you begin a hike in Death Valley California at an elevation of -86 M. you hike to a point of elevation at 45 M. what is your change in elevation?​

Answer:

8Ag2S 16Ag + S8

Explanation:

Answer: (A,B,D) [1, 2, 4]

Explanation:

This question is asking for the number of particles that one formula unit of magnesium bromide will produce when dissolved in solution. At the end, the result turns out to be three (3) particles as shown below:

In chemistry, we understand ionization as a process whereby ionic substances split into ions as they dissolve in water. In this case, for magnesium bromide, MgBr₂, we see one Mg²⁺ and two Br⁻ ions are produced as shown below:

\(MgBr_2\rightarrow Mg^{2+}+2Br^-\)

Which means we will have three (3) particles when one formula unit of this salt dissolves.

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A compound consisting of Ba2+ and Cl- :

We have to cross multiply the ionic charges:

Therefore the compound will be:

The student obtained a higher final temperature in the calorimeter when using water compared to using automobile antifreeze due to water's higher specific heat capacity (4.18 J/g°C).

To determine in which experiment the student obtained the higher final temperature in the calorimeter, we need to compare the heat capacities of water and automobile antifreeze.

Water has a specific heat capacity of 4.18 J/g°C, while automobile antifreeze has a specific heat capacity of 2.41 J/g°C. The specific heat capacity represents the amount of heat required to raise the temperature of a given substance by 1 degree Celsius per gram.

Since the student used the same amount of copper in both experiments, the heat transferred to the calorimeter (water or antifreeze) will depend on its heat capacity. A higher heat capacity means that more heat can be absorbed by the substance without a significant increase in temperature.

Since water has a higher specific heat capacity (4.18 J/g°C) compared to automobile antifreeze (2.41 J/g°C), it can absorb more heat per gram without a substantial rise in temperature. Therefore, when using water in the calorimeter, the student is likely to obtain a higher final temperature compared to when using antifreeze.

In summary, the student would obtain a higher final temperature in the calorimeter when using water rather than automobile antifreeze due to the higher specific heat capacity of water.

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Answer:

ionization energy and electronegativity

Explanation:

If you put 1.50 moles of N2 and 4.00 moles of O2 gas in a 45.0 L container at a temperature of 45°C, the total pressure of the system is 323.1 atm.

The ideal gas law, also known as the general gas equation, is the state equation for a hypothetical ideal gas. Although it has several limitations, it is a good approximation of the behavior of many gases under many conditions.

Given;

N = 5.50 moles

V = 45.0 L

R = gas constant 8.314

T = 318 kelvin

P = ?

By an Ideal gas equation,

PV = nRT

By substituting this values in ideal gas equation, and we get as follows:

P = nRT / V

= 5.50 × 8.314 × 318 / 45.0

= 323.1 atm

Thus, the total pressure of the system is 323.1 atm.

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Nadia will take 8 seconds to reach her friend's house.

Speed is the measure of the distance traveled by an object per unit of time. It is a scalar quantity and is typically expressed in units such as meters per second (m/s), miles per hour (mph), or kilometers per hour (km/h).

To calculate the time Nadia will take to reach her friend's house, we can use the formula;

time = distance / speed

where distance is the amount of space traveled by an object, and time is the duration of travel.

Put the values given in the problem, we have:

time = 24 meters / 3 m/s

time = 8 seconds

Therefore, Nadia will take 8 seconds.

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Answer:

It released hydroxide ions (OH ¯).

Explanation:

A PH of 8.3 indicates that the solution has become a basic solution.

Now, for us to have a basic solution from the addition of an alka-seltzer to Koolaid, it means the Alka-seltzer released plenty of hydroxide ons (OH¯) to the solution.

Answer:c

Explanation:c

From the calculation that we have here, the entropy of the system is obtained as 71.9 J/K.

Entropy is a thermodynamic quantity that is a measure of the degree of randomness or disorder in a system. In other words, it is a measure of the number of possible ways that the energy of a system can be distributed, or the number of possible arrangements that the system can have.

We know that;

ΔS = ΔH/T

ΔS = 69 * 10^3/959

ΔS = 71.9 J/K

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Long repeating units are used to create several natural and manmade materials. they most appropriately referred to as O Links and chains (left) and O Molecules (right)? (left).

A molecule comprised of repeating units is referred to as a polymer. These "monomers" combine to form a lengthy molecular chain. It could be made up of branches or it might just be one continuous line of identically related molecules.

A polymer or macromolecule made of many amino acids, proteins are. The monomers/building blocks of a protein are amino acids. things? There are numerous varieties of proteins, which are the supporting molecules of the cell,

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In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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Answer:

H2

Explanation:

Critical temperature is the temperature above which gas cannot be liquefied, regardless of the pressure applied.

Critical temperature directly depends on the force of attraction between atoms, it means stronger the force of higher will be the critical temperature. So, from the given options H2 should have the highest critical temperature because of high attractive forces due to H bonding.

Hence, the correct option is H2.

Answer:

CBr4

Explanation:

Critical temperature is dependent on the strength of the intermolecular forces.

First consider the types of intermolecular forces and the order of their strengths.

Dispersion forces < dipole-dipole forces < hydrogen bonding < ionic bonding

Remember, dispersion forces are present in all cases

H2: only dispersion forces are present

CH4, CCl4, CBr4, CF4: only dispersion forces are present

In order to break the tie we must start considering molar mass because larger molar masses correspond to larger intermolecular forces. Calculating molar mass shows that CBr4 is the largest and will have the strongest intermolecular forces and therefore will have the highest critical temperature.

The answer is CBr4

Answer:

The answer is

Plant also use cellular respiration

Answer:

B - Plants also use cellular respiration.

Explanation:

Did the test.

Because it takes no energy to generate a naturally occurring compound, the enthalpy of formation for an element in its elemental state will always be 0.

The free energy shift that happens when 1 mole of a material is created from its component elements in their standard states is referred to as the standard free energy of formation. The standard free energy of production of a pure element in its standard state is zero.

The distinction between Gibbs free energy and standard free energy is that the former is dependent on the experimental circumstances, whilst the latter describes the Gibbs free energy for reactants and products in their standard state.

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Answer:

Reproductive cells(also known as sex cells) are gametes.

Explanation:

Have a great day :)

Answer:

Gametes are an organism's reproductive cells

Explanation:

Answer:

The molar mass of sulfuric acid (H2SO4) can be calculated by adding the atomic masses of its constituent atoms:

Molar mass of H2SO4 = 2(1.008 g/mol) + 1(32.06 g/mol) + 4(15.99 g/mol) = 98.08 g/mol

Therefore, the mass of 2.25 moles of H2SO4 is:

mass = number of moles x molar mass

mass = 2.25 moles x 98.08 g/mol = 220.68 g

So, the mass of 2.25 moles of sulfuric acid is 220.68 grams.

the oxidation state of each atom

Hydrogen outer shell full with only two electrons, whilst a Carbon outer shell needs eight electrons to have completely filled electronic configuration.

Hydrogen has atomic number of 2 i.e., it has total of 2 electrons. As per the rule maximum of 2 electrons can be filled in first energy shell. In case of Hydrogen both the electrons are present in n = 1 shell, here n is principle quantum number. It has completely filled electronic configuration and also the most stable electronic configuration.

In case of Carbon, it has total of 6 electrons as it has atomic number 6. Out of 6 electrons two are filled in n = 1 shell , now we are left with 4 electrons. These four electrons are present in n = 2 shell. These four electrons are distributed as 2 electrons in 2s and 2 electrons in 2p and still we can fill 4 more electrons in 2p orbital to get completely filled electronic configuration which is also the stable one . So,  Carbon outer shell needs eight electrons.

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0.6 is the equilibrium constant for the given reaction.

To calculate the equilibrium constant (K) for the given reaction, we need to use the molar concentrations of the reactants and products at equilibrium. The equilibrium constant expression is given by:

\(K= [H_{2}O]^{2} / ([H_{2}^{2} * [O_{2}])\)

Given the moles of H2, O2, and H2O in the 8.1 L container, we can convert them to molar concentrations by dividing the number of moles by the volume:

[H2] = 1.83 moles / 8.1 L

[O2] = 2.33 moles / 8.1 L

[H2O] = 3.95 moles / 8.1 L

Substituting these values into the equilibrium constant expression, we have:

K = \((3.95 / 8.1)^{2}\) / (\((1.83 / 8.1)^{2}\) * (2.33 / 8.1))

Evaluating this expression and rounding to one decimal place, we find the equilibrium constant to be:

K ≈ 0.6

Therefore, the equilibrium constant for the given reaction is approximately 0.6.

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Due to the core atom's (Br) sp3d2 hybridization, the molecule has an octahedral form, but Br has two lone pairs of electrons in the axial position, giving it a square planar shape.

​​​​​​

All of the information on the chemical molecule bromine pentafluoride is provided in the hybridization of bromine pentafluoride notes. It is a hybrid molecule made up of five fluorine atoms, five pentavalent bromine atoms, and one pair of missing electrons. Since it is so reactive, oxidizers are added to chemical reactions and commercial rocket propellants.

A square pyramidal molecular structure is produced via the hybridization of bromine pentafluoride, which results in an sp3d2 hybridization. Due to the covalent electron sharing and a bond angle of roughly 90 degrees, the hybrid molecule features six sigma bonds. Two bromine electrons must move from its 4p orbital to its 4d orbital for hybridization to take place.

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Answer: KE = 8.6917248 J

I'm not for sure but I am pretty positive this is the answer

The pairs of solutions that produces a precipitate when combined are  \(Cu(NO_{3})_{2}\) and \(K_{2} CO_{3}\)3. So the correct option is B.

A precipitate is a solid that is created from a solution in an aqueous state in which two chemicals react. The precipitate then, once formed, will remain floating in solution. If you intervene in the process by putting the solution in a centrifuge, it will press the mass to the bottom of the tube, generating a compact mass.

The generation of the precipitate can be generated only if the characteristics of the compounds will overcome the solubility that it has to be able to generate a reaction.

All this will be generated because in the solution there will be components which will generate a chemical reaction between two ionic compounds. For this reason, the correct option will be B. \(Cu (NO_{3}) _{2}\) and \(K_{2} CO_{3}\).

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The molar mass (formula weight) of carbon dioxide (CO2) is 44.01 g/mol.

At STP (Standard Temperature and Pressure), which is defined as 0°C (273.15 K) and 1 atm of pressure, 1 mole of any gas occupies 22.4 L of volume.

Now, we have 3.9 x 10^23 molecules of CO2:

- To find the number of moles, we divide the number of molecules by Avogadro's number:

n = N/Na = 3.9 x 10^23/6.022 x 10^23 = 0.648 moles

- To find the mass, we multiply the number of moles by the molar mass:

mass = n x M = 0.648 mol x 44.01 g/mol = 28.52 grams

Therefore, the mass of 3.9 x 10^23 molecules of carbon dioxide gas at STP is approximately 28.6 grams (option A).

Answer: The molar mass of the unknown compound is 200 g/mol

Explanation:

Depression in freezing point is given by:

\(\Delta T_f=i\times K_f\times m\)

\(\Delta T_f=2.74^0C\) = Depression in freezing point

i= vant hoff factor = 1 (for molecular compound)

\(K_f\) = freezing point constant = \(5.12^0C/m\)

m= molality

\(\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}\)

Weight of solvent (benzene)= 0.250 kg  

Molar mass of solute = M g/mol

Mass of solute  = 26.7 g

\(2.74^0C=1\times 5.12\times \frac{26.7g}{Mg/mol\times 0.250kg}\)

\(M=200g/mol\)

Thus the molar mass of the unknown compound is 200 g/mol

The molar mass of an unknown solute compound in the solution has been 199.626 g/mol.

With the addition of the solute to the solution, there has been a depression in the freezing point. The depression in the freezing point can be expressed as:

Depression in freezing point = Van't Hoff factor × Freezing point constant × molality

The molality can be defined as the moles of solute per kg solvent

Molaity = \(\rm \dfrac{Mass\;of\;solute\;(g)}{Molecular\;mass\;of\;solute}\;\times\;\dfrac{1}{Mass\;of\;solvent\;(kg)}\)

The depression in freezing point can be given as:

Depression in freezing point = Van't Hoff factor × Freezing point constant ×  \(\rm \dfrac{Mass\;of\;solute\;(g)}{Molecular\;mass\;of\;solute}\;\times\;\dfrac{1}{Mass\;of\;solvent\;(kg)}\) ......(i)

Given, the depression in freezing point = 2.74 \(\rm ^\circ C\)

Van't Hoff factor = 1 (Molecular compound)

Freezing point constant (Kf) = 5.12 \(\rm ^\circ C\)/m

Mass of solute = 26.7 g

Mass of solvent = 0.250 kg

Substituting the values in equation (i):

2.74 \(\rm ^\circ C\) = 1 × 5.12

\(\rm \dfrac{2.74}{5.12}\) = \(\rm \dfrac{1}{Molecular\;mass\;of\;solute}\;\times\;\dfrac{26.7}{0.250\;kg}\)

0.535 = \(\rm \dfrac{1}{Molecular\;mass\;of\;solute}\;\times\;106.8\)

Molecular mass of solute = \(\rm \dfrac{106.8}{0.535}\) g/mol

Molecular mass of solute = 199.626 g/mol

The molar mass of an unknown solute compound in the solution has been 199.626 g/mol.

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The compound that contains the atom with the highest oxidation number is CrO₃ (option E).

Oxidation number is the hypothetical charge of an atom within a molecule or compound.

The oxidation number of an atom or ion determines the subscript given to the other elements in the molecule.

According to this question;

Therefore, it can be said that the molecule that posseses the atom with the highest oxidation number is CrO₃.

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