Answer:
1.7333333m/s²
Explanation:
Tension of the line = the weight + force from pulling up the fish
30N = mg + ma
30 = (6)(9.8) + (6)a
10.4 = 6a
∴ a = 1.7333333m/s²
You are fishing and catch a fish with a mass of 6 kg. If the fishing line can withstand a maximum tension of 30 N, the maximum acceleration is 1.7333333 m/s².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
Tension of the line = the weight + force from pulling up the fish
30 N = mg + ma
30 = (6)(9.8) + (6)a
10.4 = 6 a
a = 1.7333333 m/s²
You are fishing and catch a fish with a mass of 6 kg. If the fishing line can withstand a maximum tension of 30 N, the maximum acceleration is 1.7333333 m/s².
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A car is traveling at a steady 71 km/h in a 50 km/h zone. A police motorcycle takes off at the instant the car passes it, accelerating at a steady 7.5 m/s2.
a. How much time elapses before the motorcycle is moving as fast as the car?
b. How far is the motorcycle from the car when it reaches this speed?
(a) The time elapses before the motorcycle is moving as fast as the car is 2.6296 second.
(b) The motorcycle is 25.93 meter far from the car when it reaches this speed.
What is acceleration?Acceleration is rate of change of velocity with time. Si unit of acceleration is meter/second² (m/s²).
Speed of the car = 71 km/h = 71 ×5/18 m/s = 19.722 m/s.
Acceleration of the police motorcycle = 7.5 m/s²
Hence, Time taken by the motorcycle to be as fast as the car = 19.722 ÷ 7.5 s
= 2.6296 second.
The distance between the motorcycle and the car
= (19.722×2.6296 - 1/2×7.5 × 2.6296²) meter
= 25.93 meter.
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A person walks 5 meters to the east, then turns and walks 7 meters south.
What is their total displacement?
Answer:
8.6 meters to south east
Explanation:
Displacement is change in position or a distance between initial position to final position.
Since a person walks to east and then to the south, it forms a right triangle path. We can use Pythagoras Theorem to help finding the displacement:
\(\displaystyle{\vec s = \sqrt{s_x^2 + s_y^2}}\)
Where \(\displaystyle{\vec s}\) is displacement, \(\displaystyle{s_x}\) is horizontal distance (east) and \(\displaystyle{s_y}\) is vertical distance (south). Therefore:
\(\displaystyle{\vec s = \sqrt{5^2 + 7^2}}\\\\\displaystyle{\vec s = \sqrt{25+49}}\\\\\displaystyle{\vec s = \sqrt{74}}\\\\\displaystyle{\vec s = 8.6 \ \, \sf{meters \ \, to \ \, south \ \, east}}\)
Therefore, the displacement is 8.6 meters to south east.
(The attachment is added for visual reference on displacement and direction.)
There are caps that accompany the boomwhacker tubes, which change the sound of the note we are hearing. Explain how this works (the underlying physics), using a visual with a written description accompanying it.
The caps used with boomwhacker tubes alter the sound of the notes by changing the effective length of the air column inside the tube.
This modification affects the fundamental frequency produced when the tube is struck or tapped against a surface.The fundamental frequency determines the pitch of the sound we hear.
When a boomwhacker tube is struck without any cap, the air column inside vibrates at its natural frequency, producing a specific pitch. By adding caps to the tube, we effectively shorten its length, which increases the frequency of the vibrations and raises the pitch. Conversely, removing caps increases the effective length, lowering the frequency and lowering the pitch.
To visualize this, imagine a tube with a cap on one end. The cap acts as a barrier, preventing the air column from vibrating in that direction. Therefore, the effective length of the tube becomes the distance between the cap and the open end. This shorter length results in a higher pitch. Removing the cap increases the effective length, resulting in a lower pitch.By using different combinations of caps on the boomwhacker tubes, we can produce a range of pitches, creating a musical and colorful experience.
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how is the side of the construction paper with sunblock lotion different from the side without sunblock lotion
Answer:
The side of the paper with sunblock lotion stays on its the same color/tone while the other side of the paper without sunblock lotion faded
Explanation:
Ultraviolet (UV) radiation from the sun is the main cause of skin cancer, so one of the best ways to prevent skin cancer is to protect your skin from sun exposure with the use of sunscreen/sunblock. The sunlight that reaches us is made up of two types of harmful rays: long waves (UVA) and short waves (UVB)
1. A book resting on a shelf was found
to have a gravitational potential energy
of 12 J relative to the ground. If the
book falls to the ground, neglecting air
resistance, what is the kinetic energy of
the book just as it was about to hit the
ground?
Answer:
12J
Explanation:
Right before it hits the ground, the initial potential energy and the final kinetic energy will equal each other due to conservation of energy.
if something is frictionless does it have thermal energy
Answer:
No
Explanation:
because there is no pressure
An electron gun shoots electrons at a metal plate that is 4.0 mm away in a vacuum. The plate is 5.0 V lower in potential than the gun. How fast must the electrons be moving as they leave the gun if they are to reach the plate?
The speed of the electron is 1.3 * 10^6 m/s
What is the velocity?We know that when the electron gun is shot, the potential energy of the electron is converted into kinetic energy. The mass of the electron is given as 9.11 * 10^-31 Kg.
The energy of the electron is;
eV = 1e * 5V = ev or 8 * 10^-19 J
Given that E = 1/2mv^2
8 * 10^-19 = 0.5 * 9.11 * 10^-31 * v^2
v = √ 8 * 10^-19/0.5 * 9.11 * 10^-31
v = √1.75 * 10^12
v = 1.3 * 10^6 m/s
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7) A 2 kg cart rolls down a frictionless ramp. It starts with 58.8 J of energy at the top of the ramp. How fast would the cart be moving when it is halfway (in height) down?
Answer:
The problem is asking one to assume that the potential energy at the top of the ramp is 58.8 J and the potential bottom is zero:
then 1/2 m v^2 = 29.9 J or 1/2 the energy - one cannot solve for v without knowing a value for KE
v^2 = 58.8 / 2 = 29.9
v = 5.47 m/s
(if the cart had any KE at the top of the ramp then one cannot solve the problem because the speed of the cart is not defined)
A free falling object starts from rest. After 3 seconds, it will have a speed of about
Answer: 30 m/s
hope this helps
Two loudsspeakers emit identical sound waves along the x axis. THe osund at a point on the axis has maximum intensity when the speakers are 40 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 50 cm. If the distance between the speakers continuse to increase, at what separation will the sound intensity again be a maximum?
Answer: 30 cm.
Solving
The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.
When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.
If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:
d = λ/2 + nλ
where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.
At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:
λ = 2(d_max - d_min) = 20 cm
Substituting λ and n into the formula gives:
d = λ/2 + nλ = 10 cm + 20 cm = 30 cm
Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.
Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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The diagram below shows two waves. At which letter (A-D) on the diagram is constructive interference going to occur?
A. A
B. B
C. C
D. D
At A and C, there is constructive interference occur.
constructive interference happens when two waves are in phase, right?Constructive interference happens when the maxima of two waves combine (the waves are in phase), resulting in a wave whose amplitude is equal to the total of the amplitudes of the separate waves. In a similar way, the wave minima would line up.
Where may one find constructive interference?The intersection of the lines (indicating peaks) is when constructive interference happens. To put it another way, when two waves are in phase, they interact positively. When two waves are fully out of phase (their peak is in the middle), destructive interference happens.
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What type of image can be larger or smaller than the object?
A. An expansion
B. A magnification
C. A reduction
D. An enlargement
Calculate the temperature at which the root-mean-square speed of oxygen molecules will have the value of 640 m/s. [1 kilomole of oxygen has a mass of 32kg].
The temperature of the oxygen atom would be obtained as 525507 Kelvin.
What is the root mean square velocity?We know that a sample of a substance is composed of so many molecules of the substance. When we are trying to obtain the average speed that all the molecules of the substance has, we call it the root mean square speed.
Given that;
v = √3RT/M
R = gas constant
T = temperature of the gas
M = molar mass of the gas
640 = √3 * 8.314 * T/32
(640)^2 = 3 * 8.314 * T/32
(640)^2 * 32/ 3 * 8.314 = T
T =525507 Kelvin
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A 6 kg blue ball rolls across the ground and collides with a stationary 1 kg red ball.
Before the collision the blue ball moved right with a speed of 4 m/s, and after the
collision it moved left with a speed of 1 m/s. If the red ball was not moving before the
collision, how fast is it moving after the collision?
The final velocity of the red ball is 18 m/s.
What is momentum?The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.
Then;
Mass of the blue ball = 6 kg
Mass of the red ball = 1 kg
Initial velocity of the blue ball = 4 m/s
Initial velocity of the red ball = 0 m/s
Final velocity of the red ball = ??
Final velocity of the blue ball = 1 m/s
We now have;
(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)
24 = v + 6
v = 24 - 6
v = 18 m/s
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A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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(Figure 1) shows a container with a cross-section area of 15 cm^2 in which a layer of water floats on top of a layer of mercury. A 1.0 kg wood block with a cross-section area of 10 cm^2 floats on the water. The water depth, measured from the bottom of the block, is 25 cm. A pressure gauge at the bottom of the container reads 26 kPa.
A container with vertical walls is filled with a layer of mercury of height h at the bottom and a layer of water above it. A rectangular block of 1.0 kilogram floats on the water. The distance from the mercury layer to the bottom side of the block is 25 centimeters. The area of the horizontal cross section of the block is 10 square centimeters. The area of the bottom of the container is 15 square centimeters. A pressure gauge is located at the bottom of the container.
Part A
What is the depth dm of the mercury? Use ρw = 1000 kg/m3 as the density of water and ρm = 13,600 kg/m3 as the density of mercury.
Pressure gauge is located at the bottom of the container thus, the depth of the mercury = 11.05 cm
What is pressure?Pressure refers to the force applied on a unit area of a surface. It works parallel to the pressure-applied surface. Pressure = force multiplied by the area on which it operates. The stronger the power, the smaller the area.
Given that,
pressure exerted by block (\(P_{B}\))= weight / cross-section area of block
\(P_{B}\) = (1 ×9.81) ÷ (10 × 10⁻⁴)
= 9810 Pa
Now, pressure at bottom of container is given as:
\(P_{Bottom}\) = \(P_{B}\) + ρ × g × h + ρ₁ × g × h₁
[ ρ = density of water,
ρ₁ = density of Hg,
h = height of water and
h₁ = height of Hg ]
Thus, 27000 = 9810 + (1000 × 9.81 × 0.25) + (13600 × 9.81 × h₁)
h₁ = 14737.5 ÷ 133416
h₁ = 0.1105 m
h₁ = 11.05 cm
Thus, depth of the mercury = 11.05 cm.
So, the depth of the mercury = 11.05 cm
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PLEASE HELP !!!!!! As seen in the lesson video, solar photovoltaic technologies help provide clean electrical energy. Using the video animation as a guide, diagram and label the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems. Include a screenshot or picture of your diagram below.
We can see here that the diagram that reveals the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems is seen below.
What is photon?A photon is a fundamental particle or quantum of light.
It is the smallest indivisible unit of electromagnetic radiation, which also includes radio waves, microwaves, X-rays, visible light, ultraviolet light, and infrared radiation. In scientific calculations, photons are represented by the symbol "c" and move at the speed of light in a vacuum while carrying energy.
Wave-particle duality is the idea that photons are both particles and have wave-like characteristics. This means that they can exhibit wave-like properties like interference and diffraction as well as discrete particle behavior, each with a distinct energy and momentum.
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The figure below shows a small, charged bead, with a charge of q = +37.0 nC, that moves a distance of d = 0.192 m from point A to point B in the presence of a uniform electric field E of magnitude 285 N/C, pointing right.
What is the magnitude (in N) and direction of the electric force on the bead?
What is the work (in J) done on the bead by the electric force as it moves from A to B?
What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.)
What is the potential difference (in V) between A and B?
a. The magnitude of the electric force on the bead is 1.0545 × 10⁻⁵ N and its direction is to the right.
b. The work done on the bead is 2.025 × 10⁻⁶ J
c. The change in electric potential energy (in J) as the bead moves from A to B is -2.025 × 10⁻⁶ J
d. The potential difference (in V) between A and B is -60 V
a. What is the magnitude (in N) and direction of the electric force on the bead?The magnitude of the electric force on the charge is given by F = qE where
q = charge on bead = +37.0 nC = +37.0 × 10⁻⁹C and E = magnitude of electric field = 285 N/CSo, substituting the values of the variables into the equation, we have
F = qE
F = 37.0 × 10⁻⁹C × 285 N/C
= 10545 × 10⁻⁹ N
= 10.545 × 10⁻⁶ N
= 1.0545 × 10⁻⁵ N
Since the electric field is pointing to the right and the charge is positive, so, the direction of the electric force is to the right.
So, the magnitude of the electric force on the bead is 1.0545 × 10⁻⁵ N and its direction is to the right.
b. What is the work (in J) done on the bead by the electric force as it moves from A to BThe work done on the bead by the electric force is W = Fd where
F = electric force = 1.0545 × 10⁻⁵ N and d = distance moved by bead = 0.192 mSo, substituting the values of the variables into the equation, we have
W = Fd
= 1.0545 × 10⁻⁵ N × 0.192
= 2.02464 × 10⁻⁶ J
≅ 2.025 × 10⁻⁶ J
So, the work done on the bead is 2.025 × 10⁻⁶ J
c. What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.)From work-energy principles, the work done by the bead, W equal the change in electric potential energy of the bead ΔU.
ΔU = -W
Since W = 2.025 × 10⁻⁶ J
ΔU = -W
= -2.025 × 10⁻⁶ J
So, the change in electric potential energy (in J) as the bead moves from A to B is -2.025 × 10⁻⁶ J
d. What is the potential difference (in V) between A and B?The potential difference between A and B is given by ΔV = ΔU/q where
ΔU = electric potential energy change = -2.025 × 10⁻⁶ J and q = charge on bead = +37.0 × 10⁻⁹CSo, substituting the values of the variables into the equation, we have
ΔV = ΔU/q
ΔV = -2.025 × 10⁻⁶ J/37.0 × 10⁻⁹C
= -0.06 × 10³ V
= -60 V
So, the potential difference (in V) between A and B is -60 V
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Can anyone please help me answer this question?
Two particles A and B move into the region between charged parallel plates, A is an electron and B is a proton. Thus, option D is correct.
The electric field between the charged conductors is obtained by the ratio of potential difference and distance between two plates. When the plates are connected to a battery, one plate acquires a positive charge and another plate acquires a negative charge. The electric field lines pass from positive to negative plates.
From the given diagram, the field lines pass from the positive to the negative plate. Unlike charges are attract each other. The particle A attracts towards the positive plate and hence it is the electron. The particle B attracts towards the negative plate and hence it is a proton.
Thus, the ideal solution is option D.
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Which of the following is a physical property? 1.flammability 2.acidity 3.color 4.rusting
Answer:
Color is a physical property, the rest are chemical properties.
A battery has an emf of ε = 15.0 V. THe terminal voltage of the battery is Vt = 11.6 V when it is delivering P = 20.0 W of power to an external load resistor R. (a) What is the value of R? (b) What is the internal resistance r of the battery?
AnswerHM???
Explanation:
I dONT KNOW
Chase grew up wanting to wear his sister's dresses over his brother's pants and button up shirts. When Chase turns 18, he decides to begin living as woman, though he's still only sexually attracted to women. He decides he doesn't want to undergo surgery. Chase is
Explanation:
she is a woman, i dont understand why youre still using he/him after she comes out
An ant sits on the back of a mouse. The mouse carries the ant across the floor for a distance of 150m to her bedroom. How much work did the mouse do?
Answer:
Since the weight of the ant is not given, we cannot determined the work done.
Explanation:
Given parameters:
Distance covered = 150m
Unknown:
Work done by mouse = ?
Solution:
To solve this problem, we need to understand that work done is the force applied to move a body through a certain distance.
In this case, work done;
Work done = force x distance
Work done = Weight x distance
Since the weight of the ant is not given, we cannot determined the work done.
When two positive charges are brought close together, what happens to the
field lines of the charges?
Answer:
they will move away from each other
Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place
Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.
Why is it colder at the bottom of the pool than the top of the pool?
There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;
Heat transfer by radiationHeat transfer by convection Heat transfer by radiationThe surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.
Heat transfer by convectionThe heat from the air is transferred to the pool through convection.
Thus, these two heat transfer processes causes the surface water of the pool to be warm which decreases with depth.
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Q3. A car is initially heading east at 55.0 km h when it turns a corner and heads N 55° Eat
65.0 km h -1. Determine the change in the velocity of the car during this time.
Answer:
37.3 km/h at N 2.70° E
Explanation:
Find the horizontal and vertical components of the initial velocity (u) and final velocity (v). Remember that N 55° E means 55° east of north.
uₓ = 55.0 km/h
uᵧ = 0 km/h
vₓ = 65.0 km/h × sin 55° = 53.24 km/h
vᵧ = 65.0 km/h × cos 55° = 37.28 km/h
Find the difference.
vₓ − uₓ = -1.76 km/h
vᵧ − uᵧ = 37.28 km/h
The magnitude is:
|v − u| = √((-1.76 km/h)² + (37.28 km/h)²)
|v − u| = 37.3 km/h
The direction is:
θ = tan⁻¹(37.28 / -1.76)
θ = 92.70°
θ = N 2.70° E
A 2.0 cm tall object is placed 25 cm in front of a converging lens. The image is found 64 cm on the other side of the lens.
The focal length of the lens is ________.
0.011 cm
0.024 cm
41 cm
0.056 cm
18 cm
15 cm
Since focal length cannot be negative for a converging lens, we take the positive value: f ≈ 41 cm Option C
To determine the focal length of the lens, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens. The lens formula is given by:
1/f = 1/v - 1/u
In this case, the object distance (u) is 25 cm and the image distance (v) is 64 cm. We can substitute these values into the lens formula to solve for the focal length:
1/f = 1/v - 1/u
1/f = 1/64 cm - 1/25 cm
To simplify the equation, we can find a common denominator:
1/f = (25 - 64) / (64 * 25)
1/f = -39 / (64 * 25)
Now, we can invert both sides of the equation to solve for the focal length:
f = (64 * 25) / -39
f ≈ -41.03 cm
Since focal length cannot be negative for a converging lens, we take the positive value:
f ≈ 41 cm
Therefore, the correct answer is option C) 41 cm.
It's important to note that in the lens formula, distances are measured with respect to the lens, with positive values indicating distances on the opposite side of the incident light. The negative value obtained for the focal length indicates that the lens is a converging lens, as expected. Option C
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Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2 as F1 = 45 N 70degree And F2 = 75 N , 20 Degree (a) Find the magnitude and direction of the force that third person should exert to stop this cart. You can ignore the effects of friction. (b) If the third person exerts the force found in part (a), the cart accelerates at 200 m/S2 in the (+) x-direction. What is the weight of the cart
Answer:
a) F₃ = 109.5 N , θ₃ = 38.35, b) m = 0.429 kg
Explanation:
For this force addition exercise, let's decompose the forces into a coordinate system
strength 1
cos 70 = F₁ₓ / F₁
sin 70 = \(F_{1y}\) / F₁
F₁ₓ = F₁ cos 70
F_{1y} = F₁ sin 70
F₁ₓ = 45 cos 70 = 15.39 N
F_{1y} = 45 sin70 = 42.29 N
Strength 2
cos 20 = F₂ₓ / F₂
sin 20 = F_{2y} / F₂
F₂ₓ = F₂ cos 20
F_{2y} = F₂ sin20
F₂ₓ = 75 cos 20 = 70.48 N
F_{2y} = 75 sin 20 = 25.65 N
a) in the first part we are asked to find the magnitude of force 3 so that the body is in equilibrium
X axis
∑ Fₓ = 0
F₁ₓ + F₂ₓ + F₃ₓ = 0
F₃ₓ = - F₁ₓ - F₂ₓ
F₃ₓ = - 15.39 - 70.48
F₃ₓ = - 85.87 N
Y Axis
∑ F_{y} = 0
F_{1y} + F_{2y} +F_{3y} = 0
F_{3y} = - F_{1y} -F_{2y}
F_{3y} = - 42.29 - 25.65
F_{3y} = - 67.94 N
the magnitude of this force can be found using the Pythagorean theorem
F₃ = √ (F₃ₓ² + F_{3y}^2)
F₃ = √ (85.87² + 67.94²)
F₃ = 109.5 N
The direction of this force can be found using trigonometry
tan θ = F₃ = \(F_{3y}\) / F₃ₓ
θ₃ = Tan⁻¹ (67.94 / (85.87))
θ₃ = 38.35º
since the two vectors are negative this angle is in the third quadrant, measured from the positive side of the x axis is
θ₃ = 180 + 38.53
θ₃ = 218.35º
b) I think you have an error in your statement, we have two possibilities:
1) If we eliminate the third force, what is the mass
it should say: "if we apply the third force force ...", they ask that we find the masses of the vehicle, let's use Newton's second law
X axis
F₁ₓ + F₂ₓ = m a
15.39 + 70.48 = m 200
m = 85.87 / 200
m = 0.429 kg
2) If the force F3 is in the first quadrant
F1x + F2x + F3x = m a
m = (15.39 + 70.48 + 85.87) / 200
m = 0.8587 kg
What is the first job u do on the ISS if u were an astronaut
If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.
What is expected at ISS?I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.
Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.
Find out more on ISS here: https://brainly.com/question/19594570
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