 6 + 0.7Q

P = 6 + 0.7 * 192.31

P ≈ 6 + 134.62

P ≈ 140.62

Therefore, the price at which the total quantity supplied is 250 is approximately $11.58.

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Answer:

length = \(8\frac{1}{6}\) inches

Step-by-step explanation:

A rectangle is a quadrilateral which has opposite sides to be equal.

Area of a rectangle = length × width

Given that: Area = \(36\frac{3}{4}\) square inches, width = \(4\frac{1}{2}\) inches, length = l. Thus;

\(36\frac{3}{4}\) = l × \(4\frac{1}{2}\)

\(\frac{147}{4}\)  = l × \(\frac{9}{2}\)

divide both sides by \(\frac{9}{2}\),

l = \(\frac{147}{4}\)  ÷  \(\frac{9}{2}\)

 = \(\frac{147}{4}\)   x \(\frac{2}{9}\)

 = \(\frac{49}{6}\)

l  = \(8\frac{1}{6}\)

Therefore, the length of the rectangle is \(8\frac{1}{6}\) inches.

To calculate the probability that the sample proportion does not exceed 0.16, we use the normal distribution and assume that the true proportion is 10%. The sample size is 119 grocery shoppers. The answer should be provided as a number accurate to four decimal places.

To calculate the probability, we need to standardize the sample proportion using the standard error formula for proportions:

Standard Error = sqrt[(p * (1-p)) / n]

Where p is the assumed true proportion (10%) and n is the sample size (119). Plugging in the values:

Standard Error = sqrt[(0.10 * (1-0.10)) / 119] ≈ 0.0301

Next, we calculate the z-score using the formula:

z = (x - p) / Standard Error

Plugging in x = 0.16 (sample proportion), p = 0.10, and the calculated Standard Error:

z = (0.16 - 0.10) / 0.0301 ≈ 1.9934

Finally, we find the probability using the standard normal distribution table or calculator. The probability that the sample proportion does not exceed 0.16 is approximately 0.9767.

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Answer:

71

you just had to add them

Step-by-step explanation:

a) The x-range of a unit square is from o to 1 and y-range is also from 0 to 1

Sample space = {(x, y)} , 0≤x≤1,  0≤y≤1.

So, sample space associated with this random experiment is

{(x, y)} , 0≤x≤1,  0≤y≤1.

b) From the given data,

Sample space for A : {1, 3, 5, 7, 9, 11,...}

Sample space for B: {5, 10, 15, 20, 25,...}

Therefore, the sample space for A∩B will be the set of all odd natural numbers divisible by 5 which is

{5, 15, 25, 35,....}

c) First letter is the capital letter = 26 Possibilities

then four digits = 9*10*10*10

two lower case letters = 26*26

Total possible ways = 26*9*10*10*10*26*26

= 15,81,84,000 ways.

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Complete question:

Suppose a point is to be selected at random from the unit square. Write the sample space associated with this random experiment. 2. Let S = {0, 1, 2, 3, 4, ...), A = the set of odd natural numbers, and B = the set of natural numbers divisible by 5. What is the set An B? 3. A computer password consists of two lowercase letters followed by a capital letter and four digits. Find the total number of possible passwords.

30% of students mean 30 students wear contact lenses from a random selection of 100 students studying in a university.

Percentage is a fraction or a ratio of a random sample in which the value of whole is always 100. For example, if Sam received 30% on his arithmetic test, he received 30 points out of 100. It is expressed as 30/100 in fractional form and 30:100 in ratio form.

Percentage is defined as a certain fraction or number out of a hundred. It is a fraction with the denominator 100, and the sign for it is "%."

Finding the proportion of a whole in terms of 100 is the goal of percentage calculations. There are two methods to calculate a percentage:

Use the unitary approach or try adjusting the fraction's denominator to 100.

How to solve?

30 % = 30/100 of a sample = 0.3 of a sample

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Vasco's optimal bundle, we need to maximize his utility function U = 10x²z subject to his budget constraint.

His budget constraint can be written as:10x + 2z = 150

To solve this problem, we can use the method of Lagrange multipliers. The Lagrangian function is:L = 10x²z + λ(150 - 10x - 2z)

Taking the partial derivatives with respect to x, z, and λ, and setting them equal to zero, we have:

∂L/∂x = 20xz - 10λ = 0        (1)

∂L/∂z = 10x² - 2λ = 0          (2)

∂L/∂λ = 150 - 10x - 2z = 0    (3)

From equation (1), we have: 20xz = 10λ              (4)

From equation (2), we have: 10x² = 2λ                (5)

Dividing equation (4) by equation (5), we get:

(20xz) / (10x²) = (10λ) / (2λ)

2z / x = 5

Rearranging the equation, we have:

z = 5x / 2

Substituting this into equation (3), we have: 150 - 10x - 2(5x / 2) = 0

Simplifying the equation, we get: 150 - 10x - 5x = 0

15x = 150

x = 10

Substituting the value of x into z = 5x / 2, we have:

z = 5(10) / 2

z = 25

Therefore, the optimal bundle for Vasco is x = 10 units of X and z = 25 units of Z.

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The proababilities are: i) P(Aᶜ) = 0.6, ii) P(Bᶜ) = 0.4

iii) Probability that exactly one of the events A, B occurs = 0.7

Let A and B be any two disjoint events such that P(A) = 0.4 and P(A ∪ B) = 0.7. We need to find the following probabilities:

i) P(Aᶜ): This is the probability of the complement of event A, which represents the probability of not A occurring. Since A and B are disjoint, Aᶜ and B are mutually exclusive and their union covers the entire sample space.

Therefore, P(Aᶜ) = P(B) = 1 - P(A) = 1 - 0.4 = 0.6.

ii) P(Bᶜ): This is the probability of the complement of event B, which represents the probability of not B occurring. Since A and B are disjoint, Bᶜ and A are mutually exclusive and their union covers the entire sample space.

Therefore, P(Bᶜ) = P(A) = 0.4.

iii) Probability that exactly one of the events A, B occurs: This can be calculated by subtracting the probability of both events occurring (P(A ∩ B)) from the probability of their union (P(A ∪ B)).

Since A and B are disjoint, P(A ∩ B) = 0.

Therefore, the probability that exactly one of the events A, B occurs is P(A ∪ B) - P(A ∩ B) = P(A ∪ B) = 0.7.

To summarize:

i) P(Aᶜ) = 0.6

ii) P(Bᶜ) = 0.4

iii) Probability that exactly one of the events A, B occurs = 0.7

Note: The provided values of P(A), P(A ∪ B), and the disjoint nature of A and B are used to derive the above probabilities.

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Answer: We can see that it has a parabola for its graph, so we can say that f(x) is a quadratic function. This means that f(x) has a parent function of y = x2.

Step-by-step explanation:

(Hope this helped Btw not mine)

Answer:

Absolute value parent function

Step-by-step explanation:

GIVEN:

We are given a circle with center A and diameter CB.

The length of arc CDB is 14;

Required;

We are required to calculate the lenght of the radius.

Step-by-step solution;

The length of an arc with the central angle measured in radians is;

The length of the arc is given, so also is the angle theta (180 degrees, that is half the circle).

We can convert the degree measure of the angle into radians as follows;

Now we substitute the value of d (degree measure);

Now we take the formula for the length of an arc as follows;

Divide both sides by pi;

Therefore, the radius is

ANSWER:

a. The amount of their adjusted gross income is $48,515.

b. Diego and Dolores should itemize deductions in the amount of $10,425 to minimize taxable income.

c. Their taxable income is $38,090.

d. Without the specific year's tax brackets and rates, the exact tax liability can not be provided.

We have,

a. To calculate the adjusted gross income (AGI), we need to subtract the deductions from their total income:

Total income = Salaries + Interest income

Total income = $49,300 + $875

Total income = $50,175

Adjusted gross income = Total income - Deductions for adjusted gross income

Adjusted gross income = $50,175 - $1,660

Adjusted gross income = $48,515

b. To minimize taxable income, Diego and Dolores should choose the higher value between the standard deduction for married filing jointly ($12,700) and their itemized deductions ($10,425).

Therefore, they should itemize deductions in the amount of $10,425.

c. Taxable income is calculated by subtracting deductions (either standard or itemized) from the adjusted gross income:

Taxable income = Adjusted gross income - Deductions

Taxable income = $48,515 - $10,425

Taxable income = $38,090

d. To determine the tax liability, we need to refer to the tax brackets and rates for the specific year.

Since the information provided does not specify the year, It is unable to provide the exact tax liability.

Tax brackets and rates can vary from year to year.

Thus,

a. The amount of their adjusted gross income is $48,515.

b. Diego and Dolores should itemize deductions in the amount of $10,425 to minimize taxable income.

c. Their taxable income is $38,090.

d. Without the specific year's tax brackets and rates, the exact tax liability can not be provided.

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