why when i shut my husqvarna mower off and try to start it again it want start and the spark plugs are wet with fuel
Answers
Husqvarna mowers are popular among homeowners who enjoy maintaining their own lawns. This issue can arise for various reasons, including the carburetor being clogged, a damaged or clogged air filter, or a bad spark plug.
Below are some reasons why your Husqvarna mower won't start after you shut it off and a few tips to fix this issue.
1. Clogged Carburetor
One of the most common causes of a Husqvarna mower not starting after shutting it off is a clogged carburetor. Dirt and other debris can build up in the carburetor over time, blocking fuel from flowing and preventing the engine from starting. To fix this, remove the carburetor from the mower and clean it with carburetor cleaner and a small brush.
2. Damaged or Clogged Air Filter
Another possible cause of a Husqvarna mower not starting after being shut off is a damaged or clogged air filter. The air filter removes dirt and debris from the air before it enters the engine. Over time, the filter can become clogged with dirt and debris, reducing airflow and causing the engine to stall. If the air filter is dirty, replace it with a new one.
3. Bad Spark Plug
The spark plug is responsible for igniting the fuel in the engine and is an essential component of any mower. If the spark plug is dirty, damaged, or not functioning correctly, the engine will not start. To fix this issue, remove the spark plug from the engine, clean it with a wire brush, and check the gap. If the spark plug is damaged or worn out, replace it with a new one.
In conclusion, when you shut your Husqvarna mower off and try to start it again, but it won't start, the spark plugs may be wet with fuel. It can be frustrating to deal with, but by troubleshooting the potential causes and taking the necessary steps, you can fix the issue and get back to mowing your lawn.
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Related Questions
Define the amplitude of a wave
Answers
Answer:
amplitude of a wave is the maximum displacement of a particle from its rest position
What is the use of the information obtained from remote sensing camera?
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Answer:
jshsbsbsbsnsnnshshabahabzb
What would be the volume of a liquid that has a density of 1.2 g/mL and a mass of 24 grams
Answers
Answer:
The answer is 20 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\\)
From the question
mass = 24 g
density = 1.2 g/mL
We have
\(volume = \frac{24}{1.2} \\ \)
We have the final answer as
20 mLHope this helps you
If you blow up a balloon, tie it off, and release it, it will fall to the ground.
Why does it fall instead of float?
NO LINKS YA FILTHY VERMINS
Answers
Answer:
carbon dioxide (what you are blowing up the balloon with) is a heavy gas. so when you fill the Balloon with it, the balloon will not float. helium is a light gas and floats. gravity takes another. part in this
If the boy travelled 2 meters to the right and 4 meters to the left what is the total distance that he travelled?
4 m
-4 m
6 m
2 m
Answers
Answer:
6m
Explanation:
2+4=6
Someone please help me into what was the average speed for the entire trip thank you
Answers
From the position-time graph, we have the following:
Distance covered Time
0 to 28 m 0 to 20 seconds
28m to 52 m 20 to 60 seconds
At 52 m 60 to 80 seconds
52 to -20m 80 to 110 seconds
Let's find the average speed for the entire trip.
To find the average speed, apply the formula:
\(avg\text{ spe}ed=\frac{total\text{ distance}}{total\text{ time}}\)Distance at line 1: 28 - 0 = 28m
Distance at line 2: 52 - 28 = 24 m
Distance at line 3: 0 m
Distance at line 4: -20m - 52 = -72 m
Thus, we have the equation:
\(s=\frac{d_1}{t_1}+\frac{d_2}{t_2}+\frac{d_3}{t_3}+\frac{d_4}{t_4}\)Where:
d1 = 28 m
d2 = 24 m
d3 = 0 m
d4 = 72 m
t = 110 s
Now substitue values into the equation:
\(\begin{gathered} s=\frac{28}{20}+\frac{24}{40}+\frac{0}{20}+\frac{72}{30} \\ \\ s=4.4\text{ m/s} \end{gathered}\)Therefore, the average speed for the trip is 4.4 m/s.
ANSWER:
Equation:
\(s=\frac{d_1}{t_1}+\frac{d_2}{t_2}+\frac{d_3}{t_3}+\frac{d_4}{t_4}\)Substitution:
\(s=\frac{28}{20}+\frac{24}{40}+\frac{0}{20}+\frac{72}{30}\)Calculation:
\(\begin{gathered} s=1.4\text{ + }0.6\text{ + 0 + }2.4 \\ \\ s=4.4\text{ m/s} \end{gathered}\)Distinguish between heat and work in terms of energy
Answers
Answer:
Heat is the energy associated with the random motion of particles, while work is the energy of ordered motion in one direction. Therefore heat is "low-quality" energy and work is "high-quality" energy, and this supports the entropy statement of the Second Law.
Explanation:
photoelectron energy Radiation with an energy of 4.2 eV strikes a photocell. If the work function of the photocell is 2.31 eV, what is the energy of the ejected photoelectron?
Equation Sheet:
E = nhf
E = hf
KE= -eΔVo
h = 6.62607004 x 10^-34 m^2 kg/s
E = hc / λ = 1240 eV . nm/λ
KE = hf - hf0
Electron (mc) 9.109 xx 10^-33 kg
e = 1.60 x 10^-19 C
p = hf/c = h/ λ
λ = h/p = h/mv
Answers
The energy of the ejected photoelectron is 1.89 eV.
Energy of radiation, E = 4.2 eV Work function of photocell, φ = 2.31 eV
Energy of ejected photoelectron is given by the difference of the energy of incident radiation and the work function of the metal. That is, KE = hυ - φ where, h is Planck's constant, υ is the frequency of radiation, c = λυ is the speed of lightλ is the wavelength of radiation and c is the speed of light.
From the energy formula of radiation, E = hυE = hc / λ, by substituting h and c values
KE = hc / λ - φ
Given, h = 6.626 x 10^-34 J-s, c = 3 x 10^8 m/s
λ = hc / E
= (6.626 x 10^-34 J-s x 3 x 10^8 m/s) / (4.2 eV x 1.6 x 10^-19 J/eV)
= 4.93 x 10^-7 m
KE = hc / λ - φ
= (6.626 x 10^-34 J-s x 3 x 10^8 m/s) / (4.93 x 10^-7 m) - (2.31 eV x 1.6 x 10^-19 J/eV)
= 1.89 eV
Therefore, the energy of the ejected photoelectron is 1.89 eV.
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A volleyball dug out by the opponent popped straight up into the air. It takes 2.05 seconds for the ball to reach its peak. Determine the height to which the ball flies. So far, I got the givens of t=2.05 seconds x=? a=9.8 meter per seconds squared final velocity=0 m/s they might be wrong though so help please!!!!
Answers
Answer:
The height to which the ball flies is 86.6 m.
Explanation:
Given that,
Time = 2.05 sec
Acceleration = 9.8 m/s²
We need to calculate the initial velocity of volleyball
Using equation of motion
\(v=u-at\)
Where, u = initial velocity
a = acceleration
t = time
Put the value into the formula
\(0=u-9.8\times(2.05)^2\)
\(u=41.2\ m/s\)
We need to calculate the height of the the ball
Using equation of motion
\(v^2=u^2-2ah\)
Put the value into the formula
\(0=(41.2)^2-2\times9.8\times h\)
\(h=\dfrac{(41.2)^2}{2\times9.8}\)
\(h=86.6\ m\)
Hence, The height to which the ball flies is 86.6 m.
part a what is the shortest de broglie wavelength for the electrons that are produced as photoelectrons?
Answers
The shortest possible de Broglie wavelength for the photoelectron is given by this equation, which depends on the frequency of the incident photon and the mass of the electron.
The shortest de Broglie wavelength for electrons that are produced as photoelectrons can be calculated using the equation λ = h/p, where λ is the de Broglie wavelength, h is Planck's constant, and p is the momentum of the electron. The momentum of the electron can be calculated using the equation p = sqrt(2mK), where m is the mass of the electron and K is the kinetic energy of the electron.
Since the photoelectrons are produced by the absorption of photons, the kinetic energy of the photoelectron can be calculated using the equation K = hf - W, where h is Planck's constant, f is the frequency of the photon, and W is the work function of the material.
Assuming that the photoelectron has the minimum possible kinetic energy (i.e. K = 0), the momentum of the electron can be calculated using the equation p = sqrt(2mhf). Substituting this value of p into the equation for the de Broglie wavelength, we get:
λ = h/p = h/sqrt(2mhf)
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An object initially traveling at 20.0 m/s south decelerates uniformly at 6.00 m/s2 and is displaced 25.0 m. What is the final velocity of the object? (magnitude and direction)
Answers
Answer:
50.37 m/s and 40ms object
How fast would you (70kg) need to run in order to have the same momentum as a car (750kg) driving at 5 km/hr?
Answers
From the calculations and the data provided, the speed is obtained as 15 m/s
What is momentum?The term momentum refers to the product of mass and velocity. Given that we can now proceed with the answer.
Since;
p = mv
m = 750kg
v = 5 km/hr or 1.4 m/s
p = 750kg * 1.4 m/s
p = 1050 kgm/s
If the mass of the body is 70kg, the speed is
v = p/m
v = 1050 kgm/s/70 Kg
= 15 m/s
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An electron is released from a negatively charged plate 0.5m away.The potential difference between the plates is 25v.
Calculate the speed of the electrons as it reaches the positively charged plate
Answers
Explanation:
In brief, electrons are negative charges and protons are positive charges. An electron is considered the smallest quantity of negative charge and a proton the smallest quantity of positive charge.
Two negative charges repel. Also, two positive charges repel. A positive charge and a negative charge attract each other (all experimentally verified.)
Point Charge: An accumulation of electric charges at a point (a tiny volume in space) is called a point charge.
Note: When an atom loses an electron, the separated electron forms a negative charge, but the remaining that contains one less electron or consequently one more proton becomes a positive charge. A positive charge is not necessarily a single proton. In most cases, a positive charge is an atom that has lost one or more electron(s).
What fraction of chlorine-36 remains UN-decayed after 800,000 years?
Answers
What is the likely reason that we cannot find any examples of the first generation stars?
A) We do not know how the first generation stars were formed.
B) The first generation stars formed such a long time ago that the light from them has not yet had time to reach us.
C) The first generation stars are too faint to be visible now.
D) The first generation stars formed with only H and He and therefore have no spectral features.
E) The first generation stars were all very massive and exploded as supernova
Answers
The likely reason that we cannot find any examples of the first generation stars is that the first generation stars formed such a long time ago that the light from them has not yet had time to reach us. The correct option is B.
The likely reason we cannot find any examples of the first generation stars is because they formed a very long time ago, about 13 billion years ago, in the early universe. As a result, their light has not yet had enough time to reach us. This makes it difficult for us to observe them directly.
In addition, the first generation stars are believed to have formed with only hydrogen and helium, and therefore, they may not have any distinct spectral features that would make them easier to detect. This, combined with the fact that they were likely very massive and had short lifetimes, could also make them more difficult to observe.
Moreover, these stars are expected to have exploded as supernovae, leaving behind only remnants such as black holes or neutron stars. This further complicates their detection as we have to rely on indirect observations of their effects on surrounding gas and stars.
Therefore, although we have not directly observed any first-generation stars, their existence is inferred through indirect observations of their effects on the interstellar medium, such as the formation of heavy elements. The study of these effects has provided crucial insights into the early universe's formation and evolution.
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The vitreous humor, a transparent, gelatinous fluid that fills most of the eyeball, has an index of refraction of 1.34. Visible light ranges in wavelength from 400 nm (violet) to 700 nm (red), as measured in air. This light travels through the vitreous humor and strikes the rods and cones at the surface of the retina.
1.What are the ranges of the wavelength of the light just as it approaches the retina within the vitreous humor?
Answer in the order indicated. Express your answers in nanometers separated by comma.
2.What are the ranges of the frequency of the light just as it approaches the retina within the vitreous humor?
Answer in the order indicated. Express your answers in hertz separated by comma.
3.What is the speed of the light just as it approaches the retina within the vitreous humor?
Express your answer in meters per second.
Answers
1. The range of the wavelength of light is 298.51 nm to 522.39 nm.
2. The range of the frequency of light is 400 THz to 428.57 THz.
3. The speed of light just as it approaches the retina is 2.24 × 10⁸ m/s.
1.
To evaluate the ranges of the wavelength, frequency, and speed of light as it approaches the retina within the vitreous humor, we can use the principles of refraction and the index of refraction for the vitreous humor.
For violet light with a wavelength of 400 nm:
\(\lambda_{violet_{vitreous}} = 400 / 1.34 = 298.51 nm\)
For red light with a wavelength of 700 nm:
\(\lambda_{red_{vitreous}} = 700 / 1.34 = 522.39 nm.\)
Therefore, the ranges of the wavelength of light just as it approaches the retina within the vitreous humor are 298.51 nm to 522.39 nm.
2.
Frequency Range:
The frequency of light remains constant as it passes from one medium to another. The formula for calculating the frequency is given by:
\(f_{medium} = f_{air}\),
where\(f_{medium}\) is the frequency in the medium and \(f_{air}\) is the frequency in air.
The ranges of frequency for violet and red light remain the same as in air. Thus, the ranges of the frequency of light just as it approaches the retina within the vitreous humor are the same as the frequency in air.
For violet light: 400 THz.
For red light: 428.57 THz.
Therefore, the ranges of the frequency of light just as it approaches the retina within the vitreous humor are 400 THz to 428.57 THz.
3.
Speed of Light:
The speed of light in a medium is given by:
\(v_{medium} = c / n_{medium}\),
where \(v_{medium}\) is the speed of light in the medium, c is the speed of light in a vacuum (approximately 3.00 × 10⁸ m/s), and \(n_{medium}\) is the index of refraction of the medium.
The speed of light just as it approaches the retina within the vitreous humor can be calculated as:
v = (3.00 × 10⁸ ) / 1.34 = 2.24 × 10⁸ m/s.
Therefore, the speed of light just as it approaches the retina within the vitreous humor is 2.24 × 10⁸ m/s.
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In order for a full-wave bridge rectifier to convert AC to DC, there must be A); diodes going the same direction connected to both sides of the diode B); diodes going in opposite directions connected to both sides of the diode C); a diode directed into the positive side of a resistor and into the negative side of the resistor D); a diode directed out the positive side of a resistor and out the negative side of the resistor
Answers
To convert AC to DC using a full-wave bridge rectifier, diodes going in opposite directions connected to both sides of the diode are required.
A full-wave bridge rectifier is a circuit that converts AC voltage into DC voltage. It does so by using a combination of diodes arranged in a bridge configuration.
The diodes are arranged so that they block the flow of current in one direction while allowing current to flow in the other direction.
To make this work, there must be diodes going in opposite directions connected to both sides of the diode. This configuration ensures that the AC voltage is always flowing through at least one diode in the correct direction to produce DC voltage at the output.
The diode directed into the positive side of a resistor and into the negative side of the resistor or directed out the positive side of a resistor and out the negative side of the resistor would not work in this circuit.
It is crucial that the diodes be connected in the correct orientation to ensure that the AC voltage is properly converted to DC voltage.
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Please help me with the following question!!! I think I know it but I'm not so sure of myself.
Sunlight travels all the way from the Sun through Earth's atmosphere to the ground. However, sunlight does not always reach the bottom of the ocean. Which of the following best explains why little to no sunlight reaches the bottom of the deepest oceans?
A.Light is reflected by deep ocean currents.
B.Light travels more slowly in water and is absorbed.
C.Light changes speed as it gets farther from the Sun.
D.Light is reflected off the ocean's surface and back into the air.
Answers
Answer:
d
Explanation:
radiation
Answer:
I would say option D is the answer
According to coulomb's law, rank the interactions between charged particles from highest potential energy to lowest potential energy.rank from highest to lowest potential energy. to rank items as equivalent, overlap them.1. 1+ charge and 1- charge seperated by 200pm2. 1+ charge and 1+ charge seperated by 100pm3. 1+ charge and 1- charge seperated by 100pm4. 2+ charge and 1- charge seperated by 100pm
Answers
Answer: (2) > (1) > (3) > (4)
Explanation:
(1) a +1 charge and a -1 charge separated by 200 pm:
The potential energy in this case will be,
\(U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+1 \ C)(-1 \ C)}{200 \times 10^{-9} \ m } \\ & = - \frac{1}{2}k \times 10^7 \ \rm J\)
(2) a +1 charge and a +1 charge separated by 100 pm:
The potential energy in this case will be,
\(U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+1 \ C)(+1\ C)}{100 \times 10^{-9} \ m } \\ & = k \times 10^7 \ \rm J\)
(3) a +1 charge and a -1 charge separated by 100 pm:
The potential energy in this case will be,
\(U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+1 \ C)(-1 \ C)}{100 \times 10^{-9} \ m } \\ & = - k \times 10^7 \ \rm J\)
(4) a +2 charge and a -1 charge separated by 100 pm:
The potential energy in this case will be,
\(U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+2 \ C)(-1 \ C)}{100 \times 10^{-9} \ m } \\ & = - 2k \times 10^7 \ \rm J\)
So, the order from highest potential energy to lowest potential energy is:
(2) > (1) > (3) > (4)
help please asappp.
Answers
Answer:
Radio
Explanation:
As the stonger the waves get the more compressed they get
What is the kinetic energy of a 4.0 kg cart that is moving at a speed of 0.50 m/s?
Answers
Explanation:
K.E = 1/2mv²
K.E = 1/2 x 4 x 0.5²
K.E = 0.5J
Give a real-world example of how energy is transformed from electrical energy to thermal energy. Describe how the heat can be transferred to other objects through conduction, convection, or radiation.
Answers
Answer:
A microwave
Explanation:
Car
Lightbulb is a really good one
Same with the sun. That one has Chemical as well
Answer:
A stove
Explanation:it transfers heat
Mass is 56.8 g and the volume is 10 mL what is the density
Answers
Explanation; Divide the mass of the unknown substance and the volume of the unknown substance and you will have your answer.
Hope this helps! ^^ if you can pls mark me brainiest!
If 100.0 g of a substance releases 45 kJ of energy as it cools from 13.0°C to –15.0°C, what is the specific heat capacity of the substance?
Answers
Answer:
16,071.42J/kgKExplanation:
The formula for expressing the quantity of heat released is expressed as;
Q = mcΔt
m is the mass of the substance = 100g - 0.1kg
c is the specific heat capacity of the substance
Δt is the change in temperature = 13 -(-15) = 28°C
Substitute and get c;
45000 = 0.1c(28)
2.8c = 45000
c = 45000/2.8
c = 16,071.42J/kgK
Hence the specific heat capacity of the substance is 16,071.42J/kgK
A 0.225 kg block of iron at -28.7 °C is put in a cup of 0.150 kg of water at 18.9 °C. What is their equilibrium temperature?
Answers
Answer:
12.3°C should be the correct answer
Answer:
12.3
Explanation:
em 6
Which provides a definition for
matter?
Anything that
A.
B.
C.
D.
is solid and has weight
takes up space and is heavy
takes up space and has mass
is a liquid or solid
Answers
Answer:
definition of matter is that matter takes up space and has mass
what is meant by input and output work
Answers
Answer:
the x and y values
Explanation:
because on the table the x is the input and y is the output
Which of the following parts of a motor cycle is there only to give the feedback ( information) to the driver?
Answers
The brake light is a part of the motorcycle which is there only to give the feedback ( information) to the driver.
What is a Motorcycle?This is referred to as a type of vehicle which has only two wheels and is without pedals. it is used in the transportation of people and goods from one location to another.
This vehicle has different parts and an example is the brake light which denotes that the driver is slowing down as a result of the brake being pressed which helps to reduce sand eliminate incidences of collisions and other forms of accident.
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how does it take bee to travel 90 miles of she travels a constant speed of 60 mph in her car?
a, 2 hours and 15 minutes
b, 1 hour and 30 minute
c, 1/2 an hour
d, 30 minutes
e, 45 minutes
help pls
Answers
Answer:
b
Explanation:
90 miles
60 mph (miles per hour)
1 hour = 60 minutes = 60 miles
90 miles - 60 miles = 30 miles
30 miles = 30 minutes
1 hour and 30 minutes
Heyyyy...Please i need helppp
Answers
anticlockwise = clockwise (Force*distance)
1 * 20 = 2 * x
x = 10