You work for a company that specializes in electron beam-impact deposition. This apparatus uses a tightly focused electron beam to deposit atoms on a surface with very fine spatial resolution. You are given the job of calculating the maximum possible deflection of the electron beam when the random magnetic fields in the laboratory are reduced (by shielding) to a maximum value of 0. 15 mGauss. The electrons are accelerated from rest through 20 kV and the path length is 3. 6 cm. If the magnetic fields were later discovered to be twice as large, what modified path length would yield the same deflection as you originally calculated

Answer:

Hee answer is B

Explanation:

____________.

Answer:

Please mark as Brainliest!!

Explanation:

He will not succeed as it blows the trumpet harder that only increase the amplitude of the sound wave that means the intensity of the sound will increase but the frequency remains the same.

Answer:

he wont

Explanation:

The tension in the string at the bottom of the circle is 6.4 Newtons.

To find the tension in the string at the bottom of the circle, we can use the concept of centripetal force.

The centripetal force required to keep an object moving in a circular path is given by the formula:

\(F = m * (v^2 / r)\)

Where:

F is the centripetal force

m is the mass of the object

v is the velocity of the object

r is the radius of the circular path

In this case, the circular path is the vertical circle, and the object is at the bottom of the circle. At the bottom, the tension in the string provides the centripetal force required.

Given:

m = 0.40 kg (mass of the object)

v = 8.0 rad/s (angular speed of the object)

r = 0.50 m (radius of the circular path)

Since the angular speed (ω) is given in rad/s, we need to convert it to linear velocity (v) using the formula:

v = ω * r

Substituting the values:

v = 8.0 rad/s * 0.50 m = 4.0 m/s

Now, we can calculate the tension (T) in the string using the centripetal force formula:

\(F = m * (v^2 / r)\)

\(T = m * (v^2 / r)\)

\(T = 0.40 kg * (4.0 m/s)^2 / 0.50 m\)

\(T = 0.40 kg * 16 m^2/s^2 / 0.50 m\)

T = 6.4 N

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The wave's wavenumber equals 0.628 radians per meter.

The given progressive wave equation is represented by Y = A sin 2π(0.15t + 0.1x), where Y is the displacement of the wave at a point in space and time, A is the amplitude of the wave, t is the time, and x is the position of the point along the direction of wave propagation.

The period of a wave is the time it takes for one complete cycle of the wave to occur. In the given equation, the coefficient of t in the argument of the sine function is 0.15. This means that the wave completes one cycle in (1/0.15) = 6.67 seconds.

Therefore, the period of the wave is 6.67 seconds.

The wavenumber of a wave is the number of waves that occur in a given distance. In the given equation, the coefficient of x in the argument of the sine function is 0.1. This means that the wave completes one cycle in a distance of (1/0.1) = 10 meters.

Therefore, the wavenumber of the wave is (2π/10) = 0.628 radians per meter.

In summary, the period of the given wave is 6.67 seconds and the wavenumber is 0.628 radians per meter. These values can be used to calculate other properties of the wave, such as its frequency and velocity, using the relevant formulas.

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(a) The frequency of the wave is 10.0 Hz, (b) the wavelength is 1.00 m, and (c) the speed of the wave is 10.0 m/s. (d) The node with the smallest value of x is located at x = 0.5 m, (e) the second smallest node is at x = 1.5 m, and (f) the third smallest node is at x = 2.5 m. (g) The smallest antinode is at x = 0.25 m, (h) the second smallest antinode is at x = 0.75 m, and (i) the third smallest antinode is at x = 1.25 m.

(a) What is the frequency

(b) wavelength

(c) speed of the wave described by y = (6.0 cm) cos π/2 [(2.00 m^-1)x + (10.0 s^-1)t] and y = (6.0 cm) cos π/2 [(2.00 m^-1)x – (10.0 s^-1)t]?

(d) Find the location of the node with the

(e) second smallest and

(f) third smallest values of x for x > 0. Also, determine the location of the antinode with the

(g) smallest

(h) second smallest

(i) third smallest values of x for x > 0.

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The frequency of the wave is 1.59 Hz, wavelength is 3.14 m, and speed is 5 m/s. The smallest, second & third smallest location of nodes are at 0.79 m, 2.36 m and 3.93 m respectively. For antinodes, they are located at 1.57 m, 3.14 m, and 4.71 m.

The equations given represent waves, specifically cosine waves, with variables x representing position and t representing time. The general form of a wave equation is y = A cos(kx - wt), where A is amplitude, k is wavenumber, w is angular frequency, x is position, and t is time.

(a) To calculate the frequency, we can convert angular frequency (w) to frequency (f) using the formula w = 2πf. Given w = 10 s^-1, therefore f = w / (2π) = 10 / 2π = 1.59 Hz.

(b) Wavelength (λ) can be calculated using the formula λ = 2π / k. Given k = 2 m^-1, therefore λ = 2π / 2 = π m or approximately 3.14 m.

(c) The speed (v) of the wave is given by v = λ * f. Substitute the previous values to get: v= 1.59 Hz * 3.14 m = 5 m/s

(d,e,f) For a cosine wave, nodes occur where the function is zero. This occurs when the argument of the cosine function is an odd multiple of π/2. For smallest, second smallest, and third smallest values of x having a node, you get x = λ/4 = 0.79 m, x = 3λ/4 = 2.36 m, and x = 5λ/4 = 3.93 m, respectively.

(g,h,i) Similar approach for anti-nodes, but now the argument of the cosine function is a multiple of π. Thus, the smallest, second smallest, third smallest x for anodites are x = λ/2 = 1.57 m, x = λ = 3.14 m, and x = 3λ/2 = 4.71 m, respectively.

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Answer:

Initial velocity is the velocity at time interval=0 and it is represented by u.lt is the velocity at which the motion starts. they are four initial velocity formulas:(1) if time, acceleration and final velocity are provided,the initial velocity is articulated as.

l hope it's helpful for you.....

Answer:

4.31×10⁹Hz

Explanation:

v=2.5×10³ms⁻¹    wavelength=5.80×10⁻⁷m

v=frequency × wavelength

2.5×10³=f×5.80×10⁻⁷

f=4.31×10⁹Hz

The frequency of the wave is 4.3 × 10⁹Hz

HOW TO CALCULATE FREQUENCY OF A WAVE:

f = v/λ

Where;

f = frequency (Hz)

v = speed of the wave (m/s)

λ = wavelength (m)

f = v/λ

f = 2.5 × 10³ ÷ 5.80 x 10-⁷

f = 2.5/5.80 × 10³+⁷

f = 0.43 × 10¹⁰

f = 4.3 × 10⁹Hz or s-¹

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Answer: The energy to move the fluid is provided by the pressure on the fluid surface.

Explanation:  The frictional losses in the suction pipework and rises in the suction pipework system will reduce the fluid pressure at the pump inlet. If the pump inlet connection is removed the fluid will not flow out of the suction pipework. Hope this helps! :)

Answer:

Approximately \(1.3\times 10^{8}\; \rm m\cdot s^{-1}\).

Explanation:

Look up the speed of light in vacuum: \(c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}\). Denote the speed as \(c\).

If the speed of light in a medium is \(v\), the refractive index of that medium would be:

\(\displaystyle n = \frac{c}{v}\).

Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.

Rearrange this equation to find the speed of light \(v\) in this medium:

\(\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}\).

I'm pretty sure this poor guy could never have been accepted for astronaut training, much less a mission to the Moon.  

He weighs something like 335 pounds when he's ON THE MOON !

If he has enough fuel, and survives a trip back to Earth, he'll weigh around 9,080 Newtons here.  That's like 2,040 pounds ... durn close to a ton ! !

Answer:

Gravitational field strength:

Moon is 1.6N/kg

Earth is 9.8N/kg or 10N/kg

Moon:

Weight = mass x gravitational field

1500N = m x 1.6N/kg

÷1.6 both sides

937.5 = m

Mass of astronaut is 937.5kg

(Your mass doesn't change, no matter where you go, in space)

Earth:

Weight = mass x gravitational field

= 937.5kg x 9.8 N/kg

= 9187.5N

Or

Weight = mass x gravitational field

= 937.5kg x 10 N/kg

= 9375N

Thus, the astronaut's weight will be 9187.5N or 9375N on Earth.

Hope this helps!

Answer:

The possibility of Adenine=40% and Thymine=60% is only in single stranded DNA molecule. In the question, the DNA sample referred is a single stranded DNA. If guanine=10% as guanine will always pair with cytosine, i.e.cytosine is also 10% then adenine and thymine accounts 80% as adenine will always pair with thymine.

A molecule of DNA cannot contain 60% thymine because this amount will surpass 100% in consideration of its complementary base.

DNA or deoxyribonucleic acid is a biological molecule that stores genetic information in living cells.

DNA is a double stranded molecule that consists of nucleotide bases as follows:

According to Chargaff in his rule, the amount of adenine & thymine and guanine & cytosine in a DNA molecule is the same, which must equal 100% overall.

Therefore, if thymine is 60% in the DNA, adenine will also be 60%, which in total has already surpassed 100% without adding the other two bases.

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Kinetic energy is the energy when a object is in motion. ...  energy gets transferred to the object,  The energy transferred is kinetic energy, and it depends on the mass and speed.

Explanation:

Answer:

ρ = .68 g / cm^3 = 680 kg / m^3      for gasoline

M = ρ V = 38 kg

V = 38 kg / 680 kg/m^3 = .056 m^3

.4 * .6 * D = .056 m^3

D = .23 m

Answer:

The velocity of the cricket ball is 17.32 m/s

Time is taken by the ball to reach the highest point = 0.8660 seconds

Explanation:

The cricket ball can be seen and treated as a projectile in this case

The maximum height attained by a projectile in motion can be calculated using the formula:

\(h = \frac{v^2 sin^2 \theta }{2g}\)

In any projectile problem, once we know see that the object was released vertically upwards, we need to know that this means that the angle of projection is 90 degrees, and sin 90 is = 1

hence, h will be modified to become

\(h = \frac{v^2 }{2g}\)

\(v = \sqrt{2gh}\)

We are given that h = 15m and g = 10m/s2

\(v = \sqrt{2 \times 10 \times 15} = 17.32m/s\)

The velocity of the cricket ball is 17.32 m/s

B. We can get the time it took to reach the highest point by dividing

time = distance/speed

Time = 15/17.32 = 0.8660 seconds

Answer:

Mass and volume.

Explanation:

The equation for density is always mass divided by volume. To determine the density of a fluid, you would need to find its volume and its mass.

Answer: 0.36N

Explanation:

Newton's Law of Gravitation states that the gravitational force that an object feels is directly proportional the product of its mass with the mass creating the field. It also states that the gravitational force is inversely proportional to the distance squared according to the inverse square law. The constant of proportionality is called Newton's gravitation constant denoted with a capital 'G'. We have that:

\(F=G(\frac{Mm}{r^2} )\)

Plugging in the values, you get:

\(F=6.67*10^-^1^1(\frac{4.5*10^7*2.5*10^6}{145^2} )\)

\(F=0.36N\)

Answer:

because these units are derived from combinations of two or more of the seven base units

Answer:

14.3 x 10^8Hz

Explanation:

Using

Frequency= speed of light /wavelength

Then substituting

3*10^8m/s / 0.21m

= 14.3 x10^8 Hz

U find no neutral hydrogen in the part of galactic halo.

The region of the Milky Way where you would find little or no neutral hydrogen, no current star formation, and stars that are older than 10 billion years is the galactic halo.

The halo also contains globular clusters, which are dense clusters of very old stars that orbit the galaxy in a halo-like distribution.

The lack of neutral hydrogen and current star formation in the halo is due to the lack of the necessary materials and conditions for these processes.

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The force on the object due to its acceleration at (5, 10) is -1/2mi - 1/2mj, where m is the mass of the object.

To find the force on the object due to its acceleration at the point (5, 10) on the parabola y = 2x, we need to determine the acceleration of the object at that point.

The velocity of the object is constant at 13 units/sec, so the magnitude of the velocity vector is 13 units/sec. Since the object is moving along the parabola, the velocity vector is tangent to the curve at every point.

To find the acceleration, we differentiate the equation of the parabola with respect to time. The derivative of y = 2x is dy/dx = 2, which represents the slope of the tangent line at any point on the parabola.

Since the magnitude of the velocity vector is constant, the acceleration vector is perpendicular to the velocity vector. Therefore, the acceleration vector is given by the negative reciprocal of the slope of the tangent line, which is -1/2.

At the point (5, 10), the acceleration vector is (-1/2)i + (-1/2)j.

Applying Newton's second law, F = ma, where m is the mass of the object, and a is the acceleration vector, we can substitute the values:

F = m(-1/2)i + m(-1/2)j

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power = work done / time taken

= 20/4

= 5 watt

hope it helps

Answer:

A. So that you can see if the answer to a problem makes physical sense.

Explanation:

Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments.

An experiment can be defined as an investigation which typically involves the process of manipulating an independent variable (the cause) in order to be able to determine or measure the dependent variable (the effect).

This ultimately implies that, an experiment can be used by scientists to show or demonstrate how a condition causes or gives rise to another i.e cause and effect, influence, behavior, etc in a sample.

Measurements refers to the process which typically involves the process of identifying and determining the dimensions of a physical object. The dimensions include important parameters such as width, height, length, area, volume, circumference etc.

In Science, making rough estimates of physical quantities is useful so that you can see if the answer to a problem makes physical sense.

For example, you could make a rough estimate of a storage tank and deductively determine whether or not it's in tandem with its physical size in reality.

To start the magnetic field

Answer:

A= 5/3 m/s ^2 or 1.667 m/s^2

Explanation:

The formula is F=ma

F=1500N

m=2500kg

a=?

F=ma

1500=2500 x a

a= 2500/1500

a= 5/3 m/s^2 or 1.667 m/s^2

Nuclear fusion occurs in the core of the sun. It does not take place in the radiative zone or the convection zone.

The sun is composed of different layers, each with specific functions and properties. The core, which is the innermost layer, is where nuclear fusion takes place. This is a process in which hydrogen atoms combine to form helium, releasing a massive amount of energy in the form of light and heat. The temperature in the core reaches around 15 million degrees Celsius, which is essential for nuclear fusion to occur.

The radiative zone, located above the core, is where energy from nuclear fusion moves outward in the form of photons. The temperature in this zone gradually decreases as you move further away from the core. The radiative zone does not host nuclear fusion, but it plays a crucial role in transporting the energy produced in the core to the outer layers of the sun.

The convection zone, situated above the radiative zone, is where heat and energy are transported by convection currents. Hot plasma rises to the surface, cools down, and then sinks back down to be reheated. This process creates a continuous cycle that efficiently transfers energy from the radiative zone to the surface of the sun. Like the radiative zone, the convection zone does not host nuclear fusion but is vital in the sun's overall energy transport process.

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Difference between their wavelengths  position

= 2.403 - 2.217 = .186 mm .

What is wavelength and frequency ?

The wavelength is the distance between two wave crests, and it will be the same for troughs. The frequency is the number of vibrations that pass over a given spot in one second, and it is measured in cycles per second (Hz) (Hertz).

Position of n the order fringe = n λ D / d

for n = 2

position = 2 λ D / d

λ = 710 nm , D = 1.1 m

d = .65 x 10⁻³

position 1 = 2 x 710 x 10⁻⁹ x 1.1 / .65 x 10⁻³

= 2403.07 x 10⁻⁶ m

= 2.403 x 10⁻³ m

= 2.403 mm .

For λ = 655 nm

position = 2 λ D / d

λ = 655 nm , D = 1.1 m

d = .65 x 10⁻³

position 2 = 2 x 655 x 10⁻⁹ x 1.1 / .65 x 10⁻³

= 2216.91 x 10⁻⁶ m

= 2.217 x 10⁻³ m

= 2.217 mm .

Difference between their position

= 2.403 - 2.217 = .186 mm .

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Answer:

\(E=\dfrac{1}{2}mv^2\)

Explanation:

If m is the mass of the object and v is the velocity of the object. The kinetic energy is due to the motion of an object. It is given by the relation as follows :

\(E=\dfrac{1}{2}mv^2\)

The above formula is used to find the kinetic energy of an object.

Answer:

A) d_o = 20.7 cm

B) h_i = 1.014 m

Explanation:

A) To solve this, we will use the lens equation formula;

1/f = 1/d_o + 1/d_i

Where;

f is focal Length = 20 cm = 0.2

d_o is object distance

d_i is image distance = 6m

1/0.2 = 1/d_o + 1/6

1/d_o = 1/0.2 - 1/6

1/d_o = 4.8333

d_o = 1/4.8333

d_o = 0.207 m

d_o = 20.7 cm

B) to solve this, we will use the magnification equation;

M = h_i/h_o = d_i/d_o

Where;

h_o = 3.5 cm = 0.035 m

d_i = 6 m

d_o = 20.7 cm = 0.207 m

Thus;

h_i = (6/0.207) × 0.035

h_i = 1.014 m