a net ionic equation to show why solid potassium hydroxide, koH (s), forms a basic solution when it dissolves in water
Equation
KOH (s) [H2O ] → K+(aq)+OH−(aq)
The Arrhenius theory, the Brnsted-Lowry theory, and the Lewis theory are the three ideas that have contributed to the definitions of acids and bases over time. According to Arrhenius, an acid is a chemical that, when ionised, releases protons (hydrogen ions) into the solution, whereas a base releases hydroxide ions.
According to Brnsted-Lowry, a base is a proton acceptor and an acid is a proton giver. According to Lewis, a base is an electron-pair donor, while an acid is an electron-pair acceptor
KOH satisfies the Arrhenius theory's definition of a base by producing hydroxide ions when ionised. The hydroxide ion is the base component from a Brnsted-Lowry perspective since it can accept a proton to create water. Although it is a little more difficult to understand from a Lewis perspective why this is a base, the oxygen in the hydroxide has three pairs of non-bonding electrons on it. When a proton (acid) is present, it lacks the electrons necessary to create a covalent link, therefore hydroxide donates an electron pair to the proton in order to build a coordinate covalent bond, which produces water. The three theoretical requirements for a base are thus satisfied by the aforementioned net ionic equation.
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A pool is treated with calcium hypochlorite pool shock. If Ca(OCl)₂ has 50.0% available chlorine by mass, what ppm chlorine increase will result from the addition of 3.50 kg of pool shock to a 40.0 x 10³ L swimming pool? (density of water = 1.00 kg/L)
The addition of 3.50 kg of calcium hypochlorite pool shock will result in a chlorine increase of 0.044 ppm in a 40,000 L swimming pool.
Why does calcium hypochlorite get used to treat water?Granules of calcium hypochlorite are a potent disinfectant that clean and sanitise the water flowing through potable water lines by killing about 99.9% of all germs (bacteria, viruses, and mildew).
First, we need to calculate the amount of available chlorine in 3.50 kg of calcium hypochlorite pool shock:
Amount of available chlorine = 50.0% of 3.50 kg
= 0.50 x 3.50 kg
= 1.75 kg
Next, we can use the following formula to calculate the increase in ppm (parts per million) of chlorine in the pool:
(ppm chlorine increase) = (amount of chlorine added in kg) / (pool volume in liters)
To use this formula, we need to convert the pool volume from liters to kg, using the density of water:
Pool volume in kg = pool volume in liters x density of water
= 40,000 L x 1.00 kg/L
= 40,000 kg
Now we can plug in the values and calculate the ppm chlorine increase:
(ppm chlorine increase) = (1.75 kg) / (40,000 kg)
= 0.000044 or 0.044 ppm
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how are the electrons that are lost by the chlorophyll molecules replaced
By dividing water, the electron that was lost from the chlorophyll special pair is replaced. Protons are pumped from the stroma to the thylakoid lumen as a result of the electron passing through the first link in the electron transport chain.
The electrons from photosystem II that have traveled via the electron transport chain replace the electrons lost by these chlorophyll molecules. The two chlorophyll "a" molecules of photosystem II are compelled by light energy to go up an energy level.
The energy storage molecule ATP and the reduced electron carrier NADPH are produced by the light-dependent processes using light energy, which is required for the subsequent stage of photosynthesis. Light reactions in plants occur in the thylakoid membranes of organelles referred to as chloroplasts in chlorophyll.
The light reactions are largely controlled by photosystems, sizable complexes of proteins, and pigments (light-absorbing molecules) that are designed to capture light. Photosystem I (PSI) and Photosystem II are the two different types of photosystems (PSII). Via a process known as photolysis, the chlorophyll molecule regains the lost electron from a water molecule, releasing dioxygen (O2) in the process.
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What's the difference between a reflected in defecated sound wave
A. A reflected sound wave changes direction as it passes through an opening a diffracted sound wave bounces back to the place of origin
B. A reflected sound wave bounces back to the place if origin, a diffracted sound wave is absorbed as it passes through an opening
C. a reflected sound wave is absorbed by the medium, a diffracted sound wave changes direction as it passes through an opening
D. A reflected sound wave bounces back to the place of origin, a diffracted sound wave changes direction as it passes through an opening
Answer:
D
Explanation:
The difference between a reflected and diffracted sound wave is:
A. A reflected sound wave changes direction as it passes through an opening, whereas a diffracted sound wave bounces back to the place of origin.
Reflection occurs when a sound wave hits a surface and bounces back in the opposite direction. When a sound wave is reflected, it changes direction but does not necessarily change its wavelength or frequency. This is why we can hear echoes in a room with reflective surfaces.
Diffraction, on the other hand, occurs when a sound wave passes through an opening or around an obstacle and changes direction. When a sound wave is diffracted, it spreads out and changes its wavelength and frequency. This is why we can hear sound around corners or through a partially open door.
Therefore, option D is the correct answer: A reflected sound wave bounces back to the place of origin, a diffracted sound wave changes direction as it passes through an opening.
How do you prepare the benzene sulphonic acid from benzene?
Answer:
add sulfur trioxide
Explanation:
To produce benzenesulfonic acid from benzene, fuming sulfuric acid and sulfur trioxide are added. Fuming sulfuric acid, also refered to as oleum, is a concentrated solution of dissolved sulfur trioxide in sulfuric acid.
How many mL of 0. 8291 M NaCl are required to prepare 500. 00 mL of a 0. 0500 M NaCl olution?
To prepare 500. 00 mL of a 0. 0500 M NaCl Solution of 0. 8291 M NaCl 30.48 ml volume is needed
M1=0.82
V1=?
M2=0.05
V2=500 ml
M1V1=M2V2
0.82×V1=500×0.05
V1=30.48 ml
The area occupied within an object's boundaries determines its volume in three dimensions. On occasion, it is referred to as the object's capacity. The volume of an object can be used to calculate how much is needed to fill it; for instance, how much water is needed to fill a bottle, aquarium, or water tank. A sphere is the most basic and prevalent type of three-dimensional shape. We come across spheres all the time in the form of balls, globes, ornamental lights, oranges, etc.
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carbon is able to form a wide variety of stable chain, ring, and branched compounds. which factors contribute to this behavior? select all that apply.
Due to catenation property of carbon
What is catenation property ?
Carbon has the capacity to join together to form lengthy chains. In actuality, among all the other atoms present in nature, carbon atoms are distinct due to catenation. Tetravalent connections between carbon atoms are what cause carbon chains to develop today.
They create tetravalent bonds, in which one carbon atom joins forces with four additional carbon atoms. They have a repeating structure because this structure can be repeated indefinitely without affecting the stability of the bonds or the compounds created.
In actuality, chains can create branches, which in turn, create sub-branches, which create rings, and so on. Now, there are two categories of carbon compounds, the first of which is open-chain or aliphatic molecules.
C forms covalent bonds almost exclusively.
C-C bonds are relatively short and therefore strong.
C-C multiple bonds form readily and are stable.
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How many oxygen atoms are there in 5 molecules of Al2(SO4)?
Answer:
There are two aluminum ions and three sulfate ions; or two aluminum, three sulfur, and twelve oxygen atoms.
Explanation:
In 5 molecules of Al₂( SO₄ ) there are 20 oxygen atoms are present. In one molecule of aluminum sulphate there are 4 oxygen atoms present and in 5 molecules of Al₂( SO₄ ) 20 oxygen atoms present.
What is molecule ?According to the environment, the word may or may not include ions that meet this requirement. A molecule is a collection of two or more atoms bound together by the attractive forces known as chemical bonds.
There are three different kinds of molecules: atom-sized molecules, element-sized molecules, and compound-sized molecules.
A molecule is the smallest unit of any material that is composed of one or more elements and is capable of existing independently while maintaining all the substance's physical and chemical characteristics. Further atom division occurs within molecules.
Thus, In 5 molecules of Al₂( SO₄ ) there are 20 oxygen atoms are present.
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What is the solvent in blood?
Answer:
Water serves to suspend the red blood cells to carry oxygen to the cells. It is the solvent for the electrolytes and nutrients needed by the cells, and also the solvent to carry waste material away from the cells. With water as the solvent, osmotic pressure acts to transport the needed water into cells.
Explanation:
You have a 5.8 ml sample of mercury. What is the mass of your sample?
Mass = volume × density
Since the volume of the sample = 5.8 ml
& the density of mercury = 13.5 g/mL
∴ Mass = 5.8 mL × 13.5 g/mL
= 78.3 g
thus a 5.8 mL sample of mercury has a mass of 78.3 gWhat do all iron atoms and ions have in common ?
Answer:
All atoms and ions of iron have 26 protons. Iron's atomic number is 26. Atoms don't gain or lose protons. The atomic mass of this ion is 56, which is the sum of its protons and neutrons.
Answer:
They both have 26 protons.
The one thing ions and iron atoms have in common is that they both have 26 protons. Hope it helps!
120g of C₂H, react with 288g of O₂, What is the limiting reactant? How many grams of water can be produced? How many grams of excess? If 130 grams of water are actually produced, what is the percent yield?
The percentage yield is equal to 200.6%.
The balanced equation for the given chemical reaction is :
2C2H + 5O2 → 4CO2 + 2H2O
Let's find the limiting reagent:
Mass of C2H = 120 g
Mass of O2 = 288 g
Molar mass of C2H = 26 g/mol
Molar mass of O2 = 32 g/mol
The number of moles of C2H is equal to:
120 g × 1 mol/26 g = 4.62 mol
The number of moles of O2 is equal to:
288 g × 1 mol/32 g = 9 mol
According to the stoichiometry of the balanced equation, 2 moles of C2H react with 5 moles of O2, so:
If 4.62 moles of C2H is used, then the required amount of O2 would be:
5/2 × 4.62 mol = 11.6 mol
We only have 9 mol of O2 which means it is the limiting reagent.
C2H is the excess reagent.
Let's find the mass of water produced:
According to the stoichiometry of the balanced equation,2 moles of H2O is produced per 2 moles of C2H2 moles of H2O is produced per 5 moles of O2If 9 mol of O2 is used, the number of moles of water produced would be:
2/5 × 9 mol = 3.6 mol
The mass of water produced is equal to:
3.6 mol × 18 g/mol = 64.8 g
Therefore, 64.8 g of water can be produced.
The amount of excess reagent is equal to:
4.62 mol - 2/2 × 9 mol = 4.62 - 9
= -4.38 mol
C2H is the excess reagent and it is not possible to have negative amount of a substance.
So, we assume that there is no excess reagent.
If 130 grams of water is produced, then the percentage yield is equal to:
Percent yield = actual yield/theoretical yield × 100
Theoretical yield is equal to 64.8 g
Actual yield is equal to 130 g
Percent yield = 130/64.8 × 100
= 200.6%
Therefore, the percentage yield is equal to 200.6%.
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Explain how the experimental molecular mass would have been affected (too high, too low or unchanged) if the mass of the flask had been measured with condensed vapor and residual water on the outside. Please support your answer.
If the flask already has water, your measure is going to be higher than expected and MW is going to be higher too.
At first sight, we need to assume 1 atm as atmospheric pressure, probably forgot to write down this value in the Lab. By doing this, we got all values to calculate the MW.
So, for trial 1:
MW = [0.36 g x (0.082 atm x L / K x mol) x 301 K] / (1 atm x 0.125 L) = 71.08 g/mol
Trial 2:
MW = [0.38 g x (0.082 atm x L / K x mol) x 301 K] / (1 atm x 0.125 L) = 75.53 g/mol
Average MW = 73.31 g/mol
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Ngawang has 5.6X10²⁴atoms of helium gas to fill balloons at a ball game.If each balloon holds 1.5 litres of helium, how many balloons can the fill? Assume STP.
We must first convert the amount of atoms of helium to moles in order to solve this issue. This much helium gas can be used by Ngawang to fill about 14 balloons at STP.
A petrol is what?Along with liquids, solids, and plasmas, gases are among the four basic states of matter. Gases are made up of atoms or molecules that are constantly moving and spaced far apart from one another. Gases, in contrast to solids and liquids, do not have a set shape or volume and always fill their container to the top.
In addition to other characteristics like density, viscosity, and compressibility, gases can be classified according to their volume, pressure, and temperature. Additionally, they can change physically and chemically through processes including expansion, compression.
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if 30 ml of a 0.80 m solution of k is mixed with 50 ml of a 0.45 m solution of clo−4, will a precipitate be observed? the ksp for the following equilibrium is 0.004. kclo4(s)↽−−⇀k (aq) clo−4(aq)
If 30 ml of a 0.80 m solution of k is mixed with 50 ml of a 0.45 m solution of clo−4, a precipitate will be observed in this solution.
The solution contains k (potassium) and clo−4 (chlorate) ions and we are to find out if a precipitate will form or not. The ksp for the following equilibrium is 0.004. kclo4(s)↽−−⇀k (aq) clo−4(aq)
We can obtain the molarity of k ions as follows: 0.80 M = (moles of K)/(0.030 L)Moles of K = 0.80 M × 0.030 L = 0.024 mol
We can obtain the molarity of clo−4 ions as follows: 0.45 M = (moles of clo−4)/(0.050 L)Moles of clo−4 = 0.45 M × 0.050 L = 0.0225 mol
The concentration of K and clo−4 ions are 0.8 M and 0.45 M respectively. Now, we need to calculate the reaction quotient Q of the solution to find out whether the precipitate will form or not. Q = [K+][clo−4] = 0.8 M × 0.45 M = 0.36
Since Q (0.36) > Ksp (0.004), the reaction quotient is greater than the solubility product constant. It indicates that the product is more than what it should be. The excess products will precipitate to form a solid. Hence, we can say that a precipitate will be observed in this solution.
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Which phrase describes non-foliated rocks? only one!
have grains in parallel layers
include quartzite and marble
tend to split along their bands
form from crystallized magma
Answer:
include quartzite and marble
Explanation:
non-foliated rocks are
1. metamorphic rocks
2. they are formed in the surrounding of igneous rocks
3. The environmental condition of formation of non-foliated rocks are that temperature is very high
4. pressure is very low but equal from all direction on igneous rocks
5. The constituent material crystalizes to form large rocks in which atoms are tightly and closely packed. Due to this density of these rocks are also higher.
Example of such rocks are
Quartzite : Its constituent material are mineral quartz and metamorphosed sandstone
Marble : its constituent material are mineral calcite; metamorphosed limestone
Hence, include quartzite and marble is the correct choice.
Answer:
include quartzite and marble
Explanation:
(ik this isn’t chemistry) if i had a neutral atom of oxegyn and removed an electron from it, what kind of ion would i get?
1)anion
2)cation
3)dogion
4)mouseion
Answer:
Cation
Explanation:
I'm pretty sure the last two options are a joke, but electrons are negative so losing one gives a positive charge.
A gas sample is made entirely of carbon dioxide and water, and there are 300 moles of CO2 and 500 moles of H2O. If the total pressure of the sample is 21 atm, what is the partial pressure of H2O ? Ptotal = Pa + Pb+ Pc....... Pa = Xa(Ptotal)
Answer:
Explanation:
Total moles = 300 + 500 = 800 moles
mole fraction of carbon dioxide = 300 / 800 = 3 / 8
water = 500 / 800 = 5 / 8
Total pressure = 21 atm
partial pressure of water = total pressure x mole fraction of water
= 21 x 5 / 8
= 13.125 atm
my chem test is tomorrow!! please help
Answer:
The pH of the pure water is not always neutral but actually sometimes it can be slightly acidic but not of the same extent or value as HCl obviously. However ,it is enough to result to a color change in the presence of phenolphthalein.
Explanation:
I will try to be brief and spare the boring details .Basically ,this is caused by the reaction of water and CO2 that is naturally present in the atmosphere to produce a weak acid known as carbonic acid.
~Hope this helps:)
Compare diamonds and graphite - Structure, bonding, properties, use
Answer:
Carbon atoms each form four strong bonds. The bonds are covalent (atoms share electrons). This gives graphite its characteristic properties such as high melting and boiling points, good electrical conductivity, and softness. Use as pencil 'lead', as a lubricant in oil, furnace linings, electrodes, neutron moderators in nuclear power stations.
Diamond atoms each form three strong covalent bonds in the same layer and one weak bond to an atom in another layer. Diamonds have a high level of hardness, thermal conductivity, and optical dispersion. It is used for jewellery, oil-well drills, abrasives and cutting tools.
Explanation:
Structure of Graphite and Diamond (attached below):
What is the genetic makeup of both parents ?
Answer:
A, T, C y G, son las "letras" del código del ADN; representan los compuestos químicos adenina (A), timina (T), citosina (C) y guanina (G), respectivamente, que constituyen las bases de nucleótidos del ADN. ...El código genético es el conjunto de reglas que define cómo se traduce una secuencia de nucleótidos en el ARNm a una secuencia de aminoácidos en una proteína
Propose an efficient synthesis for the following compound (0.4 points) 2-methylpentan-3-one
To synthesize 2-methylpentan-3-one efficiently, following process has to be followed:
Start with the synthesis of 2-methylpentan-3-ol, which can be prepared via a Grignard reaction. Firstly, prepare 2-methylpentan-3-ol by reacting ethyl magnesium bromide with 3-methylbutanal.
Afterward, hydrolysis of this Grignard reagent using HCl or dilute sulfuric acid provides the alcohol.2-methylpentan-3-ol.
( Grignard reaction -The Grignard reaction is an organometallic chemical reaction in which carbon alkyl, allyl, vinyl, or aryl magnesium halides (Grignard reagent) are added to the carbonyl groups of either an aldehyde or ketone. This reaction is important for the formation of carbon–carbon bonds.)
Now,the oxidation of 2-methylpentan-3-ol is carried out using oxidizing agents like PCC (pyridinium chlorochromate), PDC (pyridinium dichromate), or Jones reagent to synthesize 2-methylpentan-3-one.Oxidation of 2-methylpentan-3-ol to synthesize 2-methylpentan-3-one can be represented as follows: PCC or PDC or Jones Reagent2-methylpentan-3-one.
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A divalent metal oxide contains 60 % of metal. What is atomic weight of metal ?
Atomic weight of metal : 24
Further explanationProust states the Comparative Law that compounds are formed from elements with the same Mass Comparison so that compounds have a fixed composition of elements
Divalent metal oxide=XO
MW O = 16
MW XO₂ = X+16
\(\tt \%mass=\dfrac{Ar~X}{X+16}\times 100\%\\\\0.6=\dfrac{X}{X+16}\\\\0.6(X+16)=X\\\\0.6X+9.6=X\\\\0.4X=9.6\rightarrow X=24\)
According to the force field analysis, equilibrium occurs when ________ of change are balanced with ________ of change resulting in a relatively steady state. group of answer choices
A reasonably constant condition results from equilibrium, according to the force field analysis, when driving forces of change are equal to restraining forces of change.
what is force field analysis?A force field is a computer technique used to estimate the forces between atoms within molecules as well as between molecules in the context of chemistry and molecular modelling.
Driving forces are those that exert pressure in a direction that brings about a change or that enable a change by exerting pressure on a person in the desired direction. Restraining forces are those that work against the driving force and impede change by pulling a person in the opposite direction of what is wanted.
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All of the following metals will float in mercury except
Answer:
gold
Explanation:
it has a higher density of 19.32g/cm³
Answer:
Gold
Explanation:
It has a higher density which is 19.32g/cm³.
help with this question plsss
Answer:
The atomic number tells us how many protons and electrons are in the element we are looking at.
All of the planets in our solar system affect the wind and water currents on earth through gravitational force."
A. True B. False
A __________________ chemical equation shows that the same number of atoms in the reactants are also in the product.
balanced
rearranged
transferred
beautiful
Is it alr to have a rebound??
Answer:
Next time you're just recently out of a serious relationship, and you're craving some sort of intimacy and comfort, feel confident that a rebound might actually be a good thing as long as it's an upgrade, either physically, emotionally, a fun date, or even just finding a way to shift your mentality toward viewing. so what im saying is if your happy in that relationship stay in it and if he or she becomes a meany leave it its not goo for your health
Directions: Determine the molar mass of the following substances.
6. Nas
1. CaO
7. AICI:
2. Mg(CO3)
8. (14H4)2(SO4)
3. Zn(NO3)2
9. Ni3(PO4)2
4. Cuz(CrO4)
10. Ba(NnO4)2
5. Na(C103)
1. 40.08 + 16 = 56.08 g/mol CaO
2. 24.30 + 12.01 + 48.00 = 84.31 g/mol Mg(CO3)
3. 65.39 + 28.02 + 96 = 189.41 g/mol Zn(NO3)2
4. "Cuz" isn't an actual element. 52.00 + 64.00 = 116.00 g/mol CrO4
5. 22.99 + 1237.03 = 1260.02 g/mol Na(C103)
6. 22.99 + 32.06 = 55.05 g/mol NaS
7. 26.98 + 35.45 = 62.43 g/mol AlCl
8. 113.12 + 32.06 + 64 = 209.18 g/mol (14H4)2(SO4)
9. 176.07 + 61.94 + 128.00 = 366.01 g/mol Ni3(PO4)2
10. 137.33 + "Nn" isn't an actual element. 128.00 = 265.33 g/mol Ba(O4)2
whats the volume of dry hydrogen gas at standard astrospheric pressure
The volume of dry hydrogen gas at standard atmospheric pressure (which is typically defined as 1 atm or 101.325 kPa) depends on the number of moles of hydrogen gas present. The ideal gas law, PV = nRT, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of an ideal gas. Assuming standard temperature and pressure (0°C and 1 atm), one mole of any ideal gas occupies a volume of 22.4 L. Therefore, to find the volume of dry hydrogen gas at standard atmospheric pressure, we need to know how many moles of hydrogen gas we have.
For example, if we have 1 mole of dry hydrogen gas at standard atmospheric pressure, the volume would be 22.4 L. If we have 0.5 moles of dry hydrogen gas, the volume would be 11.2 L. And so on.