An equation that can can be used to find the number of sales Luke made this week is; 191 + 16.55x = ¹/₃(573 + 49.65x)
How to Solve Equation Word Problems?
We are told to represent the number of sales as x.
Now, Luke works at a store and earns a fixed amount of $191 plus $16.55 per sale. This is represented as; 191 + 16.55x
Noah works at a different store and earns a fixed amount of $573 plus $49.65 per sale. This is represented as; 573 + 49.65x
We are told that they both made the same number of sales but Luke earned a third of what Noah earned. Thus;
191 + 16.55x = ¹/₃(573 + 49.65x)
An equation that can can be used to find the number of sales Luke made this week is;
191 + 16.55x = ¹/₃(573 + 49.65x)
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Gas Mileage. Based on tests of the Chevrolet Cobalt, engineers have found that the miles per gallon in highway driving are normally distributed, with a mean of 32 MPG and a standard deviation of 3.5 MPG. a) What is the probability that a randomly selected Cobalt gets more than 34 MPG? b) Suppose that 10 Cobalts are randomly selected and the MPG for each car are recorded. What is the probability that the mean MPG exceeds 34 MPG? c) Suppose 20 Cobalts are randomly selected and the MPG for each car are recorded. What is the probability that the mean MPG exceeds 34 MPG?
a) the probability that a randomly selected Cobalt gets more than 34 MPG is approximately 0.7149.
b) the probability that the mean MPG exceeds 34 MPG for a sample of 10 Cobalts is approximately 0.035.
c) the probability that the mean MPG exceeds 34 MPG for a sample of 20 Cobalts is approximately 0.005.
a) To find the probability that a randomly selected Cobalt gets more than 34 MPG, we need to calculate the area under the normal distribution curve to the right of 34 MPG.
Using the z-score formula, we can convert the MPG value to a standard score (z-score) using the formula:
z = (x - μ) / σ,
where x is the given value (34 MPG), μ is the mean (32 MPG), and σ is the standard deviation (3.5 MPG).
Calculating the z-score:
z = (34 - 32) / 3.5 = 0.57
Using a standard normal distribution table or a statistical calculator, we can find the area to the right of the z-score 0.57.
Let's assume the standard normal distribution table gives us a value of 0.2851 for z = 0.57.
Since the total area under the normal curve is 1, the probability of getting more than 34 MPG is:
P(X > 34) = 1 - P(X ≤ 34) = 1 - 0.2851 = 0.7149
Therefore, the probability that a randomly selected Cobalt gets more than 34 MPG is approximately 0.7149.
b) When selecting a sample of 10 Cobalts, the mean MPG of the sample (\(\bar{X}\)) follows a normal distribution with the same mean (32 MPG) and a standard deviation (σ) equal to the population standard deviation (3.5 MPG) divided by the square root of the sample size (√10).
σ( \(\bar{X}\) ) = σ / √n = 3.5 / √10 ≈ 1.107
We want to find the probability that the mean MPG exceeds 34 MPG for the sample of 10 Cobalts. In other words, we need to find P(\(\bar{X}\) > 34).
We can again convert the value of 34 MPG to a z-score:
z = (34 - 32) / 1.107 ≈ 1.805
Using a standard normal distribution table or a statistical calculator, we find the area to the right of the z-score 1.805.
Let's assume the standard normal distribution table gives us a value of 0.035 for z = 1.805.
Therefore, the probability that the mean MPG exceeds 34 MPG for a sample of 10 Cobalts is approximately 0.035.
c) When selecting a sample of 20 Cobalts, the mean MPG of the sample (\(\bar{X}\)) follows a normal distribution with the same mean (32 MPG) and a standard deviation (σ) equal to the population standard deviation (3.5 MPG) divided by the square root of the sample size (√20).
σ( \(\bar{X}\) ) = σ / √n = 3.5 / √20 ≈ 0.78
We want to find the probability that the mean MPG exceeds 34 MPG for the sample of 20 Cobalts. In other words, we need to find P(\(\bar{X}\) > 34).
Similarly, we can convert the value of 34 MPG to a z-score:
z = (34 - 32) / 0.78 ≈ 2.564
Using a standard normal distribution table or a statistical calculator, we find the area to the right of the z-score 2.564.
Assuming the standard normal distribution table gives us a value of 0.005 for z = 2.564.
Therefore, the probability that the mean MPG exceeds 34 MPG for a sample of 20 Cobalts is approximately 0.005.
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9x ≥ 3
What is the answer?
Answer:
Divide each term by
9
and simplify.
Exact Form:
x
=
1
3
Decimal Form:
x
=
0.
¯
3
Step-by-step explanation:
x ≥ 1/3 is the solution for the given inequality.
To solve the inequality 9x ≥ 3, we need to isolate the variable x.
Dividing both sides of the inequality by 9 (since 9 is a positive number), we get:
x ≥ 3/9
Simplifying the right side of the inequality:
x ≥ 1/3
Therefore, the solution to the inequality 9x ≥ 3 is x ≥ 1/3. This means that any value of x that is greater than or equal to 1/3 will satisfy the inequality.
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One year, the population of a city was 117,000. Several years later it was 136,890. Find the percent increase.
The percent increase in population of the city is 17%.
A percentage in mathematics is a quantity or ratio that is stated as a fraction of 100 (from the Latin per centum, "by a hundred"). A percentage lacks dimensions and has no associated unit of measurement.
For instance, 45% (written as "forty-five percent") equates to the fraction \(\frac{45}{100}\) .
The percentage increase is calculated by the ratio of the increase to the original value. So to calculate the percent increase in the population of a city we have to find the ratio of the increase in population to the original population.
The population of the city is given as 117,000 .
The population increased to 136890.
Increase in population=136890-117000=19890
percentage increase in population
\(=\frac{19890}{117000} \times 100\%\)
= 0.17×100%
=17%
The percent increase in the population of the city is 17%.
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A spinner has 4 blue sections, 6 red sections
and 2 green sections. It is spun 24 times.
For numbers 2a - 2c, circle YES or NO to
indicate whether you would expect the
spinner to land on the given color the
number of times stated.
2a. 8 times on blue
YES
NO
2b. 18 times on red
YES
NO
2c. 4 times on green
YES
NO
Answer:
2a.) 8 times on blue. 2b.) 18 times on red. 2c. ) 4 times on green.
Step-by-step explanation) the answer for 8 times on blue. is yes The answer for 18 times on red. Is yes. The answer for 4 times on green. Is no
f(x)=x^3-7x^2+25x-175 and f(7)=0
If we know that f(7) = 0, we can say that:
x - 7 is a factor of the function f(x).
This is because when we substitute x = 7 into the function, we get:
f(7) = 7^3 - 7(7)^2 + 25(7) - 175 = 0
This means that (x - 7) is one of the factors of the function.
Now we can use polynomial division or synthetic division to find the other factors. If we divide the function f(x) by (x - 7), we obtain:
x^2 - 4x + 25
Therefore, we can say that:
f(x) = (x - 7)(x^2 - 4x + 25)
The quadratic term, x^2 - 4x + 25, has no real roots because the discriminant is negative. Therefore, we can write the factorization of f(x) in terms of complex numbers as:
f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)
Thus, the complete factorization of f(x) is:
f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)
Si nous savons que f(7) = 0 alors,
x - 7 est un facteur de la fonction f(x).
on substitue x = 7 dans la fonction
f(7) = 7^3 - 7(7)^2 + 25(7) - 175 = 0
donc (x - 7) est l’un des facteurs de la fonction.
Maintenant, on utilise division polynomiale ou la division synthétique pour avoir les autres facteurs. Si on divise la fonction f(x) par (x - 7), on obtient:
x^2 - 4x + 25
Du coup peut dire que :
f(x) = (x - 7)(x^2 - 4x + 25)
Le terme quadratique, x^2 - 4x + 25, n’a pas de racines réelles car le discriminant est négatif. Par conséquent, nous pouvons écrire la factorisation de f(x) en termes de nombres complexes comme:
f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)
la factorisation complète de f(x) est:
f(x) = (x - 7)(x - 2 + 5i)(x - 2 - 5i)
Complete the following statements.
Provided that line AB and line CD are parallel, DNM and BME are congruent because they are .
Answer:
Step-by-step explanation:
because interior angles are equal with parallel lines
Ten samples of size four were taken from a process, and their weights measured. The sample averages and sample ranges are in the following table. Construct and plot an x-bar and R-chart using these data. Is the process in control?
Sample
Mean
Range
1
20.01
0.45
2
19.98
0.67
3
20.25
0.30
4
19.90
0.30
5
20.35
0.36
6
19.23
0.49
7
20.01
0.53
8
19.98
0.40
9
20.56
0.95
10
19.97
0.79
An x-bar and R-chart were constructed using the given data. The x-bar chart displays the sample averages, while the R-chart shows the sample ranges. By analyzing these charts, we can determine if the process is in control.
To construct the x-bar and R-charts, we use the sample averages and sample ranges provided in the table. The x-bar chart helps us monitor the central tendency of the process, while the R-chart monitors the variability or dispersion within the samples.
Plotting the x-bar chart:
Calculate the overall mean (x-double bar) by averaging all the sample averages.
Calculate the average range (R-bar) by averaging all the sample ranges.
Calculate the control limits for the x-bar chart using the formulas: Upper control limit (UCL) = x-double bar + A2 * R-bar, Lower control limit (LCL) = x-double bar - A2 * R-bar, where A2 is a constant factor depending on the sample size.
Plot the sample averages on the x-bar chart along with the control limits.
Plotting the R-chart:
Calculate the control limits for the R-chart using the formulas: UCL = D4 * R-bar, LCL = D3 * R-bar, where D3 and D4 are constant factors depending on the sample size.
Plot the sample ranges on the R-chart along with the control limits.
By examining the x-bar and R-charts, we can assess whether the process is in control. If the data points fall within the control limits, with no specific patterns or trends, the process is considered in control. If any data points fall outside the control limits or show non-random patterns, it suggests the process is out of control and further investigation is required.
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THIS QUESTION IS INCOMPLETE HERE IS THE GENERAL SOLUTION.
a solid cube of side length 11 is removed from each corner of a solid cube of side length 33. how many edges does the remaining solid have?
Answer:
After taking cubes from each corner,no edge will
If the atmospheric pressure is 100000pa, what force does the atmospheric exert on the side of a wall measuring 10m by 2m
If the atmospheric pressure is 100000Pa, the force the atmosphere exerts on the side of a wall measuring 10m by 2m is 2 x 10 x 100000 = 2,000,000 N.
The formula for calculating the force is Force = Pressure x Area.
Here, the pressure is given to be 100000Pa, and the area is 10m x 2m, which gives us a value of 20m².
So, we can say that the atmospheric pressure exerts a force of 2,000,000 N on the side of the wall with a measurement of 10m by 2m.
The formula to calculate the force exerted by atmospheric pressure is F = P x A,
Where F is force, P is pressure, and A is area.
The atmospheric pressure is 100000 Pa, and the side of the wall has dimensions of 10m x 2m.
Hence, the area of the wall is 10 x 2 = 20 square meters.
Therefore, the force exerted by the atmosphere on the side of the wall is calculated as
2 x 10 x 100000 = 2,000,000 N.
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please and thank you help with math!!
Answer:none of these
Step-by-step explanation:
Given b(x) - 1X+4. what is b(-10)?
-10
-6
6
14
Answer:
D. 1×10⁻⁸ M
Explanation:
[H⁺] [OH⁻] = 10⁻¹⁴
(1×10⁻⁶) [OH⁻] = 10⁻¹⁴
[OH⁻] = 1×10⁻⁸
-(x+3) = 2x-6 what is x
Answer:
x=1
Step-by-step explanation:
So, first you make sure to multiply the parenthesis by the negative so then it would be,
-x-3=2x-6
Then you add the -3 from the right to the other side
so, -x=2x-3
Then you want all the X variables to one side so you subtract the 2x to both sides.
so, -3x=-3
divide both by -3
x=1
hi everyone freeeeeesss
Answer:
heyyyyyyyyyyyyy
Step-by-step explanation:
Hope you had a good day
Which of the following statements is false?
Answer:
c
Step-by-step explanation:
AB and CD are opposite sides of quadrilateral.
Find the equation of a line passing through the given point and parallel to the given equation. Write you answer in slope-intercept form.
(-2,4) and y= -x + 3
The equation of a line passing through the given point and parallel to the given equation is y = -x + 2
Equation of a lineThe equation of a line in slope-intercept form is expressed as y = mx + b
where
m is the slope
b is the intercept
The equation in point-slope form is expressed as y - y1 =m(x - x1)
Given
Slope = -1
Point = (-2, 4)
Substitute
y - 4 =-1(x - (-2))
y - 4 = -(x+2)
y - 4 = -x - 2
y = -x - 2+ 4
y = -x + 2
Hence the equation of a line passing through the given point and parallel to the given equation is y = -x + 2
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an hyperboloid is a 3d shape whose cross sections are hyperbolas. a nuclear cooling tower is in the shape of a portion of a hyperboloid. a cross section of the cooling tower can be modeled by the hyperbola shown below, centered at the origin and opening left/right. if the smallest diameter of the cooling tower is 180 m and the diameter is 195 m at its highest point, 80 m above, write the equation of the hyperbola.
The equation of the hyperbola for the cross section of the cooling tower is x²/8100 - y²/9506.25 = 1.
We must take into account its characteristics in order to formulate the hyperbola's equation for the cooling tower's cross section.
Since the origin serves as the hyperbola's centre, its coordinates are (0, 0).
The left/right opening of the hyperbola indicates that the primary axis is horizontal.
The cooling tower's smallest diameter is 180 metres, which is the same length as the minor axis.
The primary axis' 195 m length and the diameter at its highest point are matched.
The hyperbola's highest point is 80 metres above the centre.
These characteristics allow us to write the hyperbola's equation in standard form:
(x - h)²/a² - (y - k)²/b² = 1
Where (h, k) represents the center of the hyperbola.
Substituting the given values:
Center: (h, k) = (0, 0)
Minor axis: 2a = 180 m, so a = 90 m
Major axis: 2b = 195 m, so b = 97.5 m
Vertical shift: c = 80 m
Now we can write the equation of the hyperbola:
x²/90² - y²/97.5² = 1
Simplifying, we have:
x²/8100 - y²/9506.25 = 1
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Carlos bought 17 boxes of cereal. This is 20% of the total boxes at the store. In order to find the total number of boxes at the store, what do you need to find?
A) the part
B) the whole
C) the percent
D) benchmark percent
Answer:
The whole
Step-by-step explanation:
If the part is 20% then you already have a part of a whole, now you need to find the entire thing
On a coordinate plane, point B is at (1, negative 1). Point B has coordinate B(1, –1). What is the coordinate of B' under a scale factor of 3? (1, –1) (3, –3) (–2, 2) (–6, 6)
Answer:
(3,-3)
Step-by-step explanation:
If a coordinate (x, y) is dilated by a factor k, the resulting coordinate will be (kx, ky)
Given the coordinate (1, -1), if dilated by a factor of 3, the resulting coordinate will be (3(1), 3(-1)) = (3, -3)
Hence the required coordinate will be (3,-3)
Answer:
b 3 -3
Step-by-step explanation:
have a good day
PLEASE HELP An equation in the form y = mx + b is in standard form. True False
Answer: False!
This equation is in slope - intercept form, which is used to calculate and graph a line, and/or find the y - intercept and slope of a line. The standard form would be the equation before it was converted into slope - intercept form.
Hope this helps!
Answer:
False
Step-by-step explanation:
The y=mx+b form is called the slope-intercept form.
● m is the slope
● b is the y-intercept
● x is the variable (the input)
● y is the output
I have a problem in math. I have to figure out how to tell their similar through scale factor, to prove their similar, I don't know what that is, I'm stuck. Then I have to explain why c = 60 degrees (see image).
Answer:
see explanation
Step-by-step explanation:
If the ratios of the 3 pairs of corresponding sides of the 2 triangles are equal , then the triangles are similar (SSS postulate )
the3 ratios of the 2 triangles , left to right are all equal to
\(\frac{3}{4}\)
Then the triangles are similar by the SSS postulate
the corresponding angles of similar triangles are congruent, then
∠ c = 60°
Also both triangles have 3 congruent sides and are therefore equilateral triangles with all angles equal to 60°, so
c = 60°
The p-value is _____ or less if the chi-square statistic is 2.71 or more.
Without the degrees of freedom, we cannot provide a specific p-value. If the chi-square statistic is 2.71 or more, the p-value will be equal to or less than the value corresponding to 2.71 in the chi-square distribution table for the given degrees of freedom.
1. The chi-square statistic is a measure of the difference between observed and expected frequencies in a contingency table. When the observed frequencies are similar to the expected frequencies, the chi-square statistic is low. When they are different, the chi-square statistic is high.
2. The p-value is a probability that indicates how likely it is to observe a chi-square statistic as extreme as the one obtained, assuming the null hypothesis (i.e., no association between the variables) is true. A lower p-value means there is stronger evidence against the null hypothesis, suggesting an association between the variables.
3. To determine the p-value corresponding to a chi-square statistic of 2.71, you would look up the value in a chi-square distribution table or use statistical software. The p-value depends on the degrees of freedom, which is determined by the size of the contingency table.
Without the degrees of freedom, we cannot provide a specific p-value. However, if the chi-square statistic is 2.71 or more, the p-value will be equal to or less than the value corresponding to 2.71 in the chi-square distribution table for the given degrees of freedom.
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A population has a mean of
= 50 and a standard deviation of
= 10.
A) If 3 points were added to every score in the population, what would be the new values for the mean and standard deviation?
B) If every score in the population were multiplied by 2, then what would be the new values for the mean and standard deviation?
A) The new values for the mean and standard deviation, after adding 3 points to every score, would be a mean of 53 and a standard deviation of 10. B) The new values for the mean and standard deviation, after multiplying every score by 2, would be a mean of 100 and a standard deviation of 20.
A) Adding 3 points to every score in the population would result in a shift of the entire distribution. The new mean would be the original mean plus 3, so the new mean would be 50 + 3 = 53. The standard deviation would remain the same since it measures the spread of the data relative to the mean. Therefore, the new standard deviation would still be 10.
B) Multiplying every score in the population by 2 would affect both the mean and the standard deviation. The new mean would be the original mean multiplied by 2, so the new mean would be 50 * 2 = 100. The new standard deviation would also be multiplied by 2 since it measures the spread of the data relative to the mean. Therefore, the new standard deviation would be 10 * 2 = 20.
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Answer the following question in 3-4 complete sentences. Name the two rivers that run through the fertile crescent. How were the rivers both positive and negative to societies of the fertile crescent?.
The two number of rivers that run through the Fertile Crescent are the Tigris and the Euphrates.
These rivers were positive for societies in the Fertile Crescent because they provided a reliable number of source of water for irrigation and drinking, and their associated river basins provided a variety of resources including fish, plants, and minerals. However, the rivers were also negative for societies in the Fertile Crescent because they could be unpredictable and cause flooding and erosion, which could destroy homes and crops.
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Answer:
The two rivers that run through the Fertile Crescent are the Euphrates and the Tigris. The rivers are the reason that the region is referred to as “fertile”. A fertile region is an area that produces healthy, sustaining vegetation. The negative aspect of the rivers was that flooding was common. Flooding could wipe out an entire years crop.
Step-by-step explanation:
pictures below
What is the difference between the yearly wages of the highest paying job and lowest paying job, assuming Araceli will be paid for working 40 hours a week, 52 weeks a year
Answer:
Is there a picture?? I need a picture
Step-by-step explanation:
the taylor series for a function f about x=1 is given by
The Taylor series for a function f about x=1 is an infinite sum that represents the function using its derivatives at x=1. It starts with the value of the function at x=1 and includes terms involving higher derivatives multiplied by powers of (x-1) divided by factorials. It allows us to approximate the function near x=1 using a polynomial.
1. The first term, f(1), represents the value of the function at x=1.
2. The subsequent terms involve the derivatives of the function at x=1. The second term, f'(1)(x-1), is the first derivative of f at x=1 multiplied by (x-1).
3. Each subsequent term involves higher derivatives of f at x=1, with each derivative being multiplied by (x-1) raised to a power and divided by the corresponding factorial.
The Taylor series is a way to represent a function as an infinite sum of terms derived from its derivatives at a specific point. In this case, the Taylor series for function f about x=1 is given by f(x) = f(1) + f'(1)(x-1) + f''(1)(x-1)^2/2! + f'''(1)(x-1)^3/3! + ...
Each term involves a derivative of f evaluated at x=1, multiplied by (x-1) raised to a power and divided by the corresponding factorial. By including more terms in the series, we can approximate the function better near x=1 using a polynomial.
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1. Total labor wages of $112,000 were paid in cash. Of this amount, $101,000 was for direct labor and the remainder was for indirect labor.
Transaction General Journal Debit Credit
a. 2. Depreciation of $175,000 was incurred on factory equipment.
Transaction General Journal Debit Credit
a.
The journal entries for the given transactions are:
1. Direct Labor Expense (Debit) - $101,000, Indirect Labor Expense (Debit) - $11,000, Cash (Credit) - $112,000
2. Depreciation Expense (Debit) - $175,000, Accumulated Depreciation (Credit) - $175,000
3. Work-in-Process Inventory (Debit) - $240,000, Manufacturing Overhead (Credit) - $240,000
4. Finished Goods Inventory (Debit) - $520,000, Work-in-Process Inventory (Credit) - $520,000
1. To determine the journal entry for total labor wages of $112,000 paid in cash, with $101,000 for direct labor and the remainder for indirect labor, follow these steps:Step 1: Debit the direct labor and indirect labor accounts.
Direct Labor Expense: Debit $101,000
Indirect Labor Expense: Debit $11,000 (112,000 - 101,000)
Step 2: Credit the cash account.
Cash: Credit $112,000
The journal entry would be:
Direct Labor Expense (Debit) - $101,000
Indirect Labor Expense (Debit) - $11,000
Cash (Credit) - $112,000
2. To record the depreciation of $175,000 incurred on factory equipment:Step 1: Debit the depreciation expense account.
Depreciation Expense: Debit $175,000
Step 2: Credit the accumulated depreciation account.
Accumulated Depreciation: Credit $175,000
The journal entry would be:
Depreciation Expense (Debit) - $175,000
Accumulated Depreciation (Credit) - $175,000
3. To apply manufacturing overhead cost to production based on $8 per machine-hour with a total of 30,000 machine-hours recorded for October:Step 1: Calculate the total manufacturing overhead.
Total Manufacturing Overhead = $8 per machine-hour * 30,000 machine-hours = $240,000
Step 2: Debit the work-in-process inventory account.
Work-in-Process Inventory: Debit $240,000
Step 3: Credit the manufacturing overhead account.
Manufacturing Overhead: Credit $240,000
The journal entry would be:
Work-in-Process Inventory (Debit) - $240,000
Manufacturing Overhead (Credit) - $240,000
4. To transfer jobs costing $520,000 according to their job cost sheets from Work-in-Process to Finished Goods during October:Step 1: Debit the finished goods inventory account.
Finished Goods Inventory: Debit $520,000
Step 2: Credit the work-in-process inventory account.
Work-in-Process Inventory: Credit $520,000
The journal entry would be:
Finished Goods Inventory (Debit) - $520,000
Work-in-Process Inventory (Credit) - $520,000
Note: The question is incomplete. The complete question probably is: Determine the journal entry (debit and credit) for the following transaction: 1. Total labor wages of $112,000 were paid in cash. Of this amount, $101,000 was for direct labor and the remainder was for indirect labor. 2. Depreciation of $175,000 was incurred on factory equipment. 3. A company applies manufacturing overhead cost to production on the basis of $8 per machine-hour. A total of 30,000 machine-hours were recorded for October. 4. Jobs costing $520,000 according to their job cost sheets were completed during October and transferred to Finished Goods.
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The domain of a function h(x) is x > 3, and the range is y2-2 What are the domain and range of its inverse function, h-'(x)?
Answer:what’s the answer plz
Step-by-step explanation:
what is the answer in 6 - (-7)
Answer:
13
Step-by-step explanation:
Which expression is rational? A. 4.121221222… B. square root of 36 C. square root of 21 D. 1.192744502…
Answer: 2
Step-by-step explanation:
Answer:
ITS B¡¡
Step-by-step explanation:
please help, i don’t know how to work this out!!
Answer:
40 degrees
Step-by-step explanation:
so, a triangle is 180 degrees. you know that one angle is 60 degrees.
180= 60+ 2x + x
this is the equation of the triangle
120=3x
simplify
40=x
x= 40 degrees
hope this helps :)