you drink a can of coke, 140 Calories, how many pushups do you have to do to burn off all the energy you took in? Your mass is 80 kg (although you only lift half that, 40 kg in a pushup) and your push up lifts you 0.50m.

Answers

Answer 1

You'd need to perform about 262 pushups to expend the energy in a can of Coke.

How many calories are burned while performing 20 pushups?

Push-ups typically result in a 32 calorie burn. This suggests that 3.2 calories would be burned if you performed 10 pushups. Instead, if you performed 25 pushups, you would burn about 8 calories.

Energy (in Joules) = force x distance x mass x gravity

1 calorie = 4.184 joules

140 Calories = 140 x 4.184 joules = 586.96 joules

Force = mass x gravity x fraction of body weight lifted

\(Force = 40 kg x 9.81 m/s^2 = 392.4 N\)

Distance = 0.50 m

When the values are added to the formula, we obtain:

\(Energy = 392.4 N x 0.50 m x 80 kg x 9.81 m/s^2\)

Energy = 153,532.16 joules

Number of pushups = 153,532.16 joules / 586.96 joules per pushup

Number of pushups = 261.9

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Related Questions

what must the charge (sign and magnitude) of a 2.45 g particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 590 n/c?

Answers

For the particle to be stationary, net force vertically must be zero. That means, the weight acting downwards must be equal in magnitude to the electric force acting upwards on the particle. Since electric field is directed downwards and electric force is acting upwards, particle is negatively charged.

Since Fnet = 0,
Weight = Electric Force
mg = qE
(0.00245)(9.81) = q(590)
q = 4.07 x 10^-5

Hence charge is -4.07 x 10^-5

The angular size of Venus has a maximum value of 55" during "inferior conjunction," when it is 0.3AU from Earth (Venus is 0.7AU from Sun). It’s orbital eccentricity is 0.007

Calculate the Diameter (physical size) of Venus.

Answers

The diameter of Venus can be calculated using the angular size at inferior conjunction and its orbital parameters. With an angular size of 55" and a distance of 0.3 AU from Earth, the physical size of Venus can be determined.

The angular size of an object is the angle it subtends at the observer's location. In this case, the maximum angular size of Venus is given as 55" (arcseconds) during inferior conjunction. Inferior conjunction occurs when Venus is positioned between Earth and the Sun, and its distance from Earth is 0.3 AU (astronomical units). Venus is also stated to be 0.7 AU from the Sun.

To calculate the physical size of Venus, we can use the small-angle formula, which relates the angular size, distance, and physical size of an object. The formula is given by:

Angular size (in radians) = Physical size / Distance

Since the angular size is usually measured in arcseconds, it needs to be converted to radians. One radian is equal to 206,265 arcseconds.

Converting the given angular size of 55" to radians:

Angular size (in radians) = 55" / 206,265 ≈ 0.000266 radians

Using the small-angle formula, we can rearrange it to solve for the physical size:

Physical size = Distance × Angular size

Substituting the values, where the distance is 0.3 AU:

Physical size = 0.3 AU × 0.000266 radians ≈ 0.00008 AU

Finally, to convert the physical size from astronomical units to kilometers, we can use the conversion factor of 1 AU = 149.6 million kilometers:

Physical size = 0.00008 AU × 149.6 million kilometers/AU ≈ 12,000 kilometers

Therefore, the diameter (physical size) of Venus is estimated to be approximately 12,000 kilometers.

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terms used to measure motion

Answers

Answer:

velocity term

Explanation:

Answer:velocity term

Explanation:

Which of the following objects can be described as simple harmonic motion? Pick Two
A)A dog chasing his tail
B)A butterfly flapping its wings
C)A car driving on a highway
D)A cat eating asparagus​

Answers

Simple harmonic motion is when an object goes back and forth along the same pathway.

The only ones present that have a same pathway of motion would be answers A and B.

A highway can have variable different pathways and a cat can have different ways of eating an asparagus. That is my logic and reasoning. Hope this helps!

what is the electric flux through one side of a cube that has a single point charge of placed at its center?

Answers

\(56497.1Nm^2\) is the electric flux through one side of a cube that has a single point charge of placed at its center.

Electric flux is a measure of the electric field lines that are crossing the surface in electromagnetism. Although an electric field cannot flow on its own, it can be used to describe the strength of the field at any distance from the charge that generated it.

We may determine the electric flux across the cube's surfaces using Gauss's Law, then divide the result by 6.

We may eliminate the intermediary for Gauss's Law by using symmetry.

E * A = Qencl / ∈

where  \(= 8.85*10^{-12}\)

The charge is \(-3.00*10^{-6} C\)

Divide \(-3.00*10^{-6} C/ 8.85*10^{-12}\) F/m

We obtain a flux of \(338983.0508 Nm^2\) as a result.

We may calculate the flux through one side by dividing by 6:

\(338983/6 = 56497.1Nm^2\)

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Correct question:

What is the electric flux through one side of a cube that has a single point charge of -3.00 µc placed at its center?

A car accelerates uniformly from rest to a speed of 6. 6 m/s in 6. 5 seconds. Find the distance the car travels during this time.

Answers

The distance covered by the vehicle is 21.45 meters.

How far is another word for total distance traveled.

Applying the motion equation, s = (v+u)t/2. Equation 1

Where, s is the distance the car traveled, v is its ultimate speed, u is its starting speed, and t is the passing of time.

Given by the query: v = 6.6 m/s, u = 0 m/s (from rest), and t = 6.5 s

Replace these values in equation 1\ss = (6.6+0) 6.5/2\ss = 21.45 m

As a result, the distance covered by the car is 21.45 meters.

What is the straightforward definition of distance?

Distance is the overall movement of an object without consideration of direction. Independent of an object's originating or finishing place, proximity can be described as the amount of terrain it has covered.

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calculate the amount of work done to move 1 kg mass from the surface of the earth to a point 10⁵ km from the centre of the earth

Answers

The  quantum of work done to move a 1 kg mass from the  face of the earth to a point 10 ⁵ km from the centre of the earth is4.92 x 10 ⁸J.    

The  quantum of work done to move 1 kg mass from the  face of the earth to a point 10 ⁵ km from the centre of the earth can be calculated using the gravitational implicit energy formula.

The gravitational implicit energy is the  quantum of work done by an external force in bringing an object from  perpetuity to a point in space where it can be  told  by  graveness. When an object is moved from the  face of the earth to a point 10 ⁵ km from the centre of the earth, the gravitational implicit energy of the object increases.  

The formula for gravitational implicit energy is given by  U = - GMm/ r  where U is the gravitational implicit energy  G is the universal gravitational constant  M is the mass of the earth  m is the mass of the object  r is the distance between the object and the centre of the earth.  

We know that the mass of the object is 1 kg,  the mass of the earth is    and the distance from the centre of the earth to a point 10 ⁵ km down is           Plugging these values into the formula, we get         thus, the  quantum of work done to move a 1 kg mass from the  face of the earth to a point 10 ⁵ km from the centre of the earth is 4.92 x 10 ⁸J.

the mass of the earth is \(5.97 * 10^2^4 kg\),

and the distance from the centre of the earth to a point 10⁵ km away is:

\(= 6.38 * 10^6 + 10^5 km\)

\(= 6.48 * 10^6 km\)

\(= 6.48 * 10^9 m\).

Plugging these values into the formula, we get

\(U = -6.67 * 10^-^1^1 * 5.97 * 10^2^4 * 1 / 6.48 * 10^9\)

   \(= -4.92 * 10^8 J\)

Therefore, the amount of work done to move a 1 kg mass from the surface of the earth to a point 10⁵ km from the centre of the earth is 4.92 x 10⁸ J.

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if an object doubles its luminosity in 10 hours, how large can the emitting source of light be?

Answers

If an object doubles its luminosity in 10 hours, emitting source of light can be about 10 light hours across.

Luminosity, L, is a measure of the total amount of energy radiated by a star or other celestial object per second. This is therefore the power output of a star. A star's power output across all wavelengths is called its bolometric luminosity. A star's luminosity can be determined from two stellar characteristics: size and effective temperature. The difference between luminosity and apparent brightness depends on distance.

Since, the luminosity of the object doubles in 10 hours, emitting source of light can be about 10 light hours across.

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Circular motion requires the application of a constant force in which direction?
Outward from the circle
Toward the center of the circle
Toward the object in motion
Away from an object

Answers

Toward the center of the circle

The final motion characteristic for an object undergoing uniform circular motion is the net force. The net force acting upon such an object is directed towards the center of the circle. The net force is said to be an inward or centripetal force.

1: Solve for acceleration. Write the units of your answer next to the number
What is the acceleration of a drag racing car that accelerates from 0 to 32 m/s in 4.5
seconds?
2) A sky diver jumps out of a plane. If the diver falls from rest (0 m/s) and reaches a speed
of 18 m/s in 1.92 seconds, what is the diver's acceleration ?

Answers

1. 7.1111m/s Recurring
Solution a = v/t basically divide the velocity by the time taken
2. 9.375m/s
Same solution as before

Two automobiles of equal mass approach an intersection. One vehicle is traveling with speed v2i toward the east, and the other is traveling north with speed . Neither driver sees the other. The vehicles collide in the intersection and stick together, leaving parallel skid marks at an angle of 55,0 degress north of east. The speed limit for both roads is 35mi/h , and the driver of the northward-moving vehicle claims he was within the speed limit when the collision occurred. Is he telling the truth? Explain your reasoning.

Answers

No, the driver of the northward-moving vehicle was not within the speed limit when the collision occurred.

To determine whether the driver of the northward-moving vehicle was within the speed limit, we need to analyze the collision and the resulting skid marks.

Given that the skid marks left by the collided vehicles are parallel and at an angle of 55.0 degrees north of east, it indicates that the vehicles were not moving directly along the east or north direction. Instead, they were moving at an angle.

If the northward-moving vehicle was within the speed limit of 35 mi/h, its speed would not have been sufficient to result in skid marks at an angle of 55.0 degrees. The collision and the resulting skid marks indicate a significant impact and angular momentum, which would require a higher speed than the speed limit allowed.

Therefore, based on the skid marks and the collision angle, the driver of the northward-moving vehicle was likely exceeding the speed limit when the collision occurred, and his claim of being within the speed limit is not valid.

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A light-year is a unit of a. time. c. mass. b. distance. d. density. please select the best answer from the choices provided a b c d

Answers

Answer:

distance

Explanation:

it is the distance traveled by light in one year

B. Distance

A light-year has a bit of a deceiving name. Despite the fact that it seems to imply it is a measure of time, this is not of fact correct. A light-year refers to how far light can travel within a year. One light year is approximately 6 trillion miles. Light years are used to measure extremely far distances such as how far the sun is from other stars, or how far away other exoplanets (planets outside our solar system) are.

breadth of the widest part of a wedge is 8cm and its length 20 cm by the application of the effort pf 400N on the widest part it resist the force of 800 N inside a wooden block . Calculate its velocity ratio

Answers

The application of the effort pf 400N on the widest part it resist the force of 800 N inside a wooden block the velocity ratio of the wedge is 4.

We know the effort and resistance forces, so we can solve for the distance moved by each force:

Distance moved by effort = (Resistance x distance moved by resistance) ÷ Effort

Distance moved by effort = (800 N x 8 cm) ÷ 400 N

Distance moved by effort = 16 cm

Distance moved by resistance = length of wedge - distance moved by effort

Distance moved by resistance = 20 cm - 16 cm

Distance moved by resistance = 4 cm

Now we can plug these distances into the formula for the velocity ratio:

Velocity ratio = distance moved by effort ÷ distance moved by resistance

Velocity ratio = 16 cm ÷ 4 cm

Velocity ratio = 4

Velocity ratio is a term used in mechanics and is defined as the ratio of the distance traveled by the effort to the distance traveled by the load in a machine. It is a fundamental concept that is used to determine the mechanical advantage of a simple machine. The velocity ratio is essential in understanding how a machine works and how it can be used to make work easier.

The velocity ratio is an important factor in the efficiency of a machine. A higher velocity ratio means that the load can be moved with less effort, resulting in a higher mechanical advantage. Therefore, machines with a high velocity ratio are considered to be more efficient and can be used to perform work more easily. Understanding the concept of velocity ratio is important in designing and operating machines, especially in situations where work needs to be done with minimal effort.

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A policeman kicks in a door with a force of 4500 N. What force does the door apply to the policeman’s leg?

Answers

Answer:

-4500 N

Source: Brainly

The police officer must be angry 0_0

what percentage of the earth's mass is the moon's mass?earth's mass - 5.98 x 10²⁴ kgmoon's mass - 7.35 x 10²² kg

Answers

Given data:

* The mass of Earth is,

\(M=5.98\times10^{24}\text{ kg}\)

* The mass of Moon is,

\(m=7.35\times10^{22}\text{ kg}\)

Solution:

The percentage of the Moon mass in comparison to the Earth's mass is,

\(P=\frac{m}{M}\times100\text{ \%}\)

Substituting the known values,

\(\begin{gathered} P=\frac{7.35\times10^{22}}{5.98\times10^{24}}\times100\text{ \%} \\ P=1.23\times10^{22-24}\times100\text{ \%} \\ P=1.23\times10^{-2}\times100\text{ \%} \\ P=1.23\times\frac{100}{100}\text{ \%} \\ P=1.23\text{ \%} \end{gathered}\)

Thus, the Moon's mass is 1.23 percent of mass of Earth.

achievement and challenges of science and technology explain?​

Answers

Science and technology have had a significant influence on society, with both successes and difficulties.

The achievements can be noted as -

Medical Growth - Scientists and medical professionals have been able to create vaccinations, medicines, and surgical techniques thanks to advancements in technology that save millions of lives annually. This covers developments like cancer therapy, organ transplantation, and enhanced medical imaging. Communication Growth - People may now contact and communicate with one another more easily because to developments in communication technology. People may now communicate globally thanks to advancements in communication technologies, like the telephone and the internet.Commutation - Transport has also been enhanced by science and technology, becoming quicker and more effective. This includes technological advancements like electric autos, high-speed trains, and aeroplanes.

The challenges can be noted as -

Environmental Degradation - Environmental degradation, including pollution, deforestation, and climate change, has been brought on by the development and usage of technology.Expensive - It may be expensive to develop and adopt new technology, which might put people and communities at a financial disadvantage. This may restrict access to these breakthroughs and worsen already existing inequities.Dependency - Genetic engineering, artificial intelligence, and privacy are just a few of ethical issues that have been brought up by these advancements. It is crucial to consider possible effects of these breakthroughs and make sure they are applied for the benefit of everybody.

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The ________ represents the complete range of frequencies of light energy from radio waves to cosmic rays

Answers

Electromagnetic spectrum represents the complete range of frequencies of light energy from radio waves to cosmic rays.

What is electromagnetic spectrum?

Electromagnetic spectrum is nothing but the complete range of electromagnetic radiation, classified by frequency or wavelength.

What are Electromagnetic waves?

When an electric field interacts with a magnetic field, electromagnetic waves are created. Therefore, they are referred to as "electromagnetic" waves.

The following are Electromagnetic waves in order:

these are ranging from  highest to lowest energy

gamma rays X-rays ultraviolet radiation visible light infrared radiation microwaves radio waves.Properties of Electromagnetic wave:are transverse waves that can pass through a vacuum move at the same speed—300,000,000 m/s for light—when moving through one.electromagnetic waves, like all waves:energy transfer from one location to another it can also be reflected it can be refracted.In the electromagnetic spectrum, each are different from:frequencywavelength

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Error and uncertainty are interchangeable words that describe the same concept.

Answers

Error is the difference between actual value and the calculated value.

Uncertanity of a measured value in an interval around that value such that any repetition of measurement will produce a new result that lies within the interval.

Hence, error and uncertanity are interchangeable words that describes the same concept.

Why are cells described as the "building blocks" of all living things?
-)
A)
A cell is the smallest part of the air living things need to breathe.
B)
They are found in everything tiving things teed, including water and food
o
A cell is the smallest part of a living thing that can function on its own.
D
Cells are always stacked in rows, like bricks, to build the parts of living
things.

Answers

B
They are found in everything, including water and food


This is because cells are all around you this can range from the chair that you are sat on, to the milk in the fridge and even to the alien on the moon :/

Answer:

Explanation:

ya B is right

Car manufacturers use radiation for which task? sealing windows drying paint cleaning tires lubricating engines

Answers

Answer: drying paint

Explanation:

From the options that are given in the question, we should note that car manufacturers use radiation for drying paint.

The radiation is vital as it keeps the car cool and also helps in the reduction if heat in the vehicle. The other options such as sealing windows, cleaning tires and lubricating engines aren't true as radiation isn't used for that purpose by the car manufacturers.

Answer:

drying paint

Explanation:

A car traveling 77 km/h slows down at a constant 0.48 m/s2 just by "letting up on the gas." A) Calculate the distance the car coasts before it stops. B)Calculate the time it takes to stop. C)Calculate the distance it travels during the first second. D)Calculate the distance it travels during the fifth second.

Answers

Answer:

(a) 477 m

(b) 44.6 s

(c) 21.16 m

(d) 19.24 m

Explanation:

initial speed, u = 77km/h = 21.4 m/s

acceleration, a = - 0.48 m/s2

final speed v =  0  

(a) let the stopping distance is s.

Use third equation of motion

\(v^2 = u^2 + 2 a s\\\\0 = 21.4^2 - 2 \times 0.48\times s\\\\s = 477 m\)

(b) Let t is time.

Use first equation of motion

v = u + at

0 = 21.4 - 0.48 t

t = 44.6 s

(c) Let the distance is s in first second.

Use second equation of motion

\(s = u t + 0.5 at^2\\\\s = 21.4\times 1 - 0.5\times 0.48\times 1\\\\s = 21.4 - 0.24 = 21.16 m\)

(d) distance traveled in 5 th second is given by

\(s = u + 0.5 a (2 n - 1) \\\\s = 21.4 - 0.5\times 0.48 \times (2\times 5 -1)\\\\s= 21.4 - 2.16 = 19.24 m\)

Based on your daily experience, how do we quantify motion? For example, how do we quantify how fast an object moves?

Answers

The time it takes one to move from one place to another daily, can be used to quantify motion. Speed is used to quantify how fast an object moves.

What is motion?

This is the displacement with time of the position or orientation of a body. The displacement can be along a straight line or a curve.

Hence from the definition of motion, we can see that motion is dependent on time. We quantify motion by measuring the distance and dividing it by the time taken to move.

Speed measures how fast an object is moving through a distance, and it is calculated using this formula:

S= Δd/ Δt,

where S stands for speed,

d stands for distance, and

t stands for time.

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A ball is released from a height of 20m calculate
The time it takes to fall
The velocity with which it hits the ground​

Answers

Answer: Uh here

Explanation:

s=h=20

a=g=±10m/s=10m/s (since it is dropped)

v^2-u^2= 2as

v^2=2x10x20 (u=0; it is dropped not thrown)

v=20m/s

for calculating time

we know,

v=u+at

20= 0+ 10xt

t=2seconds

thus, it will attain a speed of 20m/s before touching the ground, but the time taken to reach the ground is 2seconds. Because the velocity is not uniform but acceleration/gravity is. If still there is any confusion. Try the same problem with 80 of height.

A truck with a mass of 15,000 kg moving at 25 m/s crashes into the back of a small 1,100 kg car moving at 15 m/s. They
stick together after the collision. Calculate the momentum of the system before the collision and after the collision.

Answers

Explanation:

Given that,

Mass of a truck = 15,000 kg

Speed of the truck = 25 m/s

Mass of car = 1,100 kg

Speed of the car = 15 m/s

As they stick together after the collision. Let V be the speed after the collision.

Initial momentum of the system,

\(P_i=15000\times25+1100\times15\\\\=391500\ kg-m/s\)

Final momentum of the system,

\(P_f=(15000+1100)V\\\\=16100V\)

Hence, this is the required solution.

Convert 250mm to kilometers using conversion factor

Answers

Answer:

0.00025 kilometers

Explanation:

divide the length value by 1e+6

Answer:

250 mm = 0.00025 km.

Explanation:

250 mm equal 0.00025 km

Conversion details

To convert mm to km use the following formula:

1 mm equals 0.000001 km

So, to convert 250 mm to km, multiply 0.000001 by 250 i.e.,

250 mm = 0.000001 * 250 km = 0.00025 km

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What is the term used to describe the energy of a system that is available to do work?.

Answers

The term used to describe the energy of a system that is available to do work is free energy.

What is free energy?

Free energy is the energy that is available in a particular chemical system to do useful work.

The Gibbs free energy denoted by G is the enthalpy of a system minus the product of its entropy and absolute temperature.

It is referred to as free because the energy is readily available anytime. Free energy is measured in kilojoules per mole (KJ/mol).

Therefore, it can be said that the term used to describe the energy of a system that is available to do work is free energy.

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Between the orbits of Mars and Jupiter, several thousand small objects called asteroids move in nearly circular orbits around the Sun. Consider an asteroid that is spherically shaped with radius r and density 2000 kg/m^3.


1. You find yourself on the surface of this asteroid and throw a baseball at a speed of 24 m/s. If the baseball is to travel around the asteroid in a circular orbit, what is the largest radius asteroid on which you are capable of accomplishing this feat?

Answers

Answer:

The radius is  \(r = 3.21*10^{4} \ m\)

Explanation:

From the question we are told that  

   The density is  \(\rho = 2000 \ kg/m^3\)

    The speed is  \(v = 24 \ m/s\)

Generally the largest radius of the asteroid is mathematically represented as

      \(r = \frac{v^2}{ \sqrt{G * \rho * [\frac{4}{3} ] * \pi} }\)

=>   \(r = \frac{24^2}{ \sqrt{ 6.67*10^{-11} * 2000 * [\frac{4}{3} ] *3.142 } }\)

=>   \(r = 3.21*10^{4} \ m\)

What is the displacement when t =2s to 3s

Answers

Answer:

t=5s

Explanation:

t=2 + t= 3s = t= 5s

Luke stands on the edge of a roof throws a ball downward. It strikes the ground with 100J of kinetic energy. Luke now throws another identical ball upward with the same initial speed, and this too falls to the ground. Neglecting air resistance, the second ball hits the ground with kinetic energy of____J

A) Less than 100
B) 100
C) 200
D) More than 200

Answers

A. Less than 100 this the answer

What are the three forms of water discussed in the passage?

Answers

Answer:

The three forms of water are gas, liquid, and ice, I'm not sure if these were mentioned in the passage since you did not attach a picture.

Please mark this the Brainliest.

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