Write a constructor that accepts arguments for each field and initializes all the fields.Save the OnlineOrder class file as OnlineOrder.java. The class should have the following fields. i. custName- The custName field references a String object that holds a customer name. ii. custNumber- The custNumber field is an int variable that holds the customer number. iii. quantity- The quantity field is an int variable that holds the quantity online ordered. iv. unitPrice- The unitPrice field is a double that holds the item price.

Answer: Photo lines

Explanation: made more sense

In Engineering, the thrust angle is checked by referencing: C. vehicle centerline.

A thrust angle can be defined as an imaginary line which is drawn perpendicularly from the centerline of the rear axle of a vehicle, down the centerline.

This ultimately implies that, the thrust angle is a reference to the centerline (wheelbase) of a vehicle, and it confirms that the two wheels on both sides are properly angled within specification.

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Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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Examples include weightlifting gloves, belts, wrist wraps, and other items that are together referred to as weightlifting gear.

No, using weightlifting hooks is not unethical. Weightlifting hooks can be a useful tool for lifters who need them if they are utilized properly and sparingly. Just be careful not to utilize them for exercises where they are not necessary.

Briefly, no. Given the aforementioned, we may conclude that sumo deadlifts are not simpler. We can also state without a doubt that sumo deadlifts are not cheating by referring to any powerlifting rulebook, which permits both conventional and sumo deadlifts in competition.

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The primary distinction between the two is that whereas the Heap permits duplicates, the Binary Search Tree does not. The Heap is not ordered, but the BST is.

It is preferable to use BST if order is important. The Heap promises to attain this time if an order is irrelevant but we still need to know that inserting and removing data will take O(log(n)) time. If the tree is entirely out of balance, this could take up to O(n) time in a binary search tree (chain is the worst case). Additionally, while Heap may be constructed in linear time, BST requires O(n * log(n)) to construct.Java uses the PriorityQueue and the TreeMap to implement these structures. By default, PriorityQueue is a Max-Heap. A balanced binary search tree serves as the foundation of TreeMap. It is done using a Red-Black Tree.

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Answer:

\(W=46141.72~J\)

Explanation:

Given:

initial pressure, \(P_1=14~bar=1.4\times10^6~Pa\)

initial volume, \(V_1=0.03~m^3\)

After isothermal expansion:

final volume, \(V_2=3V_1=0.09~m^3\)

a)

We have the work done in isothermal process as:

\(W=P_1.V_1\ln(\frac{V_2}{V_1} )\)

\(W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )\)

\(W=46141.72~J\) is the work by the gas in moving the external force

b)

When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.

\(P_1V_1^{\gamma}=P_2V_2^{\gamma}\)

\(14\times 0.03^{1.4}=P_2\times 0.09^{1.4}\)

\(P_2=3~bar\)

Now, using the formula for work done in adiabatic process:

\(W=\frac{P_1V_1-P_2V_2}{\gamma-1}\)

\(W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}\)

\(W=3750~J\)

The scale of the blueprint tells us the boundary of the drawing to real space. The correct option is a.

It is a photographic print in white on a bright blue background or blue on a white background, particularly useful for copying maps, mechanical drawings, and architect's designs

The plan of the construction is a project prediction that is slightly auto cad. The scale factor provides information on the dimensions and measurements of things represented by smaller copies in maps, blueprints, scale drawings, and scale models. The scale tells us how much actual length some length on the scale graphic represents.

Therefore, the correct option is a, Boundary.

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The method of social engineering that could be used to deliver ransomware is; email phishing

Ransomware is simply a type of social engineering that criminals use to steal data, infect computers, and infiltrate company networks.

Now, the most popular form of social engineering that could be used to deliver ransomware is email phishing. This is because email Phishing has become more pervasive and dangerous these days as it is used when attackers/criminals send fraudulent emails that either contain dangerous links or exploitative requests.

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Place a metal paper clip on a table and slowly bring each electromagnet closer to the paper clip to see which can attract the paper clip from a greater distance.(option A)

What is an electromagnet?

A coil surrounding a magnetic core through which an electric current is delivered to magnetize the core is what makes up an electromagnet. Wherever controlled magnets are needed, such as in devices where the magnetic flux needs to be adjusted, reversed, or turned on and off, an electromagnet is utilized.

The magnetic field has also been thought to be completely contained inside the coil. In actuality, the magnetic lines of force that surround the exterior of the coil, which represent the leakage flux, are constantly present and do not add to the core's magnetization.

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The question was incomplete. Check below the full question.

Jaeda designs two electromagnets of different strengths. the first electromagnet has an insulated copper wire wrapped around an iron nail many times before it is connected to a battery. the second electromagnet has its insulated copper wire wrapped around a similar nail a fewer number of times before it is connected to two smaller batteries jaeda tries to determine which electromagnet is stronger by bringing each near a bowl containing eight metal paper clips. she observes that both electromagnets attract all eight of the paper clips how can jaeda demonstrate that each electromagnet has a different strength?

A. Place a metal paper clip on a table and slowly bring each electromagnet closer to the paper clip to see which can attract the paper clip from a greater distance.

B. Determine which electromagnet has its copper wire wrapped around its iron nail a greater number of times.

C. Add plastic paper clips to the bowl and check which electromagnet can attract both kinds of paper clips.

D. Reduce the number of paper clips in the bowl and find which electromagnet attracts more paper clips.

A weighted average meter is a type of electrical meter that measures the average value of an alternating current (AC) signal over a period of time. It is commonly used to measure the power consumption of electrical devices in households and industries.

To measure alternating current, the weighted average meter uses a technique called the root mean square (RMS) method. The RMS value is the effective value of an AC waveform, which is equal to the DC value that would produce the same power. The RMS value takes into account the amplitude and frequency of the AC signal, and provides a more accurate measurement of power consumption than other methods. The weighted average meter calculates the RMS value by using a weighting factor that assigns different weights to different parts of the AC waveform. The weighting factor is usually a function of the time and the amplitude of the AC signal. The weighted average meter then integrates the weighted values over a period of time to determine the average power consumption. In conclusion, a weighted average meter measures alternating current by using the root mean square method, which calculates the effective value of the AC waveform. The meter uses a weighting factor to assign different weights to different parts of the waveform, and integrates the weighted values over time to determine the average power consumption. This method provides a more accurate measurement of power consumption than other methods and is commonly used in households and industries.

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Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source.

Engineering controls are a type of hazard control that reduces or eliminates the hazard at its source. Engineering controls are used to minimize or eliminate hazards that pose a significant risk of harm or danger to individuals, such as chemical or noise exposure.

These measures are frequently a vital component of an effective occupational health and safety program in the workplace. Examples of engineering controls include the use of ventilation to control fumes, dust, and other airborne hazards, as well as the use of sound barriers to reduce noise levels. In addition, the use of machine guards, interlocks, and other safety devices on equipment and machinery is considered a form of engineering control to safeguard workers from contact with hazardous moving parts.

Other types of engineering controls include changes in the manufacturing process or the substitution of less harmful materials to eliminate the hazard. Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source. These controls, when combined with other forms of hazard control, such as administrative and personal protective equipment, provide a comprehensive approach to worker safety and health.

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Before using a vise to mount work, wipe the vise base and worktable clean, inspect it for burrs and nicks, and bolt it firmly to the table.

The complete question is,
When a vise is used to mount work, ____.

wipe the vise base and worktable clean, inspect it for burrs and nicks, and bolt it firmly to the table

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Answer:

Answer to the following question is as follows;

Explanation:

The amount of alcohol consumption can be influenced by a variety of things, including food.

The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.

The recommended vessel wall thickness is 0.57 inches. The thickness of the walls is critical since it aids in the prevention of deformation of the walls when subjected to high-pressure environments.

The vessel's thickness is determined using the following equation: t = P r / (2S.E + 0.6P), where t is the thickness, P is the pressure, r is the radius, S.E is the joint effectiveness, and S is the maximum allowable stress.

In this scenario, P = 2200 psi, S.E = 0.88, S = 15500 psi,

and r = (3V/4π)^(1/3) = (3*9.5/4π)^(1/3) = 0.8766 feet.

Therefore, t = 2200*0.8766 / (2*0.88*15500 + 0.6*2200) = 0.57 inches.  

The pressure vessel's wall thickness is determined using the ASME boiler and pressure vessel code, section VIII, division A pressure vessel is a container that is used to contain high-pressure liquids and gases. They are frequently used in the petrochemical industry and are sometimes used to transport hazardous substances.

The maximum allowable stress of mild steel is 15500 psi.

The joint effectiveness is used to assess the strength of the vessel's welded joints. In this scenario, the joint effectiveness is 88%.The vessel's thickness is determined using the following equation:

t = P r / (2S.E + 0.6P),

where t is the thickness, P is the pressure, r is the radius, S.E is the joint effectiveness, and S is the maximum allowable stress. In this scenario,

P = 2200 psi, S.E = 0.88, S = 15500 psi,

r = (3V/4π)^(1/3) = (3*9.5/4π) ^ (1/3) = 0.8766 feet.

Therefore, t = 2200*0.8766 / (2*0.88*15500 + 0.6*2200) = 0.57 inches. The wall thickness of a pressure vessel must be sufficient to withstand the internal pressure. Furthermore, the vessel's thickness must be sufficient to prevent deformation of the walls when subjected to high-pressure environments. The thickness of the walls is often influenced by the design of the vessel. The length, radius, and shape of the vessel all play a role in determining its thickness.

The recommended vessel wall thickness is 0.57 inches. The thickness of the walls is critical since it aids in the prevention of deformation of the walls when subjected to high-pressure environments. Furthermore, the design of the vessel, including its length, radius, and shape, has an impact on the thickness of its walls.

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Formatting can make the text easier for the viewer to read. Given a ten-digit phone number, output the number in a format that is more comfortable for a person to read. To achieve this task, you can write a code in C++ that will format the phone number in a readable format for the viewer.

Let's look at the code for this. In this code, the user needs to input ten digits of the phone number, which we will store in a variable named phone, which we will then format to a readable format. Here is a code snippet that formats the phone number in C++:#include using namespace std;int main() { string phone; cin >> phone; // Using substrings to extract the area code string areaCode = phone.substr(0, 3); // Using substrings to extract the prefix string prefix = phone.substr(3, 3); // Using substrings to extract the line number string lineNum = phone.substr(6, 4); // Outputting the formatted phone number cout << "(" << areaCode << ") " << prefix << "-" << lineNum << endl; return 0;}Let's test the code with the help of an example. If the input is:1234567890The output should be:(123) 456-7890The above code is using substrings to extract the area code, prefix, and line number and then concatenating them using the appropriate characters to display the phone number in a more readable format.The final code in C++ to format a phone number in a readable format is the above.

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The gelatinous membrane that stretches across the tube to form a fluid-tight seal akin to the skin of an ear drum covers the semicircular canal receptor cells, also known as hair cells, only in the center of the circular tubes in a special epithelium.

You can sense your body's position and keep your balance thanks to the stimulation of hair-like receptors that send signals to the cerebellum at the back of the brain.

Your inner ear contains three tiny, liquid-filled tubes called semicircular canals that aid in balance. The fluid in the semicircular canals sloshes around as your head moves, moving the fine hairs that line each canal.

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To print the sum only once, after all the numbers have been added, we need to un-indent line 9 twice, move line 9 above line 7, and move and indent line 5 below line 6 to reset the sum after each loop iteration.

Un-indent line 9 once: This option would not achieve the desired result because the sum would still be printed multiple times within the loop, rather than after all the numbers have been added.

Un-indent line 9 twice: This option is correct. By un-indenting line 9 twice, it will be at the same level of indentation as line 5, which means the sum will be printed only once, after all the numbers have been added.

Move line 9 above line 8: This option would not provide the desired result because moving line 9 above line 8 would result in printing the sum before adding the next number, rather than after all the numbers have been added.

Move line 9 above line 7: This option is correct. By moving line 9 above line 7, it ensures that the sum is printed after adding all the numbers within each tuple, but before moving to the next tuple.

Move and indent line 5 below line 6: This option is correct. By moving line 5 below line 6 and indenting it to the same level as line 6, it resets the sum after each loop iteration. This ensures that the sum reflects the total after adding all the numbers.

Therefore, the correct changes to make are un-indenting line 9 twice, moving line 9 above line 7, and moving and indenting line 5 below line 6. These changes will result in the sum being printed only once, after all the numbers have been added.

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One example of an OSHA-required sharp with engineered injury protection is a safety scalpel. Safety scalpels are specifically designed to reduce the risk of accidental cuts and injuries during medical procedures or other tasks that require the use of a scalpel.

The safety scalpel incorporates various features to enhance user safety, including:

1. Retractable Blade: Safety scalpels often have a retractable blade mechanism. The blade can be extended for use, but it automatically retracts into the handle or sheath once pressure is released or when the cutting action is complete. This feature helps prevent accidental cuts or injuries when the scalpel is not in use.

2. Shield or Guard: Many safety scalpels come with a shield or guard that covers the blade when it is not in use. The shield acts as a physical barrier, preventing accidental contact with the blade and reducing the risk of injuries.

3. Activation Mechanism: Safety scalpels typically feature an activation mechanism that requires a deliberate action or a specific grip to engage the blade. This helps ensure that the blade is only exposed when intended, minimizing the potential for unintentional cuts.

4. One-Time Use: Some safety scalpels are designed for single-use, meaning that they are disposed of after a single procedure. This eliminates the need for blade handling, retraction, or disposal, further reducing the risk of injuries associated with blade manipulation.

These engineered injury protection features in safety scalpels are in line with OSHA's guidelines to minimize the risk of sharps injuries in healthcare settings and other industries where sharp objects are used. By implementing these safety measures, safety scalpels help protect healthcare workers, patients, and others from accidental cuts, thereby promoting a safer working environment.

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Answer:

positive sides:

negative sides:

Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

Explanation:

1. increase This due to increase in the pore volume.

2.increase . This is due to the fact that more liquid phase will be present at the firing.

3. Increase. This increase is because of the fact that clay on cooling forms glass.Thus, gaining more strength as the liquid phase formed fills in pore volume.

4. Increase, Rate of corrosion depends upon the surface area exposed.Since, upon vitrification surface area would increase, therefore corrosion increases.

5. Increase , glass has higher thermal conductivity than the pores it fills.

Answer:

r = 1.922 mm

Explanation:

We are given;

Yield stress; σ = 250 MPa = 250 N/mm²

Force; F = 29 KN = 29000 N

Now, formula for yield stress is;

σ = F/A

A = F/σ

Where A is area = πr²

Thus;

r² = 2900/250π

r² = 3.6924

r = √3.6924

r = 1.922 mm

A)  d) All of the above. B) The unit of efficacy is a) Lumen/Watts. and C) The luminous intensity is b) flux/Steradian.

Illuminance is the measure of the amount of light that falls on a surface per unit area. It is affected by distance, flux, and area. Distance plays a role in illuminance because the further away a light source is, the less illuminance it will produce on a surface. Flux, which is the total amount of light emitted by a source, also affects illuminance because the more flux a source produces, the more illuminance it will generate. Finally, area is a factor in illuminance because the larger the surface area that the light falls on, the lower the illuminance will be.
B. The correct answer to the multiple-choice question about the unit of efficacy is a) Lumen/Watts. Efficacy is the measure of how efficient a light source is at producing visible light. It is calculated by dividing the total amount of light output (in lumens) by the power consumed (in watts). Therefore, the unit of efficacy is lumen/watt.
C. The correct answer to the multiple-choice question about calculating luminous intensity is b) flux/Steradian. Luminous intensity is the measure of the amount of light emitted in a particular direction. It is calculated by dividing the flux (total amount of light emitted by the source) by the solid angle in which the light is emitted (measured in steradians). Therefore, the formula for calculating luminous intensity is flux/steradian.

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in relation to Lean Manufacturing on assembly lines Designing of an assembly line:

In Lean Manufacturing, designing an efficient assembly line is crucial to optimize productivity, minimize waste, and ensure smooth production flow. The design process involves careful consideration of various factors, including product specifications, workflow, ergonomics, and the elimination of non-value-added activities. Key principles of assembly line design in Lean Manufacturing include:

Continuous flow: Designing the line to achieve a smooth, uninterrupted flow of materials and components, minimizing bottlenecks and delays.

Standardized work: Developing standardized processes and workstations to ensure consistency and eliminate variations that can lead to errors or inefficiencies.

Balancing the line: Distributing work tasks evenly among workstations to achieve a balanced workload, preventing overburdening or underutilization.

Pull system: Implementing a pull-based production system where workstations signal the need for components or materials from preceding workstations, reducing excess inventory and waste.

Visual management: Using visual cues and indicators to provide real-time information, aiding operators in identifying abnormalities, maintaining organization, and ensuring adherence to standardized procedures.

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Understanding a product LCA (Life Cycle Assessment) helps in waste management and in assessing environmental impacts.

The process of life cycle assessment evaluates the environmental effects of a product over the course of its existence. The following are the most crucial applications:

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Answer:

14.5° ; THD % = 3.873 × 100 = 387.3%.

Explanation:

Okay, in this question we are given the following parameters or data or information which is going to assist us in solving the question efficiently and they are;

(1). "500 VAR reactive power from 230 Vrms 50 Hz 1.5 KVAR reactor".

(2). Consideration of up to 12th harmonic.

So, let us delve right into the solution to the question above;

Step one: Calculate the Irms and Irms(12th) by using the formula for the equation below;

Irms = reactive power /Vrms = 500/230 = 2.174 A.

Irms(12th) = 1.5 × 10^3/ 12 × 230 = 0.543 A.

Step two: Calculate the THD.

Before the Calculation of the THD, there is the need to determine the value for the dissociation factor, h.

h = Irms(12th)/Irms = 0.543/ 2.174 = 0.25.

Thus, THD = [1/ (h)^2 - 1 ] ^1/2. = 3.873.

THD % = 3.873 × 100 = 387.3%.

Step four: angle AC - Ac converter

theta = sin^-1 (1.5 × 10^3/ 12 × 500) = 14.5°.

Answer:

it gives pressure this makes it stay where it has to be and lock it

Explanation:

yan llng alam ko

Answer:

........

....... False