1.24 × 107 kilograms. Write the mass in standard notation.3

The  pressure on the upper wing surface is 4.10 x 10^3 Pa.

The lift force on an airplane wing is due to the pressure difference between the upper and lower surfaces of the wing. According to Bernoulli's principle, the pressure of a fluid decreases as its speed increases. Therefore, the air moving over the curved upper surface of the wing must have a lower pressure than the air moving over the flat lower surface of the wing.

The lift force can be calculated using the formula:

L = Cl * ρ * A * v^2 / 2

where L is the lift force, Cl is the lift coefficient, ρ is the density of the air, A is the area of the wing, and v is the speed of the air.

Since the airplane is in level flight, the lift force is equal to the weight of the airplane:

L = mg

where m is the mass of the airplane and g is the acceleration due to gravity.

We can use these two equations to find the speed of the air over the wing:

mg = Cl * ρ * A * v^2 / 2

v^2 = 2mg / (Cl * ρ * A)

v = sqrt(2mg / (Cl * ρ * A))

Let's assume that the lift coefficient is the same for both the upper and lower surfaces of the wing. Then, the lift force on each wing is:

L/2 = Cl * ρ * A * v^2 / 4

The pressure difference between the upper and lower surfaces of the wing can be found using the formula:

ΔP = 2 * (L/2) / A

Substituting the expressions for L/2 and v^2, we get:

ΔP = Cl * ρ * v^2

ΔP = Cl * ρ * (2mg / (Cl * ρ * A))

ΔP = 2mg / A

Substituting the given values, we get:

ΔP = 2 * (1.10 x 10^4 kg) * 9.81 m/s^2 / (39.0 m^2)

ΔP = 5.59 x 10^4 Pa

Since the pressure on the lower wing surface is given as 6.00 x 10^4 Pa, the pressure on the upper wing surface is:

Pupper = Plower - ΔP

Pupper = (6.00 x 10^4 Pa) - (5.59 x 10^4 Pa)

Pupper = 4.10 x 10^3 Pa

Therefore, the pressure on the upper wing surface is 4.10 x 10^3 Pa.

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The additional pressure on the air in their lungs when snorkeling down to a depth of 1.6 meters when calculated using the hydrostatic pressure formula  is option e) 15,700 N/m².

Using hydrostatic pressure formula:
P = ρgh
Where:
P is the pressure,
ρ is the density of the fluid (in this case, water),
g is the acceleration due to gravity, and h is the depth.
The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².
Plugging in the values:
P = (1000 kg/m³) * (9.8 m/s²) * (1.6 m)
Calculating this, we get:
P = 15,680 Pa
Therefore, the additional pressure on the air in their lungs when snorkeling down to a depth of 1.6 meters is approximately 15,680 Pa. Hence, the correct answer is option e) 15,700 N/m².

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a) The return on the bond when the government defaults can be calculated by considering the bond price at default (Pd) and the bond price at issuance (P). The return is given by the formula:

Return = (Pd - P) / P

b) (i) To find the range of Dt such that the bond price for this debt is the same as that for the risk-free T-Bills, we equate the bond price (P) with the risk-free rate (Rf). Since the equations for bond price are not provided, the specific range of Dt cannot be determined without additional information.

(ii) To find the range of D+ such that the bond price is zero, we set the bond price equal to zero (P = 0) and solve for D+. Without the bond price equation, it is not possible to determine the range of values.

(iii) To determine the range of D such that no investors would buy this bond in the government bond auction market, we need to consider the bond price relative to the risk-free rate. If the bond price is lower than the risk-free rate, rational investors would not be interested in buying the bond. However, without the bond price equation, it is not possible to determine the specific range of D.

c) Given it = 0, n = 0.4, Dt = 0.4, and assuming risk-neutral investors, we can calculate the probability of default (pa) on this debt and the sovereign spread.

To calculate pa, we need to integrate the probability density function (PDF) f(yt+1) over the range where default occurs (0.5 to 1.5) and divide by the total range of Yt+1 (0 to 2). Given that Yt+1 is uniformly distributed, we have:

pa = ∫[0.5,1.5] f(yt+1) dyt+1 / ∫[0,2] f(yt+1) dyt+1

Substituting the PDF f(yt+1) = 1 for 0.5 ≤ Yt+1 ≤ 1.5 and 0 otherwise, we can simplify the equation:

pa = ∫[0.5,1.5] 1 dyt+1 / ∫[0,2] 1 dyt+1

= [0.5,1.5] / [0,2]

= (1 - 0.5) / 2

= 0.25

Therefore, the probability of default (pa) on this debt is 0.25.

The sovereign spread is the difference between the interest rate on the government bond (i) and the risk-free rate on T-Bills (Rf). However, the interest rate on the government bond (i) is not provided, so the sovereign spread cannot be calculated without that information.

In summary, the return on the bond when the government defaults can be calculated based on the bond price at default and issuance. Without the bond price equation, we cannot determine the specific ranges of Dt and D+ that correspond to specific bond prices. Additionally, without the interest rate on the government bond, the sovereign spread cannot be calculated. However, given the provided parameters, we can calculate the probability of default (pa) on the debt as 0.25.

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Answer:

it is a interspecific competition

Explanation:

i just took a test with this question

Answer: If the difference in electronegativity for the atoms in a bond is greater than 0.4, we consider the bond polar. If the difference in electronegativity is less than 0.4, the bond is essentially nonpolar. If there are no polar bonds, the molecule is nonpolar

Answer:

144 Joules

Explanation:

The formula for calculating kinetic energy is KE = 1/2 mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity.

Plugging in the given values, we get:

KE = 1/2 * 32 kg * (3 m/s)^2

KE = 1/2 * 32 kg * 9 m^2/s^2

KE = 144 J

Therefore, the kinetic energy of the cat moving at a velocity of 3 m/s south would be approximately 144 Joules.

Answer:

15 m/s

Explanation:

Given:

v₀ = 25 m/s

a = -10 m/s²

t = 1.0 s

Find: v

v = at + v₀

v = (-10 m/s²) (1.0 s) + 25 m/s

v = 15 m/s

You should keep your eyes on the road and shift into neutral when gas pedal gets jammed.

In automobiles, shifting into neutral won't transmit power to the wheels and the direction of the steering wheel can still be controlled.

This helps to prevent accidents on the road as a result of such malfunctions in the car.

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Answer:

The current through the wire is equal to 0.8 A.

Explanation:

Given that,

The length of a copper wire = 2 m

Potential difference = 24 mV

The current through the wire is 0.40 A.

The new potential difference is 48 mV.

We need to find the current through the wire.

As the potential difference is doubled for second wire. So the new current will be :

I' = 2I

= 2 × 0.4

= 0.80 A

So, the current through the wire is equal to 0.8 A.

If the diameter of a wire were to increase, its electrical resistance would decrease.

The electrical resistance of a wire is directly influenced by its diameter or cross-sectional area. According to the formula for resistance:

R = ρ * (L / A),

where R represents resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

As per the formula, resistance is inversely proportional to the cross-sectional area (A) of the wire. This means that as the diameter of the wire increases, the cross-sectional area also increases, leading to a decrease in resistance.

The relationship between resistance and diameter can be understood using the concept of electron flow. In a larger diameter wire, there is more space available for electrons to flow, resulting in less obstruction to their movement. This reduces the collisions between electrons and the wire's atoms, leading to lower resistance.

It's worth noting that the resistivity (ρ) and length (L) of the wire remain constant in this scenario. If either the resistivity or the length changes, the relationship between diameter and resistance may differ.

When the diameter of a wire increases, its electrical resistance decreases. This occurs due to the larger cross-sectional area providing less obstruction to the flow of electrons, resulting in fewer collisions and a reduced resistance.

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Answer:

no yes

Explanation:

Answer:

Air temperature and air pressure both decreases

Answer: A

Explanation:

Answer:

Q = 78375 [J]

Explanation:

To solve this problem we must use the following ideal equation for the thermal energy of an element or substance depending on the temperature change.

\(Q=m*C_{p}*(T_{final}-T_{initial})\)

where:

Q = heat [J]

m = mass = 0.25 [kg]

Cp = specific heat = 4180 [J/kg*C]

Tinitial = 25[°C]

Tfinal = 100 [°C]

\(Q =0.25*4180*(100-25)\\Q = 78375 [J]\)

Answer:

Unequal access to these basics services is connected to the crime. People with poor access to education, health services, social support, and other basic services are at greater risk of not only committing a crime but committing it much more frequently. People commit crimes to meet their needs.

Answer:2.67

Explanation:

Nun

Of the given options, it is unlikely that the change in temperature of the substance would be zero over one cycle of a cyclic process. This is because in a cyclic process, the substance undergoes a series of transformations that cause changes in the internal energy, pressure, volume, and other properties.

These changes are typically accompanied by changes in temperature as the substance absorbs or releases heat. For example, in a Carnot cycle, the substance undergoes isothermal expansion and compression, during which its temperature remains constant, but then undergoes adiabatic expansion and compression, during which its temperature changes.

In contrast, the work done by the substance, the change in volume of the substance, the change in the internal energy of the substance, and the change in pressure of the substance can all be zero over one cycle of a cyclic process, depending on the specific nature of the process.

For example, if a gas undergoes a reversible isothermal expansion and compression, the work done by the gas would be zero over one cycle, since the net work done on the gas is zero. Similarly, if a gas undergoes a reversible adiabatic expansion and compression, the change in internal energy of the gas would be zero over one cycle, since the net heat added to or removed from the gas is zero.

Thus, the specific conditions of the cyclic process would determine which properties are likely to be zero over one cycle.

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The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as

Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

Generally, the equation for the Voltage is mathematically given as

v(t)=Vmax=(i-e^{-t/t})

Therefore

For t=1

V=5(i-e^{-1/10})

t=0.476v

For t=5s

V2=5(i-e^{-5/10})

t=1.967

For t=20s

V2=5(i-e^{-20/10})

V2=4.323v

Therefore, the values of voltages at the various times are

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Complete Question

A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.

Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.

Answer:

\(\boxed {\boxed {\sf E_p= 515.025 \ J}}\)

Explanation:

Potential energy is found using this formula:

\(E_p= mgh\)

The mass of the baby in the carriage is 1.5 kilograms and the height is 35 meters. Assuming this is on Earth, the gravitational acceleration is 9.81 meters per square second.

\(m=1.5 \ kg \\g= 9.81 \ m/s^2\\h= 35 \ m\)

Substitute the values into the formula.

\(E_p= (1.5 \ kg )( 9.81 \ m/s^2)(35 \ m )\)

Multiply the first numbers together.

\(E_p= 14.715 \ kg*m/s^2 (35 \ m )\)

Multiply again.

\(E_p= 515.025 \ kg*m^2/s^2\)

\(E_p= 515.025 \ J\)

The potential energy is 515.025 Joules.

Explanation:

vertical force = 460,000 * sin(70) - 300,000

Fv = 187,717.75N

Answer:

1.7 g/cm³

Explanation:

Given that:

Density of substance = 3.4 g/cm³

Relative density to another substance = 2

Density of second substance=?

Let density of second substance = x

Relative density = density of substance / density of second substance

Relative density = density of substance / x

2.0 = 3.4g/cm³ / x

2 * x = 3.4 g /cm³

x = 3.4 g/cm³ ÷ 2

x = 1.7 g/cm³

Answer:

Two objects that have equal masses head toward each other at equal speeds and then stick together. The two objects come to rest after sticking together, conserving momentum but not kinetic energy after they collide. Some of the energy of motion gets converted to thermal energy, or heat.

Explanation:

The action spectrum is broader than the absorption spectrum because it takes into account all wavelengths of light that can drive a particular biological process, not just those absorbed by a specific pigment.

The action spectrum shows the efficiency of a biological process, such as photosynthesis or vision, at different wavelengths of light. It measures the biological response to each wavelength, regardless of which pigment is responsible for absorbing the light.

On the other hand, the absorption spectrum only shows the wavelengths absorbed by a particular pigment, such as chlorophyll or rhodopsin. Therefore, the action spectrum is broader than the absorption spectrum because it considers all the wavelengths that can activate the biological process, while the absorption spectrum only shows the wavelengths absorbed by a specific pigment.

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Answer:

The answers are:

T, T, F, F, T, T, F, F, T, T, F

Good luck!

Answer:

Explanation:

Given:

F = 36 000 H

S₁ = 1 800 cm² = 0.18 m²  (The area of the base of one elephant's foot)

n = 4  (number of legs on an elephant )

______________________

p - ?

Support area:

S = n·S₁ = 4·0.18 = 0,72 m²

Pressure:

\(p = \frac{F}{S} \\p = \frac{36000}{0.72} = 112 500 Pa\)  

p ≈ 110 kPa

The mass of the car is calculated as 1021.86 kg. We can calculate the mass of the car by using the formula: mass = Force / acceleration

Given information: Acceleration of the car = 1.83 m/s²

Force acting on the car = 1870 N

We know that Force = mass × acceleration

According to the question, we need to find the mass of the car. We can calculate the mass of the car by using the formula: mass = Force / acceleration

Putting the values in the above equation, we get mass = 1870 N / 1.83 m/s²

So, the mass of the car is: mass = 1021.86 kg

Therefore, the mass of the car is 1021.86 kg.

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Answer:

The friction of braking heats up the tire and the road. The temperature is so high that it reaches the melting point of the rubber in the tire. The melting rubber is what leaves a mark on the road.

Explanation:

Answer:

the friction of braking heats up the tires and the road. then the temperature gets even hotter to the point where it melts the rubber.

Explanation:

this is my answer so be careful how you copy it, but you've got this guys schools is almost out stay strong an have fun and be safe this summer keep pushing <33.

remember you're loved by many

- Jason Edwards 5/15/23

It is a well-known fact that often applying force does not cause a change in the condition of motion. For instance, even if you use all of your force, a hefty box could not budge at all. Again, attempting to push a wall has no noticeable effect.

Because you pushed against the wall, but the wall pushed back against you with an equal and opposite force, you slide in the opposite direction (away from the wall).

Therefore, There are just two forces at work: friction and gravitation. Yes, the frictional force's magnitude must match the weight. Given that it is parallel to the wall, the friction is in the vertical direction (which is vertical)

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Answer:

Explanation:

Vm = Δs/Δt

700km/h = Δs/1.5h

700 = Δs/1.5

\(\frac{700}{1} = \frac{S}{1.5}\)

S = 700 x 1.5

S = 1050 Km

*(S = Δs)

Answer: The rocket will have traveled 1050 Km

Hope this help ☺

After 1.5 hour the rocket will have traveled 1023.54 km.

In everyday use and in kinematics, the speed (commonly referred to as v) of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.  SI unit of speed is meter/second.

Initial speed of the rocket = 700 km/hr

= 700 (1000/3600) meter/second

= 194.44 meter/second

Acceleration due to gravity is = 9.8 m/s²

Time interval is = 1.5 hour = 1.5 × 60 × 60 second

hence, after 1.5 hour the rocket will have traveled = (194.44) (1.5 × 60 × 60) - 1/2×9.8×(1.5×60×60)² meter

= 1050000 meter - 26460 meter

= 1023540 meter

= 1023.54 km.

So,  the rocket will have traveled 1023.54 km after 1.5 hour .

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