The values of the input functions when put into the function are;
f(3) = 5
f(3²) = 9
f(-2) = 8/3
f(6) = 7
How to input values in a function?We are given the function to be represented as;
f(x) = ²/₃x + 3
Now, we are told that the input value of x are;
X = (3, 3², -2, 6)
Thus;
for f(3), we plug in the value of 3 into the function for x to get;
f(3) = ²/₃(3) + 3
f(3) = 2 + 3
f(3) = 5
for f(3²), we plug in the value of 3² into the function for x to get;
f(3²) = f(9) = ²/₃(9) + 3
f(3²) = 9
for f(-2), we plug in the value of -2 into the function for x to get;
f(-2) = ²/₃(-2) + 3
f(-2) = 8/3
for f(6), we plug in the value of -2 into the function for x to get;
f(6) = ²/₃(6) + 3
f(6) = 7
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there are 24 students in Ms. Woodall's class. 1/2 of the students are boys. 1/3 of the boys have brown hair. what is the number of boys in Ms. woodall's class who have brown hair?
Answer:
4
Step-by-step explanation:
1/2 of 24=12
1/3 of 12=4
Find the Maclaurin polynomials of orders n=0,1,2,3,4, and then find the nth Maclaurin polynomials for the function in sigma notation.
Enter the Maclaurin polynomials below for 5/1+x
P0(x), P1(x), P2(x), P3(x), P4(x)?
Pn(x)=
The Maclaurin polynomials of orders n=0, 1, 2, 3, and 4 for the function 5/(1+x) are P0(x) = 5, P1(x) = 5 - 5x, P2(x) = 5 - 5x + 5x^2, P3(x) = 5 - 5x + 5x^2 - 5x^3, and P4(x) = 5 - 5x + 5x^2 - 5x^3 + 5x^4, respectively.
The Maclaurin polynomials are a way to approximate a function using a polynomial expansion centered at x = 0. The Maclaurin polynomial of order n for a function f(x) is given by Pn(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3 + ... + (f^n(0)/n!)x^n, where f'(0), f''(0), f'''(0), ..., f^n(0) are the derivatives of f(x) evaluated at x = 0.
In this case, the given function is f(x) = 5/(1+x). To find the Maclaurin polynomials of orders n=0, 1, 2, 3, and 4, we evaluate the function and its derivatives at x = 0 and substitute them into the general formula for the Maclaurin polynomials.
For n=0, P0(x) = 5, as f(0) = 5.
For n=1, P1(x) = 5 - 5x, as f(0) = 5 and f'(0) = -5.
For n=2, P2(x) = 5 - 5x + 5x^2, as f(0) = 5, f'(0) = -5, and f''(0) = 10.
For n=3, P3(x) = 5 - 5x + 5x^2 - 5x^3, as f(0) = 5, f'(0) = -5, f''(0) = 10, and f'''(0) = -30.
For n=4, P4(x) = 5 - 5x + 5x^2 - 5x^3 + 5x^4, as f(0) = 5, f'(0) = -5, f''(0) = 10, f'''(0) = -30, and f^4(0) = 120.
These Maclaurin polynomials provide polynomial approximations of the given function 5/(1+x) for different orders. The higher the order (n), the more terms are included in the polynomial expansion, resulting in a more accurate approximation of the original function around x = 0.
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What am i missing here...
Image text for clarification
In a large city, the average family spending in dollars for back-to-school shopping of supplies for the 2000, 20002, 20004 and 2006 years is listed in the chart below:
2000 2002 2004 2006
113 142 183 238
What is the average increase in spending per year from the year 2000 to to the year 2002? (142-113)/2
What is the average increase in spending per year from the year 2004 to the year 2006? (238-183)/2
What is the average increase in spending per year from the year 2000 to to the year 2006?
Estimate the instantaneous increase in spending in the year 2004 by taking the average of two average rates of change.
The average increase in spending per year from:
2000 to 2002 is $14.50.
2004 to 2006 is $27.50.
2000 to 2006 is $20.83.
The estimated instantaneous increase in spending in the year 2004 is $21.75.
The average increase per year = (spending in 2002 - spending in 2000) / (number of years)
= (142 - 113) / 2
= 14.5
The average increase per year = (spending in 2006 - spending in 2004) / (number of years)
= (238 - 183) / 2
= 27.5
To find the average increase in spending per year from the year 2000 to 2006, we first find the total increase in spending over the six-year period:
Total increase = spending in 2006 - spending in 2000
= 238 - 113
= 125
The average increase per year = total increase / (number of years)
= 125 / 6
= 20.83
To estimate the instantaneous increase in spending in the year 2004, we can take the average of the average rates of change between adjacent years:
Instantaneous increase in spending in 2004 = (average increase per year from 2002 to 2004 + average increase per year from 2004 to 2006) / 2
= ( (183-142)/2 + (238-183)/2 ) / 2
= 21.75
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George decided to use blue paint to paint a wall with two windows. The wall is 12 7 8 ft by 8 ft. Both windows are 3 1 2 ft by 4 1 2 ft rectangles.
Answer:
71 1/2 square feet
Step-by-step explanation:
We want to find the area of the wall that will be painted.
We need to find the area of the two windows and subtract it from the area of the wall.
Each window is 3 1 /2 ft by 4 1/2 ft. The area of each window is therefore:
A = L * B
A = 7/2 * 9/2 = = 63/4 square feet = 15 3/4 square feet
The two windows therefore have an area of:
2 * 63/4 = 63/2 = 31 1/2 square feet.
The wall measures 12 7/8 ft by 8 ft. Therefore, the area of the wall is:
A = 103/8 * 8 = 103 square feet
The area of the wall that will be painted is therefore:
A = 103 - 31 1/2 = 71 1/2 square feet
Answer: 103
Step-by-step explanation:
helpppppppppppppppppp
Answer:
i think its 2
Step-by-step explanation:
Answer:
3,506
Step-by-step explanation:
Solve for v in the proportion.
72/81 = v/99 V = ?
Answer:
V = 88
Step-by-step explanation:
72/81 = V/99
72/81 x 99 = V
V = 88
Given the following parameters for a sampling distribution of sample proportions, calculate the standard score of the sample proportion, Round your answer to two decimal places. p = 0.85, x = 184, n = 200
Answer:
2.77
Step-by-step explanation:
The sample proportion is:
\(\hat{p}=\frac{x}{n}=\frac{184}{200}=0.92\)
Then, the standard score of the sample proportion is:
\(z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.92-0.85}{\sqrt{\frac{0.85(1-0.85)}{200}}}=2.77\)
2. f(x)=4x+1 and g(x)=x2−4x−5, find (g◦f)(4).
Answer:
(g · f)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x² - 4x- 5
(g · f)(x) = 4(x² - 5) + 1
(g · f)(4) = 4(4² - 5) + 1
Following pemdas
(g · f)(4) = 4(16 - 5) + 1
(g · f)(4) = 4(11) + 1
(g · f)(4) = 44 + 1
(g · f)(4) = 45
what is x if x(x+3)(x+3)=0
Answer:
hello :
Step-by-step explanation:
x(x+3)(x+3)=0 means : x=0 or x+3=0 or x+3=0
x=0 or x=-3 or x=3
Calculate the frequency of a wave with a speed of 250m/s and a wavelength of 50m.
HELPPPPPPPPPPPPPPPPPPPPPPPP PLS
Answer:
formulasfrequency=speed/wavelength
f=250/50
f=50hz
What is the slope?
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
The hypotenuse of a triangle is 37 millimeters long. One of the legs is 24.5 millimeters long. What is the measure of the missing leg? Round to the nearest tenth, if necessary.
Answer: 27.7 millimeters
Step-by-step explanation:
Let the missing leg be represented by x.
We will use Pythagoras formula to solve this. The measure of the missing leg will be:
x² = 37² - 24.5²
x² = 1369 - 600.25
x² = 768.75
x = ✓768.75
x = 27.7
The missing leg is 27.7 millimeter
Gina wants to take dance classes. She compares two dance studios to determine which has the best deal for her. Dance World charges a rate for each class. Toe Tappers charges a rate for each class plus a one-time registration fee. The system of equations shown models the total costs for taking x classes at each.
Dance World: y = 15x
Toe Tappers: y = 25 + 12.5x
How many classes would Gina need to take for the total cost to be the same at both dance studios?
10
15
100
150
Answer:
The correct answer is A: 10
Step-by-step explanation:
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The graphs of y = |x|_ and y= |x + 2|
are shown on the grid below.
y
-9
-9-8-7-6-5-4-3-2-1
98
-8
-7
-4
-3
65432
-2
№
-3
-4
56
-5
-6
-7
-8
-9
2 3 4 5 6 7 8 9
√x
Key
= y = |x+2|
= y = |x|
What is the solution to |x| > |x + 2| ?
The solution to |x| > |x + 2| is x < -2. This can be determined by looking at the two graphs on the grid, y = |x| and y = |x + 2|.
What is inequality?Inequality is the concept of representing a relationship between two values using a mathematical symbol. This can be used to express various forms of comparison such as greater than, less than, and not equal to. Inequality is an important concept for understanding and applying mathematical principles, such as in algebra and calculus.
The graph of y = |x| is a straight line at y = 0, and increases as x moves further away from 0. The graph of y = |x + 2| has a minimum at x = -2, and increases as x moves further away from -2. Therefore, at all locations where x is less than -2, the value of |x| is greater than the value of |x + 2|. These locations are all solutions to the inequality |x| > |x + 2|.
To visualize this solution, we can look at the graph of the two functions and see that the value of |x| is greater than the value of |x + 2| when x is less than -2. This can also be seen by looking at the numerical values of the two functions; for any x less than -2, the absolute value of x will be greater than the absolute value of x + 2.
In conclusion, the solution to the inequality |x| > |x + 2| is x < -2. This can be seen visually on the graph of the two functions, and can also be determined by looking at the numerical values of the two functions.
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Convert the given polar
coordinates into rectangular
coordinates.
(4,4)=([?],[√
Converting the polar coordinates into rectangular coordinates (4,4π/3) is: (-2, 2√3).
How to polar coordinates into rectangular coordinates?Using this formula to convert from polar coordinates into rectangular coordinates
x = r cos(θ)
y = r sin(θ)
Where:
r = radius
θ = angle in radians
So,
(r, θ) = (4, 4π/3)
Substitute
x = 4 cos(4π/3)
x = 4 (-1/2)
x = -2
y = 4 sin(4π/3)
y = 4 (√3/2)
y = 2√3
Therefore the rectangular coordinates are (-2, 2√3).
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Show that the value of cos 30 x tan 60 + sin 30 is an integer
Trigonometry ratios are used to represent sine, cosine and tangent functions. The value of cos(30) ×tan(60) +sin(30) is 2.
Trigonometry:
Trigonometry, a branch of mathematics concerned with the specific functions of angles and their use in calculations. There are six angular functions commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc).
According to the Question:
The trigonometry equation is given as:
cos(30) ×tan(60) +sin(30)
In trigonometry,
cos(30) = √3/2
tan (60) = √3
and sin(30) = 1/2
Now, Putting the value:
cos(30) ×tan(60) +sin(30) = √3/2 ×√3 + 1/2
Evaluate all products
cos(30) ×tan(60) +sin(30) = √3/2 ×√3 + 1/2
Add roots
cos(30) ×tan(60) +sin(30) = 3/2 + 1/2
⇒ cos(30) ×tan(60) +sin(30) = 4/2 = 2
Hence, the value of cos(30) ×tan(60) +sin(30) is 2.
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The product of 0.014 and 100,000 is
_ ...
because the decimal point in 0.014 moves
_ ...
places to the right.
Answer:
5
Step-by-step explanation:
In the case when we multiplied 0.014 by 100,000 so it comes
= 0.014 × 100,000
= 1,400
Since The value 0.014 were times by 5 zeros.
Therefore the decimal point would move 5 places to the right
A small rectangular pyramid shaped metal object made of a single metal is found in an archaeological dig. Because of the metals available to the area’s inhabitants at the time, scientists believe the metal could be either iron, lead, nickel, or silver. The weight of the object is 612.4 grams. The rectangular base of the pyramid is 3 cm by 6 cm and the height is 9 cm. The density for each metal is shown below: Iron: 7.874 grams/cm 3 Lead: 11.34 grams/cm 3 Nickel: 8.908 grams/cm 3 Silver: 10.49 grams/cm 3 Select the metal shown below that was used to construct the small rectangular pyramid-shaped metal object found in the archaeological dig. A. Iron C. nickel B. Lead D. silver
The metal that was used to construct the small rectangular pyramid-shaped metal object found in the archaeological dig is B. Lead of density \(11.34 grams/cm^{3}\)
Given :
The weight of the object is 612.4 grams.
The Height of the object = 9cm
The Breadth of the rectangular base = 3cm
The Length of the rectangular base = 6cm
Area of the rectangular base = Length*Breadth = 3*6 sq. cm = 18 sq. cm
Calculating the volume of the Object,
Volume = \(\frac{Length*Width*Height}{3}\)
Volume = \(\frac{6*3*9}{3} = 54 cm^{3}\)
Now, Calculating density,
\(Density = \frac{Mass}{Volume }\\\\\)
Putting the values of mass and volume, we have \(Density =\frac{612.4}{54} = 11.34 grams/cm^{3}\)
Hence, the density of the material is \(11.34 grams/cm^{3}\)
The density matches the density of LEAD.
Hence, the metal that was used to construct the small rectangular pyramid-shaped metal object found in the archaeological dig was B. Lead
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pls help pls helppppppppp
Answer:
470 g
Step-by-step explanation:
1 cm^3 = 1 gram
210 grams + 260 grams = 470 grams
if the world population is 7.0 billion in 2012, and the growth rate is constant at 1.4%, calculate the population in 2030.
The world population in 2030 will be of 9.0062 billion.
The exponential formula for population growth is given below:
P(t) = P (0)e^rt
Here, P(t) is the population in t years from now P (0) is the population in the current year and r(decimal) is the growth rate, e=2.7 is the Eular number.
If the world population is 7.0 billion in 2012.
2012 is the initial year, P (0) =7
P(t) will be measured in billions of people.
The growth rate is constant at 1 .4%.
So that, r = 0.014
Now, the population in 2030 will be :
2030-2012=18 years after 2012, so this is P(18).
P(t)= 7e^rt
P(18) = 7e^0.0014*18
= 9.0062
So, the world population in 2030 will be of 9.0062 billion.
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The world population will be 9.0062 billion in 2030.
The population growth exponential formula is as follows:
P(0)ert = P(t)
P(t) denotes the population in t years. P (0) is the current year's population, r(decimal) is the growth rate, and e=2.7 is the Euler number.
If the world population in 2012 is 7.0 billion.
The first year is 2012, and P (0) = 7.
The magnitude of P(t) will be measured in billions of people.
The rate of growth remains constant at 1.4%.
As a result, r = 0.014.
Now, in 2030, the population will be:
2030-2012 = 18 years after 2012, so P (18).
P(t)= 7e^rt
P(18) = 7e^0.0014*18
= 9.0062
As a result, the world population in 2030 will be 9.0062 billion people.
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likert-type scale response choices must be balanced at the ends of the response continuum.
that it is important for likert-type scale response choices to be balanced at the ends of the response continuum. This means that there should be an equal number of positive and negative response options to avoid any bias or skew in the results.
An explanation for this is that if there are too many positive or negative response options, respondents may feel pressured to choose a certain option even if it doesn't accurately reflect their true opinion. This can result in inaccurate data and can skew the results of the survey or study.
balancing the response choices on a likert-type scale is crucial for obtaining accurate and unbiased data. By having an equal number of positive and negative options, respondents are more likely to provide honest and accurate responses.
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Is (3,4) a solution of y < 4x -2
Answer:
Yes
Step-by-step explanation:
Substitute:
Calculate the product or quotient:
Calculate the sum or difference:
Obtain a simplified relation:
Determine true or false: True
Answer: True
Need help to break this down pleasd
Answer:
The height of the window is 150 centimeters.
Step-by-step explanation:
Use ratio and proportion to find the height of the window.
\(\frac{h}{60cm} = \frac{210cm}{84cm}\)
Cross multiply
\(h = \frac{210cm(60cm)}{84cm} \\h = \frac{12600cm^2}{84cm} \\h = 150 cm\)
apply the descriptive statistics tool for subsets of liberal arts colleges and research universities in the excel file colleges and universities. compare the two types of colleges. what can you conclude?
Liberal arts colleges have a higher median SAT score and a lower acceptance rate compared to research universities, while research universities have a higher expenditure per student and a higher percentage of top 10% high school graduates.
Descriptive statistics were calculated for liberal arts colleges and research universities based on the data given in the Excel file. The summary of descriptive statistics for each variable by school type is as shown in the table.
Based on the results, it appears that liberal arts colleges have higher median SAT scores, lower acceptance rates, and lower expenditures per student than research universities. On the other hand, research universities have higher mean expenditures per student and higher median percentages of top 10% high school graduates than liberal arts colleges. Overall, there are differences in the characteristics of these two types of colleges.
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--The complete question is, Compute descriptive statistics for liberal arts colleges and research universities in the Excel file Colleges and Universities. Compare the two types of colleges. What can you conclude?
Colleges and Universities
School Type Med SAT Accept Rate Exp./Student Top 10% HS Grad %
Amherst Lib Arts 1315 22% $26,636 85 93
Barnard Lib Arts 1220 53% $17,653 69 80
Bates Lib Arts 1240 36% $17,554 58 88
Berkeley Univ 1176 37% $23,665 95 68
Bowdoin Lib Arts 1300 24% $25,703 78 90
Brown Univ 1281 24% $24,201 80 90
Bryn MawrLib Arts1255 56% $18,847 70 84
Cal Tech Univ 1400 31% $102,262 98 75
Carleton Lib Arts 1300 40% $15,904 75 80
Carnegie University1225 64% $33,607 52 77
Claremont Lib Arts1260 36% $20,377 68 74
Colby Lib Arts 1200 46% $18,872 52 84
Colgate Lib Arts 1258 38% $17,520 61 85
ColumbiaUniversity1268 29% $45,879 78 90
Cornell University1280 30% $37,137 85 83
DavisdsonLib Arts 1230 36% $17,721 77 89
Duke University 1310 25% $39,504 91 91
GeorgetownUniv 1278 24% $23,115 79 89
Grinnell Lib Arts 1244 67% $22,301 65 73
HamiltonLib Arts 1215 38% $20,722 51 85
Harvard Univ 1370 18% $46,918 90 90
HaverfordLib Arts 1285 35% $19,418 71 87
Johns Hop. Univ 1290 48% $45,460 69 86
MiddleburyLib Arts 1255 25% $24,718 65 92
MIT University 1357 30% $56,766 95 86
Mount Lib Arts 1200 61% $23,358 47 83
NWrn University 1230 47% $28,851 77 82
Oberlin Lib Arts 1247 54% $23,591 64 77
Occidental Lib Arts 1170 49% $20,192 54 72
Pomona Lib Arts 1320 33% $26,668 79 80
Princeton University 1340 17% $48,123 89 93
Rice University 1327 24% $26,730 85 88
Smith Lib Arts 1195 57% $25,271 65 87
Stanford University 1370 18% $61,921 92 88
Swarthnore Lib Arts 1310 24% $27,487 78 88
U of MI University 1195 60% $21,853 71 77
U of Chi University 1300 45% $38,937 74 73
U of Roc University 1155 56% $38,597 52 73
U PA University 1280 41% $30,882 87 86
U Va University 1218 37% $19,365 77 88
UCLA University 1142 43% $26,859 96 61
UNC University 1109 32% $19,684 82 73
Vassar Lib Arts 1287 43% $20,179 53 84
Wash U University 1225 54% $39,883 71 76
Wash & Lee Lib Arts 1234 29% $17,998 61 78
Wellesley Lib Arts 1250 49% $27,879 76 86
Wesleyan Lib Arts 1290 35% $19,948 73 91
Williams Lib Arts 1336 28% $23,772 86 93
Yale University 1350 19% $52,468 90 93--
How much would it cost to make a million if I saved $100 everyday for a year
Identify the length, width, and height of the figure formed.
WHOEVER ANSWERS FIRST GETS BRILLIANT
Answer:
216 units
Step-by-step explanation:
lenght x width x height
Consider the quadratic function f(x)= 2(x + 4)² − 6. Does the graph open up or down
Answer:
up
Step-by-step explanation:
a is positive
Do anyone know this problem?
Answer:
me kown it
Step-by-step explanation:
The solution to -12 + n = -15 is n = 3. true or false
Answer:
False
Step-by-step explanation:
Step 1: Write out equation
-12 + n = -15
Step 2: Add 12 on both sides
n = -3
So our answer is -3 and not 3.
Answer: \(False\)
The answer to this problem is \(n=-3\)
To get -3 here is the work shown
Simplify both sides of the equation
\(n-12=-15\)
Add 12 to both sides
\(n-12+12=-15+12\\n=-3\)
what is the main difference between the dot product and the cross product? how does orthogonality relate to both results?
The dot product is a scalar quantity that represents the projection of one vector onto another, and can be used to calculate the angle between two vectors.
The cross product is a vector quantity that represents the magnitude and direction of the orthogonal projection of one vector onto another. Orthogonality is related to both results in that the dot product of two orthogonal vectors is zero, while the cross product of two parallel vectors is also zero. In addition to that, the cross product of two non-zero vectors results in a third vector that is orthogonal to both.
The dot product is a scalar product that calculates the projection of one vector onto another. The cross product is a vector product that calculates the orthogonal component of one vector with respect to another.
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