write 3 to 5 sentences about predicting the properties of acids and bases​

The energy of the photon of light can be obtained as 6.27 * 10^-20 J.

We know that a photon has to to do with a particular unit of light. We know that light can be said to be composed of very tiny corpuscles and these corpuscles of light is what we call the photon of the light.

We can be able to us the equation that is derived by Max Plank to be able to get the value of the energy of the photon of light. Now we know that a photon of light can have an energy that is able to be obtained by;

E = hf

h = Plank's constant

f = Frequency

Then;

E = 6.6 * 10^-34 Js * 9.5 * 10^13 Hz

= 6.27 * 10^-20 J

Thus as we can see from the parameters in the question, the energy of the photon is 6.27 * 10^-20 J.

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heat, temperature change, surrounding, insulated are the answers in blanks.

By monitoring the temperature change of the materials around the activity, a calorimeter determines the heat produced during reactions or other processes. The calorimeter is insulated to prevent the transfer of heat to outside the device.A calorimeter is a device used to measure the amount of heat energy released or absorbed in a chemical or physical process. The energy released or absorbed is typically measured in units of joules (J). The equation for the energy released or absorbed can be written as follows:

Energy (J) = Mass (kg) × Specific Heat Capacity (J/kg-K) × Change in Temperature (K)

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complete question:A calorimeter measures the _____ involved in reactions or other processes by measuring the _____ of the materials _____ the process. The calorimeter is _____ to prevent the transfer of heat to outside the device.

Answer:

The interpretation of the particular subject is covered in the subsection below in detail.

Explanation:

Answer:

Explanation:

When the Lewis base  (CH3)2NH reacts with Lewis acid Lewis acid (CH3CH2)3C⁺  which is also a carbocation , a new bond is formed as follows by the donation of a loan pair of electrons by the nitrogen atom of

(CH3)2NH . Here (CH3)2NH donates electrons so it acts as base and the second group accepts electrons so it is acid .

THe structure of the product formed is shown in the file attached .

Answer:

\no

Explanation:

If an electron in a hydrogen atom changes from an energy level with primary quantum numbers to the n=2 state, emitting a photon with a wavelength of 434 nm, the value of ni is five.

what does Rydberg's equation explains?

The wavelength of light produced by an electron transitioning between atomic energy levels is predicted by the Rydberg formula. There is just one spectral fingerprint for each element. Light is created when an element is heated in its gaseous state. Bright lines of different colours can be seen when this light filters through a prism or diffraction grating. Each component stands out from the others in some way.

According to the question:

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Answer:

140.3 *C

Explanation:

(P1 * V1) / T1 = (P2 * V2) / T2

where P1 = 3.000 atm, V1 = 200.0 ml, T1 = 37.0°C + 273.15 = 310.15 K, P2 = 2.000 atm, V2 = 400.0 ml.

Substituting these values into the formula gives:

(3.000 atm * 200.0 ml) / 310.15 K = (2.000 atm * 400.0 ml) / T2

Solving for T2 gives:

T2 = (2.000 atm * 400.0 ml * 310.15 K) / (3.000 atm * 200.0 ml)

T2 ≈ 413 K or 140°C.

Answer:

126.99g

Explanation:

NiO has a molar mass of 74.7 g/mol. This means that one mole of nickel (II) oxide has a mass of 74.7 grams. We can use stoichiometry/dimensional analysis to figure out how many grams are in 1.7 moles.

\(1.7mol NiO (\frac{74.7grams}{1 mole} ) = 126.99g\)

Answer: mass m = n M = 1.7 mol × 74.69 g/mol

Explanation:

Molar mass M(NiO) = (58.69+16) g/mol

The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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Answer:

Quantitative

Explanation:

quantitative is example of measuring length

The standard deviation of the sample is 0.579, rounded to the correct number of significant figures.

To calculate the standard deviation of the sample, we need to follow these steps:

To find the mean, we sum up all the data points and divide by the number of data points. Let's calculate it:

(3.09 + 4 + 2.775 + 2.5 + 3.80) / 5 = 16.165 / 5 = 3.233

To do this, we subtract the mean (3.233) from each data point and square the result:

(3.09 - 3.233)^2 = 0.020049

(4 - 3.233)^2 = 0.586489

(2.775 - 3.233)^2 = 0.209025

(2.5 - 3.233)^2 = 0.537289

(3.80 - 3.233)^2 = 0.323329

To find the variance, we sum up the squared differences from step 2 and divide by the number of data points:

(0.020049 + 0.586489 + 0.209025 + 0.537289 + 0.323329) / 5 = 1.676181 / 5 = 0.3352362

√0.3352362 = 0.579 (rounded to three significant figures)

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While having experienced polar explorers at the Catlin Arctic Survey would have been beneficial in many ways, it would also have been important for them to work collaboratively with the rest of the team.

Advantages:

Experienced polar explorers would have had a wealth of knowledge and skills, such as how to travel over the ice, how to set up camp, and how to handle emergencies.

Experienced polar explorers would have been able to make informed decisions about the best routes to take and the most efficient ways to travel. This could have helped to save time and energy.

Disadvantages:

Experienced polar explorers may have been set in their ways and resistant to new ideas. This could have hindered the team's ability to adapt to changing circumstances and make the most of new opportunities.

Experienced polar explorers may have been overconfident and taken risks that the rest of the team was not comfortable with. This could have put everyone's safety at risk.

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Given :

Mass of \(H_2SO_4\) is 571.6 g per liter .

Density of solution , \(\rho=1.329\ g/cm^3\) .

To Find :

a. Mass percentage

b. Mole fraction

c. Molality

d. molarity of H2SO4 in this solution.

Solution :

Molar mass of \(H_2SO_4\) , m = 1329 g/mol .

a ) Mass of \(H_2SO_4\) contain in 1 liter is 1329 g .

\(mass \ \%=\dfrac{571.6}{1329}\times 100=43.01 \%\)

b ) Moles of \(H_2SO_4\) = \(\dfrac{571.6\ g}{98\g/mol}=5.83\ mol\) .

Moles of \(H_2O\) = \(\dfrac{1329-571.6\ g}{18\ g/mol}=42.08\ mol\) .

Mole fraction \(=\dfrac{5.83}{5.83+42.08}=0.12\) .

c ) Molarity of \(H_2SO_4\)  \(=\dfrac{5.83\ mol}{1 \ L}=5.83\ M\) .

Hence , this is the required solution .

Answer:

2 Cu + O2 → 2 CuO

This is an oxidation-reduction (redox) reaction:

2 Cu0 - 4 e- → 2 CuII

(oxidation)

2 O0 + 4 e- → 2 O-II

(reduction)

Cu is a reducing agent, O2 is an oxidizing agent.

Answer:

HBr+LiOH->H2O+LiBr

Explanation:

Hydrogen and Lithium ions have a charge of +1, Bromine and Hydroxide ions have a charge of -1. Therefore, the result.

Answer:

they are all right

Explanation:

A piece of metal with a mass of 14.9 g is heated from 72.35°C. When the metal is placed in 75.0 g of water at 20.0°C, the temperature of the water rises by 2.85°C. 66.35 joule/Kg °C is the specific heat capacity of the metal.

In thermodynamics, the specific heat capacity (symbol c) of a substance is the heat capacity of a sample of the substance divided by the mass of the sample, also sometimes referred to as massic heat capacity.

Informally, it is the amount of heat that must be added to one unit of mass of the substance in order to cause an increase of one unit in temperature.

Cp of metal× Mass of metal*(initial temperature-final temperature)=Cp of water× Mass of water×(final temperature - initial temperature)

Cp of metal×14.9×(98–28.5)=Cp of water×75×(28.5–20)

Cp of metal×14.9×(98–28.5)=Cp of water×75×(28.5–20)

Cp of metal =66.35 joule/Kg °C.

Therefore, 66.35 joule/Kg °C is the specific heat capacity of the metal.

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Algal blooms and high concentrations of nitrogen in water are effects of water pollution. Overgrazing and the use of chemical fertilizers cause water pollution.

Algal blooms are an effect of water pollution. They occur when there is an excessive amount of nutrients, particularly nitrogen and phosphorus, in the water due to pollution. The overgrowth of algae depletes the oxygen levels in the water, which can harm fish and other aquatic animals.

Overgrazing can cause water pollution by increasing the sedimentation rate of waterways. This sedimentation can carry nutrients, bacteria, and other pollutants into the water, which can degrade water quality and cause harm to aquatic life.

The use of chemical fertilizers to enhance production is a cause of water pollution. When fertilizer is overused, it can leach into waterways and cause nutrient pollution, which can lead to algal blooms and other forms of water pollution.

High concentrations of nitrogen in water are often an effect of water pollution. This can be caused by the overuse of fertilizers or the discharge of untreated sewage into waterways. High nitrogen levels can cause algal blooms, which can lead to oxygen depletion and harm aquatic life.

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Answer:

Cause:

: : use of chemical fertilizers to enhance production

: : overgrazing

Effect:

: : high concentration of nitrogen in water

: : algal blooms

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From the given choice of substances, the one that is not a molecule is Mn.

Molecules are defined as the smallest unit of a substance that can exist and still retain the properties of that substance.

Molecules of substance are usually formed from the atom of the substances when two or more atoms of the same elements or different elements combine.

Molecules of substances are capable of existing alone but atoms of an element must combine to form molecules.

Considering the given substance to determine whether they are molecules or not:

H₂S is a molecule because it contains more than one atom of elements.

O₃ is a molecule because it contains more than one atom of elements.

KOH is a molecule because it contains more than one atom of elements.

Mn is a not molecule because it contains only one atom of elements.

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From the given data, the name of the hydrated salt would be  \(CoCl_2.83H_2O\).

The formula of the hydrated salt can be determined using the empirical formula approach. That is, we will find the mole equivalent of the anhydrous salt and the water of hydration and then combine them into a single formula after dividing by the smallest mole.

First, we need to determine the mass of the anhydrous salt and the water of hydration.

Mass of crucible (x) = 12.090 g

Mass of hydrated salt + crucible (y) = 16.250 g

Thus, the mass of the hydrated salt can be determined by subtracting x from y.

Mass of hydrated salt = 16.250 - 12.090 = 4.16 g

Mass of hydrate + crucible after evaporating off the water (z) = 12.424 g

Mass of anhydrous salt = z - x

                                      = 12.424 - 12.090

                                      = 0.334 g

Mass of water = 4.16 - 0.334

                        = 3.826 g

Now, let's find the moles:

Molar mass of \(CoCl_2\) = 129.839 g/mol

Molar mass of water = 18.01 g/mol

Mole of \(CoCl_2\) = 0.334/129.839 = 0.00257 mol

Mole of water = 3.826/18.01 = 0.2124 mol

Dividing through by the smallest mole

\(CoCl_2\) =  0.00257 / 0.00257  = 1

water = 0.2124/ 0.00257 = 83

Thus, the formula of the hydrate would be \(CoCl_2.83H_2O\)

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The molarity of aqueous lithium bromide, LiBr solution is 0.2 M

We'll begin by calculating the number of mole of Pb(NO₃)₂ in the solution.

Mole = Molarity x Volume

Mole of Pb(NO₃)₂ = 0.25 × 0.01

Mole of Pb(NO₃)₂ = 0.0025 mole

Next, we shall determine the mole of LiBr required to react with 0.0025 mole of Pb(NO₃)₂

Pb(NO₃)₂ + 2LiBr —> PbBr₂ + 2LiNO₃

From the balanced equation above,

1 mole of Pb(NO₃)₂ reacted with 2 mole of LiBr.

Therefore,

0.0025 mole of Pb(NO₃)₂ will react with = 2 × 0.0025 = 0.005 mole of LiBr

Finally, we shall determine the molarity of the LiBr solution

Molarity = mole / Volume

Molarity of LiBr = 0.005 / 0.025

Molarity of LiBr = 0.2 M

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The internal energy △E of the gas increased by 7,012.5 J.

The internal energy change of a system is given by the equation: ΔE = q + w where ΔE is the change in internal energy, q is the heat added to the system, and w is the work done by the system.

Since the volume remains constant, no work is done, so w = 0. Therefore, ΔE = q.

The heat added to the system is given by the equation:

q = nC(v)ΔT

where n is the number of moles of gas, C(v) is the molar specific heat capacity at constant volume, and ΔT is the change in temperature.

Substituting the given values, we get:

q = (1.00 mol) x (25.00 J/mol.K) x (280.5 K - 140.0 K)

q = 7,012.5 J

Therefore, the internal energy change for this process is:

ΔE = q = 7,012.5 J

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The order of the components of the electromagnetic spectrum from shortest wavelength to longest is as follows: 3-5-2-1-7-6-4.

Electromagnetic spectrum is the entire range of wavelengths of all known electromagnetic radiations extending from gamma rays, to X-rays through visible light, infrared, to radio waves.

The components of the electromagnetic spectrum from order of shortest to longest wavelength is as follows;

This suggests that gamma rays have the shortest wavelength while radio waves have the longest wavelength.

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Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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Answer:

Explanation:

When reading a scale. you should always see it from a perpendicular angle and read the lower miniscus( the base of the curve)

it is 10 mL, 9.9mL if you want this to be precise