Write the charge balance for an aqueous solution of arsenic acid, H3AsO4, in which the acid can dissociate to H2AsO24 , HAsO24 2, and AsO34 2. Look up the structure of arsenic acid in Appendix G and write the structure of HAsO24 2.

Answer:

The pencil is 8.268 inches

Answer: you have to talk to someone who wont mind wanting to wanting to like you a lot like that.

Explanation:  I wish I could be able to talk to someone who would want to get to like me like that, so its a very relatable situation.

Answer:

-4

Explanation:

The overall negative charge in the formula Ti*O2 which contains 2 oxide ions, each with a -2 charge, is -4.

The total negative charge can be calculated by adding up the charges of all the oxide ions:

2 oxide ions x -2 charge/ion = -4

So, the overall negative charge in the formula Ti*O2 is -4.

Structural isomers are molecules with the same molecular formula but with different structural formulae. This means that they have the same number and types of atoms, but they are arranged differently. The following two organic compounds are structural isomers of each other.

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Marlon can conclude that the cell belongs to the Kingdom Protista if he observes that the paramecium has a nucleus.

The presence of a nucleus is a characteristic feature of eukaryotic cells, which are found in Protists, Fungi, Plants, and Animals. Therefore, if Marlon observes that the paramecium has a nucleus, he can conclude that the cell belongs to the Kingdom Protista, which includes unicellular eukaryotic organisms.

The presence of a nucleus is one of the defining features of eukaryotic cells, which are found in Protists, Fungi, Plants, and Animals. The Protista Kingdom includes unicellular organisms that have a nucleus and other membrane-bound organelles.

However, he would need to observe other features of the cell to further classify it into a specific group or species within the Protista Kingdom.

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Answer/Explanation: Oxygen becomes liquid at -183°C.

Liquid nitrogen has a lower boiling point at −196 °C (77 K) than oxygen's −183 °C (90 K), and vessels containing liquid nitrogen can condense oxygen from air.

Answer:

Read Below

Explanation:

Electrolysis is not possible with solid lead (II) bromide. This is because the ions are held in a three-dimensional lattice, unable to move freely to the electrodes. Melting enables the ions to become mobile and to travel to the respective electrodes.

The bulb won't glow when the electrodes are embedded in solid lead bromide.  The bulb will glow when the material surrounding the electrodes is molten lead bromide. When an ionic compound is in the molten (liquid) form the positive and negative ions are free to move around.

Hopes this Helps :D

Brainiest Please

Answer:

charge

Explanation:

explaining the house

Answer:

a, b and c

Explanation:

To calculate molarity the number of moles and volume in dm3 is needed. So with the mass and molar mass the number of moles can be gotten and hence the molarity when dividing the number of moles by the volume in dm3.

Answer:

1.20 × 10³ torr

Explanation:

Step 1: Given data

Step 2: Calculate the final pressure of the gas

Considering the constant volume, if we assume the gas behaves ideally, we can calculate its final pressure using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 822 torr × 475 K/325 K = 1.20 × 10³ torr

1. To prepare 0.5 M NiCl₂ solution, dissolve 64.8 g of NiCl₂ in 1 L of water

2. To prepare 0.5 M NiCl₂.6H₂O solution, dissolve 118.8 g of NiCl₂.6H₂O in 1 L of water

1. How to prepare 0.5 M NiCl₂ solution

We'll begin by obtaining the mole of NiCl₂. This can be obatined as follow:

Mole = Molarity x Volume

Mole of NiCl₂ = 0.5 × 1

Mole of NiCl₂ = 0.5 mole

Finally, can obtain the mass of NiCl₂ needed to prepare the solution as follow:

Mass = mole × molar mass

Mass of NiCl₂ = 0.5 × 129.6

Mass of NiCl₂ = 64.8 g

Thus, to prepare 0.5 M NiCl₂, dissolve 64.8 g of NiCl₂ in 1 L of water

2. How to prepare 0.5 M NiCl₂.6H₂O solution

We'll begin by obtaining the mole of NiCl₂.6H₂O This can be obatined as follow:

Mole = Molarity x Volume

Mole of NiCl₂.6H₂O = 0.5 × 1

Mole of NiCl₂.6H₂O = 0.5 mole

Finally, can obtain the mass of NiCl₂.6H₂O needed to prepare the solution as follow:

Mass = mole × molar mass

Mass of NiCl₂ = 0.5 × 237.6

Mass of NiCl₂.6H₂O = 118.8 g

Thus, to prepare 0.5 M NiCl₂.6H₂O dissolve 118.8 g of NiCl₂.6H₂O in 1 L of water

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Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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The stoichiometric table and the rate law for the given elementary liquid phase reaction have been constructed. The rate constant and activation energy have been calculated, and the type of reaction energy has been specified as endothermic.

Stoichiometric table in terms of concentrations:

The stoichiometric table for the given reaction can be constructed as follows:

A + 2B → products

                             A                                B                                products

Feed         0.3*Cf                        0.7*Cf                                       0

Exit              (0.3-0.3X)*C             (0.7-0.7X)*C                                0

Change         -0.3XC                      -0.7XC                                     0

Where:

Cf = Total feed concentration

C = Concentration inside reactor

X = Conversion of A

Rate of reaction of A:

The rate of the reaction can be expressed as:

rA = -1/2 * dCA/dt = k*C^2

where, CA is the concentration of A and k is the rate constant.

Since the reaction is elementary, the rate law is proportional to the concentrations of the reactants raised to their stoichiometric coefficients.

The rate of disappearance of A = rate of appearance of B

rB = -dCB/dt = 2*rA

Therefore, the rate of reaction of A can be expressed as:

rA = (0.7Cf - 0.7C)/V = k*C^2

Substituting values, we get:

rA = (0.710 - 0.70.7X)/5 = k(0.3 - 0.3*X)^2

Calculation of k and E:

The rate constant k can be calculated using the Arrhenius equation:

k = A * exp(-Ea/RT)

where A is the frequency factor, Ea is the activation energy, R is the gas constant and T is the temperature in Kelvin.

Assuming the activation energy is 50 kJ/mol, we can calculate the rate constant at the given temperature of 333 K:

k = 0.00717 * exp(-50000/(8.314*333)) = 0.0001504

The reaction energy can be determined by calculating the activation energy using the rate constant at two different temperatures. Assuming the rate constant at 323 K is 0.000098, we can solve for Ea:

ln(k2/k1) = Ea/R * (1/T1 - 1/T2)

ln(0.000098/0.0001504) = Ea/8.314 * (1/323 - 1/333)

Ea = 43775 J/mol

The positive value of the activation energy indicates that the reaction is endothermic.

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Explanation:

Intermolecular forces are electrostatic in nature and include van der Waals forces and hydrogen bonds. ... The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds.May 20, 2018

Answer:

1. 0.74mol

2. 0.42mol

3. 2.125mol

4. 0.301mol

5. 4.52 × 10^23 particles

Explanation:

Number of moles (n) in a substance can be found using the formula:

mole (n) = mass/molar mass

Using this formula, the following moles are calculated:

1. Molar of Na = 23g/mol

mole = 17/23

mole = 0.74mol

2. Molar mass of Na2SO4 = 23(2) + 32 + 16(4)

= 46 + 32 + 64

= 142g/mol

Mole = 60/142

mole = 0.42mol

3. Molar mass of CO2 = 12 + 16(2)

= 12 + 32

= 44g/mol

mole = 93.5/44

mole = 2.125mol

4. Molar mass of sodium nitrate (NaNO3) = 23 + 14 + 16(3)

= 23 + 14 + 48

= 85g/mol

mole = 25.6/85

mole = 0.301mol

5. Number of particles in one mole of a substance is 6.022 × 10^23 particles. Hence, in 0.75mol of calcium hydroxide (Ca(OH)2, there will be;

0.75mol × 6.02 × 10^23

= 4.515 × 10^23

= 4.52 × 10^23 particles

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

Heat can be transmitted from a test tube to the surroundings by several different mechanisms, including conduction, convection, and radiation.

Conduction is the transfer of heat through a material, from a region of higher temperature to a region of lower temperature. In the case of a test tube, heat can be conducted through the glass walls and into the surrounding air or other materials that the test tube is in contact with.
Convection is the transfer of heat through the movement of fluids or gases. In the case of a test tube, as the contents of the test tube heat up, convection currents can be set up within the liquid or gas, which can transfer heat to the surrounding air or other materials.

Radiation is the transfer of heat through electromagnetic waves, such as infrared radiation. As the test tube and its contents heat up, they will emit some amount of infrared radiation, which can be absorbed by the surrounding air or other materials and contribute to the transfer of heat to the surroundings.
In general, the mechanism of heat transfer that dominates will depend on a variety of factors, such as the specific materials involved, the temperature difference between the test tube and the surroundings, and the rate of heating.

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The value of x​ : 2

Semi-normal Hydrochloric acid solution = 0.5 N = 0.5 M

for titration :

M₁V₁n₁=M₂V₂n₂(1=HCl,2=Na₂CO₃)

\(\tt 0.5\times 20\times 1=M_2\times V_2\times 2\\\\M_2V_2=5~mlmol=5.10^{-3}mol\)

\(\tt MW=\dfrac{mass}{mol}=\dfrac{0.715}{5.10^{-3}}=143~g/mol\)

MW Na₂CO₃.xH₂O=143

MW Na₂CO₃.xH₂O = MW Na₂CO₃+ MW xH₂O = 143

MW Na₂CO₃ = 106 g/mol

MW xH₂O = 18x

Equation :

\(\tt 106+18x=143\\\\18x=37\\\\x=\dfrac{37}{18}=2.056\approx 2\)

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

The answer is "-50.424° C".

Explanation:

Given:

Time = 1 hour

TB=?

Formula:

\(TB= \frac{-T\times P}{m \times c_i}\)

time (T) = 1 hour

             = 3600 second

\(t=(3600 -t_2)\)

Calculating T_B:

\(\to T_B= \frac{-(3600 - t_2) 36.6}{0.250 \times 2090}\\\)

          \(= \frac{-(3600 - 2880) 36.6}{522.6}\\\\= \frac{-(720) 36.6}{522.6}\\\\= \frac{-720 \times 36.6}{522.6}\\\\= \frac{-26352}{522.6}\\\\= -50.424 ^{\circ} C\)

To get the net Ionic equation we must get rid of spectator ions, I.E. the ions that repeat on either side of the equation.

So...!

\(Ni_{2}\)\((aq)^{+}\) + \(SO_{4}(aq)^2-\) + \(2Na(aq)^+\) + \(S_{2} (aq)^{2} -\) → \(2NiS(s)\) + \(2Na(aq)^{+}\) + \(SO_{4}(aq)^{2-}\)

This becomes the following net ionic.

\(Ni_{2}\)\((aq)^{+}\) + \(S_{2} (aq)^{2} -\) → \(2NiS(s)\)

Answer:

1.) 2H2 + O2=2H2O

2.)Cl2 + 2KBr= 2KCl + Br2

4.)C4H12 + 7O2= 6H2O + 4 CO2

Answer:

Voltage is the measure of electric potential energy per unit charge, current is the flow of electric charge through a circuit, and resistance is the property of a material that opposes the flow of electric current.

Ohm's Law relates these three concepts by stating that current is directly proportional to voltage and inversely proportional to resistance.

Hope this helps!

At 40°C, the maximum amount of KNO₃ that can dissolve in 200 g of water is 130 g, but since only 110 g of KCl was added, all the KCl will dissolve, and 71.5 g of KNO₃ will dissolve.

To determine how much KNO₃ will dissolve, we need to compare the amount of KCl that was added to the maximum amount of KNO₃ that can dissolve at the same temperature.

First, we can find the maximum amount of KNO₃ that can dissolve in 200 g of water at 40°C, which is given as 65 g/100 g of water

Maximum amount of KNO₃ that can dissolve

= 65 g/100 g x 200 g

= 130 g

This means that at most, 130 g of KNO₃ can dissolve in 200 g of water at 40°C.

Next, we need to compare the amount of KCl added to the maximum amount of KNO₃ that can dissolve.

The amount of KCl added is 110 g, which is less than the maximum amount of KNO₃ that can dissolve (130 g). Therefore, all of the KCl will dissolve and some of the KNO₃ will dissolve.

To find the amount of KNO₃ that will dissolve, we need to calculate how much KNO₃ would be in 110 g of the solvent (water) if it were saturated with KNO₃

Amount of KNO₃ in 110 g of water

= 65 g/100 g x 110 g

= 71.5 g

This means that 71.5 g of KNO₃ will dissolve in 110 g of water at 40°C.

Therefore, the amount of KNO₃ that will dissolve in the 200 g of water containing 110 g of KCl is 71.5 g.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{2.91 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.04833887...\)

We have the final answer as

Hope this helps you

The formula of the salts are;

CaF2, MgCl2, BaBr2, SrI2.

These salts are created when electrons move from a Group 2 element to a Group 17 element, creating negatively charged anions in Group 17 and positively charged cations in Group 2. The salts are held together by ionic bonds between these ions, which have opposing charges.

Chemical bonds known as ionic bonds are created when two atoms with vastly differing electronegativities come together. One atom, referred to as the cation, loses one or more electrons in an ionic bond, whereas the other atom, referred to as the anion, acquires those electrons.

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Answer:

D

Explanation:

i learned this in elementary

the pH of the aqueous solution is 8.51 with a hydrogen ion concentration of [H+]=3.1×\(10^-9\)M

The pH of the aqueous solution can be calculated using the formula:

pH = -log[H+]

where [H+] is the hydrogen ion concentration of the solution.

Substituting the given value, we get:

pH = -log(3.1×\(10^-9\))

pH = 8.51

An aqueous solution is one in which water serves as the solvent. It is utilised in a variety of applications, including analytical chemistry, biochemistry, and industrial chemistry. It is the most prevalent kind of solution used in chemical reactions. Water serves as both the solvent and the solute in an aqueous solution, where the solute is often a solid, liquid, or gas. Due to its high polarity and capacity to make hydrogen bonds with other molecules, water is an excellent solvent that can dissolve a variety of materials, including polar molecules and ionic compounds. Acid-base reactions, redox reactions, and precipitation reactions are just a few of the numerous chemical processes that take place in aqueous solutions. A variety of variables can have an impact on an aqueous solution's characteristics.

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Answer:

The proportionality constant of the spring is 0.42857 N/cm.

Explanation:

The proportionality constant (k) of a spring is given by the equation: force (F) = k * displacement (x)

k = F / x

Therefore, to find the proportionality constant of the spring, we can divide the force applied (75 N) by the displacement (175 cm)

k = 75 N / 175 cm

k = 0.42857 N/cm

The proportionality constant of the spring is 0.42857 N/cm.