Write an appropriate and interesting word for 15000 and 3000.solve it​

Answer:

the probability is 5/12  or 0.416 or 41%

Step-by-step explanation:

Hope I helped!

Here is the answer for prove that cos theta by 1 minus tan theta + sin theta by 1 minus cot theta equal to sin theta + cos theta

Answer:

B

Step-by-step explanation:

Volume of a triangular pyramid = \(\frac{1}{3} bh\)

where b = area of base and h = height

We are already given that the height is 17in

All we need to do is find the area of the base.

The base is a triangle with a base length of 12 in and a height of 10 in

To find the area of a triangle we multiply the base length by the height then divide by 2

so area = (12 * 10 ) / 2

12 * 10 = 120

120 / 2 = 60

Hence the area of the base is 60in²

Now we plug in the values into the formula for volume of a pyramid

\(V=\frac{1}{3} 60*17\\\frac{1}{3} 60=20\\20*17=340\)

V = 340

Hence the answer is B

Answer:

Step-by-step explanation:

The volume of cylindrical tin is 1584 \(cm^3\). The depth of the oil in the tin is 9cm.

\(V_1 =\) VOLUME OF CYLINDRICAL TIN

   \(= \pi r^2 h\)

  \(=\frac{22}{7}\) x 6 x 6 x 14

  = 44 x 36

  = 1584 \(cm^3\)

\(V_2 =\) VOLUME OF RECTANGULAR TIN

    = lbh = 1584

    = (16)(11)(h) = 1584

    = 176h =1584

    = h = 1584 / 176

    = h = 9 cm

A cylinder is a three-dimensional shape that consists of a circular base and a curved surface that extends upward to meet at a point known as the apex. The volume of a cylinder is the amount of space occupied by the shape and is given by the formula V = πr²h, Once we have calculated the area of the circular base, we can multiply it by the height of the cylinder to get the volume.

To calculate the volume of a cylinder, we need to know its dimensions, which are the radius and height. The radius is the distance from the center of the circular base to the edge, while the height is the distance between the two circular bases.

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The probability that at least one of the calculators is defective is approximately 0.522.

First, we need to find the probability that none of the calculators are defective.

The probability that the first calculator selected is not defective is 39/52. The probability that the second calculator selected is also not defective is 38/51. The probability that the third calculator selected is not defective is 37/50. And finally, the probability that the fourth calculator selected is also not defective is 36/49.

So, the probability that all four calculators are not defective is:

(39/52) * (38/51) * (37/50) * (36/49) ≈ 0.478

Therefore, the probability that at least one of the calculators is defective is:

1 - 0.478 ≈ 0.522

So, the probability that at least one of the calculators is defective is approximately 0.522.

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the awaer is -5 see if that is right step by step

THE GENERAL EQUATION OF A STRAIGHT LINE IS y=mx+c

TO FIND c I WILL SUBSTITUTE THE GIVEN KNOWN POINTS.

\( - 5= \frac{1}{2} (2) + c \\ - 5= 1 + c \\ c = - 5 - 1 \\ c = - 6\)

THEREFORE WE NOW HAVE

\( y= \frac{1}{2} x - 6\)

ATTACHED IS THE SOLUTION

$59 increase in her bank account during that week.

Any of the basic arithmetic operations—addition, subtraction, multiplication, division, raising to the power of a whole number, and taking roots (fractional power)—is considered an algebraic operation. These procedures could be applied to numerical data, in which case they are frequently referred to as arithmetic operations. Similar operations can be carried out on variables, algebraic expressions, and, more generally, on components of algebraic structures like groups and fields. Another way to describe an algebraic operation is as a function from the Cartesian power of a set to the same set.

Given that : Sheila made four withdrawals of each from an ATM. . She also made a $156 purchase with her check card. She then deposited her $375 salary.

It's difficult to determine the solution because we don't know how much money she had in her bank account before making 4 withdrawals, thus a like and rating would be really appreciated. We know she took out $40 four times, which is $160. She also used her card to make a $156 purchase, so when we sum the two amounts, we get $316. She then placed a check for $375 into the bank account, therefore we must deduct $316 from that sum to get at $59; but, since we deducted, Given that we end up with $59 rather than the money we wasted at the beginning, the fact that the price is higher than $316 indicates that there has been an increase.

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Answer:

0

Step-by-step explanation:

7√2(8)(06)+4√7(06)

7√2(8)(06)+4√7(06)

=0

When a sample of 250 observations is selected at random from an infinite population with a population proportion of 0.25, we can calculate the standard error of the sampling distribution of the sample proportion using a specific formula. The standard error (SE) measures the variability or dispersion of the sample proportion from the true population proportion.

To compute the standard error of the sample proportion, use the following formula:

SE = sqrt[(P * (1 - P)) / n]

where P is the population proportion (0.25 in this case) and n is the sample size (250).

SE = sqrt[(0.25 * (1 - 0.25)) / 250]

SE = sqrt[(0.25 * 0.75) / 250]

SE = sqrt[0.1875 / 250]

SE ≈ 0.027

Thus, the standard error of the sampling distribution of the sample proportion, given a population proportion of 0.25 and a sample size of 250, is approximately 0.027. This value represents the expected variation in the sample proportions from the true population proportion, providing an estimate of the precision of the sample proportion as a representation of the population proportion.

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The equation of the line passing through (9,11) and perpendicular to the line passing through (6,1) and (2,1) is x = 6

Find the slope of the line passing through (6,1) and (2,1):

The slope of a line passing through two points (x1,y1) and (x2,y2) is given by:

slope = (y2 - y1) / (x2 - x1)

Substituting the given coordinates, we get:

slope = (1 - 1) / (2 - 6) = 0

Therefore, the slope of the line passing through (6,1) and (2,1) is 0.

Find the slope of the line perpendicular to the line passing through (6,1) and (2,1):

The slope of a line perpendicular to a line with slope m is given by:

perpendicular slope = -1/m

Substituting the slope of the line passing through (6,1) and (2,1), we get:

perpendicular slope = -1/0 (which is undefined)

This means that the line perpendicular to the line passing through (6,1) and (2,1) is a vertical line passing through the point (6,1) and (2,1).

Write the equation of the line passing through (9,11) and perpendicular to the line passing through (6,1) and (2,1):

Since the line passing through (6,1) and (2,1) is a horizontal line with equation y = 1, the line perpendicular to it is a vertical line passing through the point (6,1) and (2,1). The equation of a vertical line passing through a point (a,b) is given by:

x = a

Substituting the value of x = 6 (since the vertical line passes through (6,1) and (2,1)), we get:

x = 6

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The values of a, b, c, and d in the parallelogram are:

a = -2

b = 10

c = 4

d = 2

To determine the values of a, b, c, and d in the parallelogram, we can use the properties of parallelograms.

Since opposite sides of a parallelogram are parallel, the y-coordinate of the point opposite (4, 10) should also be 10.

Then, we have:

Point (a, 10) and Point (c, d)

The x-coordinate of the opposite point is the same for both pairs of opposite sides. So we can set:

a = -2

c = 4

Now, we need to find the value of d. Since the opposite sides of a parallelogram are also equal in length, we can use the y-coordinate of another given point, (-2, 2), to find d.

d = 2

So the values of a, b, c, and d in the parallelogram are:

a = -2

b = 10

c = 4

d = 2

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The difference in the areas of the signals based on the information given is 549.5km².

The formula to calculate the area of a circle will be:

= πr²

where r = radius

Mast 1 broadcast radio signals that can be heard within a radius of 15km. The area will be:

= πr²

= 3.14 × 15²

= 706.5km²

Mast 2 broadcast radio signals that can be hear within a radius of 20km. The area will be:

= πr²

= 3.14 × 20²

= 1256km²

The difference in the areas will be:

= 1256km² - 706.5km²

= 549.5km²

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Complete question

Mast 1 broadcast radio signals that can be heard within a radius of 15km.

Mast 2 broadcast radio signals that can be hear within a radius of 20km.

Calculate the difference in the areas of the signals.

Answer:

c

Step-by-step explanation:

The greatest possible whole-number length of the unknown side among the option is 9 inches.

Obtuse triangle is a triangle that has one of it internal angle greater than 90 degrees.

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

If the sides of the triangles are x, y and z. Therefore,

x + y > z

x + z > y

y + z > x

Therefore, the greatest possible length among the option is 9.

Proof

12 + 14 > 9

12 + 9 > 14

14 + 9 > 12

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The true statement is the range of Mrs Plum's class is 14 greater than the range of Mr Scarlet's class.

A box plot is a graph that is used to describe a dataset. A box plot is made up of two lines and a box. The two lines are known as whiskers.

The end of the first whisker represents the minimum number and the end of the second whisker represents the maximum number. The difference between the whiskers is the range.

Range is used to measure the variation of a dataset. It is the difference between the maximum number and the minimum number.

Range = maximum number - minimum number

Range of Miss Scarlet's class = 98 - 65 = 33

Range of Miss Plum's class = 98 - 51 = 47

Difference in range = 47 - 33 = 14

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Answer:

False

Step-by-step explanation:

4/10's numerator (top number) and denominator (bottom number) can both be divided by 2. Therefore, when we do that, it will be equal to 2/5. 2/5 is not equal to 1/2. Therefore, the answer is false.

If this helps please mark as brainliest

Answer:

C) -x²+9x²-27+27

Hope it helps

:)

Answer:

22,220

Step-by-step explanation:

Because you multiply by 10 because 2222 times 1 is 1 person per race, so if there is 10 then you multiply by 10.

Answer:

it might be 30. If you lose half every 90 days, You lose half of 120, which is 60. another 45 days would make it half again, equaling 30

Answer: 30

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given in the ∆ that,

the sides of triangle∆ is

As we know that,

perimeter of the ∆ is the addition of all sides

so,

perimeter= 5x-2+2x-3+4x+3

=11x-2

Answer:

12500

Step-by-step explanation:

9260+3240==

12500

Answer:

Step-by-step explanation:

Rearrange terms: -3x+4=6-3x

-3x+4=-3x+6

Subtract 4 from both sides

-3+4-4=-3x+6-4

Subtract the numbers

=3x==3x+2

Add 3x to both sides

=3x+3x=-3x+2+3x

-3x+3x=-3x+2+3x= 0=2 which is no solution

Answer:

2d^0.7

Step-by-step explanation:

Instead of using a t-test, alternative statistical tests can be employed when the null hypothesis makes specific claims about the data. These tests are chosen based on the type of data and the specific hypothesis being tested.

When the null hypothesis makes claims about the data that go beyond a simple comparison of means, using a t-test may not be appropriate. Alternative statistical tests can be used in such situations to address specific hypotheses.

For example, if the null hypothesis involves comparing proportions, a chi-square test or Fisher's exact test can be used. These tests are suitable for analyzing categorical data and determining if there is a significant difference between observed and expected frequencies.

Similarly, if the null hypothesis involves comparing means across more than two groups, analysis of variance (ANOVA) or its non-parametric counterpart, the Kruskal-Wallis test, can be employed. These tests allow for the comparison of means across multiple groups and can provide valuable information about the overall differences between groups.

The selection of an appropriate test depends on various factors. The nature of the variables being analyzed, such as categorical or continuous, influences the choice of test. Sample size also plays a role, as some tests require larger sample sizes to yield accurate results. Additionally, each test has certain assumptions associated with it, and researchers need to ensure these assumptions are met before applying the test.

By using alternative tests that are suitable for the specific hypotheses being tested, researchers can gain a deeper understanding of their data. This approach allows for more accurate statistical inferences and can provide valuable insights into the relationships and differences present in the dataset.

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The initial velocity (vi) of the ball, when shot into the catcher, is approximately 367.5 m/s.

To solve Eq. 7.5 and Eq. 7.6 for v1​ in terms of m, M, g, and h, we will substitute the given values of m, M, and h into the equations.

Eq. 7.5: mv1​ = (m+M)V2​

Eq. 7.6: (m+M)V22​ = (m+M)gh

Given:

m = 50.0 g (mass of the ball)

M = 200.0 g (mass of the catcher)

h = 15.0 cm (rise in the center of mass)

First, let's solve Eq. 7.6 for V2​ by dividing both sides by (m+M):

V22​ = gh

Next, substitute the expression for V2​ into Eq. 7.5:

mv1​ = (m+M)(gh)

Now, solve for v1​ by dividing both sides by m:

v1​ = (m+M)(gh) / m

Substituting the given values:

v1​ = (50.0 g + 200.0 g)(9.8 m/s²)(0.15 m) / (50.0 g)

Calculating the expression:

v1​ = (250.0 g)(9.8 m/s²)(0.15 m) / (50.0 g)

v1​ = 367.5 m/s

Therefore, the initial velocity (vi) of the ball, when shot into the catcher, is approximately 367.5 m/s.

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