You started your preparation of common alum with 0. 9156 g of aluminum foil. What is your theoretical yield of alum?.

Answer:

ma herdina thesto wrestling

The statement that is FALSE about VSEPR is "When electrons are not shared equally, it causes the molecule to bend"

Option C

VSEPR theory does not imply that unequal sharing of electrons causes a molecule to bend.

Rather, it is the repulsion between electron pairs, whether they are bonding or non-bonding, that determines the molecular geometry.

The VSEPR theory is based on the idea that valence electron pairs in the outermost shell of an atom repel each other, and the resulting repulsion determines the geometry of the molecule.

Therefore, Option C is false about VSEPR.

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The number of Al atoms is greater than the number of Sn atoms

Given

20 gram sample of Tin and Aluminum

Required

Number of atoms

Solution

1 mol = 6.02 x 10²³ particles (atoms, molecules, ions)

So the number of atoms of each element is determined by the number of moles. The greater the number of moles the greater the number of atoms

mol = mass : Ar

mol = 20 : 118,71 u

mol = 0.168

mol = 20 : 26.9815 u

mol = 0.741

So the number of Al atoms > number of Sn atoms

In a Pressure-Volume experiment temperature and amount of gas is constant and In a Temperature-Pressure experiment volume and amount of gas is constant.

(a) In a Pressure-Volume experiment, the following factors are assumed to be constant:

1. Temperature: The experiment is typically conducted at a constant temperature. Any changes in pressure and volume are solely attributed to the manipulation of those variables, assuming temperature remains constant.

2. Amount of gas: The amount of gas in the system is usually kept constant throughout the experiment. This ensures that changes in pressure and volume are not influenced by changes in the number of gas molecules present.

(b) In a Temperature-Pressure experiment, the following factors are assumed to be constant:

1. Volume: The volume of the gas sample is typically kept constant during the experiment. This allows for the investigation of the relationship between temperature and pressure while eliminating the influence of volume changes.

2. Amount of gas: Similar to the Pressure-Volume experiment, the amount of gas in the system is generally kept constant. This ensures that changes in temperature and pressure are solely attributed to the manipulation of those variables, while holding the number of gas molecules constant.

By controlling these factors, researchers can isolate the effects of pressure and volume or temperature and pressure on gas behavior, allowing for a more precise understanding of the relationship between these variables.

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Answer:

B. weight is the pull of gravity

C. mass is the amount of matter in an object

E. weight can change

Answer:2.41 molecules

Explanation:

Answer:

2.41 molecules.

Explanation:

0.400 mol N2O5 contains 2.41 molecules N2O5.

1mole N2O5=6.022 × 1023molecules N2O5.

Answer:

hello :3

A cold is a contagious upper respiratory infection that affects your nose, throat, sinuses and trachea (windpipe).

Explanation:

have a nice day :3

When you divide the mass of a substance by its volume you get its density.

Density is defined as mass per unit volume of a material or substance. The formula for density is d = M/V, where d represents density, M is mass, and V is volume. Density is commonly expressed in grams per cubic centimeter. Density depends on the mass of the body, higher the mass, higher will be the density.

So we can conclude that When you divide the mass of a substance by its volume you get its density.

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Different concentrations of sulfuric acid and sodium hydroxide are used in Part I of a titration experiment to achieve the required stoichiometric ratio of 1:2, where a higher concentration of sodium hydroxide is needed to neutralize the acid.

In Part I of a titration experiment, different concentrations are used for sulfuric acid and sodium hydroxide because their stoichiometric reaction requires different amounts of each reagent to neutralize the other. The reaction between sulfuric acid and sodium hydroxide involves a 1:2 ratio of acid to base, meaning that two moles of sodium hydroxide are required to neutralize one mole of sulfuric acid.

To achieve this stoichiometric ratio, a higher concentration of sodium hydroxide is needed relative to the sulfuric acid. Therefore, in the experiment, a 3 M solution of sulfuric acid is used while a 6 M solution of sodium hydroxide is used to ensure that the stoichiometric ratio is achieved when titrating the two solutions together.

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Answer:

Global wind

Explanation:

The jet streams go around the whole earth from west to east

Hope you have a good day :)

b. Ethylene is symmetrical; all bond dipole moments cancel out.

In ethylene (C₂H₄), the molecule is symmetrical with a linear structure. Each carbon atom is bonded to two hydrogen atoms and shares a double bond with the other carbon atom. The electronegativity of carbon and hydrogen is similar, resulting in an equal sharing of electrons in the bonds. As a result, the bond dipole moments in ethylene are equal in magnitude but opposite in direction. The dipole moments cancel each other out, resulting in a net dipole moment of zero for the entire molecule.

In propene (C₃H₆), there is an additional methyl (CH₃) group attached to one of the carbon atoms. The methyl group has a slight electron-donating effect due to the presence of the carbon-hydrogen bonds. This creates a small imbalance in electron distribution within the molecule, resulting in a slight dipole moment. The dipole moment in propene is approximately 0.3 D, indicating a small separation of charges due to the presence of the methyl group.

Therefore, option b is correct as it explains that the zero dipole moment in ethylene is due to its symmetrical structure, while the small dipole moment in propene arises from the electron-donating ability of the methyl group.

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The complete question is:

Select all the statements that correctly explain why ethylene has a zero dipole moment, whereas propene has a small dipole moment of 0.3 d.

a. small dipole moment in propene arises from electron-donating ability of methyl group

b. ethylene is symmetrical; all bond dipole moments cancel out

c. small dipole moment in propene arises from electron-withdrawing ability of methyl group

The amount of heat required to raise the temperature of 125.0 g of aluminum by 12°C is 1611 joules.

Temperature = 12°C

Mass = 125.0 g

To estimate the amount of heat required, we need to use the formula:

Q = m * c * ΔT

Q = the amount of heat in joules

m = the mass of the substance in kilograms

c = the specific heat capacity of the substance

ΔT = the change in temperature in degrees

The specific heat capacity of aluminum = 0.897 J/g°C.

Q = 125.0 g * 0.897 J/g°C * 12°C

Q = 1611 J

Therefore, we can conclude that the amount of heat required is 1611 J.

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The freezing point of water will be lowered most by dissolving 1.0 mole of magnesium chloride (MgCl₂).

When a solute is dissolved in a solvent, such as water, it disrupts the orderly arrangement of water molecules, making it more difficult for them to form solid ice crystals. This disruption leads to a lowering of the freezing point of the solvent.

The extent to which the freezing point is lowered depends on the nature of the solute and its concentration. In this case, comparing the given options, dissolving 1.0 mole of magnesium chloride (MgCl2) will have the greatest effect on lowering the freezing point of water.

Magnesium chloride dissociates into three ions in water: one magnesium ion (Mg2+) and two chloride ions (Cl-). The presence of multiple ions increases the number of solute particles per mole, leading to a greater disruption of the water structure.

As a result, the freezing point depression caused by 1.0 mole of magnesium chloride is more significant compared to other solutes.

In contrast, naphthalene is a nonpolar solute and does not dissociate into ions in water. Sodium chloride (NaCl) dissociates into two ions, and ether is a nonpolar compound. Therefore, these substances would have a lesser effect on lowering the freezing point of water compared to magnesium chloride.

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(a) Magnesium sulfide (MgS) is expected to have a tetrahedral crystal structure.

(b) Lithium chloride (LiCl) is expected to have an octahedral crystal structure.

(c) Potassium bromide (KBr) is expected to have a cubic crystal structure.

To predict the kind of crystal structure expected for magnesium sulfide (MgS), lithium chloride (LiCl), and potassium bromide (KBr) using the radius-ratio rule, we need to compare the ratio of the radii of the cation and anion with the critical values for different crystal structures.

The radius-ratio rule states that the ratio of the radii of the cation to the anion in an ionic compound determines the type of crystal structure it adopts.

We can find the critical radius ratio values for different crystal structures. Here are the values for some common crystal structures:

Coordination number 6 (octahedral): 0.414 - 0.732

Coordination number 8 (cubic): 0.732 - 1.0

Coordination number 4 (tetrahedral): 0.225 - 0.414

Now let's analyze each compound:

(a) Magnesium sulfide (MgS):

Mg²⁺ ion radius: 0.072 nm

S²⁻ ion radius: 0.184 nm

Radius ratio = (cation radius) / (anion radius) = 0.072 / 0.184 ≈ 0.391

Based on the radius ratio, which is less than 0.414, we can predict that magnesium sulfide (MgS) adopts a coordination number 4 (tetrahedral) crystal structure.

(b) Lithium chloride (LiCl):

Li⁺ ion radius: 0.076 nm

Cl⁻ ion radius: 0.181 nm

Radius ratio = (cation radius) / (anion radius) = 0.076 / 0.181 ≈ 0.420

The radius ratio for lithium chloride is between 0.414 and 0.732. This suggests that lithium chloride (LiCl) adopts a coordination number 6 (octahedral) crystal structure.

(c) Potassium bromide (KBr):

K⁺ ion radius: 0.138 nm

Br⁻ ion radius: 0.196 nm

Radius ratio = (cation radius) / (anion radius) = 0.138 / 0.196 ≈ 0.704

The radius ratio for potassium bromide is within the range of 0.732 - 1.0. This indicates that potassium bromide (KBr) adopts a coordination number 8 (cubic) crystal structure.

In summary:

(a) Magnesium sulfide (MgS) is expected to have a tetrahedral crystal structure.

(b) Lithium chloride (LiCl) is expected to have an octahedral crystal structure.

(c) Potassium bromide (KBr) is expected to have a cubic crystal structure.

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Answer:

The plasmodial slime molds are the kind of protist that can live in groups in which different individuals perform different jobs. Some kinds of bacterial cell walls also have other functions.

Answer:

7.82 g of Cu

Explanation:

2 moles of Al react to 3 moles of copper sulfate in order to produce 3 moles of copper and 1 mol of aluminum sulfate.

Firstly we determine the moles of reactant.

As copper sulfate is in excess, Al is the limiting.

2.75 g . 1mol /26.98g = 0.102 moles

Ratio is 2:3. 2 moles of Al, can produce 3 moles of Cu

So the 0.102 moles of Al will produce(0.102 . 3) /2 = 0.153 moles.

We convert moles to mass: 0.153 mol . 63.5g /mol = 9.71 g

That's the theoretical yield (100 % yield reaction)

We know that: (yield produced / theoretical yield) . 100 = percent yield

We replace:

(Yield produced / 9.71g) . 100 = 80.5  %

(Yield produced / 9.71g) = 0.805

Yield produced = 0.805 .  9.71g = 7.82 g

Answer:

the answer is 6.5 x 10^4

Answer:

6.5 x 10^4

Explanation:

Answer:

9.51 x 10²² atoms Au

Explanation:(mass: 31.1g Au)

(m. mass: 196.967 g/mol Au)

(atoms: ?)

(31.1g Au x 1 mol Au x 6.022 x 10²³ atoms Au/ 196.967g Au x 1 mol Au)

Answer:

102.0 g/mol.

Explanation:

Aluminum oxide or Al2O3 is a chemical compound composed of 3 Oxygen and 2 aluminum atoms. Naturally, it is present in the form of mineral corundum in crystalline polymorphic forms. It holds significant importance in the preparation of Aluminium metal that is used as a refractory material.

To calculate the molar mass of Aluminum oxide, we will add the molar mass of 2 Al and 3 O atoms.

                        Since molar mass of Al is: 26.98 g

                              Molar mass of O is: 16.00 g

                                  Molar mass of Al2O3

                                 =   (26.98)2 +  (16.00) 3

                                    =    53.96 +   48

                                      = 101.96 g/mol

Since it is mentioned in question to round off the answer upto 4 significant figures, it will make the answer: 102.0 g/mol.

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Answer:

102 grams/mol

Explanation:

This is correct! :)

Answer:

absorbed

Explanation:

Different colors of light can be reflected or absorbed and that determines color. For instance an object that absorbs every color but green will appear green to the human eye.

In order to maximize the selectivity of the monochloroethane production relative to the dichloroethane production, the reactor must be designed for a low conversion of ethane.

What is selectivity? Selectivity is a term used to describe the extent to which a chemical reaction produces a single product rather than a mixture of multiple products. It is determined by dividing the amount of the desired product by the total amount of product(s) formed in the reaction. High selectivity implies that the desired product is produced in high quantities relative to undesired products.

A low conversion rate of ethane is preferable in this case, since the side reaction that creates dichloroethane is highly exothermic, thus raising the temperature and rate of this side reaction. So, in order to keep the production of the side product to a minimum, a lower conversion rate is needed. Processing Steps: Almost certainly additional processing steps would be required to make the process economical.

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Answer:

V₂  = 495.89 mL

Explanation:

Given data:

Initial number of moles = 0.213 mol

Initial volume = 652 mL

Final number of moles = 0.162 mol

Final volume = ?

Solution:

V₁/n₁    =    V₂/n₂

By putting values,

652 mL/0.213 mol   =  V₂ /0.162 mol

V₂  = 652 mL 0.162 mol /0.213 mol

V₂  = 105.62 mL.mol /0.213 mol

V₂  = 495.89 mL

Answer:

Well maybe the pedals they don't help much

Explanation:

Answer:

brainliest please

Explanation:

the pollen probably because other plants have it

Answer:

68.46 gms

Explanation:

2 molal solution means there is 2 moles of sucrose per kg of solvent (generally 1000 cc)

2 moles / 1000 ml * 100 ml = .2 moles

mole weight of sucrose = 342.3 gm/mole

342.3 gm/mole * .2 mole = 68.46 gms

The dark moths were better hidden from predators and therefore more of them survived and this allowed them to have offspring.

Answer:

The dark moths were better hidden from predators and therefore more of them survived and this allowed them to have offspring.

Explanation:

If all of the light colored trees disappeared and there are only dark colored ones, then that means that the light colored moths wouldn't be able to live long since their traits wouldn't match the environment. This then leads to the conclusion that dark moths would be better hidden since their trait fits their current environment and would let them be hid much better from predators. This would allow them to survive longer and eventually, reproduce.

The type of radiation in this scenario is Beta and is denoted as option C.

This is a high-speed electron which is emitted when the nucleus undergoes a radioactive decay during the process of beta decay.

In this scenario the electron is denoted as e with a superscript and subscript of 0 and -1 respectively which is the reason for the change from carbon to nitrogen.

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The net ionic equation to show why the solubility of Co(OH)2(s) increases in the presence of a strong acid is as follows: Co(OH)2(s) + 4H+(aq) → Co2+(aq) + 4H2O(l).

In this reaction, Co(OH)2 is a sparingly soluble salt that undergoes dissolution in the presence of a strong acid. The acid, represented by 4H+, protonates the hydroxide ions (OH-) from Co(OH)2, forming water (H2O) and Co2+ ions. The presence of excess H+ ions shifts the equilibrium towards the formation of Co2+ ions, increasing the solubility of Co(OH)2. To calculate the equilibrium constant (K) for this reaction, we can use the expression: K = [Co2+]/[H+]^4, where [Co2+] represents the concentration of Co2+ ions and [H+] represents the concentration of H+ ions. The values of [Co2+] and [H+] can be determined experimentally, and plugging them into the equation will give the equilibrium constant (K) for the reaction.

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Atomic size, also known as atomic radius, is a measurement of the size of an atom. It is one of the fundamental properties of elements in the periodic table and helps us understand the physical and chemical behavior of different elements.

Atomic size refers to the distance between the nucleus of an atom and the outermost electrons. It is usually measured in nanometers (nm) or picometers (pm).

The atomic size of an element can be determined by several factors, including the number of protons in the nucleus and the number of electron shells surrounding the nucleus. As a general rule, the atomic size decreases from left to right across a row in the periodic table and increases as you move down a column.

For example, the atomic size of lithium (Li) is 140 pm, while the atomic size of sodium (Na) is 186 pm. This is because sodium has one more electron shell than lithium, which makes it larger.

In addition to affecting the physical and chemical behavior of elements, atomic size also plays a vital role in determining the reactivity of different elements. For example, elements with smaller atomic sizes tend to be more reactive than elements with larger atomic sizes.

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The claim: "If the nucleus were the size of a grape, the electrons would be one mile away on average" is reasonably accurate because the ratios between the nucleus's sizes and the distances (between electrons and nucleus) for the two given examples are in the same order of magnitude.      

To know if the claim is accurate we need to calculate the ratio of the size of the nucleus (the same as a grape) and the distance between the electrons and the nucleus for example 1 (r₁):  

\( r_{1} = \frac{s_{1}}{d_{1}} \)    (1)

and to compare it with the ratio of the size and the distance given in example 2 (r₂):

\( r_{2} = \frac{s_{2}}{d_{2}} \)    (2)

Where:

s₁: is the size of the nucleus (like the size of a grape)

d₁: is the distance between electrons and nucleus of example 1 = 1 mile

s₂: is the average diameter of the nucleus  = 10⁻¹³ cm

d₂: is the average distance between electrons and nucleus of example 2 = 10⁻⁸ cm

Assuming that the diameter of a grape is 3 cm (in a spherical way), the ratio of the first example is (eq 1):

\( r_{1} = \frac{3 cm}{1 mi*\frac{160934 cm}{1 mi}} = 1.86 \cdot 10^{-5} \)

Now, the ratio of the second example is (eq 2):

\( r_{2} = \frac{10^{-13} cm}{10^{-8} cm} = 1.00 \cdot 10^{-5} \)              

Since r₁ and r₂ are in the same order of magnitude (10⁻⁵), we can conclude that the given claim is reasonably accurate.      

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