Work out the length of ab coordinate

Answer:

All-cereal=banana so 3.1 is banana

Answer:  j(x) = (x-1)(x+2)

The x-1 part is because of the root x = 1

The root x = -2 leads to the factor x+2

Answer:

C

Step-by-step explanation:

Answer:

the probability that 50% or more of the sample are overweight or obese is 0.1128 or approximately 11.28%.

Step-by-step explanation:

Given:

The population proportion of overweight/obese children in the community = p = 0.54

Sample size = n = 300

We are interested in finding the probability that the proportion of overweight/obese children in the sample will be greater than 0.5. We can use the Central Limit Theorem to approximate the distribution of the sample proportion. The mean and standard deviation of the sample proportion can be calculated as:

mean (μ) = p = 0.54

standard deviation (σ) = sqrt [p(1-p)/n] = sqrt [(0.54)(0.46)/300] = 0.033

Using the normal distribution, we can calculate the z-score corresponding to a sample proportion of 0.5 or more as:

z = (0.5 - μ) / σ = (0.5 - 0.54) / 0.033 = -1.212

Using a standard normal distribution table, the probability of getting a z-score less than or equal to -1.212 is 0.1128. Therefore, the probability of getting a sample proportion of 0.5 or more is:

P(z < -1.212) = 0.1128

So, the probability that 50% or more of the sample are overweight or obese is 0.1128 or approximately 11.28%.

Answer:

should be complementary angles

The standard matrix A is [ (1/2, √3/2) (√3/2, -1/2) ]

To find the standard matrix of a linear transformation, we need to find the images of the standard basis vectors under the transformation.

The standard basis vectors in R2 are (1,0) and (0,1). Let's find their images under T.

The image of (1,0) under a 30∘ clockwise rotation is (√3/2, 1/2). The image of this under reflection through the line y=x is (1/2, √3/2).

The image of (0,1) under a 30∘ clockwise rotation is (-1/2, √3/2). The image of this under reflection through the line y=x is (√3/2, -1/2).

The standard matrix of T is then the matrix whose columns are the images of the standard basis vectors:

A = [ (1/2, √3/2) (√3/2, -1/2) ]

= \(\left[\begin{array}{cc}1/2&\sqrt{3} /2\\\sqrt{3} /2&-1/2\end{array}\right]\)

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Answer:

The correct option is (B).

Step-by-step explanation:

The given statement is :

\(\sqrt[4]{2} =2^{\dfrac{1}{4}}\)

We need to select the correct simplification for this.

We know that, \(\sqrt[a]{x} =x^{\dfrac{1}{a}}\)

So,

\(\sqrt[4]{2} =(2)^{\dfrac{1}{4}}\)

Also, \((x^a)^b=x^{a\times b}\)

So,

\((2^{\dfrac{1}{4}})^4=2^{\dfrac{1}{4}}\times 2^{\dfrac{1}{4}}\times 2^{\dfrac{1}{4}}\times 2^{\dfrac{1}{4}}\\\\=2^{\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}}\\\\=2^1\\\\=2\)

So, these are the steps. Hence, the correct option is (B).

The recurrence relation for the number of ternary strings of length n that contain two consecutive zeros looks correct.

You can see that the first few terms match with your calculations:

a_1 = 0 (no possible strings)

a_2 = 1 (only one possible string: "00")

a_3 = 5 (possible strings: "000", "001", "002", "100", "200")

To explain your reasoning:

You can add "1" or "2" to the end of all the a_{n-1} strings, so there are 2a_{n-1} possible strings with n-1 length that end with "1" or "2".

You can add "01" or "02" to the end of all the a_{n-2} strings, so there are 2a_{n-2} possible strings with n-2 length that end with "01" or "02".

To count the number of strings of length n that contain two consecutive zeros, you need to add the strings that end with "00". There are 3^{n-2} possible strings of length n-2 that you can append "00" to.

Therefore, the recurrence relation is:

a_n = 2a_{n-1} + 2a_{n-2} + 3^{n-2}

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The factor of the expression 9t – 3u will be 3 and 3t – u.

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

One of the many branches of mathematics is algebra. Algebra, which is a common thread throughout practically all of mathematics, is broadly defined as the study of numbers and symbols and the procedures for using these symbols in formulae.

The expression is given below.

⇒ 9t – 3u

Simplify the expression, then we have

⇒ 3·3t – 3u

⇒ 3(3t – u)

The factor of the expression 9t – 3u will be 3 and 3t – u.

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Answer:

B

Step-by-step explanation:

By the Angle - Angle - Angle criteria both ΔDEF and ΔSTR are Similar to each other.

Two triangles are said to be similar triangles if all three corresponding angles are equal or if all three sides are equal. The symbol "∼" is used to represent the similarity between two triangles.    

AAA Similarity Criterion for Two Triangles:

When three angles in two triangles are equal then the two triangles are said to be similar triangles.    

Here we have

ΔDEF and ΔSTR

From ΔDEF  

∠D = 46° and ∠E = 46°  

As we know the sum of angles in a triangle = 180°

=> ∠D + ∠E + ∠F = 180°

=> 46° + 46° + ∠F = 180°

=> ∠F = 180 - 46 - 46

=> ∠F = 88°

Similarly, In ΔSTR  

=> ∠ T = 88°  

Thus,

Three corresponding angles of ΔDEF and ΔSTR are equal

Therefore,

By the Angle - Angle - Angle criteria both ΔDEF and ΔSTR are Similar to each other.

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The value of y when x is 40 is given as follows:

y = 400.

It means that 40 copies of the book were purchased, each at $100.

A proportional relationship is defined as follows:

y = kx.

In which k is the constant of proportionality.

The variables in this problem are given as follows:

Each book sells for $10, hence the constant is given as follows:

k = 10.

Then the equation is given as follows:

y = 10x.

The value of y when x is 40 is given as follows:

y = 10 x 40

y = 400.

The problem is incomplete, hence we suppose that we have that each book sells for $10, and then model a proportional relationship with it.

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Answer: 30$

Step-by-step explanation:

first you divide 420 by 35 and you get 12 times 2.50$ equals 30$

Answer:

I think the answer will be:- m = \(-\frac{5}{3}\)

Answer:

Latoya got a better deal because she paid less than Herman by 25 cents

Step-by-step explanation:

Latoya 18 divided by 8= $2.25

Herman 15 divided by 6= $2.50

So Latoya saves $0.25 cents

7173 water bottles that can be produced at a production cost of $5,258.

To find the slope (m), we can use the formula:

m = (4582 - 885) / (6280 - 1200)

m = 3697 / 5080

m ≈ 0.7274

Now, let's find the y-intercept (b) using the equation:

b = y - mx

b = 885 - 0.7274 x 1200

b = 885 - 872.88

b ≈ 12.12

Therefore, the equation of line is

y = 0.7274x + 12.12

Now, the production cost of $5,258 means put y= 5258

5258 = 0.7274x + 12.12

5239.88 = 0.7274x

x= 7203

Thus, 7173 water bottles that can be produced at a production cost of $5,258.

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The maximum amount you can finance is $896.

We are given that;

The monthly gross income = $3,200

Now,

28% of your gross monthly income on your mortgage, including taxes and insurance

The percentage = 28%

3200* 28/100

=32*28

=896

Therefore, by percentage the answer will be $896.

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Answer:

  49

Step-by-step explanation:

The greatest common divisor of the addends must also be a divisor of 2009. That number can be factored as ...

  2009 = 1×2009 = 7×287 = 41×49

The largest possible factor such that the other factor can be a sum of 9 positive integers is 49.

The maximum value of the GCD is 49.

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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I hope this pictures help

Answer:

  x = 3

Step-by-step explanation:

You want the equation of vertical line BD that includes point B(3, 2).

The equation of a vertical line is ...

  x = c . . . . . . for some constant c

Since we want the line to go through a point B(3, 2) with x-coordinate 3, that is the value the constant must have.

  x = 3 . . . . . the equation of line BD

__

Additional comment

Ordinarily, this rectangle would be named ABDC, with the vertices named in order around the figure.

Answer:

C is the answer (98%)

Step-by-step explanation:

pls mark brainliest

Answer:

seven multiplied by x to the second power multiplied by the difference of two multiplied by x subtract 3 multiplied by the product of three multiplied by z multiplied by 3 add four.

Step-by-step explanation:

This is a useless question, word form isn't in any sort of ACTUAL GLOBAL TEST. So don't stress over this.

Answer:

middle number is 150

Step-by-step explanation:

the middle of 130 - 170:

170 - 130 = 40

40/2 = 20

so the middle is:

130 + 20 = 150

or can be found:

170 - 20 = 150

middle number is 150

Answer:

150

Step-by-step explanation:

Add the two extreme numbers and take the average

130 + 170 = 300

300/2 = 150

150 is 20 distant from 130 and also 20 distant from 170

Step 1

Given;

Required; To find the median

Step 2

Arrange the data from smallest to largest

The median is the middle value in a list ordered from smallest to largest.

The number of data is even and the median is gotten with the formula

Answer; Median=39

The volume of house built by David for cat is 64 ft³.

Firstly representing the mentioned statement about volume as mathematical expression. Exponent is the power of variable or constant. So, volume = x³, where x is the edge length.

As the edge length of house of car is given, we will keep the value in formula to find the volume of house.

V = 4³

Taking cube of the value on Right Hand Side of the equation

V = 4×4×4

Performing multiplication on Right Hand Side of the equation

V = 64 ft³

Thus, the volume of the house of cat is 64 ft³.

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Answer:

$7.75

Step-by-step explanation:

Given: Adults = 4, Children = 5, All worth = $15, Total cost = $71, Each child's ticket = $5

To find: How much the adult tickets are

Solution: Use the 5 tickets at $5 to get $25

Add the $15 for concessions to reach $40

                            25 + 15 = 40

Subtract $40 from the 71 spent to get $31

                            71 - 40 =  31      

Now, divide the 31 by 4 for the number of adults which equals $7.75

                             31 ÷ 4 = 7.75

So, the cost of the adults' tickets is $7.75

Answer:

400 unit

Step-by-step explanation:

Answer:

400

Step-by-step explanation:

area us length times width