Write fourteen and five hundred sixty-one thousandths as a decimal number.

Answer:

Step-by-step explanation:

Pick two points and calculate the slope (Rise/Run).

I picked (-2,0) and (2,-2)

Rise = (-2 - 0) = -2

Run = (2-(-2)) = 4

Slope (Rise/Run) = -2/4 or -1/2

The line has an intercept of -1  (the "b" in y=mx + b)

So the equation is y = -(1/2)x -1

Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

Algebra is the branch of mathematics that deals with numbers and values which are represented with letters and symbols.

Sometimes, we do not want to mention a particular number, we can represent the number by a letter or a suitable symbol. This approach is algebraic.

For example, d + d = 2d

This is an example of an algebraic expressionns.

Given the algebraic expressions,

\(\frac{1}{2}x + 4 \\ x + 6 - \frac{1}{2}x - 2\)

Substituting 2 for x in the first expression gives:

(1/2 × 2) + 4

1 + 4

5

Substituting 2 for x in the second expression gives:

2 + 6 - (1/2 ×2) - 2

8 - 1 - 2

8 - 3

5

Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

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Answer:

the answer is d

Step-by-step explanation:

edenuity2020. also I just did it

Answer: $4,998

Step-by-step explanation:

34000*1.147

38998-34000=4998

Answer:

it takes 3 hour

Step-by-step explanation:

ypir welcome

Unit analysis is a tool that we can use to convert units. It involves multiplying the original number by a fraction to cancel out units.

We're given:

\(\dfrac{3240\hspace{4}feet}{hour}\)

We also know that:

\(\dfrac{hour}{60\hspace{4}minutes}\)

Multiply the two to cancel out the hour:

\(\dfrac{3240\hspace{4}feet}{hour}\times\dfrac{hour}{60\hspace{4}minutes}\\\\=\dfrac{3240\hspace{4}feet}{60 minutes}\)

Simplify:

\(=\dfrac{54\hspace{4}feet}{minute}\)

\(\dfrac{54\hspace{4}feet}{minute}\)

4K = 120 can be used to find the number of emergency kits K Elise packs. The total number of emergency kits packed by Elsie and her mom are 30.

Here, we are given that Elise puts 4 water bottles into each emergency kit.

Let the number of kits packed = K

Then the total number of bottles packed = 4 × K

= 4K

Also, we are given that Elsie packs a total of 120 bottles.

Thus, we get the following linear equation-

4K = 120

We can use this equation to find the number of emergency kits K Elise packs.

dividing by 4 on both sides, we get

4K/4 = 120/4

K = 30

Hence, the total number of emergency kits packed by Elsie and her mom are 30.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The coefficient of the highest degree term (x^5) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and \(x^{2}\) + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The coefficient of the highest degree term (\(x^{5}\)) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and  + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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Java libraries are built-in functions that contain several classes.

Some advantages of using Java mathematical libraries are:

There are various other advantages of the Java mathematical libraries.

Some examples of the Java mathematical libraries and their usage are:

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Answer:

1345600 meters squared

Step-by-step explanation:

devide the perimeter (4640m) by 4 and you get 1160m for each side of the square now you multiply that by itself to get 1345600 meters squared.

Answer:

Step-by-step explanation:

Square

Solve for area

A≈1.35×106m²

P Perimeter

4640

m a d a d d a P a A

Using the formulas

A=a2

P=4a

Solving forA

A=1

16P2=1

16·46402=1.3456×106m²

We got x = 16.54 by using Pythagorean theorem .

What is the Pythagorean theorem in plain English?

angle of semicircle is always be 90° .

   18² = 7.1² + x²

    324 = 50.41 + x²

     x² = 324 - 50.41

          = 273.59

    x = √ 273.59

    x = 16.54

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Answer:

its c!

Step-by-step explanation:

trust me on this!

Answer:

c

Step-by-step explanation:

the other person

well, we know they won 60% of the games, meaning 100% - 60% = 40%, they lost 40% of the games, and we also know that that number is 12.

\(\begin{array}{ccll} \%&amount\\ \cline{1-2} 40 & 12\\ 60& x \end{array} \implies \cfrac{40}{60}=\cfrac{12}{x}\implies \cfrac{2}{3}=\cfrac{12}{x} \\\\\\ 2x=36\implies x=\cfrac{36}{2}\implies x=18\)

Answer:

q = -1/8

Step-by-step explanation:

You're trying to solve for q
32q+4=0

Subtract 4 both sides
32q=-4

Now Divide -4 by 32 (This means you have to simplify)
-4/32 = -1/8 due to the common factor of 4.

q = -1/8

Answer:

4(8q+1)

Step-by-step explanation:

32q+4

4*8q+4*1

4(8q+1)

Answer: 20π/9 cm²

Step-by-step explanation:

Central angle is given as = 50°

We should note that for a complete circle to be made, it needs 360∘. Therefore, this is 50/360 = 5/36 of the area of a sector.

Area of the sector = 5/36 × πr².

= 5/16 × π × 4²

= 5/36 × π × 16

= 80π/36

= 20π/9 cm²

Dustin walk at the rate of 6 miles per hour.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Dustin can run 2 miles per hour faster than he can walk around the track. If Dustin walks around the track in 20 minutes and runs around the track in 15 minutes.

Let the speed of Dustin walking = x

We know that;

Speed = Distance / Time

For walking;

Speed = Distance / Time

x = Distance / (20/60)

x × 20/60 = Distance

Distance = x/3 miles

For run;

Speed = Distance / Time

⇒ x + 2 = (x/3) / (15/60)

⇒ 3 (x + 2) = 4x

⇒ 3x + 6 = 4x

⇒ 4x - 3x = 6

⇒ x = 6

Thus, Dustin walk at the rate of 6 miles per hour.

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Answer: C. A=[1,3,5,7,9] thats the answer

Step-by-step explanation:

The smallest positive integer n such that t \($\sqrt[4]{56 \cdot n}$\)  is an integer is 686.

We have to find the smallest positive integer n such that \($\sqrt[4]{56 \cdot n}$\) is an integer

To find the smallest positive integer n such that  \($\sqrt[4]{56 \cdot n}$\)   is an integer, we need to determine the factors of 56 and find the smallest value of n that, when multiplied by 56, results in a perfect fourth power.

The prime factorization of 56 is:

56 = 2³ × 7

The prime factors of 56 need to be raised to multiples of 4.

Therefore, we need to determine the smallest value of n that includes additional factors of 2 and 7.

To make the expression a perfect fourth power, we need to raise 2 and 7 to the power of 4, which is 2⁴ × 7⁴

The smallest value of n that satisfies this condition is:

n = 2 × 7³ = 2× 343 = 686

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Answer:

false

Step-by-step explanation:

its not correct

Answer:

yes

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

Answer:

1.5 minutes

Step-by-step explanation:

6 x 1.6 = 9.6

9.6 - 1.5 - 1.3 - 1.5 - 1.7 - 2.1 = 1.5

Kimberly had 2 times as many marshmallows as Chris. After eating 15 each, Kimberly had 3 times as many marshmallows as Chris. Kimberly had 60 marshmallows at first.

Generally, Let's call the number of marshmallows that Kimberly had at first X.

We know that Kimberly had 2 times as many marshmallows as Chris at first, so Chris had X/2 marshmallows.

After eating 15 each, Kimberly had X - 15 marshmallows, and Chris had X/2 - 15 marshmallows.

We also know that Kimberly had 3 times as many marshmallows as Chris after eating 15 each, so

(X - 15) = 3 * (X/2 - 15).

(X - 15) - 3 * (X/2 - 15) = 0

Then, we can simplify the left side of the equation:

X - 15 - 3 * X/2 + 45 = 0

Combining like terms, we get:

-3 * X/2 + X - 15 + 45 = 0

Simplifying further:

-X/2 =-30

X = 60

Therefore, Kimberly had 60 marshmallows at first.

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Here is the final matching of multiplication expressions with their estimated products:

(80)(30) = 2,400

(30)(6) = 180

(30)(5) = 150

(60)(4) = 240

(50)(30) = 1,500

29.3 x 5.9 ≈ 173

81.4 x 32.1 ≈ 2,618

32.9 x 4.81 ≈ 158

46.7 x 31.7 ≈ 1,479

59.3 x 3.57 ≈ 212

Match each multiplication expression on the left with the best estimate of its product on the right:

(80)(30) = 2,400

(30)(6) = 180

(30)(5) = 150

(60)(4) = 240

(50)(30) = 1,500

29.3 x 5.9

81.4 x 32.1

32.9 x 4.81

46.7 x 31.7

59.3 x 3.57

Matching the expressions with their estimated products:

(80)(30) = 2,400

(30)(6) = 180

(30)(5) = 150

(60)(4) = 240

(50)(30) = 1,500

Estimates for the remaining expressions:

29.3 x 5.9 ≈ 173.27

81.4 x 32.1 ≈ 2,612.94

32.9 x 4.81 ≈ 158.05

46.7 x 31.7 ≈ 1,480.39

59.3 x 3.57 ≈ 211.46

Matching the expressions with their estimated products:

(80)(30) = 2,400

(30)(6) = 180

(30)(5) = 150

(60)(4) = 240

(50)(30) = 1,500

29.3 x 5.9 ≈ 173.27

81.4 x 32.1 ≈ 2,612.94

32.9 x 4.81 ≈ 158.05

46.7 x 31.7 ≈ 1,480.39

59.3 x 3.57 ≈ 211.46

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Answer:

the answer is below

Step-by-step explanation:

A. 4.0

B. 4.5

C. 3.5

D. 4.2

Answer:

4

it's not B or C or D so it has to be A

The equation shows that the number of toys that must be bought for them to have equal profit will be 212 toys.

From the information, it should be noted that the equation that can be used to represent the information about Jaclyn company will be:

= 2125 + (49.99 × x)

= 2125 + 49.99x

The equation that can be used to represent the information about Richie company will be:

= (39.95 × x)

= 39.95x

Therefore, we will equate both equations:

2125 + 49.99x = 39.95x

49.99x - 39.95x =2125

10.04x = 2125

x = 212

Therefore, the number of toys that must be bought for them to have equal profit will be 212 toys.

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Answer:

c

Step-by-step explanation:

because on the chart is says 19% under burgers for teachers.

Tell me if it is right.

(a) The 95% confidence interval for the mean of the compressive strength is 4885.1 < μ < 5054.9.

(b) The 95% confidence interval for the mean of compressive strength is 4975.2 < μ < 5012.4.

a) We have to find the 95% confidence interval for the mean of the compressive strength.

we are given

x = sample mean = 4970

n = sample size = 9

σ = population standard deviation = 130

The 95% confidence interval for population mean is

x - Z​​​​​​a/2*(σ/√n) < μ < x + Z​​​​​​a/2*(σ/√n)

For a = 0.05 Z​​​​​​a/2 = Z​​​​​​0.025 = 1.96

4970 - 1.96*(130/√9) < μ < 4970 + 1.96*(130/√9)

4885.1 < μ < 5054.9

Hence, the 95% confidence interval for the mean of the compressive strength is 4885.1 < μ < 5054.9.

b) We have to find the 95% confidence interval for the mean of the compressive strength.

Since the population's standard deviation is unknown in this instance, the population mean's t confidence interval is used.

From the data n = 9

X = sample mean = 4993.8

s = sample standard deviation = 24.2

For a= 0.05 and degree of freedom = n -1 = 8

t​​​​​​a/2 , n-1 = t​​​​​​0.025,8 = 2.306

x - t​​​​​​a/2*(s/√n) < μ < x + t​​​​​​a/2*(s/√n)

4993.8 - 2.306*(24.2/√9) < μ < 4993.8 + 2.306*(24.2/√9)

4975.2 < μ < 5012.4

Hence, the 95% confidence interval for the mean of compressive strength is 4975.2 < μ < 5012.4.

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The complete question is:

A new cure has been developed for a certain type of cement that should change its mean compressive strength.

a) It is known that the standard deviation of the compressive strength is 130 kg/cm^2 and that we may assume that it follows a normal distribution. 9 chunks of cement have been tested and the observed sample mean is X = 4970. Find the 95% confidence interval for the mean of the compressive strength.

b) Now, assume that we do not know the standard deviation of the normal distribution. 9 chunks of cement have been tested, and the measurements are 5001, 4945, 5008, 5018, 4991, 4990, 4968, 5020, 5003. Find the 95% confidence interval for the mean of the compressive strength.

Answer:

B only

Step-by-step explanation:

Triangles A and C are similar, but not congruent to each other. Similar triangles have proportional sides and congruent angles, while congruent triangles have congruent sides and congruent angles.

Therefore, only B is correct

The question is asking for pairs of congruent triangles but lacks key information needed to accurately answer this, such as lengths or angles. Congruent triangles are identified in geometry based on either side-lengths or angles.

The question is about congruent triangles, which in mathematics means triangles that have the same size and shape. But to accurately answer which pairs show two congruent triangles, we need more information. The options provided include 'A', 'B', and 'C' but without knowing more about these elements (for example their lengths or angles), it is impossible to determine which are congruent. Congruent triangles are identified in geometry based on either side lengths (SSS: Side-Side-Side, SAS: Side-Angle-Side, ASA: Angle-Side-Angle) or angles (AAS: Angle-Angle-Side, HL: Hypotenuse-Leg for right triangles). Without this vital information, we cannot definitively answer the question. Be sure to verify all the properties required to prove two triangles congruent.

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