Write the expression for the Broglie wavelength associated with a charged particle having charge 'q' and mass 'm', when it is accelerated by a potential V.

The moon remains in orbit around earth because of gravitational energy

Data;

Moon and other centripetal bodies maintain a state of constant orbit or centripetal acceleration because of gravitational energy.

The gravitational energy acting on the moon keeps the body rotating. This is further elaborated by Einstein's theory of relativity.

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The energy transformations in a projectile launcher involve the conversion of potential energy stored in the spring into kinetic energy of the ball, which is then transformed into other forms of energy as the ball moves through the air and interacts with other objects.

When a projectile launcher uses a spring to launch a ball, there are several energy transformations that occur:

1.Potential energy is stored in the spring as it is compressed. The amount of potential energy stored is given by the equation PE = (1/2) k x², where k is the spring constant and x is the distance that the spring is compressed.

2.When the spring is released, the potential energy is transformed into kinetic energy as the spring expands and pushes the ball forward. The kinetic energy of the ball is given by the equation KE = (1/2) m v², where m is the mass of the ball and v is its velocity.

3.As the ball travels through the air, it loses some of its kinetic energy due to air resistance, which is a form of non-conservative force. This energy is transformed into heat and sound energy.

4.When the ball hits a surface, some of its kinetic energy is transferred to the surface, causing it to deform or move. The remaining kinetic energy of the ball is transformed into other forms of energy, such as heat and sound energy.

Overall, the energy transformations in a projectile launcher involve the conversion of potential energy stored in the spring into kinetic energy of the ball, which is then transformed into other forms of energy as the ball moves through the air and interacts with other objects.

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(a) To determine the reading on the thermometer after 4 more minutes, we need to consider the rate at which the temperature changes. In this case, we can assume that the temperature change follows a linear pattern.

After the first minute, the temperature dropped from 18∘C to 10∘C, indicating a decrease of 8 degrees in one minute. Therefore, the rate of temperature change is -8/1 = -8∘C per minute. Applying the same rate, after 4 more minutes, the temperature would decrease by 8∘C per minute for 4 minutes, resulting in a total temperature drop of 8∘C * 4 = 32∘C.

Therefore, the reading on the thermometer after 4 more minutes would be 10∘C - 32∘C = -22∘C.

(b) To find when the thermometer will read -7∘C, we need to determine the time it takes for the temperature to drop from 10∘C to -7∘C.

Using the rate of temperature change we established earlier (-8∘C per minute), we can set up the following equation:

10∘C + (-8∘C/min) * t = -7∘C

Solving for t:

Therefore, the thermometer will read -7∘C approximately 2.125 minutes after it was taken outdoors.

Unfortunately, the second part of your question regarding finding an equation of a curve satisfying dx/dy = 36yx^17 with a y-intercept of 2 seems to have a typographical error. The derivative dx/dy cannot be equal to 36yx^17 since the left-hand side represents the derivative of x with respect to y, while the right-hand side is a function of x only. If you can provide the correct equation or clarify the intended expression, I will be happy to assist you further.

A thermometer, also known as a temperature gauge, is a tool used to measure temperature. The term thermometer comes from the Latin thermo which means heat and meter which means to measure. There are various working principles of the thermometer, the most commonly used is the mercury thermometer.

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The total pressure experienced by the diver at the given depth is 201,880 Pa.

The given parameters:

The total pressure experienced by the diver at the given depth is calculated as follows;

\(P = \rho g h\)

where;

ρ is the density of the liquid (kg/m³)

g is acceleration due to gravity

1.03 g/cm³ = 1,030, kg/m³

P = (1030) x (9.8) x (20)

P = 201,880 N/m²

Thus, the total pressure experienced by the diver at the given depth is 201,880 Pa.

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Black holes are among the oddest and most intriguing celestial bodies. Even light cannot escape their gravitational pull due to their immense density and strength.

Yes, a blackhole might theoretically continue to consume everything in the universe if the matter entered its event horizon.

Nevertheless, as galaxies move apart, space is expanding. And because a portion of the universe will always have escaped, this circumstance will never arise as long as one galaxy is growing away from another galaxy.

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Answer:

D

Explanation:

According to the Newtons third law of motion, the collision between the bumper car and the rider will affect both of them as both the systems have mass and are moving with certain velocities.

Collision is a case where one moving object or person violently collides with another.

The law of interaction or the Newton's third law of motion, says that if one body exerts a force on a second body, the second body exerts a force equal in magnitude and opposite in direction on the first body.

As we know momentum is P = m*v i.e. momentum (P) is directly proportional to the mass and velocity.

Heavier bodies have more mass, therefore have more momentum.

here, the bumper car is the heavy system and hence, it will exerts more impact on the rider.

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Answer:

2. Mathew Maury

Explanation:

2. Mathew Maury

4. Cousteau and Gagnon

Explanation:

they made the first successful scuba in 1942

vf² = vi² + 2.a.d

0 = 26 + 2.(-6.7).d

13.4d = 26

d = 1.94 m

Answer:

mass X velocity

Explanation:

The momentum of a body is the product of its mass and velocity

R(F) = 4F - 160

a. R¹(P) represents the temperature at which a cricket chirps at a rate of P chirps per minute.

b. R(60) refers to the chirping rate of the cricket when the temperature is 60 degrees Fahrenheit, while R¹(60) represents the temperature at which the cricket chirps at a rate of 60 chirps per minute.

The equation R(F) = 4F - 160 represents the relationship between the temperature of the cricket's environment (F) and its chirping rate (R). By plugging in different temperature values, we can determine the corresponding chirping rate.

For example, when we calculate R(60), we find the chirping rate at 60 degrees Fahrenheit.

In this case, R(60) = 4(60) - 160 = 240 - 160 = 80 chirps per minute.

On the other hand, when we calculate R¹(60), we are looking for the temperature at which the cricket chirps at a rate of 60 chirps per minute. Solving the equation 60 = 4F - 160, we find F = 70 degrees Fahrenheit. Therefore, R¹(60) = 70.

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Answer:

heat energy

Explanation:

heat energy

Answer:

c. The magnitude of vertical velocity is at a maximum value.

Explanation:

I think this is correct I'm not entirely sure though

Answer:

Explanation: ns along perpendicular axes are independent and thus can be analyzed separately. This fact was discussed in Kinematics in Two Dimensions: An Introduction, where vertical and horizontal motions were seen to be independent. The key to analyzing two-dimensional projectile motion is to break it into two motions, one along the horizontal axis and the other along the vertical. (This choice of axes is the most sensible, because acceleration due to gravity is vertical—thus, there will be no acceleration along the horizontal axis when air resistance is negligible.) As is customary, we call the horizontal axis the x-axis and the vertical axis the y-axis. (Figure) illustrates the notation for displacement, where \mathbf{s} is defined to be the total displacement and \mathbf{x} and \mathbf{y} are its components along the horizontal and vertical axes, respectively. The magnitudes of these vectors are s, x, and y. (Note that in the last section we used the notation \mathbf{A} to represent a vector with components {\mathbf{A}}_{x} and {\mathbf{A}}_{y}. If we continued this format, we would call displacement \mathbf{s} with components {\mathbf{s}}_{x} and {\mathbf{s}}_{y}. However, to simplify the notation, we will simply represent the component vectors as \mathbf{x} and \mathbf{y}.)

Review of Kinematic Equations (constant a)

x={x}_{0}+\stackrel{-}{v}t

\stackrel{-}{v}=\frac{{v}_{0}+v}{2}

v={v}_{0}+\text{at}

x={x}_{0}+{v}_{0}t+\frac{1}{2}{\text{at}}^{2}

{v}^{2}={v}_{0}^{2}+2a\left(x-{x}_{0}\right)\text{.}

The total displacement \mathbf{s} of a soccer ball at a point along its path. The vector \mathbf{s} has components \mathbf{x} and \mathbf{y} along the horizontal and vertical axes. Its magnitude is s, and it makes an angle \theta with the horizontal.

A soccer player is kicking a soccer ball. The ball travels in a projectile motion and reaches a point whose vertical distance is y and horizontal distance is x. The displacement between the kicking point and the final point is s. The angle made by this displacement vector with x axis is theta.

Given these assumptions, the following steps are then used to analyze projectile motion:

Step 1.Resolve or break the motion into horizontal and vertical components along the x- and y-axes. These axes are perpendicular, so {A}_{x}=A\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {A}_{y}=A\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\theta are used. The magnitude of the components of displacement \mathbf{s} along these axes are x and \mathrm{y.} The magnitudes of the components of the velocity \mathbf{v} are {v}_{x}=v\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {v}_{y}=v\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\mathrm{\theta ,} where v is the magnitude of the velocity and \theta is its direction, as shown in (Figure). Initial values are denoted with a subscript 0, as usual.

Step 2.Treat the motion as two independent one-dimensional motions, one horizontal and the other vertical. The kinematic equations for horizontal and vertical motion take the following forms:

\text{Horizontal Motion}\left({a}_{x}=0\right)

x={x}_{0}+{v}_{x}t

{v}_{x}={v}_{0x}={v}_{x}=\text{velocity is a constant.}

\text{Vertical Motion}\left(\text{assuming positive is up}\phantom{\rule{0.25em}{0ex}}{a}_{y}=-g=-9.\text{80}{\text{m/s}}^{2}\right)

y={y}_{0}+\frac{1}{2}\left({v}_{0y}+{v}_{y}\right)t

{v}_{y}={v}_{0y}-\text{gt}

y={y}_{0}+{v}_{0y}t-\frac{1}{2}{\mathrm{gt}}^{2}

{v}_{y}^{2}={v}_{0y}^{2}-2g\left(y-{y}_{0}\right)\text{.}

Step 3. Solve for the unknowns in the two separate motions—one horizontal and one vertical. Note that the only common variable between the motions is time t. The problem solving procedures here are the same as for one-dimensional kinematics and are illustrated in the solved examples below.

Step 4.Recombine the two motions to find the total displacement\mathbf{\text{s}} and velocity \mathbf{\text{v}}. Because the x – and y -motions are perpendicular, we determine these vectors by using the techniques outlined in the Vector Addition and Subtraction: Analytical Methods and employing A=\sqrt{{A}_{x}^{2}+{A}_{y}^{2}} and \theta ={\text{tan}}^{-1}\left({A}_{y}/{A}_{x}\right) in the following form, where \theta is the direction of the displacement \mathbf{s} and {\theta }_{v} is the direction of the velocity \mathbf{v}:

Total displacement and velocity

s=\sqrt{{x}^{2}+{y}^{2}}

\theta ={\text{tan}}^{-1}\left(y/x\right)

v=\sqrt{{v}_{x}^{2}+{v}_{y}^{2}}

{\theta }_{v}={\text{tan}}^{-1}\left({v}_{y}/{v}_{x}\right)\text{.}

(a)

Answer: Not enough information but probably Mr. Szarzak does more work

Explanation: Mr. Szarzak probably does more work because W is defined as...

W = Fdcos(Ф)

where F is the force, d is displacement and Ф represents the angle of the displacement and force vector. Both are lifting the same direction so the angle does no matter. Looking at dispalcement and both Mr. Szarzak and Mrs. Szarzak lift the weight with a constant velocity, they both are applying the same force as net force is 0 but Mr. Szarzak is taller so he pulls it up more distance and thus applies more work. However, it is not enough information because force plays a role. If the force applied by Mrs. Szarzak is a decent amount greater than Mrs. Szarzak than Mrs. Szarzak will do more work so it is not enough information.

Answer:

magnetic force

Explanation:

when some one gets charged up by maybe static eletricity the person will sustain the energy and the energy will make a force field around the person which can and will attract paper and he will be attractive

Explanation:

Examples for effect of force - example

1) Can change the state of an object(rest to motion/ motion to rest):For example, pushing a heavy stone in order to move it. 2) May change the speed of an object if it is already moving. ... 3) May change the direction of motion of an object

Answer:

Michael is heavier.

Explanation:

If Michael is 104 pounds, that is equal to 47 kg.

Erica is 44 kg which is 97 pounds.

104 is greater than 97, and 47 is greater than 44.

Answer:

Michael weighs more

Explanation:

First, you need to convert either kilograms into pounds or pounds into kilograms. For this problem, I will convert kilograms into pounds.

Multiply 44kg by 2.2 pounds to find how many pounds are in 44 kg

44 x 2.2 = 96.8 pounds

Michael - 104 pounds

Erica - 96.8 pounds

Michael is heavier than Erica because he weighs 7.2 pounds more than her.

(pounds to kilograms - 104/2.2 = 47.3 kg   Michael weighs 7.3 kilograms more than Erica)

Answer:

Mass and volume

Explanation:

Answer:

They describe how (1) planets move in elliptical orbits with the Sun as a focus, (2) a planet covers the same area of space in the same amount of time no matter where it is in its orbit, and (3) a planet's orbital period is proportional to the size of its orbit (its semi-major axis).

Explanation:

Answer:

Three laws are written in detail below.

Explanation:

Kepler's three laws of planetary motion are as follows:

Law 1: The path of the planets around the sun is elliptical in shape, with the center of the sun being located at one of the foci, we call this law as The Law of Ellipses as well.

Law 2: An imaginary line drawn from the center of the sun to the center of the planet will be sweeping out equal areas in equal intervals of time. And this is also known as The Law of Equal Areas.

Law 3: The ratio of the squares of the time periods of any two planets is equal to the ratio of the cubes of their average distances from the sun.

\(T^{2}\) \(\alpha R^3\)

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The distance from the base of the cliff to the point on the ground is approximately 4047 ft when rounded to the nearest foot.

To find the distance from the base of the cliff to the point on the ground, you can use the tangent function in trigonometry. Let's denote the distance we want to find as "x".

We know the angle of depression is 7 degrees and the height of the cliff is 498 ft.

The tangent function is given by tan(θ) = opposite/adjacent, where θ is the angle, the opposite side is the height of the cliff, and the adjacent side is the distance we want to find (x).

Therefore, we can write the equation: tan(7°) = 498/x.

To find the value of x, we can rearrange the equation: x = 498/tan(7°).

Now, we can plug in the angle and calculate the distance:

x = 498/tan(7°) ≈ 4046.56 ft

Therefore, the distance from the base of the cliff to the point on the ground is approximately 4047 ft when rounded to the nearest foot.

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The complete question is:

An observer at the top of a 498 ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 7 degrees. What is the distance from the base of the cliff to the point on the ground? Round to the nearest foot.

True. Most astronomers believe that the demise of the dinosaurs 65 million years ago was caused by a large asteroid impact in the Yucatan Peninsula area, based on extensive evidence from geology, palaeontology, and impact crater studies.

True. The majority of astronomers and scientists support the theory that the extinction event leading to the demise of the dinosaurs 65 million years ago was caused by a large asteroid impact in the Yucatan Peninsula area. Extensive evidence, including the discovery of the Chicxulub impact crater, supports this hypothesis. Geological studies reveal a layer of sediment rich in iridium, a rare element found in higher concentrations in asteroids. Additionally, the discovery of shocked quartz and tektites, along with the global distribution of the debris layer, further supports the impact theory. This widely accepted explanation combines astronomical, geological, and paleontological evidence to attribute the extinction event to a significant asteroid impact.

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Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm maybe

Explanation:

i will use chainsaw to cut a tree and even if that doesn't work I will use axe to make my work easy.

hope this helps you

please mark me brainliest

have a great day :)

Answer:

INPUT force

Explanation:

You are putting force into a machine of levers to have the output of cutting something.

When your hand presses down on scissors, the force is called input force because are applying a force into an object. Thus, option a is correct.

Force is an external agent acting on a body to deform it or to change its state from rest or motion. There are various kinds of force such as magnetic force, nuclear force, gravitational force etc.

Force is a vector quantity thus, it is characterised by a magnitude and direction. According to second law of motion, the force acting on a body is the product of mass and acceleration.

Hence, the force acting on a body is directly proportional to the mass. Greater the mass, greater will be the force needed to accelerate the body. When we press down on an object we are applying an input force to the object.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Nebula evolves into a disc shape with a dense central bulge.

Solid particles come out of the solar nebula.

Grain-sized particles stick together.

Planetesimals and protoplanets form.

Formation of terrestrial planets.

Late stage bombardment.

The process of the solar system's formation is thought to have occurred in the following chronological order:

Nebula evolves into a disc shape with a dense central bulge: The initial stage involves the collapse of a massive cloud of gas and dust, known as a nebula, under the influence of gravity. As it collapses, the nebula takes on a flattened disc shape with a dense central bulge.

Solid particles come out of the solar nebula: Within the flattened disc of the nebula, solid particles, including dust and ice, begin to condense and coalesce.

Grain-sized particles stick together: The solid particles continue to collide and stick together, forming larger clumps and eventually grain-sized particles.

Planetesimals and protoplanets form: Through further collisions and accretion, the grain-sized particles gather to form larger bodies called planetesimals. These planetesimals continue to grow through additional collisions and accretion, eventually becoming protoplanets.

Formation of terrestrial planets: The protoplanets further accumulate matter and undergo differentiation, leading to the formation of terrestrial planets. Terrestrial planets are characterized by their rocky composition and relatively small size compared to gas giants.

Late stage bombardment: During the late stages of the solar system's formation, there was a period of intense bombardment known as the Late Heavy Bombardment. This period involved a significant amount of impacts from leftover planetesimals and other celestial bodies, causing widespread cratering on the surfaces of the planets and moons.

It is important to note that the precise details of the solar system's formation are still being studied and researched, and our understanding of the process continues to evolve based on new observations and discoveries.

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Answer:

Explanation. analysis, inference, and evaluation.help you to solve your problem as well as by using it you can develop scientific and critical thinking skills among students

Answer:-00=;op

Explanation:poop

Answer:

450 hz X 4 = 1800

Explanation: Speed =

Wavelength (4) X frequency (450)

Im not 100% sure though

After the collision, the two cars stick together. The final velocity of the two cars would be 0.667 meters per second as per the conservation of the momentum after the collision.

Elastic collision: What is it?

It is the kind of collision where both the system's total momentum and kinetic energy are conserved.

As stated in the issue, if the two cars keep together after the collision, we must determine their velocities.

Using the principle of momentum conservation,

The sum of the pre-collision starting momentum of the cars equals the post-collision total final momentum of the cars

1 × 2 + 2 × 0 = ( 1 + 2 ) × V

2 + 0 = 3 × V

V = 2 / 3

V equals 0.6677 meters per second.

As a result, if the two cars remained together after the incident, their combined final speed would be 0.667 meters per second.

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