The total distance traveled will be 18 miles because distance and displacement are different.
While distance and displacement appear to have the same meaning, they actually have very different definitions and implications. Displacement is the measurement of "how far an object is out of place," whereas distance refers to "how much ground an object has covered during its motion."
Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
Δd = d1 + d2 + d3.....
The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place.
Displacement = Final position - Initial position
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Use the drop-down menus to answer the questions. How do objects with the same charge interact? how do objects with opposite charges interact? how do uncharged objects interact?.
Answer:
1. They repel each other
2. They attract each other
3.They have no affect on each other
Explanation:
got em right
The interaction between the objects with same charge is repulsion.
The interaction between the objects with opposite charge is attraction.
There is no interaction between the uncharged objects.
What is meant by electrostatic force ?Electrostatic force is defined as the force of attraction or repulsion that happens between two charged particles.
Here,
The interaction between the two charged particles is due to the electrostatic force of attraction or repulsion.
Case-1
Interaction between objects with the same charge.
When two objects with same charge are placed at a distance from each other, the force existing between them is the electrostatic force of repulsion. This is because they are two like charges and we know like charges never attracts each other. So, the interaction between them is repulsion.
Case-2
Interaction between objects with opposite charges.
When two objects with opposite charges are placed at a distance from each other, the force existing between them is the electrostatic force of attraction. This is because, they are two unlike charges and we know unlike charges will always attract each other. So, the interaction between them is attraction.
Case-2
Interaction between uncharged objects
When two uncharged objects are placed at a distance from each other, there will be o force of attraction or repulsion between them. This is because the electrostatic force acts between two particles that have charge. So, there is no interaction between the uncharged objects.
Hence,
The interaction between the objects with same charge is repulsion.
The interaction between the objects with opposite charge is attraction.
There is no interaction between the uncharged objects.
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A source emits sound at a fixed constant frequency f
If the source moves away from you faster than the speed of sound in air, the frequency that you hear is
a.unrelated to f.
b.lower than f.
c.the same as f.
d.higher than f.
If the source moves away from you faster than the speed of sound in air, the frequency that you hear is lower than f.
Explanation:
This phenomenon is known as the Doppler effect.
The Doppler effect describes the change in frequency of a wave (such as sound or light) when there is relative motion between the source of the wave and the observer.
When the source moves away from the observer, the effective wavelength of the sound waves gets longer, resulting in a lower frequency being perceived by the observer.
This decrease in frequency causes the sound to be heard at a lower pitch.
Therefore, the correct answer is b. lower than f.
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1. A 1400 kg car is moving at 15 m/s when it hits a tree and comes to rest 0.30 seconds later. How
much force does the car experience?
Answer:
F = 70000 N
Explanation:
Given that,
Mass of a car, m = 1400 kg
Initial speed of the car, u = 15 m/s
Finally, it hits the ground, v = 0
Time, t= 0.3 s
We need to find the force experienced by the car. Using Newton's second law of motion to find it.
F = ma
a is acceleration of the car.
\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1400\times (0-15)}{0.3}\\\\=-70000\ N\)
So, the force experienced by the car has a magnitude of 70000 N.
If a current is 2.0 A, how many turns per centimeter must be wound on a solenoid in order to produce a magnetic field of within it
Therefore, approximately 19,739 turns per centimeter must be wound on the solenoid to produce a magnetic field of 0.5 Tesla within it.
To determine the number of turns per centimeter needed to produce a magnetic field within a solenoid, we can use the formula:
B = μ₀ * n * I
Where B is the magnetic field, μ₀ is the permeability of free space (4π x 10⁻⁷ T*m/A), n is the number of turns per meter, and I is the current in amperes.
To find the number of turns per centimeter, we need to convert the length units. There are 100 centimeters in a meter, so we divide the number of turns per meter by 100.
Let's assume we want a magnetic field of 0.5 Tesla (T) within the solenoid and the current is 2.0 A.
Using the formula, we have:
0.5 T = (4π x 10⁻⁷ T*m/A) * (n/100 turns/cm) * 2.0 A
Simplifying the equation, we can solve for n:
0.5 T = (8π x 10⁻⁷ T*m/A) * (n/100 turns/cm)
n = (0.5 T * 100 turns/cm) / (8π x 10⁻⁷ T*m/A)
Calculating this, we find:
n ≈ 19,739 turns/cm
In conclusion, to achieve a specific magnetic field within a solenoid, the number of turns per centimeter can be determined using the formula B = μ₀ * n * I.
By substituting the given values and solving the equation, we find that around 19,739 turns per centimeter are needed for a magnetic field of 0.5 Tesla with a current of 2.0 A.
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if the bat and softball are in contact for 0.80m/s, what is the average force that the bat exerts on the ball
The changes in the momentum of the ball and the time over which that change occurs. The formula for average force is: average force = change in momentum/time.
Calculation-Given: The ball's mass is 0.144 kilogram.
speed v = 38 m/s, shift in momentum presently
P = m v- ( - mv) ( - mv)= 2 mv
=2 x (0.144) x (38) (38)
= 10.944 kg-m/s
t Impulse J=F.
The impulse is equivalent to the change in momentum.
J = 10.944 kg-m/s
What forces are at play when a baseball bat strikes a fastball?Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two different objects combined.
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Pitch a baseball horizontally at 38.0 m/s weighing 0.144 kg. The baseball moves in the opposite direction and at the same speed after being struck by the bat. What is the ball's change in momentum? What kind of impetus does the bat deliver? What was the average force the bat applied to the ball during the 0.80 milliseconds that they were in contact?
I NEED HELP ASAP!! PLEASE
A skydiver falling towards Earth and is traveling at 19 m/s opens her parachute. She slows to a speed of 3 m/s The whole process takes only 2 seconds . What is her acceleration ? Explain why this acceleration is positive or negative
Answer:
Acceleration = -3m/s²
Explanation:
Given the following data;
Initial velocity = 19m/s
Final velocity = 3m/s
Time = 2secs
To find the acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time. Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
Substituting into the equation, we have;
\(a = \frac{3 - 9}{2}\)
\(a = \frac{-6}{2}\)
Acceleration = -3m/s²
The value for her acceleration is negative because she is decelerating i.e her final velocity is lower than her initial velocity.
Time is a measure of:
Answer:
the time is measured with instrument such time,I hope this help
The tank is 51m long and 20m wide.The sea water in the tank is 11m deep and has a density of 1030 kilograms per cubic meters.
Calculate the mass of water in the tank.
Answer: 1.2 x 10^7kg
Explanation:
Volume of tank = length x width x height
Volume = 51 x 20 x 11
Volume = 11220 m^3
Density = Mass/Volume
Density = 1030 kg/m^3
Volume = 11220 m^3
Mass = m
1030 = m/11220
m = 1030 x 11220
m = 11,556,600 kg or 1.2 x 10^7kg
A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test charge from a point midway between them to a point 12 cm closer to either of the charges?
Answer:
512.5 mJ
Explanation:
Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.
The electric potential at this point due to the two charges q is thus
V = kq/r₂ + kq/r₂
= 2kq/r₂
= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m
= 630/0.23 × 10³ V
= 2739.13 × 10³ V
= 2.739 MV
When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.
So, the new electric potential at this point is
V' = kq/r₃ + kq/r₄
= kq(1/r₃ + 1/r₄)
= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)
= 315 × 10³(2.857 + 9.091) V
= 315 × 10³ (11.948) V
= 3763.62 × 10³ V
= 3.764 MV
Now, the work done in moving the charge q' to the point 12 cm from either charge is
W = q'(V' - V)
= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)
= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V
= 0.5125 J
= 512.5 mJ
Work done will be: \(512.5 \mu J\).
Given:
q = +35 µC
q' = +0.50 µC
r₁ = 46 cm
r₂ = 46 cm/2 = 23 cm = 0.23 m
The electric potential at this point due to the two charges q is thus
\(V = \frac{kq}{r_2}+\frac{kq}{r_2}\\\\ V= \frac{2kq}{r_2}\\\\V= \frac{2 * 9 * 10^9Nm^2/C^2 * 35 * 10^{-6} C}{0.23 m}\\\\V= \frac{630}{0.23*10^3}V\\\\V= 2739.13 * 10^3 V\\\\V= 2.739 \mu V\)
When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now;
r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and
r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.
Thus, the new electric potential at this point is
\(V' = \frac{kq}{r_3} + \frac{kq}{r_4}\\\\V= kq(\frac{1}{r_3}+\frac{1}{r_4})\\\\V= 9 * 10^9 Nm^2/C^2 * 35 * 10^{-6} C (\frac{1}{0.35m}+\frac{1}{0.11m})\\\\V= 315 * 10^3(2.857 + 9.091) V\\\\V= 315 * 10^3 (11.948) V\\\\V= 3763.62 * 10^3 V\\\\V= 3.764 \mu V\)
Now, the work done in moving the charge q' to the point 12 cm from either charge is:
\(W = q'(V' - V)\\\\W= 0.5 * 10^{-6} C(3.764 MV - 2.739 MV)\\\\W= 0.5 *10^{-6} C(1.025 * 10^6) V\\\\W= 0.5125 J\\\\W= 512.5 \mu J\)
Thus, the work done will be: \(512.5 \mu J\).
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The environmental impact of the changes in the amount of energy resources is reduction in air pollution.
What are energy resources?Energy resources are the materials that can act as sources of energy which is grouped into two namely:
Renewable energy resources: These are energy resources that can easily be replaced by nature. A typical example is the solar energy.Non renewable energy resources: These are energy resources that cannot easily be replaced by nature. Examples include coal, nuclear and gas.From the given figures,
In 2014 renewable energy = 19%; while in 2015 it is = 25%
In 2014 non renewable energy when added = 79%; while in 2015 it is = 73%
This shows that there was reduction in the use of non renewable energy from 2014 to 2015 by 6%.
This would affect the environment positively as there would be reduction in air pollution caused by non renewable energy resources.
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Using the letters for the seven colours and starting with R (Red), what is the correct order for the colours in a rainbow? Your answer should be in the form RXXXXXX Which of these seven colours has the shortest wavelength?
Answer:
Red
Orange
Yellow
Green
Blue
Indigo
Violet
shortest wavelength: violet (380 nanometers)
¯\(°_o)/¯
Answer:
Red Orange Yellow Green Blue Indigo Violet
violet has the shortest wavelength
happy to help :)
What is the maintenance of a consistent internal environment?
OA) mitosis
OB) meiosis
OC) homeostasis
OD) photosynthesis
CAN YOU GUYS PLEASE HELP ME OUT MY DUE TO MY BOOKLET IS TOMORROW
Newton's Third Law of Motion is a fundamental principle of physics which states that for every action, there is an equal and opposite reaction. This means that whenever one object exerts a force on another object, the second object will exert an equal and opposite force on the first object.
What is Newton's Third Law about?This principle applies to all types of forces, including gravitational, electromagnetic, and mechanical forces. In the case of the apple falling from a tree, the Earth exerts a gravitational force on the apple, pulling it towards the ground with a force of 1.5N. At the same time, the apple exerts an equal and opposite gravitational force on the Earth, pulling the Earth towards the apple with a force of 1.5N. This pair of forces is an example of a Newtonian pair.
The significance of Newton's Third Law is that it helps us to understand the nature of interactions between objects.
Therefore, Newton's Third Law is a fundamental principle of physics that states that for every action, there is an equal and opposite reaction. This principle helps us to understand the nature of interactions between objects, and is a key component of our understanding of the physical world.
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See transcribed text below
Newton's Third Law
Newton's Third Law states that:
"For every action there is an equal and opposite reaction"
What this means is that because forces are interactions between pairs of objects. forces always come in pairs. We call these "Newtonian pairs".
Consider an apple falling from a tree:
gravitational force of the Earth on the apple: 1.5N
1 1
gravitational force of the apple on the Earth: 1.5N
The Earth pulls on the apple with a force of 1.5N. What's surprising is that the apple is also pulling on the Earth with a force of 1.5N. The apple is the thing we see accelerating, because its mass is small enough for 1.5N to create a significant acceleration. Newton's second law, F = ma is responsible for this.
the box weighing 18 newtons is coated with teflon® and now requires a force of 3 newtons to drag it.the coefficient of friction is .
To determine the coefficient of friction for the box weighing 18 Newtons and requiring a force of 3 Newtons to drag it after being coated with Teflon®, you can use the formula:
Coefficient of friction (μ) = Force of friction (F_ friction) / Normal force (F_ normal)
In this case, the Force of friction (F_ friction) is the force required to drag the box, which is 3 Newtons. The Normal force (F_ normal) is equal to the weight of the box, which is 18 Newtons.
Plug these values into the formula:
μ = 3 N / 18 N
μ = 0.1667
The coefficient of friction for the box coated with Teflon® is approximately 0.1667.
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In the given diagram(in the resources) which kind of lever is mentioned? Also calculate the amount of load that can be lifted with an effort of 50N.
Answer:
Solution : Given,
Load (L) = ?
L×LD=E×ED
L=100 cm=50N×40 cm
L=40×50÷100
L=20N
Explanation:
How many Watts of power does a model rocket engine have if it does 66 J of work on a model rocket in 0.9 seconds?
Power developed by a model rocket engine will be 73.3 watts. Power is the ratio of the work done or the enrgy to the time period.
What is the power output?The rate of the work done is called the power output. It is denoted by P.Its unit of a watt.
The given data in the problem is;
E is the energy = 66 J
P is the power output =?
t is the time period = 0.9 sec
The power output is given as;
\(\rm P = \frac{E}{t} \\\\ \rm P = \frac{66}{0.9} \\\\ \rm P = 73.3 \ watt\)
Hence power developed by a model rocket engine will be 73.3 watts.
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The specific heat capacity c of a solid block of mass m is determined by heating the block and measuring its temperature.
The graph above shows the variation of the temperature T of the block with the thermal energy Q transferred to the block. The gradient of the line is equal to ?
The gradient of the line is equal to c/m
The gradient of the line on the graph represents the change in temperature T per unit change in thermal energy Q. Mathematically, we can express this as:
gradient = ΔT / ΔQ
We know that the specific heat capacity c of the block is defined as the amount of thermal energy required to raise the temperature of the block by one unit, divided by the mass of the block. Mathematically, we can express this as:
c = ΔQ / (mΔT)
Rearranging this equation, we get:
ΔQ / ΔT = c/m
Comparing this equation with the equation for the gradient, we can see that the gradient is equal to c/m. Therefore, the answer is (A) c/m.
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Two runners start at the same point and jog at a constant speed along a straight path. Runner A starts at time t = 0 s, and Runner B starts at time t = 2.5 s. The runners both reach a distance 64 m from the starting point at time t = 25 s. If the runners continue at the same speeds, how far from the starting point will each be at time t = 45 s?
Answer:
See explanation below
Explanation:
First thing to do here, is to calculate the speed of each runner. The problem states that both runners jog at a constant speed. We are given data for both runners, the starting time and the time where both of them reach the same distance.
With these data we can calculate the speed of both runners. Let's do it with runner 1:
If by t = 25 s it reach a 64 m of distance, then his speed:
V = d/t (1)
Replacing we have:
V₁ = 64 / 25 = 2.56 m/s
With this speed we can calculate the distance at t = 45 s so:
d = V * t (2)
d₁ = 2.56 * 45
d₁ = 115.2 mSo Runner 1 will be at 115.2 from the starting point at 45 seconds.
For runner 2, he began at t = 2.5 s, but he reach the 64 m at 25 s, so his speed would be:
V₂ = 64 / (25-2.5) = 2.84 m/s
And the distance at t = 45 s
d₂ = 2.84 * 45
d₂ = 127.8 mRunner 2 is 127.8 m from the starting point at 45 seconds.
Hope this helps
Which would take longer to cool off by 50 degrees, 1 kg of Copper or 1 kg of liquid water?
Answer:
i believe it would be water
Explanation:
A train travel south at the
speed of 120 km/h in 1. 6 hours
Calculate it's displacement
Velocity: 120 miles/hr
Now Distance= Speed × Time
Now Velocity and speed have the same magnitude. Velocity being a vector quantity has a definite direction. Whereas speed is a scalar quantity,it indicates only the magnitude an doesn't define any direction.
Hence Distance = Velocity x time
Distance = 3.5 × 120 = 420 miles
\(\\ \sf\longmapsto Displacement=Speed(Velocity)\times Time\)
\(\\ \sf\longmapsto Displacement=120(1.6)\)
\(\\ \sf\longmapsto Displacement=192km\)
10) A 57-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37° above the horizontal. If the tension in the rope is 142 N, how much work is done on the crate to move it 6.1 m?
F=m*a
T = 142N
Work = Force x distance
distance = 6.1 M
Force = 142 x cos 37 = 113.4 N
W= 113.4N x 6.1M = 691.78 J
A wave has a period of 4 seconds. Find it’s frequency.
Answer:
4 x the frequncy
Explanation:
So 4 x the number
A force applied to a 0.25 Kg hockey puck gives the puck an acceleration of 16 m/s2. What acceleration would the same force give to a 0.50 Kg baseball?
Answer:
8 m/s².
Explanation:
We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:
Mass (m) = 0.25 Kg
Acceleration (a) = 16 m/s²
Force (F) =.?
Force (F) = mass (m) × acceleration (a)
F = ma
F = 0.25 × 16
F = 4 N
Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.
Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:
Mass (m) = 0.50 Kg
Force (F) = 4 N
Acceleration (a) =?
F = ma
4 = 0.5 × a
Divide both side by 0.5
a = 4 / 0.5
a = 8 m/s²
Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².
lonic compounds are compounds that
A figure skater begins spinning counterclockwise at an angular speed of
4.07 rad/s. During a 3.0 s interval, she slowly pulls her arms inward and
finally spins at 8.0€ rad/s. What is her average angular acceleration dur-
ing this time interval?
The average angular acceleration of the figure skater during the 3.0 s interval is 1.31 rad/s².
Describe Angular Acceleration?Angular acceleration is the rate at which the angular velocity of a rotating object changes with respect to time. It is a vector quantity and is defined as the time rate of change of angular velocity, usually denoted by the Greek letter alpha (α).
Angular acceleration occurs when the direction or magnitude of an object's rotational velocity changes. It is caused by a torque, which is the rotational equivalent of force, acting on the object. The greater the torque, the greater the angular acceleration.
The initial angular speed of the figure skater is given as w₁ = 4.07 rad/s and the final angular speed is w₂ = 8.0 rad/s. The time interval during which the acceleration occurs is t = 3.0 s.
The average angular acceleration during this time interval can be calculated using the formula:
average angular acceleration = (change in angular speed) / (time interval)
The change in angular speed is given by:
change in angular speed = w₂ - w₁
Substituting the given values:
change in angular speed = 8.0 rad/s - 4.07 rad/s = 3.93 rad/s
Now, dividing the change in angular speed by the time interval, we get:
average angular acceleration = (3.93 rad/s) / (3.0 s) = 1.31 rad/s²
Therefore, the average angular acceleration of the figure skater during the 3.0 s interval is 1.31 rad/s².
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The initial angular speed of the skater is 4.07 rad/s, and her final angular speed is 8.0 rad/s. She changes her angular speed from 4.07 rad/s to 8.0 rad/s over a time interval of 3.0 s.
To calculate the average angular acceleration during this time interval, we can use the formula:
average angular acceleration = (change in angular speed) / (time interval)
The change in angular speed is:
8.0 rad/s - 4.07 rad/s = 3.93 rad/s
Therefore, the average angular acceleration during the 3.0 s time interval is:
average angular acceleration = (3.93 rad/s) / (3.0 s) = 1.31 rad/s²
Therefore, the skater's average angular acceleration during the 3.0 s interval is 1.31 rad/s².
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Is water wet?
I need an argument.
Answer:
no :)
Explanation:
ezzzzzzzzzzzzzzzzzzzz
Liquid water is not itself wet, but can make other solid materials wet. Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.
Select the correct answer. A van traveling down a slope with a uniform acceleration of 2.15 meters/second2 attains a speed of 20.00 meters/second after 7.00 seconds. What is the initial velocity of the van
Answer:
Initial velocity of the van is 4.95m/s
Explanation:
Acceleration is found using the following formula:
\(a=\frac{v-u}{t}\)
where:
a is acceleration ( in meters per second squared)
v is final velocity ( in meters per second)
u is initial velocity ( in meters per second)
t is time ( in seconds)
We know that:
\(a = 2.15m/s^{2}\)
\(v = 20m/s\)
\(t=7s\)
Therefore, we can find the initial velocity by shifting around some values and making \(u\) the subject within the acceleration formula by multiplying both sides by \(t\):
\(a\) × \(t=v-u\)
Followed by:
\(u = v-at\)
Now we can substitute in the values we have:
\(u = 20-(2.15\) × \(7)\)
\(u = 20 - 15.05\)
\(u=4.95m/s\)
__ modified the concept by adding an internal combustion engine and marketing hybrids that were part electric and part gas powered
Hybrid
Hybrid modified the concept by adding an internal combustion engine and marketing hybrids that were part electric and part gas powered.
The driving wheels of hybrid vehicles receive power from their drivetrains. A hybrid car has numerous sources of propulsion.There are numerous hybrid configurations. A hybrid vehicle might, for instance, get its energy from burning gasoline while alternating between an electric motor and a combustion engine.Although they have primarily been employed for rail locomotives, electrical vehicles have a long history of integrating internal combustion and electrical transmission, like in a diesel-electric power-train. Because the electric drive transmission directly substitutes the mechanical gearbox rather than serving as an additional source of motive power, a diesel-electric powertrain does not meet the definition of a hybrid.Only the electric/ICE hybrid car type was readily accessible on the market as of 2017. One type used parallel operation to power both motors at the same time. Another ran in series, using one source to supply power solely and the other to supply electricity. Either source may act as the main driving force, with the other source serving to strengthen the main.To learn more about hybrid vehicles visit:
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Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?
The speed of the moving train is approximately 33.5 m/s.
The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:
\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)
where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.
We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.
Solving for \(v_s\), we get:
\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)
\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s
\(v_s\) = 33.5 m/s
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What is the type of radioactive decay represented by the equation above? A. Gamma B. Fusion C. Alpha D. Fission 40. Alberta uses clean coal technology. This means that the coal has a lower i content than coal in other parts of Canada, which results in reduced ii The statement above is completed correctly by the information in row olla sdf to ridW Row i A. sulfur greenhouse gas emissions acid deposition sulfur carbon greenhouse gas emissions acid deposition carbon B. C. D. 29. Which of the following graphs depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth? A. Field Strength (N/kg) C. Field Strength (N/kg) Mass (kg) Mass (kg) B. Field Strength (N/kg) D. Field Strength (N/kg) Mass (kg) CADLC 30. Which of the following sequences of colours represents the changing temperatu from the surface to the atmosphere of the sun? a A. Red, orange, yellow, blue B. Yellow, red, orange, blue C. Orange, yellow, blue, red D. Blue, yellow, orange, red 1. When a star undergoes a blue shift, the star is A. moving away from an observer B. moving towards an observer C. moving parallel to an observer D. stationary Mass (kg)
The sun is Yellow, red, orange, and blue. Therefore option B is correct.
The star is moving toward an observer. Therefore option B is correct.
39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.
40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.
29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.
30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.
1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.
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