Answer:
x = 10, x = 0
I dont know if you wanted an answer but yeah-
how many centimeters are in 5 inches? 1in. = 2.54 cm
5 in. = ?
paying
Activity 1.4
Solving problems with whole numbers
2. In a truck of red and green peppers, the ratio of red peppers to green peppers is 3.4.
If the truck contains 120 green peppers, how many red peppers are there?
Answer:
90
Step-by-step explanation:
3:4
R:G
total ratio =7
total peppers is y
4/7 × y = 120
7×120=4y
840÷4=y
y=210
G+R=Y
210-120=R
R=90
Ally and Christian bought 4 pounds of butter and 2 pounds of chocolate chips for cookies. How many ounces of products did they purchase?
Answer: 96
Step-by-step explanation: Multiplying by 16 (6 × 16)
Kaya’s family spends $105 to rent a boat for 7 days. The total cost, c, of the boat rental is proportional to the number of days, d, the family rents the boat.
How much does it cost, in dollars, to rent the boat for one day?
Answer:
$15/day
Step-by-step explanation:
If the rent is proportional to the number of days, the dividing the total cost by the number of days will tell you the price of each day:
105/7=15
Question 1 Can you construct one, many, or no triangle(s) with side lengths of 3 inches, 4 inches, and 8 inches?
Answer: No triangles
Step-by-step explanation: The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Which is why 3,4, and 8 do not make a triangle, hope this helped!!
Read each of the following situations and select ALL of the ones considered plagiarism.
Answer:
Ashley uses internal citation to give credit for someone else's idea
A black board of length 5m 20cm and breath 3m 40cm is to be painted. Find the cost at the rate of rs10 square metre
Step-by-step explanation:
To find the cost of painting the blackboard, we first need to calculate its area.
Length of the blackboard = 5m 20cm = 5.20m
Breadth of the blackboard = 3m 40cm = 3.40m
Area of the blackboard = Length x Breadth
Area = 5.20m x 3.40m
Area = 17.68 square meters
The cost of painting 1 square meter at the rate of Rs. 10 is Rs. 10. Therefore, the cost of painting 17.68 square meters is:
Cost = Area x Rate
Cost = 17.68 square meters x Rs. 10 per square meter
Cost = Rs. 176.80
Therefore, the cost of painting the blackboard at the rate of Rs. 10 per square meter would be Rs. 176.80.
What is the value of x?
Answer:
x = 9
Step-by-step explanation:
→Looking at the angles, you can see that a right angle is formed. This means that there must be another right angle (90 degrees) formed with the numbers. You can set up the equation, like so:
3x + 6 + 57 = 90
→Add like terms (6 and 57):
3x + 63 = 90
→Subtract 63 from both sides:
3x = 27
→Divide both sides by 3:
x = 9
Answer:
x=9
Step-by-step explanation:
a right angle is 90 degrees
90-57= 33
33-6=27
27/3 = 9
Its my request to you to mark this as the brainiest
a handful of coins has the value of 1 dollar and 79 cents there are 3 times as many dimes as quarters and 5 more pennies than dimes if there are only 3 types of coins how many of each type of coin are there
Answer:
3 Quarters 9 dimes 14 pennies
Step-by-step explanation:
so dimes are x, quarters are y, and pennies are z. Next we know that x*3 y is what dimes are and 5 more pennies then dimes so z+5. Now we do 3 quarters since thats about 100 but less then 3*3=9 so 190 we have 90+75 cents now then we add 14 the cursed number lol but we add 14 because 9+5 is 14 and there are 5 more pennies then dimes.
Solve the following equation: 3.3+4x=-6.9x+6.6
Round your answer to the nearest tenth.
The solution to the equation 3.3 + 4x = -6.9x + 6.6, rounded to the nearest tenth, is x ≈ 0.3.
To solve the equation 3.3 + 4x = -6.9x + 6.6, we need to isolate the variable x on one side of the equation.
First, let's simplify the equation by combining like terms:
3.3 + 4x = -6.9x + 6.6
Next, let's move the variable terms (4x and -6.9x) to one side and the constant terms (3.3 and 6.6) to the other side:
4x + 6.9x = 6.6 - 3.3
Combine the x terms on the left side:
10.9x = 3.3
Now, divide both sides of the equation by 10.9 to solve for x:
x = 3.3 / 10.9
Using a calculator, we can find the decimal approximation of x:
x ≈ 0.3028
Rounding to the nearest tenth, the solution to the equation is x ≈ 0.3.
In summary, the solution to the equation 3.3 + 4x = -6.9x + 6.6, rounded to the nearest tenth, is x ≈ 0.3.
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I will give Brainliest!!
Answer:
5.8 h po salamat
salamat po
Let x be the number of years since 1998, let g(x) be the average monthly bill (in dollars) for mobile phone users in the United States, and let h(x) be the average number of minutes used by U.S. mobile phone users. Then g(x) and h(x) are as given g(x) = -0.27x³ + 1.40x² + 1.05x + 39.4, h(x) = -8.25x³ + 53.1x² - 7.82x + 138 Write a rational function ƒ(x) that gives the average price per minute x years after 1998.
The rational function ƒ(x) that represents the average price per minute x years after 1998 is given by ƒ(x) = g(x) / h(x), where g(x) = -0.27x³ + 1.40x² + 1.05x + 39.4 and h(x) = -8.25x³ + 53.1x² - 7.82x + 138.
To calculate the average price per minute x years after 1998, we need to find the ratio between the average monthly bill (g(x)) and the average number of minutes used (h(x)). Therefore, the rational function ƒ(x) is defined as ƒ(x) = g(x) / h(x).
Given that g(x) = -0.27x³ + 1.40x² + 1.05x + 39.4 and h(x) = -8.25x³ + 53.1x² - 7.82x + 138, we can substitute these expressions into the rational function to obtain the final formula: ƒ(x) = (-0.27x³ + 1.40x² + 1.05x + 39.4) / (-8.25x³ + 53.1x² - 7.82x + 138).
This rational function represents the average price per minute x years after 1998 based on the given average monthly bill and average number of minutes used by U.S. mobile phone users. By plugging in different values for x, you can evaluate the function and obtain the corresponding average price per minute for each year.
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solve for x please and thank you:)
Answer: x=5
Step-by-step explanation:
Take 5 and you can see that's it's about equal to x
4 1/3 x 2 1/4 written down
Answer:
117/16
Step-by-step explanation:
4 1/3=13/4 2 1/4=9/4 multiply and that gives 117/16
Find the value of x.
Area of triangle = 40
Will mark as brainliest if it's correct :))
Answer:
4
Step-by-step explanation:
1/2 ×base ×height =40
1/2 × (x+4) × x=40
(x+4) + x =80(40×2)
x×x + 4x =80
x×x + x =80/4
x×x +x =20
x=4
hope it helps....plz mark me brainliest :)
The value of x in for the triangle having an area of 40 units is 71.6 units.
What is a triangle?A triangle is a three-sided closed-plane figure form by joining three noncolinear points. Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.
We know area of a triangle is (1/2)×base×height.
Therefore, The area of the rectangle with a base of 'x+4' units and height of 'x' units is,
(1/2)×(x+4)×x.
Given, Area is 40.
Therefore,
(1/2)×(x+4)×x = 40.
x² + 4x = 80.
x² + 4x - 80 = 0.
Solving the quadratic we get, x = 7.16 units.
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22. Find three consecutive odd numbers such that the sum of five times the smaller number and twice
the larger number is 33 more than six times the median number.
Answer:
The numbers are 37, 39 and 41.
Step-by-step explanation:
Let the smallest number be \(x\\\).
Then the other numbers will be \(x+2, x+4\) (as they are consecutive odd numbers, their difference will be 2).
As per the given statement:
LHS(Left Hand Side) : Sum of five times the smaller number and twice the larger number.
i.e. five times the smaller number = \(5\times x\)
twice the larger number = \(2 \times (x+4)\)
Their sum:
The Left Hand Side becomes:
\(5x+2(x+4)\)
RHS(Right Hand Side):
33 more than six times the median number:
i.e. \(6\times(x+2) +33\)
Equating LHS and RHS:
\(5x+2(x+4) = 6x+12 +33\\\Rightarrow 7x+8=6x+47\\\Rightarrow \bold{x =37}\)
Therefore, the numbers are 37, 39 and 41.
Write a proportion for each set of similar polygons. Solve for the unknown side.
Type the FULL Answer for both questions.
Pls Answer!
Step-by-step explanation:
The proportion of similar triangles are
\( \frac{3}{4} = \frac{9}{r} \)
Solving for r
\( \frac{4}{3} = \frac{r}{9} \)
\( \frac{9 \times 4}{3} = r\)
\(12 = r\)
On Monday, Elise walked 9. 9 kilometres. On Tuesday, she walked 0. 7 kilometres less than she had walked on Monday. How far did Elise walk on Tuesday?
Elise walked a distance of 9.2 kilometers on Tuesday.
To solve the problem, we need to first understand the information provided.
On Monday, Elise walked a distance of 9.9 kilometers.
On Tuesday, she walked a distance that was 0.7 kilometers less than what she walked on Monday.
This means that we need to subtract 0.7 kilometers from the distance that she walked on Monday to find the distance she walked on Tuesday.
To do this, we can use subtraction. We start by writing down the distance Elise walked on Monday, which is 9.9 kilometers, and then subtract 0.7 kilometers from it.
9.9 km - 0.7 km = 9.2 km
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Using the formulas you learned in Lesson 11-1, make a conjecture about the formula for the area of this type of quadrilateral if B C is b_{1} , A D is b_{2} , and A B is h . Explain.
The formula for the area of the quadrilateral with side lengths B C = b₁, A D = b₂, and A B = h can be given by the expression:
Area = ½ × (b₁ + b₂) × h
Let's consider the quadrilateral with side lengths B C = b₁, A D = b₂, and A B = h. We can divide this quadrilateral into two triangles by drawing a diagonal from B to D. The height of both triangles is equal to h, which is the perpendicular distance between the parallel sides B C and A D.
To find the area of each triangle, we use the formula: Area = ½ × base × height. In this case, the base of each triangle is b₁ and b₂, respectively, and the height is h.
Therefore, the area of each triangle is given by:
Area₁ = ½ × b₁ × h
Area₂ = ½ × b₂ × h
Since the quadrilateral is composed of these two triangles, the total area of the quadrilateral is the sum of the areas of the two triangles:
Area = Area₁ + Area₂
= ½ × b₁ × h + ½ × b₂ × h
= ½ × (b₁ + b₂) × h
Hence, the conjecture is that the formula for the area of the quadrilateral with side lengths B C = b₁, A D = b₂, and A B = h is given by the expression: Area = ½ × (b₁ + b₂) × h.
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Consider the following shape drawn on a centimetre grid. I 1.1) Determine the perimeter of this shape.
Answer:
its 19 ur welcome byeeee
Step-by-step explanation:
the price of a car was increased from 3600 to 4500. what was the percent of the increase
Answer:
25%
Step-by-step explanation:
.25(3,600)=900
3,600+900=4,500
Answer:
25%
Step-by-step explanation:
well first do 4500 minus 3600 which is eqaul to 900. then find out how much 900 is of 3600
900/360=0.25
then multiply it by 100 to get the percentage
0.25*100=25%
.A set of logical and mathematical operations performed in a specific sequence is called a(n)
complete enumeration.
diagnostic analysis.
algorithm.
objective.
None of these
The correct answer is "algorithm."
What is the term for a sequence of logical and mathematical operations?An algorithm is a step-by-step procedure or set of rules that specifies a sequence of logical and mathematical operations to solve a particular problem or perform a specific task. It provides a systematic approach to problem-solving, outlining the necessary actions and decisions required to achieve the desired outcome. Algorithms can be represented in various forms, such as pseudocode, flowcharts, or programming languages.
The use of algorithms is fundamental in computer science, mathematics, and other fields that require problem-solving and data manipulation. They serve as the foundation for creating efficient and effective solutions, enabling automation, optimization, and decision-making processes. Algorithms can be simple or complex, and their design and analysis play a crucial role in ensuring accuracy, efficiency, and reliability in various applications.
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What is the coordinate of the focus
for the following parabola:
(x - 1)2 = 12(y + 2)
A. (1, -2)
B. (0, 12)
C. (12,0)
D. (1, 1)
Answer:
I want to say B or D please tell me if I'm right lol
How exactly does Pythagorean theorem work??
Answer:
Given the sides of a triangle, the Pythagorean Theorem (its converse, really) lets us distinguish the right triangles from the other triangles. The right triangles are the ones where , where is the length of the longest sides and and are the other two. So the Pythagorean Theorem works for any triangle.
Step-by-step explanation:
Answer:
Pythagorean Theorem is used when you have to find a side length of right triangle. Leg 1 and Leg 2 could be labeled as A and B, doesn't matter which one is which. But C is always the hypotenuse which is the biggest side in the whole triangle. And to find the hypotenuse of the it is always the side length opposite to the right angle in the triangle. So the formula goes like;
A² + B² = C²
Hope this helps!
−8x 4y>3 6x−7y<−5 is (2,3) a solution of the system?
The ordered pair (2,3) is not a solution of the system
How to determine if (2,3) a solution of the system?From the question, we have the following parameters that can be used in our computation:
−8x + 4y > 3
6x - 7y < −5
The solution is given as
(2, 3)
Next, we test this value on the system
So, we have
−8(2) + 4(3) > 3
-4 > 3 --- false
This means that (2,3) is not a solution of the system
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Determine the general solution of the given differential equation that is valid in any interval not including the singular point. x2y" - 3xy 4y= 0 O ycic2 y Cixcos(In|x|) + c2x2 sin(ln |x|) y cilx2 c2lx yx2 (c C2 In]x|) y cixcos(In |x|) + c2x sin(In |x|)
The general solution of the differential equation is:
y = c1 x^2 + c2 x^(2/3) ∑(n=0)^(∞) (1/(3
To solve this differential equation, we can use the method of Frobenius. We assume that the solution has the form:
y = ∑(n=0)^(∞) a_n x^(n+r)
where r is a constant to be determined, and a_n are constants. We can differentiate y to get:
y' = ∑(n=0)^(∞) a_n (n+r) x^(n+r-1)
y'' = ∑(n=0)^(∞) a_n (n+r) (n+r-1) x^(n+r-2)
Substituting these into the differential equation, we get:
x^2 ∑(n=0)^(∞) a_n (n+r) (n+r-1) x^(n+r-2) - 3x ∑(n=0)^(∞) a_n x^(n+r+1) + 4 ∑(n=0)^(∞) a_n x^(n+r) = 0
We can simplify this equation by changing the index of the second sum:
x^2 ∑(n=0)^(∞) a_n (n+r) (n+r-1) x^(n+r-2) - 3x ∑(n=1)^(∞) a_n x^(n+r) + 4 ∑(n=0)^(∞) a_n x^(n+r) = 0
We can now factor out x^(r-2) from the first sum, x^(r+1) from the second sum, and x^r from the third sum:
x^r [a_0 (r^2 - 3r + 4) + ∑(n=1)^(∞) a_n [(n+r)(n+r-1) - 3(n+r) + 4] x^n] = 0
Since x^r ≠ 0 for any finite x, we can divide both sides by x^r and simplify:
a_0 (r^2 - 3r + 4) + ∑(n=1)^(∞) a_n [(n+r)(n+r-1) - 3(n+r) + 4] x^n = 0
This is a power series that must be zero for all x, so each coefficient must be zero. We can start by setting the coefficient of x^0 to zero:
a_0 (r^2 - 3r + 4) = 0
This gives us two possible values for r:
r = 2 and r = 2/3
Now we can set the coefficients of x^n to zero for n ≥ 1. For r = 2, we get:
a_n [(n+2)(n+1) - 6(n+2) + 4] = 0
Simplifying this expression and solving for a_n, we get:
a_n = c1 / n^2
where c1 is a constant of integration. For r = 2/3, we get:
a_n [(n+2/3)(n-1/3) - 3(n+2/3) + 4] = 0
Simplifying this expression and solving for a_n, we get:
a_n = c2 / (3n+1)
where c2 is a constant of integration.
Therefore, the general solution of the differential equation is:
y = c1 x^2 + c2 x^(2/3) ∑(n=0)^(∞) (1/(3
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Determine whether the linear transformation is one-to-one, onto, or neither. (Select all that apply.) T: R4 → R4, T(X, Y, Z, W) = (V, W, X, z) O one-to-one onto neither
To determine whether the linear transformation T is one-to-one, onto, or neither, we need to analyze the rank and nullity of the transformation.
The rank of T is the dimension of the image space, which is the span of the columns of the transformation matrix. To find the matrix, we can write T(X, Y, Z, W) = (V, W, X, Z) as a matrix equation:
|V| |0 0 1 0||X|
|W| = |0 1 0 0||Y|
|X| |1 0 0 0||Z|
|Z| |0 0 0 1||W|
From this matrix, we can see that the columns are linearly independent, so the rank of T is 4.
The nullity of T is the dimension of the kernel, which is the set of all solutions to the equation T(X, Y, Z, W) = (0, 0, 0, 0). We can set up the augmented matrix for this equation:
|0 0 1 0 0|
|0 1 0 0 0|
|1 0 0 0 0|
|0 0 0 1 0|
Row-reducing this matrix gives:
|1 0 0 0 0|
|0 1 0 0 0|
|0 0 1 0 0|
|0 0 0 1 0|
The only solution is the trivial one, so the nullity of T is 0.
Since the rank of T is equal to the dimension of the domain and the codomain, T is onto. And since the nullity of T is 0, T is also one-to-one. Therefore, the correct answer is "one-to-one and onto".
Hi! To determine whether the linear transformation T: R4 → R4, T(X, Y, Z, W) = (V, W, X, Z) is one-to-one, onto, or neither, let's analyze the properties of this transformation.
1. One-to-one: A linear transformation is one-to-one if different input vectors produce different output vectors.
In this case, T(X, Y, Z, W) = (V, W, X, Z). Observe that every input vector (X, Y, Z, W) uniquely determines the output vector (V, W, X, Z). Thus, this transformation is one-to-one.
2. Onto: A linear transformation is onto if every output vector can be produced by some input vector.
For this transformation, T(X, Y, Z, W) = (V, W, X, Z), every output vector (V, W, X, Z) can be produced by the input vector (X, Y, Z, W). So, the transformation is onto as well.
In conclusion, the linear transformation T: R4 → R4, T(X, Y, Z, W) = (V, W, X, Z) is both one-to-one and onto.
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I put 16 and it said that it was Wong
Answer: 97/100
Step-by-step explanation:
Answer:
The answer is 0.97 or 97/100
Step-by-step explanation:
9/10 = 0.9
7/100 = 0.07
0.9 + 0.07 = 0.97
Hope this helps!
Please mark as brainliest!
Please I actually need this done
Answer:
AC = 19
Step-by-step explanation:
A__C__S
AS = AC + CS
6x -4 = (4x-1) + 7
6x - 4 = 4x + 6
6x - 4x = 6+ 4
2x = 10
x = 10/2
x = 5
AC = 4x -1 = 4(5) - 1 = 20 - 1 = 19
I hope I helped you^_^
Answer:
19
Step-by-step explanation:
AS = AC + CS
6x - 4 = 4x -1 +7
6x - 4 = 4x + 6
Add 4 to both sides,
6x = 4x + 6 + 4
6x = 4x + 10
Subtract 4x from both sides
6x- 4x = 10
2x = 10
Divide both sides by 2
x = 10/2
x = 5
AC= 4x - 1
= 4*5 - 1
= 20 - 1
= 19
Kara Danvers (Supergirl) has always relied on her strength to win fights. But what happens when she meets an alien just as strong? Her sister is training her to be a more technical fighter so that Supergirl can meet any challenge. The data below record the significant strikes during randomly selected training sessions 6 months apart. Is Kara showing improvement in her fighting?
Strikes (pre): 29 32 44 34 19
Strikes (post): 51 45 68 92 64
Write the Hypotheses:
H_0:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
H_a:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
Answer:
H0 : The mean difference in strikes between pre and post strike is equal to 0
H1 : The mean difference in strikes between pre and post strike is not equal to 0
Step-by-step explanation:
The scenario described abibe meets the condition for a paired (dependent) sample t test as the same subject is involved in both the pre and post strike data. Therefore measurement from the strike(pre) must be paired with measurement from the strike(post) data.
For a paired test involving a single subject ; The mean difference in the two sample is 0 ; that is both are the same while the alternative negates the null by claiming that the mean difference is not equal to zero.