We need to add 10.90 g of NaOH to the 250 ml sample of 1.09 molarity acetic acid to make the best buffer.
To make the best buffer from a 250 ml sample of 1.09 molarity acetic acid, we need to find out how much NaOH must be added. The Henderson-Hasselbalch equation, which relates the pH of a buffer to its pKa and the ratio of its weak acid to weak base forms.pH = pKa + log([A-]/[HA])In this case, we are dealing with an acetic acid buffer, which has a pKa of 4.76.
We are given a 250 ml sample of 1.09 molarity acetic acid. The molar mass of acetic acid is 60.05 g/mol. Therefore, the number of moles of acetic acid in the sample is:n(acetic acid) = M(acetic acid) x V(acetic acid)n(acetic acid) = 1.09 mol/L x 0.250 Ln(acetic acid) = 0.2725 molNext, we need to find out the amount of NaOH we need to add to make the buffer.
This is a bit tricky because we are given the volume of the acetic acid solution, but not the volume of the final buffer. We also don't know the concentration of the NaOH solution. However, we can use the fact that the buffer is prepared by mixing a weak acid with its conjugate base. Therefore, we can assume that the final buffer will have approximately equal concentrations of acetic acid and acetate ions, which means we need to add an equal amount of NaOH to convert half of the acetic acid to acetate ions.
The balanced chemical equation for the neutralization reaction is:CH3COOH + NaOH → CH3COONa + H2OThe stoichiometry of the reaction is 1:1, which means we need to add an equal number of moles of NaOH to neutralize the acetic acid.n(NaOH) = n(acetic acid) = 0.2725 molNow we need to find out how much NaOH that is in grams.
We can use the molar mass of NaOH to convert from moles to grams.m(NaOH) = n(NaOH) x M(NaOH)m(NaOH) = 0.2725 mol x 40.00 g/molm(NaOH) = 10.90 gTherefore, we need to add 10.90 g of NaOH to the 250 ml sample of 1.09 molarity acetic acid to make the best buffer.
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Which of these is an ex
example of a composite material?
Answer:
A composite material is a material made from two or more constituent materials with significantly different physical or chemical properties that, when combined, produce a material with characteristics different from the individual components.
Explanation:
you're welcome
How many grams of sodium hydroxide (NaOH) do you need to make 6.5 L of 1.0M solution?
260grams
Explanations:The formula for calculating the moles of NaOH is expressed as
\(\begin{gathered} moles=molarity\times volume \\ moles\text{ of NaOH}=1.0M\times6.5L \\ moles\text{ of NaOH}=6.5moles \end{gathered}\)Determine the required mass of NaOH
\(\begin{gathered} Mass\text{ of NaOH}=moles\times molar\text{ mass} \\ Mass\text{ of NaOH}=6.5\cancel{moles}\times\frac{40g}{\cancel{mole}} \\ Mass\text{ of NaOH}=260grams \end{gathered}\)Hence the grams of sodium hydroxide (NaOH) you need to make 6.5 L of 1.0M solution is 260grams
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Chemistry =>Introduction to Chemistry => Scientific Method
A scientific method corresponds to a methodology to obtain new knowledge.
We must start from an idea, an assumption of how a compound or a process behaves, this is our hypothesis.
Following this, we must identify what can affect our process, what are the variables, and what will be the response variable, for this we carry out an experiment.
Once the experiments have been carried out, we must analyze the results, draw conclusions as to why the behavior occurs, and if our hypothesis is true or not.
It is useless for us to obtain new knowledge if we do not share it, We have to share the results, in this way other people can start from that knowledge to create another,
Therefore, the answer will be:
1. Make a hypothesis
2. Conduct an experiment
3. Analyze the experiment data
4. Communicate the results
pls help, I will give Brainlist if you answer correct. pls
Explanation:
The union of vinegar and bicarbonate produces carbon dioxide
The carbonic acid, which is weaker, in turn breaks down into water and carbon dioxide, which being volatile separates
will observe a yellow color, confirming that BASIC HYDROLYSIS has taken place. To the touch the bottle cools and in the end a white deposit may remain on the bottom.
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If u know any please tell!?
Answer: 176 g N2O, 72 g H2O
Explanation:
1. 64g O2 * (1 mol O2)/(32 g O2) * (2 mol N2O)/(1 mol O2) * (44g N2O)/(1 mol N2O) = 176 g N2O
2. 32g CH4 * ( 1 mol CH4)/(16 g CH4) * (2 mol H2O)/(1 mol CH4) * (18 g H2O)/(1 mol H2O) = 72 g H2O
Explain: how dose the sun cause wind
Help
Answer:
As the sun warms the earths surface the atmosphere warms too. Then cool airs moves in and replaces the rising warm air. This movement of air is what makes the wind blow.
The nonmetals include which of the following groups? Use the periodic table to answer the question.
Check all that apply.
halogens
alkali metals
lanthanides
noble gases
alkaline earth metals
Answer:
halogen
Explanation:
Group VIIA/halogen/ is the only group in periodic table in which all the elements are nonmetals. This group contains F, Cl, Br, I, and At. Halogen meaning salt producer.
Which molecules is converted directly to acetyl CoA without the intermediate step of being converted first to pyruvate
Answer:
Fatty acids
Explanation:
Acetyl coA is a compound vital for the process of cellular respiration in the mitochondria. It is the starting material of the kreb's cycle or TCA cycle, which takes place in the mitochondria. During the metabolism of glucose (glycolysis), a molecule called PYRUVATE is first synthesized before becoming acetyl coA in the mitochondrion.
However, the metabolism of FATTY ACIDS (monomers of lipids) directly gives rise to acetyl coA without first becoming pyruvate. The fatty acids molecule undergo Beta- oxidation to produce acetyl coA, which enters the TCA cycle to continue cellular respiration.
. To compute the distribution of a volatile solute between a hydrocarbon polymer phase(e.! polybutane) and the vapor phase, a weight fraction activity coefficient( n) is used. The activity of the solute in the liquid phase is: a solute =w solute (Ohm) where w seluse is the weight fraction of the solute in the polymer The weight fraction activity coefficient has the advantage of being nearly constant over a wide range of temperatures and nearly linear in weight fractions below 0.1. What is the reason for using a weight fraction activity coefficient for solutes in a polymer? A. the vapor pressure of polymers is very low b. The viscosity of concentrated polymer solutions is high c. the density of the polymer is different from the density of the solute d. The molecular weight of a polymer is an undefinable value, unlike the solute.
The reason for using a weight fraction activity coefficient for solutes in a polymer is because the viscosity of concentrated polymer solutions is high.
What is a hydrocarbon?
Hydrocarbons are organic compounds made up of only hydrogen and carbon atoms. Hydrocarbons are chemical compounds that are simple and essential. They are organic compounds that are made up of carbon and hydrogen only. Hydrocarbons may be found in a variety of types. They can be aliphatic or aromatic, depending on their structure.
What is a polymer?
A polymer is a substance made up of numerous molecules that are the same or similar to one another. Polyethylene, polystyrene, polypropylene, polyvinyl chloride, and polytetrafluoroethylene are all common polymers.
What is viscosity?
Viscosity is a physical property of fluids that reflects their resistance to flow. It describes how easily a fluid can flow and how well it can resist deformation when subjected to an external force. The viscosity of fluids is typically determined by their internal friction or the friction that occurs between molecules or layers of the fluid when they flow. Hence, the viscosity of concentrated polymer solutions is high, and that is why weight fraction activity coefficient is used for solutes in a polymer.
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.
The earth is slightly tilted on its axis. How much is it tilted?
23.5 degrees
28 degrees
20.5 degrees
25 degrees
How hot or cold the air is.
The heterosphere is the layer of the atmosphere in which the gases are ________ because of ________.
The heterosphere is the layer of the atmosphere in which the gases are
poorly mixed because of the gravity influence.
What is Heterosphere?This is a part of the atmosphere which is characterized by gases being
separated out as a result of diffusion. This is usually pronounced with
increasing altitude in the atmosphere.
The gases in the layer are poorly mixed as a result of gravity which causes
gases of different weight to separate into layers.
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what conclusions can you draw about how the plasma membrane contributes to the function of the cell as a whole write an evidence based claim. will give brainleist
Answer:
Plasma membranes have three primary functions: (1) they keep toxic substances out of the cell; (2) they contain receptors and channels that allow specific molecules, such as ions, nutrients, wastes, and metabolic products, that mediate cellular and extracellular activities to pass between organelles and between the cell and the outside environment; and (3) they separate vital but incompatible metabolic processes conducted within organelles
Explanation:
What is the pH of a solution of a 3.4 x 10-8 M [H"] solution if its pOH = 7.5?
pH =
Answer:
6.5
Explanation:
14-7.5 = 6.5
Answer: 6.75
Explanation:
Which two compounds are not isomers of each other?
a. n-pentane and 2-methylbutane
b. ch3ch2oh and ch3och3
c. ch3cooh and ch3ch2cooh
d. ch3coch3 and ch3ch2cho
e. ch3ch2ch2cl and ch3chclch3
The two compounds that are not isomers of each other are:
b. CH3CH2OH (ethanol) and CH3OCH3 (dimethyl ether).
Isomers are compounds that have the same molecular formula but different structural arrangements or connectivity of atoms. Let's analyze the options to identify the correct pair of non-isomeric compounds.
a. n-pentane and 2-methylbutane:
These compounds have the same molecular formula, C5H12, but differ in the arrangement of carbon atoms. Therefore, they are isomers of each other.
b. CH3CH2OH and CH3OCH3:
These compounds have different molecular formulas, with CH3CH2OH representing ethanol and CH3OCH3 representing dimethyl ether. They differ both in their molecular formulas and structural arrangements, so they are not isomers of each other.
c. CH3COOH and CH3CH2COOH:
These compounds have different molecular formulas, with CH3COOH representing acetic acid and CH3CH2COOH representing propanoic acid. Like the previous case, they differ in both molecular formulas and structural arrangements, making them non-isomers.
d. CH3COCH3 and CH3CH2CHO:
These compounds are isomers of each other since they have the same molecular formula, C3H6O, but differ in the connectivity of atoms. CH3COCH3 represents acetone, while CH3CH2CHO represents propanal.
e. CH3CH2CH2Cl and CH3CHClCH3:
These compounds are isomers of each other, with the same molecular formula, C3H7Cl, but different arrangements of atoms. CH3CH2CH2Cl represents 1-chloropropane, and CH3CHClCH3 represents 2-chloropropane.
To summarize, the pair of compounds that are not isomers of each other is b. CH3CH2OH and CH3OCH3.
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Light
6CO2 + 6H20
CGH12O6 +602
Chlorophyll
The equation above describes the chemical reaction that occurs during
photosynthesis. What happens to the light energy that is shown in the reaction?
Answer:
Light energy acts as a catalyst that speeds up the rate of photosynthesis
Explanation:
Identify two issues that can arise when measuring heat changes for a chemical reaction using a calorimeter.
Long-term heat loss to the calorimeter is a problem, especially for slow-moving processes.
How does a calorimeter work as a heat meter?The water iscontained in a tank whose thermal capacity and weight were predete partially rmined before the experiment began. Calculating heat and flow rates involves measuring the rise in water temperature and volume over a predetermined period of time.
What takes place when a calorimeter absorbs heat?In contrast, if the reaction absorbs heat, heat is transmitted from the calorimeter to the system, lowering the calorimeter's temperature.
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A gas is formed in the reaction shown below. The gas laws can help determine the volume of gas produced.
Zn(s) + 2 HCl(aq) → ZnCl₂ + H₂(g)
Assume that 130.8 grams of Zn was used in this reaction. To determine the number of moles of hydrogen gas formed, you need to know the number of moles of Zn reactant was used. What quantity in moles of Zn were used?
Considering the definition of molar mass, the number of moles of Zn reactant used is 2 moles.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Number of moles of Zn usedThe balanced reaction is:
Zn(s) + 2 HCl(aq) → ZnCl₂ + H₂(g)
Assume that 130.8 grams of Zn was used in this reaction.
To determine the number of moles of hydrogen gas formed, you need to know the number of moles of Zn reactant was used.
So to determine the number of moles used you know that the molar mass of Zn is 65.37\(\frac{g}{moles}\). Then:
\(molar mass=\frac{mass}{number of moles}\)
\(65.37\frac{g}{moles} =\frac{130.8 g}{number of moles}\)
Solving:
number of moles× 65.37\(\frac{g}{moles}\)= 130.8 g
\(number of moles=\frac{130.8 g}{65.37\frac{g}{moles}}\)
number of moles≅ 2 moles
Finally, the number of moles of Zn reactant used is 2 moles.
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2. Which type of glassware is used for general mixing, measuring and
boiling?
A. crucible
B. funnel
C. separatory funnel
D. beaker
Answer:
D
Explanation:
A beaker can be used for boiling coz it can withstand high temperatures.
It can be used for measuring the volume of a solid indirectly by measuring the displacement of a liquid.
It can as well be used for mixing coz it flat bottomed
A ruby has a mass of 7.5 g and a volume of 1.9 cm^3. What is the density of this ruby ?
Answer: 3.94736842105
Explanation:
Density = mass/volume
Density = 7.5/1.9
Density = 3.94736842105
In pinnately compound leaves, the leaflets arise from either side of the __________
In pinnately compound leaves, the leaflets arise from either side of the rachis. The rachis is the main axis or stalk of the leaf, to which the leaflets are attached. It serves as the central support structure for the leaflets in a pinnately compound leaf.
To better understand this, imagine the rachis as the stem of the leaf. The leaflets, which are smaller leaf-like structures, are attached to the rachis in a feather-like pattern. The leaflets can be arranged in pairs, with each pair emerging from opposite sides of the rachis.
For example, in a pinnately compound leaf like the fronds of a fern or the leaves of a rose bush, the leaflets arise from the sides of the rachis. This arrangement allows the leaf to efficiently capture sunlight and perform photosynthesis.
In summary, in pinnately compound leaves, the leaflets arise from either side of the rachis, which serves as the central axis of the leaf.
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a gas cylinder containing helium gas at a pressure of 3.0 atm and a volume of 6.0 l is used to fill an empty balloon. how many 1.0 l balloons can be filled, if the final pressure of each balloon and cylinder are 1.0 atm?
Each 1.0 L balloon requires 1/18.8 = 0.053 moles of helium gas. You can fill approximately 13 1.0 L balloons with the helium gas in the cylinder.
Now, we can use the ideal gas law again to find the final volume of each balloon when the pressure is reduced to 1.0 atm:
PV = nRT
V2 = nRT/P2
V2 = (0.716 moles x 0.082 L atm/mol K x 298 K)/1.0 atm
V2 = 18.8 L/mol
The total number of 1.0 L balloons that can be filled with the 6.0 L cylinder of helium gas is:
n_total = n_initial/n_balloon
n_total = 0.716 moles/0.053 moles per balloon
n_total = 13.5 balloons
The ideal gas law is a fundamental equation in thermodynamics that relates the pressure, volume, temperature, and amount of gas in a closed system. It is expressed mathematically as PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
This law is based on the assumption that gases are composed of small particles that move randomly and collide with each other and the walls of the container they are in. The ideal gas law is a useful tool for predicting the behavior of gases under different conditions, such as changes in temperature and pressure. Real gases deviate from ideal behavior at high pressures and low temperatures, and more complex equations must be used to describe their behavior accurately.
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help me please... tyy if you do :))
Answer:
a) HCl
Explanation:
As we know, that HCl or Hydrogen Chloride is a diatomic compound. It is formed due to the Chemical reaction of Hydrogen and Chlorine. As both Hydrogen and Chlorine have valencies of 1, the Net Valency of the Compound HCl is 1 itself. This separates it from the rest of the compounds. The rest of the compounds need to have more than 2 atoms of each kind and have different valencies too.
Please Answer Correctly
If correct I will mark brainliest
This is fill in the blank, not multiple choice.
QUESTION:
r is measured from the ____ of an object.
Explanation: The radius of an object is found from the center of the object to the perimeter. Radius can be any number, but it is the measurement from the center to the perimeter.
An atom has 21 protons, 24 neutrons, and 18 electrons. Which change will cause the atom to have more negatively charged particles than positively charged particles?
losing two protons
losing four neutrons
gaining three electrons
gaining four electrons
Answer:
ganar tres electrones
Explanation:
Answer:
gaining three electrons
Physical and chemical properties are used to describe and identify matter. Physical properties can be observed without changing the identity of the substance. Chemical properties can be observed by attempting to change the identity of a substance. What are two physical and chemical properties that you can use to help you identify a substance?
Extensive properties, such as mass and volume, depend on the amount of matter that is being measured. ... Both extensive and intensive properties are physical properties, which means they can be measured without changing the substance's chemical identity
solution is made by dissolving 0.567 mol of nonelectrolyte solute in 813 g of benzene. calculate the freezing point, f, and boiling point, b, of the solution
The freezing point of the solution is approximately 1.93 °C, and the boiling point is approximately 81.86 °C.
To calculate the freezing point depre ssion and boiling point elevation of a solution, we can use the formulas:
Freezing point depre ssion (ΔTf) = Kf × m
Boiling point elevation (ΔTb) = Kb × m
Where:
Kf is the cryos copic constant of the solvent (benzene)
Kb is the ebulli oscopic constant of the solvent (benzene)
m is the molality of the solution
First, let's calculate the molality (m) of the solution:
Molality (m) = moles of solute / mass of solvent (in kg)
Given:
Moles of solute = 0.567 mol
Mass of solvent (benzene) = 813 g = 0.813 kg
Molality (m) = 0.567 mol / 0.813 kg
m ≈ 0.697 mol/kg
Next, we need to determine the cryo scopic constant (Kf) and ebulli oscopic constant (Kb) for benzene. These constants are specific to the solvent and can be looked up in reference tables.
For benzene:
Kf = 5.12 °C/m
Kb = 2.53 °C/m
Now, we can calculate the freezing point depr ession (ΔTf) and boiling point ele vation (ΔTb) using the given molality and constants:
ΔTf = Kf × m
ΔTf = 5.12 °C/m × 0.697 mol/kg
ΔTf ≈ 3.57 °C
The freezing point of the solution is the freezing point of pure benzene (5.5 °C) min us the freezing point depre ssion:
Freezing point (f) = 5.5 °C - 3.57 °C
f ≈ 1.93 °C
ΔTb = Kb × m
ΔTb = 2.53 °C/m × 0.697 mol/kg
ΔTb ≈ 1.76 °C
The boiling point of the solution is the boiling point of pure benzene (80.1 °C) plus the boiling point elevation:
Boiling point (b) = 80.1 °C + 1.76 °C
b ≈ 81.86 °C
Therefore, the freezing point (f) of the solution is approximately 1.93 °C, and the boiling point (b) is approximately 81.86 °C.
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If a 0.5ml air bubble is present in the tip of a Burette what percent error in 10ml 20ml and 40ml samples will result if the air bubble is dislodged during the dispensing of the samples
Live as if you were to die tomorrow. ...
“That which does not kill us makes us stronger.” ...
“Be who you are and say what you feel, because those who mind don't matter and those who matter don't mind.” ...
“We must not allow other people's limited perceptions to define us.”
Suppose you want to search for high-redshift star-forming galaxies using a telescope equipped with a spectrograph able to measure the entire optical spectrum (400-700 nm). Star-forming galaxies contain copious hydrogen gas, from which stars form. Some of this gas will be ionized by the newly-formed stars; the spectra of star-forming galaxies there exhibit bright hydrogen lines in emission. Light from the newly-formed stars is absorbed by neutral hydrogen gas as it passes through the galaxy. a) If you wish to search for Lyman-a emitting galaxies, over what redshift range can you find such galaxies? [3 points] b) If you detect only one line, you cannot be certain that this line is the Lyman-a line, and hence that the galaxy is indeed at the computed redshift. Assuming you can also observe in the infrared (wavelengths >700 nm), how can you change your strategy to make sure that the line you detect is really the Lyman-a line? Give three examples of how you can increase confidence in the correct identification of the Lyman-a line considering only hydrogen gas. [3 points] c) Limited only to optical wavelengths and considering only hydrogen gas, what strategy should you adopt to be certain that the line you detect is really the Lyman-a line while maximizing the redshift range over which you find galaxies? With this strategy, over what redshift range can you find star-forming galaxies? Justify through appropriate computations and reasoning that this is in fact the optimal strategy for maximizing the redshift range of your search. [10 points] d) Apart form hydrogen emission lines, star-forming galaxies also usually exhibit bright [OIII] forbidden lines. Why can such lines be seen from interstellar gas but not the Earth's atmosphere or in the laboratory? [4 points]
a) The maximum observable range of redshifts that produces Lyman-alpha line is 0 ≤ z ≤ 10.6
b) i) identifying the galaxy with a radio source, ii) looking for other Lyman lines, iii) a coincidence with a continuum break
c)The maximum redshift range over which galaxies can be found using this strategy is z = 7 to z = 15.5.
d)Earth's atmosphere absorbs the radiation, and the laboratory conditions are not the same as interstellar conditions.
a) Lyman-alpha line is produced by the hydrogen atoms that have electrons that are in the ground state being raised to the first excited state. Over a certain range of redshifts, the Lyman-alpha line is redshifted to longer wavelengths that are observable by an optical spectrograph. The maximum observable range of redshifts that produces Lyman-alpha line is 0 ≤ z ≤ 10.6 (depending on the exact details of the galaxy's emission profile).
b) Observing the galaxy in the infrared can help in the identification of the Lyman-alpha line as it is shifted to longer wavelengths. Three ways to increase confidence in the correct identification of the Lyman-alpha line are:
i) identifying the galaxy with a radio source, ii) looking for other Lyman lines, iii) a coincidence with a continuum break.
c) The strategy that needs to be adopted is to look for the Lyman limit, which is the point at which the spectrum is cut off by the absorption of all hydrogen in the galaxy. To be certain that the line you detect is the Lyman-alpha line, you need to look for a decrement in the flux of the galaxy at wavelengths shorter than the line and a decrement in the flux at wavelengths longer than the line. This is because the Lyman limit will be shifted to longer wavelengths at higher redshifts, so to maximize the redshift range over which galaxies can be found, you need to search for the Lyman limit at the longest wavelength possible. The maximum redshift range over which galaxies can be found using this strategy is z = 7 to z = 15.5.
d) The reason why such lines can be seen from interstellar gas but not the Earth's atmosphere or in the laboratory is that the Earth's atmosphere absorbs the radiation, and the laboratory conditions are not the same as interstellar conditions. The forbidden lines from the interstellar gas are not affected by dust absorption because they are produced in regions where dust is not present.
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Which element requires the least amount of energy to remove the most loosely held electron?
Р
CI
Ar
Na
Which element requires the least amount of energy to remove the most loosely held electron?
aanswer: bromine