Answer:
x=57
Step-by-step explanation:
3x-8=163
3x=171
x=57
Answer:
X=57
Step-by-step explanation:
3x-8=163
3x-8+8=163+8
163+8=171
3x÷3= 171+3
Anna has a loyalty card good for a 7% discount at her local grocery store. What number should she multiply the prices on the tags by to find the price she would have to pay, before tax, in one step?
Anna should multiply the prices on the tags by 0.93 to find the price she would have to pay before tax in one step.
Given that Anna has a loyalty card good for a 7% discount at her local grocery store.
We have to find the number should she multiply the prices on the tags by to find the price she would have to pay, before tax
Anna should multiply the prices on the tags by 0.93 (which is 1 minus the 7% discount) to find the price she would have to pay before tax in one step.
For example, if an item costs $10 before the discount, Anna would pay $10 x 0.93 = $9.30 after the discount.
Hence, Anna should multiply the prices on the tags by 0.93 to find the price she would have to pay before tax in one step.
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Which pair of angles are corresponding angles?
Answer:
Corresponding Angles
Step-by-step explanation:
Both \(\angle 4\) and \(\angle 8\) are Corresponding Angles, they are in the same side of the transversal line, and where a line crosses two other lines.
Step-by-step explanation:
<4 and <8 are corresponding angles because they are on the same side of the transversal and are at the same location and they are congruent meaning they are equal
Solve the given initial-value problem. \[ X^{\prime}=\left(\begin{array}{rr} 10 & -1 \\ 5 & 8 \end{array}\right) X, \quad X(0)=\left(\begin{array}{r} -4 \\ 8 \end{array}\right) \]
The solution of the given initial-value problem is
\(\[X(t)=\left[\begin{array}{c} -2 e^{7 t}-2 e^{11 t} \\ 6 e^{7 t}+2 e^{11 t} \end{array}\right]\].\)
As per data that the initial value problem is:
X′ = [10−15 8]X, X(0) = [−48]
Let X(t) be the solution to the initial value problem (IVP). Then
\(\[X(t)=\left[\begin{array}{c} x_{1}(t) \\ x_{2}(t) \end{array}\right].\]\)
Thus
\(\[X^{\prime}(t)=\left[\begin{array}{c} x_{1}^{\prime}(t) \\ x_{2}^{\prime}(t) \end{array}\right].\]\)
The initial value problem can be written as
\(\[X^{\prime}=\left[\begin{array}{rr} 10 & -1 \\ 5 & 8 \end{array}\right] X=\left[\begin{array}{c} 10 x_{1}-x_{2} \\ 5 x_{1}+8 x_{2} \end{array}\right], \quad X(0)=\left[\begin{array}{r} -4 \\ 8 \end{array}\right].\]\)
Substituting into the initial value problem, we get
\(\[\begin{aligned} x_{1}^{\prime}(t) &=10 x_{1}(t)-x_{2}(t) \\ x_{2}^{\prime}(t) &=5 x_{1}(t)+8 x_{2}(t) \end{aligned}\]\)
Using the characteristic equation we get,
\(\[\begin{aligned} \lambda^{2}-18 \lambda+77 &=0 \\ (\lambda-7)(\lambda-11) &=0 \end{aligned}\]\)
Thus \(\[\lambda_{1}=7, \quad \lambda_{2}=11\]\)
The two eigenvectors can be found by solving the equation.
\(\[A v=\lambda v\]\)
Where A is the coefficient matrix and v is the eigenvector. The matrix equation gives two equations of the form
\(\[\begin{aligned} 10 x-1 y &=7 x \\ 5 x+8 y &=7 y \end{aligned}\]\)
which simplifies to,
\(\[3 x+y=0.\]\)
Thus \(\[y=-3 x.\]\)
Thus, the eigenvector corresponding to λ1 = 7 is
\(\[\vec{v_{1}}=\left[\begin{array}{c} 1 \\ -3 \end{array}\right].\]\)
Similarly, the eigenvector corresponding to λ2 = 11 is
\(\[\vec{v_{2}}=\left[\begin{array}{c} 1 \\ -1 \end{array}\right].\]\)
Therefore,
\(\[X(t)=c_{1} \vec{v_{1}} e^{7 t}+c_{2} \vec{v_{2}} e^{11 t}=\left[\begin{array}{r} c_{1} e^{7 t}+c_{2} e^{11 t} \\ -3 c_{1} e^{7 t}-c_{2} e^{11 t} \end{array}\right].\]\)
Now we use the initial condition X(0) = [-4 8] to find the constants c₁ and c₂.
\(\[\begin{aligned} X(0) &=\left[\begin{array}{r} c_{1}+c_{2} \\ -3 c_{1}-c_{2} \end{array}\right]=\left[\begin{array}{r} -4 \\ 8 \end{array}\right] \\ c_{1}+c_{2} &= -4 \\ -3 c_{1}-c_{2} &= 8 \end{aligned}\]\)
Solving this system of equations, we get c₁ = -2 and c₂₂ = -2.
Therefore, the solution of the given initial-value problem is.
\(\[X(t)=\left[\begin{array}{c} -2 e^{7 t}-2 e^{11 t} \\ 6 e^{7 t}+2 e^{11 t} \end{array}\right]\].\)
Therefore, the given initial-value problem is solved.
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Complete question is,
Solve the given initial value problem:
\(\[ X^{\prime}=\left(\begin{array}{rr} 10 & -1 \\ 5 & 8 \end{array}\right) X\), \(\quad X(0)=\left(\begin{array}{r} -4 \\ 8 \end{array}\right) \]\)
Does anybody know what the missing side lengths are?!
Answer:
x√3 = 5√ 3
x = 5√ 3 / √ 3
x= √ 3(5√ 3 / √ 3)
x= 15/3
b= 5
5x2 =10
a=10 and b=5
of all the four letter words real or imaginary that can be made uxing the english alphabet the words cannot have repeated letters in them what is the probability that it has an m first and an a second
The probability that a four letter word has an "m" first and an "a" second is 1/26 * 1/25 = 1/650.
There are 26 letters in the English alphabet, so the probability of getting an "m" as the first letter is 1/26.
Once the first letter is chosen, there are only 25 letters left to choose from for the second letter. So the probability of getting an "a" as the second letter is 1/25.
To find the probability of both events happening, we multiply the probabilities together: 1/26 * 1/25 = 1/650.
So the probability of a four letter word having an "m" first and an "a" second is 1/650.
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J] invested USD12,000 in an account that gives an annual rate of return of 8% with continuous compounding.Calculate the time that it will take the initial deposit to triple itself.The resultneed not be integer.
It will take approximately 12.25 years for the initial deposit of $12000 to triple itself with an annual rate of return of 8% with continuous compounding.
Let t be the time that it will take the initial deposit to triple itself.
Then the future value of $12000 invested with an annual rate of return of 8% with continuous compounding after t years is given by the formula:
A = Pe^{rt}
where,
A is the future value,
P is the principal (initial deposit),
r is the annual interest rate,
t is the time (in years).
In this case,
P = $12000,
r = 0.08 (8%),
A = $36000 (triple the initial deposit).
Therefore, we have: $36000 = $12000e^ {0.08t}
Dividing both sides by $12000 and taking the natural logarithm of both sides gives:
ln (3) = 0.08t
Solving for t, we get:
t = ln (3) / 0.08 ≈ 12.25 years
Therefore, it will take approximately 12.25 years for the initial deposit of $12000 to triple itself with an annual rate of return of 8% with continuous compounding.
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What is the answer to this problem ?
Answer:
2(x + 6) = 38
Step-by-step explanation:
First, we choose a variable to represent the unknown number.
1. Let x = the unknown number.
Then, we translate the sentence into an equation using the variable we chose.
"Twice the sum of six and a number is 38."
We do it piece by piece:
"the sum of six and a number": x + 6
"Twice the sum of six and a number": 2(x + 6)
"Twice the sum of six and a number is 38.": 2(x + 6) = 38
Now we have an equation that represents the sentence.
2(x + 6) = 38
There is a spinner with 10 equal areas, numbered 1 through 10. If the spinner is spun
one time, what is the probability that the result is a multiple of 5 or a multiple of 2?
Find the value of x.
Answer:
312
Step-by-step explanation:
you add the angles to equal 299.
Look at the picture and see how I checked it.
a sphere has a volume of 850 m^3 find its surface area
Answer:
SA ≈ 434.5 cm²
Step-by-step explanation:
The volume (V) of a sphere is calculated as
V = \(\frac{4}{3}\)πr³ ( r is the radius )
The surface area (SA) is calculated as
SA = 4πr²
To find r use the volume formula
\(\frac{4}{3}\)πr³ = 850 ( multiply both sides by \(\frac{3}{4}\) to clear the fraction )
πr³ = 637.5 ( divide both sides by π )
r³ = \(\frac{637.5}{\pi }\) ( take the cube root of both sides )
r = \(\sqrt[3]{\frac{637.5}{\pi } }\) ≈ 5.88 cm ( to 2 dec. places )
Then
SA = 4π × 5.88² ≈ 434.5 cm² ( to 1 dec. place )
And 7/8 hours Greg reads 2/3 chapters what’s the unit rate in chapters per hour?
The unit rate in chapters per hour is 21/16 hours
How to calculate the unit rate?Greg read 7/8 hours in 2/3 chapter
The unit rate can be calculated as follows
7/8= 2/3
1= x
cross multiply both sides
2/3x= 7/8
x= 7/8 ÷ 2/3
x= 7/8 × 3/2
x= 21/16
Hence 21/16 chapters is read in one hour
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hey guys can you help me with this question love
Answer: -∞ < x < ∞
Step-by-step explanation:
The domain is all the x-values, or inputs, of a function. The range is the y-values, or outputs, of a function.
In this case, we are looking for the x-values of the function. Since the function will keep going "out forever" in both directions, the answer should be the fourth option;
- ∞ < x < ∞
The first step that we must take to solving this problem is to fully understand what the problem statement is asking from us and what is given us to solve the problem. Looking at the problem statement, we can see that they are asking us to determine what the domain of the function is in the graph that was provided. However, first of all, let us define what domain is.
Domain ⇒ Domain is what x-values can be used in the function that is graphed. For example, if a line just goes side to side all the way to negative and positive infinity, then the domain would be negative infinity to positive infinity as it includes all of the x-values in it's solutions.Looking back at our problem, we can see that this is similar to the example that was provided in the definition. We can see that the parabola reaches out to both positive and negative infinity in the x-direction but at a slope. Although we can only see it reach -2 and 6 we know that the parabola continues going on even after that.
Therefore, looking at the options that were provided option D, -∞ < x < ∞ would be the best fit as it showcases that x reaches from negative infinity to positive infinity.
Which of the following requires the use of implicit differentiation to find dy ? dx A. 2y+3x² - x = 5 B.y=e8+*+r C. y = ex+y + x x + 3 4x-2 D. y = dy
Option C, y = e^(x+y) + x^2 + 3x - 2, requires the use of implicit differentiation to find dy/dx.
The expression that requires the use of implicit differentiation to find dy/dx is option C: y = e^(x+y) + x^2 + 3x - 2.
Implicit differentiation is a technique used to differentiate equations where the dependent variable y is not explicitly expressed as a function of x. It involves differentiating both sides of the equation with respect to x, treating y as an implicit function of x.
Let's apply implicit differentiation to option C:
Starting with the equation: y = e^(x+y) + x^2 + 3x - 2
To find dy/dx, we differentiate both sides of the equation with respect to x:
d/dx(y) = d/dx(e^(x+y) + x^2 + 3x - 2)
Using the chain rule on the right side of the equation, we get:
dy/dx = d/dx(e^(x+y)) + d/dx(x^2) + d/dx(3x) - d/dx(2)
The derivative of e^(x+y) with respect to x requires the use of implicit differentiation. We treat y as an implicit function of x and apply the chain rule:
d/dx(e^(x+y)) = e^(x+y) * (1 + dy/dx)
The derivatives of the remaining terms on the right side are straightforward:
d/dx(x^2) = 2x
d/dx(3x) = 3
d/dx(2) = 0
Substituting these derivatives back into the equation, we have:
dy/dx = e^(x+y) * (1 + dy/dx) + 2x + 3
Next, we isolate dy/dx on one side of the equation by moving the term involving dy/dx to the left side:
dy/dx - e^(x+y) * dy/dx = e^(x+y) + 2x + 3
Factoring out dy/dx, we get:
(1 - e^(x+y)) * dy/dx = e^(x+y) + 2x + 3
Finally, we solve for dy/dx:
dy/dx = (e^(x+y) + 2x + 3) / (1 - e^(x+y))
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24 cm ,18cm ,c
We are looking for c
Step-by-step explanation:
we can find the value of c by Pythagoras theorem
according to Pythagoras theorem
h² = a² + b²
where
h = hypotenuse (i.e. longest side of a right angled triangle)
a = side
b = base
so, we have to find h or hypotenuse here
h² = (24)² + (18)²
h = 576 + 324 = 900
h² = √900 = 30
c = 30
therefore, value of c is 30.
Hope this answer helps you dear!
On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3) crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3).
Which statement is true about the graphed function?
F(x) < 0 over the interval (–∞, –4)
F(x) < 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –4)
The statement that is true about the function is -
D: F(x) > 0 over the interval (-∞, -4)
What is a function?
In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.
Since the curved line has a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3), we know that the function must be decreasing from left to right over the interval from negative infinity to negative 2.5, then increasing from negative 2.5 to 0.
Since the graph crosses the y-axis at (0, negative 3), we know that the function takes the value of negative 3 when x equals 0.
Also, since the graph crosses the x-axis at (negative 4, 0), we know that the function takes the value of 0 when x equals negative 4.
Since the function is decreasing from negative infinity to negative 2.5, and the y-value of the curve is always negative, we know that F(x) < 0 over the interval (-∞, -2.5).
Since the function is increasing from negative 2.5 to 0, and the y-value of the curve is always negative, we know that F(x) < 0 over the interval (-2.5, 0).
Since the function takes the value of negative 3 when x equals 0, we know that F(0) = negative 3, which means that F(x) < 0 over the interval (-∞, 0).
Since the function takes the value of 0 when x equals negative 4, we know that F(-4) = 0, which means that F(x) > 0 over the interval (-∞,-4).
Therefore, F(x) > 0 over the interval (-∞, -4) is true.
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a ball dropped vertically falls d, in t seconds
d is directly proportional to the sqaure of t
the ball drops 80 in 4 seconds
how far does the ball drop in the next 8 seconds
\(\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] ~\dotfill\)
\(\stackrel{\textit{"d" proportional to }t^2}{ {\Large \begin{array}{llll} d=kt^2 \end{array}}}\qquad \textit{we also know that} \begin{cases} d=80\\ t=4 \end{cases}\implies 80=k(4)^2 \\\\\\ \cfrac{80}{4^2}=k\implies 5=k\hspace{15em}\boxed{d=5t^2} \\\\\\ \textit{when t = 8, what is "d"?}\qquad d=5(8)^2\implies d=640~in\)
Draw a picture or model to show the ratio 8:5 explain how you know your picture shows the ratio.
Answer:
draw a rectangle with side lengths 8 and 5. the ratio of the side lengths will be 8:5.
Andy spent the following amounts on lunches this week
Algebra is used to solve the mathematical problems, the total amount spent by Andy on lunches in this week is equals to $195.
Algebra is the branch of mathematics that use in the representation of problems or situations in the form of mathematical expressions. Mathematical ( arithmetic) operations say multiplication (×), division (÷), addition (+), and subtraction (−) are used to form a mathematical expression.
We have, a data of amount spent by Andy on lunches in a week. Let the total amount spent by him in this week be "x dollars". Using algebra of mathematics, we can written as x = sum of amounts spent by him in whole week so, x = $50 + $20 + $10 + $25 + $25 + $15 + $50 = $195
Hence, required total amount value is $195.
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Complete question:
Andy spent the following amounts on lunches this week,
day. amount
Sunday $50
Monday. $20
Tuesday $10
Wednesday $25
Thursday $25
Friday $15
Saturday $50
Calculate total amount he spent in this week.
3|y|+(y-x²)
if x = -1 and y = -5
If x is an int and y is a float, all of the following are legal except which assignment statement? A. y = x; B. x = y; C. y = (float) x; D. x = (int) y; E. all of these are legal
If x is an int and y is a float then only option that is not legal is D) x = (int) y.
Option A is legal because an int can be assigned to a float without any issues. The float will simply contain the same value as the int, but with a decimal point (e.g. 5 will become 5.0). Option B is not recommended because it involves converting a float to an int. The decimal point will be dropped, so information will be lost. However, it is still legal to do so. Option C is legal because it explicitly converts the int to a float, which can then be assigned to y. Option D is not legal because it involves converting a float to an int. This can lead to unexpected behavior, such as truncating the decimal point or rounding the value. It is generally safer to avoid such conversions. Option E is not correct because option D is not legal, as explained above.
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Write the slope- intercept form of the equation
Answer:
y = -3/4x + 1
Step-by-step explanation:
should i come out to my parents as bi O,o
Answer:
i did and it was the best thing ive ever done
Step-by-step explanation:
Answer:
yes, it feels so much better
Step-by-step explanation:
can someone help me with my geometry test please... on my page. Would love you forever lol
HELP ME PLEASE!! IM BEGGING YOU!!
Answers
x=-2
I think so ............................
Answer:
D
Step-by-step explanation:
9 is 3 squared so 9 to power x-8 can be written as 3 to power 2(x-8)
Since bases are same powers are equal so
2(x-8) = 4x-12
2x -16 =4x-12
-4 =2x
x = -2
match the type of attention with its impact on the encoding process.
Type of Attention Impact on Encoding Process
1. Sustained attention Facilitates thorough encoding of information.
2. Selective attention Enhances encoding of attended stimuli while filtering out irrelevant information.
3. Divided attention Impairs encoding by dividing attentional resources among multiple tasks.
4. Exogenous attention Captures attention involuntarily, potentially interrupting the encoding process.
5. Endogenous attention Voluntarily directed attention that can prioritize specific information for encoding.
1. Sustained attention: Sustained attention refers to the ability to maintain focus over an extended period. It has a positive impact on the encoding process as it allows for thorough and comprehensive encoding of information.
2. Selective attention: Selective attention involves focusing on specific stimuli while filtering out irrelevant information. It enhances the encoding process by directing attention to the relevant stimuli, promoting their effective encoding.
3. Divided attention: Divided attention refers to the attempt to allocate attention to multiple tasks simultaneously. Dividing attention among multiple tasks impairs the encoding process as attentional resources become fragmented, leading to less effective encoding of information.
4. Exogenous attention: Exogenous attention is captured involuntarily by external stimuli, potentially interrupting the encoding process. It can divert attention away from the intended encoding task, resulting in a negative impact on encoding.
5. Endogenous attention: Endogenous attention is voluntarily directed attention that allows individuals to prioritize specific information for encoding. It enhances the encoding process by selectively focusing on relevant stimuli and allocating cognitive resources accordingly.
Different types of attention have varying impacts on the encoding process. Sustained attention and selective attention positively influence encoding, while divided attention and exogenous attention have negative effects. Endogenous attention, on the other hand, can enhance encoding by prioritizing specific information.
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assessment started: unit 8 progress check: mcq part a. item 1 let f be the function given by f(x)=3xsinx. what is the average value of f on the closed interval 1≤x≤7 ?
To find the exact value, we would need to evaluate the definite integral, but it may not be practical to do so without further information or using numerical methods.
To find the average value of a function on a closed interval, you need to calculate the definite integral of the function over that interval and divide it by the length of the interval. In this case, we want to find the average value of the function f(x) = 3xsin(x) on the interval 1 ≤ x ≤ 7.
The average value of f on the interval [1, 7] is given by the formula:
Average value = (1/(b - a)) * ∫[a to b] f(x) dx
where a and b are the endpoints of the interval.
In our case, a = 1, b = 7, and f(x) = 3xsin(x). So, we can calculate the average value as follows:
Average value = (1/(7 - 1)) * ∫[1 to 7] (3xsin(x)) dx
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The graph represents the system of inequalities shown below. Determine whether the statement that follows the
graph is true or false.
y greater than or equal to 6
5x+3y ≤ 15
f(x,y) - 12x+3y
Assuming that x ≥ 0 and y ≥ 0, the situation is infeasible: True.
What are the rules for writing an inequality?In Mathematics, these rules are generally used for writing and interpreting an inequality or system of inequalities that are plotted on a coordinate plane:
The line on a graph is a solid line when the inequality symbol is (≥ or ≤).The inequality symbol is greater than or equal to (≥) when a solid line is shaded above.The inequality symbol is less than or equal to (≤) when a solid line is shaded below.In this context, we can logically deduce that the given system of inequalities 5x+3y ≤ 15 and y ≥ 6 would not have a feasible solution set if they are subjected to x ≥ 0 and y ≥ 0:
Assuming the ordered pair (1, 2), we have:
y ≥ 6
2 ≥ 6 (False).
5x+3y ≤ 15
5(1) +3(2) ≤ 15
5 + 6 ≤ 15
11 ≤ 15 (True).
Therefore, it is not a feasible solution.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
Simplify the Expression(20 points)-
-m - 7m
Answer:
-8m
Step-by-step explanation:
Combine like terms
−
−
7
{\color{#c92786}{-m}}{\color{#c92786}{-7m}}
−m−7m
−
8
{\color{#c92786}{-8m}}
−8m
max has x dollars. Keisha has four more dollars then max
Answer:
4x
Step-by-step explanation:
Simply add 4 and x, and that is 4x.
15. Express the repeating decimal 4.61 as an exact fraction using a geometric series with 0.01 being the repeating decimal.
Answer:
4 11/18------------------------
We have a repeating decimal 4.6(1).
Let's express it as a GP:
4.6(1) = 4.6 + 0.01 + 0.001 + 0.0001 + ...Fund the sum of infinite GP, with the first term of a = 0.01 and common ratio of r = 0.1:
S = a/(1 - r) S = 0.01/(1 - 0.1) = 0.01/0.9 = 1/90Add 4.6 to the sum:
4.6 + 1/90 =4 + 0.6 + 1/90 =4 + 6/10 + 1/90 = 4 + 54/90 + 1/90 = 4 + 55/90 = 4 + 11/184 11/18Hence the fraction is 4 11/18.
are the corresponding angles 7 and 6 /5 and 8 or 7 and 3 8and 4
please explain I'm SO confused
Answer: 7=6=3=2 and 8=5=4=1
Step-by-step explanation:
For 2 straight lines crossing, opposite angles are equal. And because the 2 vertical lines are parallel, both sets (1234 and 5678) of angles are the same. Let me know if that is too confusing
Answer:
f shape, I don't know if I'm correct