-x + 7 = 9 - x
pls help w

Answer:

A

Step-by-step explanation:

The list has the sides of ΔFGH in order from shortest to longest side GF < side HF < side HG option (C) is correct.

In terms of geometry, a triangle is a three-sided polygon with three edges and three vertices. The triangle's interior angles add up to 180°.

It is given that:

In ΔFGH, m∠F = 119° and m∠G = 40°.

From the data given in the question:

The correct order should be:

side GF < side HF < side HG

Thus, the list has the sides of ΔFGH in order from shortest to longest side GF < side HF < side HG option (C) is correct.

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Using the law of cosines, the length of BC in the given quadrilateral is: 8.1 cm.

The law of cosines that can be used to find the length of a side of a triangle with a known included angle and two sides is:

c² = a² + b² - 2 × a × b × Cos C.

Considering right triangle ABD,

BD = a

DC = b

BC = c

Use the Pythagorean theorem to find the length of BD in the quadrilateral as shown in the diagram:

BD = √(7.5² + 5²)

BD = √(7.5² + 5²)

BD = 9.0 cm

Use the law of cosines to find the length of BC:

BC² = BD² + DC² - 2 × BD × DC × Cos <BDC.

Substitute

BC² = 9.0² + 13² - 2 × 9.0 × 13 × Cos 38

BC² = 250 - 184.4

BC² = 65.6

BC = √65.6

BC = 8.1 cm

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(a) An observer standing beside a one-lane road counted in 5 minutes 20 cars traveling at 30 mph, 30 cars traveling at 50 mph and 10 cars traveling at 60 mph. The time-mean speed of the observed cars is 900 mph.

(b) The average headway of the cars is 5.08 minutes (approximately).

(a) To calculate the space and time-mean speeds of the observed cars, we need to consider the total distance traveled and the total time taken by the cars.

Given data:

Number of cars traveling at 30 mph = 20

Number of cars traveling at 50 mph = 30

Number of cars traveling at 60 mph = 10

To find the space-mean speed, we calculate the weighted average of the speeds based on the number of cars at each speed:

Space-mean speed = [(20 cars * 30 mph) + (30 cars * 50 mph) + (10 cars * 60 mph)] / (20 + 30 + 10)

               = (600 + 1500 + 600) / 60

               = 2700 / 60

               = 45 mph

The space-mean speed of the observed cars is 45 mph.

To find the time-mean speed, we calculate the total distance traveled and divide it by the total time taken:

Total distance traveled = (20 cars * 30 mph * 5/60 hours) + (30 cars * 50 mph * 5/60 hours) + (10 cars * 60 mph * 5/60 hours)

                      = (25 miles + 41.67 miles + 8.33 miles)

                      = 75 miles

Total time taken = 5 minutes = 5/60 hours

Time-mean speed = Total distance traveled / Total time taken

               = 75 miles / (5/60) hours

               = 75 miles * (60/5)

               = 900 mph

(b) Average headway is the average time interval between successive cars passing a given point.

To find the average headway, we need to calculate the total time taken by all the cars and divide it by the total number of intervals:

Total time taken by all the cars = (20 cars + 30 cars + 10 cars) * 5 minutes

                              = 60 cars * 5 minutes

                              = 300 minutes

Total number of intervals = 60 cars - 1 (as there is no interval after the last car)

Average headway = Total time taken by all the cars / Total number of intervals

              = 300 minutes / 59 intervals

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Answer:

9y-3y=6y is equivalent to 9y – 3y.

Answer:

\(\huge\boxed{Answer\hookleftarrow}\)

Given,

\(x = 7\)

Substitute the value of 'x' in the equation 3x (x - 2).

One way :-

\(3x(x - 2) \\ = 3 \times 7(7 - 2) \\ = 21(5) \\ = 21 \times 5 \\ = 105\)

Second way :-

\(3x(x - 2) \\ = 3x {}^{2} - 6x \\ = 3 \times (7) {}^{2} - 6(7) \\ = (3 \times 49) - (6 \times 7) \\ = 147 - 42 \\ = 105\)

✐ The answer is 105.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

The given equation is \(2cos^2(θ) + 2cos(θ) - 1 = 0.\) To find the approximate solutions in the interval [0, 2π), we need to solve the equation for θ.

To solve the equation, we can treat it as a quadratic equation in terms of \(cos(θ)\). We can substitute \(x = cos(θ)\) to simplify the equation:

\(2x^2 + 2x - 1 = 0\)

We can now solve this quadratic equation using factoring, completing the square, or the quadratic formula. However, solving this equation leads to complex solutions, indicating that there are no real solutions within the given interval [0, 2π). Therefore, the solution for the equation 2cos^2(θ) + 2cos(θ) - 1 = 0 in the interval [0, 2π) is DNE (Does Not Exist) as there are no real solutions in this interval.

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The area to the right of 23.337 under the chi-square distribution with 12 degrees of freedom is 0.0125.

In statistics, the chi-square distribution is a continuous probability distribution that is widely used in inferential statistics. The area to the right of a certain value can be calculated using a chi-square table or a computer program. In this case, we want to find the area to the right of 23.337 under the chi-square distribution with 12 degrees of freedom. Using a chi-square calculator or a chi-square table, we can determine that this area is 0.0125. This means that there is a 1.25% chance of getting a chi-square value greater than 23.337 with 12 degrees of freedom. This type of calculation is often used in hypothesis testing and other statistical analyses.

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Answer:

1 pint of milk

Step-by-step explanation:

1/2 pint -> .52X2=$1.04 for 1 pint

1 quart -> $2.10/2=$1.05 for 1 pint

there is 4 pints in 1/2 gallon so .99 X 4 = 3.96 for 1/2 gallon

hope this helps

Answer:

guest what you need milk

Step-by-step explanation:

The quarterly operating profit margin of TMG Ltd over the past six years is provided in Table 4.1, indicating the financial performance of the business during that period.

In order to assess the impact of the intervention strategy introduced by the current CEO three years ago, the board of directors (BOD) of TMG Ltd has contracted a researcher to analyze the data and determine if there have been significant improvements in the business outcomes. The quarterly operating profit margin serves as the unit of analysis for this evaluation.

Table 4.1 allows the researcher to examine the trend and fluctuations in the quarterly operating profit margin over the six-year period. By analyzing the data, the researcher can identify any noticeable changes in the financial performance of TMG Ltd, particularly after the implementation of the intervention strategy. The BOD is interested in understanding whether the strategy has resulted in improved profitability and overall financial health of the company.

The researcher will likely perform statistical analysis, such as calculating averages, trends, and identifying any significant variations, to draw conclusions about the effectiveness of the intervention strategy. By comparing the quarterly operating profit margin before and after the strategy's implementation, the researcher can assess whether the new CEO's efforts have had a positive impact on the company's financial performance.

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Answer:

14 cm

Step-by-step explanation:

Let the radius (r) and slant height \( l\) of the cone be 7x and 25x respectively.

Curved surface are of the cone = 2200 sq cm

\( \therefore \pi r l = 2200\)

\( \therefore \frac{22}{7} \times 7x\times 25x= 2200\)

\( \therefore \frac{22}{7} \times 175x^2 = 2200\)

\( \therefore x^2 = \frac{2200\times 7}{22\times 175} \)

\( \therefore x^2 = \frac{100}{ 25} \)

\( \therefore x^2 = 4 \)

\( \therefore x =\sqrt 4 \)

\( \therefore x =2\: cm \)

Radius = 7x = 7*2 = 14 cm

Answer:

B stu goofy jr out

Step-by-step explanation:

i took the stu goofy jr test

The answer is

7x-1/8x

a. the probability that less than 5 customers will arrive in a 5-minute period is approximately 0.0292 or 2.92%. b. The probability that the time between two consecutive arrivals will be more than 1 minute is approximately 0.1353 or 13.53%.

a. To calculate the probability that less than 5 customers will arrive in a 5-minute period, we can use the Poisson distribution formula. The Poisson distribution is commonly used to model the number of events occurring in a fixed interval of time or space when the average rate of occurrence is known.

Given that the average number of customers arriving per hour is 120, we need to adjust this rate to the 5-minute period. Since there are 60 minutes in an hour, the average rate for a 5-minute period is 120/12 = 10 customers.

To calculate the probability of less than 5 customers arriving in a 5-minute period, we can sum the probabilities of 0, 1, 2, 3, and 4 customers using the Poisson distribution formula. The formula is as follows:

P(X = k) = (e^(-λ) * λ^k) / k!,

where λ is the average rate and k is the number of events.

Using this formula, we can calculate the individual probabilities and sum them up:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4),

P(X = 0) = (e^(-10) * 10^0) / 0! = e^(-10) ≈ 0.0000454,

P(X = 1) = (e^(-10) * 10^1) / 1! = 10e^(-10) ≈ 0.000454,

P(X = 2) = (e^(-10) * 10^2) / 2! = 50e^(-10) ≈ 0.00227,

P(X = 3) = (e^(-10) * 10^3) / 3! = 500e^(-10) ≈ 0.00757,

P(X = 4) = (e^(-10) * 10^4) / 4! = 2500e^(-10) ≈ 0.01892.

Summing these probabilities:

P(X < 5) ≈ 0.0000454 + 0.000454 + 0.00227 + 0.00757 + 0.01892 ≈ 0.0292.

Therefore, the probability that less than 5 customers will arrive in a 5-minute period is approximately 0.0292 or 2.92%.

b. To find the probability that the time between two consecutive arrivals will be more than 1 minute, we need to consider the exponential distribution. The exponential distribution models the time between events in a Poisson process.

The average rate of customer arrivals per minute can be calculated by dividing the average rate per hour by 60:

λ = 120 / 60 = 2 customers per minute.

Let T represent the time between two consecutive arrivals. The exponential distribution is defined as:

P(T > t) = e^(-λt),

where λ is the average rate and t is the time interval.

Substituting the values:

P(T > 1) = e^(-2 * 1) = e^(-2) ≈ 0.1353.

Therefore, the probability that the time between two consecutive arrivals will be more than 1 minute is approximately 0.1353 or 13.53%.

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a) Activity that should be crashed first to reduce the project duration by 1 day is B.

b) Activity that should be crashed next to reduce the project duration by one additional day is C.

c) Total cost of crashing the project by 2 days = $10,000.

To determine the activities that should be crashed first and next, we need to consider the critical path method (CPM). The critical path is the longest sequence of activities that determines the total project duration. Crashing activities on the critical path will reduce the project duration.

Let's calculate the project duration and costs for each activity:

Activity A:

Normal Time: 7 days

Crash Time: 6 days

Normal Cost: $5000

Total Cost with Crashing: $5600

Activity B:

Normal Time: 4 days

Crash Time: 2 days

Normal Cost: $1500

Total Cost with Crashing: $3400

Immediate Predecessor(s): A

Activity C:

Normal Time: 11 days

Crash Time: 9 days

Normal Cost: $4200

Total Cost with Crashing: $6600

Immediate Predecessor(s): B

To find the critical path, we add the normal times of each activity:

Critical Path: A -> B -> C

a) Activity that should be crashed first to reduce the project duration by 1 day:

Since the critical path includes activities A, B, and C, we need to identify which activity's crash time can reduce the project duration by 1 day. The activity that can achieve this is B since its crash time is 2 days compared to activity A's crash time of 6 days. Therefore, activity B should be crashed first.

b) Activity that should be crashed next to reduce the project duration by one additional day:

After crashing activity B, the project duration will be reduced by 1 day. To further reduce the duration by an additional day, we need to determine which activity's crash time can achieve this. The activity that can achieve this is C since its crash time is 9 days compared to activity A's crash time of 6 days. Therefore, activity C should be crashed next.

c) Total cost of crashing the project by 2 days:

The total cost of crashing the project by 2 days is the sum of the total costs for the crashed activities:

Total cost of crashing = Total cost of crashing activity B + Total cost of crashing activity C

                   = $3400 + $6600

                   = $10,000

Therefore, the total cost of crashing the project by 2 days is $10,000.

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Complete Question:

Three activities are candidates for crashing on a project network for a large computer installation (all are, of course, critical). Activity details are in the following table.

a) Activity that should be crashed first to reduce the project duration by 1 day is

b) Activity that should be crashed next to reduce the project duration by one additional day is

c) Total cost of crashing the project by 2 days =

The solution to the system of equations is x = -1, y = -6.

What is a system of equations?

A system of equations is a set of two or more equations that are to be solved together, where the solutions must satisfy all the equations in the system. A system of equations can involve one or more variables and can be expressed in different forms, such as linear equations, quadratic equations, or any other type of equations.

The goal of solving a system of equations is to find the values of the variables that satisfy all of the equations in the system. Depending on the type and complexity of the equations, there are different methods that can be used to solve the system, such as substitution, elimination, or matrix methods.

For example, a system of two linear equations with two variables x and y can be written in the form:

a₁x + b₁y = c₁

a₂x + b₂y = c₂

where a₁, b₁, c₁, a₂, b₂, and c₂ are constants. To solve this system of equations, we need to find the values of x and y that satisfy both equations simultaneously.

Systems of equations can arise in various contexts, including in mathematics, physics, engineering, economics, and other fields. They are used to model and solve a wide range of problems that involve multiple variables and constraints.

To solve the system of equations by the method of subtraction, we need to eliminate one of the variables (x or y) by subtracting one equation from the other.

Given the system of equations:

Y=6x

2x-7y=40

We can use the first equation to express y in terms of x:

y = 6x

Substituting this expression into the second equation, we get:

2x - 7(6x) = 40

Simplifying and solving for x, we get:

2x - 42x = 40

-40x = 40

x = -1

Now that we have found the value of x, we can substitute it back into either equation to find the value of y. Using the first equation:

y = 6x = 6(-1) = -6

Therefore, the solution to the system of equations is x = -1, y = -6.

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In integration the bindefinite integral of 1/xlnx is

ln(|u|)+C=ln(|lnx|)+C with the aid of using parts, we've discovered whilst the specified formula.

The vital of the 2 capabilities are taken, with the aid of using thinking about the left time period as first feature and 2nd time period as the second one feature.

This technique is referred to as Ilate rule.The vital of xlnx is same to (x2/2) lnx - x2/4 + C, wherein C is the mixing constant. We can compare this vital the usage of the technique of integration with the aid of using parts.

We have the vital:

\(∫1xlnxdx

Use substitution. Let u=lnx so that du=1xdx . Note that each of those are presently gift withinside the vital.

∫1xlnxdx=∫(1lnx)1xdx=∫1udu

This is a not unusualplace vital:

∫1udu=ln(|u|)+C

Since u=lnx :

ln(|u|)+C=ln(|lnx|)+C\)

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well, since the y-intercept is at -5, or namely when the line hits the y-axis is at -5, that's when x = 0, so the point is really (0 , -5), and we also know another point on the line, that is (-1 ,6), to get the equation of any straight line, we simply need two points off of it, so let's use those two

\(\stackrel{y-intercept}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{0}}} \implies \cfrac{6 +5}{-1} \implies \cfrac{ 11 }{ -1 } \implies - 11\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{- 11}(x-\stackrel{x_1}{0}) \implies y +5 = - 11 ( x -0) \\\\\\ y+5=-11x\implies {\Large \begin{array}{llll} y=-11x-5 \end{array}}\)

Answer: 5/8

Step-by-step explanation:

find common denominator:

Multiple: 3/4 * 5/6 = 3 · 5/4 · 6= 15/24 = 5 · 3/8 · 3 = 5/8 Multiply both numerators and denominators. Result fraction keep to lowest possible denominator  GCD(15, 24) = 3. In the following intermediate step, cancel by a common factor of 3 gives 5/8. In other words - three quarters multiplied by five sixths = five eighths.

Answer:

Step-by-step explanation:

Let m = slope

m = (-14 - 1)/(7 - (-3))

m = (-15)/(7 + 3)

m = -15/10

m = -3/2

Done.

Answer:

x = 5

Step-by-step explanation:

Use the slope formula and slope-intercept form  y =  m x  +  b  to find the equation.

Hope this helps:)

Answer:

A

Step-by-step explanation:

i think...

The transformation is (4, 3)

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure. The original shape of the object is called the Pre-Image and the final shape and position of the object is the Image under the transformation

If the there is rotation of 90° around the origin (0,0), that can be expressed as

(x, y) => (-y, x)

Which means a 90° rotation that can done by changing coordinates positions and inverting the sign of y-coordinate.

However, the problem is giving the transformed coordinates where

Q'(–3, 4)

Hence, the transformation is (4, 3)

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The answer is x = 8,0

hope this helps!

Answer:

x = 0 and 8

Step-by-step explanation:

|x – 4| = 4    <-- separate it into 2 equations since it's an absolute value and there would be 2 answers (one number as positive and one number as negative)

--------------------------------------------------------

x – 4 = 4    <-- postive

   + 4 = + 4

      x = 8

---------------------------------------------------------

x – 4 = - 4     <-- negative

   + 4 = + 4

      x = 0

It will take the crew 28 days to lay all the track.

The crew has 66 miles of track left to lay after 17 days.

L(d) = 168 - 6d = 0

6d = 168

d = 28

So it will take the crew 28 days to lay all the track.

It should be noted that to find how many miles of track the crew has left to lay after 17 days, we can plug in d=17 into the function L(d):

L(17) = 168 - 6(17) = 66

So the crew has 66 miles of track left to lay after 17 days.

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The area of the region enclosed by the curves 10x=2y²+12y+19 and x=-4y-10 is 174/3 units².

To find the area of the region enclosed by the curves 10x=2y²+12y+19 and x=-4y-10, we need to solve this problem in the following way:

Since the curves are already in the form of x = f(y), we need to use vertical strips to find the area.

So, the integral for the area of the region is given by:

A = ∫a b [x₂(y) - x₁(y)] dy

Here, x₂(y) = 10 - 2y² - 12y - 19/5 = - 2y² - 12y + 1/2 and x₁(y) = -4y - 10

So,

A = ∫(-3)⁻²[(-2y² - 12y + 1/2) - (-4y - 10)] dy + ∫(-2)⁻²[(-2y² - 12y + 1/2) - (-4y - 10)] dy

=> A = ∫(-3)⁻²[2y² + 8y - 19/2] dy + ∫(-2)⁻²[2y² + 8y - 19/2] dy

=> A = [(2/3)y³ + 4y² - (19/2)y]₋³ - [(2/3)y³ + 4y² - (19/2)y]₋² | from y = -3 to -2

=> A = [(2/3)(-2)³ + 4(-2)² - (19/2)(-2)] - [(2/3)(-3)³ + 4(-3)² - (19/2)(-3)]

=> A = 174/3

Hence, the area of the region enclosed by the curves is 174/3 units².

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Answer:

Step-by-step explanation:

( 3m + 2) (4m-3)

Answer:

3532.5

Step-by-step explanation:

Here’s the equation you would followe

V=1/3h(3.14)r^2

H=height

R=radius

Answer:

Substitute n to that 0.72 and multiply it from 3.6

answer would be 2.592

Step-by-step explanation:

The symbolic forms for the given statements are: (b) p ∨ r, (c) p ∧ q, (d) q ~ r, and (e) p ∨ q. Statement (a) cannot be expressed symbolically.

(a) x ≥ 5: This statement represents a numerical inequality, and it cannot be expressed symbolically.

(b) p ∨ r: The symbolic form for the statement "p ∨ r" is a logical disjunction, meaning it represents the logical "OR" operation between the propositions p and r.

(c) p ∧ q: The symbolic form for the statement "p ∧ q" is a logical conjunction, indicating the logical "AND" operation between the propositions p and q.

(d) q ~ r: The symbolic form for the statement "q ~ r" is a negation, where the proposition r is negated, represented by the symbol "~".

(e) p ∨ q: The symbolic form for the statement "p ∨ q" is a logical disjunction, indicating the logical "OR" operation between the propositions p and q.

In logic, different symbols are used to represent various logical operations and relationships between propositions. The statements provided have different symbolic forms based on the logical operations they represent.

The "∨" symbol represents logical disjunction (OR), "∧" symbol represents logical conjunction (AND), and "~" symbol represents negation. It is important to understand the symbolic forms to accurately represent and analyze logical statements.

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Answer: B&D

Step-by-step explanation: