Answer:
5
Explanation:
Formula for Mass (for this question)
\(mass=\frac{Force}{Acceleration}\)
mass= 1000N/200\(m^{2}\)=5
(pls do correct me if I have any mistakes it would rlly help others!)
what physical property denotes the color of a powdered mineral?
Streak is a material property that characterizes particular mineral's coloration.
What are minerals, for instance?The mineral is an ingredient or chemical component that has emerged as a result of natural formations and is often crystalline in nature. Examples include the minerals quartz, feldspar, calcite, sulfur, and clays like kaolinite and smectite.
What does a mineral do in daily life?Minerals are necessary building blocks for our daily lives and are fundamental to the advancement of economic, social, and technological systems. For instance, consider the following: Agriculture: Additional mineral products are also utilized to improve soil, including phosphate rock, potash, and lime.
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What is the final velocity of a 50 kg skater that pushes off of a 55 kg skater who moves to the left at 7.2m/s?
The final momentum of the skater is 3.77 m/s.
What is momentum?Momentum is the product of mass and acceleration. Recall that the principle of conservation of linear momentum states that total momentum before collision must equal the total momentum after collision.
Thus;
(50 Kg × 0 m/s) + (55Kg × 7.2m/s) = (50 Kg + 55Kg) v
v = (55Kg × 7.2m/s)/(50 Kg + 55Kg)
v = 396/105
v = 3.77 m/s
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a student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.5 m in a time of 2.0 s. the average speed of the ball is
The average speed of the ball is 0.25 m/s
Define speed.
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path.
The displacement of a body over a predetermined amount of time is referred to as velocity. It has a scalar value. A vector quantity, that is.
Distance/Time = Speed.
A force has the power to alter an object's motion's direction. A greater force acting on an object will result in a greater change in motion. To undergo the same change in motion, a heavier object needs more force than a lighter thing.
S = Average speed
d = total distance
t = total time.
S = d/t.
d = 0.5m
t = 2.0s
S = 0.5/2
S = 0.25m/s
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Joel the firefighter, standing 45 m from a burning building, directs a stream of water from a ground level fire hose at an angle of 25 degrees above the horizontal. The Vi of the stream as it leaves the hose is 55 m/s. What is the water’s Vix?
can you get very smart?
Actually according to physics there should be needed a force to move things but our mind does not produce a force ...Apart from myths ...is seems quite impossible to move a object with ur mind
-Thanks for reading
HELP ME
PLS I will give brainliest
Answer:
Option 2
Explanation:
Since they want to know kinetic energy being increased, it cannot be Options 1 or 3. So now we're left with 2 and 4. 4 seems to be decreasing, so we can eliminate that. So, our answer is Option 2.
light traveling in diamond is incident on a 3 cm thick piece of sapphire. it enters the sapphire at an angle of 50 degrees as shown. when it reaches a third material, it undergoes total internal reflection. (a) what is the incident angle theta1 of the light in the diamond?
The incident angle θ1 of the light in the diamond is approximately 7.91 degrees.
The incident angle θ1 of the light in the diamond can be calculated using the Snell's law, which states that the ratio of the sine of the incident angle to the sine of the refracted angle is equal to the ratio of the speed of light in the medium of incidence (diamond) to the speed of light in the medium of refraction (air).
Using the values given in the question:
The angle of incidence θ1 = 50 degrees
The refractive index of diamond (n1) = 2.419
The refractive index of air (n2) = 1.000
The speed of light in a vacuum (c) = 299,792,458 meters per second
We can calculate the incident angle θ1 using the Snell's law:
sin(θ1) / sin(θ) = (c/n1) / (c/n2)
sin(θ1) = (c/n1) / (c/n2) * sin(θ)
θ1 = (c/n1) / (c/n2) * sin(theta)
Since the sine of an angle is always between -1 and 1, we can solve for θ1:
0.5 = (299,792,458 / 2.419) / (299,792,458 / 1.000) * sin(theta)
sin(θ1) = 0.5 / (299,792,458 / 1.000) * sin(θ)
sinθ1) = 0.5 / (2.998 x \(10^6\)) * sin(θ)
sin(θ1) = 0.5 / 7.91 x \(10^-5\) * sin(theta)
θ1= 7.91 x \(10^-5\) * sin(theta)
Therefore, the incident angle θ1 of the light in the diamond is approximately 7.91 degrees.
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This graph shows a supply curve. A graph titled Supply Curve has Quantity Supplied on the x-axis, from 0 to 50 in increments of 10, and price on the y-axis, from 0 to 15 dollars in increments of 5 dollars. A line is drawn with points (10, 5 dollars), (20, 7 dollars), (30, 10 dollars), (40, 13 dollars), and (40, 15 dollars). What happens when the price of a good increases? The quantity of goods that are produced increases. The producer of the good is certain to make less money. The quantity of goods that are produced decreases. The quantity of goods that are produced stays about the same.
Answer:
A just took the quiz on edge
Explanation:
In the supply curve, when the price of a good increases, A. The quantity of goods that are produced increases.
What is supply?Supply simply means the quantity of goods and services that a supplier is willing to sell at a particular place, price and time.
In this case, when there's an increase in the price of goods, it should be noted that producers will supply more of the goods. This is done in order to generate more revenue.
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A lorry travels 10km northwards, 4km eastwards, 6km southwards and 4km westwards to arrive at point T. What is the total displacement?
A wave has a wavelength of 45 meters and a period of 9.0 seconds. What is the frequency of the wave?
405 Hz
5.0 Hz
5.0 m/s
0.11 Hz
Answer:405
Explanation:Multiply 45x9.0=405
Answer:
405 Hz
Explanation:
Give the person on top Brainly
A light beam travels at 1.34×10^8 m/s in diamond. The wavelength of the light in diamond is 246 nm
Part A
What is the index of refraction of diamond at this wavelength?
Part B
If this same light travels through air, what is its wavelength there
Answer:
Part A: 2.24
Part B: 551 nm
Explanation:
Part A:\(n_1*v_1=n_2*v_2\) (n1 and n2 are the indexes of refraction, and v1 and v2 are the velocities of light)
Rearrange to isolate n2: \(\frac{n_1*v_1}{v_2} =n_2\)
Speed of light in a vacuum is 3*10^8 m/s, and a vacuum has index of refraction of 1.
\(n_2=\frac{1*3*10^8}{1.34*10^8}\) = 2.24
Part B:Air has index of refraction of about 1, so speed of light in air is about 3*10^8 m/s.
Speed of light is its frequency times its wavelength. Travelling through different mediums does not affect the frequency of the light.
v = λ*f (c is speed of light in diamond, λ is wavelength of light, and f is frequency of light)
Rearrange to isolate f: f = v/λ
246 nm = 2.46*10^-7 m
f = \(\frac{1.34*10^8}{2.46*10^{-7}}\) = 5.45*10^14 Hz
To find wavelength of light in air, rearrange v = λ*f to λ = v/f = \(\frac{3*10^8}{5.45*10^{14}}\) = 5.51*10^-7 m = 551 nm
Part a. The index of refraction of diamond at this wavelength is 0.0434.
Part b. The wavelength of the light in air is approximately 1.06× \(10^8\) m/s.
The index of refraction of diamond at this wavelength, we need to use the formula:
n = c/v
here n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium. We know that the speed of light in a vacuum is 299,792,458 m/s, so we can substitute this value into the formula:
n = (1.34× \(10^8\) m/s)/(299,792,458 m/s)
n = 0.0434
The index of refraction of diamond at this wavelength is 0.0434.
The wavelength of the light in air, we can use the formula:
wavelength = c/n
here wavelength is the wavelength of the light in air, and n is the index of refraction of air. We know that the index of refraction of air is 1, so we can substitute this value into the formula:
wavelength = (1.34× \(10^8\) m/s)/(1)
wavelength = 1.34× \(10^8\) m/s
Therefore, the wavelength of the light in air is approximately 1.06× \(10^8\) m/s.
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Help plzz!!
An archer pulls back the string of the bow (spring constant of 250 N/m) a distance of 1 meter. How much elastic energy is stored?
a)251.5 J
b)125 J
c)2500 J
Answer: It would be 125 J
Answer:
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Explanation:
A sales clerk at a local hardware store sells you a hammer with a mechanical advantage of 10 when used to pry up nails. You are able to create a force of 60 N. Using the hammer, what would be the maximum force that could be generated to remove a nail?
Answer:
W = 600 N
Explanation:
The mechanical advantage of any machine is the ratio of the load or weight to the effort applied. Hence, the general formula for mechanical advantage is as follows:
M.A = W/P
where,
M.A =Mechanical Advantage of Hammer = 10
W = Maximum force that could be generated = ?
P = Force created by me = 60 N
Therefore,
10 = W/60 N
W = 10*60 N
W = 600 N
does anyone know what the answers are?
Answer:
Option (C) is the answer
Explanation:
may be it is possible if that we stand so far
Indigo has announced that the speed of the Airbus A320 neo fleet is to be cut from 525 to 475 miles per hour in order conserve fuel by reducing the fuel consumption from 2200 gal/hr to 2000 gal/hr. How many kilolitres of fuel are saved in a typical 2000 km trip?
Fuel consumption rate refers to the amount of fuel consumed by a vehicle or equipment over a certain period of time. Approximately 3570.82 kiloliters of fuel are saved in a typical 2000 km trip.
Fuel consumption rate is typically measured in units such as gallons per hour (gal/hr) or liters per hour (L/hr). The fuel consumption rate indicates the efficiency or effectiveness of fuel utilization by the vehicle or equipment.
The fuel consumption rate represents the rate at which fuel is consumed by the Airbus A320 Neo aircraft. It is specified as 2200 gallons per hour (gal/hr) before the speed reduction and 2000 gallons per hour (gal/hr) after the speed reduction. This means that the aircraft consumes fuel at a rate of 2200 gallons per hour (gal/hr) when flying at a speed of 525 miles per hour (mph) and at a rate of 2000 gallons per hour (gal/hr) when flying at a reduced speed of 475 miles per hour (mph).
To calculate the amount of fuel saved in a typical 2000 km trip, we need to convert the fuel consumption rate from gallons per hour (gal/hr) to kiloliters per kilometer (kL/km).
First, let's calculate the fuel consumption rate per kilometer:
Fuel consumption rate (kL/km) = (Fuel consumption rate (gal/hr) * Conversion factor) / Distance (km)
Conversion factor: 1 gallon = 0.00378541 kiloliters
Distance: 2000 km
Fuel consumption rate (kL/km) = (2000 gal/hr * 0.00378541 kL/gal) / 2000 km
Fuel consumption rate (kL/km) = 3.78541 kL/km
Now, let's calculate the fuel saved during a typical 2000 km trip:
Fuel saved (kL) = (Fuel consumption rate before - Fuel consumption rate after) * Distance
Fuel consumption rate before: 3.78541 kL/km
Fuel consumption rate after: 2 kL/km
Distance: 2000 km
Fuel saved (kL) = (3.78541 kL/km - 2 kL/km) * 2000 km
Fuel saved (kL) = 1.78541 kL/km * 2000 km
Fuel saved (kL) = 3570.82 kL
Therefore, approximately 3570.82 kiloliters of fuel are saved in a typical 2000 km trip.
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A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
HELP ME ANSWER THIS FOR 96 POINTS PLEASE!!
The three modified Atwood's machines shown below have blocks of mass M on a frictionless surface
and hanging from a string. When the blocks are released, they accelerate.
Rank them from smallest to largest and explain why in a short paragraph using the mass terms and force.
Answer:
Smallest - B
Largest - C
Middle - A
The hanging mass provides the force for accelerating the system.
In case A the force M G accelerates 2 * M
So you have for F = M a M * g = 2 * M * a or a = g / 2
In case B F = M a M * g = 3 * M * a and a = g / 3
In case C F = 2 * M * g 2 M * g = 3 * M * a and a = 2 * g / 3
Rank from smallest to largest force Smallest - B, Middle - A, Largest - C.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Smallest - B
Largest - C
Middle - A
The hanging mass provides the force for accelerating the system.
In case A the force M G accelerates 2 * M
So you have for F = M a M * g = 2 * M * a or a = g / 2
In case B F = M a M * g = 3 * M * a and a = g / 3
In case C F = 2 * M * g 2 M * g = 3 * M * a and a = 2 * g / 3
Rank from smallest to largest force Smallest - B, Middle - A, Largest - C.
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A hollow steel shaft has an outer diameter of 150 mm and an inner diameter of 100 mm. The shaft is subjected to a torque of 35 KN-m.
The modulus of rigidity for the steel (shear modulus) is 80 GPa. Determine:
(a) The shear stress at the outer surface of the arrow.
b) The shear stress on the inner surface of the shaft.
c) The magnitude of the torsion angle (in degrees) over a length of 2.5 m.
The shear stress at the outer surface of the shaft When a shaft is subjected to a torque load, shear stresses develop along the cross-section of the shaft.
The shear stress formula is given by where,τ is the shear stress T is the applied torque, r is the radius of the shaft
Hence, the magnitude of the torsion angle (in degrees) over a length of 2.5 m is 0.15 degrees (approx).
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14. The average speed of a car was 60 m/s by the time it reached the finish line. The car moved in a straight line and traveled from the starting
line to the finish line in 8.0 sec. How far was the finish line?
A mass on a spring is first placed on a table and set in SHM and then held vertically and set in SHM. What variable/s would change between the two scenarios?
The variable that changes is the period of the motion.
What is simple harmonic motion?The term simple harmonic motion refers to a regular repeating motion. The acceleration of the SHM is always directed towards the center. The spring is an example of a system undergoing simple harmonic motion.
From the description in the question, the variable that changes is the period of the motion.
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A skydiver sky dives from an airplane. The amount of air resistance she is met with is measured at each second following her jump.
Time after jump Weight Air Resistance
1 sec 500 N 200 N
2 sec 500 N 300 N
3 sec 500 N 400 N
4 sec 500 N 500 N
Which statement best identifies her speed at each second? (AKS 8C DOK 2)
answer choices
She will be going faster at second 5
She has the fastest speed at second 1
She has the fastest speed at second 4
She has the slowest speed at second 1
The statement best identifies her speed at each second is She has the fastest speed at second 4.
As the skydiver falls faster, the drag increases until it reaches the magnitude of gravity. When drag becomes as great as gravity, a force balance is reached and the skydiver stops accelerating. To simplify the topic.
We can say that the two most common factors that directly affect the amount of drag are object velocity and object cross-sectional area. Gravity and air resistance act on a skydiver jumping out of an airplane. The speed at which an object falls and the shape of the object on the surface on which the force of air resistance acts.
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1. If the odometer on a car reads 100 km at the start and 155 km at the end of a trip, what
distance did the car travel on the trip?
2. What would be the average speed of the car in the question above if the trip took half an
hour (30 minutes)?
1. 55 km is distance the car travel on the trip.
Net distance = final distance - initial distance = 155 - 100 = 55km.
2. 110 km/hr is would be the average speed of the car in the question above if the trip took half an hour.
Average speed = distance travelled/ time = 55km/0.5hr
Hence, average speed = 110km/hr
The average speed is the full distance traveled with the aid of the object in a particular time interval. The average speed is a scalar quantity. it is represented via the significance and does not have path. average pace is calculated by way of dividing distance through time.
Speed is the directional pace of a object in movement as a demonstration of its price of alternate in role as discovered from a selected frame of reference and as measured by way of a particular trendy of time.
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NH3 → N2 + H2 Balance and classify it
Answer:
2NH3 --> N2 + 3H2 decomposition
a binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure? (a) true (b) false
The given statement '' A binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure '' is True.
A binary phase diagram is a graphical representation that shows the phases of two elements, at least one of which is metallic, as a function of composition and temperature at a specific pressure, typically atmospheric pressure.
The diagram displays different regions representing the stability of different phases (such as solid, liquid, and gas) as the composition and temperature of the system are varied. It is a valuable tool in understanding the behavior and phase transitions in binary systems.
Hence, The given statement '' A binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure '' is True.
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As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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when ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 ev . what is the maximum kinetic energy of the photoelectrons when light of wavelength 315 nm falls on the same surface?
The maximum kinetic energy of the photoelectrons when light of wavelength 315nm falls on the same surface is 1.937eV.
What is photoelectric effect?
Electrons are released when a material is exposed to electromagnetic radiation, such as light, and this is known as the photoelectric effect. These electrons are referred to as photoelectrons. To derive conclusions regarding the properties of atoms, molecules, and solids, the phenomena is researched in condensed matter physics, solid state chemistry, and quantum chemistry. Electronic devices designed for light sensing and precisely timed electron emission have found usage for the effect.
For solving this question, we will use the formula:
E=Ф+ KE where,
Ф is work function, also written as Wo
hc/λ + KE= Ф
Ф= (6.63×10 -34×3×10 8/ 400×10-9 ) - 1.6×10-9×1.10
⇒3.2095×10-19 J
KE = hc/λ - Ф
⇒(6.63×10 -34×3×10 8/ 315 ×10 -9) - 3.2095×10-19
⇒3.10×10-19 J
KE = 3.10×10-19/ 1.6 ×10-9
KE = 1.937 eV
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A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of
the car?
Answer:
16m/s
Explanation:
Mv=mv
5000x8=2500x v
V=5000x8/2500
V=40000/2500
= 16m/s
5. Explain how forming an ionic bond makes metal and nonmetal atoms more stable.
6. Describe how metallic bonds contribute to the physical characteristics of a metal.
7. Describe the type of ions created through metallic bonding.
8. List the three types of atomic bonds and describe the types of atoms-metal
or nonmetal-that form each type of bond.
A 50-kg block is at rest on a 15o slope. A force of 250 N is acting on the block up the slope parallel to it. If the block does not slide up the slope, what is the minimum value of the coefficient of static friction between the block and the slope
The minimum value of the coefficient of static friction between the block and the slope is 0.53.
Minimum coefficient of static frictionApply Newton's second law of motion;
F - μFs = 0
μFs = F
where;
μ is coefficient of static frictionFs is frictional forceF is applied forceμ = F/Fs
μ = F/(mgcosθ)
μ = (250)/(50 x 9.8 x cos15)
μ = 0.53
Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.
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A 5kg traveling at 4 m/s slams into a 1kg object and sticks to it. What will the final velocity of the two objects be?
Answer:
Below
Explanation:
Using conservation of momentum
mv = mv
5(4) + 1(0) = (4+1) v
( this assumes the 1 kg mass was not moving before being struck)
20 = 5 v
v = 4 m/s