Answer:
1.) 15hrs per week = $97.50
2.) 20hrs per week = $130
Explanation:
Choose ALL that apply
Voltage
a)pushes free protons around a circuit
b)is measured in volts
c)causes current
d)pushes free electrons around a circuit
What are the effects of reverberation?
Reverberation can enhance sound quality, create decay, reduce clarity, and cause distortion.
Power is calculated by multiplying voltage by
a.
current.
b.
energy.
c.
resistance.
d.
voltage.
Answer:
Power is calculated by multiplying voltage by current.
Explanation:
If you're calculating the power of an athlete who is lifting weights,
or the power of a windmill that is pumping water from a well, or
the power of two horses turning millstones, then those electrical
units won't help at all.
But if you happen to be calculating the power delivered to an
electrical circuit or dissipated by an electrical device, then you
can use ...
(voltage) times (current)
or
(voltage)² divided by (resistance)
or
(current)² times (resistance) .
The choice just depends on which quantities you know
or can easily measure.
Write 2 laws of reflection of light
Answer:
Answer⤵i)The first law of reflection states that the incident ray, the reflected ray, and the normal to the surface of the mirror, all lie in the same plane. ii)The second law of reflection states that the angle of reflection is equal to the angle of incidence. Both angles are measured with respect to the normal to the mirror.Martin likes to make flower bouquets that have 333 daffodils and 444 tulips per vase. A daffodil has a mass of ddd grams, a tulip has a mass of ttt grams, and the vase has a mass of vvv grams.
Mass of a bouquet = v + 3d + 4t
Calculation:Given,
Mass of daffodil = d gm
Mass of Tulip = t gm
Mass of vase = v gm
No. of daffodils = 3
No. of tulips = 4
To find,
Weight of flower bouquet =?
According to the question the equation will be
Mass of a bouquet = mass of vase + Mass of 3 daffodils + Mass of 4 tulips
Mass of 3 daffodils = 3d
Mass of 4 tulips = 4t
Now put in the equation,
Mass of a bouquet = v + 3d + 4t
Hence, the weight of flower bouquet is v + 3d + 4t.
I understand the question you are looking for is this:
Martin likes to make flower bouquets that have 3 daffodils and 4 tulips per vase. A daffodil has a mass of d grams, a tulip has a mass of t grams, and the vase has a mass of v grams. Find the total weight of the bouquet.
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Which box will not accelerate?
Answer:
b
Explanation:
i know
Answer:
b one will not accelerate
saturn orbits the sun at more than 50% of the speed of Mars 
true or false????
Answer:
(TRUE) Mars seems to pass the fastest, Jupiter next, and Saturn the slowest. But all exhibit that puzzling quirk--near the point of their celestial course precisely opposite the Sun ("opposition"), their action amongst the stars briefly turns around.
Explanation:
Mars: 24.077 km/s (53,853 miles per
hour), or a period of about 686.93 days.
Answer:is true
Explanation:
Question 10 (1 point)
The Continental Polar air mass exists in the middle upper part of the US in this
image. What are its main characteristics?
Choose ALL that apply
Lesson 1.07
Cold dry air mass
Forms over land
Moist air mass
Answer: a and b i toook the test
Answer:
Cold dry air mass forms over land
Explanation:
A double-decker London bus (Figure 1) might be in danger of rolling over in a highway accident, but at the low speeds of its urban environment, it's plenty stable. The track width is 2.05 m. With no passengers, the height of the center of gravity is 1.45 m, rising to 1.73 m when the bus is loaded to capacity.
The stability of a double-decker London bus is influenced by factors such as track width and the height of its center of gravity. At low speeds in urban environments, the bus is considered stable.
The track width of the bus is 2.05 m, which refers to the distance between the left and right wheels. A wider track width generally increases stability. Additionally, the height of the center of gravity plays a crucial role. With no passengers, the center of gravity is 1.45 m above the ground, while it rises to 1.73 m when the bus is fully loaded. A lower center of gravity enhances stability.
In summary, the double-decker London bus is stable at low speeds in its urban environment due to its track width and the position of its center of gravity. This means that the majority of the bus's mass is concentrated lower down, contributing to its stability. However, when the bus is fully loaded to capacity, the height of the center of gravity rises to 1.73 m. While this increases the risk of rollover in a highway accident, the low speeds typically encountered in urban environments keep the bus stable. In conclusion, the double-decker London bus is considered stable in its urban environment due to factors such as its track width and the position of its center of gravity.
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1. Write the goal of the lab or the question you tried to answer.
Answer:
Type your answer here.
Lab report density and buoyancy
The goal of the lab is to investigate the relationship between density and buoyancy. The lab aims to determine how different objects or substances behave in fluids and understand the principles of density and buoyancy through experimental observations and calculations.
The goal of the lab or the question being addressed in the lab report is to investigate and understand the concepts of density and buoyancy. Density refers to the measure of how much mass is contained within a given volume, while buoyancy refers to the upward force exerted on an object submerged in a fluid, such as water or air.
The lab report aims to explore the relationship between density, mass, and volume by conducting experiments and analyzing data. It may involve measurements of different objects or substances, determining their masses and volumes, and calculating their densities. The report may also involve experiments related to buoyancy, such as determining the buoyant force on an object and investigating factors affecting buoyancy.
By conducting the lab and analyzing the obtained results, the lab report aims to provide a deeper understanding of these fundamental concepts in physics and to demonstrate the principles of density and buoyancy through practical experimentation. The report may also include discussions of the significance and applications of density and buoyancy in various fields, such as engineering, architecture, and fluid dynamics.
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Determine the scalar components R, and R₂ of the force R along the nonrectangular axes a and b. Also determine the orthogonal projection Pa of R onto axis a. Assume R = 810 N, 0 = 117° = 25° R Ans
The scalar components R and R₂ of the force R along the nonrectangular axes a and b are determined using given information. The orthogonal projection Pa of R onto axis a is also calculated.
Given information:
Magnitude of force R = 810 N
Angle between R and axis a = 117°
Angle between R and axis b = 25°
To find the scalar components R and R₂, we can use trigonometry. Let's denote the angle between R and the x-axis as θ. We can express R in terms of its components as follows:
R = R₁ + R₂
Where R₁ is the component of R along axis a, and R₂ is the component of R along axis b.
Using trigonometry, we can determine the values of R₁ and R₂ as follows:
R₁ = R cos(θ)
R₂ = R sin(θ)
To find the angle θ, we subtract the given angles between R and axes a and b from 90° (since axis a and b are nonrectangular):
θ = 90° - 117° = -27°
Now we can calculate R₁ and R₂ using the given magnitude of R and the calculated angle θ:
R₁ = 810 N cos(-27°)
R₂ = 810 N sin(-27°)
Finally, to determine the orthogonal projection Pa of R onto axis a, we use the formula:
Pa = R₁ = 810 N cos(-27°)
Substituting the values into the equations, we can calculate the numerical values of R₁, R₂, and Pa.
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5. A ball rolls off a 1.5 m tall horizontal table and lands on the floor 0.70 m away.
A. How much time is the ball in the air?
B. How does that time compare with the time it takes for a dropped ball to fall that same distance.
C. What is the ball's velocity while it was on the table top?
D. What is the horizontal component of its velocity just prior to impact?
E. What is the vertical component of its velocity just prior to impact?
F. What is the magnitude of its velocity just prior to impact?
G. What is the direction of its velocity just prior to impact?
Take the starting position of the ball 1.5 m above the floor to be the origin. Then at time t, the ball's horizontal and vertical positions from the origin are
x = v₀ t
y = -1/2 gt²
where v₀ is the initial speed with which it rolls off the edge and g = 9.8 m/s².
A. The floor is 1.5 m below the origin, so we solve for t when y = -1.5 m :
-1.5 m = -1/2 gt²
⇒ t² = (3.0 m)/g
⇒ t = √((3.0 m)/g) ≈ 0.55 s
B. It would take the same amount of time.
C. The ball travels a horizontal distance of 0.70 m before reaching the floor, so we solve for v₀ with t = 0.55 s :
0.70 m = v₀ (0.55 s)
⇒ v₀ = (0.70 m) / (0.55 s) ≈ 1.3 m/s
D. At time t, the ball has horizontal and vertical velocity components
v[x] = 1.3 m/s
v[y] = -gt
so the horizontal component of the ball's final velocity vector is the same as the initial one, 1.3 m/s.
E. The vertical component of velocity would be
v[y] = -g (0.55 s) ≈ -5.4 m/s
F. The magnitude of the final velocity would be
√((1.3 m/s)² + (-5.4 m/s)²) ≈ 5.6 m/s
G. The final velocity vector makes an angle θ with the horizontal such that
tan(θ) = (-5.4 m/s) / (1.3 m/s)
⇒ θ = arctan(-5.4/1.3) ≈ -77°
i.e. approximately 77° below the horizontal.
Earth's outer layer is divided into sections called plates.
True or false
Answer:
True
Explanation:
The earth is divided into huge slabs called tectonic plates.
which statment about scientific knoledge is false
An astranaut floating alone in outer space throws a basball if the ball moves at 20 m/s
the astranout will......
Answer:
20 m/s = 44 mph
He will get moved more to earth or away
Explanation:
Answer:
They will get pulled to the earth or moved away
Explanation:
Why is the amount of energy transfer different depending on how high an air parcel travels?
Please give a simple explanation!
Answer:
When the parcel rises, its volume expands as it strives to maintain equilibrium with the lower pressure outside the air mass and pushes into the surrounding atmosphere. In this way, some of the thermal energy added to the air is used for expansion rather than warming.
1. The hydrogen balloons which are used to collect weather information from the atmosphere is made of plastic and never completely filled. Thus the pressure inside and outside are same. The balloon is filled with 150 litres of hydrogen, the air temperature is 27°C and the atmospheric pressure is 98 kPa. The balloon rises to a height where it radios back that the pressure is 30kPa and the temperature is - 33°C. i. What is the Kelvin temperature equivalent to 27°C and -33°C? (1 mark) ii. What is the volume of hydrogen at this height? (2 marks)
Answer:
Answer:- Volume of the balloon is 5.78 L.
Solution:- There are 0.24 moles of hydrogen gas in a balloon at 35 degree C and 1.05 atm pressure. It asks to calculate the volume of the balloon.
This problem is based on ideal gas law equation:
P = 1.05 atm, n = 0.24 mole, T = 35 + 273 = 308 K
R =
V = ?
The equation could be rearranged for the volume as:
Let's plug in the values and do the calculations to get the volume of the balloon:
V = 5.78 L
So, the volume of the gas balloon is 5.78 L.
how to finc the volume of the cylinder when the volume is 45pi, the radius is 9, and the height is 15
The volume of the cylinder is 1215/π cubic units, where the radius is 9 and the height is 15.
To find the volume of a cylinder when given the volume, radius, and height, you can use the formula V = πr^2h.
Substituting the given values, we get:
45π = π(9)^2(15)
Simplifying the equation:
45π = 9π(225)
45π = 2025π
Dividing both sides by π:
45 = 2025
This is not a true statement, which means there must be an error in our calculations. Checking our work, we notice that we forgot to square the radius:
45π = π(9)^2(15)
45π = π(81)(15)
45π = 1215π
Dividing both sides by π:
45 = 1215/π
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What was produced during the reaction between the iron pipes and the fertilizer?
It should be noted that Rust and sodium nitrite were been produced during the reaction between the iron pipes and the fertilizer.
What is a chemical reaction?Chemical reaction can be regarded as a process involving conversation of one or more substances, known as reactants, are converted to different substances known as products.
When iron pipes and the fertilizer which are reactants react together, then products of Rust and sodium nitrite is formed.
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URGENT!!
Your health, budget, and where you live are factors to consider when creating your?
A shopping routine
B fitness plan
C household budget
D nutrition plan
For the following questions, you may use any resources you wish to answer them. You must write your solutions by hand, cite all your references, and show all your calculations.
A) If you stand on Earth's surface and drop a typical-sized water bottle that is one-fifth full (and has a mass of 0.1 kg) one meter X times, how many joules of kinetic energy will be released?
The kinetic energy released when dropping a one-fifth full water bottle with a mass of 0.1 kg from a height of one meter can be calculated using the equation KE = 0.5 * mass * velocity^2.
The amount of kinetic energy released will depend on the final velocity of the water bottle when it hits the ground. To find the final velocity of the water bottle, we can use the equation for free fall motion, v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is 0 m/s since it is dropped from rest), a is the acceleration due to gravity (approximately 9.8 m/s^2), and s is the distance fallen (1 meter in this case). By substituting the values into the equation, we can solve for v. Once we have the final velocity, we can calculate the kinetic energy using the given mass and the derived velocity. The equation KE = 0.5 * mass * velocity^2 relates the kinetic energy to the mass and velocity of an object. By plugging in the mass of the water bottle (0.1 kg) and the calculated velocity, we can determine the amount of kinetic energy released.
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A sample of oxygen gas has a volume of 1.72 L at 27°C and 800.0 torr. How many oxygen molecules does it contain?
A) 4.43x10^22
B) 3.36x10^25
C) 4.92x10^23
D) 8.19x10^24
E) none of these
The closest answer choice is A) 4.43 x 10^22 oxygen gas molecules so that is the answer.
To solve this problem, we can use the Ideal Gas Law, which states that PV=nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature.
First, we need to convert the temperature to Kelvin by adding 273.15 to get 300.15 K. Then, we can solve for n using the formula:
n = (PV)/(RT)
n = (800.0 torr * 1.72 L) / (0.08206 L*atm/mol*K * 300.15 K)
n = 0.0746 mol
Next, we can use Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole, to find the number of molecules in the sample:
number of molecules = n * Avogadro's number
number of molecules = 0.0746 mol * 6.022 x 10^23 molecules/mol
number of molecules = 4.49 x 10^22
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Answer :A
Explanation:
First convert 800torr to atm by ( 800/760) = 1.05
then apply the gas law PV=nRT
(1.052*1.72) / ((27+273)*(0.082) =0.073
then multiply by Avogadro no.
0.073 * 6.022*10^23 =4.43*10^22
The table below shows four examples of pairs of objects, the masses of each
object in the pair, and the distances between the objects. In which example is the
gravitational force of attraction between the two objects the greatest?
F3 is the greatest of all forces , hence 3rd case in which masses were 200kg and 150 kg separated with a distance of 10 will have greatest force of all
The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them is called gravitation force of attraction
gravitation force = Gm1 m2 / \(r^{2}\)
G = gravitational constant
m1 = mass of one object
m2 = mass of other object
r = distance between them
case 1
F1 = G (50) (100) / \(20^{2}\) = 12.5 G
F2 = G (50) (10) / \(10^{2}\) = 5 G
F3 = G (200) (150) / \(10^{2}\) = 300 G
F4 = G (200) (150) / \(30^{2}\) = 33.33 G
F3 is the greatest of all forces , hence 3rd case in which masses were 200kg and 150 kg separated with a distance of 10 will have greatest force of all
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15) The diagram below represents the sequence of events (steps 1 through 10) resulting in the production of a D' meson and a D* meson. An electron and a positron (antielectron) collide (step1), annihilate each other (step 2), and become energy (step 3). This energy produces an anticharm quark and a charm quark (step 4), which then split apart (steps 5 through 7). As they split, a down quark and an antidown quark are formed, leading to the final production of a D' meson and a D* meson (steps 8 through 10).
Which statement best describes the changes that occur in this sequence of events?
(1) Energy is converted into matter and then matter
is converted into energy.
(2) Matter is converted into energy and then energy
is converted into matter.
(3) Isolated quarks are being formed from baryons.
(4) Hadrons are being converted into leptons.
A statement which describes the changes that occur in this sequence of events is: 2. matter is converted into energy and then energy is converted into matter.
What is the law of conservation of matter?The law of conservation of matter (LOCOM) states that mass can neither be created nor destroyed in any chemical reaction.
Similarly, the energy possessed by a matter can neither be created nor destroyed, but it can only be converted from one energy form to another.
In this context, we can logically deduce that a statement which best describes the changes that occur in this sequence of events is that matter is converted into energy and subsequently, energy is converted into matter.
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why does light splits into different colours while passing through a prism
Answer:
Since different colours of light travel at different speeds, the refractive index is different for each colour. As a result, when light passes through the refracting surface of the prism,its components bend into different angles, causing the single beam of light to separate
Number of atoms present in 1 mole of oxygen atom
Answer:
1 mole of every substance has 6.022 × 10^23 particles. This is called Avagadro's constant
Required information You grab a book and give it a quick push across the top of a horizontal table. After a short push, the book slides across the table, and because of friction, comes to a stop. Let the subscripts be the following: b = book, t = table, e = Earth, h = hand. If the book has a mass of 0.420 kg and the coefficient of friction between the book and the table is 0.400, what is the net force acting on the book after you have stopped pushing it, while it is sliding across the table? Enter a positive answer, if the net force is in the direction of motion and a negative answer, if the net force is opposite to the direction of motion.
To find the net force acting on the book while it is sliding across the table, we need to calculate the frictional force.
1. Identify the required information:
mass of the book (m b) = 0.420 kg and coefficient of friction (μ) = 0.400.
2. Calculate the gravitational force acting on the book (F- gravity) = m b * g,
where g = 9.81 m/s^2 (acceleration due to gravity).
F-gravity = 0.420 kg * 9.81 m/s^2 = 4.1202 N.
3. Since the book is on a horizontal table, the normal force (F_ normal) equals the gravitational force acting on the book:
F_ normal = F_ gravity = 4.1202 N.
4. Calculate the frictional force (F_ friction) acting opposite to the direction of motion using the formula: F_ friction = μ * F_ normal.
F_ friction = 0.400 * 4.1202 N = 1.64808 N.
5. The net force acting on the book (F_ net) is equal to the frictional force, but with a negative sign since it's opposite to the direction of motion:
F_net = -1.64808 N.
The net force acting on the book after you have stopped pushing it, while it is sliding across the table, is -1.64808 N.
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a hydraulic jack has an input piston of area 0.0540 m2 and an output piston of area 0.710 m2. how much force (in n) on the input piston is required to lift a car weighing 1.80 ✕ 104 n?
Approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.
The force required on the input piston of the hydraulic jack can be calculated using the principle of Pascal's law, which states that the pressure exerted in a fluid is transmitted equally in all directions.
The ratio of the output force to the input force is equal to the ratio of the output piston area to the input piston area:
Force (output) ÷ Force (input) = Area (output) ÷ Area (input)
We can rearrange this equation to solve for the input force:
Force (input) = Force (output) × (Area (input) ÷ Area (output))
Given that the weight of the car is 1.80 × \(10^{4}\) N, the output force is 1.80 × \(10^{4}\) N. The input piston area is 0.0540 \(m^{2}\), and the output piston area is 0.710 \(m^{2}\).
Plugging these values into the equation, we have:
Force (input) = (1.80 × \(10^{4}\) N) × (0.0540 \(m^{2}\) ÷ 0.710 \(m^{2}\))
Simplifying the expression gives us:
Force (input) ≈ 1377.46 N
Therefore, approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.
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Calculate the change in time for each quarter of the track. Record the change in time in Table C of your Student Guide.
The change in time for the first quarter is _____ seconds.
The change in time for the second quarter is _____ seconds.
The change in time for the third quarter is _____ seconds.
The change in time for the fourth quarter is _____ seconds.
Answer:
Calculate the change in time for each quarter of the track. Record the change in time in Table C of your Student Guide.
The change in time for the first quarter is
✔ 2.07
seconds.
The change in time for the second quarter is
✔ 1.09
seconds.
The change in time for the third quarter is
✔ 0.95
seconds.
The change in time for the fourth quarter is
✔ 0.81
seconds.
Explanation:
Got it right in edge
Answer:
b a b d
Explanation:
part beach child holds the end of a rope and child b pulls on the rope so that he moves toward child a. how far will child b have moved when he collides with child a?
3.813m far will child b have moved when he collide with child a.
We know that,
\(x_{cm}\)=\(\frac{m_{a} x_{a} +m_{b} x_{b} }{m_{a}+x_{b} }\)
\(x_{cm}\)=26(0)+49(11)/26+49=7.187
A=From a is 7.187m
B=we forces know that, the internal can't change the motion of CM. SO they will meet Collide at their C.M.
B has to move the distance from B→C.M. So they will meet Collide at their C.M B will forces.
11-7.187 = 3.863
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